21(2005), 49–54 www.emis.de/journals ISSN 1786-0091
SOME SUBCLASSES OF α-UNIFORMLY CONVEX FUNCTIONS
MUGUR ACU
Abstract. In this paper we define some subclass ofα - uniformly convex functions with respect to a convex domain included in right half planeD.
1. Introduction
LetH(U) be the set of functions which are regular in the unit discU, A={f ∈ H(U) :f(0) =f0(0)−1 = 0},
Hu(U) ={f ∈ H(U) :f is univalent inU} andS={f ∈A:f is univalent inU}.
Let consider the integral operatorLa: A→Adefined as:
(1) f(z) =LaF(z) = 1 +a za
Zz
0
F(t)·ta−1dt, a∈C, Re a≥0.
In the casea= 1,2,3, . . . this operator was introduced by S.D. Bernardi and it was studied by many authors in different general cases.
LetDn be the S˘al˘agean differential operator (see [10]) defined as:
Dn:A→A, n∈NandD0f(z) =f(z) D1f(z) =Df(z) =zf0(z), Dnf(z) =D(Dn−1f(z)).
2. Preliminary results
Definition 2.1 ([4]). Let α ∈[0,1] andf ∈ A. We say thatf is α - uniformly convex function if:
Re
½
(1−α)zf0(z) f(z) +α
µ
1 +zf00(z) f0(z)
¶¾
≥
¯¯
¯¯(1−α)
µzf0(z) f(z) −1
¶
+αzf00(z) f0(z)
¯¯
¯¯ , z∈U.
We denote this class withU Mα.
2000Mathematics Subject Classification. 30C45.
Key words and phrases. Alexander integral operator, Briot-Bouquet differential subordination, Ruscheweyh operator.
49
u v
β >1
β = 1 0< β <1
γ β= 0
Figure 1
Remark 2.1. Geometric interpretation: f ∈U Mα if and only if J(α, f;z) = (1−α)zf0(z)
f(z) +α µ
1 + zf00(z) f0(z)
¶
take all values in the parabolic region Ω ={w:|w−1| ≤Re w}={w=u+iv:v2≤ 2u−1}. We haveU M0 =SP, where the classSP was introduced by F. Ronning in [9] and U Mα ⊂Mα, whereMα is the well know class of α - convex functions introduced by P.T. Mocanu in [8].
Definition 2.2 ([1]). Letα∈[0,1] andn∈N. We say thatf ∈A is in the class U Dn,α(β, γ),β≥0,γ∈[−1,1), β+γ≥0 if
Re
·
(1−α)Dn+1f(z)
Dnf(z) +αDn+2f(z) Dn+1f(z)
¸
≥β
¯¯
¯¯(1−α)Dn+1f(z)
Dnf(z) +αDn+2f(z) Dn+1f(z)−1
¯¯
¯¯+γ.
Remark 2.2. Geometric interpretation: f ∈U Dn,α(β, γ) if and only if Jn(α, f;z) = (1−α)Dn+1f(z)
Dnf(z) +αDn+2f(z) Dn+1f(z)
take all values in the convex domain included in right half planeDβ,γ, whereDβ,γ is an elliptic region forβ >1, a parabolic region forβ= 1, a hyperbolic region for 0< β <1, the half planeu > γ forβ = 0. (Figure 1.)
We haveU D0,α(1,0) =U Mα.
The next theorem is result of the so called “admissible functions method” intro- duced by P.T. Mocanu and S.S. Miller (see [5], [6], [7]).
Theorem 2.1. Let h convex in U and Re[βh(z) +δ] > 0, z ∈ U. If p ∈ H(U) with p(0) = h(0) and p satisfied the Briot-Bouquet differential subordina- tionp(z) + zp0(z)
βp(z) +δ ≺h(z), thenp(z)≺h(z).
Definition 2.3 ([3]). The function f ∈ A is n-starlike with respect to convex domain included in right half planeDif the differential expression Dn+1f(z)
Dnf(z) takes values in the domainD.
If we considerq(z) an univalent function withq(0) = 1, Re q(z)>0,q0(0)>0 which maps the unit discU into the convex domainD we have:
Dn+1f(z)
Dnf(z) ≺q(z).
We note bySn∗(q) the set of all these functions.
3. Main results
Letq(z) be an univalent function withq(0) = 1,q0(0)>0, which maps the unit discU into a convex domain included in right half planeD.
Definition 3.1. Let f ∈ A and α ∈ [0,1]. We say that f is α-uniform convex function with respect toD, if
J(α, f;z) = (1−α)zf0(z) f(z) +α
µ
1 + zf00(z) f0(z)
¶
≺q(z).
We denote this class withU Mα(q).
Remark 3.1. Geometric interpretation: f ∈U Mα(q) if and only if J(α, f;z) take all values in the convex domain included in right half planD.
Remark 3.2. We haveU Mα(q)⊂Mα, whereMαis the well know class ofα-convex function. If we takeD= Ω (see Remark 2.1) we obtain the classU Mα.
Remark 3.3. From the above definition it easily results thatq1(z)≺q2(z) implies U Mα(q1)⊂U Mα(q2).
Theorem 3.1. For allα, α0 ∈[0,1]with α < α0 we have U Mα0(q)⊂U Mα(q).
Proof. Fromf ∈U Mα0(q) we have (2) J(α0, f;z) = (1−α0)zf0(z)
f(z) +α0 µ
1 + zf00(z) f0(z)
¶
≺q(z),
where q(z) is univalent inU with q(0) = 1,q0(0) >0, and maps the unit discU into the convex domain included in right half planeD.
With notation zf0(z)
f(z) =p(z), wherep(z) = 1 +p1z+. . . we have:
J(α0, f;z) =p(z) +α0·zp0(z) p(z) . From (2) we have p(z) +α0· zp0(z)
p(z) ≺q(z) with p(0) = q(0) and Re q(z)>0, z∈U.
In this conditions from Theorem 2.1, withδ= 0, we obtainp(z)≺q(z), orp(z) take all values inD.
If we consider the functiong: [0, α0]→C,g(u) =p(z) +u·zp0(z)
p(z) , withg(0) = p(z)∈D andg(α0) =J(α0, f;z)∈D. Since the geometric image ofg(α) is on the segment obtained by the union of the geometric image ofg(0) andg(α0), we have g(α)∈D orp(z) +αzp0(z)
p(z) ∈D.
Thus J(α, f;z) take all values in D, or J(α, f;z) ≺ q(z). This means f ∈
U Mα(q). ¤
Theorem 3.2. If F(z)∈U Mα(q) thenf(z) =La(F)(z)∈S0∗(q), where La is the integral operator defined by (1) andα∈[0,1].
Proof. From (1) we have
(1 +a)F(z) =af(z) +zf0(z).
With notation zf0(z)
f(z) =p(z), wherep(z) = 1 +p1z+. . . we have zF0(z)
F(z) =p(z) + zp0(z) p(z) +a. If we denote zF0(z)
F(z) =h(z), withh(0) = 1, we have fromF(z)∈U Mα(q) (see Definition 3.1):
h(z) +α·zh0(z)
h(z) ≺q(z),
where q(z) is univalent unU with q(0) = 1, q0(z)>0 and maps the unit disc U into the convex domain included in right half planeD.
From Theorem 2.1 we obtainh(z)≺q(z) orp(z) + zp0(z)
p(z) +a ≺q(z).
Using the hypothesis and the construction of the functionq(z) we obtain from Theorem 2.1 zf0(z)
f(z) =p(z)≺q(z) orf(z)∈S0∗(q)⊂S∗. ¤ Definition 3.2. Letf ∈A,α∈[0,1] andn∈N. We say thatf isα−n-uniformly convex function with respect toD if
Jn(α, f;z) = (1−α)Dn+1f(z)
Dnf(z) +αDn+2f(z)
Dn+1f(z) ≺q(z).
We denote this class withU Dn,α(q).
Remark 3.4. Geometric interpretation: f ∈U Dn,α(q) if and only ifJn(α, f;z) take all values in the convex domain included in right half planeD.
Remark 3.5. We haveU D0,α(q) =U Mα(q) and if in the above definition we con- siderD=Dβ,γ (see Remark 2.2) we obtain the class U Dn,α(β, γ).
Remark 3.6. It is easy to see thatq1(z)≺q2(z) impliesU Dn,α(q1)⊂U Dn,α(q2).
Theorem 3.3. For allα, α0 ∈[0,1]with α < α0 we have U Dn,α0(q)⊂U Dn,α(q).
Proof. Fromf ∈U Dn,α0(q) we have:
(3) Jn(α0, f;z) = (1−α0)Dn+1f(z)
Dnf(z) +α0Dn+2f(z)
Dn+1f(z) ≺q(z),
where q(z) is univalent inU with q(0) = 1,q0(0) >0, and maps the unit discU into the convex domain included in right half planeD.
With notation Dn+1f(z)
Dnf(z) =p(z), wherep(z) = 1 +p1z+. . . we have Jn(α0, f;z) =p(z) +α0·zp0(z)
p(z) . From (3) we have p(z) +α0· zp0(z)
p(z) ≺q(z) with p(0) = q(0) and Re q(z)>0, z∈U. In this condition from Theorem 2.1 we obtain p(z)≺q(z), orp(z) take all values inD.
If we consider the function
g: [0, α0]→C, g(u) =p(z) +u·zp0(z) p(z) ,
withg(0) =p(z)∈D andg(α0) =Jn(α0, f;z)∈D, it easy to see that g(α) =p(z) +αzp0(z)
p(z) ∈D.
Thus we haveJn(α, f;z)≺q(z) orf ∈U Dn,α(q). ¤ Theorem 3.4. If F(z)∈ U Dn,α(q) then f(z) = La(F)(z) ∈S∗n(q), where La is the integral operator defined by (1).
Proof. From (1) we have (1 +a)F(z) =af(z) +zf0(z). By means of the application of the linear operatorDn+1 we obtain:
(1 +a)Dn+1F(z) =aDn+1f(z) +Dn+1(zf0(z)) or
(1 +a)Dn+1F(z) =aDn+1f(z) +Dn+2f(z).
With notation Dn+1f(z)
Dnf(z) =p(z), wherep(z) = 1 +p1z+. . ., we have:
Dn+1F(z)
DnF(z) =p(z) + 1
p(z) +a·zp0(z).
If we denote Dn+1F(z)
DnF(z) =h(z), withh(0) = 1, we have from F∈U Dn,α(q):
h(z) +αzh0(z)
h(z) ≺q(z),
where q(z) is univalent inU with q(0) = 1,q0(0) >0, and maps the unit discU into the convex domain included in right half planeD.
From Theorem 2.1 we obtainh(z)≺q(z) orp(z) + zp0(z)
p(z) +a ≺q(z).
Using the hypothesis we obtain from Theorem 2.1 p(z)≺q(z) orf(z)∈Sn∗(q).
¤
Remark 3.7. If we consider D=Dβ,γ in Theorem 3.3 and Theorem 3.4 we obtain the main results from [1] and if we takeD =Dβ,γ and α= 0 in Theorem 3.4 we obtain the Theorem 3.1 from [2].
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Received March 24, 2004.
Department of Mathematics, University Lucian Blaga of Sibiu, Str. Dr. I. Rat.iu, No. 5-7, 550012 - Sibiu, Romania
E-mail address:acu [email protected]