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Algebraic Topology: Problem Set 2 Due: Friday, December 18. In Lecture 9, we constructed, for every map f : (X, x) → (Y, y) of pointed k-spaces, the following sequence of maps of pointed k-spaces: (Ω(Y, y), ¯y) ∂ /

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Algebraic Topology: Problem Set 2 Due: Friday, December 18.

In Lecture 9, we constructed, for every map f : (X, x) → (Y, y) of pointed k-spaces, the following sequence of maps of pointed k-spaces:

(Ω(Y, y), y) ¯

/ / (F(f, y), (x, y)) ¯

i

/ / (X, x)

f

/ / (Y, y) We define a sequence of maps of pointed k-spaces

(Ω(C, c), c) ¯

g

/ / (A, a)

h

/ / (B, b)

k

/ / (C, c)

to be a (Hurewicz ) fiber sequence if there exists a map f : (X, x) → (Y, y) of pointed k-spaces and a homotopy commutative diagram of pointed k-spaces

(Ω(Y, y), y) ¯

/ /

Ω(ψ)

(F(f, y), (x, y)) ¯

i

/ /

η

(X, x)

f

/ /

ϕ

(Y, y)

ψ

(Ω(C, c), ¯ c)

g

/ / (A, a)

h

/ / (B, b)

k

/ / (C, c)

such that the vertical maps η, ϕ, and ψ are homotopy equivalences. Here Ω(ψ) denotes the map of loop spaces induced by the map ψ. Prove that, for every map f : (X, x) → (Y, y) of pointed k-spaces, the sequence of maps of pointed k-spaces

(Ω(X, x), x) ¯

Ω(f)

/ / (Ω(Y, y), y) ¯

/ / (F(f, y), (x, y)) ¯

i

/ / (X, x), where the map − Ω(f ) is defined by

−Ω(f )(ω)(t) = f (ω(− t)), is a fiber sequence.

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