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Volume 2011, Article ID 840206,10pages doi:10.1155/2011/840206

Research Article

On Shafer and Carlson Inequalities

Chao-Ping Chen,

1

Wing-Sum Cheung,

2

and Wusheng Wang

3

1School of Mathematics and Informatics, Henan Polytechnic University, Jiaozuo City, Henan Province 454003, China

2Department of Mathematics, The University of Hong Kong, Pokfulam Road, Hong Kong

3Department of Mathematics, Hechi University, Yizhou, Guangxi 546300, China

Correspondence should be addressed to Wing-Sum Cheung,[email protected] Received 23 November 2010; Accepted 5 February 2011

Academic Editor: Martin Bohner

Copyrightq2011 Chao-Ping Chen et al. This is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited.

We present a generalized and sharp version of Shafer’s inequality for the inverse tangent function and a new lower bound of Carlson’s inequality by means of a third order estimate of the inverse cosine function.

1. Introduction

Forx >0, it is known in the literature that 3x 12√

1x2 <arctanx. 1.1

This inequality was first presented without proof by Shafer1. Three proofs of it were later given in2. Shafer’s inequality1.1was recently sharpened and generalized by Qi et al. in 3.

In view of inequality1.1, we now ask: for eacha > 0, what is the largest numberb and what is the smallest numbercsuch that the inequalities

bx 1a

1x2 ≤arctanxcx 1a

1x2 1.2

are valid for allx≥0? Theorem2.1below answers this question.

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For 0≤x <1, it is known in the literature that 6√

1−x 2√

2√

1x <arccosx <

3

4·√ 1−x

1x1/6 . 1.3

The inequalities 1.3 were established by Carlson 4 see also 5, page 246. Carlson’s inequalities1.3were recently sharpened and generalized by and Guo and Qi in6,7. In view of the first inequality in1.3, the following question has been asked: for eachν > 0, what is the largest numberλand what is the smallest numberμsuch that the inequalities

λ√ 1−x ν

1x≤arccosxμ√ 1−x ν

1x 1.4

are valid for all 0≤x ≤1? In8, Chen and Mortici answered this question. Also in8, the authors proved that for all 0≤x≤1, the inequalities

3

4·√ 1−x

α 1x1/6 ≤arccosx3

√4·√ 1−x

β 1x1/6 1.5

hold with best possible constants

α 2√3 4−π

π 0.0105708962. . ., β0. 1.6

In view of the second inequality in1.3, we now define the functionPxby Px r1−xp

1xq , 0≤x≤1. 1.7 We are interested in finding the values of the parametersp,qand r such that Px is the best 3rd order approximation of arccosxin a neighborhood of the origin. This is addressed in Theorem3.1. Motivated by the result of Theorem3.1, we establish a new lower bound for the inverse cosine function in Theorem3.2.

The following lemma is needed in our present investigation.

Lemma 1.1see9–11. Let−∞< a < b <∞, andf, g:a, b → Êbe continuous ona, band differentiable ina, b. Supposeg/0 ona, b. Iffx/gxis increasing (decreasing) ona, b, then so are

fxfa

gxga and

fxfb

gxgb. 1.8

Iffx/gxis strictly monotone, then the monotonicity in the conclusion is also strict.

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2. Generalized and Sharp Shafer’s Inequality

Theorem 2.1. The largest numberband the smallest numbercrequired by inequality1.2are:

when 0< aπ/2, b π/2a, c1a, whenπ/2< a≤2/π−2, b

4

a2−1

/a2, c1a, when 2/π−2< a <2, b

4

a2−1

/a2, c π/2a, when 2a <∞, b1a, c π/2a.

2.1

Proof. Forx 0, inequality 1.2holds for all values ofband c. For x > 0 and fora > 0, inequality1.2is equivalent to

b

1a√ 1x2

arctanx

xc. 2.2

Consider the functionfxdefined by

fx:

1a

1x2

arctanx

x , x >0,

f0:1a.

2.3

By an elementary change of variable

xtant, 0≤t < π

2, 2.4

we obtain

fx gt: t1asect

tant , 0< t < π 2, f0 g0:1a.

2.5

Differentiating with respect totyields sin2t

sinttcostgt aht, 0< t <π

2, 2.6

where

ht 2t−sin2t

2sinttcost. 2.7

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For 0≤tπ/2, let

h1t 2t−sin2t, h2t 2sinttcost. 2.8

Then,

h1t

h2 t 2 sint

t 2.9

is strictly decreasing on0, π/2. By Lemma1.1, the function

ht h1t

h2t h1t−h10

h2th20 2.10

is strictly decreasing on0, π/2, and we have π

2 lim

s→π/2hs< ht< lim

s0hs 2, ∀t∈ 0,π

2

. 2.11

We split into several cases.

Case 1. 0< aπ/2.

By 2.6 and 2.11, gt < 0 on 0, π/2. Therefore, the function gt is strictly decreasing on 0, π/2. Asx tantis strictly increasing for t ∈ 0, π/2, we see that the functionfxis strictly decreasing forx∈0,∞, and we have

π

2af< fx

1a√ 1x2

arctanx

xf0 1a, ∀x≥0. 2.12

Hence, inequality1.2holds forx≥0 with best possible constants

2a, c1a. 2.13

Case 2. π/2< a <2.

By2.11, the functionhtis strictly decreasing from0, π/2ontoπ/2,2. Therefore, for eachawithπ/2< a <2, there exists a uniqueξξa∈0, π/2such thathξ a, that is,

2ξ−sin2ξ

2sinξξcosξ a, 2.14

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or equivalently

ξ

sinξ acosξ

1acosξ. 2.15

Moreover, it follows from2.6thatgt<0 on0, ξ, andgt>0 onξ, π/2. Therefore, the functiongtis strictly decreasing on0, ξand strictly increasing onξ, π/2, thus it takes its unique minimumattξ. Write2.5as

gt tacost

sint , 0< t < π

2. 2.16

Substitutinginto2.16and using2.15, we get

gmin: acosξ2

1acosξ , ξ∈ 0,π

2

, 2.17

or equivalently,

y2a 2−g

ya2g0, whereycosξ. 2.18

From discriminant

Δ a

2−g2−4 a2g

≥0, 2.19

we obtain

g≥ 4 a2−1

a2 . 2.20

So to summarize, we have

g0 1a,

2

lim

t→π/2gt π

2a, 2.21

gtdecreases strictly on 0, ξwith minimum valuegmin 4a2−1/a2 att ξ arccosa2−2/a, and increases strictly onξ, π/2.

Subcase 2.1. 1ag0gπ/2 π/2a, that is,π/2< a≤2/π−2:

We have 4

a2−1

a2 gt t1asect

tantg0 1a, 0≤t < π

2, 2.22

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which, by the elementary change of variable2.4, can be transformed into

4 a2−1

a2 ftanξfx

1a√ 1x2

arctanx

xf0 1a, x≥0. 2.23

Hence, inequality1.2holds with best possible constants

b 4 a2−1

a2 , c1a. 2.24

Subcase 2.2. 1ag0< gπ/2 π/2a, that is, 2/π−2< a <2:

We have 4

a2−1

a2 gt t1asect

tant < lim

t→π/2gt π

2a, 0≤t < π

2, 2.25

which, by the elementary change of variable2.4, can be transformed into

4 a2−1

a2 ftanξfx

1a√ 1x2

arctanx

x < fπ

2a, x≥0. 2.26 Hence, inequality1.2holds with best possible constants

b 4 a2−1

a2 , c π

2a. 2.27

Case 3. 2a <∞.

By 2.6 and 2.11, gt > 0 on 0, π/2. Therefore, the function gt is strictly increasing on 0, π/2. As x tantis strictly increasing fort ∈ 0, π/2, we see that the functionfxis strictly increasing forx∈0,∞, and we have

1af0≤fx

1a√ 1x2

arctanx

x < fπ

2a, ∀x≥0. 2.28 Hence inequality1.2holds forx≥0 with best possible constants

b1a, c π

2a 2.29

The proof of Theorem2.1is complete.

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Remark 2.2. We would like to remark on three special cases of Theorem2.1.

iLetaπ/2. Thenbπ2/4 andc1 π/2. Thus inequality1.2becomes π2/2

x 2π

1x2 ≤arctanx≤ 2πx 2π

1x2, x≥0. 2.30

iiLeta 2/π−2. Thenb π4πandc π/π−2. Thus inequality1.2 becomes

π4ππ−2x π−2 2√

1x2 ≤arctanxπx π−2 2√

1x2, x≥0. 2.31 iiiLeta2. Thenb3 andcπ. Thus inequality1.2becomes

3x 12√

1x2 ≤arctanxπx 12√

1x2, x≥0. 2.32

Among inequalities2.30–2.32, the upper bound πx

π−2 2√

1x2 2.33

is the best, in the sense that it is the smallest one among the three upper bounds in2.30–

2.32. There is no strict comparison among the three lower bounds in2.30–2.32.

3. A New Lower Bound of Carlson’s Inequality

Theorem3.1below determines the values of the parametersp,q, andr which provides the best functionPxapproximating arccosx.

Theorem 3.1. LetPxbe defined by1.7. Then for

p π2

π2 , q π−2

π2 , r π

2, 3.1

one has

x→lim0

arccosxPx

x3 π2−8

2 . 3.2

In particular, the speed of the functionPxapproximating arccosxis given by the order estimate Ox3asx0.

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Proof. The power series expansion of arccosxPxnear 0 is arccosxPx π

2 −r

prqr−1 x

−1 2p2r1

2pr−1 2q2r−1

2qrpqr x2

1

2pq2r1 6q3r1

2q2r1 3qr1

6p3r 1 2p2qr

−1 2p2r 1

3pr−1

6 x3O x4

.

3.3

It is easy to check that forp,q,ras defined in3.1, we have π

2 −r 0, prqr−10

−1 2p2r1

2pr−1 2q2r− 1

2qrpqr0,

3.4

and so

arccosxPx arccosxπ/21xπ2/π2

1xπ−2/π2 π2−8

2 x3O x4

x−→0. 3.5

The next theorem provides a new lower bound for the inverse cosine function.

Theorem 3.2. For 0x1,

π/21−xπ2/π2

1xπ−2/π2 ≤arccosx. 3.6

Proof. Forx1, inequality3.6clearly holds. We now consider the function Fx: 1xπ−2/π2arccosx

1−xπ2/π2 , 0≤x <1. 3.7

By an elementary change of variable

xcos2t, 0< tπ

4, 3.8

we have

√1x

2 cost,

1−x

2 sint, 3.9

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andFxcan be rewritten as

Fx ft: 2t√

2 cost2π−2/π2

2 sint2π2/π2 , 0< tπ

4. 3.10

Differentiating with respect totyields, for 0< tπ/4,

π2sintπ22π4/π2costπ2−2π4/π2

2π2−4/π2 ft 4tcos2t−π2

2 sin2t 2πt. 3.11 Write

gt:4tcos2t− π2

2 sin2t 2πt, 0< tπ

4. 3.12

Motivated by the investigations in12, we are in a position to provegt>0 fort∈0, π/4.

Let

Gt

⎧⎪

⎪⎪

⎪⎪

⎪⎪

⎪⎪

⎪⎩

λ, t0,

gt

tπ/4t2, 0< t < π 4,

μ, t π

4,

3.13

whereλandμare constants determined with limits:

λ lim

t→0

gt

tπ/4t2 64−16π232π

π2 0.6704721009. . ., μ lim

t→π/4−

gt

tπ/4t22−32

π 7.47841762. . ..

3.14

Using Maple we determine Taylor approximation for the functionGtby the polynomial of the first order:

P1t 128

4−π2

π3 t16

4−π2

π2 , 3.15

which has a bound of absolute error

ε1348π2−128π−192

π2 0.3690379422. . . 3.16

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for valuest∈0, π/4. It is true that

Gt−P1t−ε1≥0, P1t−ε1>0, 3.17 fort ∈ 0, π/4. Hence, fort ∈ 0, π/4it is true thatGt > 0 and thereforegt > 0 and ft<0 fort∈0, π/4. Therefore, the functionftis strictly decreasing on0, π/4. Asx cos2tis strictly decreasing on0, π/4, we see thatFxis strictly increasing forx∈0,1, and hence

π

2 F0≤Fx 1xπ−2/π2arccosx

1−xπ2/π2 ∀x∈0,1. 3.18 By rearranging terms in the last expression, Theorem3.2follows.

Acknowledgment

This paper is supported in part by the Research Grants Council of the Hong Kong SAR, Project no. HKU7016/07P.

References

1 R. E. Shafer, “Problem E1867,” The American Mathematical Monthly, vol. 73, no. 3, pp. 309–310, 1966.

2 R. E. Shafer, L. S. Grinstein, D. C. B. Marsh, and J. D. E. Konhauser, “Problems and solutions: Solutions of elementary problems: E1867,” The American Mathematical Monthly, vol. 74, no. 6, pp. 726–727, 1967.

3 F. Qi, S.-Q. Zhang, and B.-N. Guo, “Sharpening and generalizations of Shafer’s inequality for the arc tangent function,” Journal of Inequalities and Applications, vol. 2009, Article ID 930294, 9 pages, 2009.

4 B. C. Carlson, “Inequalities for a symmetric elliptic integral,” Proceedings of the American Mathematical Society, vol. 25, pp. 698–703, 1970.

5 D. S. Mitrinovi´c, Analytic inequalities, Springer, New York, NY, USA, 1970.

6 B.-N. Guo and F. Qi, “Sharpening and generalizations of Carlson’s double inequality for the arc cosine function,”http://arxiv.org/abs/0902.3039.

7 B.-N. Guo and F. Qi, “Sharpening and generalizations of Carlson’s inequality for the arc cosine function,” Hacettepe Journal of Mathematics and Statistics, vol. 39, no. 3, pp. 403–409, 2010.

8 C.-P. Chen and C. Mortici, “Generalization and sharpness of Carlson’s inequality for the inverse cosine function,” submitted.

9 G. D. Anderson, S.-L. Qiu, M. K. Vamanamurthy, and M. Vuorinen, “Generalized elliptic integrals and modular equations,” Pacific Journal of Mathematics, vol. 192, no. 1, pp. 1–37, 2000.

10 G. D. Anderson, M. K. Vamanamurthy, and M. K. Vuorinen, Conformal Invariants, Inequalities, and Quasiconformal Maps, Canadian Mathematical Society Series of Monographs and Advanced Texts, John Wiley & Sons, New York, NY, USA, 1997.

11 G. D. Anderson, M. K. Vamanamurthy, and M. Vuorinen, “Monotonicity of some functions in calculus,” preprint.

12 B. J. Maleˇsevi´c, “One method for proving inequalities by computer,” Journal of Inequalities and Applications, vol. 2007, Article ID 78691, 8 pages, 2007.

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