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PARABOLIC INEQUALITIES IN L AS LIMITS OF RENORMALIZED EQUATIONS

K. AZELMAT, M. KBIRI ALAOUI, D. MESKINE, AND A. SOUISSI Received 21 April 2006; Revised 10 August 2006; Accepted 21 August 2006

The paper deals with the existence of solutions of some parabolic bilateral problems ap- proximated by the renormalized solutions of some parabolic equations.

Copyright © 2006 Hindawi Publishing Corporation. All rights reserved.

1. Introduction

LetΩbe a bounded domain inRNandT >0. We denote byQthe cylinderΩ×(0,T) and Γ=∂Q.

Let

A(u)= −diva(x,t,u,u) (1.1) be a Leray-Lions operator acting onLp(0,T;W01,p(Ω)), 1< p <, into its dualLp(0,T;

W1,p(Ω))(1/ p+ 1/ p=1). Consider the following parabolic problem:

u=

vLp0,T;W01,p(Ω):v(t)Ka.e., T

0

∂v

∂t,uv

dt+

Qa(x,t,u,u)(u− ∇v)dx dt T

0 f,uvdt,

v vLp0,T;W01,p(Ω):∂v

∂t Lp0,T;W1,p(Ω);v(0)=0

, (P)

whereKis a given convex inW01,p(Ω) and f Lp(0,T;W1,p(Ω)).

It is well known that (P) admits at least one solution via a classical penalty method (see Lions [5] forp2 and Landes-Mustonen [4] for 1< p <2). Recently in [6], the authors

Hindawi Publishing Corporation

International Journal of Mathematics and Mathematical Sciences Volume 2006, Article ID 46265, Pages1–18

DOI 10.1155/IJMMS/2006/46265

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L

approximated (P) by the following sequence of parabolic equations:

∂un

∂t +Aun+hx,unn1hx,unGx,t,un,un= f inQ, un(x,t)=0 on∂Q,

un(x, 0)=0 inΩ,

(Pn)

wherehandGare two Carath´eodory functions satisfying some natural growth condi- tions. The obtained convexKdepends on two obstacles constructed fromh.

In theL1 case, that is, f L1×]0,T[), the formulations (P) and (Pn) are not ap- propriate. So, we introduce the renormalized problem (Rn) associated to (Pn) (see the definition below). The study of the asymptotic behavior of (Rn) asn→ ∞leads to some bilateral parabolic problem. Our approach allows us also to prove the existence of solu- tions for general parabolic inequalities of type

Tk(u)᏷, T

0

∂v

∂t,Tk(uv)

dt+

Qa(x,t,u,u)Tk(uv)dx dt +

QH(x,t,u,u)Tk(uv)dx dt

Qf Tk(uv)dx dt, vDL(Q), (1.2) whereD= {vLp(0,T;W01,p(Ω)), ∂v/∂tLp(0,T,W01,p(Ω)) +L1(Q), v(0)=0}and whereHis a given Carath´eodory function satisfying some natural growth assumption.

For some recent and classical results for some parabolic inequalities problems, the reader can refer to [2,7,9,10].

2. Main result

LetΩbe an open bounded subset ofRN,N2 and 1< p <+. We denote byQthe cylinderΩ×(0,T) andΓ=∂Q.

LetA(u)= −div(a(x,t,u)) be a Leray-Lions operator defined onLp(0,T;W01,p(Ω)) into its dualLp(0,T;W1,p(Ω)), wherea×R×RNRNis a Carath´eodory function satisfying for a.e.xΩ, for alltRand for allζ,ζRN, (ζ=ζ) the following hold:

a(x,t,ζ)βk(x,t) +|ζ|p1 , a(x,t,ζ)a(x,t,ζ)ζ)>0,

a(x,t,ζ)ζα|ζ|p,

(2.1)

withα >0,β >0,kLp(Q).

Furthermore, leth×RRbe a Carath´eodory function such that

h(x, 0)=0, h(x,s) is nondecreasing with respect tos. (2.2)

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Gis a Carath´eodory function satisfying the following assumptions:

G(x,t,s,ξ)b|s|

c(x,t) +|ξ|p

, G(x,t,s, 0)=0, (2.3) vLp0,T;W01,p(Ω):G(x,t,v,v)=0 a.e. inQ

vLp0,T;W01,p(Ω):h(x,v)1 a.e. inQ.

(2.4) Let us suppose

for almostxΩ\Ω+ there exists=(x)>0 such that h(x,s)>1, s

q+(x),q+(x) + , for almostxΩ\Ωthere exists=(x)>0 such that

h(x,s)<1, s

q(x),q(x),

(2.5)

wherebis a continuous nondecreasing function andc(x,t)L1(Q),c0, and q+(x)=infs >0,h(x,s)1,

q(x)=sups >0,h(x,s)≤ −1, Ω+ =

xΩ:q+(x)=+ , Ω=

xΩ:q(x)= −∞

.

(2.6)

We define for allsandkinR,k0,Tk(s)=max(k, min(k,s)).

We will say thatunis a renormalized solution of (Pn) if Tk

un

Lp0,T;W01,p(Ω), k >0,

hlim→∞

{h≤|un|≤h+1}ax,t,unundx dt=0, unsatisfies in the distributional sense Aun

tdivax,t,un Aun

+ax,t,un

unAun +hx,unn1hx,unGx,t,un,unAun=f Aun,

AC1(R), A,AL(Ω), Ahas a compact support andunsatisfies the initial condition in the sense thatAun

C[0,T],L1(Ω).

(Rn)

Thanks to [8, Theorem 3.2, page 164], there exists at least one solutionunof (Rn).

Theorem 2.1. Under the hypotheses (2.1)–(2.5), f L1(Q), the problem (Pn) has at least one renormalized solution (un) such that

Tkun−→Tk(u) strongly inLp0,T;W01,p(Ω), (2.7)

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L

whereuis a solution of the following obstacle problem:

q(x)u(x,t)q+(x) a.e. (x,t)Q, Tk(u)Lp0,T;W01,p(Ω), T

0

∂v

∂t,Tk(uv)

dt+

Qa(x,t,u)Tk(uv)dx dt

Qf Tk(uv)dx dt, vDL(Q),

(R)

where

D= vLp0,T;W01,p(Ω), ∂v

∂t Lp0,T;W1,p(Ω)+L1(Q),v(0)=0

,

=

vLp0,T;W01,p(Ω),v(t)K, K=

vW01,p(Ω), qvq+

. (2.8)

Moreover, ifq,q+L(Ω), thenuLp(0,T;W01,p(Ω))L(Q).

Remark 2.2. The same result can be obtained when dealing with general operator of Leray-Lions type depending also onu, that is,A(u)= −div(a(x,t,u,u)).

Proof ofTheorem 2.1.

Step 1. LetA(t)=Hm(t),Hm(t)=t

0hm(s)ds, where

hm(s)=

1 if|s| ≤m,

affine ifm≤ |s| ≤m+ 1, 0 ifm+ 1≤ |s|.

(2.9)

Taking nowTk(Hm(un)) as test function in (Rn), we obtain T

0

∂Hm

un

∂t ,Tk

Hm

un

dt+

|Hm(un)|<kax,t,un

unh2mun

dx dt +

Q

hx,unn1hx,unGx,t,un,unhm un

Tk Hm

un dx dt +

Qa·,t,un

unhmun Tk

Hm un

dx dt=

Qf hm un

Tk Hm

un dx dt.

(2.10) Since

T

0

∂Hm

un

∂t ,Tk

Hm

un

dt

=

Ω

Hm(un(x,T))

0 Tk(s)ds

dx

Ω

Hm(un(x,0))

0 Tk(s)ds

dx

(2.11)

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and by using the fact thatΩ(0Hm(un(x,T))Tk(s)ds)0, we obtain

{|Hm(un)|<k}ax,t,un

unh2mun

dx dtCk+

{m≤|un|≤m+1}ax,t,un

undx dt,

Q

hx,unn1hx,unGx,t,un,unhmunTkHmundx dt

Ck+

{m≤|un|≤m+1}ax,t,un

undx dt.

(2.12) We haveHm(s) (resp.,hm(s)) tends tos(resp., to 1) asmgoes to +.

Using Fatou’s lemma and the definition of the renormalized solution leads to

Q

Tkunpdx dtCk, (2.13)

Q

hx,unn1hx,unGx,t,un,unTkundx dtCk, (2.14)

which gives

Q

hx,unnGx,t,un,unTk

un

k dx dtC, (2.15) and ask0 we obtain

Q

hx,unnGx,t,un,undx dtC. (2.16)

Choosing now aC2functionρk, such thatρk(s)=sfor|s| ≤kand 2ksign(s) for|s|>2k, we get

ρkuntdivax,t,unρkun+ax,t,ununρkun +hx,unn1hx,unGx,t,un,unρkun

= f ρk

un

.

(2.17)

We deduce that (ρk(un))tis bounded inL1(Q) +Lp(0,T;W1,p(Ω)).

Now thanks to the following result.

Lemma 2.3 [11]. Let p >1. If (un) is a bounded sequence ofLp(0,T;W01,p(Ω)) such that

∂un/∂tis bounded inL1+Lp(0,T;W1,p(Ω)), thenunis relatively compact inLp(Q).

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L

We deduce thatρk(un) is relatively compact inLp(Q) and so there exists a measurable functionusuch thatunua.e. inQ.

Finally, we deduce from (2.13) thatTk(un)Tk(u) weakly inLp(0,T;W01,p(Ω)), and strongly inLp(Q).

Step 2. We are dealing now with the almost convergence of the gradient.

We have to prove that, for 0< θ <1,

nlim→∞

Q

ax,t,Tk

un

ax,t,Tk(u)Tk

un

− ∇Tk(u)θdx dt=0. (2.18)

LetωLp(0,T;W01,p(Ω)), we define for anyμ >0,ωμthe time regularization ofω,

ωμ(x,t)=μ t

−∞ω(x,s) expμ(st)ds, (2.19)

whereωis the zero extension ofωfors > T. Furthermore,ωμsatisfies the following prop- erties (see [3]):

ωμ−→ω strongly inLp0,T;W01,p(Ω),

∂ωμ

∂t =μωωμ

in the distributional sense.

(2.20)

Lettingη >0, we obtain

Q

ax,t,Tkunax,t,Tk(u)Tkun− ∇Tk(u)θ

CmeasTk

un

Tk(u)μη1θ

+C

{|Tk(un)Tk(u)μ|}

ax,t,Tk

un

ax,t,Tk(u)Tk

un

− ∇Tk(u)

θ

.

(2.21)

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On the other hand, we have

{|Tk(un)Tk(u)μ|}

ax,t,Tkunax,t,Tk(u)Tkun− ∇Tk(u)dx dt

{|Tk(un)Tk(u)μ|}

ax,t,Tkun

ax,t,Tk(u)μ

Tk un

− ∇Tk(u)μ dx dt +

{|Tk(un)Tk(u)μ|}ax,t,TkunTk(u)μ− ∇Tk(u)dx dt +

{|Tk(un)Tk(u)μ|}

ax,t,Tk(u)μ

ax,t,Tk(u)Tk un

dx dt

{|Tk(un)Tk(u)μ|}ax,t,Tk(u)μ

Tk(u)μdx dt +

{|Tk(un)Tk(u)μ|}ax,t,Tk(u)Tk(u)dx dt

I1+I2+I3+I4+I5.

(2.22)

TakeTη(Hm(un)Tk(u)μ) as test function in (Rn) withA(t)=Hm(t). We obtain T

0

∂Hm

un

∂t ,Tη

Hm

un

Tk(u)μ

dt +

{|Hm(un)Tk(u)μ|}ax,t,ununh2mun− ∇Tk(u)μhmundx dt +

Q

hx,unn1hx,unGx,t,un,unhmunTηHmunTk(u)μdx dt

+

Qax,t,ununhm(un)TηHmunTk(u)μdx dt

=

Qf hmunTηHmunTk(u)μdx dt.

(2.23) We have

T

0

∂Hm

un

∂t ,Tη

Hm

un

Tk(u)μ

dt

= T

0

∂Hm

un

Tk(u)μ

∂t ,Tk

Hm

un

Tk(u)μ

dt

+ T

0

∂Tk(u)μ

∂t ,Tk

Hm

un

Tk(u)μ

dt.

(2.24)

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L Using the fact that

T

0

∂Hm

un

Tk(u)μ

∂t ,Tη

Hm

un

Tk(u)μ

dt0, T

0

∂Tk(u)μ

∂t ,Tk

Hm

un

Tk(u)μ

dt

=μ

Q

Tk(u)Tk(u)μ

Tη

Hm

un

Tk(u)μ

dx dt,

(2.25)

consequently, lim sup

n→∞ lim sup

m→∞

T

0

∂Hm un

∂t ,Tη Hm

un

Tk(u)μ dt

μ

Q

Tk(u)Tk(u)μTηuTk(u)μdx dt=(m,n)0.

(2.26)

This implies that

{|Hm(un)Tk(u)μ|}ax,t,ununh2mun− ∇Tk(u)μhmundx dt +

Q

hx,unn1hx,unGx,t,un,unhm un

Tη Hm

un

Tk(u)μ dx dt +

Qax,t,un

unhmun Tη

Hm un

Tk(u)μ dx dt

Qf hmunTηHmunTk(u)μdx dt+(m,n),

(2.27) which gives by using the fact that

Q

hx,unn1hx,unGx,t,un,unhm un

Tη Hm

un

Tk(u)μ

dx dtCη,

{|Hm(un)Tk(u)μ|}ax,t,un

unh2mun

− ∇Tk(u)μhm un

dx dt

+(m,n) +η

{m≤|un|≤m+1}ax,t,un

undx dt,

(2.28) which gives asm→ ∞,

{|unTk(u)μ|}ax,t,un

un− ∇Tk(u)μdx dt+(n). (2.29)

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Finally from (2.22), I1+(n)

{|Tk(un)Tk(u)μ|}ax,t,Tk(u)μ

Tk un

− ∇Tk(u). (2.30) Sincea(x,t,Tk(u)μ{|Tk(un)Tk(u)μ|}a(x,t,Tk(u)μ{|Tk(u)Tk(u)μ|}inLp(Q) and Tk(un)Tk(u) weakly inLp(0,T;W01,p(Ω)), then

{|Tk(un)Tk(u)μ|}ax,t,Tk(u)μ

Tk

un

− ∇Tk(u)dx dt

= −

{|Tk(u)Tk(u)μ|}ax,t,Tk(u)μTk(u)− ∇Tk(u)dx dt+(n).

(2.31)

So

I1+(n). (2.32)

For what concerns the termI2, one has

I2=(n,μ), (2.33)

since

ax,t,Tk un

χ{|Tk(un)Tk(u)μ|}−→ax,t,Tk(u)χ{|Tk(u)Tk(u)μ|} inLp(Q)N, Tk(u)μ− ∇Tk(u)χ{|Tk(un)Tk(u)μ|}−→

Tk(u)μ− ∇Tk(u)χ{|Tk(u)Tk(u)μ|}. (2.34) In the same way, we show that

I3=(n,μ), I4=(n,μ), I5=(n,μ). (2.35) Combining the above estimates, we get

nlim→∞

Q

ax,t,Tkunax,t,Tk(u)Tkun− ∇Tk(u)θdx dt=0. (2.36)

Then there exists a subsequence also denoted by (un) such that

un−→ ∇u a.e. inQ. (2.37)

Step 3. From (2.16), we deduce that

Q

hx,unnGx,t,un,undx dtC, (2.38)

which gives for everyβ >0,

|h(x,Tβ(un))|>k

Gx,t,Tβ un

,Tβ

undx dt C

kn, (2.39)

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L

wherek >1. Lettingn+forkfixed, we deduce by using Fatou’s lemma

|h(x,Tβ(u))|>k

Gx,t,Tβ(u),Tβ(u)dx dt=0, (2.40)

and so, by (2.4)

hx,Tβ(u)1 a.e. inQ. (2.41)

So

q(x)Tβu(x)q+(x) a.e. inQ. (2.42) Letting nowβ+, we deduce also that

q(x)u(x)q+(x) a.e. inQ. (2.43) Step 4. Strong convergence of the truncations.

We will prove that

nlim→∞

Q

ax,t,Tkunax,t,Tk(u)Tkun− ∇Tk(u)dx dt=0. (2.44)

Fixk >0 and letϕ(s)=exp(δs2),δ >0. Letl > kand define the functionRl(s)=s

0ρl(t)dt.

Let us considerωmμ =Tk(Hm(u)μ), wherevμ is the mollification with respect to timev.

Lettingvmμ,n=ρl(Hm(un))ϕ(Tk(Hm(un))ωmμ) as test function in the problem (Rn), we get

T

0

∂Hmun

∂tlHmunϕTkHmunωmμdt +

Qax,t,ununh2unρlHmunϕTkHmunωmμdx dt +

Qax,t,unTkHmun− ∇ωmμ

×hmunρlHmunϕTkHmunωmμdx dt +

Qax,t,un

unhmun ρl

Hm un

ϕTk Hm

un

ωμmdx dt +

Q

hx,unn1hx,unGx,t,un,un

×hm un

ρl Hm

un ϕTk

Hm un

ωμmdx dt

=

Qf vmμ,nhmundx dt.

(2.45)

We deal now with the estimate of each term of the last equalities.

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