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Application Note AN6032
FAN4800 Combo Controller Applications
www.fairchildsemi.com
© 2006 Fairchild Semiconductor Corporation www.fairchildsemi.com
FAN4800 Rev. 1.0.2 • 12/07/06
General Description
This application note shows the step-by-step process to design a high-performance supply. The equations shown in this document can also be used for different output voltages and total power.
The complete power supply circuits shown in Figures 6 and 7 demonstrate the FAN4800’s ability to manage high output power while complying with international requirements regarding AC line quality. The PFC section provides 380VDC to a dual-transistor current-mode forward converter.
The output of the converter delivers +12V at up to 8.4 amps.
The circuit operates from 85 to 265VAC with both power sec- tions switching at 100kHz.
The PFC Stage Powering the FAN4800
The FAN4800 is initialized once C12 is charged to 13V through R27 and R28. PFC switching action boosts the volt- age on C5 to 380V via L1’s inductance. T2 then supplies a well-regulated 13V for the FAN4800 from its secondary winding. T2’s primary-to-secondary turns ratio (NPRI / NSEC) is 18.8:1. For proper circuit operation, high-frequency bypassing with low-ESR ceramic or film capacitors on VCC and VREF is provided. Orderly PFC operation upon start-up is achieved when D2 quick charges the boost capacitor to the peak AC line voltage before the boost switch Q1 is turned on. This ensures the boost inductor current is zero before
IEAO
RAMP2 RAMP1 VDC
SS VRMS
ISENSE
IAC
VEAO
DC ILIMIT
GND PWM OUT PFC OUT VCC
VREF
VFB
FAN4800
1
2
3
4
5
6
7
8
16
15
14
13
12
11
10
9 F1
3.15A
C1 0.68uF
BR1 4A, 600V
KBL06 R1A 500k
R1B 500k R2A 453k
R2B 453k
R3 110k
R4 15.4k R5A
1.2 R5B
1.2 R5C 1.2
R5D 1.2
C2 0.47uF C3 0.1uF
R6 41.7k
R7A 178k
R7B 178k
R8 2.37k
R9 1.1k R10
6.2k
R11 845k R12
71.5k
R13 10k R14
33
R15 3 R17
33
R16 10k R19
220 R20A
2.2 R20B
2.2 R21
22 R27 75k
R28 240
R30 4.7k
R31 100
C4 10nF
C5 100uF 450V
C6 1.5nF C7 NOT USED
C8 68nF
C9 10nF
C10 15uF
C11 10nF
C12 10uF 35V
C13 0.1uF
C14 1uF C15
10nF C16 1uF
C17 220pF C18
470pF C19 1uF
C20 1uF C25 0.1uF
C26 100nF
C30 330uF
25V
C31 1nF D1
ISL9R460P2 D2
1N5406 D3
RGF1J
D4 MMBZ5245B
D5 RGF1J
D6 RGF1J D7
MMBZ5245B
D8 MBRS
140
D10 MBRS
140 D9
MBRS 140
D12 1N5401
D13 1N5401
VFB
VCC
VREF
RAMP1 ISENSE
L1
Q1G Q2G
Q3G
RAMP2 / DC ILIMIT
PRI GND VDC T1A
T1B
T2
VDC / +380V
U1 Q1
FQPF9N50 Q2
FQPF 6N50
Q3 FQPF6N50 AC INPUT
85 TO 265Vac
Q4 MMBT3904
Figure 1. The PFC Stage
PFC action begins. The value of the regulated voltage on C5 must always be greater than the peak value of the maximum line voltage delivered to the supply.
Because the FAN4800 uses transconductance amplifiers, the loop compensation networks are returned to ground (see the FAN4800 datasheet for the error amplifier characteristics/
advantages). This eliminates the interaction of the resistive divider network with the loop compensation capacitors, per- mitting a wide choice of divider values chosen to minimize amplifier offset voltages due to input bias currents. For reli- able operation, R7A and R7B must have a voltage rating of at least 400 volts.
Calculate the divider ratio (R7A+R7B)/R8 by:
Selecting the Power Components
The FAN4800 PFC section operates with continuous induc- tor current to minimize peak current and to maximize avail- able power. The boost inductor value found by setting ΔI, the peak-to-peak value of high-frequency current, is typically 10% to 20% of the peak value of the maximum line current.
where Iin(peak_max) is a peak value of input current occurred at low line, Vin(rms_min) is RMS value of minimum line volt- age, PO(max) is the maximum output power, and η is effi- ciency. Value Iin(peak_max) defines value of ΔI, where dI is the specified percentage rate. IL(max) is the inductor maxi- mum current.
Duty cycle D and switching frequency fS influence inductor selection.
The boost diode D1 and switch Q1 are chosen with a reverse voltage rating of 500V to safely withstand the 380V boost potential. The maximum Q1 RMS current is obtained by Equation 8 and the maximum Q1 peak current is calculated by Equation 9.
The boost diode average current can be calculated by:
The boost capacitor value is chosen to permit a given output voltage hold-up time in the event the line voltage is suddenly removed.
where:
tHLD = hold-up time (sec)
VC5(min) = minimum voltage on C5 at which the PWM stage can still deliver full output power
( )
1( ) ( )
>
> ×
>
C 5 in( rms _ max) C 5
C 5
V 2V
V 1.414 265
V 375V use 380V
+ = −
+ = −
+ =
7 A 7 B C 5
8
7 A 7 B
8
7 A 7 B
8
R R V
R 2.5 1
R R 380
R 2.5 1
R R
R 151
( )
2( )
3( )
4η
=
=
in(max) in( peak _ max)
in( rms _ min) O(max) in(max)
I 2P
V P P
Δ
Δ
= ×
= +
in( peak _ max)
L(max) in( peak _ max)
I dI I I I I
2
( )
5( )
( ) ( )
{ } ( ) ( )
( ) ( ) ( ) ( )
Δ
η
= −
= ×
×
− ⋅ ⋅
= ⋅ ⋅ ⋅
− ⋅ ⋅ ⋅
= ⋅ × ⋅ ⋅
=
O in( rms _ min) O in( rms _ min) 1
S
2 O in( rms _ min) in( rms _ min)
O S O(max)
2 5
V 2V
D V
D 2V
L f I
V 2V V
V f dI P
380 1.414 85 85 0.95
380 1 10 0.15 100
3.128mH use 3.0mH
( )
6( )
7( ) ( )
( ) ( ) ( ) ( )
( ) ( )
π
η π
Δ
η
= −
= −
⋅ ⋅ ⋅
= −
⋅ ⋅ ⋅
=
= +
=
in( rms _ min) Q1rms in( rms _ max)
O
O(max) in( rms _ min)
in( rms _ min) O
Q1 peak in( peak _ max)
O(max) in( rms
1 4 2V
I 2I
2 3 V
2P 1 4 2V
V 2 3 V
1.414 100 1 4 1.414 85
0.95 85 2 3 3.1416 380 1.06 A
I I I
2 2P
V
( )
( ) ( )
( ) ( ) { ( ) ( ) } ( ) ( )
( ) ( ) (
−)
− ⋅
+ ⋅ ⋅
− ⋅ ⋅ ⋅
= ⋅ +
⋅ ⋅ × ⋅ ×
=
O in( rms _ min) in( rms _ min)
_ min) O S 1
5 3
V 2V 2V
V f L
380 1.414 85 1.414 85 1.414 100
0.95 85 380 1 10 3 10
2.025A
( )
8( )
9=
=
= =
D1avg O(max) O(max)
O
I I
P V
100 0.26 A 380
( )
10( )
11≥ −
O(max) HLD
5 2 2
C 5( NOM ) C 5( MIN )
2P t
C V V
AN6032 APPLICATION NOTE
© 2006 Fairchild Semiconductor Corporation www.fairchildsemi.com
FAN4800 Rev. 1.0.2 • 12/07/06 3
A key advantage of using leading/trailing-edge modulation is that a large portion of the inductor current is "dumped"
directly into the load (PWM stage transformer) and not the boost capacitor. This relaxes the ESR requirement of the boost capacitor. For reference, Equation 12 should be used as a starting point when choosing C5’s maximum ripple current rating (at 120Hz).
Selecting the Power Setting Components
The maximum average power delivered by the PFC stage is set using the following procedure:1. Find the resistive divider ratio that results in the voltage at the VRMS pin being equal to 1.14V at the lowest line voltage. The voltage at this pin must be well filtered, yet able to respond well to transient line voltage changes.
The resistor and capacitor values in the typical example were found empirically to offer the lowest ripple voltage and still respond well to line voltage changes. Should a ratio be required that is greatly different from that found in Equation 13, adjust the filter capacitor values accord- ing to Equations 14 and 15.
where:
f1 = 15Hz, f2 = 23Hz
RTOT = R2A + R2B + R3 + R4
2. Find the constant of proportionality kM of the multiplier gain k in Equation 16a. To obtain "brownout" action below the lowest input voltage, the maximum gain of the multiplier must be used when finding kM. The maximum gain (0.35) occurs when the VRMS input of the multiplier is 1.14V. Equation 16 is the general expression for the multiplier gain versus the line voltage.
3. Select the value of (R1A+R1B) that permits the greatest multiplier output current without saturating the output.
The maximum output current of the multiplier is 228.57μA.
4. Select the value of the current sense resistor to complete the calculations for the power setting components.
where:
RMULO = multiplier output termination resistance (3.5kΩ).
Voltage Loop Compensation
Maximum transient response of the PFC section, without instability, is obtained when the open-loop crossover fre- quency is one-half the line frequency. For this application, the compensation components (pole/zero pair) are chosen so that the closed loop response decreases at 20dB/decade, crossing unity gain at 30Hz, then immediately decreasing at 40dB/decade. The error amplifier pole is placed at 30Hz and an effective zero at one-tenth this frequency, or 3Hz. Find the crossover frequency (GPS = 1) of the power stage. For reference, Equation 20 finds the power stage pole and Equa- tion 21 finds the power stage DC gain.
( )
=
= ⋅
O( C5 ) C5 _ rms
peak C5 _ rms
I I
2
I 2 I
( )
12( )
12a⋅π
=
4
TOT in( rms _ min)
R 1.14
R 2 2V
( )
13( ) ( )
( ) ( )
π
π
= ⋅ + ⋅ +
⎛ + ⋅ ⎞
⎜ ⎟
⎜ + ⋅ + ⎟
⎝ ⎠
= ⋅
3 TOT
1 2 A 2 B 3 4
4 TOT
2 A 2 B 3 4
2
2 4
C R
2 f R R R R
1 R R
R R R R
C 2 f R
( )
14( )
15( ) ( )
=
=
= ⋅
= ≈
M 2 rms
2 M in( rms _ min)
2
k k V
k kV
0.35 85 2528.75 2529
( )
16( )
16a( )
17( ) ( )
( ) ( ) ( ) ( )( )
( )
−
−
+ ≥ −
×
⋅ ⋅ −
+ ≥
×
+ ≥
in( rms _ min) EAO(max)
1A 1B 6
1A 1B 6
1A 1B
k 2V V 0.625
R R
228.57 10
0.35 1.414 85 6 0.625
R R
228.57 10 R R 989.38k use 1MΩ Ω
( )
( )
( ) ( )( ) ( )
( ) ( )
η
Ω Ω
⋅ − ⋅
≤ +
× ⋅ − ⋅
≤ ×
≤
MULO M EAO(max)
5 A 5B 5C 5 D
O(max) 1A 1B
3
5 A 5B 5C 5 D 6
5 A 5B 5C 5 D
R k V 0.625
R || R || R || R
P R R
3.5 10 2529 6 0.625 0.95 R || R || R || R
100 1 10 R || R || R || R 0.452 use 0.3
( )
18Figure 2. Voltage Amp Compensation
where:
The gain of the power stage at 30Hz is calculated by:
The power stage gain is attenuated by the resistive divider (R7A+R7B)/R8 according to Equation 23:
The amount of error amplifier gain required to bring the open-loop gain to unity at 30Hz is the negative of the sum of the power stage, plus divider stage gain (attenuation):
The value of R11, which sets the high-frequency gain of the error amplifier, can be determined by:
Calculate C8; which, together with R11, sets the zero fre- quency at 3Hz.
Since the pole frequency is ten times the zero frequency, the pole capacitor C9 is one-tenth the value of C8.
Current Loop Compensation
The current loop is compensated like the voltage loop, except the choice of the open-loop crossover frequency. To prevent interaction with the voltage loop, the current loop bandwidth should be greater than ten times the voltage loop crossover frequency, but no more than one sixth the switch- ing frequency, or 16.7kHz. The power stage crossover fre- quency is calculated by Equation 28, the pole frequency by Equation 29, and the power stage DC gain by Equation 30.
VBOOST
15 FB
2.5V
16 VEAO R7
R11 R8
C8 C9
( )
( )
( ) ( ) ( ) ( ) ( ) ( )
( ) ( ) ( )
π πη
π
−
−
= −
= −
= ⋅ ⋅ ⋅ ⋅ − ⋅ ×
=
=
= ⋅ ⋅ ×
=
in(max) C
O EAO(max) 5
O(max)
O EAO(max) 5
6
P L 5
6
f P
2 V V 0.625 C
P
2 V V 0.625 C
100
2 3.1416 0.95 380 6 0.625 100 10 82.02Hz
f 1 R C 1
3.1416 1444 100 10 2.20Hz
( )
20( )
19= O2
L O(max)
R V P
( ) ( )
( )
=
= ⋅
=
PS( DC ) C P
G 2 f
f
1.414 82.02
2.20 52.72 34.44dB
( )
21( )
22( )
=
=
=
C PS( 30 Hz )
G f
30 82.02
30
2.734 8.736dB
( )
−
= + +
= + +
= × −
8 RDIV
7 A 7 B 8
3
G R
R R R
2.37
178 178 2.37 6.613 10 43.59dB
( )
23( )
( )
( )
( )
= − +
= − + −
=
EA PS( 30 Hz ) RDIV
G G G
8.736 43.59 34.854dB 55.29V / V
( )
24( )
25Ω
−
=
= ×
=
EA 11
M
6
R G g
55.29
70 10
789.8k use 845kΩ
( ) ( ) ( ) ( )
= π
= ⋅ ⋅ × ⋅
=
8
11 Z
3
C 1
2 R f 1
2 3.1416 845 10 3 62.8nF use 68nF
( )
26( )
27−
=
= ×
=
9 8
9
C C 10 68 10 10
6.8nF use 10nF
AN6032 APPLICATION NOTE
© 2006 Fairchild Semiconductor Corporation www.fairchildsemi.com
FAN4800 Rev. 1.0.2 • 12/07/06 5
Figure 3. Current Amp Compensation
Find the gain of the power stage at 16.7kHz.
The current loop contains no attenuating resistors, so find the error amplifier gain with:
Determine the value of the current error amplifier setting resistor R12.
Calculate the value of C6 to form the zero at 1.67kHz.
The pole capacitor C7 is one-tenth the value of C6.
The PWM Stage
Soft-Starting the PWM Stage
The FAN4800 features a dedicated soft-start pin for control- ling the rate of rise of the output voltage and preventing overshoot during power on. The controller does not initiate soft-start action until the PFC voltage reaches its nominal value, thereby preventing stalling of the output voltage due to excessive PFC currents. PWM action is terminated in the event the FAN4800 loses power or if the PFC boost voltage falls below 228VDC. The soft-start capacitor value (C19) for 50ms of delay is found by Equation 36.
Setting the Oscillator Frequency
There is one version of the FAN4800. The FAN4800IN is where the PFC and PWM run at the same frequency.
FAN4800IN
In general, it is best to choose a small-valued capacitor C18 to maximize the oscillator duty cycle (minimize the C18 dis- charge time). Too small a value capacitor can increase the oscillator’s sensitivity to phase modulation caused by stray field voltage induction into this node. For the practical
10 GND
1 IEAO
R12
C6 14 C7 VREF
VREF
3 VEAO IAC
ISENSE
3.5k
3.5k R5AR5BR5CR5D
( )
( )( )
( ) ( ) ( ) ( )
( ) ( ) ( )
( ) ( )
π
π
−
−
−
=
= ⋅ ⋅ × ⋅
=
=
= ⋅ ⋅ ×
=
=
⋅ ×
=
=
( P P )
5 A 5B 5C 5D O
C
1 RAMP
3
P L 5
6
C PS( DC )
P
3
R || R || R || R V
f 2 L V
0.3 380
2 3.1416 3 10 2.75 2.2kHz
f 1 R C 1
3.1416 1444 100 10 2.20Hz same as (20)
G 2 f
f
1.414 2.20 10
2.20 1414 63
(
.0dB)
( )
28( )
29( )
30( )
−
= ×
= ×
×
= × −
C
PS( 16.7 kHz ) 3
3 3 1
G f
16.7 10 2.20 10
16.7 10
1.32 10 17.60dB
( )
31( )
( )
( )
= − −
= − −
=
EA PS( 16.7 kHz )
G G
17.60
17.60dB 7.58V / V
( )
32Ω Ω
−
=
= ×
=
EA 12
M ( CE )
6
R G g 7.58
85 10
89.2k use 71.5k
( )
33( ) ( ) ( ) ( )
= π
= ⋅ ⋅ × ⋅ ×
=
6
12 Z
3 3
C 1
2 R f 1
2 3.1416 71.5 10 1.67 10 1.33nF use 1.5nF
( )
34−
=
= ×
=
6 7
9
C C 10 1.5 10 10 150 pF
( )
35( )
( )
μ
−
−
⎛ × ⎞
= ⋅⎜ ⎟
⎝ ⎠
⎛ × ⎞
= ⋅⎜ ⎟
⎝ ⎠
=
6
19 SS
6
20 10
C t
0.95 20 10 0.05
0.95 1 F
( )
36example, a 470pF capacitor is chosen for C18. Equation 37 is accurate with values of R6 greater than 10k.
Current Limit
The PWM power stage operates in current mode using R20A and R20B to generate the voltage ramp for duty cycle control.
The FAN4800 limits the maximum primary current via an internal 1V comparator; which, when exceeded, terminates the drive to the external power MOSFETs. Maximum pri- mary current is:
Voltage Mode (Feedforward)
Should voltage mode control be used, it is necessary to know C5’s peak voltage to choose the correct ramp generating components. Equation 39 finds the worst-case peak-to-peak ripple voltage across C5. To find the peak voltage, divide the ripple voltage by two and add it to the regulated boost volt- age. Remember that since the FAN4800 employs leading/
trailing modulation, the actual peak-to-peak ripple voltage is generally much less than the calculated value.
where:
fL = line frequency.
Solve Equation 40 for the ramp resistor value. The ramp capacitor value should be in the range of 470pF ~ 10nF.
Choose a resistor with an adequate voltage rating to with- stand the boost voltage.
( ) ( ) ( )
Ω
−
≅ ⋅
≅ ⋅ × ⋅ ×
≅
6
SW 18
5 12
R 1
0.51 f C 1
0.51 1 10 470 10 41.7k
( )
37=
= +
×
=
PRI ( MAX )
20 A 20 B
I 1
R || R 2.2 2.2
2.2 2.2 0.91Amps
( )
38π
( )
⎛ ⎞
= ⎜ ⎟ +
⎝ ⎠
2
2
R( C5 ) OUT ( C5 ) 5
L 5
V I 1 ESR C
4 f C
( )
39IEAO
RAMP2 RAMP1 VDC
SS VRMS
ISENSE
IAC
VEAO
DC ILIMIT
GND PWM OUT PFC OUT VCC
VREF
VFB
FAN4800
1
2
3
4
5
6
7
8
16
15
14
13
12
11
10
9 R6 41.7k
R7A 178k
R7B 178k
R8 2.37k
R9 1.1k R10
6.2k
R11 845k R12
71.5k
R13 10k R14
33
R15 3 R17
33
R16 10k
R18 220
R19 220
R20A 2.2 R20B
2.2 R23
1.5k R24 1.2k
R26 10k
U3 TL431A
U2 MOC8112
R22 8.66k
R25 2.26k R30
4.7k C5
100uF 450V
C6 1.5nF C7 NOT USED
C8 68nF
C9 10nF
C10 15uF
C11 10nF
C12 10uF 35V
C13 0.1uF
C14 1uF C15
10nF C16 1uF
C17 220pF C18
470pF C19 1uF
C20 1uF
C21 2200uF
25V
C22 4.7uF
C23 100nF C24
1uF C25
0.1uF
C31 1nF
D3 RGF1J
D4 MMBZ5245B
D5 RGF1J
D6 RGF1J D7
MMBZ5245B
D8 MBRS
140
D10 MBRS
140
D11A MBR2545CT
D11B MBR2545CT
VFB
VCC
VREF
Q2G
Q3G
RAMP2 / DC ILIMIT
PRI GND VDC
12V RET 12V RETURN 12V
12V, 100W L2
T1A T1B
T2
VDC / +380V
U1
Q2 FQPF 6N50
Q3 FQPF6N50
Q4 MMBT3904
Figure 4. The PWM Stage
AN6032 APPLICATION NOTE
© 2006 Fairchild Semiconductor Corporation www.fairchildsemi.com
FAN4800 Rev. 1.0.2 • 12/07/06 7
where:
σ(MAX) = maximum PWM duty cycle (0.45 for the FAN4800)
VR = peak-to-peak boost capacitor ripple voltage for Equation 39.
The Power Transformer Turns Ratio
The minimum output voltage at the secondary of T2 is found in Equation 41. The secondary voltage is chosen to be 30 volts to increase the output voltage hold-up time.
The transformer turns ratio is derived from Equation 42:
The maximum secondary current with the output shorted is limited by Equation 43:
The output inductor and rectifier are chosen with maximum current rating larger than the maximum secondary current.
Output Filter Component Filter Selection
L2’s value is chosen to efficiently minimize output ripple current, thereby easing the ESR requirement of the filter capacitor. C21’s ESR value is the dominant contributor to the output ripple. The maximum ESR value required is found in Equation 44:where:
VR = peak-to-peak output ripple voltage.
Output Voltage Compensation
A TL431 shunt regulator U3 and opto-isolator U2 perform output voltage setting and regulation. The opto crosses the primary-to-secondary safety boundary, varying the voltage on the VDC pin to keep the output voltage constant against line and load changes. Using current-mode control simplifies loop compensation, leaving only a single pole and zero in the output stage. The pole is created from the output capacitor and equivalent load resistance. The zero is formed from the filter capacitor and its ESR. In this example, the action of the zero occurs well after the closed-loop response has crossed unity, so it was not compensated with a pole. The output pole is canceled, increasing the overall bandwidth by the addition of R26 and C23, which form a zero with TL431. For more information on using the TL431, including gain/phase versus frequency characteristics, refer to the Fairchild Semiconduc- tor datasheet for the TL431.
3.3V Output Design Changes
The latest microprocessors and support circuitry require a 3.3V supply for proper operation. The FAN4800 is ideal for these applications, including the energy-efficient, ecologi- cally friendly "Green" PC. If the total output power required varies greatly from 100 watts, it is necessary to re-select cer- tain components, beginning with the PFC stage. T2’s turn ratio must be adjusted according to Equation 42 and another low-current secondary winding added using the same turns ratio as originally found for the +12 volts. This second wind- ing is necessary to power the TL431/opto circuit because the 3.3V output is not adequate to fully bias the feedback cir- cuitry. C21 may be increased to reduce the output ripple volt- age. Figure 5 displays a 3.3V output stage capable of supplying 16 amps.
Figure 5. 3.3V Output Stage
= σ
⎛ − ⎞
⎜ + ⎟
⎝ ⎠
( MAX ) RAMP
RAMP SW REF
O R
R C f ln 1 V
V 0.5V
( )
40=σ +
= +
=
OUT
SEC( MIN ) F
( MAX )
V V V
12 1.0 0.45 27.7Volts
( )
41=
=
=
PRI O
SEC SEC( MIN )
PRI SEC
N V
N V
380 30 N : N 38 : 3
( )
42( ) ( )
=
= ⋅
=
PRI ( MAX ) PRI SEC( MAX )
SEC
I N
I N
0.91 38
3 11.5Amps
( )
43≤ R 2 SWσ
( C 21 )
SEC ( MAX )
V L f
ESR V
( )
44R23
R26
U3 TL431A
U2 MOC8112
R22 10.2k
R25 31.6k C21
C22
C23 C24
D11A
D11B
3.3V, 16A L2
T2
VOUTPUT UF4001
Figure 6. Complete 100W Circuit (Current Mode)
IEAO RAMP2RAMP1VDC
SS
VRMS
ISENSE
IAC
VEAO DC ILIMIT
GND
PWM OUT
PFC OUT
VCC
VREF
VFB
FAN4800 1 2 3 4 5 6 7 8
16 15 14 13 12 11 10 9
F1 3.15A C1 0.68uF
BR1 4A, 600V KBL06 R1A 500k R1B 500k
R2A 453k R2B 453k R3 110k R4 15.4k
R5A 1.2 R5B 1.2 R5C 1.2
R5D 1.2 C2 0.47uF
C3 0.1uF R6 41.7k
R7A 178k R7B 178k R8 2.37k
R9 1.1k
R10 6.2k R11 845k
R12 71.5k R13 10k
R14 33 R15 3
R17 33 R16 10k
R18 220 R19 220R20A 2.2R20B 2.2
R21 22 R23 1.5k
R24 1.2k R26 10k U3 TL431A
U2 MOC8112
R22 8.66k R25 2.26k
R27 75k R28 240
R30 4.7k R31 100
C4 10nF
C5 100uF 450V C6 1.5nF
C7 NOT USED C8 68nF
C9 10nF
C10 15uF C11 10nF
C12 10uF 35V C13 0.1uF
C14 1uF C15 10nF
C16 1uF C17 220pF
C18 470pFC19 1uF C20 1uF
C21 2200uF 25V C22 4.7uF C23 100nF
C24 1uF
C25 0.1uF C26 100nF
C30 330uF 25V C31 1nF
D1 ISL9R460P2
D2 1N5406D3 RGF1J D4 MMBZ5245B
D5 RGF1J D6 RGF1J
D7 MMBZ5245B D8 MBRS 140D10 MBRS 140
D9 MBRS 140 D11A MBR2545CT D11B MBR2545CT D12 1N5401 D13 1N5401
VFB VCC
VREF RAMP1
ISENSE
L1 Q1GQ2G Q3G RAMP2 / DC ILIMIT PRI GND
VDC
12V RET 12V RETURN
12V 12V, 100W
L2 T1A
T1B T2
VDC / +380V U1
Q1 FQPF9N50Q2 FQPF 6N50 Q3 FQPF6N50
NOTE : L1; PREMIER MAGNETICS TDS-1047 L2; PREMIER MAGNETICS VTP-05007 T1; PREMIER MAGNETICS PMGO-03 T2; PREMIER MAGNETICS TSO-735
AC INPUT 85 TO 265Vac Q4 MMBT3904