Advances in Difference Equations Volume 2010, Article ID 586312,23pages doi:10.1155/2010/586312
Research Article
Oscillation Behavior of Third-Order
Neutral Emden-Fowler Delay Dynamic Equations on Time Scales
Zhenlai Han,
1, 2Tongxing Li,
1Shurong Sun,
1, 3and Chenghui Zhang
21School of Science, University of Jinan, Jinan, Shandong 250022, China
2School of Control Science and Engineering, Shandong University, Jinan, Shandong 250061, China
3Department of Mathematics and Statistics, Missouri University of Science and Technology, Rolla, MO 65409-0020, USA
Correspondence should be addressed to Shurong Sun,[email protected]
Received 14 September 2009; Revised 28 November 2009; Accepted 10 December 2009 Academic Editor: Leonid Berezansky
Copyrightq2010 Zhenlai Han et al. This is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited.
We will establish some oscillation criteria for the third-order Emden-Fowler neutral delay dynamic equationsrtxt−atxτtΔΔΔptxγδt 0 on a time scaleT, whereγ > 0 is a quotient of odd positive integers withr,a,andpreal-valued positive rd-continuous functions defined onT. To the best of our knowledge nothing is known regarding the qualitative behavior of these equations on time scales, so this paper initiates the study. Some examples are considered to illustrate the main results.
1. Introduction
The study of dynamic equations on time-scales, which goes back to its founder Hilger 1 , is an area of mathematics that has recently received a lot of attention. It has been created in order to unify the study of differential and difference equations. Many results concerning differential equations carry over quite easily to corresponding results for difference equations, while other results seem to be completely different from their continuous counterparts. The study of dynamic equations on time-scales reveals such discrepancies, and helps avoid proving results twice—once for differential equations and once again for difference equations.
Several authors have expounded on various aspects of this new theory; see the survey paper by Agarwal et al.2 , Bohner and Guseinov3 , and references cited therein. A book
on the subject of time-scales, by Bohner and Peterson4 , summarizes and organizes much of the time-scale calculus; see also the book by Bohner and Peterson5 for advances in dynamic equations on time-scales.
In the recent years, there has been increasing interest in obtaining sufficient conditions for the oscillation and nonoscillation of solutions of various equations on time-scales; we refer the reader to the papers6–38 . To the best of our knowledge, it seems to have few oscillation results for the oscillation of third-order dynamic equations; see, for example,14–
16,21,35 . However, the paper which deals with the third-order delay dynamic equation is due to Hassan21 .
Hassan21 considered the third-order nonlinear delay dynamic equations ct
atxΔtΔγΔ
ft, xτt 0, t∈T, 1.1
whereτσt στtis required, and the author established some oscillation criteria for 1.1which extended the results given in16 .
To the best of our knowledge, there are no results regarding the oscillation of the solutions of the following third-order nonlinear neutral delay dynamic equations on time- scales up to now:
rtxt−atxτtΔΔΔ
ptxγδt 0, t∈T. 1.2
We assume thatγ > 0 is a quotient of odd positive integers, r, aandp are positive real-valued rd-continuous functions defined on T such that rΔt ≥ 0, 0 < at ≤ a0 <
1, limt→ ∞at a < 1,the delay functions τ : T → T, δ : T → T are rd-continuous functions such thatτt≤t, δt≤t,and limt→ ∞τt limt→ ∞δt ∞.
As we are interested in oscillatory behavior, we assume throughout this paper that the given time-scaleTis unbounded above. We assumet0 ∈ Tand it is convenient to assume t0>0.We define the time-scale interval of the formt0,∞Tbyt0,∞T t0,∞∩T.
For the oscillation of neutral delay dynamic equations on time-scales, Mathsen et al.
26 considered the first-order neutral delay dynamic equations on time-scales yt−rtyτtΔ
ptyδt 0, t∈T, 1.3
and established some new oscillation criteria of1.3which as a special case involve some well-known oscillation results for first-order neutral delay differential equations.
Agarwal et al.7 , S¸ah´ıner28 , Saker31 , Saker et al.33 , Wu et al.34 studied the second-order nonlinear neutral delay dynamic equations on time-scales
rtyt ptyτtΔγΔ
f
t, yδt
0, t∈T, 1.4
by means of Riccati transformation technique, the authors established some oscillation criteria of1.4.
Saker 32 investigated the second-order neutral Emden-Fowler delay dynamic equations on time-scales
atyt rtyτtΔ Δptyγδt 0, t∈T, 1.5
and established some new oscillation for1.5.
Our purpose in this paper is motivated by the question posed in 26 : What can be said about higher-order neutral dynamic equations on time-scales and the various generalizations? We refer the reader to the articles23,24 and we will consider the particular case when the order is 3, that is, 1.2. Set t−1 : mint∈t0,∞T{τt, δt}. By a solution of 1.2, we mean a nontrivial real-valued functionx∈Crdt−1,∞T,Rsatisfyingx−ax◦τ ∈ C2rdt0,∞T,Randrx−ax◦τΔΔ∈C1rdt0,∞T,R,and satisfying1.2for allt∈t0,∞T. The paper is organized as follows. In Section 2, we apply a simple consequence of Keller’s chain rule, devoted to the proof of the sufficient conditions which guarantee that every solution of 1.2 oscillates or converges to zero. In Section 3, some examples are considered to illustrate the main results.
2. Main Results
In this section we give some new oscillation criteria for1.2. In order to prove our main results, we will use the formula
xtγΔ γ
1
0
hxσt 1−hxt γ−1xΔtdh, 2.1
where x is delta differentiable and eventually positive or eventually negative, which is a simple consequence of Keller’s chain rulesee Bohner and Peterson4, Theorem 1.90 .
Before stating our main results, we begin with the following lemmas which are crucial in the proofs of the main results.
For the sake of convenience, we denote:zt xt−atxτt,fort∈t0,∞T.Also, we assume that
Hthere exists{ck}k∈N0⊂Tsuch that limk→ ∞ck∞andτck1 ck.
Lemma 2.1. Assume thatHholds. Further, assume thatxis an eventually positive solution of 1.2. If
∞
t0
Δt
rt ∞, 2.2
then there are only the following three cases fort≥t1sufficiently large:
izt>0,zΔt>0,zΔΔt>0,zΔΔΔt<0,
iizt<0, zΔt>0, zΔΔt>0, zΔΔΔt<0, limt→ ∞xt 0, or
iiizt > 0, zΔt < 0, zΔΔt > 0, zΔΔΔt < 0, limt→ ∞zt l ≥ 0, limt→ ∞xt l/1−a≥0.
Proof. Letx be an eventually positive solution of 1.2. Then there exists t1 ≥ t0 such that xt>0, xτt>0,andxδt>0 for allt≥t1.From1.2we have
rtzΔΔtΔ
−ptxγδt<0, t≥t1. 2.3
Hence rtzΔΔt is strictly decreasing on t1,∞T. We claim that zΔΔt > 0 eventually.
Assume not, then there existst2≥t1such that
rtzΔΔt<0, t≥t2. 2.4
Then we can choose a negativecandt3≥t2such that
rtzΔΔt≤c <0, t≥t3. 2.5
Dividing byrtand integrating fromt3tot,we have
zΔt≤zΔt3 c t
t3
Δs
rs. 2.6
Lettingt → ∞,thenzΔt → −∞by2.2. Thus, there is at4≥t3such that fort≥t4,
zΔt≤zΔt4<0. 2.7
Integrating the previous inequality fromt4tot,we obtain
zt−zt4≤zΔt4t−t4. 2.8
Therefore, there existd >0 andt5≥t4such that
xt≤ −datxτt≤ −da0xτt, t≥t5. 2.9
We can choose some positive integerk0such thatck≥t5,fork≥k0.Thus, we obtain xck≤ −da0xτck −da0xck−1≤ −d−a0da20xτck−1
−d−a0da20xck−2≤ · · · ≤ −d−a0d− · · · −ak−k0 0−1dak−k0 0xτck01 −d−a0d− · · · −ak−k0 0−1dak−k0 0xck0.
2.10
The above inequality implies thatxck<0 for sufficiently largek,which contradicts the fact thatxt>0 eventually. Hence we get
zΔΔt>0. 2.11
It follows from this that eitherzΔt>0 orzΔt<0.SincerΔt≥0, rtzΔΔtΔ
rΔtzΔΔt rσtzΔΔΔt<0, 2.12
which yields
zΔΔΔt<0. 2.13
IfzΔt>0,then there are two possible cases:
1zt>0,eventually; or 2zt<0,eventually.
If there exists a t6 ≥ t1 such that case 2 holds, then limt→ ∞zt exists, and limt→ ∞zt b ≤ 0. We claim that limt→ ∞zt 0.Otherwise, limt→ ∞zt b < 0.We can choose some positive integerk0such thatck≥t6,fork≥k0.Thus, we obtain
xck≤a0xτck a0xck−1≤a20xτck−1
a20xck−2≤ · · · ≤ak−k0 0xτck01 ak−k0 0xck0, 2.14
which implies that limk→ ∞xck 0,and from the definition ofzt,we have limk→ ∞zck
0,which contradicts limt→ ∞zt<0.Now, we assert thatxis bounded. If it is not true, there exists{sk}k∈N⊂t6,∞Twithsk → ∞ask → ∞such that
xsk sup
t0≤s≤sk
xs, lim
k→ ∞xsk ∞. 2.15
Fromτt≤t
zsk xsk−askxτsk≥1−a0xsk, 2.16
which implies that limk→ ∞zsk ∞,it contradicts that limt→ ∞zt 0.Therefore, we can assume that
lim sup
t→ ∞ xt x1, lim inf
t→ ∞ xt x2. 2.17
By 0≤a <1,we get
x1−ax1≤0≤x2−ax2, 2.18
which implies thatx1 ≤x2,sox1x2,hence, limt→ ∞xt 0.
Assume that zΔt < 0. We claim that zt ≥ 0 eventually. Otherwise, we have limt→ ∞zt<0 or limt→ ∞zt −∞.ByH,there existst7≥t1,we can choose some positive integerk0such thatck≥t7fork≥k0,and we obtain
xck≤a0xτck a0xck−1≤a20xτck−1
a20xck−2≤ · · · ≤ak−k0 0xτck01 ak−k0 0xck0, 2.19
which implies that limk→ ∞xck 0,and from the definition ofz,we have limk→ ∞zck 0, which contradicts limt→ ∞zt<0 or limt→ ∞zt −∞.Now, we have that limt→ ∞zt l≥0, herelis finite. We assert thatxis bounded. If it is not true, there exists{sk}k∈N⊂t6,∞Twith sk → ∞ask → ∞such that
xsk sup
t0≤s≤sk
xs, lim
k→ ∞xsk ∞. 2.20
Fromτt≤t
zsk xsk−askxτsk≥1−a0xsk, 2.21
which implies that limk→ ∞zsk ∞,it contradicts that limt→ ∞zt l ≥ 0.Therefore, we can assume that
lim sup
t→ ∞ xt x1∗, lim inf
t→ ∞ xt x2∗. 2.22
By 0≤a <1,we get
x1∗−ax1∗≤l≤x2∗−ax2∗, 2.23
which implies thatx1∗≤x2∗,sox1∗ x2∗,hence, limt→ ∞xt l/1−a≥0.This completes the proof.
In4, Section 1.6 the Taylor monomials{hnt, s}∞n0are defined recursively by
h0t, s 1, hn1t, s t
s
hnτ, sΔτ, t, s∈T, n≥1. 2.24
It follows from4, Section 1.6 thath1t, s t−sfor any time-scale, but simple formulas in general do not hold forn≥2.
Lemma 2.2see15, Lemma 4 . Assume thatzsatisfies case (i) ofLemma 2.1. Then
lim inf
t→ ∞
tzt
h2t, t0zΔt ≥1. 2.25
Lemma 2.3. Assume thatxis a solution of1.2satisfying case (i) ofLemma 2.1. If ∞
t0
pth2δt, t0γΔt∞, 2.26
thenzsatisfies eventually
zΔt≥tzΔΔt, zΔt
t is nonincreasing. 2.27
Proof. Letxbe a solution of1.2such that caseiofLemma 2.1holds fort≥t1.Define
Zt zΔt−tzΔΔt. 2.28
Thus
ZΔt −σtzΔΔΔt>0. 2.29
We claim thatZt>0 eventually. Otherwise, there existst2≥t1such thatZt<0 fort≥t2. Therefore,
zΔt t
Δ
−Zt
tσt >0, t≥t2, 2.30
which implies thatzΔt/tis strictly increasing ont2,∞T.Pickt3≥t2such thatδt≥δt3≥ t2,fort≥t3.Then we have
zΔδt
δt ≥ zΔδt3
δt3 P >0, 2.31
thenzΔδt≥P δtfort≥t3.ByLemma 2.2, for any 0< k <1,there existst4 ≥t3such that zt
zΔt ≥kh2t, t0
t , t≥t4. 2.32
Hence there existst5≥t4so that zδt≥kh2δt, t0
δt zΔδt≥P kh2δt, t0
δt δt P kh2δt, t0, t≥t5. 2.33
By the definition ofz,we have that
xt≥zt. 2.34
From1.2, we obtain
rtzΔΔtΔ
ptzγδt≤0. 2.35
Integrating both sides of2.35fromt5tot,we get
rtzΔΔt−rt5zΔΔt5 P kγ t
t5
psh2δs, t0γΔs≤0, 2.36
which yields that
rt5zΔΔt5≥P kγ t
t5
psh2δs, t0γΔs, 2.37
which contradicts2.26. HenceZt>0 andzΔt/tis nonincreasing. The proof is complete.
Lemma 2.4. Assume thatHholds andxis a solution of1.2which satisfies case (iii) ofLemma 2.1.
If
∞
t0
psRσsΔs∞, 2.38
whereRt:t
t0σu/ruΔufort∈t0,∞T,then limt→ ∞xt 0.
Proof. Let xbe a solution of1.2 such that caseiii of Lemma 2.1holds for t ≥ t1.Then limt→ ∞zt l ≥ 0, limt→ ∞xt l/1−a ≥0.Next we claim thatl 0.Otherwise, there existst2 ≥t1such thatzδt≥l >0 for allt≥t2.By the definition ofz,we have that2.35 holds. Integrating both sides of2.35fromtto∞,we get
zΔΔt≥ 1 rt
∞
t
pszγδsΔs. 2.39
Integrating again fromtto∞,we have
−zΔt≥ ∞
t
1 ru
∞
u
pszγδsΔsΔu. 2.40
Integrating again fromt2to∞,we obtain zt1≥
∞
t2
∞
v
1 ru
∞
u
pszγδsΔsΔuΔv≥lγ ∞
t2
∞
v
1 ru
∞
u
psΔsΔuΔv, 2.41
which contradicts2.38, since by23, Lemma 1 and3, Remark 4.7 , we get ∞
t0
∞
v
1 ru
∞
u
psΔsΔuΔv
∞
t0
∞
v
∞
u
1
rupsΔsΔuΔv
∞
t0
∞
v
σs
v
1
rupsΔuΔsΔv
∞
t0
σs
t0
σs
v
1
rupsΔuΔvΔs
∞
t0
ps σs
t0
σs
v
1
ruΔuΔvΔs ∞
t0
ps σs
t0
σu
t0
1
ruΔvΔuΔs
∞
t0
ps σs
t0
1 ru
σu
t0
ΔvΔuΔs
∞
t0
ps σs
t0
σu−t0
ru ΔuΔs
∞
t0
ps σs
t0
σu
ruΔuΔs
∞
t0
psRσsΔs.
2.42
Hence limt→ ∞xt 0 and completes the proof.
Theorem 2.5. Assume thatH,2.2,2.26, and2.38hold, γ ≥ 1.Furthermore, assume that there exists a positive functionη∈Crd1 t0,∞T,Rsuch that for some 0< k <1 and for all constants M >0
lim sup
t→ ∞
t
t0
ηspsζs− rs
ηΔs2
4kγMγ−1ηs
Δs∞, 2.43
whereζt: h2δt, t0/tγ.Then every solutionxof 1.2oscillates or limt→ ∞xt 0.
Proof. Suppose that 1.2 has a nonoscillatory solution x.We may assume without loss of generality thatxt>0, xτt>0,andxδt>0 for allt∈t1,∞T, t1 ∈t0,∞T.Then by Lemma 2.1,zsatisfies three cases. Assume thatzsatisfies casei.Define the functionωby
ωt ηtrtzΔΔt
zΔtγ , t∈t1,∞T. 2.44
Thenωt>0.Using the product rule, we have
ωΔt
rtzΔΔtσ ηt
zΔtγ
Δ
rtzΔΔtΔ ηt
zΔtγ. 2.45
By the quotient rule, we get
ωΔt
rtzΔΔtσηΔt zΔtγ
−ηt
zΔtγΔ zΔtγ
zΔσtγ
rtzΔΔtΔ ηt
zΔtγ. 2.46
By the definition ofzand1.2, we obtain2.35. From2.35and2.44, we have
ωΔt≤ ηΔt
ησtωσt−ηtptzγδt zΔtγ −ηt
rtzΔΔtσ
zΔtγΔ zΔtγ
zΔσtγ , 2.47
from2.25and2.27, for any 0< k <1,we obtain zγδt
zΔtγ zγδt zΔδtγ
zΔδtγ
zΔtγ ≥
k1/γh2δt, t0 δt
γδt t
γ k
h2δt, t0 t
γ , 2.48
hence by2.48, we have
ωΔt≤ ηΔt
ησtωσt−kηtptζt−ηt
rtzΔΔtσ
zΔtγΔ zΔtγ
zΔσtγ . 2.49
In view ofγ ≥1,from2.1andiofLemma 2.1, we have
zΔtγΔ γ
1
0
hzΔσt 1−hzΔt γ−1zΔΔtdh
≥γ
zΔtγ−1
zΔΔt≥γMγ−1zΔΔt,
2.50
whereMzΔt1.By2.49, we have
ωΔt≤ ηΔt
ησtωσt−kηtptζt−γMγ−1ηt
rtzΔΔtσ 2
zΔtγ
zΔσtγ zΔΔt
rσtzΔΔσt, 2.51
fromi,we havezΔt≤zΔσt,byrtzΔΔtΔ<0,we have
zΔΔt≥ rσt
rt zΔΔσt, 2.52
so we get
ωΔt≤ ηΔt
ησtωσt−kηtptζt−γMγ−1ηt
rtzΔΔtσ 2
rt
zΔσtγ2, 2.53 by2.44, we have
ωΔt≤ ηΔt
ησtωσt−kηtptζt−γMγ−1 ηt
rt
ησt2ωσt2. 2.54 Therefore, we obtain
ωΔt≤ −kηtptζt rt ηΔt2
4γMγ−1ηt. 2.55
Integrating inequality2.55fromt1tot, we obtain
−ωt1≤ωt−ωt1≤ − t
t1
kηspsζs−rs
ηΔs2
4γMγ−1ηs
Δs, 2.56
which yields
t
t1
kηspsζs−rs
ηΔs2
4γMγ−1ηs
Δs≤ωt1 2.57
for all larget,which contradicts2.43. Ifiiholds, fromLemma 2.1, then limt→ ∞xt 0.If caseiiiholds, byLemma 2.4, then limt→ ∞xt 0.The proof is complete.
Remark 2.6. From Theorem 2.5, we can obtain different conditions for oscillation of all solutions of1.2with different choices ofη.
For example, letηt t.NowTheorem 2.5yields the following result.
Corollary 2.7. Assume thatH,2.2,2.26, and2.38hold,γ≥1.If
lim sup
t→ ∞
t
t0
sps
h2δs, t0 s
γ
− rs 4kγMγ−1s
Δs∞ 2.58
holds for some 0 < k < 1 and for all constantsM > 0, then every solution xof 1.2 is either oscillatory or limt→ ∞xt 0.
For example, letηt 1.FromTheorem 2.5, we have the following result which can be considered as the extension of the Leighton-Wintner Theorem.
Corollary 2.8. Assume thatH,2.2,2.26, and2.38hold, andγ ≥1.If
lim sup
t→ ∞
t
t0
ps
h2δs, t0 s
γ
Δs∞, 2.59
then every solutionxof1.2is either oscillatory or limt→ ∞xt 0.
In the following theorem, we present a new Kamenev-type oscillation criteria for1.2.
Theorem 2.9. Assume thatH,2.2,2.26, and2.38hold,γ ≥1.Letζandηbe as defined in Theorem 2.5. If for some 0< k <1 and for all constantsM >0
lim sup
t→ ∞
1 tm
t
t0
t−smηspsζs− rsB2t, s ησs2 4kγMγ−1ηst−sm
Δs∞, 2.60
wherem >1,and
Bt, s t−smηΔs
ησs −mt−σsm−1, t≥σs≥t0, 2.61 then every solutionxof1.2oscillates or limt→ ∞xt 0.
Proof. Suppose that 1.2 has a nonoscillatory solution x.We may assume without loss of generality thatxt>0, xτt>0,andxδt>0 for allt∈t1,∞T, t1∈t0,∞T.Then by Lemma 2.1,zsatisfies three cases. Assume thatzsatisfies casei.We proceed as in the proof ofTheorem 2.5to get2.54for allt≥t1sufficiently large. Multiplying2.54byt−smand integrating fromt1tot,we have
t
t1
t−smkηspsζsΔs≤ − t
t1
t−smωΔsΔs t
t1
t−smηΔs
ησsωσsΔs
− t
t1
t−smγMγ−1ηs
rs
ησs2 ωσs2Δs.
2.62
Integration by parts, we obtain
− t
t1
t−smωΔsΔs−t−smωs|tt1 t
t1
t−smΔs
ωσsΔs. 2.63
Next, we show that ift≥σsandm≥1,then t−smΔs
≤ −mt−σsm−1. 2.64
Ifμs 0,it is easy to see that2.64is an equality. Ifμs>0,then we get t−smΔs
1 μs
t−σsm−t−sm
− 1 σs−s
t−sm−t−σsm
. 2.65
Using the inequality
xm−ym≥mym−1 x−y
, x≥y >0, m≥1, 2.66
we obtain fort≥σs
t−sm−t−σsm
≥mt−σsm−1σs−s, 2.67 and from this we see that2.64holds. From2.62–2.64, we get
t
t1
t−smkηspsζsΔs
≤t−t1mωt1
t
t1
t−smηΔs
ησs −mt−σsm−1
ωσsΔs
− t
t1
t−smγMγ−1ηs
rs
ησs2 ωσs2Δs.
2.68
Thus t
t1
t−smηspsζs− rsB2t, s ησs2 4kγMγ−1ηst−sm
Δs≤ 1
kωt1t−t1m, 2.69 which implies that
1 tm
t
t1
t−smηspsζs− rsB2t, s ησs2 4kγMγ−1ηst−sm
Δs≤ 1
kωt1 t−t1
t m
. 2.70
This easily leads to a contradiction of2.60. Ifiiholds, fromLemma 2.1, then limt→ ∞xt 0.Ifiiiholds, byLemma 2.4, then limt→ ∞xt 0.The proof is complete.
In the following theorem, we present a new Philos-type oscillation criteria for1.2.
Theorem 2.10. Assume thatH,2.2,2.26, and2.38hold,γ≥1.Letζandηbe as defined in Theorem 2.5. Furthermore, assume that there exist functionsH,h∈CrdD,R, whereD≡ {t, s: t≥s≥t0}such that
Ht, t 0, t≥t0, Ht, s>0, t > s≥t0, 2.71 andHhas a nonpositive continuousΔ-partial derivationHΔst, swith respect to the second variable and satisfies
HΔst, s Ht, sηΔs
ησs −ht, s ησs
Ht, s. 2.72
If for some 0< k <1 and for all constantsM >0 lim sup
t→ ∞
1 Ht, t0
t
t0
Kt, sΔs∞, 2.73
where
Kt, s Ht, sηspsζs−rsh−t, s2
4kγMγ−1ηs, 2.74
whereh−t, s max{0,−ht, s},then every solutionxof 1.2oscillates or limt→ ∞xt 0.
Proof. Suppose that 1.2 has a nonoscillatory solution x.We may assume without loss of generality thatxt>0, xτt>0,andxδt>0 for allt∈t1,∞T, t1∈t0,∞T.Then by Lemma 2.1,zsatisfies three cases. Assume thatzsatisfies casei.We proceed as in the proof ofTheorem 2.5to get2.54for allt ≥ t1sufficiently large. Multiplying both sides of2.54, withtreplaced bys,byHt, s,integrating with respect tosfromt1tot,we have
t
t1
kHt, sηspsζsΔs
≤ − t
t1
Ht, sωΔsΔs t
t1
Ht, sηΔs
ησsωσsΔs− t
t1
Ht, s γMγ−1ηs
rs
ησs2ωσs2Δs.
2.75
Integrating by parts and using2.71and2.72, we obtain t
t1
kHt, sηspsζsΔs
≤Ht, t1ωt1
t
t1
HΔst, sωσsΔs t
t1
Ht, sηΔs
ησsωσsΔs
− t
t1
Ht, s γMγ−1ηs rs
ησs2ωσs2Δs
≤Ht, t1ωt1 t
t1
−ht, s ησs
Ht, sωσs−Ht, s γMγ−1ηs
rs
ησs2ωσs2
Δs
≤Ht, t1ωt1 t
t1
h−t, s ησs
Ht, sωσs−Ht, s γMγ−1ηs
rs
ησs2ωσs2
Δs
≤Ht, t1ωt1
t
t1
rsh−t, s2 4γMγ−1ηs Δs.
2.76
Therefore, we get t
t1
Ht, sηspsζs−rsh−t, s2 4kγMγ−1ηs
Δs≤ 1
kHt, t1ωt1. 2.77
This easily leads to a contradiction of 2.73. If case ii holds, from Lemma 2.1, then limt→ ∞xt 0. If case iii holds, by Lemma 2.4, then limt→ ∞xt 0. The proof is complete.
The following result can be considered as the extension of the Atkinson’s theorem39 . Theorem 2.11. Assume thatH,2.2,2.26, and2.38hold,γ >1.If
lim sup
t→ ∞
t
t0
ps
rsσs
h2δs, t0 σs
γ
Δs∞, 2.78
then every solutionxof1.2is either oscillatory or limt→ ∞xt 0.
Proof. Suppose that 1.2 has a nonoscillatory solution x.We may assume without loss of generality thatxt>0, xτt>0 andxδt>0 for allt∈t1,∞T, t1∈t0,∞T.Then by Lemma 2.1,zsatisfies three cases. Assume thatzsatisfies casei.Define the functionω
ωt trtzΔΔt
zΔtγ , t∈t1,∞T. 2.79
Using the product rule,2.25and2.27, for any 0< k <1,we have that
zγδt
zΔσtγ zγδt zΔδtγ
zΔδtγ
zΔσtγ ≥
k1/γh2δt, t0 δt
γδt σt
γ
k
h2δt, t0 σt
γ
. 2.80
By1.2, we have that2.35holds, then from2.80, we calculate
ωΔt
rtzΔΔt σt
rtzΔΔtΔ
zΔσt−γ
trtzΔΔt
zΔt−γΔ
≤rtzΔΔt
zΔσt−γ
−σtpt
zδt zΔσt
γ
trtzΔΔt
zΔt−γΔ
≤rt
zΔt1−γΔ
1−γ −kσtpt
h2δt, t0 σt
γ
,
2.81
where the last inequality is true becausezΔt−γΔ≤0 due to2.1and because zΔt1−γΔ
1−γ1
0
hzΔσt 1−hzΔt −γzΔΔtdh
≤
1−γ1
0
hzΔσt 1−hzΔσt −γzΔΔtdh
1−γ
zΔσt−γ zΔΔt.
2.82
Upon integration we arrive at
t
t1
kσsps
rs
h2δs, t0 σs
γ
Δs≤ t
t1
zΔs1−γΔ 1−γ Δs−
t
t1
ωΔs
rs Δs
zΔt1−γ 1−γ −
zΔt11−γ 1−γ −
t
t1
ωΔs
rs Δs
≤
zΔt11−γ
γ−1 ωt1 rt1 −ωt
rt
t
t1
ωσs 1
rs Δ
Δs
≤
zΔt11−γ
γ−1 ωt1 rt1
2.83
fromrΔt≥0.This contradicts2.78. If caseiiholds, fromLemma 2.1, then limt→ ∞xt 0.If caseiiiholds, byLemma 2.4, then limt→ ∞xt 0.The proof is complete.
Theorem 2.12. Assume thatH,2.2,2.26, and2.38hold,γ ≤ 1.Furthermore, assume that there exists a positive functionη∈Crd1 t0,∞T,Rsuch that for some 0< k <1 and for all constants L >0
lim sup
t→ ∞
t
t0
ηspsζs− rs
ηΔs2
4kγLσsγ−1ηs
Δs∞, 2.84
where ζ is as defined as in Theorem 2.5. Then every solution x of 1.2 is either oscillatory or limt→ ∞xt 0.
Proof. Suppose that 1.2 has a nonoscillatory solution x.We may assume without loss of generality thatxt>0, xτt>0 andxδt>0 for allt1t∈t1,∞T, ∈t0,∞T.Then by Lemma 2.1,zsatisfies three cases. Assumezsatisfies casei.Define the functionωas2.44.
We proceed as in the proof ofTheorem 2.5and we get2.49. In view ofγ≤1,from2.1and iofLemma 2.1, we have
zΔtγΔ γ
1
0
hzΔσt 1−hzΔt γ−1zΔΔtdh
≥γ
zΔσtγ−1 zΔΔt,
2.85
from2.27, there exists a constantL >0 such thatzΔt≤Lt,so
zΔtγΔ
≥γLσtγ−1zΔΔt. 2.86 By2.49, we have
ωΔt≤ ηΔt
ησtωσt−kηtptζt−γLσtγ−1 ηt
rt
ησt2ωσt2. 2.87 Therefore, we obtain
ωΔt≤ −kηtptζt rt ηΔt2
4γLσtγ−1ηt. 2.88
Integrating inequality2.88fromt1tot, we obtain
−ωt1≤ωt−ωt1≤ − t
t1
kηspsζs− rs
ηΔs2 4γLσsγ−1ηs
Δs, 2.89
which yields
t
t1
kηspsζs− rs
ηΔs2
4γLσsγ−1ηs
Δs≤ωt1 2.90
for all larget,which contradicts2.84. If caseiiholds, fromLemma 2.1, then limt→ ∞xt 0.If caseiiiholds, byLemma 2.4, then limt→ ∞xt 0.The proof is complete.
Remark 2.13. From Theorem 2.12, we can obtain different conditions for oscillation of all solutions of1.2with different choices ofη.
For example, letηt t.NowTheorem 2.12yields the following results.
Corollary 2.14. Assume thatH,2.2,2.26, and2.38hold,γ≤1.If
lim sup
t→ ∞
t
t0
sps
h2δs, t0 s
γ
− rs
4kγLσsγ−1s
Δs∞ 2.91
holds for some 0< k <1 and for all constantsL >0,then every solutionxof1.2is either oscillatory or limt→ ∞xt 0.
For example, letηt 1.FromTheorem 2.12, we have the following result which can be considered as the extension of the Leighton-Wintner theorem.
Corollary 2.15. Assume thatH,2.2,2.26, and2.38hold,γ ≤1.If 2.59holds, then every solutionxof 1.2is either oscillatory or limt→ ∞xt 0.
In the following theorem, we present a new Kamenev-type oscillation criteria for1.2.
Theorem 2.16. Assume thatH,2.2,2.26, and2.38hold,γ≤1.Letζandηbe as defined in Theorem 2.12. If for some 0< k <1 and for all constantsL >0
lim sup
t→ ∞
1 tm
t
t0
t−smηspsζs− rsB2t, s ησs2
4kγLσsγ−1ηst−sm
Δs∞, 2.92
wherem >1,and
Bt, s t−smηΔs
ησs −mt−σsm−1, t≥σs≥t0, 2.93 then every solutionxof1.2oscillates or limt→ ∞xt 0.
The proof is similar to that of Theorem 2.9using inequality 2.88, so we omit the details.
In the following theorem, we present a new Philos-type oscillation criteria for1.2.
Theorem 2.17. Assume thatH,2.2,2.26, and2.38hold,γ≤1.Letζandηbe as defined in Theorem 2.12. Furthermore, assume that there exist functionsH,h∈CrdD,R, whereD≡ {t, s: t≥s≥t0}such that2.71holds, andHhas a nonpositive continuousΔ-partial derivationHΔst, s with respect to the second variable and satisfies2.72. If
lim sup
t→ ∞
1 Ht, t0
t
t0
Kt, sΔs∞ 2.94
holds for some 0< k <1 and for all constantsL >0,where
Kt, s Ht, sηspsζs− rsh−t, s2
4kγLσsγ−1ηs, 2.95
whereh−t, s max{0,−ht, s}.Then every solutionxof1.2oscillates or limt→ ∞xt 0.
The proof is similar to that of the proof ofTheorem 2.10using inequality2.88, so we omit the details.
The following result can be considered as the extension of the Belohorec’s theorem 40 .
Theorem 2.18. Assume thatH,2.2,2.26, and2.38holdγ <1.If
lim sup
t→ ∞
t
t0
ps
rγδsh2δs, t0γΔs∞, 2.96
then every solutionxof1.2is either oscillatory or satisfies limt→ ∞xt 0.
Proof. Suppose that 1.2 has a nonoscillatory solution x.We may assume without loss of generality thatxt>0, xτt>0,andxδt>0 for allt1t∈t1,∞T, ∈t0,∞T.Then by Lemma 2.1,zsatisfies three cases. Assume thatzsatisfies casei.Fromiand2.1we have
rtzΔΔt1−γΔ
1−γ1
0
hrtzΔΔtσ 1−hrtzΔΔt −γ
rtzΔΔtΔ dh
≤
1−γ1
0
hrtzΔΔt 1−hrtzΔΔt −γ
rtzΔΔtΔ dh
1−γ
rtzΔΔt−γ
rtzΔΔtΔ ,
2.97
so
rtzΔΔt−γ
rtzΔΔtΔ
≥
rtzΔΔt1−γΔ
1−γ . 2.98
By1.2, we have that2.35holds. Using2.25and2.27, for any 0< k <1,we obtain after dividing2.35byrtzΔΔtγfor all larget
0≥
rtzΔΔtΔ
ptzγδt rtzΔΔtγ
rtzΔΔt−γ
rtzΔΔtΔ pt
zδt rtzΔΔt
γ
≥
rtzΔΔt1−γΔ
1−γ pt
rγδt
zδt zΔδt
zΔδt zΔΔδt
γ
≥
rtzΔΔt1−γΔ
1−γ pt
rγδt
kh2δt, t0
δt δt
γ
rtzΔΔt1−γΔ
1−γ kγ pt
rγδth2δt, t0γ.
2.99