Interpolations of harmonic Bergman functions on smooth bounded domains
Kiyoki Tanaka
Osaka City University Advanced Mathematical Institute
December, 22, 2013 / 22th Functional Space Seminar
Outline
1 Setting
2 Results
3 Outline of the proof
Bergman space (origin)
LetD⊂Cbe the unit disc.
L2a(D,dA) ={f : analytic onD,kfk2<∞}
f ∈L2a(D,dA)has the following formula:
f(z) = Z
D
f(w) 1
π(1−zw)¯ 2dA(w)forz ∈D K(z,w) = π(1−z1w)¯ 2 : Bergman kernel
Forf ∈L2(D,dA),Pf(z) :=R
Df(w)π(1−z1w)¯ 2dA(w): Bergman projection
Bergman space (origin)
LetD⊂Cbe the unit disc.
L2a(D,dA) ={f : analytic onD,kfk2<∞}
f ∈L2a(D,dA)has the following formula:
f(z) = Z
D
f(w) 1
π(1−zw)¯ 2dA(w)forz ∈D K(z,w) = π(1−z1w)¯ 2 : Bergman kernel
Forf ∈L2(D,dA),Pf(z) :=R
Df(w)π(1−z1w)¯ 2dA(w): Bergman projection
Bergman space (origin)
LetD⊂Cbe the unit disc.
L2a(D,dA) ={f : analytic onD,kfk2<∞}
f ∈L2a(D,dA)has the following formula:
f(z) = Z
D
f(w) 1
π(1−zw)¯ 2dA(w)forz ∈D K(z,w) = π(1−z1w)¯ 2 : Bergman kernel
Forf ∈L2(D,dA),Pf(z) :=R
Df(w)π(1−z1w)¯ 2dA(w): Bergman projection
Examples of research
Characterization of operators onL2a(D)( Toeplitz operator, Hankel operator, composition operator, etc. )
Change setting:
measuredA weighted measureϕ(w)dA(w)(ϕ(w) = (1− |w|2)α )
D certain domain ( upper-half plane, ball inCn, pseudo-convex domain)
analytic solution of certain differential equation ( harmonic, heat equation )
Examples of research
Characterization of operators onL2a(D)( Toeplitz operator, Hankel operator, composition operator, etc. )
Change setting:
measuredA weighted measureϕ(w)dA(w)(ϕ(w) = (1− |w|2)α )
D certain domain ( upper-half plane, ball inCn, pseudo-convex domain)
analytic solution of certain differential equation ( harmonic, heat equation )
Harmonic Bergman space
1≤p<∞,Ω⊂Rn: bounded smooth domain.
bp(Ω) :={f : harmonic inΩandkfkp<∞}
bp: harmonic Bergman space.
bp(Ω)⊂Lp(Ω): closed subspace f ∈b2(Ω)has a reproducing property:
f(x) = Z
Ω
R(x,y)f(y)dy forx ∈Ω R(·,·):harmonic Bergman kernel.
Example of the harmonic Bergman kernel
WhenΩ =B(unit ball),
RB(x,y) = (n−4)|x|4|y|4+ (8x ·y−2n−4)|x|2|y|2+n n|B|((1− |x|2)(1− |y|2) +|x−y|2)1+n2 and
RB(x,x) = (n−4)|x|4+2n|x|2+n n|B|(1− |x|2)n
Preparation for results
Lemma (covering lemma)
Let0< δ < 14. We can choose N (independ ofδ),{λi} ⊂Ωand disjoint covering{Ei}forΩ.
1 Ei is measurable set for any i ∈N;
2 Ei ⊂B(λi, δr(λi))for any i ∈N;
3 {B(λi,3δr(λi))}is uniformly finite intersection with bound N
Representation theorem
Theorem (T. (2012))
Let1<p<∞,Ωbe a bounded smooth domain. There exists0< δ0
such that if{λi}satisfies covering lemma forδ < δ0, then
Ap,{λi} :`p→bp is a bounded onto map, where the operator Ap,{λi} is defined by
Ap,{λi}{ai}(x) :=
∞
X
i=1
aiR(x, λi)r(λi)(1−1p)n,
where r(x)denotes the distance between x and∂Ω.
Fix a defining functionηforΩs.t.|∇η|2=1+ηωfor someω∈C∞( ¯Ω).
B.R. Choe, H. Koo and H. Yi (2004) introduced the following kernel R1(x,y) :=R(x,y)−1
2∆y(η2(y)Rx(y)).
and shown thatR1has the reproducing property.
Theorem (T. (2013))
Let1≤p<∞andΩbe a smooth bounded domain. Then, we can choose a sequence{λi}inΩsuch that A1:`p→bpis a bounded onto map, where the operator A1is defined by
A1{ai}(x) :=
∞
X
i=1
aiR1(x, λi)r(λi)(1−1p)n,
Interpolating of harmonic Bergman functions
Let denoteV :bp(Ω)→lp by
Vp,{λi}f :={r(λi)
n pf(λi)}.
It is known thatA∗p,{λ
i}=Vq,{λi} for 1<p<∞,q: 1p+q1 =1.
Theorem (T. (2013))
Let1<p<∞. We can choose a positive constantρ0satisfying the following condition;
if{λi}i ⊂Ωsatisfy quasi-hyperbolic distanceρ(λi, λj)> ρ0for i 6=j, then V :bp(Ω)→lpis bounded and onto.
Interpolating of harmonic Bergman functions
Let denoteV :bp(Ω)→lp by
Vp,{λi}f :={r(λi)
n pf(λi)}.
It is known thatA∗p,{λ
i}=Vq,{λi} for 1<p<∞,q: 1p+q1 =1.
Theorem (T. (2013))
Let1<p<∞. We can choose a positive constantρ0satisfying the following condition;
if{λi}i ⊂Ωsatisfy quasi-hyperbolic distanceρ(λi, λj)> ρ0for i 6=j, then V :bp(Ω)→lpis bounded and onto.
ρ(x,y) := inf
γ∈Γx,y
Z
γ
1
r(z)ds(z)
The preceding works
R.R. Coifman - R. Rochberg (1980) : holomorphic on unit ball in Cn
B.R. Choe - H. Yi (1998) : harmonic on upper half space inRn K. Tanaka : harmonic on smooth bounded domain
The preceding result
Theorem (Kang-Koo 2002)
LetΩbe a smooth bounded domain andαandβbe multi-indices.
Then, there exist Cα,β >0and C>0such that for any x,y ∈Ω
|DxαDβyR(x,y)| ≤ Cα,β d(x,y)n+|α|+|β|
and
R(x,x)≥ C r(x)n
where d(x,y) :=r(x) +r(y) +|x−y|and r(x)is the distance between x and boundary ofΩ.
Outline of the proof of representation theorem
Lemma (covering lemma)
Let0< δ < 14. We can choose N (independ ofδ),{λi} ⊂Ωand disjoint covering{Ei}forΩ.
1 Ei is measurable set for any i ∈N;
2 Ei ⊂B(λi, δr(λi))for any i ∈N;
3 {B(λi,3δr(λi))}is uniformly finite intersection with bound N Remark.
If there exists a positive constantc >0 such that{B(λi,cr(λi))}is uniformly finite intersection, thenAp,{λi} andVp,{λi} are bounded for
∞.
We define the operatorsUp,{λi} :bp→`pandSp,{λi}:bp→bpas following;
Sp,{λi}f(x) :=
∞
X
i=1
R(x, λi)f(λi)|Ei|
Up,{λi}(f) :={|Ei|f(λi)r(λi)−(1−
1 p)n
}i
where{Ei}i is the disjoint covering ofΩsuch thatλi ∈Ei for anyi ∈N. BecauseS=A◦U, we may show thatSis bijective map. By
calculatingkS−Idk, we can give the condition thatSis bijective.
Interpolating of harmonic Bergman functions (again)
Let denoteV :bp(Ω)→lp by
Vp,{λi}f :={r(λi)
n pf(λi)}.
It is known thatA∗p,{λ
i}=Vq,{λi} for 1<p<∞,q: 1p+q1 =1.
Theorem (T. (2013))
Let1<p<∞. We can choose a positive constantρ0satisfying the following condition;
if{λi}i ⊂Ωsatisfy quasi-hyperbolic distanceρ(λi, λj)> ρ0for i 6=j, then V :bp(Ω)→lpis bounded and onto.
Outline of the proof of interpolating sequence theorem
We assumeρ(λi, λj)> ρ >1.
Then, there existδ >0 such that{B(λi, δr(λi))}is disjoint.We put Wp,{λi}{ai}:=V ◦A{ai}={r(λj)np
∞
X
i=1
aiR(λj, λi)r(λi)(1−1p)n}j.
We choose the{λi}i such that the operatorW is bijective. We put diagonal part ofW
D{ai}:={ajR(λj, λj)r(λj)n} and off diagonal part ofW
E{ai}:={r(λj)npX
i6=j
aiR(λj, λi)r(λi)(1−1p)n}j.
Outline of the proof of interpolating sequence theorem
We assumeρ(λi, λj)> ρ >1.
Then, there existδ >0 such that{B(λi, δr(λi))}is disjoint. We put Wp,{λi}{ai}:=V ◦A{ai}={r(λj)np
∞
X
i=1
aiR(λj, λi)r(λi)(1−1p)n}j.
We choose the{λi}i such that the operatorW is bijective. We put diagonal part ofW
D{ai}:={ajR(λj, λj)r(λj)n} and off diagonal part ofW
nX (1−1)n
Outline of the proof of interpolating sequence theorem
We assumeρ(λi, λj)> ρ >1.
Then, there existδ >0 such that{B(λi, δr(λi))}is disjoint. We put Wp,{λi}{ai}:=V ◦A{ai}={r(λj)np
∞
X
i=1
aiR(λj, λi)r(λi)(1−1p)n}j.
We choose the{λi}i such that the operatorW is bijective. We put diagonal part ofW
D{ai}:={ajR(λj, λj)r(λj)n} and off diagonal part ofW
E{ai}:={r(λj)npX
i6=j
aiR(λj, λi)r(λi)(1−1p)n}j.
BecauseD: bijective andW =D+E,kEk< kD1−1k ⇒W : bijective.
Moreover, sinceR(x,x)r(x)n≈1,kDk ≈1. We have only to give the estimate forkEk. By using Hölder’s inequality, we have
kE{ai}klp .δ
−n(p−1) p
X∞
i=1
|ai|pr(λi)
1
qX
j6=i
r(λj)n−
1
q|R(λj, λi)|1p
We calculate a part of summation;
r(λi)1qX
j6=i
r(λj)n−1q|R(λj, λi)|. Z
Ω\Eδ(λi)
r(λi)1qr(z)−1q d(z, λi)n dz
BecauseD: bijective andW =D+E,kEk< kD1−1k ⇒W : bijective.
Moreover, sinceR(x,x)r(x)n≈1,kDk ≈1. We have only to give the estimate forkEk. By using Hölder’s inequality, we have
kE{ai}klp .δ
−n(p−1) p
X∞
i=1
|ai|pr(λi)
1
qX
j6=i
r(λj)n−
1
q|R(λj, λi)|1p
We calculate a part of summation;
r(λi)1qX
j6=i
r(λj)n−1q|R(λj, λi)|. Z
Ω\Eδ(λi)
r(λi)1qr(z)−1q d(z, λi)n dz
BecauseD: bijective andW =D+E,kEk< kD1−1k ⇒W : bijective.
Moreover, sinceR(x,x)r(x)n≈1,kDk ≈1. We have only to give the estimate forkEk. By using Hölder’s inequality, we have
kE{ai}klp .δ
−n(p−1) p
X∞
i=1
|ai|pr(λi)
1
qX
j6=i
r(λj)n−
1
q|R(λj, λi)|1p
We calculate a part of summation;
r(λi)1qX
j6=i
r(λj)n−1q|R(λj, λi)|. Z
Ω\Eδ(λi)
r(λi)1qr(z)−1q d(z, λi)n dz
BecauseD: bijective andW =D+E,kEk< kD1−1k ⇒W : bijective.
Moreover, sinceR(x,x)r(x)n≈1,kDk ≈1. We have only to give the estimate forkEk. By using Hölder’s inequality, we have
kE{ai}klp .δ
−n(p−1) p
X∞
i=1
|ai|pr(λi)
1
qX
j6=i
r(λj)n−
1
q|R(λj, λi)|1p
We calculate a part of summation;
r(λi)1qX
j6=i
r(λj)n−1q|R(λj, λi)|. Z
Ω\Eδ(λi)
r(λi)1qr(z)−1q d(z, λi)n dz
Lemma (Pseudo-hyperbolic distance)
There exist constants C1>0and C2>0such that for any x,y ∈Ω 1
d(x,y) ≤ exp(−ρ(x,y)−CC 1
2 )
min{r(x),r(y)}.
By using quasi-hyperbolic distance conditionρ(λi, λj)> ρ, for 0< <1 we have
Z
Ω\Eδ(λi)
r(λi)1qr(z)−1q
d(z, λi)n dz .exp(−(ρ−C1 C2 ))→0 asρ→ ∞.
Then, there existsρ0>0 such thatkEk< kD1−1k ifρ(λi, λj)> ρ0(i6=j).
Lemma (Pseudo-hyperbolic distance)
There exist constants C1>0and C2>0such that for any x,y ∈Ω 1
d(x,y) ≤ exp(−ρ(x,y)−CC 1
2 )
min{r(x),r(y)}.
By using quasi-hyperbolic distance conditionρ(λi, λj)> ρ, for 0< <1 we have
Z
Ω\Eδ(λi)
r(λi)1qr(z)−1q
d(z, λi)n dz .exp(−(ρ−C1 C2 ))→0 asρ→ ∞.
Then, there existsρ0>0 such thatkEk< kD1−1k ifρ(λi, λj)> ρ0(i6=j).
References
[1] B. R. Choe, H. Koo and H. Yi,Projections for harmonic Bergman spaces and applications, J. Funct. Anal.,216(2004), 388–421.
[2] B. R. Choe and H. Yi,Representations and interpolations of harmonic Bergman functions on half-spaces, Nagoya Math. J.151(1998), 51–89.
[3] R.R. Coifman and R. Rochberg,Representation Theorems for
Holomorphic and Harmonic functions in Lp,Ast´erisque77(1980), 11–66.
[4] C. Fefferman,The Bergman kernel and biholomorphic mappings of pseudoconvex domains, Inv. Math. 26(1974), 1–65.
[5] H. Kang and H. Koo,Estimates of the harmonic Bergman kernel on smooth domains, J. Funct. Anal.,185(2001), 220–239.
[6] K. Tanaka,Atomic decomposition of harmonic Bergman functions, Hiroshima Math. J., 42 (2012), 143–160.
[7] K. Tanaka,Interpolation theorem for harmonic Bergman functions, RIMS Kôkyûroku Bessatu B43 (2013), 183–191.