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FOR A SEMIBOUNDED NONMONOTONE EVOLUTION EQUATION

NIKOS KARACHALIOS, NIKOS STAVRAKAKIS, AND PAVLOS XANTHOPOULOS

Received 3 September 2002

We consider a nonlinear parabolic equation involving nonmonotone diffusion.

Existence and uniqueness of solutions are obtained, employing methods for semibounded evolution equations. Also shown is the existence of a global at- tractor for the corresponding dynamical system.

1. Introduction

We consider the following nonlinear parabolic initial boundary value problem in the open bounded intervalΩR

uta(u)uxxb(u)u2xλσ(u)= f(x), x, t >0, (1.1a)

u(x,0)=u0(x), (1.1b)

u|∂Ω=0, t >0. (1.1c) This problem extends the well studied porous medium diffusion, since no cer- tain relationship between the coefficientsa(u) andb(u) is assumed. Let us men- tion that special cases of this system may typically arise in plasma physics within the context of the fluid treatment of charged particles, and in density-dependent reaction diffusion processes in mathematical biology. Naturally enough, these systems imply only positive values foru(x, t); however, in the following treat- ment, wedo notimpose such a restriction.

In order to demonstrate a specific case-modelled system, we consider the col- lisionless evolution equation for the electron pressureP=nT, which, if we ig- nore viscosity, gets the following form in thex-direction (see, Balescu [5])

3

2Pt= −qx3 2uPx5

2Pux, (1.2)

Copyright©2003 Hindawi Publishing Corporation Abstract and Applied Analysis 2003:9 (2003) 521–538 2000 Mathematics Subject Classification: 35K55, 35B40, 35B41 URL:http://dx.doi.org/10.1155/S1085337503210022

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whereurepresents the electron velocity andq is the heat flux. Now, applying Darcy’s law (see, Aronson [3])

u= −cPx, c >0, (1.3) to the above equation, we get

3

2Pt= −qx+3 2cPx2+5

2cPPxx. (1.4)

We see that the first term on the right-hand side corresponds to porous me- dium diffusion (not considered here), whereas the other two terms constitute a specific case of (1.1a), witha(P)=(5/3)cPandb(P)=c.

Concerning the applications in the dynamics of cell populations, with a spa- tial distribution of cells, we may associate an energy densitye(u), that is an inter- nal energy per unit volume of an evolving spatial pattern, whereu(x, t) denotes the cell density (see [6,14]). In this case, the total energyE(u) in a volumeVis given by

E(u)=

Ve(u)dx. (1.5)

The change in energyδE, that is the work done in changing states by an amount δu, is given by the variational derivativeδE/δuwhich defines a potential

µ(u)=δE

δu=e(u). (1.6)

The gradient of the potentialµproduces a fluxJ, which is classically proportional to this gradient, that is

J= −(u). (1.7)

By using (1.6) and (1.7), the continuity equation for the densityuis

∂u

∂t =

a(u)uxx, a(u)=ke(u). (1.8) Writing out the diffusion term in full, we end up with the nonlinear operator that appears in (1.1a), in the special case where it holdsa(u)=b(u), that is the porous medium case. Also, the nonlinearityσ(u) may stand for the possible growth dynamics.

For completeness, let us mention some of the results, concerning the large time behavior of bounded solutions of nonlinear diffusion equations. Most of them are related to porous medium type equations (degenerate, monotone dif- fusion). In [4], the existence of a global attractor for the one-dimensional porous medium equation, attracting all orbits starting fromL-initial data, is demon- strated. Extensive studies in [1,13,15] show that theω-limit set is contained

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in the set of stationary solutions. Extensions for the unbounded domain case can be found in [10,11]. We also mention [2,7,8] on the existence of global attractors for degenerate or nondegenerate quasilinear parabolic equations.

The principal assumption that will be used throughout this paper in the study of problem (1.1) is the following assumption.

Hypothesis 1.1. a, b, σC2(R),λR, and there existsc>0 such thata(s)c (i.e., we consider nondegenerate butnonmonotonediffusion).

Due to the nonmonotonicity, the standard compactness methods on exis- tence of solutions are not sufficient. To this end,the diffusion operator is treated as a semibounded operator within the functional setting of an admissible triple. This procedure allows for the construction of unique solutions in Cw([0, T], H2 H01(Ω)), the space of weakly continuous functionsu: [0, T]H2H01(Ω).

The existence of a global attractor in the phase space H=H2H01(Ω) is proved inSection 3. The result is shown assuming monotonicity for the non- linearityb(·), considered to be nonincreasing.Nevertheless, this assumption does not imply monotonicity for the diffusion operator itself. An important feature is that this assumption is sufficient to prove further regularity with respect to time for the solutions of (1.1) constructed inSection 2. Further, using this result, we may define the semigroupS(t) :u0Hu(t)H, corresponding to our prob- lem.

We conclude by recalling some well-known results, which will be frequently used (see, [16,17,18,19]).

Lemma1.2 (Gagliardo-Nirenberg inequality). Let 1p, q, r≤ ∞, j an integer, 0jm, and j/mθ1. Then

Djupconstu1qθDmuθr, uLqWm,r(Ω),ΩRn, (1.9)

where

1 p =

j n+θ

1 r

m n

+1θ

q . (1.10)

Ifmjn/ris not a nonnegative integer, then the inequality holds forj/mθ <1.

Lemma 1.3 (uniform Gronwall). Let g, h, y be three positive locally integrable functions fort0t <which satisfy

d y

dt g y+h, tt0, t+r

t g(s)dsα1,

t+r

t h(s)dsα2,

t+r

t y(s)dsα3,

(1.11)

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for alltt0, whereα12, andα3are positive constants. Then y(t+r)

α3

r +α2

expα1

, tt0. (1.12)

We also use the short (equivalent) normsux2,uxx2, anduxxx2inH01(Ω), H2H01(Ω), andH3H01(Ω), respectively (seeSection 3). From the embedding HkH01(Ω)Cbk1(Ω),k=1,2, . . . ,and the Poincar´e inequality (see [9, page 242]), we have

u(k1)constuHkH01constu(k)2. (1.13)

2. Local existence

To obtain results on local existence of solutions, we intend to write problem (1.1) as a nonlinear evolution equation in an appropriate functional setting. More precisely, we will consider anadmissible tripleof Banach spaces, which is defined as follows (see [17,18] and [19, page 784]).

Definition 2.1. Anadmissible tripleVHW has the following properties:

(i)His a real separable Hilbert space with scalar product (·|·)H, (ii){V, W}is a dual pairof real separable Banach spaces with the corresponding bilinear form

·,·(i.e.,·,·is continuous,w, v =0, for everywW, impliesv=0, and w, v =0, for everyvV, impliesw=0), (iii) the embeddingsVHW are continuous and dense, (iv) it holdsh, v =(h|v)H, for allhH,vV.

Clearly, an admissible triple generalizes the notion of the evolution triple, in the sense that for an admissible triple it may holdW=V. This generalization is necessary in order to tackle the extended version of diffusion in hand. For problem (1.1), we select the spaces

V=H4H01(Ω), H=H2H01(Ω), W=L2(Ω). (2.1) Lemma2.2. The embeddingVHWfor the spaces (2.1) defines an admissible triple.

Sketch of the proof. Consider the bilinear form ·,·:W×V R, defined by the integral

w, v =

vw+wvxxxxdx, vV, wW. (2.2) Now, it is easy to check that the inner product stemming from the bilinear form·,·

(w|v)H=

vw+wxxvxxdx, for everywH, vH (2.3)

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induces an equivalent norm inH. We also have that w, v =

vw+wvxxxxdx

w2v2+w2vxxxx

2

cwWvV,

(2.4)

hence the bilinear form ·,·is continuous. Now assume that, for some w W, it holdsw, v =0, for everyvV. Classical arguments on existence and regularity of solutions for linear elliptic equations (see [12, Chapter II]) imply the existence of solutions for the problem

vvxxxx=w, vV. (2.5)

For this solutionv, we have that

0= w, v =

w2dx, (2.6)

which implies thatw=0 and the proof is complete.

We introduce the nonlinear operatorsA,B:VWdefined by

Au= −a(u)uxx, Bu= −b(u)u2x. (2.7) The following results outline the basic properties of the operatorsAandB.

Proposition2.3. The operatorA+B:HWis bounded on bounded sets ofH. Proof. LetB=BH(R) be a closed ball inH. We will show that there exist con- stantsK1(R) andK2(R) such that

Au2K1(R)uH, Bu2K2(R)uH, uB. (2.8) Sincea,b,σC2(R) and the embeddingHC1b(Ω) is continuous, it follows that there exist constantsC1,m(R) andC2,m(R),m=0,1,2, such that

sup

x

a(m)u(x)C1,m(R), m=0,1,2, (2.9) sup

x

b(m)u(x)C2,m(R), m=0,1,2. (2.10)

Using (2.9), (2.10), and the fact thatH01(Ω) is a generalized Banach algebra, we may obtain the inequalities

Au2sup

x

au(x)uxx

2K1(R)uH, Bu2sup

x

bu(x)u2x2const sup

x

bu(x)u2H

K2(R)uH.

(2.11)

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Finally, we conclude that

(A+B)u2K(R)uH, (2.12)

whereK(R)=max{K1(R), K2(R)}.

Proposition2.4. The operatorA+B:HWis locally Lipschitz continuous.

Proof. Letu, vB=BH(R) be a closed ball inH. We have that AuAv2a(u)a(v)vxx

2+a(u)uxxvxx

2. (2.13)

From the mean value theorem and (2.9), we get

au(x)av(x)C1,1(R)u(x)v(x), (2.14) au(x)av(x)C1,2(R)u(x)v(x). (2.15)

Therefore,

a(u)a(v)vxx2

2C1,1(R)2uv2vxx2

2C(R)uv2H, a(u)uxxvxx2

2C21,0(R)uxxvxx2

2C(R)uv2H, (2.16) whereC(R) is a common symbol for the constants. Similar inequalities hold for the operatorB. So finally it holds that

(A+B)u(A+B)v2C(R)uvH. (2.17) Proposition2.5. The operatorA+B:HWis semibounded.

Proof. By definition, it must be proved that there exists a monotone increasing functiond1C1(R) such that

(A+B)u, u ≥ −d1

u2H

, for everyuV. (2.18) LetuC0(Ω)C(Ω). For the operatorA, it holds

Au, u =

Auu dx+

Auuxxxxdx. (2.19)

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Integration by parts in the second integral on the right-hand side of (2.19) gives

a(u)uxxuxxxxdx= −1 2

a(u)u2xu2xxdx1 2

a(u)u3xxdx +

a(u)u2xxxdx.

(2.20)

UsingLemma 1.2, we obtain the inequality

uxx4constu1/42 uxxx3/42 , (2.21)

which, with the aid of (2.9) and Young’s inequality, gives the following estimate:

1 2

a(u)u2xu2xxdx1 2

a(u)u3xxdx

≥ −C1,2ux2

uxx2

2C1,1uxx

2uxx2

4

≥ −Cˆ1u4HCˆ2uHu1/22 uxxx3/2

2

≥ −Cˆ1u4HCˆ3u3/2H uxxx3/2

2

≥ −Cˆ1u4HCˆ4u6Hc 2 uxxx2

2.

(2.22)

For the first integral of the right-hand side of (2.19), we have

a(u)uxxu dx≥ −C1,0uuxx1≥ −Cˆ0u2H. (2.23) UsingHypothesis 1.1, (2.19), (2.20), (2.22), (2.23), and density arguments, we obtain that

Au, u ≥ −Cˆ0u2HCˆ1u4HCˆ4u6H:= −d1,1u2H

. (2.24)

A similar procedure may be followed for the operatorB, to derive the relation Bu, u ≥ −d1,2

u2H

. (2.25)

Finally, from estimates (2.24) and (2.25) we get that there exists a monotone increasingC1- functiond1:RRsatisfying (2.18).

The previous propositions enable us to show local existence of solutions. The result is stated as follows.

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Theorem2.6. Letu0, f H. Assume thatHypothesis 1.1is satisfied. Then there existsT >0such that problem (1.1) has a unique solution

uCw[0, T], H, utCw[0, T], W. (2.26) Moreover, the solutionu: [0, T]Wis Lipschitz continuous.

Proof. (A)Existence: the first step is to show existence of at least one solution in a finite dimensional subspaceVn=span{e1, . . . , en}ofV, where{ei}i1is an orthonormal basis ofVnwith respect to (·|·)H. It holds thatnVn=VH.

We define the linear and continuous operator ˜Pn:WV as P˜nw=

n i

w, ei ei, wW. (2.27)

Now, the Galerkin equation for problem (1.1) onVnVHreads

un(t) + ˜Pn(A+B)un(t)=P˜nCun(t), t[0, T], un(0)=P˜nu0, (2.28) where

Cun(t)=λσun(t)+f . (2.29) Using Propositions2.3and2.4, Peano’s theorem justifies the existence of aC1 solution for (2.28),un: [0, T0]Vn, for someT0>0 which depends onn.

The next step is to obtain an a priori estimate for un inH. Note that ˜Pn: HVn is an orthogonal projection onto the spaceVn, since it holds ˜Pnu= n

i(u|ei)Hei,uH. Sinceunis continuous on [0, T0], (2.28) implies that un|un

H= −P˜n(A+B)un|un

H+P˜nCun|un

H

= −

(A+B)un, un +Cun, un . (2.30) Now, it is not hard to verify that there exists a monotone increasing function d2C1(R) such that

Cu, u d2

u2H

, uV. (2.31)

Hence, from (2.18), (2.30), and (2.31) we obtain the differential inequality d

dtun(t)2H2dun(t)2H, t 0, T0

, (2.32)

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whereun(0)H= Pnu0Hu0H. Since the functiond(·) is Lipschitz con- tinuous as aC1function, we may apply the theorem of Picard-Lindel¨of to con- clude that there exists aT >0, this time independent ofn, such that

un(t)2H max

t[0,T]g(t)R, t[0, T]. (2.33) Finally, using standard continuation arguments, we can extend the solutionun to the interval [0, T].

Now, from (2.33) we have that there exists a subsequence, denoted again by {un},such that

un(t) u(t), inH,asn−→ ∞, (2.34) at least in a dense countable subset of [0, T]. LetvVkH,kn. Since ˜Pnv= v, for everykn, it follows that

un(t)|vH= −P˜n(A+BC)un(t)|vH= −

(A+BC)un(t), v . (2.35) Using Proposition 2.3 and estimate (2.33), we conclude that (un(t)|v)H is equicontinuous on [0, T], which implies that (2.34) holds in the whole inter- val [0, T]. Finally, passing to the limit to (2.35) and using density ofkVkinH, we obtain thatuCw([0, T], H),utCw([0, T], W) is a solution for problem (1.1) and as a consequence,u: [0, T]Wis Lipschitz continuous.

(B)Uniqueness: the difference of solutionsw=uvof problem (1.1) satisfies the following initial value problem:

wta(u)wxxA(u, v)vxxB(u, v)λΣ(u, v)=0, w(0)=0, (2.36) where A(u, v)=a(u)a(v),B(u, v)=(b(u)b(v))vx2+b(u)(u2xv2x), andΣ(u, v)=σ(u)σ(v). Multiplying (2.36) byuand integrating overΩ, we obtain the equation

1 2

d dtw22+

a(u)vxwwxdx+

a(u)a(v)wxvxdx +

a(u)uxwwxdx+

a(u)a(v)vx2w dx

b(u)b(v)vx2w dx

b(u)u2xv2xw dx +

a(u)w2xdxλ

σ(u)σ(v)w dx=0.

(2.37)

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Using estimate (2.33) and relations (2.9), (2.10), and (2.15) the following es- timates are derived:

a(u)a(v)vx2w dxC1,2vx2w22C(R)w22,

a(u)vxwwxdxC1,1vx

w2wx

2

0wx22+C(R)w22.

(2.38)

The rest of the integrals in (2.37) can be estimated in a similar way. Hence, for sufficiently small0, we get the inequality

1 2

d

dtw(t)2W+c

2wx22Cw(t)2W. (2.39) Application of the standard Gronwall’s lemma implies uniqueness.

3. Existence of a global attractor inH

In this section, we discuss the asymptotic behavior of solutions of the nonlinear parabolic problem (1.1). To this end, in addition to the principal hypothesis, Hypothesis 1.1, we assume that the nonlinear functionsb,σsatisfy the following hypothesis.

Hypothesis 3.1. b(s)0 and there existcm>0, such that|σ(m)(s)| ≤cm|s|, for allm=0,1,2.

First, we prove that under the extra hypothesis,Hypothesis 3.1, the unique local solutionu(x, t) of problem (1.1), obtained inTheorem 2.6, exists globally in time. We denote byλthe positive constant induced by Poincar´e’s inequality.

Lemma3.2. Let Hypotheses1.1and3.1be fulfilled andu0, f H. Assume also that

λ <cλ 2c0

. (3.1)

Then there exists a constantρ2independent oft, such that,

lim sup

t→∞

ux(t)2ρ2. (3.2)

Proof. We multiply (1.1a) byuxxand integrate overΩto get 1

2 d dtux2

2+

a(u)u2xxdx+

b(u)u2xuxxdx +λ

σ(u)uxxdx=

f uxxdx.

(3.3)

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UsingHypothesis 1.1, we observe that

a(u)u2xxdxcuxx2

2, (3.4)

whereas fromHypothesis 3.1we have

b(u)u2xuxxdx= −1 3

b(u)u4xdx0. (3.5) Furthermore,Hypothesis 3.1, together with Poincar´e’s inequality

u2λ1/2ux2, (3.6) implies that

λ

σ(u)uxxdxλc0u2uxx

2λλ1c0uxx2

2. (3.7)

Relations (3.3), (3.4), and (3.7) imply that d

dtux(t)22+αuxx(t)22 1

cf22, (3.8) whereα=c2c0λλ1. Applying again Poincar´e’s inequality (3.6) to the above estimate (3.8), we get

d

dtux(t)22+αλux(t)22 1

cf22. (3.9) If assumption (3.1) is satisfied, that is,α >0 Gronwall’s lemma leads to the following estimate:

ux(t)22ux(0)22expαλt+ 1 αcλf22

1expαλt. (3.10)

Lettingt→ ∞, from estimate (3.10) we obtain that lim sup

t→∞

ux(t)22ρ22, (3.11)

whereρ22=(1/αcλ)f22and the proof is completed.

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LetᏮbe a bounded set ofH, included in a ballBH(0, M) ofH, centered at 0 of radiusM. Assuming thatu0Ꮾ, we infer fromLemma 3.2that forρ2> ρ2, there existst0(Ꮾ, ρ2)>0 such that fortt0(Ꮾ, ρ2)

ux(t)2ρ2, u(t)2ρ1=λ1/2ρ2. (3.12) Integrating (3.8) with respect tot, it follows that for everyr >0

α t+r

t

uxx(s)22ds r

cf22+ux(t)22. (3.13) Once again, lettingt→ ∞, we obtain from inequality (3.12) that

lim sup

t→∞

t+r

t

uxx(s)22ds r

αcf22+ρ22

α, for everyr >0. (3.14) and fortt0(Ꮾ, ρ2)

t+r

t

uxx(s)22ds r

αcf22+ρ22

α , for everyr >0. (3.15) Lemma3.3. Let Hypotheses1.1and3.1be fulfilled,u0, and f H. Assume also that (3.1) is satisfied. Then there exists a constantρ3 independent oft, and t1>0such that

uxx(t)2ρ3, fortt1. (3.16) Proof. Multiply (1.1a) byuxxxxand integrate overΩto get

1 2

d

dtuxx22+

a(u)uxuxxuxxxdx+

a(u)u2xxxdx + 2

b(u)uxuxxuxxxdx+λ

σ(u)uxuxxxdx +

b(u)u3xuxxxdx

= −

fxuxxxdx.

(3.17)

Using inequalities (1.13), (3.12), andHypothesis 1.1, we obtain that inequal- ities (2.9) and (2.10) hold, for alltt0(Ꮾ, ρ2), withRreplaced byρ2. It follows that

a(u)uxuxxuxxxdxC1,1ux

uxx

2uxxx

2

C1,1constuxx2

2uxxx

2

C1uxx4

2+1uxxx2

2.

(3.18)

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ApplyingLemma 1.2, we obtain the inequality

ux6constu1/32 uxx2/32 , (3.19) which can be used to get the estimate

b(u)u3xuxxxdxC2,1ux3

6uxxx

2

C2,1constu2uxx2

2uxxx

2

C2uxx4+1uxxx2

2.

(3.20)

We also have that the estimate λ

σ(u)uxuxxxdxλc1uux

2uxxx

2

λc1constuxx2

2uxxx

2

C3uxx4

2+1uxxx2

2.

(3.21)

The rest of the integral terms in (3.17) can be bounded similarly. Thus, for sufficiently small1, we get the inequalities

d

dtuxx(t)22+cuxxx(t)22M1+M2uxx(t)42, (3.22) d

dtuxx(t)22M1+M2uxx(t)42, (3.23) whereM1andM2are independent oft. We sety(t)= uxx(t)22,h(t)=M1, and g(t)=M2uxx(t)22. For fixedr >0, we use (3.15) to deduce that

t+r

t g(s)dsα1,

t+r

t h(s)dsα2,

t+r

t y(s)dsα3, (3.24) for alltt0(Ꮾ, ρ2), whereα1=M2α3,α2=M1r, andα3=(r/αc)f22+ρ22/α.

Applying uniform Gronwall’s lemma (Lemma 1.3) to the differential inequality (3.23), we conclude that

uxx(t)22 α3

r +α2

expα1

:=ρ23, tt0

Ꮾ, ρ2

+r (3.25)

and the proof is complete.

Lemma3.4. Let Hypotheses1.1and3.1be fulfilled,u0, and f H. Assume also that (3.1) is satisfied. Then, there exists a constantρ4 independent of tand t2>0, such that

uxxx(t)2ρ4, fortt2. (3.26)

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Proof. We multiply (1.1a) byu(6)and integrate overΩto get the equation 1

2 d

dtuxxx22+

a(u)u2xxxxdx+

A1(u)u2xuxxuxxxxdx + 2

A2(u)uxuxxxuxxxxdx+

A3(u)u2xxuxxxxdx +λ

σ(u)u2x+σ(u)uxx

uxxxxdx+

b(u)u4xuxxxxdx

= −

fxxuxxxxdx,

(3.27)

whereA1(u)=a(u) + 5b(u),A2(u)=a(u) +b(u), andA3(u)=a(u) + 2b(u).

Similarly toLemma 3.3, we arrive at the inequality d

dtuxxx(t)22+cuxxxx(t)22M3+M4uxxx(t)42, (3.28) whereM31, ρ2, ρ3) andM41, ρ2, ρ3) are independent oft. Moreover, from in- equality (3.22) we obtain that for fixedr>0

t+r

t

uxxx(s)2dsM1r c +ρ23

c

M2ρ23r+ 1. (3.29)

Settingy(t)=uxxx(t)22,h(t)=M3, andg(t)=M4uxxx(t)22, inequality (3.29) implies the following estimates:

t+r

t g(s)dsβ1,

t+r

t h(s)dsβ2,

t+r

t y(s)dsβ3, (3.30) where

β1=M4β3, β2=M3r, β3=M1r c +ρ23

c

M2ρ32r+ 1. (3.31)

ApplyingLemma 1.3to the differential inequality (3.28), we conclude that uxxx(t)22

β3

r +β2

expβ1

:=ρ42, fortt1+r (3.32)

to complete the proof.

Next we discuss certain regularity questions of the solution and the solution operator for problem (1.1).

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