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LEFT REVERSIBLE AND NEAR-COMMUTATIVE SEMIGROUPS AND APPLICATIONS

ZEQING LIU AND SHIN MIN KANG Received 21 May 2003

We prove some common fixed point theorems for left reversible and near-commutative semigroups in compact and complete metric spaces, respectively. As applications, we get the existence and uniqueness of solutions for a class of nonlinear Volterra integral equa- tions.

1. Introduction

Recently, Y.-Y. Huang and C.-C. Hong [15,16], T.-J. Huang and Y.-Y. Huang [14], and Y.-Y. Huang et al. [17] obtained a few fixed point theorems for left reversible and near- commutative semigroups of contractive self-mappings in compact and complete metric spaces, respectively. These results subsume some theorems in Boyd and Wong [1], Edel- stein [3], and Liu [20].

In this paper, motivated by the results in [14,15,16,17], we establish common fixed point theorems for certain left reversible and near-commutative semigroups of self- mappings in compact and complete metric spaces. As applications, we use our main re- sults to show the existence and uniqueness of solutions of nonlinear Volterra integral equations. Our results generalize, improve, and unify the corresponding results of Fisher [4,5,6,7,8,9,10,11,12], Hegedus and Szilagyi [13], Y.-Y. Huang and C.-C. Hong [16], T.-J. Huang and Y.-Y. Huang [14], Y.-Y. Huang et al. [17], Liu [18,19,20], Ohta and Nikaido [21], Rosenholtz [22], Taskovic [23], and others.

Recall that a semigroup F is said to be left reversible if, for anys,tF, there exist u,vFsuch thatsu=tv. It is easy to see that the notion of left reversibility is equivalent to the statement that any two right ideals ofFhave nonempty intersection. A semigroup Fis callednear commutativeif, for anys,tF, there existsuFsuch thatst=tu. Clearly, every commutative semigroup is near commutative, and every near-commutative semi- group is left reversible, but the converses are not true.

Throughout this paper, (X,d) denotes a metric space,N,R+, andRdenote the sets of positive integers, nonnegative real numbers, and real numbers, respectively. LetF be a semigroup of self-mappings onX and let f be a self-mapping onX. For A,BX, x,yX, define

Copyright©2005 Hindawi Publishing Corporation

Journal of Inequalities and Applications 2005:2 (2005) 175–188 DOI:10.1155/JIA.2005.175

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δd(A,B)=supd(a,b) :aA,bB, δd(A)=δd(A,A), δd(x,A)=δd

{x},A, Fx= {x} ∪ {gx:gF},

Of(x)=

fnx:n∈ {0} ∪N

, Of(x,y)=Of(x)Of(y), Cf = {h:h:X−→X, f h=h f},

Hf =

h:h:X−→X,hn∈N fnx⊆ ∩n∈NfnX, HF=

h:h:X−→X,hgFgX⊆ ∩gFgX, Φ=

φ:φ:R+−→R+is upper semicontinuous from the right, φ(0)=0,φ(t)< tfort >0.

(1.1)

A denotes the closure of A. Clearly, Hf Cf ⊇ {fn:nN} ∪ {iX}, whereiX is the identity mapping on X. The mapping f is called a closed mapping if, y= f x when- ever{xn}n∈NX such that limn→∞xn=xand limn→∞f xn=y for somex,yX. It is simple to check that the composition of two closed self-mappings in compact metric spaces is closed. The mapping f is called alocal contractionif, for eachxX, there is an open setUcontainingxand a real numberm <1 such thatd(f z,f y)md(z,y) for all z,yU. The mapping f is said to havediminishing orbital diametersif, for everyxX withδd(Of(x))>0, there existsnNsuch thatδd(Of(fnx))< δd(Of(x)). Clearly,f has diminishing orbital diameters if and only if limn→∞δd(Of(fnx))< δd(Of(x)) for allxX withδd(Of(x))>0. The semigroupFis said to havediminishing orbital diametersif, for anyxXwithδd(Fx)>0, there existsgFsuch thatδd(Fgx)< δd(Fx).

2. Common fixed points for left reversible semigroups in compact metric spaces LetFbe a left reversible semigroup. We define a relationonF byabif and only if abF∪ {b}.

It is easy to verify that (F,) is a directed set. We need the following lemma for our main theorems.

Lemma2.1. LetFbe a left reversible semigroup of closed self-mappings in a compact metric space(X,d)and letA= ∩fFf X. Then

(i) limfFδd(f X)=δd(A);

(ii)Ais nonempty, compact and f A=Afor all f F.

Proof. Note that f XgX for all f,gF with f g. Thus{δd(f X)}fF is a bounded decreasing net inR. Obviously, limfFδd(f X) exists inRand

δd(A)lim

fFδd(f X). (2.1)

We now prove that f X is a compact subset ofX for each f F. Letxbe inX and {xn}n∈NXwith limn→∞f xn=x. The compactness ofXensures that there exists a sub- sequence {xnk}k∈N of{xn}n∈N such that it converges to some pointtX. In view of closedness of f, we conclude immediately thatx= f t f X. Therefore, f X is closed.

That is, f Xis compact. This means thatAis compact.

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We next prove that

δd(A)lim

fFδd(f X). (2.2)

Given f F, there existxf,yf f Xwithd(xf,yf)=δd(f X). SinceXis compact, we can choose two subnets{xfk}and{yfk}of{xf}and{yf}, respectively, such thatxfkx and yfky for somex,yX. For every gF and fkg, we get that xfk,yfkgX.

By virtue of closedness ofgX, we infer thatx,ygX. This means thatx,yA. Conse- quently,

limfFδd(f X)=lim

fFdxf,yf

=lim

k dxfk,yfk

=d(x,y)δd(A). (2.3)

Thus (i) follows from (2.1) and (2.2).

Let nN and f1,f2,. . .,fnF. It follows from the left reversibility of F that there existg1,g2,. . .,gnFwithf1g1=f2g2= ··· = fngn=hfor somehF. Hence,ni=1fiX hX= ∅. The compactness ofXimplies thatA= ∅.

We last prove that f A=Afor all f F. Let f FandxA. For anygF, there exista,bF with f a=gb. Note thatxAaX. Thus there is yX withx=ay. It follows that f x=f ay=gbygX. This implies that f A⊆ ∩gFgX=Afor f F. For the reverse inclusion, let f,gF and yA. It follows from y f gX that there exists xggXwith f xg=y. The compactnessXensures that there exists a convergent subnet {xgk}of{xg}such thatxgkxfor somexX. The closedness of f implies thaty= f x.

For anyh,gFwithgh, we obtain thathXis closed and thatxgbelongs tohX. Thus the limit pointx of{xg}lies inhX. That is,xA. Note that y=f x f A. Therefore,

A f Afor f F. This completes the proof.

Now, we are ready to prove our main theorems.

Theorem2.2. LetFandGbe left reversible semigroups of closed self-mappings in a compact metric space(X,d). Assume that there exist f F,gGsatisfying

d(f x,g y)< δdsu:uFx,sHF,tv:vGy,tHG (2.4) for allx,yXwith f x=g y. ThenFandGhave a unique common fixed pointwXand the pointwis also a unique fixed point ofFandG, respectively. Moreover, ifF(resp.,G) is near commutative, thenF(resp.,G) has diminishing orbital diameters.

Proof. LetA= ∩sFsX andB= ∩tGtX. Ifδd(A,B)>0, then byLemma 2.1there exist a,xAandb,yB withδd(A,B)=d(a,b),a= f x, andb=g y. It follows from (2.4) that

δd(A,B)=d(f x,g y)

< δd

su:uFx,sHF

,tv:vGy,tHG

δd(A,B),

(2.5)

which is a contradiction. Therefore,δd(A,B)=0. That is,A=B= {w}for somewX.

Note that f A=gA=Afor all f F andgG. ThusF and Ghave a common fixed

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pointw. Ifvis a fixed point ofF orG, thenv∈ ∩fFf X= {w}orv∈ ∩gGgX= {w}. This means thatv=w. Hence,FandGhave a unique common fixed pointwX and the pointwis also a unique fixed point ofFandG, respectively.

Assume that one ofForG, sayF, is near commutative. Letxbe inXwithδd(Fx)>0.

So, for any f,gF, there existshFsuch thatg f =f h. It follows that δd(F f x)=δd

{f x} ∪ {g f x:gF}

δd(f X). (2.6) It follows from (2.6) andLemma 2.1that

limfFδd(F f x)=lim

fFδd(f X)=0< δd(Fx), (2.7) which implies thatFhas diminishing orbital diameters. This completes the proof.

Using the argument above, we can conclude the following two results.

Theorem 2.3. Let F be a left reversible semigroup of closed self-mappings in a compact metric space(X,d). Assume that there exist f,gFsatisfying

d(f x,g y)< δd

su:uFxF y,sHF

(2.8)

for allx,yXwith f x=g y. ThenFhas a unique fixed pointwX. Moreover, ifFis near commutative, then it has diminishing orbital diameters.

Theorem 2.4. Let F be a left reversible semigroup of closed self-mappings in a compact metric space(X,d). Assume that there exists f Fsatisfying

d(f x,f y)< δdsu:uFxF y,sHF (2.9) for allx,yXwith f x=f y. ThenFhas a unique fixed pointwX. Moreover, ifFis near commutative, then it has diminishing orbital diameters.

Corollary2.5. Let f be a closed self-mapping of a compact metric space(X,d). Assume that there existp,qNsuch that

dfpx,fqy< δd

su:uOf(x,y), sHf

(2.10)

for allx,yXwith fpx=fqy. Then f has both a unique fixed pointwXand diminish- ing orbital diameters.

Proof. TakeF= {fn:nN}. ThenF is a commutative semigroup. Obviously,Fhas a unique fixed pointwX if and only if f has a unique fixed pointwX. Note that Fx=Of(x) for allxXand thatHF=Hf. ThusCorollary 2.5follows immediately from

Theorem 2.3. This completes the proof.

Remark 2.6. Theorems2.3and2.4andCorollary 2.5extend, improve, and unify [5, The- orem 4], [6, Theorem 2], [7, Theorem 9], [8, Theorem 4], [10, Theorem 5], [11, Theorem 5], [12, Theorem 3], [9, Theorem 5], [14, Theorem 1.1], [17, Theorem 2.2], [18, Theorem 3], [20, Theorem 2], [21, Theorem 4], and so forth.

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Theorem2.7. Let(X,d)be a compact and connected metric space and letF be a left re- versible semigroup of self-mappings inXsuch that each f inFis a local contraction. Then Fhas both a unique fixed pointwXand diminishing orbital diameters. Moreover, for any xXand f F, the sequence of iterates{fnx}n∈Nconverges tow.

Proof. Letf be inF. We now show thatf has a unique fixed point inX. The compactness ofXensures that there existrf >0 andmf <1 such that

d(f x,f y)mfd(x,y) (2.11)

for allx,yXwithd(x,y)< rf. Condition (2.11) ensures that f is continuous. Assume thatV1,V2,. . .,Vnf are a fixed finite open cover ofXwith sets of diameters less thanrf. For anyx,yX, the connectedness ofXimplies that there is a chain of open sets fromx toy, chosen from the setsV1,V2,. . .,Vnf. This means thatd(x,y)nfrf. It follows from (2.11) thatd(f x,f y)mfnfrf. It is easy to check that

dfkx,fky

mfknfrf (2.12)

for allkN. By choosingkso large that (mf)knf<1, we infer thatδd(fkX)< rf. So the mapping f restricted to the setfkX, which maps fkXto itself, is a contraction. Note that fkXis closed. By the Banach contraction theorem, the restricted mapping has a unique fixed pointwf fkX. Obviously,wf is a unique fixed point of f inX. In view of (2.12), we have

δdfjX,wfδdfjX

mfjnfrf (2.13)

for alljN. Therefore,

limj→∞δdfjX,wf=0, (2.14) which implies that both limj→∞fjx=wf and f has diminishing orbital diameters.

Let f andg be inF. Then there existwf,wgXsuch thatwf = f wf,wg=gwg, and (2.14) and the following equation hold:

limj→∞δdgjX,wg=0. (2.15) GivenjN, it follows from the left reversibility ofFthat there areaj,bjFwithfjaj= gjbj. From (2.14) and (2.15), we infer that

dwf,wg

dwf,fjajx+dgjbjx,wg

δdwf,fjX+δdgjX,wg

−→0 asj−→ ∞.

(2.16)

This means thatwf =wg. That is,F has a unique fixed point inX. This completes the

proof.

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Remark 2.8. Theorem 2.7is a generalization of [22, Theorem 1].

Now we like to give two concrete examples for Theorems2.4and2.7.

Example 2.9. LetX= {0, 2/3} ∪ {1/n:nN}with the usual metricd. Define f,g:X Xby

f0= f2

3=g0=g2

3=g1=0, f1 n=

1

n+ 1, g 1 n+ 1=

1

n+ 2 (2.17) for allnN. Obviously,g f = f2, f g=g2,g f1=1/3=0= f g1, (X,d) is a compact metric space, and f andg are closed. LetF be the semigroup generated by f and g.

Now for anya,bF, there exista1,. . .,ak,b1,. . .,bn∈ {f,g}witha=a1···ak andb= b1···bn. Hence,ab=(bn)n+k=b(bn)k. ThusFis near commutative, and therefore it is left reversible also. But it is not commutative. Note thatsFsX= {0}. It is easy to verify that

d(f x,f y)1

2<1=δd

su:uFxF y,sHF

(2.18)

for allx,yXwithf x=f y. Hence,Fsatisfies the conditions ofTheorem 2.4and clearly 0 is the unique fixed point ofF.

Example 2.10. LetX=[0, 1] with the usual metricd. Define f,g:XXby f x=1

2x, gx=2

3x (2.19)

for allxX. Then (X,d) is a compact and connected metric space, f g=g f, and any one of f andgis a local contraction. LetFbe the semigroup generated by f andg. It is easy to see that every element inFis a local contraction and thatFis commutative. It follows fromTheorem 2.7thatFhas a unique fixed point.

3. Common fixed points for near-commutative semigroups in complete metric spaces Lemma3.1 (see [15]). Ifφis inΦ, thenlimn→∞φn(t)=0.

Lemma3.2 (see [2]). Ifφ:R+R+is an upper semicontinuous function withφ(0)=0 andφ(t)< tfort >0, then there exists a strictly increasing continuous functionψ:R+R+ such thatψ(0)=0andφ(t)ψ(t)< tfort >0.

Theorem3.3. LetFandGbe near-commutative semigroups of closed self-mappings in a complete metric space(X,d). Assume that the following conditions are satisfied:

(i)for anyxX,FxandGxare bounded;

(ii)there existsφΦsuch that, for anyf F,gG, there arenf,mgNsatisfying dfpx,gqyφδd(Fx,Gy) (3.1) for allx,yXandpnf,qmg.

ThenFandGhave both a unique common fixed pointwXand diminishing orbital diam- eters. Moreover, for each f FGandxX, the sequence of iterates{fnx}n∈Nconverges tow.

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Proof. We assert that, for any f F,gG,x,yX, andkmax{nf,mg},

δdF fkx,Ggkyφδd(Fx,Gy). (3.2) TakeuF fkxandvGgky. Then there aresFandtGwithu=s fkxandv=tgky.

The near commutativity ofF andGensures that there existaF andbGsuch that s fk=fkaandtgk=gkb. It follows from (3.1) that

d(u,v)=ds fkx,tgky=dfkax,gkby

φδd(Fax,Gby)φδd(Fx,Gy), (3.3) which implies that

δd

F fkx,Ggky=supd(u,v) :uF fkx,vGgky

φδd(Fx,Gy) (3.4)

for anyx,yXandkmax{nf,mg}. That is, (3.2) holds. For anyx,yXandk∈ {0} ∪ N, putak=δd(F fkmax{nf,mg}x,Ggkmax{nf,mg}y). It follows from (3.2), (i), andLemma 3.1 that

akφδdF f(k1) max{nf,mg}x,Gg(k1) max{nf,mg}y

=φak1

≤ ··· ≤φka0

=φkδd(Fx,Gy)

−→0 ask−→ ∞.

(3.5)

Let n be in N. Then there exist k,r∈ {0} ∪N and r <max{nf,mg} such that n= kmax{nf,mg}+r. In view of (3.5), we have

δdF fnx,GgnyδdF fkmax{nf,mg}x,Ggkmax{nf,mg}y

φak1

ak1−→0 asn−→ ∞. (3.6) This implies that

maxδd

F fnxd

Ggny

maxδd

F fnx,gn+1y+δd

gn+1y,F fnxd

Ggny,fn+1x+δd

fn+1x,Ggny

d

F fnx,Ggny−→0 asn−→ ∞.

(3.7) Therefore,F andG have diminishing orbital diameters. Note that {fn+ix}i∈NF fnx and{gn+iy}i∈NGgny. So{fnx}n∈Nand{gny}n∈Nare Cauchy sequences. Since (X,d) is complete,{fnx}n∈Nand{gny}n∈Nconverge to some pointsw,bX, respectively. Con- sequently,w∈ ∩n∈NF fnxandb∈ ∩n∈NGgny. It follows from (3.6) that

d(w,b)δd

F fnx,Ggny−→0 asn−→ ∞. (3.8)

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That is,w=b. The closedness of f andgimplies thatw= f wandb=gb. Hence, f and g have a common fixed pointw. By arbitrariness of f andg, we conclude thatFandG have a common fixed pointw.

Suppose thatFandGhave also a common fixed pointvX. By virtue of (3.1), for any f FandgG, we have

d(w,v)=dfnfw,gmgvφδd(Fw,Gv)=φd(w,v), (3.9)

which implies thatw=v. This completes the proof.

Theorem3.4. LetFbe near-commutative semigroup of closed self-mappings in a complete metric space(X,d). Assume that the following conditions are satisfied:

(iii)for anyxX,Fxis bounded;

(iv)there existsφΦsuch that, for anyf F, there isnf Nsatisfying

dfpx,fqxφδd(Fx) (3.10) for allxXandp,qnf.

ThenF has both a fixed point inXand diminishing orbital diameters. Moreover, for each f FandxX, the sequence of iterates{fnx}n∈Nconverges to some fixed point ofF.

Proof. It follows from (3.10) that (3.1) is satisfied forF=G,x=y, f =g, andnf =mg. ThusTheorem 3.4follows fromTheorem 3.3. This completes the proof.

Theorem3.5. LetFbe near-commutative semigroup of closed self-mappings in a complete metric space(X,d). Assume that condition (iii) and the following condition (v) hold:

(v)there existsφΦsuch that, for anyf F, there isnf Nsatisfying

dfpx,fqyφδd(FxF y) (3.11) for allx,yXandp,qnf.

ThenFhas both a unique common fixed pointwXand diminishing orbital diameters.

Moreover, for each f FandxX, the sequence of iterates{fnx}n∈Nconverges tow.

Proof. Note that (3.11) implies that both (3.10) is satisfied andF has at most one fixed point inX. ThusTheorem 3.5follows fromTheorem 3.4. This completes the proof.

Remark 3.6. It follows fromLemma 3.2thatTheorem 3.5extends [16, Theorem 2.1].

Theorem3.7. LetFandGbe near-commutative semigroups of self-mappings in a complete metric space(X,d). Assume that condition (i) and the following condition hold:

(vi)there existsφΦsuch that, for any f F,gGandx,yX,

d(f x,g y)φδd(Fx,Gy). (3.12) ThenFandGhave both a unique common fixed pointwXand diminishing orbital diam- eters. Moreover, for each f FGandxX, the sequence of iterates{fnx}n∈Nconverges tow.

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Proof. Let f andg be inFandG, respectively. As in the proof ofTheorem 3.3, we infer easily that there exists a unique pointwXsuch that

nlim→∞fnx=lim

n→∞gny=w, lim

n→∞δd

F fnx=lim

n→∞δd

Ggny=0 (3.13) for allx,yX. Thus,FandGhave diminishing orbital diameters and

nlim→∞fnx=lim

n→∞gnw=w, lim

n→∞δdF fnw=lim

n→∞δdGgnw=0. (3.14) Sincew(n∈NF fnw)(n∈NGgnw), it follows that

maxδdF fnw,wdGgnw,wmaxδdF fnwdGgnw (3.15) for allnN. Using (3.14) and (3.15), we have

nlim→∞δd

F fnw,w=lim

n→∞δd

Ggnw,w=0. (3.16)

Let>0 be arbitrary. By virtue of (3.14) and (3.16), there existskNsuch that, for all nk,

maxdw,fn+1w,dw,gn+1wd

F fnw,wd

Ggnw,w<. (3.17) For anyhG, from (3.12) and (3.17), we immediately conclude that

d(w,hw)dw,fn+1w+dfn+1w,hw+φδd

F fnw,Gw

+φδd

F fnw,w+δd(w,Gw)+φ+δd(w,Gw), (3.18) which implies that

δd(w,Gw)+φ+δd(w,Gw). (3.19) Letting 0 in the above inequality, we obtain that δd(w,Gw)φ(δd(w,Gw)). This means thatδd(w,Gw)=0. That is,Gw= {w}. Similarly,Fw= {w}. Therefore,FandG have a common fixed pointw. The uniqueness of common fixed point ofFandGfollows

immediately from (3.12). This completes the proof.

From Theorems3.5and3.7, we have the following.

Theorem3.8. LetFbe a near-commutative semigroup of self-mappings in a complete met- ric space(X,d). Assume that condition (iii) and the following condition (vii) hold:

(vii)there existsφΦsuch that, for anyf Fandx,yX,

d(f x,f y)φδd(FxF y). (3.20) ThenFhas both a unique common fixed pointwXand diminishing orbital diameters.

Moreover, for each f FandxX, the sequence of iterates{fnx}n∈Nconverges tow.

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Corollary3.9. Let f be a self-mapping of a complete metric space(X,d)and satisfy the following:

(viii)for eachxX,Of(x)is bounded;

(ix)there existsφΦsuch that, for anyx,yX,

d(f x,f y)φδdOf(x,y). (3.21) Then f has both a unique fixed pointwXand diminishing orbital diameters. Moreover, the sequence of iterates{fnx}n∈Nconverges towfor eachxX.

Proof. PutF= {fn:nN}. Condition (3.21) ensures that dfnx,fnyφδdOffn1x,fn1y

φδdOf(x,y)=φδd(FxF y) (3.22) for allnNandx,yX. SoCorollary 3.9follows fromTheorem 3.8. This completes

the proof.

Remark 3.10. Theorem 3.8extends, improves, and unifies [4, Theorem 2], [13, Theorem 5], and [19, Theorem 1].

4. Applications

Throughout this section, let (X, · X) be a real Banach space andI=[a,b]R. Define C(I,X)= {f :f :I−→Xis continuous},

C(I×I×X,X)= {f :f :I×I×X−→Xis continuous}, fC=sup

tI

f(t)X

(4.1)

for all f C(I,X). It is easy to verify that (C(I,X), · C) is a real Banach space also.

Now we investigate the existence problem of common solutions for nonlinear Volterra integral equations of the from

xα(t)=v(t) +λ t

aKα

t,s,xα(s)ds, αA,tI,

yβ(t)=v(t) +λ t

aMβ

t,s,yβ(s)ds, βB,tI,

(4.2)

wherev(t)C(I,X) is a given function,λRis an arbitrary parameter,KαandMβare inC(I×I×X,X),AandBare index sets.

Theorem4.1. LetF= {fα:αA}andG= {gβ:βB}be near-commutative semigroups and satisfy the following:

(i)for anyxC(I,X),max{δ·X(Fx),δ·X(Gx)}<;

(ii)there existsL >0such that, for anyαA,βB,x,yC(I,X), andt,sI, Kα

t,s,x(s)Mβ

t,s,y(s)X·X(Fx,Gy), (4.3)

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where

fαx(t)=v(t) +λ t

aKαt,s,x(s)ds, αA,xC(I,X),tI, gβy(t)=v(t) +λ

t

aMβ

t,s,y(s)ds, βB, yC(I,X),tI.

(4.4)

Then (4.2) have a unique common solutionwC(I,X). Moreover, for eachαA,βB, andxC(I,X), the sequences defined by

fαn

x(t)=v(t) +λ t

aKα

t,s,fαn1

x(s)ds, tI,nN, gβnx(t)=v(t) +λ

t

aMβt,s,gβn1x(s)ds, tI,nN,

(4.5)

converge to the unique solutionwin the norm · C.

Proof. For anyxC(I,X), definex=suptIe(1+|λ|)Ltx(t)X. It is easy to show that e(1+|λ|)LbxCxe(1+|λ|)LaxC. (4.6) Therefore, the norm · and the sup-norm · Care equivalent to each other. Obvi- ously, (C(I,X), · ) is also a real Banach space. Note that allfαandgβare self-mappings of (C(I,X), · ). In view of (4.3) and (4.5), we infer that, for all αA,βB, and x,yC(I,X),

fαx(t)gβy(t)

=sup

tI

e(1+|λ|)Lt|λ| t

a

Kα

t,s,x(s)Mβ

t,s,y(s)ds

X

≤ |λ|sup

tI

e(1+|λ|)Lt t

a

Kα

t,s,x(s)Mβ

t,s,y(s)Xds

≤ |λ|sup

tI

t

ae(1+|λ|)L(st)e(1+|λ|)LsKαt,s,x(s)Mβt,s,y(s)Xds

≤ |λ|sup

tI

t

ae(1+|λ|)L(st)sup

sI

e(1+|λ|)Ls·X(Fx,Gy)ds

≤ |λ|Lsup

tI

t

ae(1+|λ|)L(st)δ·(Fx,Gy)ds

|λ|

1 +|λ|δ·X(Fx,Gy) sup

tI

1e(1+|λ|)L(at)

= |λ|

1 +|λ| 1e(1+|λ|)L(ab)δ·X(Fx,Gy)

=φδ·(Fx,Gy),

(4.7)

参照

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