• 検索結果がありません。

Interpolations of harmonic Bergman functions on smooth bounded domains

N/A
N/A
Protected

Academic year: 2024

シェア "Interpolations of harmonic Bergman functions on smooth bounded domains"

Copied!
29
0
0

読み込み中.... (全文を見る)

全文

(1)

Interpolations of harmonic Bergman functions on smooth bounded domains

Kiyoki Tanaka

Osaka City University Advanced Mathematical Institute

December, 22, 2013 / 22th Functional Space Seminar

(2)

Outline

1 Setting

2 Results

3 Outline of the proof

(3)

Bergman space (origin)

LetD⊂Cbe the unit disc.

L2a(D,dA) ={f : analytic onD,kfk2<∞}

f ∈L2a(D,dA)has the following formula:

f(z) = Z

D

f(w) 1

π(1−zw)¯ 2dA(w)forz ∈D K(z,w) = π(1−z1w)¯ 2 : Bergman kernel

Forf ∈L2(D,dA),Pf(z) :=R

Df(w)π(1−z1w)¯ 2dA(w): Bergman projection

(4)

Bergman space (origin)

LetD⊂Cbe the unit disc.

L2a(D,dA) ={f : analytic onD,kfk2<∞}

f ∈L2a(D,dA)has the following formula:

f(z) = Z

D

f(w) 1

π(1−zw)¯ 2dA(w)forz ∈D K(z,w) = π(1−z1w)¯ 2 : Bergman kernel

Forf ∈L2(D,dA),Pf(z) :=R

Df(w)π(1−z1w)¯ 2dA(w): Bergman projection

(5)

Bergman space (origin)

LetD⊂Cbe the unit disc.

L2a(D,dA) ={f : analytic onD,kfk2<∞}

f ∈L2a(D,dA)has the following formula:

f(z) = Z

D

f(w) 1

π(1−zw)¯ 2dA(w)forz ∈D K(z,w) = π(1−z1w)¯ 2 : Bergman kernel

Forf ∈L2(D,dA),Pf(z) :=R

Df(w)π(1−z1w)¯ 2dA(w): Bergman projection

(6)

Examples of research

Characterization of operators onL2a(D)( Toeplitz operator, Hankel operator, composition operator, etc. )

Change setting:

measuredA weighted measureϕ(w)dA(w)(ϕ(w) = (1− |w|2)α )

D certain domain ( upper-half plane, ball inCn, pseudo-convex domain)

analytic solution of certain differential equation ( harmonic, heat equation )

(7)

Examples of research

Characterization of operators onL2a(D)( Toeplitz operator, Hankel operator, composition operator, etc. )

Change setting:

measuredA weighted measureϕ(w)dA(w)(ϕ(w) = (1− |w|2)α )

D certain domain ( upper-half plane, ball inCn, pseudo-convex domain)

analytic solution of certain differential equation ( harmonic, heat equation )

(8)

Harmonic Bergman space

1≤p<∞,Ω⊂Rn: bounded smooth domain.

bp(Ω) :={f : harmonic inΩandkfkp<∞}

bp: harmonic Bergman space.

bp(Ω)⊂Lp(Ω): closed subspace f ∈b2(Ω)has a reproducing property:

f(x) = Z

R(x,y)f(y)dy forx ∈Ω R(·,·):harmonic Bergman kernel.

(9)

Example of the harmonic Bergman kernel

WhenΩ =B(unit ball),

RB(x,y) = (n−4)|x|4|y|4+ (8x ·y−2n−4)|x|2|y|2+n n|B|((1− |x|2)(1− |y|2) +|x−y|2)1+n2 and

RB(x,x) = (n−4)|x|4+2n|x|2+n n|B|(1− |x|2)n

(10)

Preparation for results

Lemma (covering lemma)

Let0< δ < 14. We can choose N (independ ofδ),{λi} ⊂Ωand disjoint covering{Ei}forΩ.

1 Ei is measurable set for any i ∈N;

2 Ei ⊂B(λi, δr(λi))for any i ∈N;

3 {B(λi,3δr(λi))}is uniformly finite intersection with bound N

(11)

Representation theorem

Theorem (T. (2012))

Let1<p<∞,Ωbe a bounded smooth domain. There exists0< δ0

such that if{λi}satisfies covering lemma forδ < δ0, then

Ap,{λi} :`p→bp is a bounded onto map, where the operator Ap,{λi} is defined by

Ap,{λi}{ai}(x) :=

X

i=1

aiR(x, λi)r(λi)(1−1p)n,

where r(x)denotes the distance between x and∂Ω.

(12)

Fix a defining functionηforΩs.t.|∇η|2=1+ηωfor someω∈C( ¯Ω).

B.R. Choe, H. Koo and H. Yi (2004) introduced the following kernel R1(x,y) :=R(x,y)−1

2∆y2(y)Rx(y)).

and shown thatR1has the reproducing property.

Theorem (T. (2013))

Let1≤p<∞andΩbe a smooth bounded domain. Then, we can choose a sequence{λi}inΩsuch that A1:`p→bpis a bounded onto map, where the operator A1is defined by

A1{ai}(x) :=

X

i=1

aiR1(x, λi)r(λi)(1−1p)n,

(13)

Interpolating of harmonic Bergman functions

Let denoteV :bp(Ω)→lp by

Vp,{λi}f :={r(λi)

n pf(λi)}.

It is known thatAp,{λ

i}=Vq,{λi} for 1<p<∞,q: 1p+q1 =1.

Theorem (T. (2013))

Let1<p<∞. We can choose a positive constantρ0satisfying the following condition;

if{λi}i ⊂Ωsatisfy quasi-hyperbolic distanceρ(λi, λj)> ρ0for i 6=j, then V :bp(Ω)→lpis bounded and onto.

(14)

Interpolating of harmonic Bergman functions

Let denoteV :bp(Ω)→lp by

Vp,{λi}f :={r(λi)

n pf(λi)}.

It is known thatAp,{λ

i}=Vq,{λi} for 1<p<∞,q: 1p+q1 =1.

Theorem (T. (2013))

Let1<p<∞. We can choose a positive constantρ0satisfying the following condition;

if{λi}i ⊂Ωsatisfy quasi-hyperbolic distanceρ(λi, λj)> ρ0for i 6=j, then V :bp(Ω)→lpis bounded and onto.

ρ(x,y) := inf

γ∈Γx,y

Z

γ

1

r(z)ds(z)

(15)

The preceding works

R.R. Coifman - R. Rochberg (1980) : holomorphic on unit ball in Cn

B.R. Choe - H. Yi (1998) : harmonic on upper half space inRn K. Tanaka : harmonic on smooth bounded domain

(16)

The preceding result

Theorem (Kang-Koo 2002)

LetΩbe a smooth bounded domain andαandβbe multi-indices.

Then, there exist Cα,β >0and C>0such that for any x,y ∈Ω

|DxαDβyR(x,y)| ≤ Cα,β d(x,y)n+|α|+|β|

and

R(x,x)≥ C r(x)n

where d(x,y) :=r(x) +r(y) +|x−y|and r(x)is the distance between x and boundary ofΩ.

(17)

Outline of the proof of representation theorem

Lemma (covering lemma)

Let0< δ < 14. We can choose N (independ ofδ),{λi} ⊂Ωand disjoint covering{Ei}forΩ.

1 Ei is measurable set for any i ∈N;

2 Ei ⊂B(λi, δr(λi))for any i ∈N;

3 {B(λi,3δr(λi))}is uniformly finite intersection with bound N Remark.

If there exists a positive constantc >0 such that{B(λi,cr(λi))}is uniformly finite intersection, thenAp,{λi} andVp,{λi} are bounded for

∞.

(18)

We define the operatorsUp,{λi} :bp→`pandSp,{λi}:bp→bpas following;

Sp,{λi}f(x) :=

X

i=1

R(x, λi)f(λi)|Ei|

Up,{λi}(f) :={|Ei|f(λi)r(λi)−(1−

1 p)n

}i

where{Ei}i is the disjoint covering ofΩsuch thatλi ∈Ei for anyi ∈N. BecauseS=A◦U, we may show thatSis bijective map. By

calculatingkS−Idk, we can give the condition thatSis bijective.

(19)

Interpolating of harmonic Bergman functions (again)

Let denoteV :bp(Ω)→lp by

Vp,{λi}f :={r(λi)

n pf(λi)}.

It is known thatAp,{λ

i}=Vq,{λi} for 1<p<∞,q: 1p+q1 =1.

Theorem (T. (2013))

Let1<p<∞. We can choose a positive constantρ0satisfying the following condition;

if{λi}i ⊂Ωsatisfy quasi-hyperbolic distanceρ(λi, λj)> ρ0for i 6=j, then V :bp(Ω)→lpis bounded and onto.

(20)

Outline of the proof of interpolating sequence theorem

We assumeρ(λi, λj)> ρ >1.

Then, there existδ >0 such that{B(λi, δr(λi))}is disjoint.We put Wp,{λi}{ai}:=V ◦A{ai}={r(λj)np

X

i=1

aiR(λj, λi)r(λi)(1−1p)n}j.

We choose the{λi}i such that the operatorW is bijective. We put diagonal part ofW

D{ai}:={ajR(λj, λj)r(λj)n} and off diagonal part ofW

E{ai}:={r(λj)npX

i6=j

aiR(λj, λi)r(λi)(1−1p)n}j.

(21)

Outline of the proof of interpolating sequence theorem

We assumeρ(λi, λj)> ρ >1.

Then, there existδ >0 such that{B(λi, δr(λi))}is disjoint. We put Wp,{λi}{ai}:=V ◦A{ai}={r(λj)np

X

i=1

aiR(λj, λi)r(λi)(1−1p)n}j.

We choose the{λi}i such that the operatorW is bijective. We put diagonal part ofW

D{ai}:={ajR(λj, λj)r(λj)n} and off diagonal part ofW

nX (1−1)n

(22)

Outline of the proof of interpolating sequence theorem

We assumeρ(λi, λj)> ρ >1.

Then, there existδ >0 such that{B(λi, δr(λi))}is disjoint. We put Wp,{λi}{ai}:=V ◦A{ai}={r(λj)np

X

i=1

aiR(λj, λi)r(λi)(1−1p)n}j.

We choose the{λi}i such that the operatorW is bijective. We put diagonal part ofW

D{ai}:={ajR(λj, λj)r(λj)n} and off diagonal part ofW

E{ai}:={r(λj)npX

i6=j

aiR(λj, λi)r(λi)(1−1p)n}j.

(23)

BecauseD: bijective andW =D+E,kEk< kD1−1k ⇒W : bijective.

Moreover, sinceR(x,x)r(x)n≈1,kDk ≈1. We have only to give the estimate forkEk. By using Hölder’s inequality, we have

kE{ai}klp

−n(p−1) p

X

i=1

|ai|pr(λi)

1

qX

j6=i

r(λj)n−

1

q|R(λj, λi)|1p

We calculate a part of summation;

r(λi)1qX

j6=i

r(λj)n−1q|R(λj, λi)|. Z

Ω\Eδi)

r(λi)1qr(z)1q d(z, λi)n dz

(24)

BecauseD: bijective andW =D+E,kEk< kD1−1k ⇒W : bijective.

Moreover, sinceR(x,x)r(x)n≈1,kDk ≈1. We have only to give the estimate forkEk. By using Hölder’s inequality, we have

kE{ai}klp

−n(p−1) p

X

i=1

|ai|pr(λi)

1

qX

j6=i

r(λj)n−

1

q|R(λj, λi)|1p

We calculate a part of summation;

r(λi)1qX

j6=i

r(λj)n−1q|R(λj, λi)|. Z

Ω\Eδi)

r(λi)1qr(z)1q d(z, λi)n dz

(25)

BecauseD: bijective andW =D+E,kEk< kD1−1k ⇒W : bijective.

Moreover, sinceR(x,x)r(x)n≈1,kDk ≈1. We have only to give the estimate forkEk. By using Hölder’s inequality, we have

kE{ai}klp

−n(p−1) p

X

i=1

|ai|pr(λi)

1

qX

j6=i

r(λj)n−

1

q|R(λj, λi)|1p

We calculate a part of summation;

r(λi)1qX

j6=i

r(λj)n−1q|R(λj, λi)|. Z

Ω\Eδi)

r(λi)1qr(z)1q d(z, λi)n dz

(26)

BecauseD: bijective andW =D+E,kEk< kD1−1k ⇒W : bijective.

Moreover, sinceR(x,x)r(x)n≈1,kDk ≈1. We have only to give the estimate forkEk. By using Hölder’s inequality, we have

kE{ai}klp

−n(p−1) p

X

i=1

|ai|pr(λi)

1

qX

j6=i

r(λj)n−

1

q|R(λj, λi)|1p

We calculate a part of summation;

r(λi)1qX

j6=i

r(λj)n−1q|R(λj, λi)|. Z

Ω\Eδi)

r(λi)1qr(z)1q d(z, λi)n dz

(27)

Lemma (Pseudo-hyperbolic distance)

There exist constants C1>0and C2>0such that for any x,y ∈Ω 1

d(x,y) ≤ exp(−ρ(x,y)−CC 1

2 )

min{r(x),r(y)}.

By using quasi-hyperbolic distance conditionρ(λi, λj)> ρ, for 0< <1 we have

Z

Ω\Eδi)

r(λi)1qr(z)1q

d(z, λi)n dz .exp(−(ρ−C1 C2 ))→0 asρ→ ∞.

Then, there existsρ0>0 such thatkEk< kD1−1k ifρ(λi, λj)> ρ0(i6=j).

(28)

Lemma (Pseudo-hyperbolic distance)

There exist constants C1>0and C2>0such that for any x,y ∈Ω 1

d(x,y) ≤ exp(−ρ(x,y)−CC 1

2 )

min{r(x),r(y)}.

By using quasi-hyperbolic distance conditionρ(λi, λj)> ρ, for 0< <1 we have

Z

Ω\Eδi)

r(λi)1qr(z)1q

d(z, λi)n dz .exp(−(ρ−C1 C2 ))→0 asρ→ ∞.

Then, there existsρ0>0 such thatkEk< kD1−1k ifρ(λi, λj)> ρ0(i6=j).

(29)

References

[1] B. R. Choe, H. Koo and H. Yi,Projections for harmonic Bergman spaces and applications, J. Funct. Anal.,216(2004), 388–421.

[2] B. R. Choe and H. Yi,Representations and interpolations of harmonic Bergman functions on half-spaces, Nagoya Math. J.151(1998), 51–89.

[3] R.R. Coifman and R. Rochberg,Representation Theorems for

Holomorphic and Harmonic functions in Lp,Ast´erisque77(1980), 11–66.

[4] C. Fefferman,The Bergman kernel and biholomorphic mappings of pseudoconvex domains, Inv. Math. 26(1974), 1–65.

[5] H. Kang and H. Koo,Estimates of the harmonic Bergman kernel on smooth domains, J. Funct. Anal.,185(2001), 220–239.

[6] K. Tanaka,Atomic decomposition of harmonic Bergman functions, Hiroshima Math. J., 42 (2012), 143–160.

[7] K. Tanaka,Interpolation theorem for harmonic Bergman functions, RIMS Kôkyûroku Bessatu B43 (2013), 183–191.

参照

関連したドキュメント

In this paper, we investigate the existence and uniqueness of weighted pseudo almost automorphic mild solutions to semilinear boundary differential equations in Banach s‐

In [5], the representation properties of harmonic Bergman functions, as well as harmonic Bloch func-.. tions, were also proved on the unit