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Volume 2007, Article ID 27906,13pages doi:10.1155/2007/27906

Research Article

A Common Fixed Point Theorem in D

-Metric Spaces

Shaban Sedghi, Nabi Shobe, and Haiyun Zhou

Received 27 February 2007; Accepted 16 July 2007 Recommended by Thomas Bartsch

We give some new definitions ofD-metric spaces and we prove a common fixed point theorem for a class of mappings under the condition of weakly commuting mappings in completeD-metric spaces. We get some improved versions of several fixed point theo- rems in completeD-metric spaces.

Copyright © 2007 Shaban Sedghi et al. This is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited.

1. Introduction

The concept of fuzzy sets was introduced initially by Zadeh [1] in 1965. Since then, to use this concept in topology and analysis many authors have expansively developed the theory of fuzzy sets and applications. Especially, Deng [2], Erceg [3], Kaleva and Seikkala [4], and Kramosil and Mich´alek [5] have introduced the concepts of fuzzy metric spaces in different ways. George and Veeramani [6] and Kramosil and Mich´alek [5] have in- troduced the concept of fuzzy topological spaces induced by fuzzy metric which have very important applications in quantum particle physics particularly in connection with both string andE-infinity theories which were given and studied by El Naschie [7–10].

Many authors [11–17] have studied the fixed point theory in fuzzy (probabilistic) metric spaces. On the other hand, there have been a number of generalizations of metric spaces.

One of such generalizations is generalized metric space (orD-metric space) initiated by Dhage [18] in 1992. He proved the existence of unique fixed point of a self-map satis- fying a contractive condition in complete and boundedD-metric spaces. Dealing with D-metric space, Ahmad et al. [19], Dhage [18,20], Dhage et al. [21], Rhoades [22], Singh and Sharma [23], and others made a significant contribution in fixed point theory of D-metric space. Unfortunately, almost all theorems inD-metric spaces are not valid (see [24–26]).

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In this paper, we introduceD-metric which is a probable modification of the def- inition ofD-metric introduced by Dhage [18,20] and prove some basic properties in D-metric spaces.

In what follows (X,D) will denote aD-metric space,Nthe set of all natural num- bers, andR+the set of all positive real numbers.

Definition 1.1. LetXbe a nonempty set. A generalized metric (orD-metric) onXis a function,D:X3[0,), that satisfies the following conditions for eachx,y,z,aX:

(1)D(x,y,z)0,

(2)D(x,y,z)=0 if and only ifx=y=z,

(3)D(x,y,z)=D(p{x,y,z}), (symmetry) where pis a permutation function, (4)D(x,y,z)D(x,y,a) +D(a,z,z).

The pair (X,D) is called a generalized metric (orD-metric) space.

Immediate examples of such a function are (a)D(x,y,z)=max{d(x,y),d(y,z),d(z,x)}, (b)D(x,y,z)=d(x,y) +d(y,z) +d(z,x).

Here,dis the ordinary metric onX.

(c) IfX=Rnthen we define D(x,y,z)=

xyp+yzp+zxp1/ p (1.1) for everypR+.

(d) IfX=R, then we define

D(x,y,z)=

0 ifx=y=z,

max{x,y,z} otherwise. (1.2)

Remark 1.2. In aD-metric space, we prove thatD(x,x,y)=D(x,y,y). For (i)D(x,x,y)D(x,x,x) +D(x,y,y)=D(x,y,y) and similarly (ii)D(y,y,x)D(y,y,y) +D(y,x,x)=D(y,x,x).

Hence by (i), (ii) we getD(x,x,y)=D(x,y,y).

Let (X,D) be aD-metric space. Forr >0, define BD(x,r)=

yX:D(x,y,y)< r. (1.3) Example 1.3. LetX=R. DenoteD(x,y,z)= |xy|+|yz|+|zx|for allx,y,zR. Thus

BD(1, 2)=

yR:D(1,y,y)<2

=

yR:|y1|+|y1|<2

= {yR:|y1|<1} =(0, 2).

(1.4)

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Definition 1.4. Let (X,D) be aD-metric space andAX.

(1) If for every xA, there existsr >0 such that BD(x,r)A, then subset A is called open subset ofX.

(2) SubsetAofXis said to beD-bounded if there existsr >0 such thatD(x,y,y)<

rfor allx,yA.

(3) A sequence{xn}inXconverges toxif and only ifD(xn,xn,x)=D(x,x,xn)0 asn→∞. That is, for each>0 there existsn0Nsuch that

nn0=⇒Dx,x,xn<(). (1.5) This is equivalent; for each>0, there existsn0Nsuch that

n,mn0=⇒Dx,xn,xm

<(∗∗). (1.6)

Indeed, if () holds, then

Dxn,xm,x=Dxn,x,xm

Dxn,x,x+D(x,xm,xm)<

2+

2=ε. (1.7) Conversely, setm=nin (∗∗), then we haveD(xn,xn,x)<.

(4) A sequence{xn}in X is called a Cauchy sequence if for each>0, there ex- istsn0Nsuch thatD(xn,xn,xm)<for eachn,mn0. TheD-metric space (X,D) is said to be complete if every Cauchy sequence is convergent.

Let τ be the set of all AX withxA if and only if there exists r >0 such that BD(x,r)A. Thenτis a topology onX(induced by theD-metricD).

Lemma 1.5. Let (X,D) be aD-metric space. Ifr >0, then ballBD(x,r) with centerxX and radiusris open ball.

Proof. LetzBD(x,r), henceD(x,z,z)< r. LetD(x,z,z)=δandr=rδ. Lety BD(z,r), by triangular inequality we haveD(x,y,y)=D(y,y,x)D(y,y,z) +D(z, x,x)< r+δ=r. HenceBD(z,r)BD(x,r). Hence the ballBD(x,r) is an open ball.

Definition 1.6. Let (X,D) be aD-metric space.Dis said to be a continuous function onX3if

nlim→∞Dxn,yn,zn=D(x,y,z) (1.8) whenever a sequence{(xn,yn,zn)}inX3converges to a point (x,y,z)X3, that is,

nlim→∞xn=x, lim

n→∞yn=y, lim

n→∞zn=z. (1.9)

Lemma 1.7. Let (X,D) be aD-metric space. ThenDis a continuous function onX3. Proof. Suppose the sequence{(xn,yn,zn)}inX3converges to a point (x,y,z)X3, that is,

nlim→∞xn=x, lim

n→∞yn=y, lim

n→∞zn=z. (1.10)

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Then for each>0 there existn1,n2, andn3Nsuch thatD(x,x,xn)</3nn1, D(y,y,yn)</3 for allnn2, andD(z,z,zn)</3nn3.

If we setn0=max{n1,n2,n3}, then for allnn0by triangular inequality we have Dxn,yn,zn

Dxn,yn,z+Dz,zn,zn

Dxn,z,y+Dy,yn,yn

+Dz,zn,zn

D(z,y,x) +Dx,xn,xn+Dy,yn,yn+Dz,zn,zn

< D(x,y,z) + 3+

3+

3 =D(x,y,z) +.

(1.11)

Hence we have

Dxn,yn,zn

D(x,y,z)<, D(x,y,z)Dx,y,zn

+Dzn,z,z

Dx,zn,yn

+Dyn,y,y+Dzn,z,z

Dzn,yn,xn

+Dxn,x,x+Dyn,y,y+Dzn,z,z

< Dxn,yn,zn+ 3+

3+

3=Dxn,yn,zn+.

(1.12)

That is,

D(x,y,z)Dxn,yn,zn

<. (1.13)

Therefore we have|D(xn,yn,zn)D(x,y,z)|<, that is, limn→∞Dxn,yn,zn

=D(x,y,z). (1.14) Lemma 1.8. Let (X,D) be aD-metric space. If sequence{xn}inXconverges tox, thenx is unique.

Proof. Letxny and y=x. Since{xn}converges tox and y, for each>0 there exist n1,n2Nsuch thatD(x,x,xn)</2nn1andD(y,y,xn)</2nn2.

If we setn0=max{n1,n2}, then for everynn0by triangular inequality we have D(x,x,y)Dx,x,xn

+Dxn,y,y<

2+

2=. (1.15)

HenceD(x,x,y)=0 which is a contradiction. So,x=y.

Lemma 1.9. Let (X,D) be aD-metric space. If sequence{xn}inXis convergent tox, then sequence{xn}is a Cauchy sequence.

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Proof. Sincexnx, for each>0 there existsn0Nsuch thatD(xn,xn,x)</2n n0. Then for everyn,mn0, by triangular inequality, we have

Dxn,xn,xm

Dxn,xn,x+Dx,xm,xm

<

2+

2=. (1.16)

Hence sequence{xn}is a Cauchy sequence.

Definition 1.10. LetAandSbe two mappings from aD-metric space (X,D) into itself.

Then{A,S}is said to be weakly commuting pair if

D(ASx,SAx,SAx)D(Ax,Sx,Sx), (1.17) for all xX. Clearly, a commuting pair is weakly commuting, but not conversely as shown in the following example.

Example 1.11. Let (X,D) be aD-metric space, whereX=[0, 1] and

D(x,y,z)= |xy|+|yz|+|xz|. (1.18) Define self-mapsAandSonXas follows:

Sx=x

2, Ax= x

x+ 2 xX. (1.19)

Then for allxinXone gets D(SAx,ASx,ASx)=

x x+ 4

x 2x+ 4

+ x x+ 4

x x+ 4

+ x x+ 4

x 2x+ 4

= 2x2

(x+ 4)(2x+ 4) 2x2 2x+ 4

= x

2 x x+ 2

+ x 2

x x+ 2

+ 0

=D(Sx,Ax,Ax).

(1.20)

So{A,S}is a weakly commuting pair.

However, for any nonzeroxXwe have SAx= x

x+ 4> x

2x+ 4=ASx. (1.21)

ThusAandSare not commuting mappings.

2. The main results

A class of implicit relation. Throughout this section (X,D) denotes aD-metric space andΦdenotes a family of mappings such that eachϕΦ,ϕ: (R+)5→R+, andϕis con- tinuous and increasing in each coordinate variable. Alsoγ(t)=ϕ(t,t,a1t,a2t,t)< tfor everytR+wherea1+a2=3.

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Example 2.1. Let ϕ: (R+)5→R+be defined by ϕt1,t2,t3,t4,t5

=1 7

t1+t2+t3+t4+t5

. (2.1)

The following lemma is the key in proving our result.

Lemma 2.2. For everyt >0,γ(t)< tif and only if limn→∞γn(t)=0, whereγndenotes the composition ofγwith itselfntimes.

Our main result, for a completeD-metric spaceX, reads as follows.

Theorem 2.3. LetAbe a self-mapping of completeD-metric space (X,D), and letS,T be continuous self-mappings onXsatisfying the following conditions:

(i){A,S}and{A,T}are weakly commuting pairs such thatA(X)S(X)T(X);

(ii) there exists aϕΦsuch that for allx,yX, D(Ax,Ay,Az)

ϕ(D(Sx,T y,Tz),D(Sx,Ax,Ax),D(Sx,Ay,Ay),D(T y,Ax,Ax),D(T y,Ay,Ay)).

(2.2) ThenA,S, andThave a unique common fixed point inX.

Proof. Letx0Xbe an arbitrary point inX. ThenAx0X. SinceA(X) is contained in S(X), there exists a pointx1X such that Ax0=Sx1.Since A(X) is also contained in T(X), we can choose a pointx2Xsuch thatAx1=Tx2. Continuing this way, we define by induction a sequence{xn}inXsuch that

Sx2n+1=Ax2n=y2n, n=0, 1, 2,...,

Tx2n+2=Ax2n+1=y2n+1, n=0, 1, 2,.... (2.3) For simplicity, we set

dn=Dyn,yn+1,yn+1

, n=0, 1, 2.... (2.4)

We prove thatd2nd2n1. Now, ifd2n> d2n1for somenN, sinceϕis an increasing function, then

d2n=Dy2n,y2n+1,y2n+1

=DAx2n,Ax2n+1,Ax2n+1

=DAx2n+1,Ax2n,Ax2n

ϕ

DSx2n+1,Tx2n,Tx2n

, DSx2n+1,Ax2n+1,Ax2n+1

,DSx2n+1,Ax2n,Ax2n DTx2n,Ax2n+1,Ax2n+1

, DTx2n,Ax2n,A2n

=ϕ

Dy2n,y2n1,y2n1

, Dy2n,y2n+1,y2n+1

,Dy2n,y2n,y2n

Dy2n1,y2n+1,y2n+1

, Dy2n1,y2n,y2n

.

(2.5)

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Since

Dy2n1,y2n+1,y2n+1

Dy2n1,y2n1,y2n

+Dy2n,y2n+1,y2n+1

=d2n1+d2n, (2.6) hence by the above inequality we have

d2nϕd2n1,d2n, 0,d2n1+d2n,d2n1

ϕd2n,d2n,d2n, 2d2n,d2n

< d2n, (2.7) a contradiction. Hence d2nd2n1. Similarly, one can prove thatd2n+1d2n for n= 0, 1, 2,.... Consequently,{dn}is a nonincreasing sequence of nonnegative reals. Now,

d1=Dy1,y2,y2

=DAx1,Ax2,Ax2

ϕ

DSx1,Tx2,Tx2

, DSx1,Ax1,Ax1

,DSx1,Ax2,Ax2 DTx2,Ax1,Ax1

, DTx2,Ax2,A2

=ϕ

Dy0,y1,y1

, Dy0,y1,y1

,Dy0,y2,y2

Dy1,y1,y1

, Dy1,y2,y2

=ϕd0,d0,d0+d1, 0,d0

ϕd0,d0, 2d0,d0,d0

=γd0

.

(2.8)

In general, we have dnγn(d0). So ifd0>0, then Lemma 2.2gives limn→∞dn=0.

Ford0=0, we clearly have limn→∞dn=0, since then dn=0 for eachn. Now we prove that sequence{Axn=yn}is a Cauchy sequence. Since limn→∞dn=0, it is sufficient to show that the sequence{Ax2n=y2n}is a Cauchy sequence. Suppose that{Ax2n=y2n} is not a Cauchy sequence. Then there is an>0 such that for each even integer 2k, for k=0, 1, 2,..., there exist even integers 2n(k) and 2m(k) with 2k2n(k)<2m(k) such that

DAx2n(k),Ax2n(k),Ax2m(k)

>. (2.9)

Let, for each even integer 2k, 2m(k) be the least integer exceeding 2n(k) satisfying (2.9).

Therefore

DAx2n(k),Ax2n(k),Ax2m(k)2

, DAx2n(k),Ax2n(k),Ax2m(k)

>. (2.10) Then, for each even integer 2kwe have

< DAx2n(k),Ax2n(k),Ax2m(k)

DAx2n(k),Ax2n(k),Ax2m(k)2

+DAx2m(k)2,Ax2m(k)2,Ax2m(k)1

+DAx2m(k)1,Ax2m(k)1,Ax2m(k)

=DAx2n(k),Ax2n(k),Ax2m(k)2

+d2m(k)2+d2m(k)1.

(2.11)

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So, by (2.10) anddn0, we obtain

limk→∞DAx2n(k),Ax2n(k),Ax2m(k)

=. (2.12)

It follows immediately from the triangular inequality that DAx2n(k),Ax2n(k),Ax2m(k)1

DAx2n(k),Ax2n(k),Ax2m(k) d2m(k)1, DAx2n(k)+1,Ax2n(k)+1,Ax2m(k)1

DAx2n(k),Ax2n(k),Ax2m(k) < d2m(k)1+d2n(k). (2.13) Hence by (2.10), ask→∞,

DAx2n(k),Ax2n(k),Ax2m(k)1

−→, DAx2n(k)+1,Ax2n(k)+1,Ax2m(k)1

−→. (2.14)

Now

DAx2n(k),Ax2n(k),Ax2m(k)

DAx2n(k),Ax2n(k),Ax2n(k)+1

+DAx2n(k)+1,Ax2m(k),Ax2m(k)

d2n(k)

DAx2n(k),Ax2m(k)1,Ax2m(k)1

, d2n(k),DAx2n(k),Ax2m(k),Ax2m(k)

DAx2m(k)1,Ax2n(k)+1,Ax2n(k)+1

, d2m(k)1

. (2.15) Using (2.14), limk→∞dn=0, and continuity and nondecreasing property of ϕin each coordinate variable, we have

ϕ(, 0,,, 0)ϕ(,, 2,,)=γ()< (2.16) ask→∞, which is a contradiction. Thus{Axn=yn}is a Cauchy sequence and hence by completeness ofX, it converges tozX. That is,

nlim→∞Axn=lim

n→∞yn=z. (2.17)

Since the sequences{Sx2n+1=y2n+1}and{Tx2n=y2n}are subsequences of{Axn=yn}; they have the same limitz. AsSandTare continuous, we haveSTx2nSzandTSx2n+1 Tz.

Now consider

DSTx2n,TSx2n+1,TSx2n+1

=DSAx2n1,TAx2n,TAx2n

DSA2n1,ASx2n1,ASx2n1

+DASx2n1,ASx2n1,ATx2n

+DATx2n,ATx2n,TAx2n

.

(2.18)

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Using (ii) and the weak commutativity of{A,S}and{A,T}, we get DSTx2n,TSx2n+1,TSx2n+1

DSx2n1,Ax2n1,Ax2n1

+DASx2n1,ATx2n,ATx2n

+DAx2n,Ax2n,Tx2n

DSx2n1,Ax2n1,Ax2n1

DS2x2n1,T2x2n,T2x2n

, DS2x2n1,ASx2n1,ASx2n1

, DS2x2n1,ATx2n,ATx2n

DT2x2n,ASx2n1,ASx2n1

, DT2x2n,ATx2n,ATx2n

+DAx2n,Ax2n,Tx2n

DSx2n1,Ax2n1,Ax2n1

DS2x2n1,T2x2n,T2x2n

,DS2x2n1,S2x2n1,SAx2n1

+DSx2n1,Sx2n1,Ax2n1

, DS2x2n1,TAx2n,TAx2n

+DTx2n,Tx2n,Ax2n

, DT2x2n,SAx2n1,SAx2n1

+DSx2n1,Sx2n1,Ax2n1

, DT2x2n,TAx2n,TAx2n

+DTx2n,Ax2n,Ax2n

+DAx2n,Ax2n,Tx2n

.

(2.19) IfD(Sz,Tz,Tz)>0, then asn→∞we have

D(Sz,Tz,Tz)

D(z,z,z) +ϕ

D(Sz,Tz,Tz), D(Sz,Sz,Sz) + 0,D(Sz,Tz,Tz) + 0 D(Tz,Sz,Sz) + 0, D(Tz,Tz,Tz) + 0

+ 0

γD(Sz,Tz,Tz)< D(Sz,Tz,Tz),

(2.20) a contradiction.Therefore,Sz=Tz.

Now we will prove thatAz=Sz. To end this, consider the inequality DSAx2n+1,Az,AzDSAx2n+1,ASx2n+1,ASx2n+1

+DAz,Az,ASx2n+1

. (2.21) Again using (ii) and the weak commutativity of{A,S}, we have

DSAx2n+1,Az,AzDSx2n+1,Ax2n+1,Ax2n+1 +ϕ

DSz,Tz,TSx2n+1

, D(Sz,Az,Az),D(Sz,Az,Az) D(Tz,Az,Az), D(Tz,Az,Az)

. (2.22)

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Takingn→∞, we have

D(Sz,Az,Az)D(z,z,z) +ϕ

D(Sz,Tz,Tz),D(Sz,Az,Az),D(Sz,Az,Az) D(Tz,Az,Az),D(Tz,Az,Az)

=ϕ0,D(Sz,Az,Az),D(Sz,Az,Az),D(Sz,Az,Az),D(Sz,Az,Az)

δD(Sz,Az,Az)< D(Sz,Az,Az)

(2.23) given there bySz=Az. ThusAz=Sz=Tz. It now follows that

DAz,Ax2n,Ax2n

ϕ

DSz,Tx2n,Tx2n

, D(Sz,Az,Az),DSz,Ax2n,Ax2n DTx2n,Az,Az, DTx2n,Ax2n,Ax2n

. (2.24) Then asn→∞, we get

D(Az,z,z)ϕD(Sz,z,z), 0,D(Sz,z,z),D(z,Az,Az), 0

γD(Az,z,z)< D(Az,z,z), (2.25) a contradiction, and thereforeAz=z=Sz=Tz. Thuszis a common fixed point ofA,S, andT. The unicity of the common fixed point is not hard to verify. This completes the

proof of the theorem.

Example 2.4. Let (X,D) be aD-metric space, whereX=[0, 1] and

D(x,y,z)= |xy|+|yz|+|xz|. (2.26) Define self-mapsA,T, andSonXas follows:

Sx=x, Ax=1, Tx=x+ 1

2 , (2.27)

for allxX.

Let

ϕt1,t2,t3,t4,t5

=1 7

t1+t2+t3+t4+t5

. (2.28)

Then

A(X)= {1} ⊂[0, 1]1 2, 1

=S(X)T(X), (2.29) and for everyxX, we have

D(ATx,TAx,TAx)=D(1, 1, 1)=0D(Ax,Tx,Tx),

D(ASx,SAx,SAx)=D(1, 1, 1)=0D(Ax,Sx,Sx). (2.30) That is, the pairs (A,S) and (A,T) are weakly commuting.

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