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20 (2004), 45–51 www.emis.de/journals

ITERATIVE CONVERGENCE OF RESOLVENTS OF MAXIMAL MONOTONE OPERATORS PERTURBED BY THE DUALITY

MAP IN BANACH SPACES

SAFEER HUSSAIN KHAN

Abstract. For a maximal monotone operatorTin a Banach space an iterative solution of 0 T xhas been found through weak and strong convergence of resolvents of these operators. Identity mapping in the definition of resolvents has been replaced by the duality mapping. Solution after finite steps has also been established.

1. Introduction

Let E be a real Banach space and E its topological dual. Let T :E E be a maximal monotone operator. Then Jr defined byJr= (I+rT)−1 forr >0 is called resolvent of T. A well-known way to solve the inclusion 0∈T x through weak and strong convergence of resolvents of the maximal monotone operators T is to use the iteration scheme:

(1) x1=x∈E, xn+1=Jrnxn, n= 1,2,3, . . ..

where{rn}is a sequence of positive real numbers. The convergence of the iteration scheme (1) in case of Hilbert spaces was studied by Rockafellar [13], Br´ezis and Lions [3], Lions [9] and Pazy [11]. In Banach spaces the problem was carried out by Bruck and Reich [6], Bruck and Passty [5] and Jung and Takahashi [7] among others.

The purpose of this paper is to find the solution of 0 T x in the following manner. We replace the identity operator I by the duality mapping J in the definition of Jr above and definePr:E→E as

Pr= (J+rT)−1.

Since the duality mappingJ is not linear,Pris not nonexpansive as compared with Jr above. In case of a Hilbert space, both the definitions coincide. With the help of this Pr, we define

(2) Jr=Pr◦J

and

Tr=J−J◦Jr

r , r >0

where the symbolstands for the usual composition of functions. At first, we shall prove some of the properties ofTr. Afterwards, we shall give some weak and strong

2000Mathematics Subject Classification. 47H05, 49M05.

Key words and phrases. Resolvent, maximal monotone operator, weak convergence, strong convergence, iteration scheme.

45

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convergence theorems using this newJr via the iteration scheme:





x0=x∈E, xn+1=Jrnxn, kxn−Jrnxnk ≤²n, n= 0,1,2, . . ., {rn} ⊂(0,∞), rn → ∞,

n} ⊂(0,∞), P

n=1²n <∞.

At the end, following Rockafellar [13] we establish the solution of 0∈T xafter a finite number of steps.

2. Preliminaries and Notation

LetEbe a real Banach space andEits topological dual. The duality mapping J:E→E is defined as:

Jx

y∈E :hx, yi=kxk2=kyk2ª

, x∈E.

An operator T: E E (generally multivalued) is called monotone if for any x, y ∈D(T), u∈T x, v∈T y,we have hu−v, x−yi ≥0. T is termed as maximal monotone if it is monotone and for (x, u)∈E×E,the inequalitieshu−v, x−yi ≥0 for all (y, v)∈G(T) imply (x, u)∈G(T),where G(T) denotes the graph ofT.

In the sequel, the symbol * stands for the weak convergence and the symbol

for the strong convergence. In a uniformly convex Banach space E, for any sequence{xn} ∈E satisfyingxn * xandkxnk → kxk, we havexn→x.

A Banach space E is said to satisfy Opial’s condition [10] if for any sequence {xn}inE, xn* ximplies that

lim sup

n→∞ kxn−xk<lim sup

n→∞ kxn−yk for ally∈E withy6=x.

We also know that for two nonnegative sequences{sn} and{tn}satisfying sn+1≤sn+tn for alln≥1,

ifP

n=1tn<∞then limn→∞sn exists.

For the sake of simplicity we omit the symbol ◦. Thus the definitions of Pr, Jr

and Tr can be rewritten as

(3)





Pr= (J+rT)−1, Jr=PrJ,

Tr=J−JJr r, r >0.

In the sequel, T will always stand for a maximal monotone operator, J for the duality map as defined above and Pr,Jr andTrwill be as defined in (3).

Before going to the weak and strong convergence theorems, we deal with some fundamental properties ofTr.

Proposition 1. Trx∈T Jrx,r >0.

Proof. Letr >0 be arbitrary. Then for anyx∈E, Jrx= (J+rT)−1Jx or Jx= (J+rT)Jrx or Jx−JJrx

r ∈T Jrx or Trx∈T Jrx.

¤ Proposition 2. 0 T x if and only if Trx = 0. In particular, we have T−10 = F(Jr),the set of fixed points of Jr, r >0.

(3)

Proof. Letr >0 andx∈E. Then

0∈T x iff 0∈rT x

iff Jx∈(J+rT)x iff x

(J+rT)−1J¢ x iff x=Jrx

iff Jx= (JJr)x iff 0 = (J−JJr)x iff 0 =rTrx iff 0 =Trx.

¤ 3. Weak convergence of resolvents

Our purpose in this section is to prove a weak convergence theorem for resolvents of maximal monotone operators as follows.

Theorem 1. Let E be a uniformly convex Banach space which satisfies Opial’s condition. Let x0 = x E and {xn} be defined as xn+1 = Jrnxn with kxn Jrnxnk ≤ ²n for all n = 0,1,2, . . ., where {rn} ⊂ (0,∞) such that rn → ∞ and n} ⊂ (0,∞)such that P

n=1²n <∞. If T−106=φ then {xn} converges weakly to a solution of0∈T x.

Proof. Letu∈T−10. Then

kxn+1−uk ≤ kxn+1−xnk+kxn−uk

≤²n+kxn−uk.

SinceP

n=1²n<∞therefore limn→∞kxn−ukexists and hence{kxnk}is bounded.

Thus there existsM >0 such thatkxnk ≤M for alln= 0,1,2, . . .. We prove that {xn}has a unique weak subsequential limit inT−10. For, letpandqbe the weak limits of the subsequences {xni} and {xnj} of {xn}, respectively. We prove that p=q∈T−10. Since

kTrnxnk= 1 rn

kJxn−JJrnxnk

1

rn (kJxnk+kJJrnxnk)

= 1

rn (kxnk+kJrnxnk)

= 1

rn (kxnk+kxn+1k)

2M rn

0 as rn → ∞, and T is monotone, therefore

(4) hx−Jrnixni, y−Trnixnii ≥0 for allni= 0,1,2, . . .,x∈E andy∈T x.

We shall now show thatxni * p impliesJrnixni * pas ni → ∞. Letf ∈E. We know that xni* pif and only if

hf, xnii → hf, pi.

(4)

Then

hf, xnii=hf, Jrnixnii+hf, xni−Jrnixnii

≤ hf, Jrnixnii+kfkkxni−Jrnixnik

≤ hf, Jrnixnii+kfk²ni

so that

lim inf

ni→∞hf, xnii ≤lim inf

ni→∞hf, Jrnixnii+kfk lim

ni→∞²ni

or

lim inf

ni→∞hf, xnii ≤lim inf

ni→∞hf, Jrnixnii because f is bounded. Thus we obtain

(5) hf, pi ≤lim inf

ni→∞hf, Jrnixnii.

Similarly,

(6) lim sup

ni→∞hf, Jrnixnii ≤ hf, pi.

By (5) and (6), we find that

nlimi→∞hf, Jrnixnii=hf, pi and in turn

Jrnixni* p.

Hence (4) together with Jrnixni * pand Trnixni 0 as ni → ∞ provides us with

hx−p, yi ≥0

for all x∈Eandy∈T x. SinceT is maximal therefore 0∈T p. Again in the same fashion, we can prove that 0 ∈T q. Next, we prove that p=q. To this end, if p and qare distinct then Opial’s condition yields

n→∞lim kxn−pk= lim

ni→∞kxni−pk

< lim

ni→∞kxni−qk

= lim

n→∞kxn−qk

= lim

nj→∞kxnj−qk

< lim

nj→∞kxnj−pk

= lim

n→∞kxn−pk,

confuting our supposition p6=q. This completes the proof. ¤ 4. Strong convergence of resolvents

First, in this section, we prove a strong convergence theorem by using complete continuity of the duality mapping. Complete continuity is defined as follows. LetX andY be two Banach spaces. A mappingS:X →Y is called completely continuous if it is continuous from the weak topology of X to the strong topology of Y, i.e.

xn* x⇒xn→x.

Now we prove our strong convergence theorem as follows.The method of proof is partially due to Kartsatos [8].

(5)

Theorem 2. Let E be a uniformly convex Banach space satisfying Opial’s condi- tion. Suppose that J is completely continuous. Letx0=x∈E and{xn} be defined as xn+1 =Jrnxn with

kxn−Jrnxnk ≤²n

for all n= 0,1,2, . . ., where{rn} ⊂(0,∞) such that rn → ∞ and{²n} ⊂ (0,∞) such that P

n=1²n <∞. If T−10 6=φ then {xn} converges strongly to a solution of 0∈T x.

Proof. xn* x0∈T−10 follows from Theorem 1. Thus, in view of uniform convex- ity ofE,it is sufficient to prove thatkxnk → kx0k to reach our goal. To this end, notice that

rnTrnxn=Jxn−JJrnxn∈rnT Jrnxn=rnT xn+1.

Thus for some yn ∈T xn+1, rnyn =Jxn−JJrnxn. Since yn T xn+1, 0 ∈T x0

and T is monotone therefore we have 0≤rnhyn0, xn+1−x0i

=hJxn−JJrnxn, xn+1−x0i

=hJxn−Jxn+1, xn+1−x0i

=h−Jxn+1, xn+1−x0i+hJxn, xn+1−x0i

=−hJxn+1−Jx0, xn+1−x0i+hJxn−Jx0, xn+1−x0i

=−(hJxn+1, xn+1i+hJx0, x0i − hJxn+1, x0i

− hJx0, xn+1i) +hJxn−Jx0, xn+1−x0i

≤ −(kxn+1k − kx0k)2+hJxn−Jx0, xn+1−x0i

=−(kxn+1k − kx0k)2+hJxn, xn+1−x0i − hJx0, xn+1−x0i.

That is,

(kxn+1k − kx0k)2≤ hJxn, xn+1−x0i − hJx0, xn+1−x0i.

Here we make use of complete continuity of J to assure that the right hand side of the above inequality vanishes so that

lim sup

n→∞ (kxn+1k − kx0k)20

which means thatkxnk → kx0kthereby showing that xn →x0 as desired. ¤ Next we prove our strong convergence theorem using Lipschitz continuity ofT−1. Lipschitz continuity is defined as follows.

An operator S−1: E E is said to be Lipschitz continuous at origin, with modulus a >0, if there is a unique solutionx0 to 0∈Sx(i.e. S−10 ={x0}), and for some τ >0, we have

kx−x0k ≤akykwheneverx∈S−1y andkyk ≤τ.

Note that this condition guarantees the uniqueness of the solution. This condition turns out to be very natural in applications to convex programming. For details, see [12, 13].

Theorem 3. Let E be a uniformly convex Banach space and let T−1 be Lipschitz continuous at origin with modulus a > 0. Suppose that x0 = x E and {xn} defined byxn+1=Jrnxn satisfies

(7) kxn−Jrnxnk ≤²n

for all n= 0,1,2, . . ., where{rn} ⊂(0,∞) such that rn → ∞ and{²n} ⊂ (0,∞) such that P

n=1²n <∞. If T−10 6= φ then {xn} converges strongly to a unique solution of 0∈T x.

(6)

Proof. Since T−1 is Lipschitz continuous at origin, so by definition, the inclusion 0 T x has a unique solution, say x0. As in Theorem 1, Trnxn 0. Choose a positive integern0 such that

kTrnxnk ≤τ for alln≥n0

where τ is same as in the definition of Lipschitz continuity. We also have from Proposition 1 that

Jrnxn ∈T−1(Trnxn), n= 0,1,2, . . . . Thus by Lipschitz continuity, we have

(8) kJrnxn−x0k ≤akTrnxnk, n= 0,1,2, . . . which enables us to write

kJrnxn−x0k →0.

Finally, using the triangle inequality

kxn−x0k ≤ kxn−Jrnxnk+kJrnxn−x0k, we obtain

kxn−x0k →0.

Eventually,{xn} converges strongly to a unique solution of 0∈T x. ¤ Following [13], we establish the solution of 0∈T xafter a finite number of steps.

ByInt(D) we mean the interior of a setD. In this connection we prove the following theorem.

Theorem 4. Let Ebe a uniformly convex Banach space. Suppose that there exists x0∈E such that0∈Int(T x0). Letx0=x∈E and{xn}defined by xn+1=Jrnxn

for all n = 0,1,2, . . . be bounded where {rn} ⊂ (0,∞) such that rn → ∞. Then there exists a positive integer n0 such thatxn=x0 for alln≥n0.

Proof. We first show thatT−1:E→E is single-valued and constant on a neigh- bourhood of 0. That is, we prove that

(9) T−1y=x0 if kyk< ².

Let ² >0 be chosen so that kyk < ²impliesy ∈Int(T x0). Taking anyx, y ∈T x, and y0 withky0k< ², we have by monotonicity ofT that

hx−x0, y−y0i ≥0.

This yields

hx−x0, y0i ≤ hx−x0, yi.

So that

sup

ky0k<²

hx−x0, y0i ≤ hx−x0, yi whenever y∈T x implies

²kx−x0k ≤ kx−x0kkyk whenever y∈T x and hence if x6=x0,

²≤ kyk whenever y∈T x.

This means that if kyk < ² and x T−1y then x = x0. Virtually, T−1:E E is single-valued and constant on a neighbourhood of 0. Next we know from Proposition 1 that

Jrnxn ∈T−1(Trnxn), n= 0,1,2, . . . .

(7)

Thus, as in Theorem 1, Trnxn 0 so that for all ² > 0 there exists a positive integer n0 such that kTrnxnk < ²for all n ≥n0. Using (9) with y =Trnxn, we obtain

x0=T−1(Trnxn) or

x0 =Jrnxn

Hence xn =x0 for alln≥n0as desired. ¤

References

[1] V. Barbu and T. Precupanu. Convexity and optimization in Banach spaces. Editura Academiei, Bucharest, revised edition, 1978. Translated from the Romanian.

[2] H. Brezis, M. G. Crandall, and A. Pazy. Perturbations of nonlinear maximal monotone sets in Banach space.Comm. Pure Appl. Math., 23:123–144, 1970.

[3] H. Br´ezis and P.-L. Lions. Produits infinis de r´esolvantes.Israel J. Math., 29(4):329–345, 1978.

[4] F. E. Browder. Nonlinear mappings of nonexpansive and accretive type in Banach spaces.

Bull. Amer. Math. Soc., 73:875–882, 1967.

[5] R. E. Bruck and G. B. Passty. Almost convergence of the infinite product of resolvents in Banach spaces.Nonlinear Anal., 3(2):279–282, 1979.

[6] R. E. Bruck and S. Reich. Nonexpansive projections and resolvents of accretive operators in Banach spaces.Houston J. Math., 3(4):459–470, 1977.

[7] J. S. Jung and W. Takahashi. Dual convergence theorems for the infinite products of resolvents in Banach spaces.Kodai Math. J., 14(3):358–365, 1991.

[8] A. G. Kartsatos. On the connection between the existence of zeros and the asymptotic be- havior of resolvents of maximal monotone operators in reflexive Banach spaces.Trans. Amer.

Math. Soc., 350(10):3967–3987, 1998.

[9] P.-L. Lions. Une m´ethode it´erative de r´esolution d’une in´equation variationnelle.Israel J.

Math., 31(2):204–208, 1978.

[10] Z. Opial. Weak convergence of the sequence of successive approximations for nonexpansive mappings.Bull. Amer. Math. Soc., 73:591–597, 1967.

[11] A. Pazy. Remarks on nonlinear ergodic theory in Hilbert space.Nonlinear Anal., 3(6):863–

871, 1979.

[12] R. T. Rockafellar. Augmented Lagrangians and applications of the proximal point algorithm in convex programming.Math. Oper. Res., 1(2):97–116, 1976.

[13] R. T. Rockafellar. Monotone operators and the proximal point algorithm.SIAM J. Control Optimization, 14(5):877–898, 1976.

Received December 04, 2003.

Faculty of Engineering Sciences,

GIK Institute of Engineering Sciences & Technology, Topi, Swabi, N-W.F.P.,

Pakistan

E-mail address: [email protected]

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