3.4 Higher Order Differentiability
3.4.2 Under Boundedness Assumption of Z
3.4. HIGHER ORDER DIFFERENTIABILITY 49 Remark 3.4.3. The key point of the proof of Theorem 3.4.1 is seen in the estimation of (3.17) and (3.19). The degree of the integrand in H p-norm is two and we have no tools to estimate integrals in which the degree of the integrands are greater than two; for example,E[(∫T
0 ∇kZs3ds)p],E[(∫T
0 ∇kZs4ds)p] and so on. Thus, if (3.19) contains derivatives of Z more than two, we fail to estimate E[(∫T
0 ∥∇As∥ds)p]. (A4)-3) assures that there appears at most two derivatives of Z in (3.19); r ≤2.
50 CHAPTER 3. MALLIAVIN DIRREFENTIABILITY OF SOLUTIONS We introduce some examples on Theorem 3.4.4.
Example 3.4.5. Let (Wt)0≤t≤T be a one-dimensional Brownian motion and a function g: [0, T]× R ∋ (t, x) 7→ g(t, x) ∈ R belong to C1,2([0, T]×R). Set Yt =g(t, Wt) and Zt= ∂g∂x(t, Wt). Then (Y, Z) is a solution to the BSDE;
Yt =g(T, WT)−
∫ T
t
(∂g
∂t +1 2
∂2g
∂x2 )
(s, Ws)ds−
∫ T
t
ZsdWs, and it holds
DuZt= ∂2g
∂x2(t, Wt)1[0,t](u).
We now can construct some examples satisfying the assumptions (A4) or (A5) by above formulae.
(1) Let g(t, x) = tsinx. Then, (Y, Z), defined as above, is a unique solution to the BSDE;
Yt=TsinWT +
∫ T t
(
−sinWt+ Yt 2
) ds−
∫ T t
ZsdWs, which satisfies (A5) and supu,t,ω|DuZt(ω)|<∞ as well as (A4).
(2) Let g(t, x) = xarctan(2x)− 14log(1 + 4x2). Then, (Y, Z), defined as above, is a unique solution to the BSDE;
Yt =WT arctan(2WT)− 1
4log(1 + 4WT2)−
∫ T
t
cos2Zsds−
∫ T
t
ZsdWs. (A4)-3) is not satisfied but (A5) and supu,t,ω|DuZt(ω)|<∞are satisfied since
DuZt = 4
1 + 4Wt21[0,t](u).
First, we introduce the following lemma given by extracting the argument of the result of Zhen et al. [26, Proposition 2].
Lemma 3.4.6. Let (Y, Z) be an L2 solution to the BSDE (3.1) and suppose y·f(t, y, z)≤y·at+bt|y|2+ct|y||z|, (t, y, z)∈[0, T]×Rd×Rn×d, where(at)0≤≤T is aRd-valued progressively measurable process satisfyingE[∫T
0 |as|2ds]<
∞, and (bt)0≤t≤T and (ct)0≤t≤T are real progressively measurable processes satis-fying supt,ω(|bt(ω)|+|ct(ω)|)<∞. Then, there exists a γ >0 such that
|Yt|2eγt+ 1 2E
[∫ T t
eγs|Zs|2ds Ft
]
≤E [
|ξ|2eγT +
∫ T t
eγs|as|2ds Ft
]
, 0≤t ≤T.
3.4. HIGHER ORDER DIFFERENTIABILITY 51 Proof. Applying the Itˆo formula to the function [0, T]×Rd∋(t, y)7→ |y|2eγt ∈R with y=Yt and (3.1) yields that for any γ >0,
|Yt|2eγt+
∫ T t
eγs(
γ|Ys|2+|Zs|2) ds
=|ξ|2eγT +
∫ T t
2eγsYs·f(s, Ys, Zs)ds−2
∫ T t
eγsYs·ZsdWs. By the identities 2ab≤a2+b2 and 2ab≤2a2+12b2, we get
2Ys·f(s, Ys, Zs)≤2Ys·as+ 2bs|Ys|2+ 2cs|Ys||Zs|
≤2|Ys||as|+ 2|bs||Ys|2+ 2|cs||Ys||Zs|
≤ |Ys|2+|as|2+ 2∥b∥∞|Ys|2 + 2∥c∥2∞|Ys|2+ 1 2|Zs|2, where ∥·∥∞ represents the supremum with respect to (s, ω) ∈ [0, T]×Ω. Then, we obtain
|Yt|2eγt+
∫ T t
eγs {
(γ−2∥b∥∞−2∥c∥2∞−1)|Ys|2+1 2|Zs|2
} ds
≤ |ξ|2eγT +
∫ T t
eγs|as|2ds−2
∫ T t
eγsYs·ZsdWs. By choosing γ ≥2∥b∥∞+ 2∥c∥2∞+ 1 and taking the conditional expectation, we get
|Yt|2eγt+ 1 2E
[∫ T t
eγs|Zs|2ds Ft
]
≤E [
|ξ|2eγT +
∫ T t
eγs|as|2ds Ft
] .
Proof of Theorem 3.4.4. For simplicity of notation, we give the proof in the case d = n = 1. In the proof, notation C represents a positive constant which may change from place to place.
Let (Y, Z)∈S∞(R)×H ∞(R) be a unique solution to the BSDE (3.1).
Step 1: We show that for any p≥2,
i) (Y, Z)∈La1,p(R)×La1,p(R) and (∇Y,∇Z)∈Sp(H)×Hp(H), ii) (D·Y, D·Z)∈Src2(R,P¯)×H2(R,P¯) and for almost all 0≤u, t ≤T,
|DuYt|+E [∫ T
t
|DuZs|2ds Ft
]
+∥∇Yt∥H +|Zt| ≤C, iii) (D·Y, D·Z)∈Srcp(R,P¯)×Hp(R,P¯).
52 CHAPTER 3. MALLIAVIN DIRREFENTIABILITY OF SOLUTIONS Letp≥2. (A5) implies (A3)′. Hence, by Corollary 3.1.3, i) holds.
We show ii). (∇Y,∇Z)∈Sp(H)×Hp(H) solves (3.2). (D·Y, D·Z) belongs to Src2(R,P¯)×H2(R,P¯) and solves
DuYt=Duξ−1(t,T](u)Zu +
∫ T t
{Duf(s, Ys, Zs) +∂yf(s, Ys, Zs)DuYs+∂zf(s, Ys, Zs)DuZs}ds
−
∫ T t
DuZsdWs, 0≤t ≤T, a.e.u∈[0, T]. (3.20) Takeu∈[0, T] satisfying (3.20). Then, (DuY, DuZ)∈Src2(R)×H2(R) solves DuYt=Duξ
+
∫ T
t
{Duf(s, Ys, Zs) +∂yf(s, Ys, Zs)DuYs+∂zf(s, Ys, Zs)DuZs}ds
−
∫ T
t
DuZsdWs, u≤t≤T.
Lemma 3.4.6 yields that there exists a γ >0 such that
|DuYt|2eγt+ 1 2E
[∫ T t
eγs|DuZs|2ds Ft
]
≤E [
|Duξ|2eγT +
∫ T
t
eγs|Duf(s, Ys, Zs)|ds Ft
]
, u≤t≤T.
By (A5)-1),6), we obtain
|DuYt|2+E [∫ T
t
|DuZs|2ds Ft
]
≤C, u≤t ≤T.
If 0 ≤t < u, then DuYt=DuZt= 0 and E
[∫ T t
|DuZs|2ds Ft
]
=E [∫ T
u
|DuZs|2ds Ft
]
=E [
E [∫ T
u
|DuZs|2ds Fu
]Ft
] . Thus, we get
|DuYt|2+E [∫ T
t
|DuZs|2ds Ft
]
≤C, 0≤t≤T. (3.21)
3.4. HIGHER ORDER DIFFERENTIABILITY 53 By taking integrals with respect to u, we obtain
∥∇Yt∥2H ≤C, 0≤t≤T.
Since DtYt = Zt for almost all t ∈ [0, T] and by (3.21), |Zt| ≤ C for almost all t ∈[0, T]. Thus, we get for almost all u, t∈[0, T],
|DuYt|+E [∫ T
t
|DuZs|2ds Ft
]
+∥∇Yt∥H +|Zt| ≤C.
We will show iii). By ii), (D·Y, D·Z) ∈ Src2(R,P¯)×H 2(R,P¯) is a unique solution to the BSDE (3.20). Namely, putting ¯Yt1(u) = DuYt − 1[0,t](u)Zu, ( ¯Y1(·), D·Z)∈S2(R,P¯)×H 2(R,P¯) is a unique solution to the BSDE;
Y¯t1(u) = Duξ−Zu+
∫ T
t
{Duf(s, Ys, Zs) +∂yf(s, Ys, Zs)1[0,s](u)Zu
+∂yf(s, Ys, Zs) ¯Ys1(u) +∂zf(s, Ys, Zs)DuZs}ds
−
∫ T t
DuZsdWs, 0≤t ≤T, a.e.u∈[0, T].
Let p≥2. By ii) and (A5)-3),6), we get E
[∫ T
0
(∫ T
0
|Duf(s, Ys, Zs) +∂yf(s, Ys, Zs)1[0,s](u)Zu|ds )p
du ]
<∞, E
[∫ T 0
sup
0≤t≤T
|1[0,t](u)Zu|pdu ]
<∞.
Thus, we obtain (D·Y, D·Z)∈Srcp(R,P¯)×Hp(R,P¯).
Step 2: We show the following Claims 1-4 for k ≥2 by induction:
Claim 1 Letp≥2. Then, (∇k−1Y,∇k−1Z)∈La1,p(H⊗(k−1))×La1,p(H⊗(k−1)) and (∇kY,∇kZ)∈Sp(H⊗k)×H p(H⊗k) is a unique solution to the BSDE;
∇kYt=∇kξ−
k−1
∑
i=0
∇i (∫ ·
·∧t
∇k−1−iZsds )
+
∫ T
t
{Aks +Bsk∇kYs+ Γks∇kZs} ds−
∫ T
t
∇kZsdWs, 0≤t≤T, where Btk =∂yf(t, Yt, Zt), Γkt =∂zf(t, Yt, Zt) and Ak is defined inductively as
A1t =∇f(t, Yt, Zt),
Akt =∇Akt−1+∇Btk−1∇k−1Yt+∇Γkt−1∇k−1Zt, k ≥2.
54 CHAPTER 3. MALLIAVIN DIRREFENTIABILITY OF SOLUTIONS Moreover, it holds that
Akt =∇kf(t, Yt, Zt)
+∑
1,k
(∇α1Yt⊗ · · · ⊗ ∇αm−1−rYt
⊗ ∇β1Zt⊗ · · · ⊗ ∇βrZt⊗ ∇γ∂ym−1−r∂zrf(t, Yt, Zt))Σ
+∑
2,k
∂ym−r∂zrf(t, Yt, Zt)
×(∇α1Yt⊗ · · · ⊗ ∇αm−rYt⊗ ∇β1Zt⊗ · · · ⊗ ∇βrZt)Σ, (3.22) where the notations of summation represent
∑
1,k
:=
∑k m=2
m∑−1 r=0
∑
α∈NmND−1−r
β∈NrND
γ∈N
|α|+|β|+γ=k
, ∑
2,k
:=
∑k m=2
∑m r=0
∑
α∈NmND−r
β∈NrND
|α|+|β|=k
,
NkND and the superscript Σ represent the same as in the proof of Theorem 3.4.1.
Claim 2 The following holds;
E [∫ T
0
(∫ T
0
∥K˜uAks∥H⊗(k−1)ds )2
du ]
<∞.
In addition, (D·∇k−1Y, D·∇k−1Z)∈Src2(H⊗(k−1),P¯)×H 2(H⊗(k−1),P¯) and Dt∇k−1Yt=∇k−1Zt for almost all t∈[0, T].
Claim 3 For almost all 0≤t ≤T, u∈[0, T]k and v ∈[0, T]k−1,
|DkuYt|+E [∫ T
t
|DkuZs|2ds Ft
]
+|Dkv−1Zt|+∇kYt
H⊗k +∇k−1Zt
H⊗(k−1) ≤C.
Claim 4 (D·∇k−1Y, D·∇k−1Z)∈Src∞(H⊗(k−1),P¯)×H∞(H⊗(k−1),P¯).
We show the case whenk = 2. Let p≥2. By Corollary 3.3.2, (∇2Y,∇2Z)∈ Sp(H⊗2)×H p(H⊗2) solves (3.11). Then, Claim 1 holds. As in the proof of Theorem 3.4.1, Claim 2 holds. We will show Claim 3 and 4.
We now prove Claim 3. For a.e.(u, v) ∈ [0, T]2, (D2u,vY, D2u,vZ) ∈ S2(R)× H 2(R) solves
D2u,vYt=D2u,vξ+
∫ T t
{K˜u,v2 A2s+∂yf(s, Ys, Zs)D2u,vYs+∂zf(s, Ys, Zs)Du,v2 Zs}ds
3.4. HIGHER ORDER DIFFERENTIABILITY 55
−
∫ T t
Du,v2 ZsdWs, u∨v ≤t≤T, where
K˜u,v2 A2s =Du,v2 f(s, Ys, Zs) +DuYsDv∂yf(s, Ys, Zs) +DuZsDv∂zf(s, Ys, Zs) +Du∂yf(s, Ys, Zs)DvYs+Du∂zf(s, Ys, Zs)DvZs
+∂y2f(s, Ys, Zs)DuYsDvYs+∂y∂zf(s, Ys, Zs)DuYsDvZs +∂z∂yf(s, Ys, Zs)DuZsDvYs+∂z2f(s, Ys, Zs)DuZsDvZs.
Fix a.e.(u, v)∈[0, T]2 as above. By Lemma 3.4.6, there exists aγ2 >0 such that
|D2u,vYt|2eγ2t+1 2E
[∫ T t
eγ2s|D2u,vZs|2ds Ft
]
≤E [
|Du,v2 ξ|2eγ2T +
∫ T t
eγ2s|K˜u,v2 A2s|2ds Ft
]
, u∨v ≤t≤T. (3.23) Since supu,t,ω|DuZt(ω)| <∞, by (A5)-3),5),6) and Step 1-ii), we see for almost all s∈[0, T],
|K˜u,v2 A2s|2 ≤C.
Hence, we get
E [∫ T
t
|K˜u,v2 A2s|2ds Ft
]
≤C.
By Step 1-ii), (A5)-1) and (3.23), we see
|Du,v2 Yt|+E [∫ T
t
|Du,v2 Zs|2ds Ft
]
≤C, u∨v ≤t ≤T.
Thus, in the same manner as Step 1-ii), we obtain for almost all u, v, t∈[0, T],
|Du,v2 Yt|+E [∫ T
t
|Du,v2 Zs|2ds Ft
]
≤C.
And then, for almost all v, t ∈[0, T], we get
|DvZt|=|DvDtYt| ≤C.
Integration of |Du,v2 Yt|2 and |DvZt|2 with respect tou and v yield also that ∇2Yt
H⊗2 +∥∇Zt∥H ≤C.
56 CHAPTER 3. MALLIAVIN DIRREFENTIABILITY OF SOLUTIONS Claim 3 is proved.
We now prove Claim 4. (D·∇Y, D·∇Z)∈Src2(H,P¯)×H 2(H,P¯) is a unique solution to the BSDE;
Du∇Yt=Du∇ξ−Du (∫ ·
·∧t
Zsds )
−1(t,T](u)∇Zu +
∫ T t
{K˜uA2s+∂yf(s, Ys, Zs)Du∇Ys+∂zf(s, Ys, Zs)Du∇Zs}ds
−
∫ T t
Du∇ZsdWs, 0≤t ≤T, du⊗dP-a.e.
Namely, putting ¯Yt2(u) =Du∇Yt−Du(∫·∧t
0 Zsds)−1[0,t](u)∇Zu, ( ¯Y2(·), Du∇Z)∈ S2(H,P¯)×H 2(H,P¯) is a unique solution to the BSDE;
Y¯t2(u) = Du∇ξ−Du (∫ ·
0
Zsds )
− ∇Zu +
∫ T
t
{
K˜uA2s+∂yf(s, YS, Zs) (
Du
(∫ ·∧s
0
Zrdr )
+1[0,s](u)∇Zu )
+∂yf(s, Ys, Zs) ¯Ys2(u) +∂zf(s, Ys, Zs)Du∇Zs }
ds
−
∫ T
t
Du∇ZsdWs, 0≤t≤T, du⊗dP-a.e.
Let p ≥ 2. Since ∥Du(∫·∧s
0 Zrdr)∥2H = ∫s
0 |DuZr|2dr and by Claim 3 and (A5)-3),5),6), we see
E [∫ T
0
(∫ T
0
K˜uA2s+∂yf(s, YS, Zs) (
Du
(∫ ·∧s
0
Zrdr )
+1[0,s](u)∇Zu) H
ds )p
du ]
≤C (
1 +E [∫ T
0
{ sup
0≤t≤T|DuYt|p+ (∫ T
0
|DuZs|2ds )p2}
du ])
<∞, E
[∫ T 0
sup
0≤t≤T
Du
(∫ ·∧t 0
Zsds )
+1[0,t](u)∇Zu p
H
du ]
<∞.
Thus, we obtain (D·∇Y, D·∇Z)∈Srcp(H,P¯)×H p(H,P¯). The proofs of Claims 1-4 for k = 2 completes.
Next, assumek >2 and Claims 1-4 for 2,3, . . . , k−1 hold.
We will show Claim 1. Letp≥2. By the inductive assumption, (∇k−1Y,∇k−1Z)∈ S2p(H⊗(k−1))×H 2p(H⊗(k−1)) is a unique solution to the BSDE;
∇k−1Yt =∇k−1ξ−
k−2
∑
i=0
∇i (∫ ·
·∧t
∇k−2−iZsds )
3.4. HIGHER ORDER DIFFERENTIABILITY 57 +
∫ T t
{Aks−1+Bsk−1∇k−1Ys+ Γks−1∇k−1Zs
}ds−
∫ T t
∇k−1ZsdWs, 0≤t≤T, (3.24)
whereBk−1t =∂yf(t, Yt, Zt), Γk−1t =∂zf(t, Yt, Zt), Akt−1 =∇kf(t, Yt, Zt)
+ ∑
1,k−1
(∇α1Yt⊗ · · · ⊗ ∇αm−1−rYt
⊗ ∇β1Zt⊗ · · · ⊗ ∇βrZt⊗ ∇γ∂ym−1−r∂zrf(t, Yt, Zt))Σ
+ ∑
2,k−1
∂ym−r∂zrf(t, Yt, Zt)
×(∇α1Yt⊗ · · · ⊗ ∇αm−rYt⊗ ∇β1Zt⊗ · · · ⊗ ∇βrZt)Σ. We show (∇k−1Y,∇k−1Z)∈La1,p(H⊗(k−1))×La1,p(H⊗(k−1)) by applying Theorem 3.2.5. By (3.24) and (A5)-5), we see (A2)-3) is satisfied . The correspondence to (3.6) is as follows;
ξ =∇k−1ξ, ζt=
k−2
∑
i=0
∇i
(∫ ·∧t 0
∇k−2−iZsds )
, which satisfy (A2)-1),4). We see that for any F, G∈H⊗(k−1),
∇Btk−1F =∇∂yf(t, Yt, Zt)⊗F +∂y2f(t, Yt, Zt)∇Yt⊗F +∂z∂yf(t, Yt, Zt)∇Zt⊗F, B˜kt−1 =∂yf(t, Yt, Zt),
∇Γkt−1G=∇∂zf(t, Yt, Zt)⊗G+∂y∂zf(t, Yt, Zt)∇Yt⊗G+∂z2f(t, Yt, Zt)∇Zt⊗G, Γ˜kt−1 =∂zf(t, Yt, Zt).
Hence, (A2)-6) is satisfied.
By messy but not difficult calculation, we obtain that∇Akt−1+∇Btk−1∇k−1Yt+
∇Γkt−1∇k−1Zt is equal to the right-hand side of (3.22). Then by (A5)-3),5),6), we get
E
[(∫ T
0
∇Aks−1
H⊗kds )p]
≤C
1 + ∑
m,r∈Z+
1≤m+r≤2
∑
α∈(Z+∩[1,k−1])m+r m+r≤|α|≤k
E
[(∫ T 0
∏m j=1
∥∇αjYs∥H⊗αj
∏r j′=1
∥∇αj′+mZs∥H⊗αj′+mds )p]
58 CHAPTER 3. MALLIAVIN DIRREFENTIABILITY OF SOLUTIONS
+ ∑
m,r∈Z+ 3≤m+r≤k
∑
α∈(Z+∩[1,k−2])m+r m+r≤|α|≤k
E
[(∫ T 0
∏m j=1
∥∇αjYs∥H⊗αj
∏r j′=1
∥∇αj′+mZs∥H⊗αj′+mds )p]
, (3.25)
where the products in (3.25) are defined to take 1 when m = 0 or r= 0. By the H¨older inequality, for each term of the first summation in (3.25), we see
E
[(∫ T 0
∏m j=1
∥∇αjYt∥H⊗αj
∏r j′=1
∥∇αj′+mZs∥H⊗αj′+mds )p]
≤ {
E [
sup
0≤t≤T
∏m j=1
∥∇αjYt∥2pH⊗αj
]}12
E
(∫ T 0
∏r j′=1
∥∇αj′+mZs∥H⊗αj′+mds )2p
1 2
≤(1 +Tp2)
∏m j=1
∥∇αjY∥pS2pj(H⊗αj)
∏r j′=1
∥∇αj′+mZ∥pH2qj′(H⊗αj′+m)
<∞,
where 1/p = ∑m
j=11/pj = ∑r
j′=11/qj′. By the inductive assumption Claim 3, all ∥∇αjYs∥H⊗αj and ∥∇αj′+mZs∥H⊗αj′+m in the second summation in (3.25) are bounded; because for each 1 ≤ i ≤ m +r, αi ≤ k−2. Therefore, the second summation in (3.25) is bounded. Thus, we get
E
[(∫ T 0
∇Aks−1
H⊗kds )p]
<∞. (A2)-5) is satisfied.
Now, we see that (A2)-2),3) are satisfied because the properties corresponding to them are shown in previous k on (A2)-7) and Claim 2.
From the above results, applying Theorem 3.2.5 yields that (∇k−1Y,∇k−1Z)∈ La1,p(H⊗(k−1))×La1,p(H⊗(k−1)) and that (∇kY,∇kZ)∈Sp(H⊗k)×H p(H⊗k) is a unique solution to the BSDE;
∇kYt=∇kξ−
k−1
∑
i=0
∇i (∫ ·
·∧t
∇k−1−iZsds )
+
∫ T t
{∇Ak−1s +∇Bk−1∇k−1Ys+∇Γk−1∇k−1Zs+ ˜Bsk−1∇kYs+ ˜Γk−1s ∇kZs }
ds
−
∫ T t
∇kZsdWs, 0≤t≤T.
3.4. HIGHER ORDER DIFFERENTIABILITY 59 DefineAkt =∇Akt−1+∇Btk−1∇k−1Yt+∇Γkt−1∇k−1Zt. As mentioned above,Akt is written as (3.22). Claim 1 is proved.
We show Claim 2. By (3.22) and (A5)-3),5),6), we get E
[∫ T 0
(∫ T
0
∥K˜uAks∥H⊗(k−1)ds )2
du ]
≤C {
1 +∑
1.1
E [∫ T
0
(I1m,r,α(u))2du ]
+∑
1.2
E [∫ T
0
(I1m,r,α(u))2du ]
+∑
2.1
E [∫ T
0
(I2m,r,α(u))2du ]
+∑
2.2
E [∫ T
0
(I2m,r,α(u))2du ]}
, (3.26)
where I1m,r,α(u) =
∫ T
0
Du∇α1−1Ys
H⊗(α1−1)
∏m j=2
∥∇αjYs∥H⊗αj
∏r j′=1
∥∇αj′+mZs∥H⊗αj′+mds,
∑
1.1
= ∑
m,r∈Z+
m≥1 1≤m+r≤2
∑
α∈(Z+∩[1,k−1])m+r m+r≤|α|≤k
, ∑
1.2
= ∑
m,r∈Z+
m≥1 3≤m+r≤k
∑
α∈(Z+∩[1,k−2])m+r m+r≤|α|≤k
,
I2m,r,α(u) =
∫ T
0
Du∇α1+m−1Zs
H⊗(α1+m−1)
∏m j=1
∥∇αjYs∥H⊗αj
∏r j′=2
∥∇αj′+mZs∥H⊗αj′+mds,
∑
2.1
= ∑
m,r∈Z+ r≥1 1≤m+r≤2
∑
α∈(Z+∩[1,k−1])m+r m+r≤|α|≤k
, ∑
2.2
= ∑
m,r∈Z+ r≥1 3≤m+r≤k
∑
α∈(Z+∩[1,k−2])m+r m+r≤|α|≤k
,
defining a product ∏b
j=axj = 1 if b < a.
If m, r ∈ Z+, m ≥1, 1 ≤ m+r ≤ 2 and α ∈(Z+∩[1, k−1])m+r, m+r ≤
|α| ≤k, then by the Schwarz inequality and the inductive assumption (1), E
[∫ T
0
(I1m,r,α(u))2du ]
≤E [∫ T
0
du
∫ T
0
Du∇α1−1Ys2
H⊗(α1−1)ds
×
∫ T 0
∏m j=2
∥∇αjYs∥2H⊗αj
∏r j′=1
∥∇αj′+mZs∥2H⊗αj′+mds ]
≤(T +T2)E [ m
∏
j=1
sup
0≤t≤T∥∇αjYs∥2H⊗αj
∫ T
0
∏r j′=1
∥∇αj′+mZs∥2H⊗αj′+mds ]
≤(T +T2) {
E [ m
∏
j=1
sup
0≤t≤T
∥∇αjYs∥4H⊗αj ]}12
60 CHAPTER 3. MALLIAVIN DIRREFENTIABILITY OF SOLUTIONS
×
E
(∫ T 0
∏r j′=1
∥∇αj′+mZs∥2H⊗αj′+mds )2
1 2
≤(T +T2)
∏m j=1
∥∇αjY∥2S2pj(H⊗αj)
∏r j′=1
∥∇αj′+mZ∥2H4(H⊗αj′+m)
<∞,
where, to see in the fourth inequality above, r ≤1 is used, and 1/2 =∑m
j=11/pj. Hence, we get
∑
1.1
E [∫ T
0
(I1m,r,α(u))2du ]
<∞.
Ifm, r ∈Z+,r≥1, 1≤m+r≤2 andα ∈(Z+∩[1, k−1])m+r,m+r≤ |α| ≤k, then by the inductive assumption Claim 1,
E [∫ T
0
(I2m,r,α(u))2du ]
≤ E [∫ T
0
du
∫ T 0
Du∇α1+m−1Zs2
H⊗(α1+m−1)ds
×
∫ T
0
∏m j=1
∥∇αjYs∥2H⊗αj
∏r j′=2
∥∇αj′+mZs∥2H⊗αj′+mds ]
≤ E [∫ T
0
∥∇α1+mZs∥2H⊗α1+mds
×
∫ T 0
∏m j=1
∥∇αjYs∥2H⊗αj
∏r j′=2
∥∇αj′+mZs∥2H⊗αj′+mds ]
≤ (1 +T) {
E
[(∫ T 0
∥∇α1+mZs∥2H⊗α1+mds
)2]}1
2
×
E
∏m
j=1
sup
0≤t≤T∥∇αjYs∥4H⊗αj (∫ T
0
∏r j′=2
∥∇αj′+mZs∥2H⊗αj′+mds )2
1 2
≤ (1 +T)
∏m j=1
∥∇αjY∥2S4(H⊗αj)
∏r j′=1
∥∇αj′+mZ∥H4(H⊗αj′+m)
<∞. Thus, we get
∑
2.1
E [∫ T
0
(I2m,r,α(u))2du ]
<∞.
3.4. HIGHER ORDER DIFFERENTIABILITY 61 If αi ≤k −2 for 1 ≤ i ≤m+r, then by the inductive assumption Claim 3,
∥∇αjYs∥H⊗αj and ∥∇αj′+mZs∥H⊗αj′+m are bounded. Then, we see
∑
1.2
E [∫ T
0
(I1m,r,α(u))2du ]
+∑
2.2
E [∫ T
0
(I2m,r,α(u))2du ]
<∞. Hence, we obtain
E [∫ T
0
(∫ T 0
∥K˜uAks∥ds )2
du ]
<∞,
which implies (A2)′-8). Thus, by Theorem 3.3.1, we get (D·∇k−1Y, D·∇k−1Z) ∈ Src2(H⊗(k−1),P¯)×H 2(H⊗(k−1),P¯) andDt∇k−1Yt=∑k−1
i=1 Dt∇i−1(∫·∧t
0 ∇k−1−iZsds)+
∇k−1Zt. Since for 1 ≤i≤k−1, Du∇i−1
(∫ ·∧t
0
∇k−1−iZsds) 2
H⊗(k−1)
=
0, t ≤u,
∫ t
u
Du∇k−2Zs2
H⊗(k−2)ds, u < t, we obtain Dt∇k−1Yt=∇k−1Zt for almost all t∈[0, T]. Claim 2 is proved.
We prove Claim 3. For a.e.u= (u1, . . . , uk)∈[0, T]k, (DkuY, DukZ)∈Src2(R)× H 2(R) solves
DkuYt=Dkuξ+
∫ T t
{K˜ukAks+∂yf(s, Ys, Zs)DukYs+∂zf(s, Ys, Zs)DukZs}ds
−
∫ T t
DukZsdWs, u¯≤t≤T, where ¯u= max{u1, . . . , uk}. By Lemma 3.4.6, there exists a γk >0 such that
|DkuYt|2eγkt+ 1 2E
[∫ T
t
eγks|DukZs|2ds Ft
]
≤E [
|Dkuξ|2eγkT +
∫ T t
eγks|K˜ukAks|2ds Ft
]
, u¯≤t≤T. (3.27) By (3.22), we see
|K˜ukAks|2 ≤C {
1 +∑
1,k
∑
σ∈Sk
J1,m,r,α,β,σ
u (s) +∑
2,k
∑
σ∈Sk
J2,m,r,α,β,σ
u (s)
}
, (3.28) where Sk represents the symmetric group of degree k and
J1,m,r,α,β,σ
u (s) =
m∏−1−r j=1
|Duασ,αj
j Ys|2
∏r j′=1
|Dβj′
uσ,βj′ Zs|2|Dγuσ,γ∂ym−1−r∂zrf(t, Yt, Zt)|2,
62 CHAPTER 3. MALLIAVIN DIRREFENTIABILITY OF SOLUTIONS J2,m,r,α,β,σ
u (s) =
m∏−r j=1
|Duασ,αj j
Ys|2
∏r j′=1
|Dβj′
uσ,βj′ Zs|2, α0 = 1, β0 = 1,
uσ,αj = (uσ(∑j
i=1αi−1), uσ(∑j
i=1αi−1+1), . . . , uσ(∑j
i=1αi−1+αj−1)), uσ,βj′ = (u
σ(|α|+∑j′
i=1βi−1), u
σ(|α|+∑j′
i=1βi−1+1), . . . , u
σ(|α|+∑j′
i=1βi−1+βj′−1)), uσ,γ = (uσ(|α|+|β|+1), uσ(|α|+|β|+2), . . . , uσ(|α|+|β|+γ)).
We divide the first summation of (3.28) into three ones;
∑
1,k
∑
σ∈Sk
Ju1(s) = ∑
1,k r=0
∑
σ∈Sk
J1,m,r,α,β,σ
u (s) +∑
1,k r=1
∑
σ∈Sk
J1,m,r,α,β,σ
u (s) +∑
1,k r≥2
∑
σ∈Sk
J1,m,r,α,β,σ
u (s).
Ifr = 0, derivatives ofZ do not appear inJ1,m,r,α,β,σ
u (s) and eachαj ≤k−1. By the inductive assumption and (A5)-6), we get
∑
1,k r=0
∑
σ∈Sk
E [∫ T
t
J1,m,r,α,β,σ
u (s)ds
Ft
]
≤C.
Ifr= 1, β ∈Nandβ1 ≤k−1. By the inductive assumption and (A5)-6), we get
∑
1,k r=1
∑
σ∈Sk
E [∫ T
t
J1,m,r,α,β,σ
u (s)ds
Ft
]
≤C∑
1,k r=0
∑
σ∈Sk
E [∫ T
t
|Dβ1
uσ,β1 Zs|2ds Ft
]
≤C.
If r≥2, each βj′ ≤k−2. By the inductive assumption and (A5)-6), we get
∑
1,k r≥2
∑
σ∈Sk
E [∫ T
t
J1,m,r,α,β,σ
u (s)ds
Ft
]
≤C.
In the same manner as above, we can obtain
∑
2,k
∑
σ∈Sk
E [∫ T
t
J2,m,r,α,β,σ
u (s)ds
Ft
]
≤C.
Thus by (3.28), we get E
[∫ T t
|K˜ukAks|2ds Ft
]
≤C.
3.4. HIGHER ORDER DIFFERENTIABILITY 63 Hence by (3.27) and (A5)-1), we obtain
|DukYt|2+E [∫ T
t
|DukZs|2ds Ft
]
≤C, u¯≤t ≤T.
In the same manner as Step 1-ii), we see
|DkuYt|2+E [∫ T
t
|DkuZs|2ds Ft
]
≤C, 0≤t≤T.
And then, for almost all (v, t)∈[0, T]k−1×[0, T], we get
|Dvk−1Zt|=|Dkv−1DtYt| ≤C.
Integration of |DukYt|2 and |Dkv−1Zt|2 with respect to u and v yield also that ∇kYt2
H⊗k+∇k−1Zt2
H⊗(k−1) ≤C.
Claim 3 is now proved.
We show Claim 4. (D·∇k−1Y, D·∇k−1Z)∈Src2(H⊗(k−1),P¯)×H 2(H⊗(k−1),P¯) is a unique solution to the BSDE;
Du∇k−1Yt=Du∇k−1ξ−ζT(u) +ζt(u) +
∫ T t
{K˜uAks+∂yf(s, Ys, Zs)Du∇k−1Ys+∂zf(s, Ys, Zs)Du∇k−1Zs}ds
−
∫ T t
Du∇k−1ZsdWs, 0≤t ≤T, du⊗dP-a.e., whereζt(u) = ∑k−1
i=1 Du∇i−1(∫·∧t
0 ∇k−1−iZsds)+1[0,t](u)∇k−1Zu. Namely, putting Y¯tk(u) =Du∇k−1Yt−ζt(u), ( ¯Y2(·), Du∇Z)∈S2(H⊗(k−1),P¯)×H 2(H⊗(k−1),P¯) is a unique solution to the BSDE;
Y¯tk(u) = Du∇k−1ξ−ζT(u) +
∫ T
t
{K˜uAks+∂yf(s, YS, Zs)ζs(u)
+∂yf(s, Ys, Zs) ¯Ysk(u) +∂zf(s, Ys, Zs)Du∇k−1Zs}ds
−
∫ T
t
Du∇k−1ZsdWs, 0≤t≤T, du⊗dP-a.e.
Let p≥2. By Claim 2, we get Du∇k−2Zs =DuDs∇k−2Ys and by Claim 3, E
[∫ T 0
sup
0≤t≤T∥ζt(u)∥pH⊗(k−1)du ]
64 CHAPTER 3. MALLIAVIN DIRREFENTIABILITY OF SOLUTIONS
≤CE [∫ T
0
{(∫ T 0
∥Du∇k−2Zs∥2H⊗(k−2)ds )p2
+∥∇k−1Zu∥pH⊗(k−1)
} du
]
<∞.
Thus in the same manner as (3.26) and (A5)-3)-6), we get E
[∫ T 0
(∫ T 0
∥K˜uAks+∂yf(s, YS, Zs)ζs(u)∥H⊗(k−1)ds )p
du ]
≤C (
1 +
k−2
∑
α=0
E [∫ T
0
{ sup
0≤t≤T∥Du∇αYt∥2pH⊗α + (∫ T
0
∥Du∇αZs∥2H⊗αds )p}
du ])
<∞. Hence, we obtain (D·∇k−1Y, D·∇k−1Z)∈Srcp(H⊗(k−1),P¯)×H p(H⊗(k−1),P¯).
Acknowledgements
I would like to express my sincere gratitude to my supervisor, Professor Setsuo Taniguchi, for his patience and persistent guidance on me throughout my Ph.D period of time. I am profoundly grateful to him for all of the help, encouragement, and suggestions. Furthermore, his rigorous and uncompromised attitudes toward mathematics told me a lot of importance in studying mathematical problems.
Without his valuable suggestions and contributions, it is not possible for me to achieve these results.
65
Bibliography
[1] O. Aboura and S. Bourguin, Density estimates for solutions to one dimen-sional backward SDE’s, Potential Anal., 2013, 38, 573-587.
[2] F. Antonelli and A. Kohatsu-Higa, Densities of One-Dimensional Backward SDEs, Potential Anal., 2005,22, 263-287.
[3] P. Briand and F. Confortola, Differentiability of Backward Stochastic Differ-ential Equations in Hilbert Spaces with Monotone Generetors, Appl. Math.
Optim., 2008,57, 149-176.
[4] P. Briand, B. Delyon, Y. Hu, E. Pardoux and L. Stoica, Lp solutions of backward stochastic differential equations, Stochastic Process. Appl., 2003, 108, 109-129.
[5] P. Briand and C. Labart, Simulation of BSDEs By Wiener Chaos Expansion, Ann. Appl. Probab., 2014, 24, No. 3, 1129-1171.
[6] S. Chen, Lp solutions of one-dimensional backward stochastic differential equations with continuous coefficients, Stoch. Anal. Appl., 2010, 28, 820-841.
[7] N. El Karoui, S. Peng, and M.C. Quenez, Backward stochastic differential equations in finance, Math. Finance, 1997,7, 1-71.
[8] S. J. Fan and L. Jiang, Lp (p > 1) solutions for one-dimensional BSDEs with linear-growth generators, J. Appl. Math. Comput., 2012, 38, Issue 1, 295-304.
[9] M. Fuhrman and G. Tessitore, Nonlinear Kolmogorov Equations in Infinite Dimensional Spaces: The Backward Stochastic Differential Equations Ap-proach and Applications to Optimal Control, Ann. Probab., 2002, 30, No. 3, 1397-1465.
[10] M. Fuhrman and G. Tessitore, Infinite Horizon Backward Stochastic Dif-ferential Equations and Elliptic Equations in Hilbert Spaces, Ann. Probab., 2004, 32, No. 1, 607-660.
67
68 BIBLIOGRAPHY [11] M. Fuhrman and G. Tessitore, Generalized Directional Gradients, Backward Stochastic Differential Equations and Mild Solutions of Semilinear Parabolic Equations, Appl. Math. Optim, 2005, 51, 279-332.
[12] G. Guatteri, On a Class of Forward-Backward Stochastic Differential Sys-tems in Infinite Dimensions, Journal of Applied Mathematics and Stochastic Analysis, 2007, Aarticle ID 42640.
[13] Y. Hu, D. Nualart and X. Zhong, Malliavin Calculus for Backward Stochastic Differential Equations and Application to Numerical Solutions, Ann. Appl.
Probab., 2011, 21, No. 6, 2379-2423.
[14] N. Ikeda, S. Watanabe, Stochastic Differential Equations and Diffusion Pro-cesses, 2nd ed., 1989, Kodansha.
[15] Y. Izumi, The Lp Cauchy sequence for one-dimensional BSDEs with linear growth generators, Stat. Probabil. Lett., 2013,83, 1588-1594.
[16] Y. Izumi, Higher order differentiability of solutions to backward stochastic differential equations, Stochastics, 2018, 90, No. 1, 102-150.
[17] J. P. Lepeltier and J. San Martin, Backward stochastic differential equations with continuous coefficient. Statist. Probab. Lett., 1997, 32, 425-430.
[18] Q. Lin, Malliavin Derivatives of Solutions for BSDE, Chinese J. Appl.
Probab. Statist., 2000,16, No. 3, 285-294.
[19] P. Malliavin, Stochastic Analysis, 1997, Springer-Verlag.
[20] T. Mastrolia, D. Possama¨ı and R´eveillac, Density Analysis of BSDEs. To appears in the Annals of Probability, arXiv:1402.4416, 2014.
[21] T. Mastrolia, D. Possama¨ı and R´eveillac, On the Malliavin differentiability of BSDEs, arXiv:1404.1026, 2015.
[22] D. Nualart,The Malliavin Calculus and Related Topics, 2nd ed., 2006, Prob-ability and Its Applications, Springer-Verlag.
[23] E. Pardoux and S. Peng, Adapted Solutions of a Backward Stochastic Dif-ferential Equation, Systems Control Lett., 1990, 14, 55-61.
[24] E. Pardoux and S. Peng, Backward Stochastic Differential Equations and Quasilinear Parabolic Partial Differential Equations, Lecture Notes in CIS, vol. 176. Springer-Verlag, 200-217.
[25] I. Shigekawa,Stochastic Analysis, 2004, Translations of Mathematical Mono-graphs, American Mathematical Society.