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1.Introduction RenatoColucciandGerardoR.Chacón HyperbolicRelaxationofaFourthOrderEvolutionEquation ResearchArticle

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Volume 2013, Article ID 372726,11pages http://dx.doi.org/10.1155/2013/372726

Research Article

Hyperbolic Relaxation of a Fourth Order Evolution Equation

Renato Colucci and Gerardo R. Chacón

Departamento de Matem´aticas, Pontificia Universidad Javeriana, Cra. 7 No. 43-82, Bogot´a, Colombia

Correspondence should be addressed to Renato Colucci; [email protected] Received 26 November 2012; Revised 30 January 2013; Accepted 3 February 2013 Academic Editor: Juan J. Nieto

Copyright © 2013 R. Colucci and G. R. Chac´on. This is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited.

We propose a hyperbolic relaxation of a fourth order evolution equation, with an inertial term𝜂𝑢𝑡𝑡, where𝜂 ∈ (0, 1]. We prove the existence of several absorbing sets having different regularities and the existence of a global attractor that is bounded in𝐻4(𝐼) × {𝐻2(𝐼) ∩ 𝐻01(𝐼)}.

1. Introduction

Leting𝐼 ⊂Rbe an open interval, with|𝐼| ≤ 1, we consider the following initial-boundary value problem for𝑢 : 𝐼 ×R+ → R:

𝜂𝑢𝑡𝑡+ 𝑢𝑡= − 𝜀2𝑢𝑥𝑥𝑥𝑥 +1

2𝑊󸀠󸀠(𝑢𝑥) 𝑢𝑥𝑥, (𝑥, 𝑡) ∈ 𝐼 ×R+, 𝑢 (𝑥, 0) = 𝑢0(𝑥) , in 𝐼,

𝑢𝑡(𝑥, 0) = 𝑢1(𝑥) , in 𝐼, 𝑢 = 𝑢𝑥𝑥= 0, in 𝜕𝐼, 𝑡 ≥ 0,

(1)

where the function𝑊(𝑝) = (𝑝2− 1)2is the so-called double- well potential, 0 < 𝜀 ≪ 1 and 𝜂 ∈ (0, 1] are positive parameters.

Problem (1), with𝜂 = 0, was proposed in [1] where the global dynamics was studied. In particular, the dynamical behavior of the solutions for small values of the parameter 𝜀 was studied by means of numerical experiments. The existence of three well-differentiated time scales with peculiar dynamical behavior was showen. In the first time scale of order𝑂(𝜀2)there is the formation of microstructure (see [2]) in the region where the gradient of the initial datum falls in the nonconvex region of𝑊; this phenomenon produces a drastic reduction of the energy of the initial datum. In the second time scale of order𝑂(1)the equation exhibits a heat equation-like behavior in the convex regions while slow

motion in the nonconvex ones. In the last time scale of order 𝑂(𝜀−2)the equation shows a finite-dimensional behavior: the solution is approximately the union of consecutive segments and the dynamic is slow.

In [3], the third time scale was studied; the authors proved the existence of a global attractor A𝜀 ⊂ 𝐿2(𝐼) (see [4]) that is bounded in𝐻2(𝐼). The time for which the solutions enter the absorbing set B𝜀 is of order 𝑂(𝜀−2) and it is consistent with the estimates found in [1]. Moreover the authors proved the existence of an exponential attractorI𝜀 with finite fractal dimension of order 𝑂(𝜀−10). In [5] the authors proved the existence of an inertial manifoldM𝜀(see [6]) whose dimension is of order 𝑂(𝜀−19), and by the 𝑛- dimensional volume elements methods (see [7]) an estimate of the dimension of the global attractor of order𝑂(𝜀−1)was found. This estimate is also consistent with the numerical experiments developed in [1]; in fact it was found that the wave length of the microstructure is of order𝑂(𝜀−1).

In the last years the viscous and no viscous hyperbolic relaxation of the Cahn-Hilliard equation has been extensively investigated. The model was proposed in [8] while in [9] the existence of a family of exponential attractors was proved.

The viscous and nonviscous perturbation has been studied in [10] where the existence of a family of global attractors that are upper semicontinuous with respect to the vanishing of perturbations parameters was proved. These results have been extended in 2 and 3 dimensions; see for example [11,12] and the references therein.

Due to the similarity of problem (1) to the Cahn-Hilliard equation we consider it interesting to study the hyperbolic

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relaxation of the fourth order evolution equation proposed in [1]. In particular ifVis the solution of the Cahn-Hilliard equation

V𝑡+ Δ [𝜀2ΔV− 𝑊󸀠(V)] = 0, (2) with Neumann boundary conditions:

𝜕

𝜕𝑛V= 𝜕

𝜕𝑛ΔV= 0, 𝑥 ∈ {0, 1} , (3)

then

𝑢 (𝑥) = ∫𝑥

0 V(𝑠) 𝑑𝑠, (4)

is the solution of (1), with𝜂 = 0, with the corresponding boundary conditions:

𝑢 = 𝑢𝑥𝑥= 0, 𝑥 ∈ {0, 1} . (5)

In the present work we put the problem in the correct mathematical framework and prove the existence of a global attractorA𝜂,𝜀while we have left the proof of the existence of exponential attractors for a forthcoming paper. In Sections 2and3we define the solution semigroup in the appropriate spaces and present some important energy estimates. In Section 4we prove the existence of several absorbing sets with different regularities while in the last section we prove the existence of the global attractor.

2. Preliminaries

We begin this section by defining the following Hilbert spaces that will be helpful for our analysis:

H𝜂,𝜀= [𝐻2(𝐼) ∩ 𝐻01(𝐼)] × 𝐿2(𝐼) , (6)

V𝜂,𝜀= 𝐷 (𝐴) × 𝐻2(𝐼) , (7)

where

𝐷 (𝐴) = { 𝑢 ∈ 𝐻4(𝐼) : 𝑢 = 𝑢𝑥𝑥= 0 in 𝜕𝐼} (8) is the domain of the differential operator𝐴 = 𝜕4/𝜕𝑥4. The above spaces are equipped with the norms

‖(𝑢,V)‖2H𝜂,𝜀= 𝜀2

2󵄩󵄩󵄩󵄩𝑢𝑥𝑥󵄩󵄩󵄩󵄩2+𝜂

2‖V‖2, (9)

‖(𝑢,V)‖2V𝜂,𝜀= 𝜀2

2󵄩󵄩󵄩󵄩𝑢x𝑥𝑥𝑥󵄩󵄩󵄩󵄩2+𝜂

2󵄩󵄩󵄩󵄩V𝑥𝑥󵄩󵄩󵄩󵄩2, (10) where‖ ⋅ ‖represents the𝐿2norm. We will denote by⟨⋅, ⋅⟩the inner product in𝐿2(𝐼). We recall that for all𝑢 ∈ 𝐻2(𝐼)∩𝐻01(𝐼) with|𝐼| ≤ 1, we have

‖𝑢‖ ≤ 󵄩󵄩󵄩󵄩𝑢𝑥󵄩󵄩󵄩󵄩 ≤ 󵄩󵄩󵄩󵄩𝑢𝑥𝑥󵄩󵄩󵄩󵄩. (11) Throughout the paper we will use two norms that are equiv- alent to (9) and (10) in order to simplify the computation.

Given functions𝑢 ∈ 𝐻2(𝐼) ∩ 𝐻10(𝐼)andV∈ 𝐿2(𝐼)we define the functioñ𝐸onH𝜂,𝜀by

̃𝐸 (𝑢,V) = 𝜂‖V‖2+1

2𝜀2󵄩󵄩󵄩󵄩𝑢𝑥𝑥󵄩󵄩󵄩󵄩2+ 𝛽𝜂⟨V, 𝑢⟩, (12) where𝛽 ∈ [0, 𝜀2].

Proposition 1. For all𝛽 ∈ [0, 𝜀2]the functioñ𝐸(⋅, ⋅)induces a norm equivalent to the norm onH𝜂,𝜀.

Proof. By Schwartz inequality (11) and using the fact that𝛽 ≤ 𝜀2< 1,𝜂 ∈ (0, 1], we get

𝛽𝜂 ⟨V, 𝑢⟩ ≤ 𝛽𝜂 ‖V‖‖𝑢‖ ≤ 1

2𝜂2‖V‖2+1

2𝜀4󵄩󵄩󵄩󵄩𝑢𝑥𝑥󵄩󵄩󵄩󵄩2

≤ 𝜂

2‖V‖2+𝜀2

2󵄩󵄩󵄩󵄩𝑢𝑥𝑥󵄩󵄩󵄩󵄩2= ‖(𝑢,V)‖2H𝜀,𝜂.

(13)

From the previous inequality and by definition of̃𝐸(𝑢,V)we get

̃𝐸 (𝑢,V) ≤ 3‖(𝑢,V)‖2H𝜀,𝜂. (14) By a different application of Schwartz inequality and from (11) we get

𝛽𝜂 ⟨V, 𝑢⟩ ≤ 𝛽𝜂 ‖V‖ ‖𝑢‖ ≤ 𝜂2‖V‖2+𝛽2 4 ‖𝑢‖2

≤ 𝜂‖V‖2+𝜀4

4‖𝑢‖2≤ 𝜂‖V‖2+𝜀2 4󵄩󵄩󵄩󵄩𝑢𝑥𝑥󵄩󵄩󵄩󵄩2.

(15)

Combining (13) and (15) we get

̃𝐸 (𝑢,V) ≥max{𝜂 2‖V‖2,1

4𝜀2󵄩󵄩󵄩󵄩𝑢𝑥𝑥󵄩󵄩󵄩󵄩2} , (16) and as a consequence

̃𝐸 (𝑢,V) ≥ 1

3‖(𝑢,V)‖2H𝜀,𝜂. (17)

The proof of the following theorem follows from classical applications of the Faedo-Galerkin method. We will only show a Lipschitz estimate that will be needed for further computations.

Theorem 2. For every(𝑢0, 𝑢1) ∈ H𝜀,𝜂there exists a unique solution𝑢(𝑡)for the initial value problem(1)such that

𝑢 ∈ 𝐶𝑏(R+; 𝐻2(𝐼) ∩ 𝐻01(𝐼)) ∩ 𝐶1𝑏(R+; 𝐿2(𝐼)) . (18) If, moreover,(𝑢0, 𝑢1) ∈V𝜀,𝜂, then:

𝑢 ∈ 𝐶𝑏(R+; 𝐷 (𝐴)) ∩ 𝐶1𝑏(R+; 𝐻2(𝐼) ∩ 𝐻01(𝐼))

∩ 𝐶2𝑏(R+; 𝐿2(𝐼)) . (19)

(3)

Proposition 3. For any constant𝑅 ≥ 0there exists a positive constant𝐾 = 𝐾(𝑅)such that, for any initial data𝑢1(0),𝑢2(0) with‖𝑢𝑖(0)‖𝐻𝜂,𝜀 ≤ 𝑅,𝑖 = 1, 2one has

󵄩󵄩󵄩󵄩󵄩𝑆𝜀,𝜂(𝑡)𝑢1(0) − 𝑆𝜀,𝜂(𝑡)𝑢2(0)󵄩󵄩󵄩󵄩󵄩𝐻𝜂,𝜀 ≤ 𝑒(𝐾2/𝜀2)𝑡󵄩󵄩󵄩󵄩𝑢1(0) − 𝑢2(0)󵄩󵄩󵄩󵄩𝐻𝜂,𝜀, (20) where𝑆𝜀,𝜂(𝑡)is the solution semigroup of the problem(1).

Proof. Let𝑢1,𝑢2, two solutions of (1) with initial data𝑢1(0) and𝑢2(0). Let,𝑤 = 𝑢1− 𝑢2then we write

𝜂𝑤𝑡𝑡+ 𝑤𝑡+ 𝜀2𝑤𝑥𝑥𝑥𝑥=1 2

𝑑

𝑑𝑥{𝑊󸀠(𝑢1𝑥) − 𝑊󸀠(𝑢2𝑥)} . (21) We multiply the above equation by𝑤𝑡in𝐿2(𝐼); then

𝜂 2

𝑑

𝑑𝑡󵄩󵄩󵄩󵄩𝑤𝑡󵄩󵄩󵄩󵄩2+𝜀2 2

𝑑

𝑑𝑡󵄩󵄩󵄩󵄩𝑤𝑥𝑥󵄩󵄩󵄩󵄩2+ 󵄩󵄩󵄩󵄩𝑤𝑡󵄩󵄩󵄩󵄩2

= −2 ∫

𝐼𝑤𝑥𝑥𝑤𝑡𝑑𝑥 + 6 ∫

𝐼{𝑢21𝑥𝑤𝑥𝑥+ 𝑢2𝑥x𝑤𝑥[𝑢1𝑥+ 𝑢2𝑥]} 𝑤𝑡𝑑𝑥

≤ 2 󵄩󵄩󵄩󵄩𝑤𝑥𝑥󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩𝑤𝑡󵄩󵄩󵄩󵄩 + 6󵄩󵄩󵄩󵄩𝑢1𝑥󵄩󵄩󵄩󵄩2󵄩󵄩󵄩󵄩𝑤𝑥𝑥󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩𝑤𝑡󵄩󵄩󵄩󵄩

+ 12 󵄩󵄩󵄩󵄩𝑢2𝑥𝑥󵄩󵄩󵄩󵄩(∫𝐼𝑤2𝑥𝑤2𝑡[𝑢21𝑥+ 𝑢22𝑥] 𝑑𝑥)1/2

≤ 2 {1 + 18𝐶2󵄩󵄩󵄩󵄩𝑢1𝑥𝑥󵄩󵄩󵄩󵄩2+ 12 󵄩󵄩󵄩󵄩𝑢2𝑥𝑥󵄩󵄩󵄩󵄩

×(󵄩󵄩󵄩󵄩𝑢1𝑥𝑥󵄩󵄩󵄩󵄩2+ 󵄩󵄩󵄩󵄩𝑢2𝑥𝑥󵄩󵄩󵄩󵄩2)1/2} 󵄩󵄩󵄩󵄩𝑤𝑥𝑥󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩𝑤𝑡󵄩󵄩󵄩󵄩

≤ 2 {1 + (36𝐶2+ 24√2)𝑅2

𝜀2} 󵄩󵄩󵄩󵄩𝑤𝑥𝑥󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩𝑤𝑡󵄩󵄩󵄩󵄩

≤ 2𝐾 󵄩󵄩󵄩󵄩𝑤𝑥𝑥󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩𝑤𝑡󵄩󵄩󵄩󵄩 ≤ 𝐾2󵄩󵄩󵄩󵄩𝑤𝑥𝑥󵄩󵄩󵄩󵄩2+ 󵄩󵄩󵄩󵄩𝑤𝑡󵄩󵄩󵄩󵄩2,

(22)

where we have used the following inequality (see [13] and inequality (11)):

󵄩󵄩󵄩󵄩𝑢𝑥󵄩󵄩󵄩󵄩2≤ 𝐶2󵄩󵄩󵄩󵄩𝑢𝑥󵄩󵄩󵄩󵄩2𝐻1(𝐼)≤ 2𝐶2󵄩󵄩󵄩󵄩𝑢𝑥𝑥󵄩󵄩󵄩󵄩2. (23) The constant𝐾 can be explicitly computed using the esti- mates of the absorbing set presented in the next section.

From the last inequality we get 𝑑

𝑑𝑡󵄩󵄩󵄩󵄩(𝑤,𝑤𝑡)󵄩󵄩󵄩󵄩2H𝜀,𝜂 ≤2𝐾2

𝜀2 󵄩󵄩󵄩󵄩(𝑤,𝑤𝑡)󵄩󵄩󵄩󵄩2H𝜀,𝜂, (24) and then using Gronwall’s lemma we get

󵄩󵄩󵄩󵄩(𝑤,𝑤𝑡)󵄩󵄩󵄩󵄩H𝜀,𝜂 ≤ 𝑒(𝐾2/𝜀2)𝑡󵄩󵄩󵄩󵄩(𝑤(0),𝑤𝑡(0))󵄩󵄩󵄩󵄩H𝜀,𝜂. (25)

3. A Priori Estimates

In this section we provide useful a priori estimates of energy type. Equation (1) admits a Liapunov functional of the form:

𝐸 (𝑢, 𝑢𝑡) = 𝜂󵄩󵄩󵄩󵄩𝑢𝑡󵄩󵄩󵄩󵄩2+1

2𝜀2󵄩󵄩󵄩󵄩𝑢𝑥𝑥󵄩󵄩󵄩󵄩2+1 2∫

𝐼𝑊 (𝑢𝑥) 𝑑𝑥, (26) that is not increasing along the solutions; in fact if we multiply (1) by𝑢𝑡and integrate over𝐼we obtain

𝑑

𝑑𝑡𝐸 (𝑢, 𝑢𝑡) = −󵄩󵄩󵄩󵄩𝑢𝑡󵄩󵄩󵄩󵄩2. (27) Moreover, integrating the previous inequality on(0, 𝑡)with respect to time we get

𝑡

0󵄩󵄩󵄩󵄩𝑢𝑡󵄩󵄩󵄩󵄩2𝑑𝑠 + 𝐸 (𝑢, 𝑢𝑡) = 𝐸 (𝑢0, 𝑢1) . (28) Then for any fixed initial data(𝑢0, 𝑢1) ∈H𝜀,𝜂we have that the corresponding solution satisfies

sup𝑡≥0{𝜂

2󵄩󵄩󵄩󵄩𝑢𝑡󵄩󵄩󵄩󵄩2+𝜀2

2󵄩󵄩󵄩󵄩𝑢𝑥𝑥󵄩󵄩󵄩󵄩2} =sup

𝑡≥0󵄩󵄩󵄩󵄩(𝑢,𝑢𝑡)󵄩󵄩󵄩󵄩2H𝜀,𝜂

≤ 𝐸 (𝑢0, 𝑢1) .

(29)

Moreover if we integrate overR+we get the integral control

0 󵄩󵄩󵄩󵄩𝑢𝑡󵄩󵄩󵄩󵄩2𝑑𝑡 ≤ 𝐸 (𝑢0, 𝑢1) . (30) We consider an important estimate that will be useful later.

Let𝛽 > 0be a parameter to be determined later; if we multiply (1) by𝛽𝑢we obtain

𝛽𝜂 ∫𝐼𝑢𝑡𝑡𝑢𝑑𝑥 +𝛽 2

𝑑

𝑑𝑡‖𝑢‖2+ 𝛽𝜀2󵄩󵄩󵄩󵄩𝑢𝑥𝑥󵄩󵄩󵄩󵄩2 + 2𝛽󵄩󵄩󵄩󵄩𝑢𝑥󵄩󵄩󵄩󵄩44= 2𝛽󵄩󵄩󵄩󵄩𝑢𝑥󵄩󵄩󵄩󵄩2.

(31)

By summing (27) and (31) we get 𝑑

𝑑𝑡𝐸 + 𝛽𝜂𝑑

𝑑𝑡⟨𝑢𝑡, 𝑢⟩ + (1 − 𝛽𝜂) 󵄩󵄩󵄩󵄩𝑢𝑡󵄩󵄩󵄩󵄩2 +𝛽

2 𝑑

𝑑𝑡‖𝑢‖2+ 𝛽𝜀2󵄩󵄩󵄩󵄩𝑢𝑥𝑥󵄩󵄩󵄩󵄩2+ 2𝛽󵄩󵄩󵄩󵄩𝑢𝑥󵄩󵄩󵄩󵄩44

= 2𝛽󵄩󵄩󵄩󵄩𝑢𝑥󵄩󵄩󵄩󵄩2.

(32)

Using the expression of the energy we can rewrite the previous in the following way:

𝑑

𝑑𝑡𝐸 + 𝛽𝜂𝑑

𝑑𝑡⟨𝑢𝑡, 𝑢⟩ + (1 − 3𝛽𝜂) 󵄩󵄩󵄩󵄩𝑢𝑡󵄩󵄩󵄩󵄩2 + 𝛽⟨𝑢𝑡, 𝑢⟩ + 2𝛽 (𝐸 +󵄩󵄩󵄩󵄩𝑢𝑥󵄩󵄩󵄩󵄩44

2 − |𝐼|

2) = 0.

(33)

We will estimate some of the terms of the previous inequality in the following lemma.

(4)

Lemma 4. Fix𝜂 ≤ 1then for all𝛽 ∈ (0, 1/3)one has 2𝛽2𝜂⟨𝑢𝑡, 𝑢⟩ ≤ (1 − 3𝛽𝜂) 󵄩󵄩󵄩󵄩𝑢𝑡󵄩󵄩󵄩󵄩2+ 𝛽󵄩󵄩󵄩󵄩𝑢𝑥󵄩󵄩󵄩󵄩44+ 𝛽 |𝐼| + 𝛽⟨u𝑡, 𝑢⟩.

(34) Proof. By Holder’s inequality we get

2󵄩󵄩󵄩󵄩𝑢𝑥󵄩󵄩󵄩󵄩2≤ 2󵄩󵄩󵄩󵄩𝑢𝑥󵄩󵄩󵄩󵄩24 |𝐼|1/2≤ 󵄩󵄩󵄩󵄩𝑢𝑥󵄩󵄩󵄩󵄩44+ |𝐼| , (35) then we use Poincar´e’s inequality and the fact that|𝐼| ≤ 1to conclude that

‖𝑢‖2≤ 󵄩󵄩󵄩󵄩𝑢𝑥󵄩󵄩󵄩󵄩44

2 + |𝐼|

2 . (36)

Therefore, for a positive constant𝑐1to be determined later, we have that

⟨𝑢𝑡, 𝑢⟩ ≤ 󵄩󵄩󵄩󵄩𝑢𝑡󵄩󵄩󵄩󵄩‖𝑢‖ ≤ 𝑐21󵄩󵄩󵄩󵄩𝑢𝑡󵄩󵄩󵄩󵄩2+ 1 2𝑐1‖𝑢‖2

≤ 𝑐1

2󵄩󵄩󵄩󵄩𝑢𝑡󵄩󵄩󵄩󵄩2+ 1

2𝑐1(󵄩󵄩󵄩󵄩𝑢𝑥󵄩󵄩󵄩󵄩44

2 + |𝐼|

2 ) .

(37)

Consequently, by choosing the parameters𝑐1= 1/12and𝛽 <

1/3we have that

(2𝛽2𝜂 − 𝛽) ⟨𝑢𝑡, 𝑢⟩

≤ 󵄨󵄨󵄨󵄨󵄨2𝛽2𝜂 − 𝛽󵄨󵄨󵄨󵄨󵄨𝑐1 2󵄩󵄩󵄩󵄩𝑢𝑡󵄩󵄩󵄩󵄩2 +󵄨󵄨󵄨󵄨󵄨2𝛽2𝜂 − 𝛽󵄨󵄨󵄨󵄨󵄨

4𝑐1 󵄩󵄩󵄩󵄩𝑢𝑥󵄩󵄩󵄩󵄩44+󵄨󵄨󵄨󵄨󵄨2𝛽2𝜂 − 𝛽󵄨󵄨󵄨󵄨󵄨

4𝑐1 |𝐼|

≤ (1 − 3𝛽𝜂) 󵄩󵄩󵄩󵄩𝑢𝑡󵄩󵄩󵄩󵄩2+ 𝛽󵄩󵄩󵄩󵄩𝑢𝑥󵄩󵄩󵄩󵄩44+ 𝛽 |𝐼| .

(38)

Now, using the previous lemma and (33) we conclude that 𝑑

𝑑𝑡𝐸 + 𝛽𝜂𝑑

𝑑𝑡⟨𝑢𝑡, 𝑢⟩ + 2𝛽2𝜂 ⟨𝑢𝑡, 𝑢⟩ + 2𝛽𝐸 ≤ 2𝛽 |𝐼| . (39) If we set

Φ (𝑢, 𝑢𝑡) = Φ (𝑡) = 𝐸 (𝑢, 𝑢𝑡) + 𝛽𝜂⟨𝑢𝑡, 𝑢⟩, (40) then from (39) we get

𝑑

𝑑𝑡Φ (𝑡) + 2𝛽Φ (𝑡) ≤ 2𝛽. (41)

Now, integrating we have that

Φ (𝑡) ≤ [Φ (𝑢0, 𝑢1) − 1] 𝑒−2𝛽𝑡+ 1. (42) The previous inequality will be used in the next section to show the existence of absorbing sets for the problem (1).

We remark that the following inequality holds for the functions𝐸,̃𝐸, andΦ:

Φ (𝑡) = ̃𝐸 (𝑡) +1 2∫

𝐼𝑊 (𝑢𝑥) 𝑑𝑥 ≥ ̃𝐸 ≥ 0. (43)

4. Absorbing Sets

In this section we will show the existence of several absorbing sets for the solution semigroup of (1) in the spaceH𝜀,𝜂. Also, assuming further regularity of the initial data, the existence of a more regular absorbing sets is also shown.

First, notice the following estimate of the nonlinear term of the energy functional defined in (26). Using (23) we get

1 2∫

𝐼𝑊 (𝑢𝑥) 𝑑𝑥 ≤ 1

2󵄩󵄩󵄩󵄩𝑢𝑥󵄩󵄩󵄩󵄩2󵄩󵄩󵄩󵄩𝑢𝑥󵄩󵄩󵄩󵄩2𝐿(𝐼)− 󵄩󵄩󵄩󵄩𝑢𝑥󵄩󵄩󵄩󵄩2+ |𝐼|

2

≤ 1

2󵄩󵄩󵄩󵄩𝑢𝑥󵄩󵄩󵄩󵄩2󵄩󵄩󵄩󵄩𝑢𝑥𝑥󵄩󵄩󵄩󵄩2+ |𝐼|

2

≤ 1

2󵄩󵄩󵄩󵄩𝑢𝑥𝑥󵄩󵄩󵄩󵄩4+ |𝐼|

2 .

(44)

We will use this inequality several times in what follows.

4.1. Absorbing Set inH𝜀,𝜂

Proposition 5. For all𝑅0> 1the set

𝐵Φ:= {(𝑢, 𝑢𝑡) ∈H𝜀,𝜂: Φ (𝑢, 𝑢𝑡) ≤ 𝑅0} (45) is bounded, absorbing, and positively invariant for the semi- group𝑆𝜀,𝜂(𝑡)inH𝜀,𝜂.

Proof. The set is positively invariant, in fact if(𝑢0, 𝑢1) ∈H𝜀,𝜂 withΦ(𝑢0, 𝑢1) ≤ 𝑅0we have, from (42), that

Φ (𝑢, 𝑢𝑡) ≤ [𝑅0− 1] 𝑒−2𝛽𝑡+ 1 ≤ 𝑅0, ∀𝑡 > 0. (46) The boundness of𝐵Φfollows directly from (42). Now suppose that(𝑢0, 𝑢1)are such thatΦ(𝑢0, 𝑢1) ≤ 𝑅, with𝑅 > 𝑅0then again from (42) we get

Φ (𝑢, 𝑢𝑡) ≤ 𝑅0, ∀𝑡 ≥ 𝜏Φ, (47) where

𝜏Φ:= 1

2𝛽log{𝑅 − 1

𝑅0− 1} . (48)

Then𝐵Φis absorbing for the semigroup𝑆𝜀,𝜂(𝑡).

Proposition 6. For all𝑅1> 1one has that the set

𝐵̃𝐸:= {(𝑢, 𝑢𝑡) ∈H𝜀,𝜂: ̃𝐸 (𝑢, 𝑢𝑡) ≤ 𝑅1} (49) is absorbing for the semigroup𝑆𝜀,𝜂(𝑡).

Proof. We have from (42) and (43) that

̃𝐸 (𝑢, 𝑢𝑡) ≤ [Φ (𝑢0, 𝑢1) − 1] 𝑒−2𝛽𝑡+ 1. (50) Now, take(𝑢0, 𝑢1)such that̃𝐸(𝑢0, 𝑢1) ≤ 𝑅, with𝑅 > 𝑅1. Then, by (42) and (44) we get that

̃𝐸 (𝑡) ≤ Φ (𝑡) ≤ ̃𝐸 (𝑡) + 12󵄩󵄩󵄩󵄩𝑢𝑥󵄩󵄩󵄩󵄩44+ |𝐼|

2

≤ ̃𝐸 (𝑡) +1

2󵄩󵄩󵄩󵄩𝑢𝑥𝑥󵄩󵄩󵄩󵄩4+ |𝐼|

2

≤ ̃𝐸 (𝑡) + 4

𝜀2̃𝐸(𝑡)2+ |𝐼|

2 .

(51)

(5)

Therefore,

̃𝐸 (𝑢, 𝑢𝑡) ≤ {̃𝐸 (𝑢0, 𝑢1) + 4

𝜀2̃𝐸(𝑢0, 𝑢1)2+ |𝐼|

2 − 1} 𝑒−2𝛽𝑡+ 1

≤ {𝑅 + 4

𝜀2𝑅2+ |𝐼|

2 − 1} 𝑒−2𝛽𝑡+ 1.

(52) Consequently, we have that

̃𝐸 (𝑢, 𝑢𝑡) ≤ 𝑅1, ∀𝑡 ≥ 𝜏̃𝐸, (53) where

𝜏̃𝐸= 1

2𝛽log{𝑅 + (4/𝜀4) 𝑅2+ (|𝐼| /2) − 1

𝑅1− 1 } . (54)

Now using the equivalence of the norm onH𝜀,𝜂and (52) we get

󵄩󵄩󵄩󵄩(𝑢,𝑢𝑡)󵄩󵄩󵄩󵄩2H𝜀,𝜂 ≤ 3 {3󵄩󵄩󵄩󵄩(𝑢0, 𝑢1)󵄩󵄩󵄩󵄩2H𝜀,𝜂

+36

𝜀2󵄩󵄩󵄩󵄩(𝑢0, 𝑢1)󵄩󵄩󵄩󵄩4H𝜀,𝜂+ |𝐼|

2 − 1} 𝑒−2𝛽𝑡+ 3.

(55) Let𝑅2> √3. If(𝑢0, 𝑢1) ∈H𝜀,𝜂is such that

󵄩󵄩󵄩󵄩(𝑢0, 𝑢1)󵄩󵄩󵄩󵄩H𝜀,𝜂 ≤ 𝑅, (56) then we have that

󵄩󵄩󵄩󵄩(𝑢,𝑢𝑡)󵄩󵄩󵄩󵄩H𝜀,𝜂 ≤ 𝑅2, ∀𝑡 ≥ 𝜏𝐻, (57) where

𝜏𝐻= 1

2𝛽log3 { 3𝑅2+ (36/𝜀2) 𝑅4+ |𝐼| /2 − 1}

𝑅22− 3 . (58)

Thus, we have proved the following.

Proposition 7. For all𝑅2> √3one has that the ball

𝐵H𝜀,𝜂:= {(𝑢, 𝑢𝑡) ∈H𝜀,𝜂: 󵄩󵄩󵄩󵄩(𝑢, 𝑢𝑡)󵄩󵄩󵄩󵄩H𝜀,𝜂≤ 𝑅2} (59) is an absorbing set for the semigroup𝑆𝜀,𝜂(𝑡)inH𝜀,𝜂.

4.2. Absorbing Set in U𝜀,𝜂. Now suppose that the initial data has some additional regularity. Then we can prove the existence of more regular absorbing sets. Let us define the following space:

U𝜀,𝜂= { 𝐻3(𝐼) ∩ 𝐻2(𝐼) ∩ 𝐻01(𝐼)} × 𝐻1(𝐼) , (60) equipped with the norm

󵄩󵄩󵄩󵄩(𝑢,𝑢𝑡)󵄩󵄩󵄩󵄩2U𝜀,𝜂 =𝜂

2󵄩󵄩󵄩󵄩𝑢𝑡𝑥󵄩󵄩󵄩󵄩2+𝜀2

2󵄩󵄩󵄩󵄩𝑢𝑥𝑥𝑥󵄩󵄩󵄩󵄩2. (61) Then we have the following.

Proposition 8. There exists𝑅3> 0such that the closed ball

B3= {(𝑢, 𝑢𝑡) ∈U𝜀,𝜂: 󵄩󵄩󵄩󵄩(𝑢, 𝑢𝑡)󵄩󵄩󵄩󵄩U𝜀,𝜂≤ 𝑅3} , (62)

is a bounded absorbing set for𝑆𝜀,𝜂(𝑡)inU𝜀,𝜂.

Proof. If we multiply (1) by𝑢𝑥𝑥𝑡+ 𝑢𝑥𝑥and integrate over𝐼we obtain

𝑑 𝑑𝑡{𝜂

2󵄩󵄩󵄩󵄩𝑢𝑡𝑥󵄩󵄩󵄩󵄩2+𝜀2

2󵄩󵄩󵄩󵄩𝑢𝑥𝑥𝑥󵄩󵄩󵄩󵄩2+1

2󵄩󵄩󵄩󵄩𝑢𝑥󵄩󵄩󵄩󵄩2+ 𝜂⟨𝑢𝑡𝑥, 𝑢𝑥⟩}

+ (1 − 𝜂) 󵄩󵄩󵄩󵄩𝑢𝑡𝑥󵄩󵄩󵄩󵄩2+ 𝜀2󵄩󵄩󵄩󵄩𝑢𝑥𝑥𝑥󵄩󵄩󵄩󵄩2

= −1

2⟨[𝑊󸀠(𝑢𝑥)]𝑥, 𝑢𝑥𝑥𝑡⟩ −1

2⟨[𝑊󸀠(𝑢𝑥)]𝑥, 𝑢𝑥𝑥⟩ . (63) Let us denote the differential term of the previous inequality as

Ψ0(𝑡) = 𝜂

2󵄩󵄩󵄩󵄩𝑢𝑡𝑥󵄩󵄩󵄩󵄩2+𝜀2

2󵄩󵄩󵄩󵄩𝑢𝑥𝑥𝑥󵄩󵄩󵄩󵄩2+ 𝜂 ⟨𝑢𝑡𝑥, 𝑢𝑥⟩ +1

2󵄩󵄩󵄩󵄩𝑢𝑥󵄩󵄩󵄩󵄩2.

(64)

We will estimate the right hand side of (63). The first term can be estimated as follows:

−1

2⟨[𝑊󸀠(𝑢𝑥)]𝑥, 𝑢𝑥𝑥⟩ ≤ 1

2󵄩󵄩󵄩󵄩󵄩𝑊󸀠󸀠(𝑢𝑥)󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩𝑢𝑥𝑥󵄩󵄩󵄩󵄩2

≤ 2 (3󵄩󵄩󵄩󵄩𝑢𝑥󵄩󵄩󵄩󵄩2+ 1) 󵄩󵄩󵄩󵄩𝑢𝑥𝑥󵄩󵄩󵄩󵄩2

≤ 2 (3󵄩󵄩󵄩󵄩𝑢𝑥𝑥󵄩󵄩󵄩󵄩2+ 1) 󵄩󵄩󵄩󵄩𝑢𝑥𝑥󵄩󵄩󵄩󵄩2

≤ 4

𝜀2𝑅22(6𝑅22

𝜀2 + 1) := 𝐶1. (65)

Let us define

Ψ1= 1 4∫

𝐼𝑊󸀠󸀠(𝑢𝑥) 𝑢2𝑥𝑥𝑑𝑥; (66) then we can rewrite the the second term of r.h.s of (63)

−1

2⟨[𝑊󸀠(𝑢𝑥)]𝑥, 𝑢𝑥𝑥𝑡⟩ = −𝑑 𝑑𝑡Ψ1+1

4∫

𝐼𝑊󸀠󸀠󸀠(𝑢𝑥) 𝑢𝑥𝑡𝑢2𝑥𝑥, (67) and estimate

(6)

1 4∫

𝐼𝑊󸀠󸀠󸀠(𝑢𝑥) 𝑢𝑥𝑡𝑢2𝑥𝑥

≤ 6󵄩󵄩󵄩󵄩𝑢𝑥𝑥󵄩󵄩󵄩󵄩

𝐼𝑢𝑥𝑢𝑥𝑡𝑢𝑥𝑥𝑑𝑥

≤ 6󵄩󵄩󵄩󵄩𝑢𝑥𝑥󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩𝑢𝑥𝑡󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩𝑢𝑥𝑢𝑥𝑥󵄩󵄩󵄩󵄩

≤ 6󵄩󵄩󵄩󵄩𝑢𝑥𝑥󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩𝑢𝑥𝑡󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩𝑢𝑥𝑥󵄩󵄩󵄩󵄩2

≤ 6󵄩󵄩󵄩󵄩𝑢𝑥𝑥󵄩󵄩󵄩󵄩5/2󵄩󵄩󵄩󵄩𝑢𝑥𝑥𝑥󵄩󵄩󵄩󵄩1/2󵄩󵄩󵄩󵄩𝑢𝑥𝑡󵄩󵄩󵄩󵄩

≤ 6(√2 𝜀 𝑅2)

5/2󵄩󵄩󵄩󵄩𝑢𝑥𝑥𝑥󵄩󵄩󵄩󵄩1/2󵄩󵄩󵄩󵄩𝑢𝑥𝑡󵄩󵄩󵄩󵄩

≤𝜂

2󵄩󵄩󵄩󵄩𝑢𝑥𝑡󵄩󵄩󵄩󵄩2+18 𝜂(√2

𝜀 𝑅2)

5󵄩󵄩󵄩󵄩𝑢𝑥𝑥𝑥󵄩󵄩󵄩󵄩

≤𝜂

2󵄩󵄩󵄩󵄩𝑢𝑥𝑡󵄩󵄩󵄩󵄩2+1 2[18

𝜂𝜀(√2 𝜀 𝑅2)

5

]

2

+𝜀2 2󵄩󵄩󵄩󵄩𝑢𝑥𝑥𝑥󵄩󵄩󵄩󵄩2 := 𝜂

2󵄩󵄩󵄩󵄩𝑢𝑥𝑡󵄩󵄩󵄩󵄩2+𝜀2

2󵄩󵄩󵄩󵄩𝑢𝑥𝑥𝑥󵄩󵄩󵄩󵄩2+ 𝐶2.

(68)

Then if𝜂 ∈ (0, 1/2)and settingΨ := Ψ0+ Ψ1,𝐶 := 𝐶1+ 𝐶2 we have

𝑑 𝑑𝑡Ψ +𝜂

2󵄩󵄩󵄩󵄩𝑢𝑥𝑡󵄩󵄩󵄩󵄩2+𝜀2

2󵄩󵄩󵄩󵄩𝑢𝑥𝑥𝑥󵄩󵄩󵄩󵄩2≤ 𝐶. (69) To conclude the proof we note that

Ψ ≥ 󵄩󵄩󵄩󵄩(𝑢, 𝑢𝑡)󵄩󵄩󵄩󵄩2U𝜀,𝜂+1 2󵄩󵄩󵄩󵄩𝑢𝑥𝑥󵄩󵄩󵄩󵄩2

− 𝜂 󵄩󵄩󵄩󵄩𝑢𝑡𝑥󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩𝑢𝑥󵄩󵄩󵄩󵄩 − 󵄩󵄩󵄩󵄩𝑢𝑥𝑥󵄩󵄩󵄩󵄩2

≥ 󵄩󵄩󵄩󵄩(𝑢, 𝑢𝑡)󵄩󵄩󵄩󵄩2U𝜀,𝜂−𝜂

4󵄩󵄩󵄩󵄩𝑢𝑡𝑥󵄩󵄩󵄩󵄩2−3 2󵄩󵄩󵄩󵄩𝑢𝑥𝑥󵄩󵄩󵄩󵄩2

≥ 1

2󵄩󵄩󵄩󵄩(𝑢,𝑢𝑡)󵄩󵄩󵄩󵄩2U𝜀,𝜂− 3 𝜀2𝑅22 := 1

2󵄩󵄩󵄩󵄩(𝑢,𝑢𝑡)󵄩󵄩󵄩󵄩2U𝜀,𝜂− 𝑐1,

(70)

and that

Ψ ≤ 󵄩󵄩󵄩󵄩(𝑢, 𝑢𝑡)󵄩󵄩󵄩󵄩2U𝜀,𝜂+𝜂

2󵄩󵄩󵄩󵄩𝑢𝑡𝑥󵄩󵄩󵄩󵄩2+ 󵄩󵄩󵄩󵄩𝑢𝑥𝑥󵄩󵄩󵄩󵄩2 + 󵄩󵄩󵄩󵄩𝑢𝑥𝑥󵄩󵄩󵄩󵄩2(3󵄩󵄩󵄩󵄩𝑢𝑥󵄩󵄩󵄩󵄩2+ 1)

≤ 2󵄩󵄩󵄩󵄩(𝑢, 𝑢𝑡)󵄩󵄩󵄩󵄩2U𝜀,𝜂+ 2 𝜀2𝑅22(6

𝜀2𝑅22+ 2) := 2󵄩󵄩󵄩󵄩(𝑢, 𝑢𝑡)󵄩󵄩󵄩󵄩2U𝜀,𝜂+ 𝑐2.

(71)

From the previous inequalities we get 1

2󵄩󵄩󵄩󵄩(𝑢,𝑢𝑡)󵄩󵄩󵄩󵄩2U𝜀,𝜂− 𝑐1≤ Ψ ≤ 2󵄩󵄩󵄩󵄩(𝑢, 𝑢𝑡)󵄩󵄩󵄩󵄩2U𝜀,𝜂+ 𝑐2. (72)

Then from (72) we get 𝑑 𝑑𝑡Ψ +1

2Ψ ≤ 𝐶 + 𝑐2:= ̃𝐶, (73)

and by Gronwall’s lemma we obtain

Ψ (𝑡) ≤ (Ψ (0) − 2̃𝐶) 𝑒−(1/2)𝑡+ 2̃𝐶,

󵄩󵄩󵄩󵄩(𝑢,𝑢𝑡)󵄩󵄩󵄩󵄩2U𝜀,𝜂 ≤ 2 (󵄩󵄩󵄩󵄩(𝑢0, 𝑢1)󵄩󵄩󵄩󵄩2U𝜀,𝜂+ 𝑐2− 2̃𝐶) 𝑒−(1/2)𝑡 + 4̃𝐶 + 2𝑐1.

(74)

Then if(𝑢0, 𝑢1) ∈U𝜀,𝜂such that

󵄩󵄩󵄩󵄩(𝑢0, 𝑢1)󵄩󵄩󵄩󵄩U𝜀,𝜂≤ 𝑅, (75) we have that

󵄩󵄩󵄩󵄩(𝑢,𝑢𝑡)󵄩󵄩󵄩󵄩U𝜀,𝜂≤ 𝑅3, ∀𝑡 ≥ 𝜏𝑈, (76) where

𝜏𝑈:= 2log(2𝑅2+ 2𝑐2− 4̃𝐶

𝑅23− 4̃𝐶 − 2𝑐1 ) , (77) and this concludes the proof.

4.3. Absorbing Set in V𝜀,𝜂. We consider the space V𝜀,𝜂 as defined in (7), equipped with the norm defined in (10). By considering more regular initial conditions we can prove the following result.

Proposition 9. There exists𝑅4> 0such that the closed ball B4= {(𝑢, 𝑢𝑡) ∈V𝜀,𝜂: 󵄩󵄩󵄩󵄩(𝑢, 𝑢𝑡)󵄩󵄩󵄩󵄩V𝜀,𝜂 ≤ 𝑅4} (78)

is a bounded absorbing set for the semigroup𝑆𝜀,𝜂(𝑡)inV𝜀,𝜂. Proof. Multiply (1) by𝑢𝑥𝑥𝑥𝑥𝑡+ 𝑢𝑥𝑥𝑥𝑥; then we obtain

𝑑 𝑑𝑡{𝜂

2󵄩󵄩󵄩󵄩𝑢𝑡𝑥𝑥󵄩󵄩󵄩󵄩2+𝜀2

2󵄩󵄩󵄩󵄩𝑢𝑥𝑥𝑥𝑥󵄩󵄩󵄩󵄩2 +𝜂 ⟨𝑢𝑡𝑥𝑥, 𝑢𝑥𝑥⟩ +1

2󵄩󵄩󵄩󵄩𝑢𝑥𝑥𝑥󵄩󵄩󵄩󵄩2} + (1 − 𝜂) 󵄩󵄩󵄩󵄩𝑢𝑥𝑥𝑡󵄩󵄩󵄩󵄩 + 𝜀2󵄩󵄩󵄩󵄩𝑢𝑥𝑥𝑥𝑥󵄩󵄩󵄩󵄩2

= 1

2⟨[𝑊󸀠(𝑢𝑥)]𝑥, 𝑢𝑥𝑥𝑥𝑥𝑡+ 𝑢𝑥𝑥𝑥𝑥⟩ .

(79)

(7)

We call𝜃0(𝑡)the differential term of the previous inequality and we estimate the r.h.s.:

1

2⟨[𝑊󸀠(𝑢𝑥)]𝑥, 𝑢𝑥𝑥𝑥𝑥

= −1

2⟨[𝑊󸀠(𝑢𝑥)]𝑥𝑥, 𝑢𝑥𝑥𝑥

= −1

2⟨𝑊󸀠󸀠󸀠(𝑢𝑥) 𝑢2𝑥𝑥, 𝑢𝑥𝑥𝑥⟩ −1

2⟨[𝑊󸀠󸀠(𝑢𝑥)]𝑥𝑥, 𝑢2𝑥𝑥𝑥

= −12 ∫

𝐼𝑢𝑥𝑢2𝑥𝑥𝑢𝑥𝑥𝑥𝑑𝑥 − 2 ∫

𝐼(3𝑢2𝑥− 1) 𝑢2𝑥𝑥𝑥𝑑𝑥

≤ 2󵄩󵄩󵄩󵄩𝑢𝑥𝑥𝑥󵄩󵄩󵄩󵄩2+ 12󵄩󵄩󵄩󵄩𝑢𝑥𝑥󵄩󵄩󵄩󵄩2󵄩󵄩󵄩󵄩𝑢𝑥󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩𝑢𝑥𝑥𝑥󵄩󵄩󵄩󵄩

≤ 2󵄩󵄩󵄩󵄩𝑢𝑥𝑥𝑥󵄩󵄩󵄩󵄩2(6󵄩󵄩󵄩󵄩𝑢𝑥𝑥󵄩󵄩󵄩󵄩2+ 1)

≤ 𝜀2𝑅23(12

𝜀2𝑅22+ 1) := 𝐴1.

(80) Let us define

𝜃1(𝑡) :=1 4∫

𝐼𝑊󸀠󸀠(𝑢𝑥) 𝑢𝑥𝑥𝑥2 𝑑𝑥; (81) then

1

2⟨[𝑊󸀠(𝑢𝑥)]𝑥, 𝑢𝑥𝑥𝑥𝑥𝑡

= −1

2⟨[𝑊󸀠(𝑢𝑥)]𝑥𝑥, 𝑢𝑥𝑥𝑥𝑡

= −1

2⟨𝑊󸀠󸀠󸀠(𝑢𝑥) 𝑢2𝑥𝑥, 𝑢𝑥𝑥𝑥𝑡

−1

2⟨𝑊󸀠󸀠(𝑢𝑥) 𝑢𝑥𝑥𝑥, 𝑢𝑥𝑥𝑥𝑡

= −𝑑 𝑑𝑡𝜃1+1

2⟨[𝑊󸀠󸀠󸀠(𝑢𝑥) 𝑢2𝑥𝑥]𝑥, 𝑢𝑥𝑥𝑡⟩ +1

4∫

𝐼𝑊󸀠󸀠󸀠(𝑢𝑥) 𝑢𝑥𝑡𝑢2𝑥𝑥𝑥𝑑𝑥.

(82)

We estimate the last two terms of the previous equality:

1 4∫

𝐼𝑊󸀠󸀠󸀠(𝑢𝑥) 𝑢𝑥𝑡𝑢2𝑥𝑥𝑥𝑑𝑥

= 6 ∫

𝐼𝑢𝑥𝑢𝑥𝑡𝑢2𝑥𝑥𝑥𝑑𝑥

≤ 6󵄩󵄩󵄩󵄩𝑢𝑥𝑥𝑥󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩𝑢𝑥󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩𝑢𝑥𝑡󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩𝑢𝑥𝑥𝑥󵄩󵄩󵄩󵄩

≤ 6󵄩󵄩󵄩󵄩𝑢𝑥𝑥𝑥󵄩󵄩󵄩󵄩3/2󵄩󵄩󵄩󵄩𝑢𝑥𝑥𝑥𝑥󵄩󵄩󵄩󵄩1/2󵄩󵄩󵄩󵄩𝑢𝑥𝑡󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩𝑢𝑥𝑥󵄩󵄩󵄩󵄩2

≤ (12 ⋅ 23/4𝑅22𝑅3/23

𝜀7/2 ) 󵄩󵄩󵄩󵄩𝑢𝑥𝑥𝑥𝑥󵄩󵄩󵄩󵄩1/2󵄩󵄩󵄩󵄩𝑢𝑥𝑡󵄩󵄩󵄩󵄩

≤ (12 ⋅ 23/4𝑅22𝑅3/23 𝜀7/2 )

2󵄩󵄩󵄩󵄩𝑢𝑥𝑥𝑥𝑥󵄩󵄩󵄩󵄩 + 󵄩󵄩󵄩󵄩𝑢𝑥𝑡󵄩󵄩󵄩󵄩2

≤ 1

2𝜀2(12 ⋅ 23/4𝑅22𝑅3/23 𝜀7/2 )

4

+2 𝜂𝑅23+𝜀2

2󵄩󵄩󵄩󵄩𝑢𝑥𝑥𝑥𝑥󵄩󵄩󵄩󵄩2 := 𝜀2

2󵄩󵄩󵄩󵄩𝑢𝑥𝑥𝑥𝑥󵄩󵄩󵄩󵄩2+ 𝐴2, 1

2⟨[𝑊󸀠󸀠󸀠(𝑢𝑥) 𝑢2𝑥𝑥]𝑥, 𝑢𝑥𝑥𝑡

= 1

2⟨𝑊𝑖V(𝑢𝑥) 𝑢3𝑥𝑥+ 𝑊󸀠󸀠󸀠(𝑢𝑥) 2𝑢𝑥𝑥𝑢𝑥𝑥𝑥, 𝑢𝑥𝑥𝑡

= 12 ∫

𝐼𝑢3𝑥𝑥𝑢𝑥𝑥𝑡𝑑𝑥 + 24 ∫

𝐼𝑢𝑥𝑢𝑥𝑥𝑢𝑥𝑥𝑥𝑢𝑥𝑥𝑡𝑑𝑥

≤ 12 (󵄩󵄩󵄩󵄩𝑢𝑥𝑥󵄩󵄩󵄩󵄩2󵄩󵄩󵄩󵄩𝑢𝑥𝑥󵄩󵄩󵄩󵄩

+2󵄩󵄩󵄩󵄩𝑢𝑥󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩𝑢𝑥𝑥󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩𝑢𝑥𝑥𝑥󵄩󵄩󵄩󵄩)󵄩󵄩󵄩󵄩𝑢𝑥𝑥𝑡󵄩󵄩󵄩󵄩

≤ 12 (󵄩󵄩󵄩󵄩𝑢𝑥𝑥󵄩󵄩󵄩󵄩2󵄩󵄩󵄩󵄩𝑢𝑥𝑥𝑥󵄩󵄩󵄩󵄩

+2󵄩󵄩󵄩󵄩𝑢𝑥𝑥󵄩󵄩󵄩󵄩3/2󵄩󵄩󵄩󵄩𝑢𝑥𝑥𝑥󵄩󵄩󵄩󵄩3/2) 󵄩󵄩󵄩󵄩𝑢𝑥𝑥𝑡󵄩󵄩󵄩󵄩

≤ 𝜂

2󵄩󵄩󵄩󵄩𝑢𝑥𝑥𝑡󵄩󵄩󵄩󵄩2+ 72 (󵄩󵄩󵄩󵄩𝑢𝑥𝑥󵄩󵄩󵄩󵄩2󵄩󵄩󵄩󵄩𝑢𝑥𝑥𝑥󵄩󵄩󵄩󵄩

+2󵄩󵄩󵄩󵄩𝑢𝑥𝑥󵄩󵄩󵄩󵄩3/2󵄩󵄩󵄩󵄩𝑢𝑥𝑥𝑥󵄩󵄩󵄩󵄩3/2)2

≤ 𝜂

2󵄩󵄩󵄩󵄩𝑢𝑥𝑥𝑡󵄩󵄩󵄩󵄩2+ 72[2√2𝑅22𝑅3

𝜀3 + 2(2𝑅2𝑅3 𝜀2 )3/2]

2

:= 𝜂

2󵄩󵄩󵄩󵄩𝑢𝑥𝑥𝑡󵄩󵄩󵄩󵄩2+ 𝐴3.

(83)

Then if we set𝜃(𝑡) = 𝜃0(𝑡) + 𝜃1(𝑡)we get

𝑑

𝑑𝑡𝜃 (𝑡) + 󵄩󵄩󵄩󵄩(𝑢, 𝑢𝑡)󵄩󵄩󵄩󵄩2V𝜀,𝜂 ≤ 𝐴1+ 𝐴2+ 𝐴3:= 𝐴. (84)

Moreover we have

𝜃 (𝑡) ≥ 󵄩󵄩󵄩󵄩(𝑢, 𝑢𝑡)󵄩󵄩󵄩󵄩2V𝜀,𝜂−𝜂

4󵄩󵄩󵄩󵄩𝑢𝑥𝑥𝑡󵄩󵄩󵄩󵄩2−1 2󵄩󵄩󵄩󵄩𝑢𝑥𝑥󵄩󵄩󵄩󵄩2

≥ 1

2󵄩󵄩󵄩󵄩(𝑢,𝑢𝑡)󵄩󵄩󵄩󵄩2V𝜀,𝜂−1 2𝑅22 := 1

2󵄩󵄩󵄩󵄩(𝑢,𝑢𝑡)󵄩󵄩󵄩󵄩2V𝜀,𝜂− 𝑎1,

(8)

𝜃 (𝑡) ≤ 󵄩󵄩󵄩󵄩(𝑢, 𝑢𝑡)󵄩󵄩󵄩󵄩2V𝜀,𝜂+ 𝜂 󵄩󵄩󵄩󵄩𝑢𝑥𝑥𝑡󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩𝑢𝑥𝑥󵄩󵄩󵄩󵄩

+1

2󵄩󵄩󵄩󵄩𝑢𝑥𝑥󵄩󵄩󵄩󵄩2+1

4󵄩󵄩󵄩󵄩󵄩𝑊󸀠󸀠(𝑢𝑥)󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩󵄩𝑢𝑥𝑥𝑥󵄩󵄩󵄩󵄩3

≤ 2󵄩󵄩󵄩󵄩(𝑢, 𝑢𝑡)󵄩󵄩󵄩󵄩2V𝜀,𝜂+ 󵄩󵄩󵄩󵄩𝑢𝑥𝑥󵄩󵄩󵄩󵄩2 + (3󵄩󵄩󵄩󵄩𝑢𝑥󵄩󵄩󵄩󵄩2+ 1) 󵄩󵄩󵄩󵄩𝑢𝑥𝑥𝑥󵄩󵄩󵄩󵄩2

≤ 2󵄩󵄩󵄩󵄩(𝑢, 𝑢𝑡)󵄩󵄩󵄩󵄩2V𝜀,𝜂+ 2

𝜀2𝑅22+ (6

𝜀2𝑅22+ 1) 2 𝜀2𝑅23 := 2󵄩󵄩󵄩󵄩(𝑢, 𝑢𝑡)󵄩󵄩󵄩󵄩2V𝜀,𝜂+ 𝑎2.

(85) Then putting all together we get

1

2󵄩󵄩󵄩󵄩(𝑢,𝑢𝑡)󵄩󵄩󵄩󵄩2V𝜀,𝜂− 𝑎1≤ 𝜃 (𝑡) ≤ 2󵄩󵄩󵄩󵄩(𝑢, 𝑢𝑡)󵄩󵄩󵄩󵄩2V𝜀,𝜂+ 𝑎2. (86) From the previous inequality we get

𝑑

𝑑𝑡𝜃 (𝑡) + 1

2𝜃 (𝑡) ≤ 𝐴 +𝑎2

2 := ̃𝐴 (87)

and by Gronwall’s lemma

𝜃 (𝑡) ≤ [𝜃 (0) − 2̃𝐴] 𝑒−(1/2)𝑡+ 2̃𝐴. (88) Using again (86) we get

󵄩󵄩󵄩󵄩(𝑢,𝑢𝑡)󵄩󵄩󵄩󵄩2V𝜀,𝜂 ≤ 2 [2󵄩󵄩󵄩󵄩(𝑢0, 𝑢1)󵄩󵄩󵄩󵄩2V𝜀,𝜂+ 𝑎2− 2̃𝐴] 𝑒−(1/2)𝑡 + 4̃𝐴 + 2𝑎1.

(89)

Then if(𝑢0, 𝑢1) ∈V𝜀,𝜂such that

󵄩󵄩󵄩󵄩(𝑢0, 𝑢1)󵄩󵄩󵄩󵄩V𝜀,𝜂 ≤ 𝑅, (90) then there exists𝑅4> 0:

󵄩󵄩󵄩󵄩(𝑢,𝑢𝑡)󵄩󵄩󵄩󵄩V𝜀,𝜂 ≤ 𝑅4, ∀𝑡 ≥ 𝜏𝑉, (91) where

𝜏𝑉:= 2log[2 (2𝑅2+ 𝑎2− 2̃𝐴)

𝑅42− 4̃𝐴 − 2𝑎1 ] , (92) and this concludes the proof.

5. Global Attractor

In this section we will show the existence of a global attractor for the semigroup 𝑆𝜀,𝜂(𝑡) in H𝜀,𝜂. Since we have already proved the existence of the absorbing set inH𝜀,𝜂, then it is sufficient (see, e.g., [4] or [14] for general results or [15] for a recent application on a weakly damped wave equation) to prove that, for any fixed bounded setB⊂H𝜀,𝜂, the solution semigroup𝑆𝜀,𝜂(𝑡)admits the decomposition:

𝑆𝜀,𝜂(𝑡) = 𝐿𝜀,𝜂(𝑡) + 𝑁𝜀,𝜂(𝑡) , (93)

such that

(𝐶1) sup

𝑡≥0 sup

𝑧∈H𝜀,𝜂󵄩󵄩󵄩󵄩󵄩𝐿𝜀,𝜂(𝑡)𝑧󵄩󵄩󵄩󵄩󵄩V𝜀,𝜂 < ∞, (94)

(𝐶2) lim

𝑡 → ∞{sup

𝑧∈H𝜀,𝜂󵄩󵄩󵄩󵄩󵄩𝑁𝜀,𝜂(𝑡) 𝑧󵄩󵄩󵄩󵄩󵄩H𝜀,𝜂} = 0. (95) LetB ⊂ H𝜀,𝜂be a fixed bounded set and let(𝑢0, 𝑢1) ∈ B⊂H𝜀,𝜂. We will define the decomposition of𝑆𝜀,𝜂as follows:

𝑆𝜀,𝜂(𝑡) (𝑢0, 𝑢1) = (𝑢, 𝑢𝑡) , 𝐿𝜀,𝜂(𝑡) (𝑢0, 𝑢1) = (ℎ, ℎ𝑡) , 𝑁𝜀,𝜂(𝑡) (𝑢0, 𝑢1) = (V,V𝑡) ,

(96)

whereℎandVare solutions of the following problems:

𝜂ℎ𝑡𝑡+ ℎ𝑡+ 𝜀2𝑥𝑥𝑥𝑥− 𝛼ℎ𝑥𝑥

= 1

2𝑊󸀠󸀠(ℎ𝑥) ℎ𝑥𝑥− 𝛼𝑢𝑥𝑥, ℎ (𝑥, 0) = 0,

𝑡(𝑥, 0) = 0, ℎ = ℎ𝑥𝑥= 0, in𝜕𝐼,

(97)

𝜂V𝑡𝑡+V𝑡+ 𝜀2V𝑥𝑥𝑥𝑥− 𝛼V𝑥𝑥

= 1

2𝑊󸀠󸀠(𝑢𝑥) 𝑢𝑥𝑥−1

2𝑊󸀠󸀠(ℎ𝑥) ℎ𝑥𝑥, V(0) = 𝑢0,

V𝑡(0) = 𝑢1, V=V𝑥𝑥= 0, in 𝜕𝐼,

(98)

where

𝛼 ≥ 6√2

𝜀 𝑅2> 6√6. (99)

Before showing that the semigroups𝐿𝜀,𝜂(𝑡)and𝑁𝜀,𝜂(𝑡)satisfy the conditions (94) and (95), respectively, we consider the following lemma (see [9]) that will be useful for the sequel.

Lemma 10. Let𝜓 : R+ → Rbe an absolutely continuous function which fulfills, for some]> 0and almost every𝑡 ≥ 0, the differential inequality

𝑑

𝑑𝑡𝜓 (𝑡) + 2]𝜓 (𝑡) ≤ 𝑓 (𝑡) 𝜓 (𝑡) , (100) where𝑓is a positive function satisfying

𝑡

0𝑓 (𝑦) 𝑑𝑦 ≤]𝑡 + 𝑐, ∀𝑡 ≥ 0. (101) Then

𝜓 (𝑡) ≤ 𝑐𝜓 (0) 𝑒−]𝑡, 𝑡 ≥ 0. (102)

参照

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