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Linear Algebra I Exercises I

担当

: Saka´ e Fuchino (

渕野 昌

) May 8, 2014

This list of exercises (and its possible further update) is downloadable as:

http://kurt.scitec.kobe-u.ac.jp/~fuchino/kobe/lin-alg1-ss14-ex1.pdf Some other materials connected to to the lecuture might be found at:

http://kurt.scitec.kobe-u.ac.jp/~fuchino/kobe/index.html

A lecture note of the course will be also linked to this page in the course of the semester.

1. Let A =

1 4 2 5 3 6

7 8 9

, B =

2 0 0 2 1 0

1 0 2

, C =

−1 0 0 1 −1 0

1 0 1

.

Calculate (1) AB, (2) B + C, (3) 7A 3B, (4) AB + AC

(Hint for (4): use The Distributive Law (see 4. ) to simplify the calculation), 2. Let

A =

2 2

2

2 2

2 2 2

B =

[ 1 −1 1 1

] .

Calculate AB, BA, A 2 , B 2 , A 3 , B 3 . 3. Let

A =

 

0 1 0 0

0 0 1 0

0 0 0 1

0 0 0 0

  .

Calculate A 2 , A 3 , A 4 .

4. For l × m matrix A = [a i,j ], and m × n matrices B = [b j,k ], C = [c j,k ], show that the following equation (The Distributive Law) always holds: A(B + C) = AB + AC. Show that the corresponding calculation rule (A + B)C = AC + BC also holds (note that the size of matrices should be declared differently for this equation).

5. For a 1 ,..., a n R , let diag(a 1 , ..., a n ) be the n × n matrix D = [d i,j ] (the diagonal matrix with diagonal entries a 1 , ..., a n ) defined by:

d i,j =

{ a i , if j = i

0, otherwise.

(1) What is diag(2, 3, 1, 4)?

(2) Show the following equation:

diag(a 1 , a 2 , ..., a n )diag(b 1 , b 2 , ..., b n ) = diag(a 1 b 1 , a 2 b 2 , ..., a n b n ).

(3) Show that, for an m × n matrix A = [a 1 a 2 · · · a n ],

A diag(a 1 , a 2 , ..., a n ) = [a 1 a 1 a 2 a 2 · · · a n a n ]

holds.

(2)

6. Find the matices M ϕ

1

, M ϕ2 corresponding to the following linear mappings ϕ 1 , ϕ 2 :

ϕ 1 : R 3 R 2 ;

a a

12

a

3

7→

[ a

1

a

2

]

(projection)

ϕ 1 : R 3 R 5 ;

a a

12

a

3

7→

 

 

a

1

a

2

a

3

0 0

 

  (canonical embedding)

7. Show the following:

(1) If a 1 , ..., a n R are all 6= 0 then diag(a 1 , ..., a n ) is invertible and (diag(a 1 , a 2 , ..., a n )) 1 = diag( a 1

1

, a 1

2

, ..., a 1

n

).

(2) If at least one of a 1 , ..., a n R is equal to 0 then diag(a 1 , ..., a n ) is not invertible.

8 (1) Suppose that both of n × n-matrices A and B are invertible. Show that then the matrices AB and BA are invertible as well.

(2) Auppose that A, B are n × n-matrices and A is invertible. Show that AB is invertible if and only if B is invertible 1 .

1

Actually we can even show: For n × n-matrix A and B , AB (or BA) is invertible if and only if both A

and B are invertible. But for the proof of this theorem, we need some deep results we will learn later. In

contrast, the assertion of 8 , (2) can be proved quite easily.

参照

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