The Upper Bound of a Reserve
HSIder’s Type Operator Inequality and its Applications
MASARUTOMINAGA
Departmentof Mathematical Science, Graduate Schoolof Science and Technology, Niigata University, Niigata 950-2181, Japan
(Received12January2000;Infinal form 15March2000)
Inourpreviouspaper,weobtained areverseHrlder’stype inequalitywhichgivesanupper boundofthedifference:
(
ak)l/P(
bqk)1/q-2Z
akbkwith aparameter 2>0,forn-tuplesa (al,... ,an)and b (bl,...bn)of positive numbers and for p>1,q> satisfying 1/p+1/q 1. In this paper for commutative positive operatorsA andBon aHilbertspaceHand a unit vector x EH, wegiveanupper bound ofthedifference
(APx,x)lip(Oqxx)l/q 2(ABx, x).
As applications, considering special cases, we induce some difference and ratio operator inequalities. Finally, using the geometric mean inthe Kubo-Andotheory we shall givea reverseHrlder’s type operator inequality fornoncommutativeoperators.
Keywords: Hrlder’s inequality; Difference inequality; Ratio inequality; Reverse Hrlder’s inequality;Geometricmean
Corresponding author.E-mail:[email protected]
ISSN 1025-5834print;ISSN 1029-242X. (C)2002Taylor&FrancisLtd DOI: 10.1080/1025583021000022423
1 INTRODUCTION
Thispaperis acontinuation ofourpaper[7]. Inthispaper,we assume that real numbersp> 1,q > satisfy lip
+
1/q 1.The H61der inequality is one ofthe most important inequalities in analysis: Ifa (al
an)
and b(bl
bn) are n-mples ofnon- negative numbers, then(E a)I/P(E bqk)
llq>-- E akbk.
In [7],weintroduced acomplementary inequalityderived from(1), i.e.,
(E a/)I/P(E bqk)
l/q )E
a,bk <_ nMM2Fo(2) for2 > 0undercertain conditions (see Theorem A and F0(2) is definedthere). We considerthe operatorversionofthis inequality, i.e.,wegive an estimation ofthe followingdifference"
(APx,
x1/p(Bqx,
x l/q 2(ABx, x)(2)
forcommuting positive operatorsA andBon a HilbertspaceHsatisfy- ing
0 <
m
<A <M, 0 < m2 _<B <M2, ml <MI
andm2 <M2 (3)
andfor a unit vector x6H. WeshowMiMz.Fo(2).asthe upper bound of (2), i.e.,(APx, x)I/p(Bqx,
x)1/q2(ABx,
x) <MMzFo(2), (4)
which we call a reverse H61der’s type operator inequality. We derive some other inequalities which are given for p q 2 and B I (I is theidentity operator)in(4).Consideringthe cases 2 and2satis- fying F0(2) 0, we obtain difference and ratio inequalities which are operator versionsof known inequalities. Furthermorewe obtainanon- commutative version of a reverse H61der’s type operator inequality,
using thes-geometricmean
AsB
introduced in theKubo-Ando theory [8], which is definedbyAIsB A/Z(A-/ZBA-/)SA
/2(0
< s <1)
forinvertible positiveoperators.4 andB.2
AN
OPERATORVERSION
OFA REVERSE HLDER’S TYPE
INEQUALITY
Firstwedefineseveral notationsneeded later. Let and
fl
be realnum-bers with 0< < and 0 < < 1, and denote several constants as follows"
g,r r gy,...r goqpl/pgfl,ql/q
’1- Ky,
r])r-I
Kpl/pql/q
[,:=
Kl/ql/p ( , fl,
r p,q).Inourpaper [7, Lemma2.3],we pointedoutthat forany positive real number 2, theequation
(1
e)(2
Kz1/q) (1 )(/
Kz-1/p)
has aunique positivesolutionz zx. We definedtheconstant
c
byc,
(1 -00(2- X’r,1/q) (-- (1 fl)(2- KT,;1/P)). (5)
Furthermore in [7, Theorem 3.5], we showed the following theorem whichgivesanupper boundof the difference in H61der’sinequality(1):
THEOREMA Leta
(al,..., an)
and b(bl,..., bn)
ben-tuplesof
positive numbers satisfying 0
<
ml<_
ate<_ M,
0<
m2<_ bk <_ M2 (k
1,2,n),
ml< ml
and m2< M2.
Put o ml/M1
andfl m2/m2.
Thenfor
any>
0(Y ak)l/P(Y bqk)
l/q-/Z akbk
<_nM1M2Fo(2), (6)
where
Fo(2)
F0(2;, fl,
p) istheconstantdefined
byFo()O
K,p + Kfl,--
-1 21)2
oPfl
q(1 P)(I
flq)C2flq
if
O <2 <min{ K’p Kfl’q
qf
Kfl’----q(
m n{ K
Pp Kqflq}
<2<K
<2<K
if
K<_2 <_K (7)(=maxl(’P’(ll’q})p
qfl(1 2) /f
max <P q
Since K< <
,
we remark for 2Fo(1)
K--,p
-I-fl,
q (1 ,)(1 flq) cl, and the following inequality [6, Theorem2.2] is obtained(, a
) /P()-. bq
) /qY
akbk
<nMi
M2Fo(1).(8)
Moreovertheequation
Fo(2)
0hasaunique solution[7,Theorem3.6 and Lermna5.1I io "-’pl/pql/q(fl flq)l/P(o Pflq pfl)l/q
(E[g, g]),(9)
and the following Gheorghiu inequality [4]
(or
a reverse H61der’s in- equality [10, p.685]) is obtained:(- a/k)I/P(’ bqk)
1/q <0 akbk. (10)
Nowwe giveareverseH61der’s type operator inequality, that is, anop- erator version of(6).
We also consider the special cases of2 1 and 220.
THEOREM 1 Let
A
andBbe two commuting positive operatorson H satisfying(3). Put ml/MI, fl m2/M2.
Thenfor
any2>
0andanyunitvectorx EH
(APx, x)1/p(Bqx, x)1/q 2(ABx,
x) <M1M2Fo(2), (11)
where
Fo(2)
is the constantdefined
by(7).Furthermore thefollowing
facts
hold:(i)
If
2 1, then(APx, X)lip
(Bqx x)1/q (ABx, x)<
M1M2 {K_,p + /,q
1(1
1-Pflq0)(1
q) Cl} (12)
(ii) The equation
Fo(2)
0 hasa unique solution 220(E
[K,K]) defined
by(9) andthe following inequality holds(APx,x)1/p(Bqx,x)1/q .<
’0
(ABx, x) (13)Proof
Leta andbben-tupleswiththe same conditions of TheoremA and let w--(wl,..., Wn)
be an n-tuple of nonnegative numbers withw
=1
wk. Thenbythe samemethodas [6,Theorem4.1],wehavetheweighted version ofTheoremA, that is, forany 2
>
0(" Wktlt)I/P(., Wkbqk)
I/q-" Z Wkakbk <--wmlm2Fo(/]’)
(14) Next let p be a positive measure on the rectangle X--[m
l,MI]
[m2,M2]
withIt(X)
1, and letL"(X)(r
> 1)be the set of measurable functionsf
such thatIll"
are integrable on X. Supposethat j’ U’(X) and g Lq(X) satisfying 0 < ml <
f
<M
and0 < m2 < g <
M2.
Furthermore let X1,X2 Xn
be a decomposition ofX and letxkX.(k
1,2,...,n). Then from(14) we obtain{
f(xky,p(Xk)}i/z,yg(xk)ql(Xk)] l/q_) y
f(x.)g(xk)p(Xk)<_MM:Fo()O.
Taking thelimitof the decomposition,we obtain
(IX fPdll)
lip(Ixgqdlt)
l/q 2L
fgdp <MMzFo(2). (15)
Now since A and B are commuting, there exist commuting spectral families EA(’) and EB(.) corresponding to A and B such that for any polynomialp(A, B) (or a uniformlimit ofpolynomials) inA and
B,
(p(A, B)x, x) p(s, t)d (EA
(s)E
B(t)x, x} for x 6H, [13,p.287].Letdpd(EA(s)EO(t)x,x) dllE(s)EO(t)xll -.
Then from(15) we have
(APx,
x)/p(Bqx,x)I/q
2(ABx, x)(I Ix sPdP)
/p(I L tqd#)1/q
2.I Ix
stdp<M,M2Fo(2)
and hence wehavethe desiredinequality (l1).
Furthermoreweeasilyhave(12) and
(13),
putting in(11),respectively.Weremark that the differenceinequality(12)wasobtained in[6,The- orem4.3]asanoperatorversion of(8),and that the ratioinequality(13) was obtained in
[2,
Theorem4] as anoperatorversionof Gheorghiu’s inequality(10).
3
FURTHER APPLICATIONS
TO OPERATOR INEQUALITIES Inthis section asapplicationsofTheorem 1,wededuce threecorollaries whichgive special inequalitiesasthe cases ofp q 2orfl
1. Theinequalities for 2 correspond with difference inequalities given in [6], and those for the solution 2 of
F0(2)=
0 correspond with ratio inequalities which are operator versions of known numerical inequalities.If
fi
-+ inTheorem 1, thenwecaneasilyseethatK(Ko,p/p)l/P
and
-- (K,p/pp-1)/p.
Sowe obtain the following corollary:COROLLARY 2 LetA be apositive operatoronH satisfying
(3).
Putm/M.
Thenfor
any2>
0 and any unitvectorx H(APx,
x)/p 2(Ax,x) <_MF (2), (16)
where
F1 (2)
istheconstantdefined
by1-2
(2)
/f0<2< K,p
P
if K’p
p <2<pap-1 K=,p
/f
<2.Furthermore thefollowing
facts
hold:(i)
,/)"
2 1, then(APx,
x)1/p (Ax, x) <M1
p(1
00 (17)
(ii) The equation
F (2)
0 has a unique solution2=21=
pl/pqllq(1 z)l/P(ot op)l/q " ’pzp-l’
andthe following inequality holds
(A
nx,
x)/p <2
(Ax, x). (18)Proof
LetM2
and m2fl
--+ in Theorem 1. Then we obtain(16) by using the same methodas in [7, Theorem4.1]. Moreover(17)
isensuredby
K,p K,p
< < and (18) is obtainedby an elementary
p
poe ’-’
computation, using the factthat aunique solution2
2
of the equa-tion
Fl (2)
0 satisfiesK,p .K,p
p
Theinequality(17)wasgivenin
[6]
and the inequality(18)wasgiven in [2], [3], [9], [11]. Theconstant2
coincides with thep-th root ofthe constant definedbyKy
Fan [1 ], orFuruta [3].Nextwetake p q 2 inTheorem 1:
COROLLARY3 LetA andBbetwocommuting positive operatorsonH satisfying (3). Put
t-min{ml/Ml,mz/Mz}, fl-- max{ml/M, m2/M2},
7(1 + cz)I/2(1 + fl)i/2/2
and7//2fl 1/2.
Writec
theconstant
of(5)
with respecttop q 2. Thenfor
any 2>
0and anyunitvectorxEH
(AZx,
x)I/Z(BZx, x)1/z
2(ABx, x) < MMzF2(2),where
F2(2)
is the constantdefined
byF()
1-2
/f0<2<
1+2
<2<
422 1+’
2/f
1+
2
(1-fl)2
_c,
{ 1-2fl2 }
2(1
+
)(1+ fl)
(12)(1 f12)
(1+ ’422 )1+, f12 9
< 2 < 1+2(1-2)
1+2 <2"
Furthermore the following
facts
hold:(i)
If
2 1, then(1 fl)2 (A2x,
x)/2(B-x,
x)/2 (ABx, x) <_M M2
2(1 + )(1 + fl)" (19)
(ii) The equation
F2(2)=
0 hasa uniquesolution+ fl ( [7, 9]),
2
22
21/2fll/2
and thefollowing inequality holds
(A2x,
x)l/2(B2x,
x)1/2 _<22
(ABx,x).(20) Proof
Letp-q- 2 in Theorem 1. Then we obtain the desired in- equalities by using thesame methodas [7, Theorem4.3].The inequality
(19)
was givenin [6]. Theinequality (20) isa commu- tative operatorversion of theP61ya-Szeg6 inequality[12], [10, p.684]:_, a Z b
<(M, M2 +
m,m2)
24M1Mz
m m2(-
akbk ) 2,
orGreub-W. Rheinboldt inequality[5]:
_,pka2 -pkb
< (M,Mz +
m,m2)24M M2
m m2(Y
p,a,b,) 2.
with aweightpk > 0(k 1,2 n) with pk 1.
Inparticular, weobtain the following corollary, putting p q 2 in Corollary 2 or
fl
in Corollary3"COROLLARY 4 LetA be apositive operator on Hsatis.ing (3). Put
m/Ml.
Thenfor
any 2>
0 andanyunit vectorx E H(42X, X)1/2
,,(AX,X)MIF3(2),
where
F3(2)
isthe constantdefined
byF3()0
1-2
/f0<2<
1+2
l+oe oe 1+o, l+z
2
/f
<2<42
+
2 2(1-2) /f
l+z2 <2.
Furthermore the Jbllowing
facts
hold:(i)
If
2 1, then(A2x,
x}1/2 (Ax,x}<
4(M(M1+ m!)2
ml)(21)
(ii) Theequation F3(2) 0has aunique solution
andthefollowing inequality hoMs
{A2x,
x}1/2.< 23
(Ax, x}.(22)
The inequalities (21) and
(22)
are well-known inequalities(cf.
[6]) related tothe following celebratedKantorovich inequality:(Ax,x)
(A-x,
x) <_(m
-I-m)
2 4mMAs anapplicationofTheorem 1 (orCorollary 2), we shallshow some operator inequalities without commutativity assumption. In [8], E Kubo and T. Andointroducedthe s-geometric mean
AtlsB
definedbyAsB A/2(A-/2BA-/2)*A
/2(0
< s<_1)
for positiveinvertibleoperatorsAandB. Wenotethat
Bql/pA
p ABif A andB commute.Using the s-geometric mean, we have anoncommutative version of Theorem 1"
THEOREM 5 LetA andB be two positive invertible operators on H satisfying (3). Put
- ml/M1, fl- m2/M2 y-ofl
q-1 M1M- mlm-I
and
gT (_ gT,p
Pflqeq-1"
Thenfor
any 2>
0 andanyunitvectorxEH(APx,
x)l/p(Bqx,
x)l/q2(Bql/pAPx,
x) <_M1M2
q-1 FlI()’ (23)
where
F(2)
istheconstantdefined
byF,()
1{ 1--TP ]
q-1 7--p7(1 2)
/fO <,
<K
p
/f K,
< 2 <K,
p
pyp-1
if p, K,
<,.
Proof
In Corollary 2,F1 (2)
is determinedby 2, (and p), and hencewe may write
F (2) F (2, ).
IfC is a positive operator such that0 < m < C<
M,
thenfrom(16)we have for any 2 > 0and anyvectorxEH
(CPx,
x)l/p(x,
x)l/q l],(Cx, x)MFI(,, 3?o)(X,
X) (24) holds for 70 m/M.(CorrespondinglywereplacetheconstantK,p
inCor--0.)
Now, wereplace C and xby(B-q/2APB-q/2)I/P
ollary2 by
K.o
-70
and Bq/2xwithx having unit norm in(24), respectively. Thensince 0<
m (B-q/2APB-q/2)I/P
<M1
q-IM-i
< m2wehave
(APx,
x)I/p(Bqx x)1/q2(Bq/2(B-q/2APB-q/2)l/pBq/2x,
x)<
M! F(2,
y)(Bqx, x)mq2_-f
<
MIM2 El (2 ) q-1
for
, M flq-
PuttingF(2)--F(2, ),),
we obtain the desired inequality(23).If we put 2 in (23), then we have the following inequality [6, Theorem4.5] whichisthe noncommutativeversionof(12):
(AI’x, x)1/p
(Bqxx)1/q (Bql/pAPx
x)(25) By
an elementary computation we can see thatF(2)
0 has a un-ique solution 2
20
E defined by (9). Sowe have the p p7p-!following result [2, Theorem 4]"
COROLLARY 6 Let
A
andBbetwopositive invertible operators onH satisfying(3).
Putm /M
andfl mz/m2.
Thenfor
anyunit vectorxH
(APx, x)lip
(Bqx x)1/q< ,o(Bql/pAPx,
x),where2o ( [
r,pTp-Kr ’])
isthecnstantdefinedby(9)(26)
Acknowledgment
Theauthorwouldlike toexpress special thankstoProfessor SaichiIzu- mino for various commentsand many important suggestions.
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