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Volume 2012, Article ID 240432,18pages doi:10.1155/2012/240432

Research Article

Instability Induced by Cross-Diffusion in a Predator-Prey Model with Sex Structure

Shengmao Fu and Lina Zhang

Department of Mathematics, Northwest Normal University, Lanzhou 730070, China

Correspondence should be addressed to Lina Zhang,[email protected] Received 26 July 2011; Accepted 15 January 2012

Academic Editor: Junjie Wei

Copyrightq2012 S. Fu and L. Zhang. This is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited.

In this paper, we consider a cross-diffusion predator-prey model with sex structure. We prove that cross-diffusion can destabilize a uniform positive equilibrium which is stable for the ODE system and for the weakly coupled reaction-diffusion system. As a result, we find that stationary patterns arise solely from the effect of cross-diffusion.

1. Introduction

Sex ratio means the comparison between the number of male and female in the species. The sex ratio is generally regarded as 1 : 1. But for wildlife, the sex ratio of species varies with the category, environment condition, community behavior, orientation and heredity, and so forth.

The animal’s sex ratio in the different life history stages may vary with different animals. Take a bird as an example: the number of the older males is larger than that of the older females with the increase in age, which is contrary to the case of the mammal where the number of the older females is larger than that of the older males with the increase in age1,2. Sex ratio is the basis of analyzing the dynamic state of different species, the variation of which has a huge influence on the dynamic state of the species1–7. Abrahams and Dill5have provided evidence that male and female guppies forage differently in the presence of predators and that sexual differences in the energetic equivalence of the risk of predation exist. Eubanks and Miller6have found that female Gladicosa pulchraLycosidaewolf spiders climb trees significantly more often than males in the presence of forest floor predators. It is found that the sex of voles affects the risk of predation by mammals and female voles are more easily predated than male voles in7.

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Incorporating the sex of prey in a classical Lotka-Volterra model, Liu et al.1con- sidered the following sex-structure model:

ut b1vuD1kukvc1w, vt vb2D2kukvc1w,

wt w−D3c2uc2vc3w,

1.1

whereu,v, and w are the population densities of the male prey, the female prey, and the predator species respectively. The parametersD1,D2, andD3are their mortality rates,b1and b2are the birth rates of the male prey and the female prey,c1 andc2 are the predation rate and the conversion rate of the predators, andkandc3are the intraspecific competition rates of the prey and predators. All the parameters in model1.1are positive.

Ifβ b2D2 > 0, then two obvious nonnegative equilibria of model1.1areu0 0,0,0andu1 u1, v1,0, where

u1 b1β k

b1D1β, v1 β D1β k

b1D1β. 1.2

Moreover, model1.1has a positive equilibrium if and only if

R:c2βkD3>0. H1

In this case the positive equilibrium is uniquely given byu u, v, w, where

u b1

c3βc1D3 b1D1β

c3kc1c2, v

D1β

c3βc1D3 b1D1β

c3kc1c2,

w c2βkD3 c3kc1c2

.

1.3

It turns out thatRplays an important role in determining the stability ofu1andu1. To be precise,u1 is locally asymptotically stable ifR < 0, whileu is locally asymptotically stable ifR > 0. This shows that a uniform coexistence state exists and is stable when the intrinsic growth rateβof the female prey is larger than the critical valuekD3/c2.

Taking account of the inhomogeneous distribution of the prey and the predator in different spatial locations within a fixed bounded domainΩat any given time, and the natural tendency of each species to diffuse to areas of smaller population concentration, Liu and Zhou in8investigated the following weakly coupled reaction-diffusion system:

utd1Δub1vuD1kukvc1w, x∈Ω, t >0, vtd2Δvv

βkukvc1w

, x∈Ω, t >0, wtd3Δww−D3c2uc2vc3w, x∈Ω, t >0,

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ηux, t ∂ηvx, t ∂ηwx, t 0, x∂Ω, t >0, ux,0 u0x, vx,0 v0x, wx,0 w0x, x∈Ω,

1.4

whereηis the outward unit normal vector of the boundary∂Ωwhich is smooth,η ∂/∂η. The homogeneous Neumann boundary condition indicates that the predator-prey system is self-contained with zero population flux across the boundary. The constantsd1,d2, andd3, called diffusion coefficients, are positive, and the initial valuesu0x,v0x, andw0xare nonnegative smooth functions which are not identically zero. Liu and Zhou in8found that the nonnegative constant steady states have the same stability properties as the ODE model 1.1. Therefore, Turing instability cannot occur for this reaction-diffusion system.

However, in model 1.4, only diffusion of each individual species is taken into account. In some cases, the reality is that the female prey is easily predated because of physiological factor, while the male prey can congregate and form a huge group to protect itself from the attack of the predators 7, 9; therefore, the predators tend to keep away from their male prey. Similarly as in 10–12, we model this by the cross-diffusion term Δd3wd4uwfor the predators, whered4 > 0, called the cross-diffusion coefficient. Thus, the cross-diffusion system that we will study is the following:

utd1Δub1vuD1kukvc1w:G1u, v, w, x∈Ω, t >0, vtd2Δvv

βkukvc1w

:G2u, v, w, x∈Ω, t >0, wt−Δd3wd4uw w−D3c2uc2vc3w:G3u, v, w, x∈Ω, t >0,

ηux, t ∂ηvx, t ∂ηwx, t 0, x∂Ω, t >0, ux,0 u0x, vx,0 v0x, wx,0 w0x, x∈Ω.

1.5

To our knowledge, only a few works investigated the effect of cross-diffusion on population structure and dynamics in the above model. Recently, H. Xu and S. Xu in13investigated the global existence of solutions for the corresponding full SKT model of1.5when the space dimension is less than ten.

An interesting feature of1.5is that the interaction between the predators and the male prey gives rise to a cross-diffusion term. The resulting mathematical model is a strongly coupled system of three equations which is mathematically much more complex than those considered earlier. In this paper, we will show that cross-diffusion can destabilize the uniform equilibriumu which is stable for models 1.1and1.4. Moreover, we will demonstrate that the nonlinear dispersive force can give rise to a spatial segregation of these species.

Our paper is organized as follows. InSection 2, we analyze the local stability of u for1.5and calculate the fixed point index, which is important for our later discussions on the existence of nonconstant positive steady states. InSection 3, we prove global asymptotic stability ofu with d4 0, that is, when no cross-diffusion occurs in the model. This implies that cross-diffusion has a destabilizing effect. InSection 4, we establish a priori upper and lower bounds for all possible positive steady states of1.5. InSection 5, we study the global existence of nonconstant positive steady states of1.5for suitable values of the parameters.

This is done by using the Leray-Schauder degree theory and the results obtained in Sections2,

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3, and 4. InSection 6, we discuss the nonexistence of nonconstant positive steady states of 1.5. In the last section, we give a brief discussion about our model.

2. Local Stability Analysis and Fixed Point Index of u

Letu u, v, wT,Φu d1u, d2v, d3wd4uwT, andGu G1u, G2u, G3uT. Then the stationary problem of1.5can be written as

−ΔΦu Gu inΩ; ηu0 on ∂Ω. 2.1

In this section, we study the linearization of2.1atu and calculate the fixed point index.

Similar to14,15, let 0μ1 < μ2< μ3 < μ4· · · be the eigenvalues of the operator−Δ onΩwith the homogeneous Neumann boundary condition, and letibe the eigenspace corresponding toμi inH1Ω. Let{φij :j 1,2, . . . ,dimi}be the orthonormal basis of i,X H1Ω3, andXij{cφij :c∈R3}. Then

X

i1Xi, XidimEμi

j1 Xij. 2.2

LetY C1Ω3,Y{u∈Y :u, v, w >0 onΩ}, andBC {u∈Y :C−1< u, v, w < Con Ω}forC > 0. Since detΦuu d1d2d3d4u >0 for all nonnegativeu,Φ−1u uexists and det{Φ−1u u}is positive. Hence,u is a positive solution to2.1if and only if

Fu:u−I−Δ−1

Φ−1u uGu ∇uΦuuu∇u u

0 inY, 2.3

whereI−Δ−1is the inverse ofI−Δunder homogeneous Neumann boundary conditions.

Further, we note thatDuFu I−I−Δ−1−1u uGuu I}andλis an eigenvalue ofDuFuif and only if, for somei≥1, it is an eigenvalue of the matrix

Bi:I− 1 1μi

Φ−1u uGuu I 1 1μi

μiI−Φ−1u uGuu . 2.4

Writing

H μ

H u;μ

:det

μI−Φ−1u uGuu

, 2.5

we see that if i/0, then for each integer 1 ≤ j ≤ dimi, the number of negative eigenvalues ofDuFuonXij is odd if and only ifi<0. As a consequence, we have the following proposition.

Proposition 2.1see16. Suppose that, for alli1,Hμi/0. Then

indexF·,u −1 γ, 2.6

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where

γ

i≥1,Hμi<0 dimE

μi

. 2.7

To facilitate our computation of indexF·,u, we need to determine the sign of i. In particular, as the aim of this paper is to study the existence of stationary patterns of2.1 with respect to the cross-diffusion coefficientd4, we will concentrate on the dependence of i ond4. At this point, we note that det{Φ−1u u}det{μΦuuGuu}. Since det{Φ−1u u}is positive, we will need only to consider det{μΦuuGuu}. By

Guu

⎜⎜

−kuD1β b1ku −c1u

−kv −kv −c1v c2w c2w −c3w

⎟⎟

, Φuu

⎜⎜

d1 0 0

0 d2 0

d4w 0 d3d4u

⎟⎟

, 2.8

we have

det

μΦuuGuu

C3d4μ3C2d4μ2C1d4μ−detGuu :C

d4;μ

, 2.9

where

C3d4 d1d2d3d4u,

C2d4 d1d2c3wd1kd3d4u vd2d3d4u

kuD1β

d2d4c1uw, C1d4 d1kc3vw d2c3

kuD1β

w d3d4u

kuD1β

kvd4c1vwk ub1

c1u−d 2c2wkd4vw c1c2d1vw−d3d4uk vk ub1, detGuu vw

−kc3c1c2

kuD1β

c1c2kc3kub1 .

2.10

Notice thatkub1 < 0; thus detGuu < 0. We consider the dependence of Con d4. Let

μ1d4,μ2d4, andμ3d4be the three roots ofCd4;μ 0 with Re{μ1d4} ≤Re{μ2d4} ≤ Re{μ3d4}. It follows thatμ1d4μ2d4μ3d4 <0 from detGuu< 0. Thus, amongμ1d4,

μ2d4,μ3d4at least one is real and negative, and the product of the other two is positive.

Consider the following limits:

dlim4→ ∞

C3d4

d4 d1d2u:a3,

dlim4→ ∞

C2d4

d4 d1kuvd2u

kub1v u

d2c1uw d1kuvd2

ku2b1vc1uw :a2,

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dlim4→ ∞

C1d4 d4 u

kub1v u

kvc1vwk ub1c1uk vwuk vkub1 b1v

β−2c1w :a1.

2.11

Therefore,a1<0 if

β <2c1w. H2

In the following, we restrict our attention toβ <2c1w. In this range, a1<0 andC1d4<0 for all sufficiently larged4. Notice that

dlim4→ ∞

C d4;μ

d4 a3μ3a2μ2a1μμ

a3μ2a2μa1

2.12

and a1 < 0 < a3. A continuity argument shows that, when d4 is large, μ1d4 is real and negative. Furthermore, asμ2d4μ3d4>0,μ2d4andμ3d4are real and positive, and

dlim4→ ∞μ1d4

−a2

a22−4a1a3

2a3

<0,

dlim4→ ∞μ2d4 0,

dlim4→ ∞μ3d4

−a2

a22−4a1a3

2a3 :μ > 0.

2.13

Thus we have the following proposition.

Proposition 2.2. Assume thatH1andH2hold. Then there exists a positive numberd4such that, whend4d4, the three rootsμ1d4,μ2d4,μ3d4ofCd4;μ 0 are all real and satisfy2.13.

Moreover, for alld4d4,

−∞1d4<02d43d4, C

d4;μ

<0, μ

−∞,μ1d4

μ2d4,μ3d4 , C

d4;μ

>0, μ

μ1d4,μ2d4

μ3d4,∞ .

2.14

Remark 2.3. Proposition 2.2 gives a criterion for the instability of u when μ > μ 2 and the cross-diffusion coefficientd4is large enough. We further check conditionsH1andH2. Let the parametersd1,d2,d3,b1,D1,k,c1,c2, andc3 be fixed. ConditionH1is equivalent to β > kD3/c2, and conditionH2is equivalent toβ >2kc1D31for someγ1:c1c2kc3 >0.

Notice that 2c11 > 1/c2, so there exists an unbounded region U1 {D3, β ∈ R2 : β >

2kc1D31}, such that for anyD3, βU1,u is an unstable equilibrium with respect to 1.5 whenμ > μ 2and the cross-diffusion coefficientd4is sufficiently large.

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3. Global Asymptotic Stability of u for 1.4

The aim of this section is to prove Theorem 3.2 which shows that model 1.4 has no nonconstant positive steady state no matter what the diffusion coefficientsd1,d2, andd3are;

in other words, diffusion alonewithout cross-diffusioncannot drive instability and cannot generate patterns for this predator-prey model. For this, we will make use of the following result.

Lemma 3.1see17. Letaandbbe positive constants. Assume thatϕ, ψC1a,∞,ψt0, andϕis bounded from below. Ifϕt≤ −bψtandψtis bounded ina,∞, then limt→ ∞ψt 0.

Theorem 3.2. Let the parametersd1,d2,d3,b1,D1,D3,k,c1,c2,c3, andβbe fixed positive constants that satisfyH1and

b21<4kuD 1b1. H3

Letu, v, wbe a positive solution of 1.4. Then

u·, t−u L2Ω−→0, v·, t−v L2Ω−→0,

w·, t−w L2Ω−→0 as t−→ ∞. 3.1 Proof. Notice from8thatu is uniformly and locally asymptotically stable in the sense of 18. We only need to prove the global stability ofu. Define

V1u, v, w 1 2

Ωu−u 2dxλ

Ω

vvvlnv v

dxρ

Ω

wwwlnw w

dx,

3.2 whereλu, ρc1u/c 2. Obviously,V1u, v, wis nonnegative andV1u, v, w 0 if and only ifu, v, w u, v, w. The time derivative of V1u, v, wfor the system1.4satisfies

dV1u, v, w

dt

Ω

u−uu tλvv

v vtρww w wt

dx:−I1t−I2t, 3.3

where I1t

Ω

d1|∇u|2λd2v

v2 |∇v|2ρd3w w2 |∇w|2

dx, I2t

Ω

D1kukukvc1wuu 2λkvv 2ρc3w−w 2

2kub1u−uvv dx,

Ω

D1kuuu 2λkvv 2ρc3w−w 2 2kub1u−uvv dx.

3.4

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If the matrix

⎜⎜

⎜⎜

D1ku 1

22kub1 0 1

22kub1 λk 0

0 0 ρc3

⎟⎟

⎟⎟

⎠ 3.5

is positive definite, then the quadratic form

D1kuuu 2λkvv 2ρc3w−w 2 2kub1u−uvv 3.6 is positive definite. A direct calculation shows that the matrix is positive definite ifH3holds.

Meanwhile, for everyδsuch that 0 < δ < min{c3ρ,4kuD 1b1b21/4D12ku}, we have

I2t≥δ

Ω

u−u 2 v−v 2 w−w 2 dx. 3.7

Thus,

dV1u, v, w

dt ≤ −δ

Ω

u−u 2 vv 2 ww 2 dx. 3.8

Similarly to19, Theorem 2.1, we can prove that the solutionu, v, wis bounded, and so are the derivatives of

Ωu−u 2 v−v 2 w−w 2dxby the equations in1.4. Using Lemma 3.1, we have

u·, t−u L2Ω−→0, v·, t−v L2Ω−→0,

w·, t−w L2Ω−→0 ast−→ ∞. 3.9 By the fact that V1u, v, w is decreasing fort ≥ 0, it is obvious that u, v, w is globally asymptotically stable, and the proof ofTheorem 3.2is completed.

Remark 3.3. Notice that conditionH3is equivalent to γ2β > b1kc3c1c2

4k −c1D3, γ2 3kb1c34kc3D1b1c1c2

4kb1D1 . 3.10

Ifγ2<0, it is easy to verify that−c12> k/c2. Hence, there exists an unbounded region U2

D3, β

∈R2:β > kD3

c2 , γ2β > b1kc3c1c2 4k −c1D3

, 3.11

such that for anyD3, βU2,u is the unique positive steady state with respect to 1.4.

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Remark 3.4. From Remarks2.3and3.3, there exists an unbounded region

U3U1U2 D3, β

∈R2 :γ1>0, β >2kc1 γ1

D3, γ2β > b1kc3c1c2 4k −c1D3

, 3.12

such that for anyD3, βU3, cross-diffusion can destabilize the uniform equilibriumu of 1.5whenμ > μ 2andd4is sufficiently large.

4. A Priori Estimates

In the following, the generic constantsC, C, and so forth, will depend on the domain Ω and the dimensionN. However, asΩand the dimensionNare fixed, we will not mention the dependence explicitly. Also, for convenience, we will writeΛ instead of the collective constants b1, D1, D3, c1, c2, c3, k, β. The main purpose of this section is to give a priori positive upper and lower bounds for the positive solutions to2.1whenR > 0. For this, we will cite the following two results.

Lemma 4.1Harnack’s inequality20. LetwC2Ω∩C1Ωbe a positive solution toΔwx cxwx 0, wherecCΩ, satisfying the homogeneous Neumann boundary condition. Then there exists a positive constantCwhich depends only oncsuch that maxΩwCminΩw.

Lemma 4.2maximum principle21. Letg×R1andbjCΩ,j1,2, . . . , N.

iIfwC2Ω∩C1Ωsatisfies

Δwx N

j1

bjxwxjgx, wx≥0 in Ω, ηw≤0 on ∂Ω, 4.1

andwx0 maxΩwx, thengx0, wx00.

iiIfwC2Ω∩C1Ωsatisfies

Δwx N

j1

bjxwxjgx, wx0 inΩ, ηw≥0 on ∂Ω, 4.2

andwx0 minΩwx, thengx0, wx00.

Theorem 4.3upper bound. Letdanddbe two fixed positive constants. Assume thatdid, i 1,2,3, and 0d4d. Then every possible positive solutionu, v, wof 2.1satisfies

maxΩ ub1

k, max

Ω vβ

k, max

Ω w

1 db1

dk c2

b1β

c3k . 4.3

Proof. A direct application of the maximum principle to2.1givesvβ/konΩ. Letux0

maxΩu. Using the maximum principle again, we haveb1vx0ux0D1kux0 kvx0

c1wx0. Thus,kux0vx0b1vx0andux0b1/k.

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Defineϕd3wd4uw; then,ϕsatisfies

−Δϕw−D3c2uc2vc3w inΩ, ηϕ0 on ∂Ω. 4.4

Letϕx1 maxΩϕ. ByLemma 4.2, we have

−D3c2ux1 c2vx1c3wx1≥0. 4.5

It follows that

wx1c2

c3ux1 vx1c2 c3

b1 k β

k

c2

b1β

c3k . 4.6

Hence,

ϕx1 d3d4ux1wx1

d3d4b1

k c2

b1β c3k , maxΩ wmax

Ω

ϕ d3d4u

1d4b1 d3k

c2

b1β c3k

1db1 dk

c2

b1β c3k

4.7

for anyd3dand 0≤d4d.

Turning now to the lower bound, we first need some preliminary results.

Lemma 4.4. Let dij be positive constants, i 1,2,3,4, j 1,2, . . ., and let uj, vj, wj be the corresponding positive solution of 2.1 with di dij. If uj, vj, wj → u, v, w uniformly onΩasj → ∞andu, v, wis a constant vector, thenu, v, wmust satisfy

b1vuD1kukvc1w 0, βkukvc1w0,

−D3c2uc2vc3w0. 4.8

Moreover, ifu,v, andware positive constants, thenu, v, w u, v, w.

Proof. It is easy to see that for allj,

ΩG1

uj, vj, wj

dx0. 4.9

IfG1u, v, w> 0, thenG1uj, vj, wj >0 whenjis large sinceuj, vj, wj → u, v, w. This is impossible. Similarly,G1u, v, w < 0 is impossible. Therefore,G1u, v, w 0.

The same argument shows thatβkukvc1w 0 and−D3c2uc2vc3w 0.

Consequently,u, v, w u,v, w.

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Lemma 4.5. The system

utd1Δub1vuD1kukv, x∈Ω, t >0, vtd2Δvv

βkukv

, x∈Ω, t >0,

ηu∂ηv0, x∂Ω, t >0, ux,0≥/≡0, vx,0≥/≡0, x∈Ω,

4.10

has a unique positive constant steady stateu1, v1which is globally asymptotically stable, whereu1 andv1are given by1.2.

Proof. Let

V2u, v 1 2

Ωu−u12dxρ

Ω

vv1v1ln v v1

dx, 4.11

whereρ b1ku1/kb1b1D1/kb1D1β>0, and letu, vbe a positive solution of4.10. Then a direct computation gives

dV2

dt

Ω

d1|∇u|2ρd2v1

v2 |∇v|2 D1kuku1kvuu12ρkvv12

dx≤0, 4.12

anddV2/dt 0 holds if and only ifu, v u1, v1. ByLemma 3.1, we can conclude that u1, v1is globally asymptotically stable.

Theorem 4.6lower bound. Letdandd be two fixed positive constants. Assume thatdid, i 1,2,3, and 0d4d. Then there exists a positive constantC CΛ, d, d, such that every possible positive solutionu, v, wof 2.1satisfies

minΩ u, min

Ω v, min

Ω wC. 4.13

Proof. If the conclusion does not hold, then there exists a sequence{d1j, d2j, d3j, d4j}j1with d1j, d2j, d3jdand 0≤d4jdsuch that the corresponding positive solutionuj, vj, wjof 2.1satisfies

min

minΩ uj, min

Ω vj,min

Ω wj

−→0, asj−→ ∞. 4.14

Moreover, we assume that dijdi ∈ d,∞ for i 1,2,3, and d4jd4 ∈ 0, d. By Theorem 4.3and the standard regularity theory for the elliptic equations, we may also assume thatuj, vj, wj → u, v, winC2Ω3for some nonnegative functionsu, v, w. It is easy to see thatu, v, walso satisfies estimate4.3, and min{minΩu, minΩv, minΩw}0.

Moreover, we observe that, ifd1, d2, d3<∞, thenu, v, wsatisfies2.1.

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Next we derive a contradiction for all possible cases.

Firstly, we consider the cased1, d2, d3<∞.

1In view of2.1, minΩv0 impliesv0 onΩfrom the Harnack inequality. In this case, by the strong maximum principle and the Hopf boundary lemma, it follows thatuw0 onΩ. This is a contradiction toLemma 4.4. Thus, minΩv >0.

2If minΩ u0, we denoteux0 minΩu0. By the maximum principle we have b1vx0ux0D1kux0 kvx0 c1wx0 0, and so minΩ v0. This is a contradiction to minΩv >0. Thus minΩu >0.

3If minΩ w0, letϕd3wd4uw. Then minΩ ϕ0 andϕsatisfies

−Δϕϕ−D3c2uc2vc3wd3d4u−1 inΩ, ηϕ0 on∂Ω. 4.15

The Harnack inequality shows that minΩϕ0 impliesϕ0 onΩ. Hence,w0 onΩ. From Lemma 4.5, we haveu, v u1, v1. Definewjwj/wj; then,uj, vj,wj, wjsatisfies

−d1jΔujb1vjuj

D1kujkvjc1wj inΩ,

−d2jΔvj vj

βkujkvjc1wj

inΩ,

−Δ

d3jwjd4jujwj

wj

−D3c2ujc2vjc3wj

inΩ,

ηuj ηvjηwj0 on ∂Ω.

4.16

Similarly to the above, we can prove that there exists a subsequence of{wj}, denoted by itself, and a nonnegative function w, such thatwjw inC2Ωand w 1. Moreover, w satisfies

−d3d4u1Δww−D3c2u1c2v1 inΩ, ηw0 on∂Ω. 4.17 Sincew 1, by the strong maximum principle and the Hopf boundary lemma, we find thatw > 0 onΩ. Applying the maximum principle again, we have−D3 c2u1c2v1 0.

Thus,u1v1D3/c2. Noting thatu1v1β/kin1.2, it follows thatc2βkD30, which is a contradiction to the conditionRc2βkD3>0.

Next, we consider the remaining cases.

Integrating by parts, we obtain that

b1

Ωvjdx

Ωuj

D1kujkvjc1wj dx,

Ωvj

βkujkvjc1wj dx0,

Ωwj

−D3c2ujc2vjc3wj

dx0,

4.18

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forj1,2, . . .. Moreover,u, v, wsatisfies b1

Ωvdx

ΩuD1kukvc1wdx,

Ωv

βkukvc1w dx0,

Ωw−D3c2uc2vc3wdx0.

4.19

Ifd1∞, thenusatisfies

−Δu0 in Ω, ηu0 on∂Ω. 4.20 Hence,uis a constant. Ifu0, from4.19, we have in turn thatvw0. This contradicts Lemma 4.4. So,uis a positive constant and either minΩv0 or minΩw0.

Ifd2 < ∞. In the case of minΩv0, similarly to the arguments of1, we havev0 onΩ. This contradicts the first equation of4.19. Thus minΩv >0 and minΩw0. Note that wsatisfies

−d3d4uΔww−D3c2uc3w inΩ, ηw0 on∂Ω. 4.21

Ifd3 < ∞, the Harnack inequality implies thatw 0 onΩ. Ifd3 ∞, thenw ia a constant. Since minΩw 0, sow 0 onΩ. Therefore, byLemma 4.5,u, v, w u1, v1,0.

Similarly to the arguments of3, we arrive atc2βkD3 0, which is a contradiction.

Similarly, we can derive contradictions for all the other cases.

5. Existence of Stationary Patterns for the Model 1.5

In this section we discuss the existence of nonconstant positive solutions to 2.1. These solutions are obtained for large cross-diffusion coefficientd4, with the other parametersd1, d2,d3,b1,D1,D3,k,c1,c2,c3, andβsuitably fixed. Our main result is as follows.

Theorem 5.1. Let the parametersd1,d2,d3,b1,D1,D3,k,c1,c2,c3, andβbe fixed such thatH1, H2, andH3hold. Let μbe given by the limit2.13. Ifμ ∈ μn, μn1for some n2 and the sum!n

i2dimiis odd, then there exists a positive constantd4such that2.1has at least one nonconstant positive solution ford4> d4.

Proof. ByProposition 2.2and our assumption on μ, there exists a positive constant d4 such that2.14holds ifd4> d4, and

μ1d4<0μ12d4< μ2, μ3d4

μn, μn1

. 5.1

We will prove that for anyd4 > d4,2.1has at least one nonconstant positive solution. The proof, which is by contradiction, is based on the homotopy invariance of the topological degree.

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Suppose on the contrary that the assertion is not true for somed4 d4 > d4. In the following we fixd4d4.

Forθ∈0,1, defineΦθ;u d1u, d2v, d3wθd4uwTand consider the problem

−ΔΦθ;u Gu inΩ, ηu0, on ∂Ω. 5.2 Thenu is a positive nonconstant solution of2.1if and only if it is such a solution of5.2for θ 1. It is obvious thatu is the unique constant positive solution of 5.2for any 0≤ θ≤1.

As we observed inSection 2, for any 0≤θ≤1,u is a positive solution of5.2if and only if Fθ;u:u−I−Δ−1

Φu−1θ;uGu ∇uΦuuθ;u∇u u

0 in Y. 5.3

It is obvious thatF1;u Fu.Theorem 3.2shows that F0;u 0 has only the positive solutionu in Y . By a direct computation,

DuFθ;u I−I−Δ−1

Φu−1θ;uG uu I

. 5.4

In particular,

DuF0;u I−I−Δ−1

D−1Guu I

, 5.5

whereDdiagd1, d2, d3and

DuF1;u I−I−Δ−1

Φu−1Guu I

DuFu. 5.6

From2.5and2.9we see that H

μ det

Φu−1u C

d4;μ

. 5.7

In view of2.14and5.1, it follows that H

μ1

H0>0, H

μi

<0, 2≤in, H

μi

>0, in1.

5.8

Therefore, zero is not an eigenvalue of the matrixμiIΦu−1uGuufor alli≥1, and

i≥1,Hμi<0 dimE

μi n

i2

dimE μi

σn, which is odd. 5.9

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Thanks toProposition 2.1, we have

indexF1;·,u −1 γ −1σn −1. 5.10

Similarly, we can easily show that

indexF0;·,u −1 0 1. 5.11

Now, by Theorems4.3and4.6, there exists a positive constantCsuch that, for all 0≤θ≤1, the positive solutions of2.1satisfy 1/C < u, v, w < C. Therefore,Fθ;u/0 on∂BCfor all 0≤θ≤1. By the homotopy invariance of the topological degree,

degF1;·,0, BC degF0;·,0, BC. 5.12

On the other hand, by our supposition, both equationsF1;u 0 andF0;u 0 have only the positive solutionu in BC. Hence, by5.10and5.11, we have

degF1;·,0, BC indexF1;·,u −1, degF0;·,0, BC indexF0;·,u 1.

5.13

This contradicts5.12, and thus we complete the proof ofTheorem 5.1.

Remark 5.2. Assume that all the conditions hold inTheorem 5.1.Theorem 3.2shows thatu is a globally asymptotically stable equilibrium for the system1.4. However,Theorem 5.1 implies that the cross-diffusion system1.5has at least one nonconstant positive steady state.

Our results demonstrate that stationary patterns can be found due to the emergence of cross- diffusion.

6. Nonexistence of Nonconstant Positive Solution of 2.1

In this section, we discuss the nonexistence of nonconstant positive solution of2.1when the cross-diffusion coefficientd4>0 is small.

Theorem 6.1. If the parametersd1,d3,d4,b1,D1,D3,k,c1,c2,c3, andβsatisfyH1,H3, and

c1d24uw

c2 <4d1d3, H4

then the problem2.1has no nonconstant positive solution.

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Proof. Assume thatu, v, wis a positive solution of2.1. Letλu, ρc1u/c 2. Multiplying the equations of2.1byu−u, λvv/v, and ρww/w, respectively, and integrating by parts, as in the proof ofTheorem 3.2, we obtain 0−I3I4, where

I3

Ω

d1|∇u|2λd2v

v2 |∇v|2ρwd 3d4u

w2 |∇w|2ρd4w

w ∇u· ∇w

dx, I4

Ω

D1kukukvc1wuu 2λkvv 2

ρc3w−w 2 2kub1u−uvv dx.

6.1

ApplyingH3andH4, it is easy to prove thatI3≥0 andI4≥0. This implies thatu, v, w u,v, w onΩand the proof is complete.

Remark 6.2. Theorem 6.1shows that the problem2.1has no nonconstant positive solutions if one ofd1andd3is sufficiently large; that is, unlimitedly increasing one of the diffusion rates d1andd3will eventually wipe out all nonconstant solutions of2.1. However,Theorem 6.1 does not tell us the effect of the diffusion rated2on the stationary problem2.1. Using the similar arguments inSection 2, we can find thatd2does not cause instability ofu. Therefore, we conjecture that the problem2.1has no nonconstant positive solutions ifd2is sufficiently large.

Remark 6.3. Theorems5.1and6.1seem to indicate that diffusion tends to suppress pattern formation, while cross-diffusion seems to help create patterns.

7. Discussion

In this paper, we have introduced a more realistic mathematical model for a diffusive predator-prey system where the prey has a sex structure comprising male and female mem- bers. In this model, we model the tendency of the predators to keep away from the male prey by a cross-diffusion. As a result, our model is a strongly coupled cross-diffusion system, which is mathematically more complex than systems used to model sex-structured predator- prey behavior hitherto 1, 8. What is noteworthy about this model is that, as the cross- diffusion term arises, it is precisely this cross-diffusion that destabilizes the uniform positive equilibrium and gives rise to stationary patterns for the model. Indeed, stationary patterns do not arise for the ODEspatially independentmodel, nor the PDE model without cross- diffusion.

In fact, one can see that this particular cross-diffusion term is also significant from the mathematical point of view. The following system represents the general form of SKT-type cross-diffusion22in the predator-prey model

ut−Δd1ud12uvd13uw G1u, v, w, x∈Ω, t >0, vt−Δd2vd21uvd23vw G2u, v, w, x∈Ω, t >0, wt−Δd3wd31uwd32vw G3u, v, w, x∈Ω, t >0,

ηux, t ∂ηvx, t ∂ηwx, t 0, x∂Ω, t >0, ux,0 u0x, vx,0 v0x, wx,0 w0x, x∈Ω,

7.1

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