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Relic Abundance and The Spin Independent Cross Section

3.7 Relic Abundance and The Spin Independent

Here, we approximate that the incoming momenta are zero, and using the conservation of energy, then we can simply perform the integral pφ to ob-tain:

hσvi =nEQσL 2Z 1 (2π)3

d3pσL

2EσL

1 (2π)3

d3pσL

2EσL

1 (2π)3

d3pφ+ (2Eφ+)2

1 (2π)3 (2π)41

2δ(EσLEφ+)Gφσ2 exp(−EσL/T)exp(−EσL/T). Then usingd3pφ+ =4πp2

φ+dpφ+ =4πpφ+Eφ+dEφ+ =4πq E2

φ+m2DMEφ+dEφ+, we arrive at

hσvi = nEQσL 2Z 1 (2π)3

d3pσL

2EσL

1 (2π)3

d3pσL

2EσL

1 (2π)6

4πq E2

φ+m2DMEφ+dEφ+ (2Eφ+)2

(2π)41

2δ(EσLEφ+)Gφσ2 exp(−EσL/T)exp(−EσL/T)

= nEQσL

2Z 1 (2π)3

d3pσL

2EσL

1 (2π)3

d3pσL

2EσL

1 (2π)62

4π q

E2σLm2DMEσL

(2EσL)2

(2π)41

2G2φσexp(−2EσL/T).

SubstitutingEσL =qp2σL +m2σL =q0+m2σL =mσL, we obtain the thermally averaged cross section forσLσLφ+φ:

hσ(σLσL;φ+φ)vi =nEQσL

2Z d3pσL

(2π)3 d3pσL

(2π)3 1 2EσL

exp(−2EσL/T) G

2 φσ

32πmσ2

L

× r

1−mDM mσL

= G

2 φσ

32πmσ2

L

r

1−mDM mσL

. (3.77)

First diagram in Fig.3.8 correspond to φ+φW+W. From this dia-gram, we obtain:

(−iGφh) i

p2hm2h(−igνh) d

4ph

(2π)4(2π)4eµWeµ,Wδ4(pφ+ +pφph)(2π)4δ4(phpW+pW)

−→ −iGφhheWµ eµ,W

(pφ+ +pφ)2m2h(2π)4δ4(pφ+ +pφpW+pW),

Mφ+φ→W± = h φ

φ+ W+

W (a)

Mφ+φ→Z0Z0 = h φ

φ+ Z0

Z0 (b)

Mφ+φtt = h φ

φ+ t

t (c)

Mφ+φhh = φ

φ+ h

h

+ h

φ

φ+ h

h

+ φ

φ+ h

h φ

(d)

FIGURE 3.8: Annihilation of Dark Matterφinto the Standard Model particles

so that the amplitude is given by

M= Gφhhe

µ Weµ,W

(pφ+ +pφ)2m2h or

M = 2GφhMWe

µ Weµ,W

(2mDM)2m2h , (3.78) where,g =2MW2h and pφ+ +pφ = 2mDM. Because we want to calculate thermal average cross section, we should have squared the amplitude above:

polarization

|M|2 = 4G

2 φhMW4 (2mDM)2m2h2

gµνp

µpν m2W

!

gµνpµpν m2W

!

= 4G

2 φhMW4 (2mDM)2m2h2

4− m

2 W

m2Wm

2 W

m2W + (p·p)2 m4W

!

= 4G

φh2 MW4 (2mDM)2m2h2

2+ 1 m4W

s 2

2

2s 2

m2W+m4W !

= 4G

φh2 MW4 (2mDM)2m2h2

2+ 1 m4W

4m4DM4m2DMm2W+m4W

!

= 4G

φh2 MW4 (2mDM)2m2h2

3−4m

2DM

mW2 +4m4DM m4W

!

, (3.79)

where √

s is the center of mass energy. Now, for the thermal average cross section, we have the formula

hσvi=nEQφ 2Z 1 (2π)3

d3pφ+ 2Eφ+

1 (2π)3

d3pφ

2Eφ

1 (2π)3

d3pW+ 2EW+

1 (2π)3

d3pW

2EW

(2π)4δ4(pφ++pφpW+pW)|M|2expEφ+/T exp

Eφ/T .

Substituting eq.(3.79) to the equation above, we obtain hσvi=nEQφ 2Z 1

(2π)3 d3pφ+

2Eφ+ 1 (2π)3

d3pφ

2Eφ

1 (2π)3

d3pW+ 2EW+

1 (2π)3

d3pW

2EW

(2π)4δ(Eφ+ +EφEW+EW)δ3(−pφ+pφ +pW+ +pW) 4Gφh2 M4W

(2mDM)2m2h2

3−4m

2 DM

m2W +4m4DM m4W

! exp

Eφ+/T

exp

Eφ/T .

Then settingEφ+ = Eφ, EW+ = EW, and assuming that the incoming mo-menta are equal to zero, we find

hσvi=nEQφ 2Z d3pφ+ (2π)3

d3pφ

(2π)3exp

Eφ+/T exp

Eφ/T 1

4E2φ+

1 (2π)62

d3pW+ 2EW+

d3pW

2EW+

4G2φhMW4 (2mDM)2m2h2

3−4m

2DM

m2W +4m4DM m4W

!

(2π)41

2δ(Eφ+EW+)δ3(pW+ +pW)

=nEQφ 2Z d3pφ+ (2π)3

d3pφ

(2π)3exp

Eφ+/T exp

Eφ/T d3pW+

32E2φ+E2W+

1 (2π)2

4G2φhMW4 (2mDM)2m2h2

3−4m

2DM

m2W +4m4DM m4W

!

δ(Eφ+EW+).

Noting thatd3pW+ =4πp2W+dpW+ =4πpW+EW+dEW+andpW+ =qE2W+ +m2W+ = EW+

r

1+ mE2W+

W+, we arrive at

hσ(φ+φ;W+W)vi =nEQφ 2Z d3pφ+ (2π)3

d3pφ

(2π)3 exp

Eφ+/T exp

Eφ/T

r

1+ mE2W+

W+

E2W+dEW+ 32E2

φ+

EW2 +

1

(2π)

4Gφh2 MW4 (2mDM)2m2h2 3−4m

2 DM

m2W +4m4DM m4W

!

δ(Eφ+EW+)

=

nEQφ 2

((((((((((((((((((((((( Z d3pφ+

(2π)3 d3pφ

(2π)3 exp

Eφ+ T

exp

Eφ T

1 32πE2

φ+

4G2φhMW4 (2mDM)2m2h2

3−4m

2DM

m2W +4m4DM m4W

!

× s

1+ m

2 W+

Eφ+

= 1

32πm2DM

4Gφh2 MW4 (2mDM)2m2h2

3−4m

2 DM

mW2 +4m4DM m4W

!

× s

1+ m

2 W+

mDM, (3.80)

whereE2

φ+ = p2

φ+ +m2

φ+ =0+m2

φ+.

In the casehσviforφ+φ → ZZ, we have the same result except for a 1/2 (the statistical factor for the identical particles) andmW is replaced withmZ,

hσ(φ+φ;Z0Z0)vi= 1 32πm2DM

2G2φhM4Z

4m2DMm2h2 34m

2DM

m2Z +4m4DM m4Z

!

s

1+ m

2Z

mDM. (3.81)

For φ+φ → hh, we have to compute the last three diagrams in Fig.3.8.

In this case, the squared amplitude has a form

|M|2= 1

2Gφh 1+24 λH

4mDMm2h m2W

g2 +8Gφh 1

2mDM+m2h m2W

g2

!2

, (3.82)

and from this result we obtain hσ(φ+φ;hh)vi = Gφh

64πm2DM(1−m2h/m2DM)1/2

× 1+24 λH 4mDMm2h

m2W

g2 +8Gφh 1

2mDM+m2h m2W

g2

!2

. (3.83) Forφ+φ →tt, with the same pattern of calculation, we obtain

hσ(φ+φ;tt)vi= Gφh

64πm2DM(1−m2h/m2DM)1/2

× 24 λH

4mDMm2hm

2t(m2DMm2t)

!

(3.84)

MσLσL→W± = h σL

σL W+

W (a)

MσLσLZ0Z0 = h σL

σL Z0

Z0 (b)

MσLσLtt= h σL

σL t

t (c)

MσLσLhh= σL

σL h

h

+ h

σL

σL h

h

+ σL

σL h

σL h (d)

FIGURE3.9: The diagrams contributing the annihilation cross section ofσLinto the Standard Model particles

MσLW+W =

h

h σL

W+

W (a)

MσLZ0Z0 =

h

h σL

Z0

Z0 (b)

MσLtt=

h

h σL

t

t (c)

FIGURE3.10: The diagrams contributing the decay width ofσL

The thermally averaged annihilation cross section and decay width forσ can be calculated in a similar way. The corresponding diagram are shown in Fig.3.9. Summing up all the results we obtain:

hσ(σLσL;φ+φ)vi = G

2 φσ

32πm2σ(1−m2DM/m2σ)1/2, (3.85) hσ(φLφL; SM)vi = 1

32πm2DM

I=W,Z,t,h

(1−m2I/m2DM)1/2

×aI(Gφh,mDM), (3.86)

hσ(σLσL; SM)vi = 1

32πm2L

I=W,Z,t,h

(1−m2I/m2L)1/2

×aI(Gσh,mL), (3.87)

hγ(σL)i = 1

16πmL

I=W,Z,t

(1−4m2I/m2L)1/2

×aI(G¯σh,mL/2) + G¯σh 32πmL

(1−4m2h/m2L)1/2

×

1+24λHh(mL/2)mL/2 g2

, (3.88)

where

aW(Z)(G,m) =4(2)G22h(m)mW(Z) 3+4 m4

m4W(Z)4 m2 m2W(Z)

! , at(G,m) =24G22h(m)m2t(m2m2t),

ah(G,m) =1

2G2 1+24λHh(m)m

2 W

g2 +8G∆th(m)m

2 W

g2

!2

. (3.89)

Hereg=0.65 is theSU(2)L gauge coupling constant, and

h(m) = (4m2m2h)1(∆h(m)t = (−2m2+m2h)1) (3.90) is the Higgs propagator in thes(t)−channel.

Yϕ

Yϕ

Yσ Yσ

0 10 20 30 40 50μm/T

10-23 10-19 10-15 10-11 Yi

FIGURE3.11:Yφ, ¯Yφ,YσL, and ¯YσLas a function ofx=µm/T

The plot of the coupled Boltzmann equation is displayed in Fig.3.11, where we use:

mDM =500 GeV, mσL =550 GeV, hσ(σLσL;φ+φ)vi =5.2×106GeV2 hσ(σLσL; SM)vi =1011GeV2, hσ(φ+φ; SM)vi =1011GeV2

hγ(σL)i =109GeV.

In this graph, we see thatYφ (orYσL) and ¯Yφ (or ¯YσL) have the same value at the beginning, but thenYφ (orYσL) separate from the equilibrium values asx increases. The Dark Matter particle number over entropy becomes constant (Freeze out), while σL decreases with the speed slower than the equilib-rium value.

Relic abundances forσLandφ±can be obtained fromYσL;∞YσL(x=∞) and Yφ;∞Yφ(x = ∞) in the coupled Boltzmann equations (eq.(3.75) and

eq.(3.76)):

σLh2 = gσLmDMYσL,φ;∞S0

ρc/h2 , (3.91)

where gσL is the degree of freedom of σL,φ, s0 = 2890 cm3 is the en-tropy density at present, andρc/h2=1.05×105GeV/cm3is the critical en-ergy density over the dimensionless Hubble constant at present [18]. When hγ(σL)i is sufficiently large, YσL may be approximated by its equilibrium value ¯YσL, then the {} in the right-hand side of eq.(3.76) can be rewritten as

"

1

2hσ(φ+φ; SM)vi+1

4hσ(σLσL;φ+φ)vi m

3 σL

m3DM exp 2xm2DMm2L mDMmL

!#

× YφYφY¯φφ

. (3.92)

From this equation, ifmL mDM, then the second term is neglected or sup-pressed. SomL must be nearly equal tomDM to make it effectively increases the annihilation rate of the Dark matter. In the Dark matter case, relic abun-dance must be at certain value, which is ΩDM ' 0.12, thus if the second term in the above equation suppressed, we must setλHSi big, to fulfill this value. However, if the second term is efficient, we can loosen the value of λHSi which is useful when we consider the spin-independent elastic cross section.

In order to compare this model result with the WIMP DM direct-detection search experiment [20–22], evaluation of the spin-independent elastic cross section of the nucleonσSI is done in [19]. Here, the spin-independent elastic cross section of the nucleon calculation is given by [23]:

σSI = 1

4π rˆGφhm2N mDMm2h

!2

mDM

mN+mDM 2

, (3.93)

where mN ' 940 MeV is the nucleon mass and ˆr ∼ 0.3 originated from the nucleonic matrix element [24–26]. Here, the parameter space where vh = 246 GeV, mh = 125 GeV, and ΩDMh2 ' 0.12 are satisfied. From all of this data, eq.(3.91) can be written as a constraint with form:

mDMYφ;∞ =4.35986×1010GeV (3.94)

FIGURE3.12: The Spin-Independent cross section in the case of U(2)(red),U(1)×U0(1)×Z(2)(blue), andU(1)×U0(1)(pink)

[19]

and eq.(3.93), which is the main equation to produce Fig.(3.12), can be written as:

σSI(mDM) =7.6345×1011

Gφh 0.94+mDM

2

. (3.95)

There are several constraints to obtainλs values other than those mentioned above. First is from the assumption thatλs must be positive. The second is from eq.(3.19):

1

2 +lnhM2i0i Λ2H >0

hM2i0i>Λ2He12. (3.96) The third is the constraint data where it used the values of mh = 125 GeV and vh = 246 GeV, where these values are bounding of the value of λ1, λ2, λ12, λ012, λHS1, λHS2, λH, and ΛH. The fourth is the value of hfii and hMi0i are not allowed to be negative. In this calculation, the value ofλH is set around 0.145−0.153, λHSi is around 0.05−0.2, and λ12,λ012 are around 0.01−4. The result of this model in U(1)×U0(1) symmetry is given in Fig.3.12 with the pink points. We can see from eq.(3.95) thatσSI depend on theGφhwhich is proportional toλHSi, from this relation we have to setλHSi not too big to make σSI overcome the constraint from the direct detection experiment. However, we know that relic abundance of the Dark matter de-pend onhσ(φ+φ; SM)iwhich also proportional toλHSi. To fulfill the value that given in eq.(3.94),λHSimust be big. However, thanks to the second term in the eq.(3.92), as long as this second term is efficient, the mass ofσL is nearly proportional to Dark matter mass, we can loosen the value ofhσ(φ+φ; SM)i which mean loosen the value ofλHSi.

In this figure, the green and yellow bands denote the 1σ and 2σ bands of XENON1T [27], respectively. The black dashed, solid, and dotted line inside of the green bands stand for the current upper bound from the direct detection experiments of LUX [28], XENON1T [27], and PandaX-II [29]. Here, theU(2) flavor symmetry which shown by the red dot, is almost excluded because it does not have much points below the constraint that given by the experiments. Enlarging the model with the permutation symmetry,U(1)× U0(1)×Z2, which requires λ1 = λ2 and λHS1 = λHS2 inLeff from eq.(3.3) also shown. This model enlargement also has a good result likeU(1)×U0(1) symmetry because of it still far from the given constraint. Single-scalar model of dark matter is also included for comparison that shown in the brown point.

Chapter 4

Concluding Remarks

We have considered a scale-invariant extension of the Standard model with introducing the hidden sector described by anSU(2) gauge theory with the scalar fieldsSai (a =1· · ·Nc,i =1· · ·Nf) in the fundamental representation ofSU(Nc) and U(1)Nf. Here we restrict ourself to the minimal model, i.e., Nf =2 and set Nc =6. We assume that the origin of the electroweak scale is a scalar-bilinear condensationhSiSji which forms due to theSU(Nc) gauge interaction. From this scaleless Lagrangian, we have shown that mass can be generated from massless Lagrangian, where scale is generated by quantum effect within scaleless effective theory (eq.(3.3)) of the hidden sector. This scale characterizes the origin of the scales of both the hidden sector and the electroweak sector.

By using mean field approximation and auxiliary method, we investigate the vacuum structure of the effective LagrangianLeff. From this discussion, by setting some parameters we obtain the term of the Higgs mass squared m2h0with the value 135GeV. After considering one loop contribution from the standard model sector,δm2h, we obtain the Higgs mass 125.8 GeV in eq.(3.36).

As a byproduct of this model, three new particlesφ,σL, andσHintroduced with assumptionmσH > mσL > mφ where the lightest particle (the complex scalar particle) considered as a dark matter candidate. Mass of the Dark mat-ter particle has been calculated by calculating its inverse propagator and set it equal to zero, this inverse propagator also used to calculate the wave func-tion renormalizafunc-tion. Relic abundance and the interacfunc-tion of the dark matter particles with the Standard model particles were evaluated where the effec-tive interaction of dark matter and the other particles obtained by setting the external momenta equal to zero.

To evaluate relic abundance, we encounter the coupled Boltzmann equa-tion that describes the evoluequa-tion of the number density ofσL andφparticles over entropy density (eq.(3.76) and eq.(3.75)). By solving this coupled Boltz-mann equation, we obtain Fig.3.11 which tells us about the evolution of the number of particles over entropy density (Yi) over x = µm/T. From this graph, we see that in the smallx,YσL(Yφ) coincides with its equilibrium state Y¯σL( ¯Yφ), and after some value, they parted away with its equilibrium state.

Yφ becomes constant after some value of x, on the other hand YσL still goes down but with a slower speed compared with its equilibrium state. After some value, we can make an approach and assumeYσLY¯σL and from this we can obtain the approximation expression that given by eq.(3.92). In this equation, the second term will have an effective role if the mass ofσL is big-ger but nearly equal to dark matter massmDM, because its much larger than dark matter mass it will be suppressed and do not have a contribution. Higgs portal coupling, λHSi, which introduced in this model, not only useful as a bridge between the standard model sector and the hidden sector but also important in the dark matter case. This λHSi has a double role in the relic abundance calculation in eq.(3.91) which is loosened its value by the exis-tence of second term in eq.(3.92) as long as this term is effective, and in the calculation of the spin independent in eq.(3.93).

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