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(1)ASYMPTOTIC DISTRIBUTION OF EIGENFUNCTIONS AND EIGENVALUES OF THE BASIC BOUNDARY-CONTACT OSCILLATION PROBLEMS OF THE CLASSICAL THEORY OF ELASTICITY T

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ASYMPTOTIC DISTRIBUTION OF EIGENFUNCTIONS AND EIGENVALUES OF THE BASIC

BOUNDARY-CONTACT OSCILLATION PROBLEMS OF THE CLASSICAL THEORY OF ELASTICITY

T. BURCHULADZE AND R. RUKHADZE

Abstract. The basic boundary-contact oscillation problems are con- sidered for a three-dimensional piecewise-homogeneous isotropic elas- tic medium bounded by several closed surfaces. Using Carleman’s method, the asymptotic formulas for the distribution of eigenfunc- tions and eigenvalues are obtained.

1. After the remarkable papers of T. Carleman [1–2] the method based on the asymptotic investigation of the resolvent kernel (or of any other function of the considered operator) with a subsequenet use of Tauberian theorems has become quite popular. By generalizing Carleman’s method (and combining it with the variational one) A. Plejel [3] derived the asymp- totic formulas for the distribution of eigenfunctions and eigenvalues of the boundary value oscillation problems of classical elasticity. Mention should also be made of T. Burchuladze’s papers [4–5], where the asymptotic formu- las for the distribution of eigenfunctions of the boundary value oscillation problems are obtained for isotropic and anisotropic elastic bodies using in- tegral equations and Carleman’s method. Further progress in this direction was made by R. Dikhamindzhia [6]. He obtained the asymptotic formulas for the distribution of eigenfunctions and eigenvalues for two- and three- dimensional boundary value oscillation problems of couple-stress elasticity which generalize analogous formulas of classical elasticity. In his recent work M. Svanadze [7] derived the asymptotic formulas for oscillation boundary value problems of the linear theory of mixtures of two homogeneous isotropic elastic materials.

1991Mathematics Subject Classification. 73C02.

Key words and phrases. Carleman method, boundary-contact oscillation problems of elasticity, eigenfunctions and eigenvalues, asymptotic formulas for distribution, Green’s tensor.

107

1072-947X/99/0300-0107$15.00/0 c1999 Plenum Publishing Corporation

(2)

2. Throughout the paper we shall use the following notation: x = (x1, x2, x3),y= (y1, y2, y3) are points ofR3;|x−y|=€ P3

k=1(xk−yk)21/2

is the distance between the points x and y; D0 R3 is a finite domain bounded by closed surfaces S0, S1, . . . , Sm of the class Ω2(α) 0 < α 1 [8] withS0covering all otherSk while the latter surfaces not covering each other; Si∩Sk =fori6=k,i, k= 0, m; the finite domain bounded bySk

(k = 1, m) will be denoted byDk; D0 = D0€ m

k=0 Sk

, Dk = Dk∪Sk, k= 1, m.

Ifuandv are the three-component real vectorsu= (u1, u2, u3) andv= (v1, v2, v3), thenuv=P3

i=1uiviis the scalar product of these vectors;|u|=

€ P3

i=1u2i1/2

. The matrix product is obtained by multipliing a row by a column; the sign [·]T denotes the operation of transposition; ifA=kAijk3×3

is a 3×3 matrix, then|A|2 = P3

i,j=1A2ij. Any vector u= (u1, u2, u3) is treated as a 3×1 one-column matrix: u=kuik3×1;Ak =kAjkk3j=1 is the k-th column vector of the matrixA.

The vectoru= (u1, u2, u3) will be called regular inDk if ui∈C1(Dk)∩C2(Dk), i= 1,2,3.

A system of differential homogeneous equations of oscillation of classical elasticity for a homogeneous isotropic elastic medium has the form [8]

µ∆u+ (λ+µ) grad divu+ρω2u= 0, (1) whereu(x) = (u1, u2, u3) is the displacement vector, ∆ is the three-dimen- sional Laplace operator, ρ = const > 0 is the medium density, ω is the oscillation frequency,λandµare the elastic Lam´e constants satisfying the natural conditions

µ >0, 3λ+ 2µ >0.

We introduce the matrix differential operator A(∂x) =Aij(∂x)

3×3, Aij(∂x) =δijµρ1∆ + (λ+µ)ρ1 2

∂xi∂xj

,

where δij is the Kronecker symbol. Then equation (1) can be rewritten in the vector-matrix form

A(∂x)u+ω2u= 0. (2)

The matrix-differential operator

T(∂x, n(x)) =Tij(∂x, n(x))

3×3, where

Tij(∂x, n(x)) =λρ1ni(x)

∂xj

+λρ1nj(x)

∂xi

+µρ1δij

∂n(x),

(3)

n(x) is an arbitrary unit vector at the point x(if x∈ Sk, thenk = 0, m is the normal unit vector external with respect to the domainD0) is called the stress operator.

It will be assumed that the domainsDk,k= 0, m0 are filled with homo- geneous isotropic elastic media with the Lam´e constantsλk,µk and density ρk, while the other domainsDk,k=m0+ 1, mare hollow inclusions. When the operatorsAandT containλk andµk instead ofλandµ, we shall write

k

AandTk, respectively.

We introduce the notation u+(z) = lim

D03xzSk

u(x), k= 0, m; u(z) = lim

Dk3xzSk

u(x), k= 1, m0. The notation €

T(∂z, n(z))u(z)±

has a similar meaning.

3. A Kupradze matrix of fundamental solutions of the homogeneous equation of oscillation (2) has the form [8]

Γ(x−y, ω2) =Γkj(x−y, ω2)

3×3, where

Γkj(x−y, ω2) =ρδkj

4πµ eik2r

r 1

4πω2

2

∂xk ∂xj

eik1r−eik2r

r , (3)

iis the imaginary unit,r=|x−y|,k1 andk2 are the nonnegative numbers defined by the equalities

k12= ρω2

λ+ 2µ, k22=ρω2

µ . (4)

Let κ0 be an arbitrary real fixed positive integer and κ > κ0 be an arbitrary number. If in (3) we replaceω=, then we obtain

Γkj(x−y,−κ2) =ρδkj

4πµ eκrc2

r + 1

κ2

2

∂xk∂xj

eκrc1 −eκrc2

r , (5)

wherec21= (λ+ 2µ)ρ1,c22=µρ1. Sinceµ >0 and 3λ+ 2µ >0, we have λ+µ >0 andλ+ 2µ > µ. Hence c1> c2 and c11 < c21. Letδ < 2c1

1 be an arbitrary positive integer. Then (5) can be rewritten as

Γkj(x−y,−κ2) = ρδkj

4πµeακreδ1κr

r +

+ 1 4πκ2

2

∂xk∂xjeακreδκr

r −eδ1κr r

‘

, (6)

whereδ1=c12 −α= c12 c11 +δ >0.

Moreover,

(4)

(1)

∂xj



eακreδ1κr r

‘

= eακr

r2 eδ1κr

1 1

c2κr‘ ∂r

∂xj

; (2) 2

∂xk∂xj

eακreδ1κr r

‘= eακr

r3 eδ1κr 3 + 3

c2κr+

+1

c22κ2r2‘ ∂r

∂xj

∂r

∂xk

+eακr

r3 eδ1κr

1 1 c2κr‘

δkj ∂r

∂xk

,

(3) the functions (κr)neδ1κr,n= 0,1,2, . . . are bounded in the inter- valκ∈[0,+).

Taking into account the above arguments, from (6) we obtain the esti- mates

ŒŒ

ŒnΓpq(x−y,−κ2)

∂xi1∂xj2∂xk3

ŒŒ

Πconst

rn+1eακr, (7) i+j+k=n; n= 0,1,2, . . .; p, q= 1,3.

4. Let x, y ∈Dk, k= 0, m0 and ly be the distance from the pointy to the boundary ofDk.

Denoteρy(x) = max{r, ly}.and introduce an auxiliary matrix bk

Γ(x−y,−κ2) =

” 1

1 rm ρmy (x)

‘n•k

Γ(x−y,−κ2), (8) where Γ(xk −y,−κ2) is the Kupradze matrix of fundamental solutions for the operatorA(∂x)k −κ2I (I is the 3×3 unit matrix).

We denote by B(y, ly) a sphere of radius ly and center at the point y, and by C(y, ly) its boundary. It is easy to verify that €

1 ρmyrm(x)

n

vanishes together with its derivatives up to the (n1)-th order inclusive when the point x B(y, ly) tends to the point of the boundary C(y, ly).

Forx∈Dk\B(y, ly) we have 1

1 rm ρmy(x)

‘n

= 1 and

B(y,ly)3xlimzC(y,ly)

” 1

1 rm ρmy (x)

‘n•

= 1.

Thus

bk

Γ(x−y,−κ2) =Γ(xk −y,−κ2)

for x∈ Dk\B(y, ly), while, in passing the boundaryC(y, ly), the function b

k

Γ and its derivatives up to the (n1)th order inclusive remain continuous.

(5)

We writebk Γ as bk

Γ(x−y,−κ2) =Γ(xk −y,−κ2

nrmmy(x) +· · · .

It is easy ti find that bk

Γ and its derivatives up to the (m2)-th order inclusive are continuous forx=y, while for x∈B(y, ly) we have, by virtue of (7), the estimates

ŒŒ

Œsbk

Γpq(x−y,−κ2)

∂xi1∂xj2∂xk3

ŒŒ

Œconsteακr

lym rms1, (9) p, q= 1,3, i+j+k=s; m≥s+ 1.

5. We determine the limit

xlimy

hk

Γ(x−y,−κ2)Γ(xk −y,−κ02)i

, x, y∈Dk, k= 0, m0. Taking into consideration the expansion

eκc1r r = 1

r κ c1

+ κ2

2!c21r− κ3

3!c31r2+· · · , we obtain

(1) eκc2r

r −eκ0 c2r

r = κ0−κ c2

+κ2−κ20

2!c22 r+· · ·, (2) eκc1r

r −eκc2r r =κ

1 c1

+ 1 c2

‘

+κ2 1

2!c21 1 2!c22

‘ r+

+κ3

1

3!c31+ 1 3!c32

‘r2+· · ·,

(3) 2

∂xk∂xj

eκc1r −eκc2r

r =κ2 1

2!c21 1 2!c22

‘ 2r

∂xk∂xj

+ +κ3 1

6c32 1 6c31

‘ 2r2

∂xk ∂xj

+· · · , (4) 2r2

∂xk∂xj = 2δkj.

By virtue of the above relations we have

xlimy

hk

Γpq(x−y,−κ2)Γkpq(x−y,−κ02)i

=

= (κ0−κ3/2k

4πµ3/2k δpq+(κ0−κ3/2k 12π

” 1

k+ 2µk)3/2 1 µ3/2k

• δpq=

(6)

= (κ0−κ3/2k 12π

” 1

k+ 2µk)3/2 + 2 µ3/2k

•

δpq, p, q= 1,3. (10)

6. Our further investigation will be carried out for the first problem.

The other problems are treated analogously.

We apply the term “Green’s tensor of the first basic boundary-contact problem of the operatorA(∂x)k −κ02I” to the 3×3 matrixG(x, y,−κ02) = G(x, y,k −κ20),x∈Dk,y∈D €

D= m0

k=0Dk

,x6=y,k∈0, m0 which satisfies the following conditions:

(1)∀x∈Dk,∀y∈D,x6=y:

k

A(∂x)G(x, y,k −κ02)−κ20 k

G(x, y,−κ20) = 0,k= 0, m0, (2)∀z∈Sk, ∀y∈D:G+(x, y,−κ02) =Gk (x, y,−κ02),

€

T(∂z, n(z))G(z, y, −κ02+

k

T(∂z, n(z))G(z, y,k −κ20

,k= 1, m0, (3)∀z∈Sk, ∀y∈D:G+(z, y,−κ02) = 0, k= 0, m0+ 1, . . . , m;

(4)G(x, y,k −κ20) =Γ(xk −y,−κ02)−g(x, y,k −κ02),x∈Dk,y∈D,k= 0, m0, whereg(x, y,k −κ02) is a regular in Dk solution of the following problem:

(1)∀x∈Dk,∀y∈D:A(∂x)k g(x, y,k −κ02)−κ02

kg(x, y,−κ02) = 0,k= 0, m0; (2)∀z∈Sk, ∀y∈D:g+(z, y,−κ02)−gk(z, y,−κ02) =

=Γ(z −y,−κ20)Γ(zk −y,−κ02),

€

T(∂z, n(z))g(z, y, −κ02+

€k

T(∂z, n(z))g(z, y,k −κ20

=

=T(∂z, n(z))Γ(z −y,−κ02)−T(∂k z, n(z))Γ(zk −y,−κ20),k= 1, m0; (3)∀z∈Sk, ∀y∈D:g+(z, y,−κ02) =Γ(z −y,−κ02),

k= 0, m0+ 1, . . . , m;

The solvability of this problem is shown in [8] and thereby the existence of G(x, y,−κ20) is proved. As is known [8],G(x, y,−κ02) possesses a symmetry property of the form

G(x, y,−κ20) =GT(y, x,−κ02). (11) Moreover, we have the estimates [9]

(x, y)∈Dk×Dk :Gpq(x, y,−κ02) =O(|x−y|1),

∂xj

Gpq(x, y,−κ02) =O(|x−y|2), m, n, j= 1,3; k= 0, m0.



(12)

(7)

7. Let u(x) = u(x) andk v(x) = v(x),k x Dk, be arbitrary (regular) vectors of the classC1(Dk)∩C2(Dk),k= 0, m0. Then the following Green formula is valid [8]:

m0

X

k=0

Z

Dk

(vkAkuk+E(k v,k u))dxk = Z

S

v+(Tu) +ds+

+

m0

X

k=1

Z

Sk

€

v+(Tu) +kv(Tku)k 

ds, (13)

whereS=S0 m

k=m0+1Sk,

k

E(v,k u) =k ρk1(3λk+ 2µk)

3 divvkdivuk+ρk1µk

2 X

p6=q

∂vkp

∂xq

+

+∂vkq

∂xp

‘∂ukp

∂xq +∂ukq

∂xp

‘

+ρk1µk

3 X

p,q

∂vkp

∂xp −∂vkq

∂xq

‘∂ukp

∂xp −∂ukq

∂xq

‘ . (14)

It follows from (14) thatE(k v,k u) =k E(k u,k kv) andE(k v,k kv)≥0.

For the regular inDk,k= 0, m0vectoru(x) the following general integral representation is valid [8]:

∀y∈Dk: uj(y) =

m0

X

k=0

Z

Dk

k

Γj(x−y,−κ2)(A(∂x)k u(x)k −κ2u(x))dxk +

+ Z

S

‚k

Γj(z−y,−κ2)(T(∂ z, n(z))u(z)) +

−u+(z)T(∂z, n(z))Γj(z−y,−κ2dzS+ +

m0

X

k=1

Z

Sk

‚

Γj(z−y,−κ2)(T(∂ z, n(z))u(z)) +

Γkj(z−y,−κ2)(Tk(∂z, n(z))u(z))k ƒ dzS−

m0

X

k=1

Z

Sk

‚

u+(z)(T(∂z, n(z))Γj(z−y,−κ2)

−uk(z)(Tk(∂z, n(z))Γkj(z−y,−κ2

dzS, j = 1,2,3. (15)

(8)

8. To establish the asymptotic behavior of eigenfunctions and eigenvalues we have to estimate the regular part of Green’s tensorg(x, y,−κ2) asκ→

. To this end we consider the functional L[u] =

m0

X

k=0

Z

Dk

€k

E(u,k u) +k κ2uk2 dx−2

m0

X

k=1

Z

Sk

‚

u+(z)T(∂z, n(z))×

×Γj(z−y,−κ2)−uk(z)(Tk(∂z, n(z))Γkj(z−y,−κ2

dzS, (16) wherej = 1,2,3 is the fixed number andyis an arbitrary fixed point inDk, k= 0, m0, which is defined in the class of regular inDk, k= 0, m0, vector functions satisfying the conditions:

(1)∀z∈Sk : u+(z)−uk(z) =Γj(z−y,−κ2)Γkj(z−y,−κ2), (Tu(z)) +(Tku(z))k =T(∂z, n(z))Γj(z−y,−κ2)

Tk(∂z, n(z))Γkj(z−y,−κ2),k= 1, m0,

(2)∀z∈Sk : u+(z) =Γj(z−y,−κ2), k= 0, m0+ 1, . . . , m.

Theorem 1.The functionalLtakes a minimal value foru=gj(x, y,−κ2).

Proof. Let ube an arbitrary vector from the domain of definition of the functionalL, and letv=u−gj. Then, with (14) taken into account, (16) implies

L[u] =L[v+gj] =

m0

X

k=0

Z

Dk

€k

E(vk+gkj,kv+kgj) +κ2(vk+gkj)2ƒ dx−

2

m0

X

k=1

Z

Sk

‚(v+gj)TΓj(kv+kgj)TkΓkjƒ ds=

=

m0

X

k=0

Z

Dk

‚k

E(v,k kv) + 2E(k v,k gkj) +E(k gkj,kgj) +κ2(kv2+ 2vkkgj+gkj2dx−

m0

X

k=1

Z

Sk

‚

v+TΓjkvTkΓkj

ƒds−2

m0

X

k=1

Z

Sk

€

gj+TΓj−gkjTkΓkj

ƒds=

=L[gj] +

m0

X

k=0

Z

Dk

‚k

E(kv,v) +k κ2vk2ƒ dx+ 2

m0

X

k=0

Z

Dk

‚k

E(kv,gkj) +

+κ2kvkgjƒ dx−2

m0

X

k=1

Z

Sk

‚

v+TΓjkvTkΓkj

ƒds. (17)

(9)

Using the Green formula (13) for v = u−gj, u = gj and taking into account that Akkgj =κ2kgj, v+(z) = 0 for z∈Sk,k = 0, m0+ 1, . . . , m, we obtain

m0

X

k=0

Z

Dk

‚k

E(v,k kgj) +κ2vkkgjƒ dx=

m0

X

k=1

Z

Sk

‚

v+(Tgj)+−vk(Tkkgj)ƒ

ds. (18)

Now, since v+(z) = kv(z), (Tgj)+(Tkgkj) =TΓj −TkΓkj forz ∈Sk, k= 1, m0 (17) by virtue of (18) takes the form

L[u] =L[gj] +

m0

X

k=0

Z

Dk

‚k

E(kv,v) +k κ2vk2ƒ

dx≥L[gj].

Theorem 2. The estimate

ŒŒgjj(y, y,−κ2)−gjj(y, y,−κ02)ŒŒconst ly1+δ

, y∈D, δ >0, (19) holds for the function gjj(y, y,−κ2).

Proof. We write formula (15) foruj(x) =gjj(x, y,−κ2) and Γj(x−y,−κ2) = Gj(x−y,−κ2). Then taking into account the boundary and contact con- ditions forg andG, we get

(x, y)∈Dk:gjj(x, y,−κ2) =

= Z

S

Γj(z−x,−κ2)(T(∂ z, n(z))Gj(z, y,−κ2))+dzS−

+

m0

X

k=1

Z

Sk

‚

Gj+(z, x,−κ2)T(∂z, n(z))Γj(z−y,−κ2)

−Gkj(z, x,−κ2)Tk(∂z, n(z))Γkj(z−y,−κ2dzS−

m0

X

k=1

Z

Sk

‚

Γj(z−x,−κ2)(T(∂z, n(z))Gj(z, y,−κ2))+

Γkj(z−x,−κ2)(Tk(∂z, n(z))Gkj(z, y,−κ2))ƒ

dzS. (20)

Using formula (13) foru=v, (16) can be rewritten as L[u] =−

m0

X

k=0

Z

Dk

uk‚k

A(∂x)u(x)k −κ2u(x)k ƒ dx+

Z

S

u+(z)(Tu(z)) +dzS+

(10)

+

m0

X

k=1

Z

Sk

‚

u+(z)(Tu(z)) +−uk(z)(Tku(z))k ƒ dzS−

2

m0

X

k=1

Z

Sk

‚

u+(z)T(∂ z, n(z))Γj(z−y,−κ2)

−uk(z)Tk(∂z, n(z))Γkj(z−y,−κ2

dzS. (21)

which foru(x) =gj(x, y,−κ2) = Γj(x−y,−κ2)−Gj(x, y,−κ2) implies L[gj] =

Z

S

Γj(z−y,−κ2)T(∂ z, n(z))Γj(z−y,−κ2)dzS−

Z

S

Γj(z−y,−κ2

T(∂z, n(z))Gj(z, y,−κ2+

dzS+

+

m0

X

k=1

Z

Sk

‚

Γj(z−y,−κ2)T(∂z, n(z))Γj(z−y,−κ2)

Γkj(z−y,−κ2)T(∂k z, n(z))Γkj(z−y,−κ2dzS+ +

m0

X

k=1

Z

Sk

‚

Gj+(z, y,−κ2)T(∂z, n(z))Γj(z−y,−κ2)

−Gkj(z, y,−κ2)Tk(∂z, n(z))Γkj(z−y,−κ2dzS−

m0

X

k=1

Z

Sk

‚

Γj(z−y,−κ2)(T(∂z, n(z))Gj(z, y,−κ2))+

Γkj(z−y,−κ2)(T(∂k z, n(z))Gkj(z, y,−κ2))ƒ

dzS. (22)

On the basis of (22), from (20) we obtain gjj(y, y,−κ2) =L[gj]

Z

S

Γj(z−y,−κ2)T(∂z, n(z))Γj(z−y,−κ2)dzS+

+

m0

X

k=1

Z

Sk

‚

Γj(z−y,−κ2)T(∂z, n(z))Γj(z−y,−κ2)

Γkj(z−y,−κ2)Tk(∂z, n(z))Γkj(z−y,−κ2

dzS. (23)

(11)

The vectorbk

Γj(x−y,−κ2) defined by (8) belongs to the domain of defi- nition of the functionalLand, sincegj(x, y,−κ2) imparts a minimal value to the functionalL, it is obvious that

L[gj]≤L[j].

Now (23) implies

gjj(y, y,−κ2)≤L[j] Z

S

Γj

TΓjds+

+

m0

X

k=1

Z

Sk

j

TΓjΓkj k

TΓkj)ds, y∈Dk. (24)

By virtue of the properties ofΓ, from (21) we obtainb L[j] =

Z

B(y,ly)

Γbj(AbΓj−κ2j)dx+ Z

S

Γj

TΓjds−

m0

X

k=1

Z

Sk

j

TΓjΓkj k

TΓkj)ds. (25)

By (25) and (24) we have gjj(y, y,−κ2)≤ −

Z

B(y,ly)

Γbj(AbΓj−κ2Γbj)dx, y∈Dk, k= 0, m0. (26)

Taking into account estimates (9), form= 5 we obtain

ŒŒbΓmj(x, y,−κ2)ŒŒ const ly

for s= 0,

ŒŒκ2ij(x, y,−κ2)ŒŒ≤κ2consteακr ly5 r4=

= const

ly5 r2(κ2r2)eακrconst

l3y for s= 0,

ŒŒAj(x, y,−κ2)ŒŒconst

l3y for s= 2.

Hence (26) implies

gjj(y, y,−κ2) const ly4 ·4

3πl3y const

ly const l1+δy

, (27)

whereδ >0 is an arbitrary integer.

(12)

Let us estimate gjj(y, y,−κ2) from below. For this we introduce the notation:

M[u] =

m0

X

k=0

Z

Dk

‚k

E(u,k u) +k κ2uk2ƒ

dx, M0[u] =

m0

X

k=0

Z

Dk

‚k

E(u,k u) +k κ02

uk2ƒ dx,

N[u] =

m0

X

k=1

Z

Sk

‚

u+(z)TΓj(z−y,−κ2)−uk(z)TkΓkj(z−y,−κ2dzS.

Sinceκ02≤κ2, we have

L[gj(x, y,−κ2)] = minL[u] = min(M[u]2N[u])min(Mo[u]2N[u]).

Let the vector functionϕ(x, y) impart a minimal value to the functional M0[u]2N[u]. Then ϕ(x, y) is a regular inDk (k= 0, m0) solution of the following problem:

(1)∀x∈Dk,∀y∈D:A(∂x)k ϕ(x, y)k −κ02

ϕ(x, y) = 0,k k= 0, m0;

(2)∀z∈Sk,∀y∈D:ϕ+(z, y)−ϕk(z, y) =Γ(z −y,−κ2)Γ(zk −y,−κ2), (Tϕ(z, y)) +(Tkϕ(z, y))k =TΓ(z −y,−κ2)−TkΓ(zk −y,−κ2);

(3)∀z∈Sk,∀y∈D:ϕ+(z, y) =Γ(z −y,−κ2),k= 0, m0+ 1, . . . , m.

Rewriting formula (15) forϕ(x, y) with Γ =G, we obtain

(x, y)∈Dk:ϕ(x, y) =− Z

S

Γj(z−x,−κ2)TGj(z, y,−κ20)dzs+

+

m0

X

k=1

Z

Sk

‚

Gj(z, x,−κ02)TΓj(z, y,−κ2)−Gkj(z, x,−κ02)×

×TkΓkj(z−y,−κ2dzs−

m0

X

k=1

Z

Sk

‚

Γj(z−x,−κ2)(TGj(z, y,−κ02))+

Γkj(z−x,−κ2)(TkGkj(z, y,−κ20))ƒ

dzs. (28)

By (7) and (12) and the theorem on kernel composition [10] it follows from (28) that

(x, y)∈Dk×Dk: |ϕ(x, y)| ≤ const rxy

, k= 0, m0, rxy =|x−y|. (29) In that case

L[gj(x, y,−κ2)≥M0[ϕ]2N[ϕ]≥ −2N[ϕ] =

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