PARABOLIC INEQUALITIES IN L AS LIMITS OF RENORMALIZED EQUATIONS
K. AZELMAT, M. KBIRI ALAOUI, D. MESKINE, AND A. SOUISSI Received 21 April 2006; Revised 10 August 2006; Accepted 21 August 2006
The paper deals with the existence of solutions of some parabolic bilateral problems ap- proximated by the renormalized solutions of some parabolic equations.
Copyright © 2006 Hindawi Publishing Corporation. All rights reserved.
1. Introduction
LetΩbe a bounded domain inRNandT >0. We denote byQthe cylinderΩ×(0,T) and Γ=∂Q.
Let
A(u)= −diva(x,t,u,∇u) (1.1) be a Leray-Lions operator acting onLp(0,T;W01,p(Ω)), 1< p <∞, into its dualLp(0,T;
W−1,p(Ω))(1/ p+ 1/ p=1). Consider the following parabolic problem:
u∈=
v∈Lp0,T;W01,p(Ω):v(t)∈Ka.e., T
0
∂v
∂t,u−v
dt+
Qa(x,t,u,∇u)(∇u− ∇v)dx dt≤ T
0 f,u−vdt,
∀v∈∩ v∈Lp0,T;W01,p(Ω):∂v
∂t ∈Lp0,T;W−1,p(Ω);v(0)=0
, (P)
whereKis a given convex inW01,p(Ω) and f ∈Lp(0,T;W−1,p(Ω)).
It is well known that (P) admits at least one solution via a classical penalty method (see Lions [5] forp≥2 and Landes-Mustonen [4] for 1< p <2). Recently in [6], the authors
Hindawi Publishing Corporation
International Journal of Mathematics and Mathematical Sciences Volume 2006, Article ID 46265, Pages1–18
DOI 10.1155/IJMMS/2006/46265
L
approximated (P) by the following sequence of parabolic equations:
∂un
∂t +Aun+hx,unn−1hx,unGx,t,un,∇un= f inQ, un(x,t)=0 on∂Q,
un(x, 0)=0 inΩ,
(Pn)
wherehandGare two Carath´eodory functions satisfying some natural growth condi- tions. The obtained convexKdepends on two obstacles constructed fromh.
In theL1 case, that is, f ∈L1(Ω×]0,T[), the formulations (P) and (Pn) are not ap- propriate. So, we introduce the renormalized problem (Rn) associated to (Pn) (see the definition below). The study of the asymptotic behavior of (Rn) asn→ ∞leads to some bilateral parabolic problem. Our approach allows us also to prove the existence of solu- tions for general parabolic inequalities of type
Tk(u)∈, T
0
∂v
∂t,Tk(u−v)
dt+
Qa(x,t,u,∇u)∇Tk(u−v)dx dt +
QH(x,t,u,∇u)Tk(u−v)dx dt≤
Qf Tk(u−v)dx dt, ∀v∈∩D∩L∞(Q), (1.2) whereD= {v∈Lp(0,T;W01,p(Ω)), ∂v/∂t∈Lp(0,T,W0−1,p(Ω)) +L1(Q), v(0)=0}and whereHis a given Carath´eodory function satisfying some natural growth assumption.
For some recent and classical results for some parabolic inequalities problems, the reader can refer to [2,7,9,10].
2. Main result
LetΩbe an open bounded subset ofRN,N≥2 and 1< p <+∞. We denote byQthe cylinderΩ×(0,T) andΓ=∂Q.
LetA(u)= −div(a(x,t,∇u)) be a Leray-Lions operator defined onLp(0,T;W01,p(Ω)) into its dualLp(0,T;W−1,p(Ω)), wherea:Ω×R×RN→RNis a Carath´eodory function satisfying for a.e.x∈Ω, for allt∈Rand for allζ,ζ∈RN, (ζ=ζ) the following hold:
a(x,t,ζ)≤βk(x,t) +|ζ|p−1 , a(x,t,ζ)−a(x,t,ζ)(ζ−ζ)>0,
a(x,t,ζ)ζ≥α|ζ|p,
(2.1)
withα >0,β >0,k∈Lp(Q).
Furthermore, leth:Ω×R→Rbe a Carath´eodory function such that
h(x, 0)=0, h(x,s) is nondecreasing with respect tos. (2.2)
Gis a Carath´eodory function satisfying the following assumptions:
G(x,t,s,ξ)≤b|s|
c(x,t) +|ξ|p
, G(x,t,s, 0)=0, (2.3) v∈Lp0,T;W01,p(Ω):G(x,t,v,∇v)=0 a.e. inQ
⊂
v∈Lp0,T;W01,p(Ω):h(x,v)≤1 a.e. inQ.
(2.4) Let us suppose
for almostx∈Ω\Ω∞+ there exists=(x)>0 such that h(x,s)>1, ∀s∈
q+(x),q+(x) + , for almostx∈Ω\Ω∞−there exists=(x)>0 such that
h(x,s)<−1, ∀s∈
q−(x)−,q−(x),
(2.5)
wherebis a continuous nondecreasing function andc(x,t)∈L1(Q),c≥0, and q+(x)=infs >0,h(x,s)≥1,
q−(x)=sups >0,h(x,s)≤ −1, Ω∞+ =
x∈Ω:q+(x)=+∞ , Ω∞−=
x∈Ω:q−(x)= −∞
.
(2.6)
We define for allsandkinR,k≥0,Tk(s)=max(−k, min(k,s)).
We will say thatunis a renormalized solution of (Pn) if Tk
un
∈Lp0,T;W01,p(Ω), ∀k >0,
hlim→∞
{h≤|un|≤h+1}ax,t,∇un∇undx dt=0, unsatisfies in the distributional sense Aun
t−divax,t,∇un Aun
+ax,t,∇un
∇unAun +hx,unn−1hx,unGx,t,un,∇unAun=f Aun,
∀A∈C1(R), A,A∈L∞(Ω), Ahas a compact support andunsatisfies the initial condition in the sense thatAun
∈C[0,T],L1(Ω).
(Rn)
Thanks to [8, Theorem 3.2, page 164], there exists at least one solutionunof (Rn).
Theorem 2.1. Under the hypotheses (2.1)–(2.5), f ∈L1(Q), the problem (Pn) has at least one renormalized solution (un) such that
Tkun−→Tk(u) strongly inLp0,T;W01,p(Ω), (2.7)
L
whereuis a solution of the following obstacle problem:
q−(x)≤u(x,t)≤q+(x) a.e. (x,t)∈Q, Tk(u)∈Lp0,T;W01,p(Ω), T
0
∂v
∂t,Tk(u−v)
dt+
Qa(x,t,∇u)∇Tk(u−v)dx dt
≤
Qf Tk(u−v)dx dt, ∀v∈∩D∩L∞(Q),
(R)
where
D= v∈Lp0,T;W01,p(Ω), ∂v
∂t ∈Lp0,T;W−1,p(Ω)+L1(Q),v(0)=0
,
=
v∈Lp0,T;W01,p(Ω),v(t)∈K, K=
v∈W01,p(Ω), q−≤v≤q+
. (2.8)
Moreover, ifq−,q+∈L∞(Ω), thenu∈Lp(0,T;W01,p(Ω))∩L∞(Q).
Remark 2.2. The same result can be obtained when dealing with general operator of Leray-Lions type depending also onu, that is,A(u)= −div(a(x,t,u,∇u)).
Proof ofTheorem 2.1.
Step 1. LetA(t)=Hm(t),Hm(t)=t
0hm(s)ds, where
hm(s)=
⎧⎪
⎪⎪
⎪⎨
⎪⎪
⎪⎪
⎩
1 if|s| ≤m,
affine ifm≤ |s| ≤m+ 1, 0 ifm+ 1≤ |s|.
(2.9)
Taking nowTk(Hm(un)) as test function in (Rn), we obtain T
0
∂Hm
un
∂t ,Tk
Hm
un
dt+
|Hm(un)|<kax,t,∇un
∇unh2mun
dx dt +
Q
hx,unn−1hx,unGx,t,un,∇unhm un
Tk Hm
un dx dt +
Qa·,t,∇un
∇unhmun Tk
Hm un
dx dt=
Qf hm un
Tk Hm
un dx dt.
(2.10) Since
T
0
∂Hm
un
∂t ,Tk
Hm
un
dt
=
Ω
Hm(un(x,T))
0 Tk(s)ds
dx−
Ω
Hm(un(x,0))
0 Tk(s)ds
dx
(2.11)
and by using the fact thatΩ(0Hm(un(x,T))Tk(s)ds)≥0, we obtain
{|Hm(un)|<k}ax,t,∇un
∇unh2mun
dx dt≤Ck+
{m≤|un|≤m+1}ax,t,∇un
∇undx dt,
Q
hx,unn−1hx,unGx,t,un,∇unhmunTkHmundx dt
≤Ck+
{m≤|un|≤m+1}ax,t,∇un
∇undx dt.
(2.12) We haveHm(s) (resp.,hm(s)) tends tos(resp., to 1) asmgoes to +∞.
Using Fatou’s lemma and the definition of the renormalized solution leads to
Q
∇Tkunpdx dt≤Ck, (2.13)
Q
hx,unn−1hx,unGx,t,un,∇unTkundx dt≤Ck, (2.14)
which gives
Q
hx,unnGx,t,un,∇unTk
un
k dx dt≤C, (2.15) and ask→0 we obtain
Q
hx,unnGx,t,un,∇undx dt≤C. (2.16)
Choosing now aC2functionρk, such thatρk(s)=sfor|s| ≤kand 2ksign(s) for|s|>2k, we get
ρkunt−divax,t,∇unρkun+ax,t,∇un∇unρkun +hx,unn−1hx,unGx,t,un,∇unρkun
= f ρk
un
.
(2.17)
We deduce that (ρk(un))tis bounded inL1(Q) +Lp(0,T;W−1,p(Ω)).
Now thanks to the following result.
Lemma 2.3 [11]. Let p >1. If (un) is a bounded sequence ofLp(0,T;W01,p(Ω)) such that
∂un/∂tis bounded inL1+Lp(0,T;W−1,p(Ω)), thenunis relatively compact inLp(Q).
L
We deduce thatρk(un) is relatively compact inLp(Q) and so there exists a measurable functionusuch thatun→ua.e. inQ.
Finally, we deduce from (2.13) thatTk(un)Tk(u) weakly inLp(0,T;W01,p(Ω)), and strongly inLp(Q).
Step 2. We are dealing now with the almost convergence of the gradient.
We have to prove that, for 0< θ <1,
nlim→∞
Q
ax,t,∇Tk
un
−ax,t,∇Tk(u)∇Tk
un
− ∇Tk(u)θdx dt=0. (2.18)
Letω∈Lp(0,T;W01,p(Ω)), we define for anyμ >0,ωμthe time regularization ofω,
ωμ(x,t)=μ t
−∞ω(x,s) expμ(s−t)ds, (2.19)
whereωis the zero extension ofωfors > T. Furthermore,ωμsatisfies the following prop- erties (see [3]):
ωμ−→ω strongly inLp0,T;W01,p(Ω),
∂ωμ
∂t =μω−ωμ
in the distributional sense.
(2.20)
Lettingη >0, we obtain
Q
ax,t,∇Tkun−ax,t,∇Tk(u)∇Tkun− ∇Tk(u)θ
≤CmeasTk
un
−Tk(u)μ≥η1−θ
+C
{|Tk(un)−Tk(u)μ|<η}
ax,t,∇Tk
un
−ax,t,∇Tk(u)∇Tk
un
− ∇Tk(u)
θ
.
(2.21)
On the other hand, we have
{|Tk(un)−Tk(u)μ|<η}
ax,t,∇Tkun−ax,t,∇Tk(u)∇Tkun− ∇Tk(u)dx dt
≤
{|Tk(un)−Tk(u)μ|<η}
ax,t,∇Tkun
−ax,t,∇Tk(u)μ
∇Tk un
− ∇Tk(u)μ dx dt +
{|Tk(un)−Tk(u)μ|<η}ax,t,∇Tkun∇Tk(u)μ− ∇Tk(u)dx dt +
{|Tk(un)−Tk(u)μ|<η}
ax,t,∇Tk(u)μ
−ax,t,∇Tk(u)∇Tk un
dx dt
−
{|Tk(un)−Tk(u)μ|<η}ax,t,∇Tk(u)μ
∇Tk(u)μdx dt +
{|Tk(un)−Tk(u)μ|<η}ax,t,∇Tk(u)∇Tk(u)dx dt
≤I1+I2+I3+I4+I5.
(2.22)
TakeTη(Hm(un)−Tk(u)μ) as test function in (Rn) withA(t)=Hm(t). We obtain T
0
∂Hm
un
∂t ,Tη
Hm
un
−Tk(u)μ
dt +
{|Hm(un)−Tk(u)μ|<η}ax,t,∇un∇unh2mun− ∇Tk(u)μhmundx dt +
Q
hx,unn−1hx,unGx,t,un,∇unhmunTηHmun−Tk(u)μdx dt
+
Qax,t,∇un∇unhm(un)TηHmun−Tk(u)μdx dt
=
Qf hmunTηHmun−Tk(u)μdx dt.
(2.23) We have
T
0
∂Hm
un
∂t ,Tη
Hm
un
−Tk(u)μ
dt
= T
0
∂Hm
un
−Tk(u)μ
∂t ,Tk
Hm
un
−Tk(u)μ
dt
+ T
0
∂Tk(u)μ
∂t ,Tk
Hm
un
−Tk(u)μ
dt.
(2.24)
L Using the fact that
T
0
∂Hm
un
−Tk(u)μ
∂t ,Tη
Hm
un
−Tk(u)μ
dt≥0, T
0
∂Tk(u)μ
∂t ,Tk
Hm
un
−Tk(u)μ
dt
=μ
Q
Tk(u)−Tk(u)μ
Tη
Hm
un
−Tk(u)μ
dx dt,
(2.25)
consequently, lim sup
n→∞ lim sup
m→∞
T
0
∂Hm un
∂t ,Tη Hm
un
−Tk(u)μ dt
≥μ
Q
Tk(u)−Tk(u)μTηu−Tk(u)μdx dt=(m,n)≥0.
(2.26)
This implies that
{|Hm(un)−Tk(u)μ|<η}ax,t,∇un∇unh2mun− ∇Tk(u)μhmundx dt +
Q
hx,unn−1hx,unGx,t,un,∇unhm un
Tη Hm
un
−Tk(u)μ dx dt +
Qax,t,∇un
∇unhmun Tη
Hm un
−Tk(u)μ dx dt
≤
Qf hmunTηHmun−Tk(u)μdx dt+(m,n),
(2.27) which gives by using the fact that
Q
hx,unn−1hx,unGx,t,un,∇unhm un
Tη Hm
un
−Tk(u)μ
dx dt≤Cη,
{|Hm(un)−Tk(u)μ|<η}ax,t,∇un
∇unh2mun
− ∇Tk(u)μhm un
dx dt
≤Cη+(m,n) +η
{m≤|un|≤m+1}ax,t,∇un
∇undx dt,
(2.28) which gives asm→ ∞,
{|un−Tk(u)μ|<η}ax,t,∇un
∇un− ∇Tk(u)μdx dt≤Cη+(n). (2.29)
Finally from (2.22), I1≤Cη+(n)−
{|Tk(un)−Tk(u)μ|<η}ax,t,∇Tk(u)μ
∇Tk un
− ∇Tk(u). (2.30) Sincea(x,t,∇Tk(u)μ)χ{|Tk(un)−Tk(u)μ|<η}→a(x,t,∇Tk(u)μ)χ{|Tk(u)−Tk(u)μ|<η}inLp(Q) and Tk(un)→Tk(u) weakly inLp(0,T;W01,p(Ω)), then
−
{|Tk(un)−Tk(u)μ|<η}ax,t,∇Tk(u)μ
∇Tk
un
− ∇Tk(u)dx dt
= −
{|Tk(u)−Tk(u)μ|<η}ax,t,∇Tk(u)μ∇Tk(u)− ∇Tk(u)dx dt+(n).
(2.31)
So
I1≤Cη+(n). (2.32)
For what concerns the termI2, one has
I2=(n,μ), (2.33)
since
ax,t,∇Tk un
χ{|Tk(un)−Tk(u)μ|<η}−→ax,t,∇Tk(u)χ{|Tk(u)−Tk(u)μ|<η} inLp(Q)N, ∇Tk(u)μ− ∇Tk(u)χ{|Tk(un)−Tk(u)μ|<η}−→
∇Tk(u)μ− ∇Tk(u)χ{|Tk(u)−Tk(u)μ|<η}. (2.34) In the same way, we show that
I3=(n,μ), I4=(n,μ), I5=(n,μ). (2.35) Combining the above estimates, we get
nlim→∞
Q
ax,t,∇Tkun−ax,t,∇Tk(u)∇Tkun− ∇Tk(u)θdx dt=0. (2.36)
Then there exists a subsequence also denoted by (un) such that
∇un−→ ∇u a.e. inQ. (2.37)
Step 3. From (2.16), we deduce that
Q
hx,unnGx,t,un,∇undx dt≤C, (2.38)
which gives for everyβ >0,
|h(x,Tβ(un))|>k
Gx,t,Tβ un
,∇Tβ
undx dt≤ C
kn, (2.39)
L
wherek >1. Lettingn→+∞forkfixed, we deduce by using Fatou’s lemma
|h(x,Tβ(u))|>k
Gx,t,Tβ(u),∇Tβ(u)dx dt=0, (2.40)
and so, by (2.4)
hx,Tβ(u)≤1 a.e. inQ. (2.41)
So
q−(x)≤Tβu(x)≤q+(x) a.e. inQ. (2.42) Letting nowβ→+∞, we deduce also that
q−(x)≤u(x)≤q+(x) a.e. inQ. (2.43) Step 4. Strong convergence of the truncations.
We will prove that
nlim→∞
Q
ax,t,∇Tkun−ax,t,∇Tk(u)∇Tkun− ∇Tk(u)dx dt=0. (2.44)
Fixk >0 and letϕ(s)=exp(δs2),δ >0. Letl > kand define the functionRl(s)=s
0ρl(t)dt.
Let us considerωmμ =Tk(Hm(u)μ), wherevμ is the mollification with respect to timev.
Lettingvmμ,n=ρl(Hm(un))ϕ(Tk(Hm(un))−ωmμ) as test function in the problem (Rn), we get
T
0
∂Hmun
∂t ,ρlHmunϕTkHmun−ωmμdt +
Qax,t,∇un∇unh2unρlHmunϕTkHmun−ωmμdx dt +
Qax,t,∇un∇TkHmun− ∇ωmμ
×hmunρlHmunϕTkHmun−ωmμdx dt +
Qax,t,∇un
∇unhmun ρl
Hm un
ϕTk Hm
un
−ωμmdx dt +
Q
hx,unn−1hx,unGx,t,un,∇un
×hm un
ρl Hm
un ϕTk
Hm un
−ωμmdx dt
=
Qf vmμ,nhmundx dt.
(2.45)
We deal now with the estimate of each term of the last equalities.