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(CO)HOMOLOGY OF TRIASSOCIATIVE ALGEBRAS DONALD YAU Received 24 October 2005; Revised 28 March 2006; Accepted 6 April 2006

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DONALD YAU

Received 24 October 2005; Revised 28 March 2006; Accepted 6 April 2006

We study homology and cohomology of triassociative algebras with nontrivial coeffi- cients. The cohomology theory is applied to study algebraic deformations of triassociative algebras.

Copyright © 2006 Hindawi Publishing Corporation. All rights reserved.

1. Introduction

Triassociative algebras, introduced by Loday and Ronco [8], are analogues of associative algebras in which there are three binary operations, satisfying 11 relations. These algebras are closely related to some very interesting combinatorial objects. In fact, the operadTrias for triassociative algebras is modeled by the standard simplices. This operad is Koszul, in the sense of Ginzburg and Kapranov [6]. Its Koszul dual operadTriDendis modeled by the Stasheffpolytopes [11,12], or equivalently, planar trees. The algebras for the latter operad are called tridendriform algebras, which have three binary operations whose sum is an associative operation.

The purpose of this paper is to advance the study of triassociative algebras in the fol- lowing ways: (1) algebraic foundation: when studying (co)homology, the first task is to figure out the correct coefficients. We introduce homology and cohomology with non- trivial coefficients for triassociative algebras. In fact, Loday and Ronco [8] already defined homology with trivial coefficients for these algebras. We will build upon their construc- tion. (2) Deformation: once (co)homology is in place, we use it to study algebraic de- formations of triassociative algebras, following the pattern established by Gerstenhaber [5].

We should point out that deformations of dialgebras [7], the analogues of triasso- ciative algebras with only two binary operations, have been studied by Majumdar and Mukherjee [9]. One difference between triassociative algebras and dialgebras is the co- boundary operator in cohomology. Specifically, in both cases, the coboundary involves certain productsψj. The definition of this product is more delicate in the triassociative al- gebra case than in the dialgebra case. This is due to the fact that planar trees, which model

Hindawi Publishing Corporation

International Journal of Mathematics and Mathematical Sciences Volume 2006, Article ID 69248, Pages1–21

DOI10.1155/IJMMS/2006/69248

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triassociative algebra cohomology, are more complicated than planar binary trees, which model dialgebra cohomology. A more fundamental difference is that the sets of planar trees form a simplicial set, whereas the sets of binary trees form only an almost simplicial set [7, Section 3.10]. This is important, since the author intends to adapt the algebraic works in the present paper to study topological triassociative (co)homology, in analogy with topological Hochschild (co)homology (see, e.g., [2,3,10]). Such objects should be defined as the geometric realization of a certain simplicial spectrum (or theTotof a cer- tain cosimplicial spectrum), modeled after the algebraic (co)simplicial object that defines (co)homology.

In the classical case of an associative algebraR, the coefficients in Hochschild homol- ogy and cohomology are the same, namely, theR-representations. In contrast, in the case of triassociative algebras (and also dialgebras), the coefficients in homology and coho- mology are not the same. The natural coefficient for triassociative cohomology is a repre- sentation, which can be defined using the 11 triassociative algebra axioms. This leads to an expected algebraic deformation theory. To define triassociative homology with coeffi- cients, we will construct the universal enveloping algebra (UA), which is a unital associa- tive algebra of a triassociative algebraA. A leftUA-module is exactly anA-representation.

We then define anA-corepresentation to be a rightUA-module. These rightUA-modules are the coefficients in triassociative homology. In the classical Hochschild theory, the uni- versal enveloping algebra isRe=RRop.

We remark that all of the results in this paper can be reproduced for tridendriform and tricubical algebras in [8] with minimal modifications.

Organization. The next section is devoted to defining triassociative algebra cohomol- ogy with nontrivial coefficients, in which we begin with a brief discussion of represen- tations over a triassociative algebra. The construction of triassociative algebra cohomol- ogy requires a discussion of planar trees. We observe that the sets of planar trees form a simplicial set (Proposition 2.1). After that we define the cochain complexCTrias(A,M) for a triassociative algebraAwith coefficients in anA-representationM (Theorem 2.2) and give descriptions of the low-dimensional cohomology modulesHTrias for∗ ≤2. It is also shown thatHTriasn (A,) is trivial for alln2 whenAis a free triassociative algebra (Theorem 2.3).

InSection 3, we construct triassociative algebra homology with nontrivial coefficients by using the universal enveloping algebra (UA) of a triassociative algebraA. TheA-repre- sentations are identified with the leftUA-modules (Proposition 3.1). We then compute the associated graded algebra ofUAunder the length filtration (Theorem 3.2). This leads to a triassociative version of the Poincar´e-Birkhoff-Witt theorem (Corollary 3.3). We then use the rightUA-modules as the coefficients for triassociative algebra homology, analo- gous to the dialgebra case [4]. To show that the purported homology complex is actually a chain complex, we relate it to the cotangent complex (Proposition 3.4), which can be used to define both the homology and the cohomology complexes. The cotangent complex is the analogue of the bar complex in Hochschild homology. When the coefficient module is taken to be the ground field (i.e., trivial coefficients), our triassociative homology agrees with the one constructed in Loday and Ronco [8]. That section ends with descriptions of H0TriasandH1Trias.

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Section 4is devoted to studying algebraic deformations of triassociative algebras. We define algebraic deformations and their infinitesimals for a triassociative algebraA. It is observed that an infinitesimal is always a 2-cocycle inC2Trias(A,A) whose cohomology class is determined by the equivalence class of the deformation (Theorem 4.1). A triassociative algebraAis called rigid if every deformation ofAis equivalent to the trivial deformation.

It is observed that the cohomology moduleHTrias2 (A,A) can be thought of as the obstruc- tion to the rigidity ofA. Namely, we observe thatAis rigid, provided that the module HTrias2 (A,A) is trivial (Corollary 4.3). As examples, free triassociative algebras are rigid (Corollary 4.4). Finally, we identify the obstructions to extend 2-cocycles inCTrias2 (A,A) to deformations. Given a 2-cocycle, there is a sequence of obstruction classes inC3Trias(A,A), which are shown to be 3-cocycles (Lemma 4.5). The simultaneous vanishing of their co- homology classes is equivalent to the existence of a deformation whose infinitesimal is the given 2-cocycle (Theorem 4.6). In particular, these obstructions always vanish if the cohomology moduleHTrias3 (A,A) is trivial (Corollary 4.7). We remark that the work of Balavoine [1] gives another approach to study deformations of triassociative algebras.

2. Cohomology of triassociative algebras

For the rest of this paper, we work over a fixed ground fieldK. Tensor products are taken overK. We begin by recalling some relevant definitions about triassociative algebras and planar trees from [8].

2.1. Triassociative algebras and representations. A triassociative algebra is a vector space Athat comes equipped with three binary operations,(left),(right), and(middle), satisfying the following 11 triassociative axioms for allx,y,zA:

(xy)z=x(yz), (2.1a)

(xy)z=x(yz), (2.1b)

(xy)z=x(yz), (2.1c)

(xy)z=x(yz), (2.1d)

(xy)z=x(yz), (2.1e)

(xy)z=x(yz), (2.1f)

(xy)z=x(yz), (2.1g)

(xy)z=x(yz), (2.1h)

(xy)z=x(yz), (2.1i)

(xy)z=x(yz), (2.1j)

(xy)z=x(yz). (2.1k)

Note that the first 5 axioms state that (A,,) is a dialgebra [7], and they do not involve the middle product. From now on,A will always denote an arbitrary triassociative algebra, unless stated otherwise.

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A morphism of triassociative algebras is a vector space map that respects the three products.

AnA-representation is a vector spaceMtogether with (i) 3 left operations,,:A MM, (ii) 3 right operations ,,:MAM satisfying (2.1a)–(2.1k) whenever exactly one ofx, y,z is fromMand the other two are fromA. Thus, there are 33 total axioms. From now on,Mwill always denote an arbitraryA-representation, unless stated otherwise.

For example, ifϕ:ABis a morphism of triassociative algebras, thenBbecomes an A-representation viaϕ, namely,xb=ϕ(x)bandbx=bϕ(x) forxA,bB, and∈ {,,⊥}. In particular,Ais naturally anA-representation via the identity map.

In order to construct triassociative algebra cohomology, we also need to use planar trees.

2.2. Planar trees. For integersn0, letTndenote the set of planar trees withn+ 1 leaves and one root in which each internal vertex has valence at least 2. We will call them trees from now on. The first four setsTnare listed below:

T0= , T1=

, T2=

, , ,

T3=

, , , , , , , , , , .

(2.2)

Trees inTnare said to have degreen, denoted by|ψ| =nforψTn. Then+ 1 leaves of a tree inTnare labeled{0, 1,. . .,n}from left to right.

A leaf is said to be left oriented (resp., right oriented) if it is the leftmost (resp., right- most) leaf of the vertex underneath it. Leaves that are neither left nor right oriented are called middle leaves. For example, in the tree , leaves 0 and 2 are left oriented, while leaf 3 is right oriented. Leaf 1 is a middle leaf.

Given treesψ0,. . .,ψk, one can form a new tree by the operation of grafting. Namely, the grafting of thesek+ 1 trees is the treeψ0∨ ··· ∨ψkobtained by arrangingψ0,. . .,ψk

from left to right and joining thek+ 1 roots to form a new (lowest) internal vertex, which is connected to a new root. The degree ofψ0∨ ··· ∨ψkis

ψ0+ 1+···+ψk+ 11=k+

k i=0

ψi. (2.3)

Conversely, every treeψcan be written uniquely as the grafting ofk+ 1 trees,ψ0∨ ··· ∨ ψk, where the valence of the lowest internal vertex ofψisk+ 1.

Before defining cohomology, we make the following observation, which is not used in the rest of the paper but maybe useful in future studies of triassociative cohomology.

For 0in+ 1, define a function

di:Tn+1−→Tn, (2.4)

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which sends a treeψTn+1to the treediψTnobtained fromψby deleting theith leaf.

For 0in, define another function

si:Tn−→Tn+1 (2.5)

as follows: forψTn,siψTn+1is the tree obtained fromψby adding a new leaf to the internal vertex connecting to leafi, and this new leaf is placed immediately to the left of the original leafi. For example, ifψ= , thens0(ψ)= ands1(ψ)=s2(ψ)= . Proposition 2.1. The sets{Tn}n0form a simplicial set with face mapsdiand degeneracy mapssi.

Proof. Recall that the simplicial relations are didj=dj1di ifi < j,

disj=

sj1di ifi < j, Id ifi=j,j+ 1, sjdi1 ifi > j+ 1, sisj=sj+1si ifij.

(2.6)

All of them are immediate from the definitions.

2.3. Cohomology. For integersn0, define the module ofn-cochains ofAwith coeffi- cients inMto be

CTriasn (A,M) :=HomK

KTnAn,M. (2.7) To define the coboundary maps, we need the following operations. For 0in+ 1, define a function

i:Tn+1−→ {,,⊥} (2.8)

according to the following rules. Letψ be a tree inTn+1, which is written uniquely as ψ=ψ0∨ ··· ∨ψkin which the valence of the lowest internal vertex ofψ isk+ 1. Also, writeψi fori(ψ). Thenψ0 is given by

ψ0 =

ifψ0=0,k=1, ifψ0>0,

ifψ0=0,k >1.

(2.9)

For 1in,ψi is given by

ψi =

if theith leaf ofψis left oriented, if theith leaf ofψis right oriented,

if theith leaf ofψis a middle leaf.

(2.10)

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Finally,ψn+1is given by

ψn+1=

ifψk>0, ifk=1,ψ1=0,

ifk >1,ψk=0.

(2.11)

For example, for the 11 treesψinT3(from left to right), we have

ψ0 =,,,,,,,,,,,

ψn+1=,,,,,,,,,,. (2.12) Now define the map

δn:CTriasn (A,M)−→CTriasn+1(A,M) (2.13) to be the alternating sum

δn=

n+1 i=0

(1)iδin, (2.14)

where

δinfψ;a1,. . .,an+1=

a1ψ0 fd0ψ;a2,. . .,an+1 ifi=0, fdiψ;a1,. . .,aiψi ai+1,. . .,an

if 1in, fdn+1ψ;a1,. . .,an

ψn+1an+1 ifi=n+ 1,

(2.15)

for f CnTrias(A,M),ψTn+1, anda1,. . .,an+1A.

Theorem 2.2. The mapsδinsatisfy the cosimplicial identities,

δn+1j δin=δin+1δnj1, (2.16) for 0i < jn+ 2. In particular, (CTrias(A,M),δ) is a cochain complex.

Proof. First, note that for 1in, the mapδni is dual to the map di:Cn+1Trias(A)=KTn+1

An+1−→KTn

An=CnTrias(A) (2.17) in Loday and Ronco [8], that is,δni =Hom(di,M). It is shown there that thesedisatisfy the simplicial identities. Therefore, to prove the cosimplicial identities, it suffices to consider the following three cases: (i)i=0, j=n+ 2, (ii)i=0< j < n+ 2, and (iii) 0< i < j= n+ 2.

Consider case (i). Suppose thatψTn+2,a1,. . .,an+2A, and f CnTrias(A,M). Let αbe the element (ψ;a1,. . .,an+2) inK[Tn+2]An+2. Writeψ asψ0∨ ··· ∨ψkuniquely

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withk+ 1 being the valence of the lowest internal vertex ofψ. We have δn+2n+1δ0nf(α)=

δ0nfdn+2ψ;a1,. . .,an+1

ψn+2an+2

=

a1d0n+2ψ fd0dn+2ψ;a2,. . .,an+1

ψn+2an+2

=

a1d0n+2ψyψn+2an+2,

(2.18)

wherey= f(dn+1d0ψ;a2,. . .,an+1). Here we used the simplicial identityd0dn+2=dn+1d0. On the other hand, we have

δ0n+1δn+1n f(α)=a1ψ0

δnn+1fd0ψ;a2,. . .,an+2

=a1ψ0

ydn+10ψan+2

. (2.19)

In order to show that

a1d0n+2ψ yψn+2an+2=a1ψ0

ydn+10ψan+2

, (2.20)

we need to consider 7 different cases.

(1) Ifk=1 and|ψ0| =0, thenψ0 == ◦d0n+2ψ. In this case, it follows from the triasso- ciative algebra axioms (2.1a), (2.1b), and (2.1f) that

a1yan+2=a1

yan+2 (2.21)

regardless of what,∈ {,,⊥}are.

(2) If k=1 and|ψ1| =0, thenψn+2== ◦dn+10ψ. It then follows from axioms (2.1d), (2.1e), and (2.1j) that

a1yan+2=a1

yan+2 (2.22)

regardless of what,∈ {,,⊥}are.

(3) Fork1, if both|ψ0|and|ψk|are positive, thend0n+2ψ== ◦ψ0 andψn+2==

dn+10ψ. Therefore, (2.20) holds by axiom (2.1c).

(4) Ifk=2 and|ψ0| =0= |ψ2|, thend0n+2ψ=,ψn+2= ⊥,ψ0 = ⊥, anddn+10ψ =. It follows from axiom (2.1h) that (2.20) holds.

(5) Ifk >2 and|ψ0| =0= |ψk|, thend0n+2ψ= ◦ψn+2= ◦ψ0 = ◦dn+10ψ= ⊥. Thus, (2.20) fol- lows from axiom (2.1k).

(6) Ifk2,|ψ0| =0, and|ψk|>0, thend0n+2ψ = ⊥ = ◦ψ0 andψn+2== ◦dn+10ψ. There- fore, it follows from axiom (2.1g) that (2.20) holds.

(7) Ifk2,|ψ0|>0, and|ψk| =0, thend0n+2ψ == ◦ψ0 andψn+2= ⊥ = ◦dn+10ψ. There- fore, (2.20) follows from axiom (2.1i).

Therefore, the cosimplicial identity holds in the casei=0, j=n+ 2.

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Next, we consider case (ii), wherei=0,j=1,. . .,n+ 1. We have δn+1j δ0nf(α)=

δ0nfdjψ;a1,. . .,ajψj aj+1,. . .,an+2

=

a1ψ1a2

d01ψz ifj=1, a1d0jψx if 2jn+ 1,

(2.23)

where

z= fd0d0ψ;a3,. . .,an+2 ,

x= fdj1d0ψ;a2,. . .,ajψj aj+1,. . .,an+2

. (2.24)

Here we used the simplicial identityd0dj=dj1d0for 0< j. On the other hand, we have δ0n+1δnj1f(α)=a1ψ0

δnj1fd0ψ;a2,. . .,an+2

=

a1ψ0

a2d00ψz ifj=1, a1ψ0w if 2jn+ 1,

(2.25)

where

w=fdj1d0ψ;a2,. . .,ajdj0ψ1aj+1,. . .,an+2

. (2.26)

In the cases 2jn+ 1, we have thatψj = ◦dj0ψ1 andd0jψ= ◦ψ0, and hencea1d0jψx= a1ψ0 w. In the casej=1, we need to show the identity

a1ψ1a2

d01ψz=a1ψ0

a2d00ψz. (2.27) We break it into three cases.

(1) If|ψ0| ≥2, thend01ψ== ◦d00ψ. Therefore, it follows from axioms (2.1d), (2.1e), and (2.1j) that

a1a2

z=a1

a2z (2.28)

regardless of what,∈ {,,⊥}are.

(2) If|ψ0| =1, thenψ1 == ◦ψ0 and

d00ψ= ◦d01ψ=

ifk=1,

ifk2. (2.29)

Therefore, (2.27) holds by axiom (2.1c) ifk=1 and by axiom (2.1i) ifk2.

(3) Now suppose that|ψ0| =0. Ifk=1, thenψ0 == ◦ψ1. It follows that (2.27) holds by axioms (2.1a), (2.1b), and (2.1f). Ifk2, thenψ0 = ⊥. To figure out what the other three operations are, we need to consider two subcases.

(i) If |ψ1|>0, thend00ψ=,ψ1 =, and d01ψ = ⊥. Thus, (2.27) holds by axiom (2.1h).

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(ii) If|ψ1| =0, thenψ1 = ⊥and

d01ψ= ◦d00ψ=

ifk=2,

ifk >2. (2.30)

It follows that (2.27) holds by axiom (2.1g) when k=2 and by axiom (2.1k) whenk >2.

This proves the cosimplicial identities for theδlnwheni=0 and 1jn+ 1. The proof for the case 1in+ 1,j=n+ 2 is similar to the argument that was just given.

In view ofTheorem 2.2, we define thenth cohomology ofAwith coefficients in the rep- resentationMto be

HTriasn (A,M) :=HnCTrias(A,M),δ (2.31) forn0. We describe the first three cohomology modules below.

2.4.HTrias0 andHTrias1 . A linear mapϕ:AMis called a derivation ofAwith values inM if it satisfies the condition

ϕ(ab)=ϕ(a)b+aϕ(b), (2.32) for alla,bAand∗ ∈ {,,⊥}. Denote by Der(A,M) the submodule of HomK(A,M) consisting of all the derivations ofAwith values inM. For an elementmM, define the mapadm:AM, where

adm(a) :=amma (2.33)

for aA. Such a map is called an inner derivation of A with values inM. It follows immediately from the triassociative algebra axioms (2.1) that each mapadm belongs to Der(A,M). Let Inn(A,M) denote the submodule of Der(A,M) consisting of all the inner derivations ofAwith values inM.

IdentifyCTrias0 (A,M) withMandCTrias1 (A,M) with HomK(A,M). Under such identifi- cations, the coboundary mapδ0:MHomK(A,M) is given byδ0(m)=adm. Therefore, the cohomology moduleHTrias0 (A,M), which is the kernel ofδ0, is the following submod- ule ofM:

HTrias0 (A,M)=MA:=

mM|am=maaA. (2.34) The image ofδ0is the module Inn(A,M). Now if f CTrias1 (A,M), then

δ1f(ψ;a,b)=af(b)f(ab) +f(a)b, (2.35) where

∗ =

ifψ= , ifψ= ,

ifψ= .

(2.36)

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In particular, the kernel ofδ1is exactly Der(A,M). Therefore, as in the cases of associative algebras and dialgebras [4], we have

HTrias1 (A,M)=Der(A,M)

Inn(A,M). (2.37)

2.5.HTriasi (A,) whenAis free. It is shown in [8, Theorem 4.1] that the operadTrias for triassociative algebras is Koszul. In other words,HnTrias(A,K)=0 forn2 ifAis a free triassociative algebra. Here HnTrias(A,K) denotes the triassociative homology ofAwith trivial coefficients defined by Loday and Ronco [8]. It agrees with our triassociative ho- mology defined below. The Koszulness ofTriasimplies that free triassociative algebras have trivial higher cohomology modules.

Theorem 2.3. LetAbe a free triassociative algebra. Then

HTriasn (A,M)=0 (2.38)

for alln2 and anyA-representationM.

Proof. The first line in the proof ofTheorem 2.2implies that for any triassociative algebra A,

HTriasn (A,M)=HomK

HnTrias(A,K),M. (2.39)

The theorem now follows from the Koszulness ofTrias.

2.6. Abelian extensions andHTrias2 . Define an abelian triassociative algebra to be a trias- sociative algebraPin which all three products,,,, are equal to 0. In this case, we will just say thatPis abelian. Any vector space becomes an abelian triassociative algebra when equipped with the trivial products. Suppose thatξ: 0Pi Eπ A0 is a short exact sequence of triassociative algebras in whichP is abelian. ThenP has an induced A-representation structure via ap=ei(p) and pa=i(p)efor∗ ∈ {,,⊥}, pP,aA, and any elementeEsuch thatπ(e)=a.

Now consider anA-representationM. By an abelian extension ofAbyM, we mean a short exact sequence

ξ: 0−→M−−→i E−−→π A−→0 (2.40)

of triassociative algebras in whichMis abelian and such that the inducedA-representa- tion structure onM coincides with the original one. An abelian extension is said to be trivial if it splits triassociative algebras. Given another abelian extensionξ= {0M EA0}ofAbyM, we say thatξandξare equivalent if there exists a mapϕ:EE of triassociative algebras making the obvious ladder diagram commutative. (Note that such a mapϕmust be an isomorphism.) Denote by [ξ] the equivalence class of an abelian extensionξand denote by Ext(A,M) the set of equivalence classes of abelian extensions ofAbyM.

Suppose thatξ is an abelian extension ofAbyM as in (2.40). By choosing a vector space splittingσ:AE, one can identify the underlying vector space ofEwithMA.

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As usual, there exists a map

fξ:KT2

A2−→M (2.41)

such that the products inEbecome (m,a)(n,b)=

mb+an+fξ(ψ;a,b),ab (2.42) for∗ ∈ {,,⊥},m,nM, anda,bA. HereψT2is given by

ψ=

if∗ =, if∗ =, if∗ = ⊥.

(2.43)

Note that this is basically (2.36). We will always identify the 3 trees inT2with the products {,,⊥}like this. It is easy to check that the 11 triassociative algebra axioms (2.1) inE are equivalent to fξCTrias2 (A,M) being a 2-cocycle. For instance, we have

(0,x)(0,y)(0,z)= fξ

;x,y,xy(0,z)

= fx

;x,yz+fξ

;xy,z, (xy)z. (2.44) On the other hand, a similar calculation yields

(0,x)

(0,y)(0,z)= xfξ

;y,z+fξ

;x,yz,x(yz). (2.45) These two expressions are equal by axiom (2.1f). By equating the first factors, we obtain

δ2fξ

;x,y,z=0. (2.46)

Similar arguments, using the other 10 triassociative algebra axioms, show that (δ2fξ)(ψ;

x,y,z)=0 for the other 10 treesψT3.

Conversely, suppose thatgCTrias2 (A,M) is a 2-cocycle. Then one can define a trias- sociative algebra structure on the vector spaceMAusing (2.42) withg in place of fξ. Again, the triassociative algebra axioms are verified because of the cocycle condition on g. This yields an abelian extension ofAbyM,

ζg: 0−→M−−→i MA−−→π A−→0 (2.47) in whichiandπ are, respectively, the inclusion into the first factor and the projection onto the second factor.

Theorem 2.4. The above constructions induce well-defined maps Ext(A,M)−→HTrias2 (A,M), [ξ]−→

fξ,

HTrias2 (A,M)−→Ext(A,M), [g]−→

ζg, (2.48)

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that are inverse to each other. In particular, there is a canonical bijectionHTrias2 (A,M)= Ext(A,M).

The proof is basically identical to that of the classical case for associative algebras (see, e.g., [13, pages 311-312] or [4, Sections 2.8-2.9]). Therefore, we omit the details. Note that one only needs to see that the maps are well defined, since they are clearly inverse to each other.

3. Universal enveloping algebra and triassociative homology

The purpose of this section is to construct triassociative algebra homology with nontrivial coefficients. In [8], Loday and Ronco already constructed triassociative homology with trivial coefficients (i.e.,K). Our homology agrees with the one in Loday and Ronco [8]

by taking coefficients inK. In order to obtain the nontrivial coefficients, we first need to discuss the universal enveloping algebra. The dialgebra analogue of the results in this section is worked out in [4].

3.1. Universal enveloping algebra. Fix a triassociative algebraA. We would like to iden- tify theA-representations as the left modules of a certain associative algebra. This requires 6 copies ofA, since 3 copies are needed for the left actions and another 3 for the right ac- tions. Therefore, we make the following definition. For aK-vector spaceV,T(V) denotes the tensor algebra ofV, which is the free unital associativeK-algebra generated byV.

Define the universal enveloping algebra ofAto be the unital associativeK-algebraUA obtained from the tensor algebraTlAαrAαmAβlAβrAβmA) on 6 copies ofAby imposing the following 33 relations fora,bA(3 relations for each of the 11 triassociative axioms (2.1)):

βl(b)·βl(a)(1)=βl(ab)(2)=βl(ab)(3)=βl(ab), βl(b)·αl(a)(4)=αl(a)·βl(b)(5)=αl(a)·βm(b)(6)=αl(a)·βr(b),

αl(ab)(7)=αl(a)·αl(b)(8)=αl(a)·αm(b)(9)=αl(a)·αr(b), βr(ab)(10)= βr(b)·βr(a)(11)= βr(b)·βl(a)(12)= βr(b)·βm(a), αr(a)·βr(b)(13)= βr(b)·αr(a)(14)= βr(b)·αl(a)(15)= βr(b)·αm(a),

αr(a)·αr(b)(16)= αr(ab)(17)= αr(ab)(18)= αr(ab), βl(b)·βr(a)(19)= βr(ab), βl(b)·αr(a)(20)= αr(a)·βl(b),

αl(ab)(21)= αr(a)·αl(b),

βl(b)·βm(a)(22)= βm(ab), βl(b)·αm(a)(23)= αm(a)·βl(b),

(13)

αl(ab)(24)= αm(a)·αl(b),

βm(b)·βl(a)(25)= βm(ab), βm(b)·αl(a)(26)= αm(a)·βr(b), αm(ab)(27)= αm(a)·αr(b),

βm(b)·βr(a)(28)= βr(ab), βm(b)·αr(a)(29)= αr(a)·βm(b), αm(ab)(30)= αr(a)·αm(b),

βm(b)·βm(a)(31)= βm(ab), βm(b)·αm(a)(32)= αm(a)·βm(b), αm(ab)(33)= αm(a)·αm(b).

(3.1) Proposition 3.1. LetMbe aK-vector space. Then anA-representation structure onMis equivalent to a leftUA-module structure onM.

Proof. The correspondence is given by (aA,xM)

αl(a)·x=ax, αr(a)·x=ax, αm(a)·x=ax,

βl(a)·x=xa, βr(a)·x=xa, βm(a)·x=xa. (3.2) Soαandβcorrespond to left and rightA-actions, respectively, and the subscript indi- cates where the product points to. In particular, the conditions (1)–(9) above correspond to axioms (2.1a), (2.1b), and (2.1f). Conditions (10)–(18) correspond to axioms (2.1d), (2.1e), and (2.1j). The other 5 groups of conditions correspond to the remaining 5 axioms

in (2.1).

3.2. Filtration onUA. Each homogeneous element inUAhas a length: elements inK have length 0. The elementsγ(a), whereγ=α,β,∗ =l,r,m, andaA, have length 1.

Inductively, the homogeneous elements inUAof length at mostk+ 1 (k1) are theK- linear combinations of the elementsγ(a)·xandx·γ(a), wherexhas length at most k.

Fork0, consider the following submodule ofUA:

FkUA= {xUA:xhas length k}. (3.3) These submodules form an increasing and exhaustive filtration ofUA, so thatF0UA=K, FkUAFk+1UA, andUA= ∪k0FkUA. Moreover, it is multiplicative, in the sense that (FkUA)·(FlUA)Fk+lUA. Therefore, it makes sense to consider the associated graded algebraGrUA= ⊕k0GrkUA, whereGrkUA=FkUA/Fk1UA. It is clear thatGr0UA= K. The following result identifies the other associated quotients.

参照

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