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Volume 2012, Article ID 694251,10pages doi:10.1155/2012/694251

Research Article

Modular Identities and Explicit Evaluations of a Continued Fraction of Ramanujan

Nipen Saikia

Department of Mathematics, Rajiv Gandhi University, Rono Hills, Doimukh-791112, Arunachal Pradesh, India

Correspondence should be addressed to Nipen Saikia,[email protected] Received 23 March 2012; Accepted 11 June 2012

Academic Editor: Stefaan Caenepeel

Copyrightq2012 Nipen Saikia. This is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited.

We study a new continued fraction of Ramanujan. We prove its modular identities and give some explicit evaluations.

1. Introduction

Throughout the paper, we assume|q|<1. As usual, for positive integersnand any complex numbera, we write

an: a;q

n:n−1

j0

1−aqj

, a: a;q

:

n0

1−aqn

. 1.1

Ramanujan’s general theta-functionfa, bis defined by

fa, b:

k−∞

akk1/2bkk−1/2, 1.2

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where|ab|<1. After Ramanujan, we define

φ q

:f q, q

12 k1

qk2

−q;q2

q2;q2

q;q2

−q2;q2

, 1.3

ψ q

:f q, q3

k0

qkk1/2

q2;q2

q;q2

, 1.4

f

−q :f

−q,−q2

k0

−1kqk3k−1/2

k1

−1kqk3k1/2 q;q

, 1.5

χ q

f q f

−q2

−q;q2

. 1.6

Ramanujan recorded many q-continued fractions and some of their explicit values in his second notebook1and in his lost notebook2. The following beautiful continued fraction identity was recorded by Ramanujan in his second notebook and can be found in3, p. 11, Entry 11:

−ab−a−b

−ab a−b ab 1−q

abq aqb 1−q3 q

abq2

aq2b

1−q5 · · ·, 1.7 where eitherq,a, andbare complex numbers with|q|<1, orq,a, andbare complex numbers withabqmfor some integerm. Several elegantq-continued fractions have representations asq-products and some of them can be expressed in terms of Ramanujan’s theta-functions.

An account of this can be found in in Chapter 32 of Berndt’s book4 also see5. The most famous one, of course, is the Rogers-Ramanujan continued fractionRqdefined by

R q

: q1/5 1 q

1 q2 1 q3

1 · · ·. 1.8

The continued fractionRqhas a very beautiful and extensive theory almost all of which was developed by Ramanujan. In particular, his lost notebook2contains several results on the Rogers-Ramanujan continued fraction. We refer to the paper by Berndt et al.6, Kang 7,8for proofs of many of these theorems.

In this paper, we examine another continued fractionTqof Ramanujan arising from 1.7and is defined by

T q

: q

1−q2 q4

1−q6 q8

1−q10 · · ·. 1.9 Note that, replacingqbyq2and then settingaqandb0 in1.7, we obtain1.9.

InSection 2, we record some preliminary results.Section 3is devoted to prove some modular identities for the continued fractionTq. Finally, inSection 4, we give some explicit evaluations ofTq.

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We complete this introduction by defining Ramanujan’s modular equation from Berndt’s book3. The complete elliptic integral of the first kindKkis defined by

Kk: π/2

0

1−k2sin2φ

π 22F1

1 2,1

2; 1;k2

, 1.10

where 0< k <1,2F1denotes the ordinary or Gaussian hypergeometric function. The number k is called the modulus ofK, andk : √

1−k2 is called the complementary modulus. Let K, K, L, andL denote the complete elliptic integrals of the first kind associated with the modulik,k,l, andl, respectively. Suppose that the equality

nK K L

L 1.11

holds for some positive integern. Then, a modular equation of degreenis a relation between the modulikandlwhich is implied by1.11. If we set

qexp

−πK K

, qexp

−πL L

, 1.12

we see that1.11is equivalent to the relationqnq. Thus, a modular equation can be viewed as an identity involving theta-functions at the argumentsqandqn. Ramanujan recorded his modular equations in terms ofαandβ, whereαk2 andβl2. We say thatβhas degreen overα. The multipliermconnectingαandβis defined by

m K

L, 1.13

wherezr φ2qr.

2. Preliminary Results

In this section, we record some results that will be used in the subsequent sections.

Lemma 2.1see3, p. 124, Entry 12iandii. One has f

q

z12−1/6{α1−α}1/24q−1/24, f

−q √

z12−1/61−α1/6α1/24q−1/24. 2.1 Lemma 2.2see3, p. 214, Entry 24iii. Ifβhas degree 2 overα, then

m

α−1 β1, m2

α−1β1.

2.2

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Lemma 2.3see3, p. 230, Entry 5ii. Ifβhas degree 3 overα, then αβ1/4

1−α

1−β1/4 1. 2.3

Lemma 2.4see3, p. 215,24.22. Ifβhas degree 4 overα, then

β

1−1−α1/4 1 1−α1/4

2

. 2.4

Lemma 2.5see3, p. 280-281, Entry 13vandvi. Ifβhas degree 5 overα, then

m 1 1−β5

/1α1/8

1

1−α3

1−β1/8 , 5

m 1−

1−α5/

1−β1/8 1−

1−α

1−β31/8 .

2.5

Lemma 2.6see3, p. 314, Entry 19i. Ifβhas degree 7 overα, then αβ1/8

1−α

1−β1/8

1. 2.6

3. Modular Identitites for T q

In this section, we use Ramanujan’s modular equations to prove certain modular identities forTq.

Theorem 3.1. One has

T q

f q

f

−q f

q f

−q. 3.1

Proof. Replacingqbyq2and the settingaqandb0 in1.7and simplifying, we obtain −q;q2

q;q2

−q;q2

q;q2

q

1−q2 q4

1−q6 q8

1−q10 · · · . 3.2 Employing1.6and1.9in3.2and simplifying, we complete the proof.

Corollary 3.2. One has

1T q 1−T

q f q f

−q. 3.3

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Proof. Dividing numerator and denominator on right-hand side of the identity in Theorem 3.1byf−qand simplifying, we complete the proof.

Theorem 3.3. One has iα1−

1−T q 1T

q 8

, iiβ1−

1−Tqn 1Tqn

8

, 3.4

whereβhas degree n overα.

Proof. We employLemma 2.1inCorollary 3.2to complete the proof.

Theorem 3.4. LetuTqandvT−q. Then,

uv0. 3.5

Proof. Replacingqby−qinCorollary 3.2, we obtain 1T

−q 1−T

−q f

−q f

q . 3.6

Now, eliminatingfq/f−qbetween3.6andCorollary 3.2and simplifying, we complete the proof.

Theorem 3.5. LetuTqandvTq2. Then,

u2v−2u2vu4v6u2v2v3−2u2v3u4v3u2v40. 3.7 Proof. Eliminatingmin2.2and then simplifying, we deduce that

1β

β−1√ 1−α2

−4β0. 3.8

FromTheorem 3.3i, we have

√1−α

1−T q 1T

q 4

. 3.9

Now, employing Theorem 3.3ii with n 2 and 3.9 in 3.8 and factorizing using Mathematica, we obtain

−1v8

u2v−2u2vu4v6u2v2v3−2u2v3u4v3u2v4

×

12u2u4−16u2v6v212u2v26u4v2−16u2v3v42u2v4u4v4 0.

3.10

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It can be seen that the first and the last factors in3.10 do not vanish for|q| → 0. So, by identity theorem, we have

u2v−2u2vu4v6u2v2v3−2u2v3u4v3u2v40. 3.11

Theorem 3.6. LetuTqandvTq3. Then,

u3v−3u2v3uv23u3v2−3u2v3u4v3uv40. 3.12

Proof. FromLemma 2.3, we obtain

αβ

1−1−α1/4

1−β1/44

0. 3.13

FromTheorem 3.3, we deduce that

α1− 1−u

1u 8

, β1− 1−v

1v 8

,

1−α1/4 1−u

1u 2

,

1−β1/4

1−v 1v

2 ,

3.14

whereβhas degree 3 overα.

Employing3.14in3.13and factorizing using Mathematica, we arrive at −u3v3u2v−3uv2−3u3v23u2v3u4v3uv4

×

−u3u2vu4v−3uv2−3u3v2v33u2v3u3v4 0.

3.15

It can be seen that the second factor of3.15 does not vanish for|q| → 0, so by identity theorem, we have

u3v−3u2v3uv23u3v2−3u2v3u4v3uv40. 3.16

Theorem 3.7. LetuTqandvTq4. Then,

u4v−4u2v2u4v−4u6vu8v28u4v2−7v3−28u2v314u4v3−28u6v3

−7u8v370u4v4−7v5−28u2v514u4v5−28u6v5−7u8v528u4v6v7−4u2v7 2u4v7−4u6v7u8v7u4v80.

3.17

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Proof. Squaring the modular equation inLemma 2.4and simplifying, we obtain

β

1−1−α1/4 1 1−α1/4

4

0. 3.18

FromTheorem 3.3i, we have

1−α1/4

1−T q 1T

q 2

. 3.19

Now, employingTheorem 3.3iiwithn4 and3.19in3.18and simplifying, we complete the proof.

Theorem 3.8. LetuTqandvTq5. Then,

u5v−5u2v10u3v25u5v2−10u2v3−10u4v35uv410u3v4−5u4v5u6v5uv60.

3.20 Proof. FromTheorem 3.3, we obtain

c: 1−α1/8 1−u

1u

, d:

1−β1/8

1−v 1v

, 3.21

whereβhas degree 5 overα.

Employing3.21in2.5, we find that

m cd5

c1c3d, 3.22

5

m dc5

d1cd3, 3.23

respectively.

Eliminatingmbetween3.22and3.23and simplifying, we deduce that 5cd

1c3d

1−cd3

cd5 dc5

0. 3.24

Substituting forcanddfrom3.21in3.24and simplifying, we arrive at

u5v−5u2v10u3v25u5v2−10u2v3−10u4v35uv410u3v4−5u4v5u6v5uv60.

3.25

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Theorem 3.9. LetuTqandvTq7. Then,

u8uv−7u3v−7u5v7u7v28u6v2−7uv3−49u3v37u5v3−7u7v370u4v4

−7uv57u3v5−49u5v5−7u7v528u2v67uv7−7u3v7−7u5v7u7v7v80.

3.26

Proof. FromLemma 2.6, we obtain

αβ

1−1−α1/4

1−β1/48

0. 3.27

Again, fromTheorem 3.3, we deduce that

α1− 1−u

1u 8

, β1− 1−v

1v 8

,

1−α1/8 1−u

1u

,

1−β1/8

1−v 1v

,

3.28

whereβhas degree 7 overα.

Employing3.28in3.27and simplifying using Mathematica, we arrive at u8uv−7u3v−7u5v7u7v28u6v2−7uv3−49u3v37u5v3−7u7v370u4v4

−7uv57u3v5−49u5v5−7u7v528u2v67uv7−7u3v7−7u5v7u7v7v80.

3.29

4. Explicit Evaluations of T q

In this section, we establish some general theorems for the explicit evaluations of the continued fractionTqand give examples.

Forq:e−πn, Ramanujan’s two class invariantsGnandgnare defined by Gn2−1/4q−1/24χ

q

, gn2−1/4q−1/24χ

−q

. 4.1

The class invariantsGnandgnare connected by the relation4, p. 187, Entry 2.1:

g4n21/4gnGn. 4.2

The singular modulusαn is defined byαn : αe−πn, wherenis a positive integer and unique positive number between 0 and 1 satisfying

n 2F11/2,1/2; 1; 1−αn

2F11/2,1/2; 1;αn . 4.3

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Class invariants and singular moduli are intimately related by the equalities4, p. 185, 1.6:

Gnn1−αn−1/24, gn

n1−αn−2−1/24

. 4.4

An account of Ramanujan’s class invariants and singular moduli can be found in Chapter 34 of Berndt’s book4.

Theorem 4.1. One has

T e−πn

1−1−αn1/8

1 1−αn1/8. 4.5

Proof. We setq: e−πn inTheorem 3.3iand use the definition of singular moduliαnand simplifying, we complete the proof.

In the scattered places of his first notebook1, Ramanujan calculated over 30 singular moduliαn. See Chapter 34 of Berndt’s book4for details. Thus, one can useTheorem 4.1to find the values ofTe−πnif the corresponding values ofαnare known. For example, from 4, p. 281, Theorem 9.2, we note that

α2√ 2−12

. 4.6

Employing4.6inTheorem 4.1, we calculate

T e−π2

1−

−22√ 21/8 1

−22√

21/8. 4.7

Many other values ofTe−πncan be computed by using the known values ofαn. Theorem 4.2. One has

T e−πn

g4n−21/4gn2 g4n−21/4gn2

. 4.8

Proof. Dividing numerator and denominator of right-hand side ofTheorem 3.1and employ- ing1.6, we obtain

T q

χ q

χ

−q χ

q χ

−q. 4.9

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Settingq:e−πn, employing the definitions ofGnandgnfrom4.1in4.9and simplifying, we obtain

T e−πn

Gngn

Gngn. 4.10

Substituting forGnfrom4.2in4.10and simplifying, we complete the proof.

Theorem 4.2implies that if we know the values ofgnandg4nfor any positive number n, then corresponding values ofTe−πncan easily be calculated. Saikia9evaluated several values ofgn andg4nfor positive numbern. For example, noting from9, Theorem 3.5, we have

g32−1/6 2√

31/8

, g1221/6 2√

31/8

. 4.11

Employing4.11inTheorem 4.2, we obtain

T e−π3

2−23/4 2√

31/8 223/4

2√

31/8. 4.12

Many other values ofTe−πncan be determined by using the values ofgnandg4nevaluated in9.

References

1 S. Ramanujan, Notebooks, vol. 1,2, Tata Institute of Fundamental Research, Bombay, India, 1957.

2 S. Ramanujan, The Lost Notebook and Other Unpublished Papers, Narosa, New Delhi, India, 1988.

3 B. C. Berndt, Ramanujan’s Notebooks, part 3, Springer, New York, NY, USA, 1991.

4 B. C. Berndt, Ramanujan’s Notebooks, Part 4, Springer, New York, NY, USA, 1998.

5 B. C. Berndt, “Flowers which we cannot yet see growing in Ramanujan’s garden of hypergeometric series, elliptic functions, andq’s,” in Special Functions 2000: Current Perspective and Future Directions, J.

Bustoz, M. E. H. Ismail, and S. K. Suslov, Eds., vol. 30, pp. 61–85, Kluwer Academic, Dordrecht, The Netherlands, 2001.

6 B. C. Berndt, S. S. Huang, J. Sohn, and S. H. Son, “Some theorems on the Rogers-Ramanujan continued fraction in Ramanujan’s lost notebook,” Transactions of the American Mathematical Society, vol. 352, no.

5, pp. 2157–2177, 2000.

7 S.-Y. Kang, “Some theorems on the Rogers-Ramanujan continued fraction and associated theta function identities in Ramanujan’s lost notebook,” The Ramanujan Journal, vol. 3, no. 1, pp. 91–111, 1999.

8 S.-Y. Kang, “Ramanujan’s formulas for the explicit evaluation of the Rogers-Ramanujan continued fraction and theta-functions,” Acta Arithmetica, vol. 90, no. 1, pp. 49–68, 1999.

9 N. Saikia, “Ramanujan’s modular equations and Weber-Ramanujan’s class invariants Gn and gn ,”

Bulletin of Mathematical Sciences, vol. 2, no. 1, pp. 205–223, 2012.

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