From the elliptic regulator to exotic relations
Nouressadat TOUAFEK
Abstract
In this paper we prove an identity between the elliptic regulators of some 2-isogenous elliptic curves. This allow us to prove a new exotic relation for the elliptic curve 20A of Cremona’s tables. Also we prove the (conjectured) exotic relation for the curve 20B given by Bloch and Grayson in [3].
1 Introduction
For some elliptic curves, the elliptic dilogarithm satisfies linear relations, called exotic by Bloch and Grayson [3].
In [3] a list of elliptic curves that satisfies exotic relations is given. Recently some of these relations are proved by Bertin [1], Touafek [7].
We note that whenever we can find a tempered model of the elliptic curve, the existence of exotic relations is related to elements in the second group of the K-theory K2(E) hence to elliptic regulators, so we can prove the exotic relations.
Bloch and Grayson conjectured the following fact.
Conjecture 1 Suppose that E(Q)tors is cyclic and d = #E(Q)tors > 2.
Write Σ for the number of fibres of type Iν with ν ≥3 in the N´eron model, and supposed−1
2
−Σ>1. Then there should be at leastd−1
2
−Σ−1exotic relations
[d−12 ]
r=1
arDE(rP) = 0,
Key Words: Elliptic curves, Elliptic dilogarithm, Elliptic regulator, Exotic relations.
Mathematics Subject Classification: 11G05, 14G05, 14H52.
Received: April, 2008 Accepted: September, 2008
117
where P is ad-torsion point and ar∈Z.
In particular, these conditions are satisfied for the curve 20Aof Cremona’s tables [4]: E(Q)tors cyclic,d= 6 and Σ = 0.
In section 3 we use an identity between regulators and some equalities between the elliptic dilogarithm to prove a new exotic relation for the elliptic curve 20A and also we prove the (conjectured) exotic relation for the curve 20B of Cremona’s tables given by Bloch and Grayson in [3].
2 Preliminaries
LetE be an elliptic curve defined overQ.
Throughout this paper, the notationE= [a1, a2, a3, a4, a6] means that the elliptic curveE is in the Weierstrass form
y2+a1xy+a3y=x3+a2x2+a4x+a6. 2.1 The elliptic regulator
Let F be a field. By Matsumoto’s theorem, the second group of K-theory K2(F) can be described in terms of symbols{f, g}, forf, g∈F∗and relations between them.
The relations are
⎧⎨
⎩
{f1f2, g} ={f1, g}+{f2, g}
{f, g1g2} ={f, g1}+{f, g2} {1−f, f} = 0.
For example, if v is a discrete valuation on F with maximal ideal M and residual fieldk, the Tate’s tame symbol
(x, y)ν≡(−1)ν(x)ν(y)xν(y)
yν(x) modM defines a homomorphism
λv:K2(F)−→k∗.
Let Q(E) be the rational function field of the elliptic curve E. To any P ∈ E(Q) is associated a valuation on Q(E) that gives the homomorphism
λP :K2(Q(E))−→Q(P)∗
and the exact sequence
0→K2(E)⊗Q→K2(Q(E))⊗Q→
P∈E(Q)
Q(P)∗⊗Q→...
By definitionK2(E) is defined modulo torsion by K2(E)kerλ= ∩
PkerλP ⊂K2(Q(E)) where
λ:K2(Q(E))⊗Q−→
P∈E(Q)
(Q(P)∗⊗Q).
Definition 1 A polynomial in two variables is tempered if the polynomial of the faces of its Newton polygon has only roots of unity.
When drawing the convex hull of points (i, j) ∈ Z2 corresponding to the monomialsai,jxiyj, ai,j = 0, you also draw points located on the faces. The polynomial of the face is a polynomial in one variabletwhich is a combination of the monomials 1,t,t2,.... The coefficients of the combination are given when going along the face, that isai,j if the lattice point of the face belongs to the convex hull and 0 otherwise.
In particular, the polynomials
P1(X1, Y1) =Y12+ 2X1Y1−X13+X1 and
P2(X2, Y2) =Y22+ 2X2Y2+ 2Y2−(X2−1)3
are tempered, so we get {X1, Y1} ∈ K2(E1) and {X2, Y2} ∈ K2(E2), see Rodriguez-Villegas [5]. HereE1is the elliptic curve defined byP1(X1, Y1) = 0 andE2 the elliptic curve defined byP2(X2, Y2) = 0.
Letf and gbe inQ(E)∗. Let us define
η(f, g) = log|f|d(argg)−log|g|d(argf).
Definition 2 The elliptic regulatorrof E is given by r: K2(E)−→ R
{f, g} −→ 2π1
γη(f, g)
for a suitable loop γ generating the subgroup H1(E,Z)− of H1(E,Z), where the complex conjugation acts by−1.
2.2 The elliptic dilogarithm We have two representations forE(C)
E(C)−→∼ C/(Z+τZ) −→∼ C∗ qZ (℘(u), ℘´(u))−→ u( mod Λ)−→ z=e2πiu
where ℘is the Weierstrass function, Λ = {1, τ} the lattice associated to the elliptic curve andq=e2πiτ.
Definition 3 The elliptic dilogarithm DE [2] is defined by
DE(P) =
n=+∞
n=−∞
D(qnz),
where P ∈E(C) is the image of z∈C∗,z =e2πiu, u=ξτ+η and D is the Bloch-Wigner dilogarithm
D(x) :=Li2(x) + log|x|arg(1−x).
Remark 1 1. The Bloch-Wigner dilogarithm is a function univalued, real analytic in P1(C)\{0,1,∞}, continuous in P1(C)[9].
2. There is a second representation of the elliptic dilogarithm given by Bloch [2], [10] in terms of Eisenstein-Kronecker series
DE(P) =(τ)2
π (
m,n∈Z (m,n)=(0,0)
exp( 2πi(nξ−mη)) (mτ+n)2(m−τ+n)
). (1)
3. The elliptic dilogarithm can be extended to divisors onE(C) DE((f)) =
i
niDE(Pi), where
(f) =
i
ni[Pi].
2.3 The diamond operation
LetZ[E(C)]− be the subgroup ofZ[E(C)] modulo the equivalence relation cl([−P]) =−cl([P]).
Definition 4 The diamond operation is defined by
♦ : Z[E(C)]× Z[E(C)] −→ Z[E(C)]−
((f),(g)) −→
i,jnimjcl([Pi−Pj]) where
(f) =
i
ni[Pi] and(g) =
j
mj[Pj].
The following theorem [2], establishes the relation between the elliptic regula- tor and the elliptic dilogarithm.
Theorem 1 The elliptic dilogarithm DE can be extended to a morphism Z[E(C)]−−→R.
If f, g are functions on E and{f, g} ∈K2(E), then πr({f, g}) =DE((f)♦(g));
in particular
DE((f)♦(1−f)) = 0.
3 An identity between regulators
LetE1 be the elliptic curve, isomorphic to the curve 20A,with equation Y12+ 2X1Y1=X13−X1
and letE2 be the elliptic curve, isomorphic to the curve 20B, with equation Y22+ 2X2Y2+ 2Y2= (X2−1)3.
Proposition 1 We have
πr({X1, Y1}) = −4DE1(P1)−4DE1(2P1) πr({X2, Y2}) = 6DE2(P2) + 6DE2(2P2)
where P1= (−1,2)is the 6-torsion point of the curve E1= [2,0,0,−1,0]and P2= (5,4)is the 6-torsion point of the curveE2= [2,−3,2,3,−1].
Proof. We need to compute the following divisors (X1) = 2 [3P1]−2 [O1]
(Y1) = [3P1] + [4P1] + [5P1]−3 [O1] (X2) = 2 [3P2]−2 [O2] (Y2) = 3 [2P2]−3 [O2]
hence
(X1)♦(Y1) =−4cl([P1])−4cl([2P1]) and
(X2)♦(Y2) = 6cl([P2]) + 6cl([2P2]) so, by theorem 1 we get
πr({X1, Y1}) =−4DE1(P1)−4DE1(2P1) and
πr({X2, Y2}) = 6DE2(P2) + 6DE2(2P2).
Remark 2 Using the previous proposition and formula (1), we have find by the computer,
r({X2, Y2})=? r({X1, Y1}),
where the notationA=? B, means ” A is conjectured to be equal to B ”, that is A and B are numerically equal to at least 25 decimal places.
Theorem 2 We have the following identity
r({X2, Y2}) =r({X1, Y1}).
Proof. Let Ξ1= 20Abe the elliptic curve with equation S12=T13+T12−T1
and Ξ2 be the elliptic curve, isomorphic to 20B, with equation S22=T23−2T22+ 5T2.
It is easy to check that
T1=X1, S1=Y1+X1 (2) and
T2=X2, S2=Y2+X2+ 1 (3) give isomorphisms
Ξ1E1, Ξ2E2. Also we have the 2-isogeny [6] given by
Φ : Ξ1 −→Ξ2 (T1, S1) −→
S12
T12,−S1(TT122+1) 1
. (4)
Using (2), (3) and (4) we can see Φ as
Φ : E1 −→E2
(X1, Y1) −→(XΦ, YΦ) = ((Y1+XX21)2
1 ,−(Y1+X1+1)(YX21+X12+X1)
1 ).
The elliptic curveE1 can be considered as a double cover ofP1 by πX1 :E1−→P1
ramified at the zeros ofX13+X12−X1,i.e. 0,−1+2√5,−1−2√5.The closed curve σ1=π−1X1([0,−1+2√5]) generatesH1(E1,Z)−.
The elliptic curveE2 can be considered as a double cover ofP1 by πX2 :E2−→P1
ramified at the zeros ofX23−2X22+ 5X2,i.e. 0,1 + 2i,1−2i.The closed curve σ2=π−1X2([1−2i,1 + 2i]) generatesH1(E2,Z)−.
Using the 2-isogeny we get
2P1, 5P1 −→Φ 2P2 P, Q −→Φ 3P2 P1, 4P1 −→Φ 4P2 3P1, O1 −→Φ O2 where
P = (−ϕ, ϕ), Q= (−1 ϕ,1
ϕ), Q=P+ 3P1, ϕ= 1 +√ 5 2 .
Also, when (X2, Y2) describesσ2, (XΦ, YΦ) describes twice the closed curve σ={(X1, Y1)∈E1(C)/|X1|= 1},
which generatesH1(E1,Z)−, because it’s in the same homology class asσ1. Hence,
r({X2, Y2}) =±1 2r
XΦ, YΦ
. (5)
We have
(1 +X1+Y1) = [2P1] + 2 [5P1]−3 [O1] (X1+Y1) = [3P1] + [P] + [Q]−3 [O1] (Y1+X1+X12) = [3P1] + [5P1] + 2[2P1]−4 [O1].
Performing the necessary computation, we obtain
(XΦ)♦(YΦ) = −12cl([P1]) + 12cl([2P1]) + 12cl([P−2P1]) + 12cl([P−2Q]) +12cl([Q−2P1]) + 12cl([Q−2P])
and
(1 +X1+Y1)♦(X1+Y1) = 5cl([P1])−cl([2P1])−3cl([P−2P1])−3cl([P−2Q])
−3cl([Q−2P1])−3cl([Q−2P]).
Using the fact that
DE((1 +X1+Y1)♦(X1+Y1)) = 0 we get
DE1(XΦ♦YΦ) = 8DE1(P1) + 8DE1(2P1) so by Theorem 1 and Proposition 1
r
XΦ, YΦ
=−2r({X1, Y1}). (6) By (5), (6) and remark 2 we get
r({X2, Y2}) =r({X1, Y1}).
LetE1,E2 be as above. We have the following theorem [8].
Theorem 3 We have the following equalities
1) DE1(P1) =−2DE2(P2) + 3DE2(2P2) 2) DE1(2P1) =−2DE2(P2) + 2DE2(2P2).
Proof. The proof follow the same way of the proof of Theorem 3.2 in [7]
Now, we are able to give a new exotic relation for the curve 20A.
Corollary 1 We have the linear relation
16DE1(P1)−11DE1(2P1) = 0.
Proof. It results from Proposition 1 and Theorem 2 that
−4DE1(P1)−4DE1(2P1) = 6DE2(P2) + 6DE2(2P2);
so by theorem 3, we get
16DE1(P1)−11DE1(2P1) = 0.
Remark 3 1. In turn, by Theorem 3, the relation 16DE1(P1)−11DE1(2P1) = 0 becomes
5DE2(P2)−13DE2(2P2) = 0.
This achieves the proof of the (conjectured) exotic relation for the curve 20B given by Bloch and Grayson in [3].
2. In [3] only elliptic curves with negative discriminant are considered, so our new exotic relation does not appear in the list of Bloch and Grayson because the curve20A have a positive discriminant.
References
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[8] N. Touafek, Th`ese de Doctorat, Universit´e de Constantine, Algeria, 2008.
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Laboratoire de Physique Th´eorique Equipe de Th´eorie des Nombres Universit´e de Jijel, Algeria [email protected]