• 検索結果がありません。

Under Boundedness Assumption of Z

ドキュメント内 Backward Stochastic Differential Equations and Solutions (ページ 56-76)

3.4 Higher Order Differentiability

3.4.2 Under Boundedness Assumption of Z

3.4. HIGHER ORDER DIFFERENTIABILITY 49 Remark 3.4.3. The key point of the proof of Theorem 3.4.1 is seen in the estimation of (3.17) and (3.19). The degree of the integrand in H p-norm is two and we have no tools to estimate integrals in which the degree of the integrands are greater than two; for example,E[(T

0 kZs3ds)p],E[(T

0 kZs4ds)p] and so on. Thus, if (3.19) contains derivatives of Z more than two, we fail to estimate E[(T

0 ∥∇As∥ds)p]. (A4)-3) assures that there appears at most two derivatives of Z in (3.19); r 2.

50 CHAPTER 3. MALLIAVIN DIRREFENTIABILITY OF SOLUTIONS We introduce some examples on Theorem 3.4.4.

Example 3.4.5. Let (Wt)0tT be a one-dimensional Brownian motion and a function g: [0, T]× R (t, x) 7→ g(t, x) R belong to C1,2([0, T]×R). Set Yt =g(t, Wt) and Zt= ∂g∂x(t, Wt). Then (Y, Z) is a solution to the BSDE;

Yt =g(T, WT)

T

t

(∂g

∂t +1 2

2g

∂x2 )

(s, Ws)ds

T

t

ZsdWs, and it holds

DuZt= 2g

∂x2(t, Wt)1[0,t](u).

We now can construct some examples satisfying the assumptions (A4) or (A5) by above formulae.

(1) Let g(t, x) = tsinx. Then, (Y, Z), defined as above, is a unique solution to the BSDE;

Yt=TsinWT +

T t

(

sinWt+ Yt 2

) ds−

T t

ZsdWs, which satisfies (A5) and supu,t,ω|DuZt(ω)|<∞ as well as (A4).

(2) Let g(t, x) = xarctan(2x) 14log(1 + 4x2). Then, (Y, Z), defined as above, is a unique solution to the BSDE;

Yt =WT arctan(2WT) 1

4log(1 + 4WT2)

T

t

cos2Zsds−

T

t

ZsdWs. (A4)-3) is not satisfied but (A5) and supu,t,ω|DuZt(ω)|<∞are satisfied since

DuZt = 4

1 + 4Wt21[0,t](u).

First, we introduce the following lemma given by extracting the argument of the result of Zhen et al. [26, Proposition 2].

Lemma 3.4.6. Let (Y, Z) be an L2 solution to the BSDE (3.1) and suppose y·f(t, y, z)≤y·at+bt|y|2+ct|y||z|, (t, y, z)[0, T]×Rd×Rn×d, where(at)0≤≤T is aRd-valued progressively measurable process satisfyingE[T

0 |as|2ds]<

∞, and (bt)0tT and (ct)0tT are real progressively measurable processes satis-fying supt,ω(|bt(ω)|+|ct(ω)|)<∞. Then, there exists a γ >0 such that

|Yt|2eγt+ 1 2E

[∫ T t

eγs|Zs|2ds Ft

]

≤E [

|ξ|2eγT +

T t

eγs|as|2ds Ft

]

, 0≤t ≤T.

3.4. HIGHER ORDER DIFFERENTIABILITY 51 Proof. Applying the Itˆo formula to the function [0, T]×Rd(t, y)7→ |y|2eγt R with y=Yt and (3.1) yields that for any γ >0,

|Yt|2eγt+

T t

eγs(

γ|Ys|2+|Zs|2) ds

=|ξ|2eγT +

T t

2eγsYs·f(s, Ys, Zs)ds2

T t

eγsYs·ZsdWs. By the identities 2ab≤a2+b2 and 2ab2a2+12b2, we get

2Ys·f(s, Ys, Zs)2Ys·as+ 2bs|Ys|2+ 2cs|Ys||Zs|

2|Ys||as|+ 2|bs||Ys|2+ 2|cs||Ys||Zs|

≤ |Ys|2+|as|2+ 2∥b∥|Ys|2 + 2∥c∥2|Ys|2+ 1 2|Zs|2, where ∥·∥ represents the supremum with respect to (s, ω) [0, T]×Ω. Then, we obtain

|Yt|2eγt+

T t

eγs {

2∥b∥2∥c∥21)|Ys|2+1 2|Zs|2

} ds

≤ |ξ|2eγT +

T t

eγs|as|2ds−2

T t

eγsYs·ZsdWs. By choosing γ 2∥b∥+ 2∥c∥2+ 1 and taking the conditional expectation, we get

|Yt|2eγt+ 1 2E

[∫ T t

eγs|Zs|2ds Ft

]

≤E [

|ξ|2eγT +

T t

eγs|as|2ds Ft

] .

Proof of Theorem 3.4.4. For simplicity of notation, we give the proof in the case d = n = 1. In the proof, notation C represents a positive constant which may change from place to place.

Let (Y, Z)∈S(R)×H (R) be a unique solution to the BSDE (3.1).

Step 1: We show that for any p≥2,

i) (Y, Z)La1,p(R)×La1,p(R) and (∇Y,∇Z)∈Sp(H)×Hp(H), ii) (D·Y, D·Z)∈Src2(R,P¯)×H2(R,P¯) and for almost all 0≤u, t ≤T,

|DuYt|+E [∫ T

t

|DuZs|2ds Ft

]

+∥∇YtH +|Zt| ≤C, iii) (D·Y, D·Z)∈Srcp(R,P¯)×Hp(R,P¯).

52 CHAPTER 3. MALLIAVIN DIRREFENTIABILITY OF SOLUTIONS Letp≥2. (A5) implies (A3). Hence, by Corollary 3.1.3, i) holds.

We show ii). (∇Y,∇Z)∈Sp(H)×Hp(H) solves (3.2). (D·Y, D·Z) belongs to Src2(R,P¯)×H2(R,P¯) and solves

DuYt=Duξ−1(t,T](u)Zu +

T t

{Duf(s, Ys, Zs) +yf(s, Ys, Zs)DuYs+zf(s, Ys, Zs)DuZs}ds

T t

DuZsdWs, 0≤t ≤T, a.e.u[0, T]. (3.20) Takeu∈[0, T] satisfying (3.20). Then, (DuY, DuZ)∈Src2(R)×H2(R) solves DuYt=Duξ

+

T

t

{Duf(s, Ys, Zs) +yf(s, Ys, Zs)DuYs+zf(s, Ys, Zs)DuZs}ds

T

t

DuZsdWs, u≤t≤T.

Lemma 3.4.6 yields that there exists a γ >0 such that

|DuYt|2eγt+ 1 2E

[∫ T t

eγs|DuZs|2ds Ft

]

≤E [

|Duξ|2eγT +

T

t

eγs|Duf(s, Ys, Zs)|ds Ft

]

, u≤t≤T.

By (A5)-1),6), we obtain

|DuYt|2+E [∫ T

t

|DuZs|2ds Ft

]

≤C, u≤t ≤T.

If 0 ≤t < u, then DuYt=DuZt= 0 and E

[∫ T t

|DuZs|2ds Ft

]

=E [∫ T

u

|DuZs|2ds Ft

]

=E [

E [∫ T

u

|DuZs|2ds Fu

]Ft

] . Thus, we get

|DuYt|2+E [∫ T

t

|DuZs|2ds Ft

]

≤C, 0≤t≤T. (3.21)

3.4. HIGHER ORDER DIFFERENTIABILITY 53 By taking integrals with respect to u, we obtain

∥∇Yt2H ≤C, 0≤t≤T.

Since DtYt = Zt for almost all t [0, T] and by (3.21), |Zt| ≤ C for almost all t [0, T]. Thus, we get for almost all u, t∈[0, T],

|DuYt|+E [∫ T

t

|DuZs|2ds Ft

]

+∥∇YtH +|Zt| ≤C.

We will show iii). By ii), (D·Y, D·Z) Src2(R,P¯)×H 2(R,P¯) is a unique solution to the BSDE (3.20). Namely, putting ¯Yt1(u) = DuYt 1[0,t](u)Zu, ( ¯Y1(·), D·Z)∈S2(R,P¯)×H 2(R,P¯) is a unique solution to the BSDE;

Y¯t1(u) = Duξ−Zu+

T

t

{Duf(s, Ys, Zs) +yf(s, Ys, Zs)1[0,s](u)Zu

+yf(s, Ys, Zs) ¯Ys1(u) +zf(s, Ys, Zs)DuZs}ds

T t

DuZsdWs, 0≤t ≤T, a.e.u[0, T].

Let p≥2. By ii) and (A5)-3),6), we get E

[∫ T

0

(∫ T

0

|Duf(s, Ys, Zs) +yf(s, Ys, Zs)1[0,s](u)Zu|ds )p

du ]

<∞, E

[∫ T 0

sup

0tT

|1[0,t](u)Zu|pdu ]

<∞.

Thus, we obtain (D·Y, D·Z)∈Srcp(R,P¯)×Hp(R,P¯).

Step 2: We show the following Claims 1-4 for k 2 by induction:

Claim 1 Letp≥2. Then, (k1Y,∇k1Z)∈La1,p(H(k1))×La1,p(H(k1)) and (kY,∇kZ)∈Sp(Hk)×H p(Hk) is a unique solution to the BSDE;

kYt=kξ−

k1

i=0

i (∫ ·

·∧t

k1iZsds )

+

T

t

{Aks +BskkYs+ ΓkskZs} ds−

T

t

kZsdWs, 0≤t≤T, where Btk =yf(t, Yt, Zt), Γkt =zf(t, Yt, Zt) and Ak is defined inductively as

A1t =∇f(t, Yt, Zt),

Akt =∇Akt1+Btk1k1Yt+Γkt1k1Zt, k 2.

54 CHAPTER 3. MALLIAVIN DIRREFENTIABILITY OF SOLUTIONS Moreover, it holds that

Akt =kf(t, Yt, Zt)

+∑

1,k

(α1Yt⊗ · · · ⊗ ∇αm−1−rYt

⊗ ∇β1Zt⊗ · · · ⊗ ∇βrZt⊗ ∇γym1rzrf(t, Yt, Zt))Σ

+∑

2,k

ym−rzrf(t, Yt, Zt)

×(α1Yt⊗ · · · ⊗ ∇αmrYt⊗ ∇β1Zt⊗ · · · ⊗ ∇βrZt)Σ, (3.22) where the notations of summation represent

1,k

:=

k m=2

m1 r=0

α∈NmND1r

β∈NrND

γ∈N

|α|+|β|+γ=k

,

2,k

:=

k m=2

m r=0

α∈NmNDr

β∈NrND

|α|+|β|=k

,

NkND and the superscript Σ represent the same as in the proof of Theorem 3.4.1.

Claim 2 The following holds;

E [∫ T

0

(∫ T

0

∥K˜uAksH(k1)ds )2

du ]

<∞.

In addition, (D·k1Y, D·k1Z)∈Src2(H(k1),P¯)×H 2(H(k1),P¯) and Dtk1Yt=k1Zt for almost all t∈[0, T].

Claim 3 For almost all 0≤t ≤T, u∈[0, T]k and v [0, T]k1,

|DkuYt|+E [∫ T

t

|DkuZs|2ds Ft

]

+|Dkv1Zt|+kYt

Hk +k1Zt

H⊗(k−1) ≤C.

Claim 4 (D·k1Y, D·k1Z)∈Src(H(k1),P¯)×H(H(k1),P¯).

We show the case whenk = 2. Let p≥2. By Corollary 3.3.2, (2Y,∇2Z) Sp(H⊗2)×H p(H⊗2) solves (3.11). Then, Claim 1 holds. As in the proof of Theorem 3.4.1, Claim 2 holds. We will show Claim 3 and 4.

We now prove Claim 3. For a.e.(u, v) [0, T]2, (D2u,vY, D2u,vZ) S2(R)× H 2(R) solves

D2u,vYt=D2u,vξ+

T t

{K˜u,v2 A2s+yf(s, Ys, Zs)D2u,vYs+zf(s, Ys, Zs)Du,v2 Zs}ds

3.4. HIGHER ORDER DIFFERENTIABILITY 55

T t

Du,v2 ZsdWs, u∨v ≤t≤T, where

K˜u,v2 A2s =Du,v2 f(s, Ys, Zs) +DuYsDvyf(s, Ys, Zs) +DuZsDvzf(s, Ys, Zs) +Duyf(s, Ys, Zs)DvYs+Duzf(s, Ys, Zs)DvZs

+y2f(s, Ys, Zs)DuYsDvYs+yzf(s, Ys, Zs)DuYsDvZs +zyf(s, Ys, Zs)DuZsDvYs+z2f(s, Ys, Zs)DuZsDvZs.

Fix a.e.(u, v)[0, T]2 as above. By Lemma 3.4.6, there exists aγ2 >0 such that

|D2u,vYt|2eγ2t+1 2E

[∫ T t

eγ2s|D2u,vZs|2ds Ft

]

≤E [

|Du,v2 ξ|2eγ2T +

T t

eγ2s|K˜u,v2 A2s|2ds Ft

]

, u∨v ≤t≤T. (3.23) Since supu,t,ω|DuZt(ω)| <∞, by (A5)-3),5),6) and Step 1-ii), we see for almost all s∈[0, T],

|K˜u,v2 A2s|2 ≤C.

Hence, we get

E [∫ T

t

|K˜u,v2 A2s|2ds Ft

]

≤C.

By Step 1-ii), (A5)-1) and (3.23), we see

|Du,v2 Yt|+E [∫ T

t

|Du,v2 Zs|2ds Ft

]

≤C, u∨v ≤t ≤T.

Thus, in the same manner as Step 1-ii), we obtain for almost all u, v, t∈[0, T],

|Du,v2 Yt|+E [∫ T

t

|Du,v2 Zs|2ds Ft

]

≤C.

And then, for almost all v, t [0, T], we get

|DvZt|=|DvDtYt| ≤C.

Integration of |Du,v2 Yt|2 and |DvZt|2 with respect tou and v yield also that 2Yt

H2 +∥∇ZtH ≤C.

56 CHAPTER 3. MALLIAVIN DIRREFENTIABILITY OF SOLUTIONS Claim 3 is proved.

We now prove Claim 4. (D·∇Y, D·∇Z)∈Src2(H,P¯)×H 2(H,P¯) is a unique solution to the BSDE;

Du∇Yt=Du∇ξ−Du (∫ ·

·∧t

Zsds )

1(t,T](u)∇Zu +

T t

{K˜uA2s+yf(s, Ys, Zs)Du∇Ys+zf(s, Ys, Zs)Du∇Zs}ds

T t

Du∇ZsdWs, 0≤t ≤T, du⊗dP-a.e.

Namely, putting ¯Yt2(u) =Du∇Yt−Du(∫·∧t

0 Zsds)−1[0,t](u)∇Zu, ( ¯Y2(·), Du∇Z)∈ S2(H,P¯)×H 2(H,P¯) is a unique solution to the BSDE;

Y¯t2(u) = Du∇ξ−Du (∫ ·

0

Zsds )

− ∇Zu +

T

t

{

K˜uA2s+yf(s, YS, Zs) (

Du

(∫ ·∧s

0

Zrdr )

+1[0,s](u)∇Zu )

+∂yf(s, Ys, Zs) ¯Ys2(u) +zf(s, Ys, Zs)Du∇Zs }

ds

T

t

Du∇ZsdWs, 0≤t≤T, du⊗dP-a.e.

Let p 2. Since ∥Du(∫·∧s

0 Zrdr)∥2H = ∫s

0 |DuZr|2dr and by Claim 3 and (A5)-3),5),6), we see

E [∫ T

0

(∫ T

0

K˜uA2s+yf(s, YS, Zs) (

Du

(∫ ·∧s

0

Zrdr )

+1[0,s](u)∇Zu) H

ds )p

du ]

≤C (

1 +E [∫ T

0

{ sup

0tT|DuYt|p+ (∫ T

0

|DuZs|2ds )p2}

du ])

<∞, E

[∫ T 0

sup

0tT

Du

(∫ ·∧t 0

Zsds )

+1[0,t](u)∇Zu p

H

du ]

<∞.

Thus, we obtain (D·∇Y, D·∇Z)∈Srcp(H,P¯)×H p(H,P¯). The proofs of Claims 1-4 for k = 2 completes.

Next, assumek >2 and Claims 1-4 for 2,3, . . . , k1 hold.

We will show Claim 1. Letp≥2. By the inductive assumption, (k1Y,∇k1Z)∈ S2p(H(k1))×H 2p(H(k1)) is a unique solution to the BSDE;

k1Yt =k1ξ−

k2

i=0

i (∫ ·

·∧t

k2iZsds )

3.4. HIGHER ORDER DIFFERENTIABILITY 57 +

T t

{Aks1+Bsk1k1Ys+ Γks1k1Zs

}ds−

T t

k1ZsdWs, 0≤t≤T, (3.24)

whereBk−1t =yf(t, Yt, Zt), Γk−1t =zf(t, Yt, Zt), Akt1 =kf(t, Yt, Zt)

+ ∑

1,k−1

(α1Yt⊗ · · · ⊗ ∇αm−1−rYt

⊗ ∇β1Zt⊗ · · · ⊗ ∇βrZt⊗ ∇γym1rzrf(t, Yt, Zt))Σ

+ ∑

2,k1

ymrzrf(t, Yt, Zt)

×(α1Yt⊗ · · · ⊗ ∇αmrYt⊗ ∇β1Zt⊗ · · · ⊗ ∇βrZt)Σ. We show (k1Y,∇k1Z)∈La1,p(H(k1))×La1,p(H(k1)) by applying Theorem 3.2.5. By (3.24) and (A5)-5), we see (A2)-3) is satisfied . The correspondence to (3.6) is as follows;

ξ =k1ξ, ζt=

k2

i=0

i

(∫ ·∧t 0

k2iZsds )

, which satisfy (A2)-1),4). We see that for any F, G∈H(k1),

Btk1F =∇∂yf(t, Yt, Zt)⊗F +y2f(t, Yt, Zt)∇Yt⊗F +zyf(t, Yt, Zt)∇Zt⊗F, B˜kt1 =yf(t, Yt, Zt),

Γkt1G=∇∂zf(t, Yt, Zt)⊗G+yzf(t, Yt, Zt)∇Yt⊗G+z2f(t, Yt, Zt)∇Zt⊗G, Γ˜kt1 =zf(t, Yt, Zt).

Hence, (A2)-6) is satisfied.

By messy but not difficult calculation, we obtain that∇Akt1+Btk1k1Yt+

Γkt1k1Zt is equal to the right-hand side of (3.22). Then by (A5)-3),5),6), we get

E

[(∫ T

0

∇Aks1

Hkds )p]

≤C







1 + ∑

m,r∈Z+

1≤m+r≤2

α(Z+[1,k1])m+r m+r≤|α|≤k

E

[(∫ T 0

m j=1

∥∇αjYsHαj

r j=1

∥∇αj′+mZsH⊗αj′+mds )p]

58 CHAPTER 3. MALLIAVIN DIRREFENTIABILITY OF SOLUTIONS

+ ∑

m,r∈Z+ 3m+rk

α(Z+[1,k2])m+r m+r≤|α|≤k

E

[(∫ T 0

m j=1

∥∇αjYsH⊗αj

r j=1

∥∇αj′+mZsHαj′+mds )p]





, (3.25)

where the products in (3.25) are defined to take 1 when m = 0 or r= 0. By the H¨older inequality, for each term of the first summation in (3.25), we see

E

[(∫ T 0

m j=1

∥∇αjYtH⊗αj

r j=1

∥∇αj′+mZsHαj′+mds )p]

{

E [

sup

0tT

m j=1

∥∇αjYt2pHαj

]}12

E

(∫ T 0

r j=1

∥∇αj′+mZsHαj′+mds )2p



1 2

(1 +Tp2)

m j=1

∥∇αjY∥pS2pj(H⊗αj)

r j=1

∥∇αj′+mZ∥pH2qj′(Hαj′+m)

<∞,

where 1/p = ∑m

j=11/pj = ∑r

j=11/qj. By the inductive assumption Claim 3, all ∥∇αjYsHαj and ∥∇αj′+mZsH⊗αj′+m in the second summation in (3.25) are bounded; because for each 1 i m +r, αi k−2. Therefore, the second summation in (3.25) is bounded. Thus, we get

E

[(∫ T 0

∇Aks1

H⊗kds )p]

<∞. (A2)-5) is satisfied.

Now, we see that (A2)-2),3) are satisfied because the properties corresponding to them are shown in previous k on (A2)-7) and Claim 2.

From the above results, applying Theorem 3.2.5 yields that (k1Y,∇k1Z)∈ La1,p(H(k1))×La1,p(H(k1)) and that (kY,∇kZ)∈Sp(Hk)×H p(Hk) is a unique solution to the BSDE;

kYt=kξ−

k1

i=0

i (∫ ·

·∧t

k1iZsds )

+

T t

{∇Ak−1s +Bk−1k−1Ys+Γk−1k−1Zs+ ˜Bsk−1kYs+ ˜Γk−1s kZs }

ds

T t

kZsdWs, 0≤t≤T.

3.4. HIGHER ORDER DIFFERENTIABILITY 59 DefineAkt =∇Akt1+Btk1k1Yt+Γkt1k1Zt. As mentioned above,Akt is written as (3.22). Claim 1 is proved.

We show Claim 2. By (3.22) and (A5)-3),5),6), we get E

[∫ T 0

(∫ T

0

∥K˜uAksH(k1)ds )2

du ]

≤C {

1 +∑

1.1

E [∫ T

0

(I1m,r,α(u))2du ]

+∑

1.2

E [∫ T

0

(I1m,r,α(u))2du ]

+∑

2.1

E [∫ T

0

(I2m,r,α(u))2du ]

+∑

2.2

E [∫ T

0

(I2m,r,α(u))2du ]}

, (3.26)

where I1m,r,α(u) =

T

0

Duα11Ys

H⊗(α1−1)

m j=2

∥∇αjYsH⊗αj

r j=1

∥∇αj′+mZsHαj′+mds,

1.1

= ∑

m,r∈Z+

m1 1m+r2

α∈(Z+∩[1,k−1])m+r m+r≤|α|≤k

,

1.2

= ∑

m,r∈Z+

m1 3m+rk

α∈(Z+∩[1,k−2])m+r m+r≤|α|≤k

,

I2m,r,α(u) =

T

0

Duα1+m1Zs

H1+m−1)

m j=1

∥∇αjYsH⊗αj

r j=2

∥∇αj′+mZsHαj′+mds,

2.1

= ∑

m,r∈Z+ r1 1m+r2

α(Z+[1,k1])m+r m+r≤|α|≤k

,

2.2

= ∑

m,r∈Z+ r1 3m+rk

α(Z+[1,k2])m+r m+r≤|α|≤k

,

defining a product ∏b

j=axj = 1 if b < a.

If m, r Z+, m 1, 1 m+r 2 and α (Z+[1, k1])m+r, m+r

|α| ≤k, then by the Schwarz inequality and the inductive assumption (1), E

[∫ T

0

(I1m,r,α(u))2du ]

≤E [∫ T

0

du

T

0

Duα11Ys2

H⊗(α1−1)ds

×

T 0

m j=2

∥∇αjYs2H⊗αj

r j=1

∥∇αj′+mZs2Hαj′+mds ]

(T +T2)E [ m

j=1

sup

0tT∥∇αjYs2Hαj

T

0

r j=1

∥∇αj′+mZs2H⊗αj′+mds ]

(T +T2) {

E [ m

j=1

sup

0tT

∥∇αjYs4H⊗αj ]}12

60 CHAPTER 3. MALLIAVIN DIRREFENTIABILITY OF SOLUTIONS

×



E

(∫ T 0

r j=1

∥∇αj′+mZs2H⊗αj′+mds )2



1 2

(T +T2)

m j=1

∥∇αjY∥2S2pj(Hαj)

r j=1

∥∇αj′+mZ∥2H4(H⊗αj′+m)

<∞,

where, to see in the fourth inequality above, r 1 is used, and 1/2 =∑m

j=11/pj. Hence, we get

1.1

E [∫ T

0

(I1m,r,α(u))2du ]

<∞.

Ifm, r Z+,r≥1, 1≤m+r≤2 andα (Z+[1, k1])m+r,m+r≤ |α| ≤k, then by the inductive assumption Claim 1,

E [∫ T

0

(I2m,r,α(u))2du ]

E [∫ T

0

du

T 0

Duα1+m1Zs2

H⊗(α1+m−1)ds

×

T

0

m j=1

∥∇αjYs2H⊗αj

r j=2

∥∇αj′+mZs2Hαj′+mds ]

E [∫ T

0

∥∇α1+mZs2Hα1+mds

×

T 0

m j=1

∥∇αjYs2Hαj

r j=2

∥∇αj′+mZs2H⊗αj′+mds ]

(1 +T) {

E

[(∫ T 0

∥∇α1+mZs2Hα1+mds

)2]}1

2

×



E

∏m

j=1

sup

0tT∥∇αjYs4H⊗αj (∫ T

0

r j=2

∥∇αj′+mZs2Hαj′+mds )2



1 2

(1 +T)

m j=1

∥∇αjY∥2S4(Hαj)

r j=1

∥∇αj′+mZ∥H4(Hαj′+m)

<∞. Thus, we get

2.1

E [∫ T

0

(I2m,r,α(u))2du ]

<∞.

3.4. HIGHER ORDER DIFFERENTIABILITY 61 If αi ≤k 2 for 1 i ≤m+r, then by the inductive assumption Claim 3,

∥∇αjYsH⊗αj and ∥∇αj′+mZsHαj′+m are bounded. Then, we see

1.2

E [∫ T

0

(I1m,r,α(u))2du ]

+∑

2.2

E [∫ T

0

(I2m,r,α(u))2du ]

<∞. Hence, we obtain

E [∫ T

0

(∫ T 0

∥K˜uAks∥ds )2

du ]

<∞,

which implies (A2)-8). Thus, by Theorem 3.3.1, we get (D·k1Y, D·k1Z) Src2(H(k1),P¯)×H 2(H(k1),P¯) andDtk1Yt=∑k1

i=1 Dti1(∫·∧t

0 k1iZsds)+

k1Zt. Since for 1 ≤i≤k−1, Dui1

(∫ ·∧t

0

k1iZsds) 2

H⊗(k−1)

=





0, t ≤u,

t

u

Duk2Zs2

H(k2)ds, u < t, we obtain Dtk1Yt=k1Zt for almost all t∈[0, T]. Claim 2 is proved.

We prove Claim 3. For a.e.u= (u1, . . . , uk)[0, T]k, (DkuY, DukZ)∈Src2(R)× H 2(R) solves

DkuYt=Dkuξ+

T t

{K˜ukAks+yf(s, Ys, Zs)DukYs+zf(s, Ys, Zs)DukZs}ds

T t

DukZsdWs, u¯≤t≤T, where ¯u= max{u1, . . . , uk}. By Lemma 3.4.6, there exists a γk >0 such that

|DkuYt|2eγkt+ 1 2E

[∫ T

t

eγks|DukZs|2ds Ft

]

≤E [

|Dkuξ|2eγkT +

T t

eγks|K˜ukAks|2ds Ft

]

, u¯≤t≤T. (3.27) By (3.22), we see

|K˜ukAks|2 ≤C {

1 +∑

1,k

σSk

J1,m,r,α,β,σ

u (s) +∑

2,k

σSk

J2,m,r,α,β,σ

u (s)

}

, (3.28) where Sk represents the symmetric group of degree k and

J1,m,r,α,β,σ

u (s) =

m1r j=1

|Duασ,αj

j Ys|2

r j=1

|Dβj′

uσ,βj′ Zs|2|Dγuσ,γym1rzrf(t, Yt, Zt)|2,

62 CHAPTER 3. MALLIAVIN DIRREFENTIABILITY OF SOLUTIONS J2,m,r,α,β,σ

u (s) =

mr j=1

|Duασ,αj j

Ys|2

r j=1

|Dβj′

uσ,βj′ Zs|2, α0 = 1, β0 = 1,

uσ,αj = (uσ(j

i=1αi−1), uσ(j

i=1αi−1+1), . . . , uσ(j

i=1αi−1j1)), uσ,βj = (u

σ(|α|+j′

i=1βi−1), u

σ(|α|+j′

i=1βi−1+1), . . . , u

σ(|α|+j′

i=1βi−1j′1)), uσ,γ = (uσ(|α|+|β|+1), uσ(|α|+|β|+2), . . . , uσ(|α|+|β|+γ)).

We divide the first summation of (3.28) into three ones;

1,k

σSk

Ju1(s) = ∑

1,k r=0

σSk

J1,m,r,α,β,σ

u (s) +∑

1,k r=1

σSk

J1,m,r,α,β,σ

u (s) +∑

1,k r2

σSk

J1,m,r,α,β,σ

u (s).

Ifr = 0, derivatives ofZ do not appear inJ1,m,r,α,β,σ

u (s) and eachαj ≤k−1. By the inductive assumption and (A5)-6), we get

1,k r=0

σSk

E [∫ T

t

J1,m,r,α,β,σ

u (s)ds

Ft

]

≤C.

Ifr= 1, β Nandβ1 ≤k−1. By the inductive assumption and (A5)-6), we get

1,k r=1

σSk

E [∫ T

t

J1,m,r,α,β,σ

u (s)ds

Ft

]

≤C

1,k r=0

σSk

E [∫ T

t

|Dβ1

uσ,β1 Zs|2ds Ft

]

≤C.

If r≥2, each βj ≤k−2. By the inductive assumption and (A5)-6), we get

1,k r2

σSk

E [∫ T

t

J1,m,r,α,β,σ

u (s)ds

Ft

]

≤C.

In the same manner as above, we can obtain

2,k

σSk

E [∫ T

t

J2,m,r,α,β,σ

u (s)ds

Ft

]

≤C.

Thus by (3.28), we get E

[∫ T t

|K˜ukAks|2ds Ft

]

≤C.

3.4. HIGHER ORDER DIFFERENTIABILITY 63 Hence by (3.27) and (A5)-1), we obtain

|DukYt|2+E [∫ T

t

|DukZs|2ds Ft

]

≤C, u¯≤t ≤T.

In the same manner as Step 1-ii), we see

|DkuYt|2+E [∫ T

t

|DkuZs|2ds Ft

]

≤C, 0≤t≤T.

And then, for almost all (v, t)[0, T]k1×[0, T], we get

|Dvk1Zt|=|Dkv1DtYt| ≤C.

Integration of |DukYt|2 and |Dkv1Zt|2 with respect to u and v yield also that kYt2

H⊗k+k1Zt2

H(k1) ≤C.

Claim 3 is now proved.

We show Claim 4. (D·k1Y, D·k1Z)∈Src2(H(k1),P¯)×H 2(H(k1),P¯) is a unique solution to the BSDE;

Duk1Yt=Duk1ξ−ζT(u) +ζt(u) +

T t

{K˜uAks+yf(s, Ys, Zs)Duk1Ys+zf(s, Ys, Zs)Duk1Zs}ds

T t

Duk1ZsdWs, 0≤t ≤T, du⊗dP-a.e., whereζt(u) = ∑k1

i=1 Dui1(∫·∧t

0 k1iZsds)+1[0,t](u)k1Zu. Namely, putting Y¯tk(u) =Duk1Yt−ζt(u), ( ¯Y2(·), Du∇Z)∈S2(H(k1),P¯)×H 2(H(k1),P¯) is a unique solution to the BSDE;

Y¯tk(u) = Duk1ξ−ζT(u) +

T

t

{K˜uAks+yf(s, YS, Zss(u)

+yf(s, Ys, Zs) ¯Ysk(u) +zf(s, Ys, Zs)Duk1Zs}ds

T

t

Duk1ZsdWs, 0≤t≤T, du⊗dP-a.e.

Let p≥2. By Claim 2, we get Duk2Zs =DuDsk2Ys and by Claim 3, E

[∫ T 0

sup

0tT∥ζt(u)pH(k1)du ]

64 CHAPTER 3. MALLIAVIN DIRREFENTIABILITY OF SOLUTIONS

≤CE [∫ T

0

{(∫ T 0

∥Duk2Zs2H⊗(k−2)ds )p2

+∥∇k1ZupH(k1)

} du

]

<∞.

Thus in the same manner as (3.26) and (A5)-3)-6), we get E

[∫ T 0

(∫ T 0

∥K˜uAks+yf(s, YS, Zss(u)H(k1)ds )p

du ]

≤C (

1 +

k2

α=0

E [∫ T

0

{ sup

0tT∥DuαYt2pH⊗α + (∫ T

0

∥DuαZs2Hαds )p}

du ])

<∞. Hence, we obtain (D·k1Y, D·k1Z)∈Srcp(H(k1),P¯)×H p(H(k1),P¯).

Acknowledgements

I would like to express my sincere gratitude to my supervisor, Professor Setsuo Taniguchi, for his patience and persistent guidance on me throughout my Ph.D period of time. I am profoundly grateful to him for all of the help, encouragement, and suggestions. Furthermore, his rigorous and uncompromised attitudes toward mathematics told me a lot of importance in studying mathematical problems.

Without his valuable suggestions and contributions, it is not possible for me to achieve these results.

65

Bibliography

[1] O. Aboura and S. Bourguin, Density estimates for solutions to one dimen-sional backward SDE’s, Potential Anal., 2013, 38, 573-587.

[2] F. Antonelli and A. Kohatsu-Higa, Densities of One-Dimensional Backward SDEs, Potential Anal., 2005,22, 263-287.

[3] P. Briand and F. Confortola, Differentiability of Backward Stochastic Differ-ential Equations in Hilbert Spaces with Monotone Generetors, Appl. Math.

Optim., 2008,57, 149-176.

[4] P. Briand, B. Delyon, Y. Hu, E. Pardoux and L. Stoica, Lp solutions of backward stochastic differential equations, Stochastic Process. Appl., 2003, 108, 109-129.

[5] P. Briand and C. Labart, Simulation of BSDEs By Wiener Chaos Expansion, Ann. Appl. Probab., 2014, 24, No. 3, 1129-1171.

[6] S. Chen, Lp solutions of one-dimensional backward stochastic differential equations with continuous coefficients, Stoch. Anal. Appl., 2010, 28, 820-841.

[7] N. El Karoui, S. Peng, and M.C. Quenez, Backward stochastic differential equations in finance, Math. Finance, 1997,7, 1-71.

[8] S. J. Fan and L. Jiang, Lp (p > 1) solutions for one-dimensional BSDEs with linear-growth generators, J. Appl. Math. Comput., 2012, 38, Issue 1, 295-304.

[9] M. Fuhrman and G. Tessitore, Nonlinear Kolmogorov Equations in Infinite Dimensional Spaces: The Backward Stochastic Differential Equations Ap-proach and Applications to Optimal Control, Ann. Probab., 2002, 30, No. 3, 1397-1465.

[10] M. Fuhrman and G. Tessitore, Infinite Horizon Backward Stochastic Dif-ferential Equations and Elliptic Equations in Hilbert Spaces, Ann. Probab., 2004, 32, No. 1, 607-660.

67

68 BIBLIOGRAPHY [11] M. Fuhrman and G. Tessitore, Generalized Directional Gradients, Backward Stochastic Differential Equations and Mild Solutions of Semilinear Parabolic Equations, Appl. Math. Optim, 2005, 51, 279-332.

[12] G. Guatteri, On a Class of Forward-Backward Stochastic Differential Sys-tems in Infinite Dimensions, Journal of Applied Mathematics and Stochastic Analysis, 2007, Aarticle ID 42640.

[13] Y. Hu, D. Nualart and X. Zhong, Malliavin Calculus for Backward Stochastic Differential Equations and Application to Numerical Solutions, Ann. Appl.

Probab., 2011, 21, No. 6, 2379-2423.

[14] N. Ikeda, S. Watanabe, Stochastic Differential Equations and Diffusion Pro-cesses, 2nd ed., 1989, Kodansha.

[15] Y. Izumi, The Lp Cauchy sequence for one-dimensional BSDEs with linear growth generators, Stat. Probabil. Lett., 2013,83, 1588-1594.

[16] Y. Izumi, Higher order differentiability of solutions to backward stochastic differential equations, Stochastics, 2018, 90, No. 1, 102-150.

[17] J. P. Lepeltier and J. San Martin, Backward stochastic differential equations with continuous coefficient. Statist. Probab. Lett., 1997, 32, 425-430.

[18] Q. Lin, Malliavin Derivatives of Solutions for BSDE, Chinese J. Appl.

Probab. Statist., 2000,16, No. 3, 285-294.

[19] P. Malliavin, Stochastic Analysis, 1997, Springer-Verlag.

[20] T. Mastrolia, D. Possama¨ı and R´eveillac, Density Analysis of BSDEs. To appears in the Annals of Probability, arXiv:1402.4416, 2014.

[21] T. Mastrolia, D. Possama¨ı and R´eveillac, On the Malliavin differentiability of BSDEs, arXiv:1404.1026, 2015.

[22] D. Nualart,The Malliavin Calculus and Related Topics, 2nd ed., 2006, Prob-ability and Its Applications, Springer-Verlag.

[23] E. Pardoux and S. Peng, Adapted Solutions of a Backward Stochastic Dif-ferential Equation, Systems Control Lett., 1990, 14, 55-61.

[24] E. Pardoux and S. Peng, Backward Stochastic Differential Equations and Quasilinear Parabolic Partial Differential Equations, Lecture Notes in CIS, vol. 176. Springer-Verlag, 200-217.

[25] I. Shigekawa,Stochastic Analysis, 2004, Translations of Mathematical Mono-graphs, American Mathematical Society.

ドキュメント内 Backward Stochastic Differential Equations and Solutions (ページ 56-76)

関連したドキュメント