• 検索結果がありません。

発表ファイル 数理物理・物性基礎論セミナー Watanabe 1 intro

N/A
N/A
Protected

Academic year: 2018

シェア "発表ファイル 数理物理・物性基礎論セミナー Watanabe 1 intro"

Copied!
7
0
0

読み込み中.... (全文を見る)

全文

(1)

nonrelativistic systems

Haruki Watanabe

Ph.D. candidate (Vishwanath Group)

University of California, Berkeley

Appointed as a Pappalardo fellow at MIT (2015–2018)

Yoichiro Nambu (born Jan. 1921) Jeffrey Goldstone (born Sept. 1933)

1. Introduction

Main issues to be clarified today

When several internal symmetries are spontaneously broken, - what’s the number and dispersion of Goldstone modes in general? - Is this fixed by symmetry alone?

- Simple and self-contained description?

Why are they important?

- Spontaneous symmetry breaking is ubiquitous phenomenon in nature.

- Universal outcomes irrespective of microscopic details (we’ll see examples in Sec. 2) - Gapless modes determines low-energy properties of the system:

Debye’s CHTL µ Td law, Bloch’s D MzHTL µ Td2 law,

Review:

T. Brauner, “Spontaneous Symmetry Breaking and Nambu–Goldstone Bosons in Quantum Many-Body Systems”, Symmetry 2010, 2, 609.

If time permits, I’ll also talk about

- impossiblity of “quantum time crystals”

- non-Fermi liquids due to interactions with NGBs.

Printed by Mathematica for Students

(2)

What is spontaneous symmetry breaking?

Ref: Koma-Tasaki, 1993, 1994, see also the recent lecture note.

G: Symmetry of “Hamiltonian H + commutation relations” or “Lagrangian L”® The laws of physics (EOMs, …) H: Symmetry of the state realized in nature.

When H Ì G (and H ¹ G), we say the original symmetry G is spontaneously broken into H.

G”H (element of G but not of H): broken symmetries.

The coset space GH represents the set of degenerate ground states.

UH1L8e< = S1, SOH3LSOH2L = S2 If G is a Lie group, G = ei ΕiQi discrete subgroups. - dim G = the number of generators of G,

- dimHGHL = dim G - dim H = the number of broken symmetries dimHML: the dimension of manifold M.

dimHGHL is fixed by the continuous part of G and H (discrete subgroups do not change it).

Ÿ Definition of SSB

Order parameter ΦHxL: transforms under U Î G: Φ 'HxL = U¾ Φ HxL U.

If XΦHxL\ changes value before and after the symmetry transformation, i.e., XΦ' HxL\ = XU¾ Φ HxL U\ ¹ XΦHxL\,

we say the symmetry is broken.

For Lie group UHΕL = eä Ε Q, we use the infinitesimal form, X∆ΦHxL\ ºXΦ' HxL\-XΦHxL\

Ε =X@ä Q, ΦHxLD\ ¹ 0. ¬ definition in field theory textbook. Q itself contains IR divergence but the volume integral in

X@ä Q, ΦHy, tLD\ = Ù ddx äYAj0Hx, tL, ΦHy, tLE]

is harmless thanks to the locality of the commutation relation.

Ÿ Subtlety

Can we understand the infinite system with SSB as the thermodynamic limit of a finite-size system?

In a finite-size system,

@H, UD = 0 Þ simultaneous diagonalization H n, u\ = En n, u\, U n, u\ = ãä u n, u\. Then,

Xn, u¤ Φ ' HxL  n, u\

=Xn, u¤ U¾ Φ HxL U  n, u\

=Xn, u¤ ã-ä uΦHxL ãä u n, u\

=Xn, u¤ Φ HxL  n, u\

No SSB in the ground state or in the ensemble!!

D = 0 Þ   q\   q\

  \

Þ H

Printed by Mathematica for Students

(3)

No SSB in the ground state or in the ensemble!!

For Lie group,

@H, QD = 0 Þ H  n, q\ = En n, q\, Q n, q\ = q  n, q\. Then,

Xn, u¤@Q, ΦHxLD  n, q\

=Xn, q¤ Q ΦHxL  n, q\ - Xn, q¤ ΦHxL Q  n, q\

= qXn, q¤ ΦHxL  n, q\ - q Xn, q¤ ΦHxL  n, q\

= 0.

- This argument cannot be applied to nonabelian symmetries Þ ferromagnet is an exception.

- In general, if the order parameter does not commute witht H, no SSB in the ground state or ensemble in a finite-size system. Naive thermodynamic limit does not work.

e.g., Marshall-Lieb-Mattis theorem for Heisenberg antiferromagnet (The GS is an S = 0 state).

Ÿ Example: transverse field Ising model H = -ÚiΣizΣi+1z- gÚiΣix.

 gs\ = ­\+ ¯\

2 + OHgL, UZ2 gs\ = + gs\  1 st\ = ­\- ¯\

2

+ OHgL, UZ2 1 st\ = - 1 st\ EGS- E1 stµ g-N.

 gs\,  1 st\ are unphysical in the sense that they - do not have the clustering property

Xgs¤ ΣizΣjz gs\ = 1 + OHhL for i ¹ j but Xgs¤ Σiz gs\ = 0. - are not ergodic (O(1) fluctuation of m = Úi=1NΣiz

N )

- are not robust against a local mesurement.

Ÿ Resolution: symmetry breaking field H ' = H - hÙ ddx jHxL

limh®+0limV®¥XΦ' HxL\ ¹ limh®+0limV®¥XΦHxL\ limh®+0limV®¥X@Q, ΦHxLD\

Note: limh®0limV®¥¹ limV®¥limh®0

The external field picks up a symmetry breaking state. e.g. H = -ÚiΣizΣi+1z- gÚiΣix- hÚiΣiz

 gs\ H0L > ­\+ ¯\

2

 gs\ HhL >  ­\

D EHhL > h N + OIg-NM ® Even if OH1L energy cost, symmetry breaking state wins.

Ÿ Long-range order

XΦHxL ΦHyL\ ® Σ2> 0 for a large enough  x - y¤ (much larger than any microscopic length scale). limV®¥

YF2] V2 = Σ

2 for F =

Ù ddx ΦHxL.

Note: we do not apply symmetry breaking field in the definition of Σ2. e.g.  gs\ > ­\+ ¯\

2 .

-  ­\ and  ¯\ have a completely different expectation value of order parameter Þ cancellation after sum. -  ­\ and  ¯\ have the same long-range order Þ no cancellation.

Ÿ Kaplan, Horsch & von der Linden (1989)

Printed by Mathematica for Students

(4)

LRO Þ SSB

at T = 0 (Kaplan, Horsch & von der Linden) at T > 0 (Griffiths, Koma-Tasaki)

XgsHhL¤ F  gsHhL\

V ³

X0¤ F`F` 0\ V2 + OJ

1 V2N.

Variational principle:

XgsHhL¤ HH - h FL  gsHhL\ £ XΨ¤ HH - h FL  Ψ\ for any state  Ψ\.

XgsHhL¤ F` gsHhL\

V ³

XΨ¤ F` Ψ\

V +

XgsHhL¤ H  gsHhL\-XΨ¤ H  Ψ\

h V ³

XΨ¤ F` Ψ\

V +

E0-XΨ¤ H  Ψ\ h V

Take  Ψ\ =

 gsH0L\+F

` gs\

³ F` gs\·

2 . then XΨ¤ F` Ψ\

V =

Xgs¤ F`F` gs\ V2 and

XΨ¤ H  Ψ\ = Xgs¤ H  gs\ +Xgs¤ F

` H F` gs\

2Xgs¤ F`F` gs\ = E0+ OI 1 VM

Ÿ Horsch & von der Linden (1988)

LRO at T = 0 Þ V2Σ2=Xgs¤ F F  gs\ for F = Ù ddx ΦHxL. XH\ =Xgs¤ F H F  0\

X0¤ F F  0\ = E0+ 1 2

Xgs¤@F,@ H, FD  gs\

Xgs¤ F F  gs\ = E0+ OI 1

VM where H  gs\ = E0 gs\. - F 0\ is a low-lying energy state.

- Ortogonal to the ground state: Xgs¤ F  gs\ = 0.

Ÿ Divergence of susceptibility Χ ³ IV

2Σ2M2

X0¤BF`,BH,F`FF  0\µ V 2.

* V2Σ2=Xgs¤ F`F`  gs\ = Ún¹0Xgs¤ F`  n\Xn¤F`  gs\ =Ù d Ω SHΩL, where SHΩL = Ún¡Xgs¤ F`  n\¥2HΩ - EnL.

* Perturbation theory:  gs\H1L= gs\ + h  n\ Xn¤ F  gs\

En HE0= 0L

HXgs¤ F  gs\LH1L

V =

1

V JXgs¤ + h Xgs¤ F  n\

n Xn¤N FJ gs\ + Ε  n\Xn¤ F  gs\

n N =

Xgs¤ F  gs\

V + h

2 V

Xgs¤ F  n\ Xn¤ F  gs\

n + OIh

2M

Χ =

HXgs¤ F  gs\LH1L

V -

Xgs¤ F  gs\ V

h =

2 V

Xgs¤ F  n\ Xn¤ F  gs\

En =

2

V Ù d ΩSHΩL

* 1

2X0¤AF

`,AH, F` EE 0\ = Ún¡X0¤ F`  n\¥2En=Ù d Ω Ω SHΩL Cauchy–Schwarz inequality Hx×yL2£Hx×xL Hy×yL IÙ d Ω SHΩLM2£IÙ d Ω HΩ SHΩLLMIÙ d Ω' HSHΩ'LΩ'LM

IV2Σ2M2£ 21X0¤AF`,AH, F` EE 0^ V2 Χ I took this argument from

L. Capriotti, Int. J. Mod. Phys. B (2001)

(5)

(Anderson) Tower of states

Review: C. Lhuillier, cond-mat/0502464

Some exact results in Koma-Tasaki, J. Stat. Phys. 76, 745 (1994)

Ÿ Crystals H = 1

2mÚix

 

i2-Úi< jVIxi- xjM

= P2

2 m N+Úk¹0B pk¾×pk

2 m n0 + EHkiukLF

.

where P is the total momentum of the system. The ground state is a plane-wave state P = 0.

The observed crsytal (symmetry-breaking state) should be a superposition:

 crystal\ = ÚGCG P = G\ ® higher energy than the ground state at least in a finite volume system. D E = YP

2]

2 m N =ÚG CG¤ 2 G2

2 m N µ 1 Volume?

If YP2] = OHVL in the “physical” symmetry-breaking state, D E remains OH1L even after taking V ® ¥ limit (?).

Ÿ Antiferromangets L= Ρ

2 v2 n

  × n  - 1

2 Ρ Ñin × Ñin,

H = v2

2 Ρ S×S

V +Úk¹0J v2

2 Ρsk¾× sk+ 1 2 Ρ k

2n k¾× nkN where S =Ù d x Ρ

v2n

 ´ n. AsΑ, sΒE = i ΕΑΒΓsΓ

AsΑ, nΒE = i ΕΑΒΓnΓ AnΑ, nΒE = 0.

Neel order n and the uniform magnetization s do not commute ® if we fix s, n is uncertain.

From Lhuillier’s review

Ÿ BEC

H = i Ψ¾ Ψ  - 1

2 mÑ Ψ¾ × Ñ Ψ + Μ Ψ¾ Ψ - g

2HΨ¾ ΨL 2

HN-N0L2

2 N0 +Úk¹0J Μ k2

2 m gΘk¾Θk+ g 2J1 +

k2

4 m ΜN ∆ nk¾∆ nkN

.

Coherent state ® Y∆ N2] = N0 and XH\ = ̐2 = OH1L. ref: Shimizu-Miyadera PRD (2001)

Ÿ Ferromangets

L= mHcosΘ - 1L Φ  +2 vΡ2n

 × n , H =Úk1

2 Ρ k 2n

k¾× nk=Úk¹0 1 2 Ρ k

2n k¾× nk.

Printed by Mathematica for Students

(6)

Ú 2 ¾ Ú 2 ¾ No TOS! No sutlety.

Nambu-Goldstone theorem for Lorentz-invariant systems

九 後汰一郎 (Taichro Kugo)「 ゲージ場 の 量子 論II」

Ÿ Statement

Ÿ Proof

To derive the simple spectral rep, one has to use the Lorentz invaiance - Xn, k¤ jРn, k\ µ kΜ

- UL n, k\ µ  n, L k\ ¬ PΜ n, k\ = kΜ n, k\ - DFIx, Σ2M = Ù

d4k äH2 ΠL4

1 Σ2-k2-ä Εã

-ä k x

(7)

Ÿ Number of NGBs

Suppose jΜ1= fΠ1ΜΦ1, jΜ2= fΠ2ΜΦ2. Lorentz invariance ® fΠ1,2 are real. If Φ1= Φ2= Φ, then

fΠ2jΜ1- fΠ1jΜ2= fΠ2IfΠ1ΜΦM - fΠ1IfΠ2ΜΦM = 0 Þ fΠ2Q1- fΠ1Q2 is unbroken (contradiction).

Nambu-Goldstone theorem for Lorentz-invariant systems

Review: T. Brauner, “Spontaneous Symmetry Breaking and Nambu–Goldstone Bosons in Quantum Many-Body Systems”, Symmetry 2010, 2, 609

X0¤@QVHtL, ΦH0LD  0\

=ÙVddxX0¤@jHx, tL, ΦH0LD  0\

=Ù

Vd dx

nX0¤ jH0L  n\ Xn¤ ΦH0L  0\ ãä kn×x-ä Ent-ÚnX0¤ ΦH0L  n\ Xn¤ jH0L  0\ ã-ä kn×x+ä EntE

=ÚnH2 ΠLdkn,0AX0¤ jH0L  n\ Xn¤ ΦH0L  0\ ã-ä Ent-X0¤ ΦH0L  n\ Xn¤ jH0L  0\ ã+ä EntE Note that the ground state  n\ =  0\ does not contribute to the sum:

X0¤ jH0L  0\ X0¤ ΦH0L  0\ - X0¤ ΦH0L  0\ X0¤ jH0L  0\ = 0.

We also note that X0¤@QVHtL, ΦH0LD  0\ is (i) time independent and (ii) nonzero.

Hence, some excitation  NG\ with ENGHk = 0L = 0 should couple to the current X0¤ jH0L  NG\ ¹ 0 and the order parame- ter XNG¤ ΦH0L  0\ ¹ 0.

- Not necessarily modes? - How many NGBs? - What’s the disperison?

Printed by Mathematica for Students

参照

関連したドキュメント

Easy to see that in this case the direction of B should be purely rational such that the orthogonal plane (B) contains two different reciprocal lattice vectors. It is evident also

Key words: branching laws; intertwining operators; symmetry breaking operators; symmet- ric pairs; holomorphic discrete series representations; highest weight modules.. 2010

With this technique, each state of the grid is assigned as an assumption (decision before search). The advan- tages of this approach are that 1) the SAT solver has to be

However, Verrier and Evans [28] showed it was 4th order superintegrable, and Tanoudis and Daskaloyannis [21] showed in the quantum case that, if a second 4th order symmetry is added

 当図書室は、専門図書館として数学、応用数学、計算機科学、理論物理学の分野の文

[r]

職場環境の維持。特に有機溶剤規則の順守がポイント第2⇒第3

原子炉建屋から採取された試料は、解体廃棄物の汚染状態の把握、発生量(体 積、質量)や放射能量の推定、インベントリの評価を行う上で重要である。 今回、 1