• 検索結果がありません。

On a class of multivalent functions defined by Salagean operator

N/A
N/A
Protected

Academic year: 2022

シェア "On a class of multivalent functions defined by Salagean operator"

Copied!
10
0
0

読み込み中.... (全文を見る)

全文

(1)

On a class of multivalent functions defined by Salagean operator

Sevtap S¨umer Eker and Bilal S¸eker

Abstract

The present paper investigates new subclasses of multivalent functions involving Salagean operator. Coefficient inequalities and other interesting properties of these classes are studied.

2000 Mathematical Subject Classification: Primary 30C45 Keywords : Multivalent functions, Salagean operator, Coefficient

Inequalities, Extreme Points, Integral Means.

1 Introduction and definitions

LetA denote the class of functionsf(z) of the form

(1) f(z) =z+

X

j=2

ajzj 154

(2)

which are analytic in the open disc U={z :|z|<1}.

Forf(z)∈ A, Salagean [1] introduced the following operator:

D0f(z) = f(z)

D1f(z) = Df(z) =zf0(z)

Dnf(z) =D(Dn−1f(z)) (nN= 1,2,3, ...).

We note that,

Dnf(z) =z+ X

j=2

jnajzj (nN0 =N∪ {0}).

Let Ap denote the class of functions f(z) of the form

(2) f(z) = zp+

X

j=p+1

ajzj (p1)

which are analytic and p-valent in the open disc U. We can write the following equalities for the functions f(z)∈ Ap :

D0f(z) = f(z) D1f(z) = Df(z) = z

pf0(z) =zp+ X

j=p+1

µj p

ajzj

... ...

Dnf(z) = D(Dn−1f(z)) =zp+ X

j=p+1

µj p

n

ajzj (nN0 =N∪ {0}).

LetNp(m, n, α, β) denote the subclass ofAp consisting of functionsf(z) which satisfies the inequality

Re

½Dmf(z) Dnf(z)

¾

> β

¯¯

¯¯Dmf(z) Dnf(z) 1

¯¯

¯¯+α.

(3)

for some 0≤α <1, β0, m∈N, n∈N0 and allz U.

Special cases of our classes are following:

(i)N1(m, n, α, β) =Nm,n(α, β) which was studied by Eker and Owa [5].

(ii)N1(1,0, α, β) = SD(α, β) which was studied by Shams at all [3].

(iii) N1(1,0, α,0) = S(α) and N1(2,1, α,0) =K(α) which was studied by Silverman [2].

(iv)N1(m, n, α,0) =Km,n(α) which was studied by Eker and Owa [4].

2 Coefficient inequalities for classes N

p

(m, n, α, β)

Theorem 1. If f(z)∈ Ap satisfies (3)

X

j=2

Ψp(m, n, j, α, β)|aj| ≤2(1−α) where

(4) Ψp(m, n, j, α, β) =

¯¯

¯¯(1 +α) µj

p

n

µj

p

m¯

¯¯

¯+ µ

(1−α) µj

p

n +

µj p

m

+2β

¯¯

¯¯ µj

p

m

µj

p

n¯

¯¯

¯

for someα(0≤α <1), β 0, m∈Nandn∈N0 thenf(z)∈ Np(m, n, α, β).

Proof. Suppose that (3) is true for α(0≤α < 1), β 0, m N , n N0. Using the fact that Rew > α if and only if |1−α+w| > |1 +α−w|, it suffices to show that

(4)

(5) ¯

¯(1−α)Dnf(z) +Dmf(z)−βe|Dmf(z)−Dnf(z)|¯

¯

¯

¯(1 +α)Dnf(z)−Dmf(z) +βe|Dmf(z)−Dnf(z)|¯

¯>0 Substituting forDnf(z) and Dmf(z) in (5) yields,

¯¯(1−α)Dnf(z) +Dmf(z)−βe|Dmf(z)−Dnf(z)|¯

¯

¯

¯(1 +α)Dnf(z)−Dmf(z) +βe|Dmf(z)−Dnf(z)|¯

¯

=

¯¯

¯¯

¯(2−α)zp+ X

j=p+1

· (1−α)

µj p

n +

µj p

m¸

ajzj−βe

¯¯

¯¯

¯ X

j=p+1

·µj p

m

µj

p

n¸ ajzj

¯¯

¯¯

¯

¯¯

¯¯

¯

¯¯

¯¯

¯αzp+ X

j=p+1

· (1+α)

µj p

n

µj

p

m¸

ajzj+βe

¯¯

¯¯

¯ X

j=p+1

·µj p

m

µj

p

n¸ ajzj

¯¯

¯¯

¯

¯¯

¯¯

¯

(2−α)|z|p X

j=p+1

¯¯

¯¯(1−α) µj

p

n +

µj p

m¯¯

¯¯|aj| |z|j−β¯

¯e¯

¯X

j=p+1

¯¯

¯¯ µj

p

m

µj

p

n¯¯

¯¯|aj| |z|j

−α|z|p X

j=p+1

¯¯

¯¯(1+α) µj

p

n

µj

p

m¯

¯¯

¯|aj| |z|j−β¯

¯e¯

¯X

j=p+1

¯¯

¯¯ µj

p

m

µj

p

n¯

¯¯

¯|aj| |z|j

2(1−α)−

X j=p+1

·¯¯

¯¯(1+α) µj

p

n

µj

p

m¯

¯¯

¯+ µ

(1−α) µj

p

n +

µj p

m +2β

¯¯

¯¯ µj

p

m

µj

p

n¯

¯¯

¯

¸

|aj|

0

Example 1.The function f(z) given by

f(z) = zp+ X

j=p+1

2(p+ 1 +δ)(1−α)²j

(j +δ)(j + 1 +δ)Ψp(m, n, j, α, β)zj

belongs to the class Np(m, n, α, β) forδ >−p−1, 0≤α <1, β 0, ²j C and j|= 1.

(5)

3 Relation for N e

p

(m, n, α, β )

In view of Theorem 1, we now introduce the subclass Nep(m, n, α, β) which consist of functions f(z) ∈ Ap whose Taylor-Maclaurin coefficients satisfy the inequality (3). By the coefficient inequality for the class Nep(m, n, α, β) we see,

Theorem 2. If f(z)∈ Ap, then

Nep(m, n, α, β2)⊂Nep(m, n, α, β1) for some β1 and β2, 0≤β1 ≤β2.

Proof. For 0≤β1 ≤β2 we obtain X

j=p+1

Ψp(m, n, j, α, β1)|aj| ≤ X

j=p+1

Ψp(m, n, j, α, β2)|aj|.

Therefore, if f(z) Nep(m, n, α, β2), then f(z)∈Nep(m, n, α, β1). Hence we get the required result.

4 Extreme points

The determination of the extreme points of a familyF of univalent functions enables us to solve many extremal problems for F.

Theorem 3. Let fp(z) =zp and fj(z) = zp+ 2(1−α)²j

Ψp(m, n, j, α, β)zj (j =p+ 1, p+ 2, ... ; j|= 1).

(6)

Then f ∈Nep(m, n, α, β) if and only if it can be expressed in the form f(z) =λpfp(z) +

X

j=p+1

λjfj(z),

where λj >0 and λp = 1 X

j=p+1

λj.

Proof. Suppose that f(z) =λpfp(z) +

X

j=p+1

λjfj(z) =zp+ X

j=p+1

λj 2(1−α)²j

Ψp(m, n, j, α, β)zj Then

X

j=p+1

Ψp(m, n, j, α, β)

¯¯

¯¯ 2(1−α)²j

Ψp(m, n, j, α, β)λj

¯¯

¯¯= X

j=p+1

2(1−α)λj

= 2(1−α) X

j=p+1

λj

= 2(1−α)(1−λp)

2(1−α)

Thus,f(z)∈Nep(m, n, α, β) from the definition of the class ofNep(m, n, α, β).

Conversely, suppose that f(z)∈Nep(m, n, α, β). Since

|aj| ≤ 2(1−α)

Ψp(m, n, j, α, β) (j =p+ 1, p+ 2, ...), we may set

λj = Ψp(m, n, j, α, β)

2(1−α)²j aj (|²j|= 1) and

λp = 1 X

j=p+1

λj.

(7)

Then,

f(z) = λpfp(z) + X

j=p+1

λjfj(z).

This completes the proof of theorem.

Corollary 1. The extreme points of Nep(m, n, α, β) are the functions fp(z) =zp and

(6) fj(z) = zp+ 2(1−α)²j

Ψp(m, n, j, α, β)zj (j =p+ 1, p+ 2, ... ; j|= 1).

5 Integral means inequalities

Definition 1. (Subordination Principle) For two functions f and g, analytic in U, we say that the function f(z) is subordinate to g(z) in U, and write

f(z)≺g(z) (z U),

if there exists a Schwarz function w(z), analytic in U with

w(0) = 0 and |w(z)|<1 , such that

f(z) = g(w(z)) (z U).

In particular, if the function g is univalent inU, the above subordination is equivalent to

f(0) = g(0) and f(U)⊂g(U).

In 1925, Littlewood [6] proved the following subordination theorem. (See also Duren [7])

(8)

Theorem 4. (Littlewood [6]) If f and g are analytic in U with f ≺g, then for µ >0 and z =re(0< r <1)

Z

0

|f(z)|µ 5 Z

0

|g(z)|µdθ.

We will make use of Theorem 5 to prove

Theorem 5. Letf(z)∈Nep(m, n, α, β)and supposed thatfj(z)is defined by (6). If there exists an analytic function w(z) given by

{w(z)}j−p = Ψp(m, n, j, α, β) 2(1−α)²j

X

j=p+1

ajzj−p, then for z =re and 0< r <1,

Z

0

¯¯f(re

¯µ Z

0

¯¯fj(re

¯µ (µ >0).

Proof We must show that Z

0

¯¯

¯¯

¯1 + X

j=p+1

ajzj−p

¯¯

¯¯

¯

µ

Z

0

¯¯

¯¯1 + 2(1−α)²j

Ψp(m, n, j, α, β)zj−p

¯¯

¯¯

µ

dθ.

By applying Littlewood’s subordination theorem, it would suffice to show that

1 + X

j=p+1

ajzj−p 1 + 2(1−α)²j

Ψp(m, n, j, α, β)zj−p. By setting

1 + X

j=p+1

ajzj−p = 1 + 2(1−α)²j

Ψp(m, n, j, α, β){w(z)}j−p we find that

{w(z)}j−p = Ψp(m, n, j, α, β) 2(1−α)²j

X

j=p+1

ajzj−p

(9)

which readily yields w(0) = 0.

Furthermore, using (3), we obtain

|{w(z)}|j−p =

¯¯

¯¯

¯

Ψp(m, n, j, α, β) 2(1−α)²j

X

j=p+1

ajzj−p

¯¯

¯¯

¯

Ψp(m, n, j, α, β) 2(1−α)|²j|

X

j=p+1

|aj| |z|j−p

≤ |z|<1.

This completes the proof of the theorem.

References

[1] G.S. Salagean, Subclasses of univalent functions, Lecture Notes in Math. Springer-Verlag 1013,(1983), 362-372.

[2] H. Silverman, Univalent functions with negative coefficients, Proc.

Amer. Math. Soc.51(1) (1975), 109-116.

[3] S.Shams, S.R.Kulkarni, J.M.Jahangiri, Classes of uniformly starlike and convex functions, International Journal of Mathematics and Math- ematical Sciences, Vol. 2004 (2004), Issue 55, 2959-2961.

[4] S.S.Eker, S.Owa, New applications of classes of analytic functions in- volving Salagean operator, International Symposium on Complex Func- tion Theory and Applications, Brasov, Romania 1-5 September 2006 [5] S.S.Eker, S.Owa, Certain Classes Of Analytic Functions Involving

Salagean Operator, J. Inequal. Pure Appl. Math. (in course of pub- lication).

(10)

[6] J. E. Littlewood,On inequalities in the theory of functions, Proc. Lon- don Math. Soc.23(1925), 481-519.

[7] P. L. Duren, Univalent Functions, Springer-Verlag, New York ,1983.

Department of Mathematics Faculty of Science and Letters Dicle University

Diyarbakır, Turkey

Email address: [email protected] and [email protected]

参照

関連したドキュメント

Obradovi´c, Starlikeness and certain class of rational functions, Math.. Radomir, A class of univalent

In this paper we derive subordination results for certain subclass of analytic functions defined by using Salagean operator.. 2000 Mathematics Subject

Key words: Multivalently analytic functions, Hadamard product (or convolution), Differential subordination, Hypergeometric functions, Fractional Differintegral operator,

In this paper, we introduce a new class of multivalent func- tions defined by Dziok-Srivastava operator to study some of the interesting properties like coefficient

In this paper we derive several subordination results for certain new classes of analytic functions defined by using Salagean operator.. (1.2) Definition 1 (Hadamard Product

Key words: Analytic function; Multivalent function; Linear operator; Convex univalent func- tion; Hadamard product (or convolution); Subordination; Integral operator.... Analytic

Abstract: By using the Euler-Maclaurin’s summation formula and the weight coefficient, a pair of new inequalities is given, which is a decomposition of Hilbert’s inequal- ity..

Finally, using the geometric mean in the Kubo-Ando theory we shall give a reverse Hrlder’s type operator inequality for noncommutative operators.. Keywords: Hrlder’s