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Advances in Difference Equations Volume 2010, Article ID 586312,23pages doi:10.1155/2010/586312

Research Article

Oscillation Behavior of Third-Order

Neutral Emden-Fowler Delay Dynamic Equations on Time Scales

Zhenlai Han,

1, 2

Tongxing Li,

1

Shurong Sun,

1, 3

and Chenghui Zhang

2

1School of Science, University of Jinan, Jinan, Shandong 250022, China

2School of Control Science and Engineering, Shandong University, Jinan, Shandong 250061, China

3Department of Mathematics and Statistics, Missouri University of Science and Technology, Rolla, MO 65409-0020, USA

Correspondence should be addressed to Shurong Sun,[email protected]

Received 14 September 2009; Revised 28 November 2009; Accepted 10 December 2009 Academic Editor: Leonid Berezansky

Copyrightq2010 Zhenlai Han et al. This is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited.

We will establish some oscillation criteria for the third-order Emden-Fowler neutral delay dynamic equationsrtxt−atxτtΔΔΔptxγδt 0 on a time scaleT, whereγ > 0 is a quotient of odd positive integers withr,a,andpreal-valued positive rd-continuous functions defined onT. To the best of our knowledge nothing is known regarding the qualitative behavior of these equations on time scales, so this paper initiates the study. Some examples are considered to illustrate the main results.

1. Introduction

The study of dynamic equations on time-scales, which goes back to its founder Hilger 1 , is an area of mathematics that has recently received a lot of attention. It has been created in order to unify the study of differential and difference equations. Many results concerning differential equations carry over quite easily to corresponding results for difference equations, while other results seem to be completely different from their continuous counterparts. The study of dynamic equations on time-scales reveals such discrepancies, and helps avoid proving results twice—once for differential equations and once again for difference equations.

Several authors have expounded on various aspects of this new theory; see the survey paper by Agarwal et al.2 , Bohner and Guseinov3 , and references cited therein. A book

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on the subject of time-scales, by Bohner and Peterson4 , summarizes and organizes much of the time-scale calculus; see also the book by Bohner and Peterson5 for advances in dynamic equations on time-scales.

In the recent years, there has been increasing interest in obtaining sufficient conditions for the oscillation and nonoscillation of solutions of various equations on time-scales; we refer the reader to the papers6–38 . To the best of our knowledge, it seems to have few oscillation results for the oscillation of third-order dynamic equations; see, for example,14–

16,21,35 . However, the paper which deals with the third-order delay dynamic equation is due to Hassan21 .

Hassan21 considered the third-order nonlinear delay dynamic equations ct

atxΔtΔγΔ

ft, xτt 0, t∈T, 1.1

whereτσt στtis required, and the author established some oscillation criteria for 1.1which extended the results given in16 .

To the best of our knowledge, there are no results regarding the oscillation of the solutions of the following third-order nonlinear neutral delay dynamic equations on time- scales up to now:

rtxt−atxτtΔΔΔ

ptxγδt 0, t∈T. 1.2

We assume thatγ > 0 is a quotient of odd positive integers, r, aandp are positive real-valued rd-continuous functions defined on T such that rΔt ≥ 0, 0 < at ≤ a0 <

1, limt→ ∞at a < 1,the delay functions τ : T → T, δ : T → T are rd-continuous functions such thatτt≤t, δt≤t,and limt→ ∞τt limt→ ∞δt ∞.

As we are interested in oscillatory behavior, we assume throughout this paper that the given time-scaleTis unbounded above. We assumet0 ∈ Tand it is convenient to assume t0>0.We define the time-scale interval of the formt0,∞Tbyt0,∞T t0,∞∩T.

For the oscillation of neutral delay dynamic equations on time-scales, Mathsen et al.

26 considered the first-order neutral delay dynamic equations on time-scales yt−rtyτtΔ

ptyδt 0, t∈T, 1.3

and established some new oscillation criteria of1.3which as a special case involve some well-known oscillation results for first-order neutral delay differential equations.

Agarwal et al.7 , S¸ah´ıner28 , Saker31 , Saker et al.33 , Wu et al.34 studied the second-order nonlinear neutral delay dynamic equations on time-scales

rtyt ptyτtΔγΔ

f

t, yδt

0, t∈T, 1.4

by means of Riccati transformation technique, the authors established some oscillation criteria of1.4.

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Saker 32 investigated the second-order neutral Emden-Fowler delay dynamic equations on time-scales

atyt rtyτtΔ Δptyγδt 0, t∈T, 1.5

and established some new oscillation for1.5.

Our purpose in this paper is motivated by the question posed in 26 : What can be said about higher-order neutral dynamic equations on time-scales and the various generalizations? We refer the reader to the articles23,24 and we will consider the particular case when the order is 3, that is, 1.2. Set t−1 : mint∈t0,∞T{τt, δt}. By a solution of 1.2, we mean a nontrivial real-valued functionx∈Crdt−1,∞T,Rsatisfyingx−ax◦τ ∈ C2rdt0,∞T,Randrx−ax◦τΔΔ∈C1rdt0,∞T,R,and satisfying1.2for allt∈t0,∞T. The paper is organized as follows. In Section 2, we apply a simple consequence of Keller’s chain rule, devoted to the proof of the sufficient conditions which guarantee that every solution of 1.2 oscillates or converges to zero. In Section 3, some examples are considered to illustrate the main results.

2. Main Results

In this section we give some new oscillation criteria for1.2. In order to prove our main results, we will use the formula

xtγΔ γ

1

0

hxσt 1−hxt γ−1xΔtdh, 2.1

where x is delta differentiable and eventually positive or eventually negative, which is a simple consequence of Keller’s chain rulesee Bohner and Peterson4, Theorem 1.90 .

Before stating our main results, we begin with the following lemmas which are crucial in the proofs of the main results.

For the sake of convenience, we denote:zt xt−atxτt,fort∈t0,∞T.Also, we assume that

Hthere exists{ck}k∈N0⊂Tsuch that limk→ ∞ck∞andτck1 ck.

Lemma 2.1. Assume thatHholds. Further, assume thatxis an eventually positive solution of 1.2. If

∞

t0

Δt

rt ∞, 2.2

then there are only the following three cases fort≥t1sufficiently large:

izt>0,zΔt>0,zΔΔt>0,zΔΔΔt<0,

iizt<0, zΔt>0, zΔΔt>0, zΔΔΔt<0, limt→ ∞xt 0, or

iiizt > 0, zΔt < 0, zΔΔt > 0, zΔΔΔt < 0, limt→ ∞zt l ≥ 0, limt→ ∞xt l/1−a≥0.

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Proof. Letx be an eventually positive solution of 1.2. Then there exists t1 ≥ t0 such that xt>0, xτt>0,andxδt>0 for allt≥t1.From1.2we have

rtzΔΔtΔ

−ptxγδt<0, t≥t1. 2.3

Hence rtzΔΔt is strictly decreasing on t1,∞T. We claim that zΔΔt > 0 eventually.

Assume not, then there existst2≥t1such that

rtzΔΔt<0, t≥t2. 2.4

Then we can choose a negativecandt3≥t2such that

rtzΔΔt≤c <0, t≥t3. 2.5

Dividing byrtand integrating fromt3tot,we have

zΔt≤zΔt3 c t

t3

Δs

rs. 2.6

Lettingt → ∞,thenzΔt → −∞by2.2. Thus, there is at4≥t3such that fort≥t4,

zΔt≤zΔt4<0. 2.7

Integrating the previous inequality fromt4tot,we obtain

zt−zt4≤zΔt4t−t4. 2.8

Therefore, there existd >0 andt5≥t4such that

xt≤ −datxτt≤ −da0xτt, t≥t5. 2.9

We can choose some positive integerk0such thatck≥t5,fork≥k0.Thus, we obtain xck≤ −da0xτck −da0xck−1≤ −d−a0da20xτck−1

−d−a0da20xck−2≤ · · · ≤ −d−a0d− · · · −ak−k0 0−1dak−k0 0xτck01 −d−a0d− · · · −ak−k0 0−1dak−k0 0xck0.

2.10

The above inequality implies thatxck<0 for sufficiently largek,which contradicts the fact thatxt>0 eventually. Hence we get

zΔΔt>0. 2.11

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It follows from this that eitherzΔt>0 orzΔt<0.SincerΔt≥0, rtzΔΔtΔ

rΔtzΔΔt rσtzΔΔΔt<0, 2.12

which yields

zΔΔΔt<0. 2.13

IfzΔt>0,then there are two possible cases:

1zt>0,eventually; or 2zt<0,eventually.

If there exists a t6 ≥ t1 such that case 2 holds, then limt→ ∞zt exists, and limt→ ∞zt b ≤ 0. We claim that limt→ ∞zt 0.Otherwise, limt→ ∞zt b < 0.We can choose some positive integerk0such thatck≥t6,fork≥k0.Thus, we obtain

xck≤a0xτck a0xck−1≤a20xτck−1

a20xck−2≤ · · · ≤ak−k0 0xτck01 ak−k0 0xck0, 2.14

which implies that limk→ ∞xck 0,and from the definition ofzt,we have limk→ ∞zck

0,which contradicts limt→ ∞zt<0.Now, we assert thatxis bounded. If it is not true, there exists{sk}k∈N⊂t6,∞Twithsk → ∞ask → ∞such that

xsk sup

t0≤s≤sk

xs, lim

k→ ∞xsk ∞. 2.15

Fromτt≤t

zsk xsk−askxτsk≥1−a0xsk, 2.16

which implies that limk→ ∞zsk ∞,it contradicts that limt→ ∞zt 0.Therefore, we can assume that

lim sup

t→ ∞ xt x1, lim inf

t→ ∞ xt x2. 2.17

By 0≤a <1,we get

x1−ax1≤0≤x2−ax2, 2.18

which implies thatx1 ≤x2,sox1x2,hence, limt→ ∞xt 0.

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Assume that zΔt < 0. We claim that zt ≥ 0 eventually. Otherwise, we have limt→ ∞zt<0 or limt→ ∞zt −∞.ByH,there existst7≥t1,we can choose some positive integerk0such thatck≥t7fork≥k0,and we obtain

xck≤a0xτck a0xck−1≤a20xτck−1

a20xck−2≤ · · · ≤ak−k0 0xτck01 ak−k0 0xck0, 2.19

which implies that limk→ ∞xck 0,and from the definition ofz,we have limk→ ∞zck 0, which contradicts limt→ ∞zt<0 or limt→ ∞zt −∞.Now, we have that limt→ ∞zt l≥0, herelis finite. We assert thatxis bounded. If it is not true, there exists{sk}k∈N⊂t6,∞Twith sk → ∞ask → ∞such that

xsk sup

t0≤s≤sk

xs, lim

k→ ∞xsk ∞. 2.20

Fromτt≤t

zsk xsk−askxτsk≥1−a0xsk, 2.21

which implies that limk→ ∞zsk ∞,it contradicts that limt→ ∞zt l ≥ 0.Therefore, we can assume that

lim sup

t→ ∞ xt x1∗, lim inf

t→ ∞ xt x2∗. 2.22

By 0≤a <1,we get

x1∗−ax1∗≤l≤x2∗−ax2∗, 2.23

which implies thatx1∗≤x2∗,sox1∗ x2∗,hence, limt→ ∞xt l/1−a≥0.This completes the proof.

In4, Section 1.6 the Taylor monomials{hnt, s}∞n0are defined recursively by

h0t, s 1, hn1t, s t

s

hnτ, sΔτ, t, s∈T, n≥1. 2.24

It follows from4, Section 1.6 thath1t, s t−sfor any time-scale, but simple formulas in general do not hold forn≥2.

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Lemma 2.2see15, Lemma 4 . Assume thatzsatisfies case (i) ofLemma 2.1. Then

lim inf

t→ ∞

tzt

h2t, t0zΔt ≥1. 2.25

Lemma 2.3. Assume thatxis a solution of1.2satisfying case (i) ofLemma 2.1. If ∞

t0

pth2δt, t0γΔt∞, 2.26

thenzsatisfies eventually

zΔt≥tzΔΔt, zΔt

t is nonincreasing. 2.27

Proof. Letxbe a solution of1.2such that caseiofLemma 2.1holds fort≥t1.Define

Zt zΔt−tzΔΔt. 2.28

Thus

ZΔt −σtzΔΔΔt>0. 2.29

We claim thatZt>0 eventually. Otherwise, there existst2≥t1such thatZt<0 fort≥t2. Therefore,

zΔt t

Δ

−Zt

tσt >0, t≥t2, 2.30

which implies thatzΔt/tis strictly increasing ont2,∞T.Pickt3≥t2such thatδt≥δt3≥ t2,fort≥t3.Then we have

zΔδt

δt ≥ zΔδt3

δt3 P >0, 2.31

thenzΔδt≥P δtfort≥t3.ByLemma 2.2, for any 0< k <1,there existst4 ≥t3such that zt

zΔt ≥kh2t, t0

t , t≥t4. 2.32

Hence there existst5≥t4so that zδt≥kh2δt, t0

δt zΔδt≥P kh2δt, t0

δt δt P kh2δt, t0, t≥t5. 2.33

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By the definition ofz,we have that

xt≥zt. 2.34

From1.2, we obtain

rtzΔΔtΔ

ptzγδt≤0. 2.35

Integrating both sides of2.35fromt5tot,we get

rtzΔΔt−rt5zΔΔt5 P kγ t

t5

psh2δs, t0γΔs≤0, 2.36

which yields that

rt5zΔΔt5≥P kγ t

t5

psh2δs, t0γΔs, 2.37

which contradicts2.26. HenceZt>0 andzΔt/tis nonincreasing. The proof is complete.

Lemma 2.4. Assume thatHholds andxis a solution of1.2which satisfies case (iii) ofLemma 2.1.

If

∞

t0

psRσsΔs∞, 2.38

whereRt:t

t0σu/ruΔufort∈t0,∞T,then limt→ ∞xt 0.

Proof. Let xbe a solution of1.2 such that caseiii of Lemma 2.1holds for t ≥ t1.Then limt→ ∞zt l ≥ 0, limt→ ∞xt l/1−a ≥0.Next we claim thatl 0.Otherwise, there existst2 ≥t1such thatzδt≥l >0 for allt≥t2.By the definition ofz,we have that2.35 holds. Integrating both sides of2.35fromtto∞,we get

zΔΔt≥ 1 rt

∞

t

pszγδsΔs. 2.39

Integrating again fromtto∞,we have

−zΔt≥ ∞

t

1 ru

∞

u

pszγδsΔsΔu. 2.40

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Integrating again fromt2to∞,we obtain zt1≥

∞

t2

∞

v

1 ru

∞

u

pszγδsΔsΔuΔv≥lγ ∞

t2

∞

v

1 ru

∞

u

psΔsΔuΔv, 2.41

which contradicts2.38, since by23, Lemma 1 and3, Remark 4.7 , we get ∞

t0

∞

v

1 ru

∞

u

psΔsΔuΔv

∞

t0

∞

v

∞

u

1

rupsΔsΔuΔv

∞

t0

∞

v

σs

v

1

rupsΔuΔsΔv

∞

t0

σs

t0

σs

v

1

rupsΔuΔvΔs

∞

t0

ps σs

t0

σs

v

1

ruΔuΔvΔs ∞

t0

ps σs

t0

σu

t0

1

ruΔvΔuΔs

∞

t0

ps σs

t0

1 ru

σu

t0

ΔvΔuΔs

∞

t0

ps σs

t0

σu−t0

ru ΔuΔs

∞

t0

ps σs

t0

σu

ruΔuΔs

∞

t0

psRσsΔs.

2.42

Hence limt→ ∞xt 0 and completes the proof.

Theorem 2.5. Assume thatH,2.2,2.26, and2.38hold, γ ≥ 1.Furthermore, assume that there exists a positive functionη∈Crd1 t0,∞T,Rsuch that for some 0< k <1 and for all constants M >0

lim sup

t→ ∞

t

t0

ηspsζs− rs

ηΔs2

4kγMγ−1ηs

Δs∞, 2.43

whereζt: h2δt, t0/tγ.Then every solutionxof 1.2oscillates or limt→ ∞xt 0.

Proof. Suppose that 1.2 has a nonoscillatory solution x.We may assume without loss of generality thatxt>0, xτt>0,andxδt>0 for allt∈t1,∞T, t1 ∈t0,∞T.Then by Lemma 2.1,zsatisfies three cases. Assume thatzsatisfies casei.Define the functionωby

ωt ηtrtzΔΔt

zΔtγ , t∈t1,∞T. 2.44

Thenωt>0.Using the product rule, we have

ωΔt

rtzΔΔtσ ηt

zΔtγ

Δ

rtzΔΔtΔ ηt

zΔtγ. 2.45

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By the quotient rule, we get

ωΔt

rtzΔΔtσηΔt zΔtγ

−ηt

zΔtγΔ zΔtγ

zΔσtγ

rtzΔΔtΔ ηt

zΔtγ. 2.46

By the definition ofzand1.2, we obtain2.35. From2.35and2.44, we have

ωΔt≤ ηΔt

ησtωσt−ηtptzγδt zΔtγ −ηt

rtzΔΔtσ

zΔtγΔ zΔtγ

zΔσtγ , 2.47

from2.25and2.27, for any 0< k <1,we obtain zγδt

zΔtγ zγδt zΔδtγ

zΔδtγ

zΔtγ ≥

k1/γh2δt, t0 δt

γδt t

γ k

h2δt, t0 t

γ , 2.48

hence by2.48, we have

ωΔt≤ ηΔt

ησtωσt−kηtptζt−ηt

rtzΔΔtσ

zΔtγΔ zΔtγ

zΔσtγ . 2.49

In view ofγ ≥1,from2.1andiofLemma 2.1, we have

zΔtγΔ γ

1

0

hzΔσt 1−hzΔt γ−1zΔΔtdh

≥γ

zΔtγ−1

zΔΔt≥γMγ−1zΔΔt,

2.50

whereMzΔt1.By2.49, we have

ωΔt≤ ηΔt

ησtωσt−kηtptζt−γMγ−1ηt

rtzΔΔtσ 2

zΔtγ

zΔσtγ zΔΔt

rσtzΔΔσt, 2.51

fromi,we havezΔt≤zΔσt,byrtzΔΔtΔ<0,we have

zΔΔt≥ rσt

rt zΔΔσt, 2.52

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so we get

ωΔt≤ ηΔt

ησtωσt−kηtptζt−γMγ−1ηt

rtzΔΔtσ 2

rt

zΔσtγ2, 2.53 by2.44, we have

ωΔt≤ ηΔt

ησtωσt−kηtptζt−γMγ−1 ηt

rt

ησt2ωσt2. 2.54 Therefore, we obtain

ωΔt≤ −kηtptζt rt ηΔt2

4γMγ−1ηt. 2.55

Integrating inequality2.55fromt1tot, we obtain

−ωt1≤ωt−ωt1≤ − t

t1

kηspsζs−rs

ηΔs2

4γMγ−1ηs

Δs, 2.56

which yields

t

t1

kηspsζs−rs

ηΔs2

4γMγ−1ηs

Δs≤ωt1 2.57

for all larget,which contradicts2.43. Ifiiholds, fromLemma 2.1, then limt→ ∞xt 0.If caseiiiholds, byLemma 2.4, then limt→ ∞xt 0.The proof is complete.

Remark 2.6. From Theorem 2.5, we can obtain different conditions for oscillation of all solutions of1.2with different choices ofη.

For example, letηt t.NowTheorem 2.5yields the following result.

Corollary 2.7. Assume thatH,2.2,2.26, and2.38hold,γ≥1.If

lim sup

t→ ∞

t

t0

sps

h2δs, t0 s

γ

− rs 4kγMγ−1s

Δs∞ 2.58

holds for some 0 < k < 1 and for all constantsM > 0, then every solution xof 1.2 is either oscillatory or limt→ ∞xt 0.

For example, letηt 1.FromTheorem 2.5, we have the following result which can be considered as the extension of the Leighton-Wintner Theorem.

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Corollary 2.8. Assume thatH,2.2,2.26, and2.38hold, andγ ≥1.If

lim sup

t→ ∞

t

t0

ps

h2δs, t0 s

γ

Δs∞, 2.59

then every solutionxof1.2is either oscillatory or limt→ ∞xt 0.

In the following theorem, we present a new Kamenev-type oscillation criteria for1.2.

Theorem 2.9. Assume thatH,2.2,2.26, and2.38hold,γ ≥1.Letζandηbe as defined in Theorem 2.5. If for some 0< k <1 and for all constantsM >0

lim sup

t→ ∞

1 tm

t

t0

t−smηspsζs− rsB2t, s ησs2 4kγMγ−1ηst−sm

Δs∞, 2.60

wherem >1,and

Bt, s t−smηΔs

ησs −mt−σsm−1, t≥σs≥t0, 2.61 then every solutionxof1.2oscillates or limt→ ∞xt 0.

Proof. Suppose that 1.2 has a nonoscillatory solution x.We may assume without loss of generality thatxt>0, xτt>0,andxδt>0 for allt∈t1,∞T, t1∈t0,∞T.Then by Lemma 2.1,zsatisfies three cases. Assume thatzsatisfies casei.We proceed as in the proof ofTheorem 2.5to get2.54for allt≥t1sufficiently large. Multiplying2.54byt−smand integrating fromt1tot,we have

t

t1

t−smkηspsζsΔs≤ − t

t1

t−smωΔsΔs t

t1

t−smηΔs

ησsωσsΔs

− t

t1

t−smγMγ−1ηs

rs

ησs2 ωσs2Δs.

2.62

Integration by parts, we obtain

− t

t1

t−smωΔsΔs−t−smωs|tt1 t

t1

t−smΔs

ωσsΔs. 2.63

Next, we show that ift≥σsandm≥1,then t−smΔs

≤ −mt−σsm−1. 2.64

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Ifμs 0,it is easy to see that2.64is an equality. Ifμs>0,then we get t−smΔs

1 μs

t−σsm−t−sm

− 1 σs−s

t−sm−t−σsm

. 2.65

Using the inequality

xm−ym≥mym−1 x−y

, x≥y >0, m≥1, 2.66

we obtain fort≥σs

t−sm−t−σsm

≥mt−σsm−1σs−s, 2.67 and from this we see that2.64holds. From2.62–2.64, we get

t

t1

t−smkηspsζsΔs

≤t−t1mωt1

t

t1

t−smηΔs

ησs −mt−σsm−1

ωσsΔs

− t

t1

t−smγMγ−1ηs

rs

ησs2 ωσs2Δs.

2.68

Thus t

t1

t−smηspsζs− rsB2t, s ησs2 4kγMγ−1ηst−sm

Δs≤ 1

kωt1t−t1m, 2.69 which implies that

1 tm

t

t1

t−smηspsζs− rsB2t, s ησs2 4kγMγ−1ηst−sm

Δs≤ 1

kωt1 t−t1

t m

. 2.70

This easily leads to a contradiction of2.60. Ifiiholds, fromLemma 2.1, then limt→ ∞xt 0.Ifiiiholds, byLemma 2.4, then limt→ ∞xt 0.The proof is complete.

In the following theorem, we present a new Philos-type oscillation criteria for1.2.

Theorem 2.10. Assume thatH,2.2,2.26, and2.38hold,γ≥1.Letζandηbe as defined in Theorem 2.5. Furthermore, assume that there exist functionsH,h∈CrdD,R, whereD≡ {t, s: t≥s≥t0}such that

Ht, t 0, t≥t0, Ht, s>0, t > s≥t0, 2.71 andHhas a nonpositive continuousΔ-partial derivationHΔst, swith respect to the second variable and satisfies

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HΔst, s Ht, sηΔs

ησs −ht, s ησs

Ht, s. 2.72

If for some 0< k <1 and for all constantsM >0 lim sup

t→ ∞

1 Ht, t0

t

t0

Kt, sΔs∞, 2.73

where

Kt, s Ht, sηspsζs−rsh−t, s2

4kγMγ−1ηs, 2.74

whereh−t, s max{0,−ht, s},then every solutionxof 1.2oscillates or limt→ ∞xt 0.

Proof. Suppose that 1.2 has a nonoscillatory solution x.We may assume without loss of generality thatxt>0, xτt>0,andxδt>0 for allt∈t1,∞T, t1∈t0,∞T.Then by Lemma 2.1,zsatisfies three cases. Assume thatzsatisfies casei.We proceed as in the proof ofTheorem 2.5to get2.54for allt ≥ t1sufficiently large. Multiplying both sides of2.54, withtreplaced bys,byHt, s,integrating with respect tosfromt1tot,we have

t

t1

kHt, sηspsζsΔs

≤ − t

t1

Ht, sωΔsΔs t

t1

Ht, sηΔs

ησsωσsΔs− t

t1

Ht, s γMγ−1ηs

rs

ησs2ωσs2Δs.

2.75

Integrating by parts and using2.71and2.72, we obtain t

t1

kHt, sηspsζsΔs

≤Ht, t1ωt1

t

t1

HΔst, sωσsΔs t

t1

Ht, sηΔs

ησsωσsΔs

− t

t1

Ht, s γMγ−1ηs rs

ησs2ωσs2Δs

≤Ht, t1ωt1 t

t1

−ht, s ησs

Ht, sωσs−Ht, s γMγ−1ηs

rs

ησs2ωσs2

Δs

≤Ht, t1ωt1 t

t1

h−t, s ησs

Ht, sωσs−Ht, s γMγ−1ηs

rs

ησs2ωσs2

Δs

≤Ht, t1ωt1

t

t1

rsh−t, s2 4γMγ−1ηs Δs.

2.76

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Therefore, we get t

t1

Ht, sηspsζs−rsh−t, s2 4kγMγ−1ηs

Δs≤ 1

kHt, t1ωt1. 2.77

This easily leads to a contradiction of 2.73. If case ii holds, from Lemma 2.1, then limt→ ∞xt 0. If case iii holds, by Lemma 2.4, then limt→ ∞xt 0. The proof is complete.

The following result can be considered as the extension of the Atkinson’s theorem39 . Theorem 2.11. Assume thatH,2.2,2.26, and2.38hold,γ >1.If

lim sup

t→ ∞

t

t0

ps

rsσs

h2δs, t0 σs

γ

Δs∞, 2.78

then every solutionxof1.2is either oscillatory or limt→ ∞xt 0.

Proof. Suppose that 1.2 has a nonoscillatory solution x.We may assume without loss of generality thatxt>0, xτt>0 andxδt>0 for allt∈t1,∞T, t1∈t0,∞T.Then by Lemma 2.1,zsatisfies three cases. Assume thatzsatisfies casei.Define the functionω

ωt trtzΔΔt

zΔtγ , t∈t1,∞T. 2.79

Using the product rule,2.25and2.27, for any 0< k <1,we have that

zγδt

zΔσtγ zγδt zΔδtγ

zΔδtγ

zΔσtγ ≥

k1/γh2δt, t0 δt

γδt σt

γ

k

h2δt, t0 σt

γ

. 2.80

By1.2, we have that2.35holds, then from2.80, we calculate

ωΔt

rtzΔΔt σt

rtzΔΔtΔ

zΔσt−γ

trtzΔΔt

zΔt−γΔ

≤rtzΔΔt

zΔσt−γ

−σtpt

zδt zΔσt

γ

trtzΔΔt

zΔt−γΔ

≤rt

zΔt1−γΔ

1−γ −kσtpt

h2δt, t0 σt

γ

,

2.81

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where the last inequality is true becausezΔt−γΔ≤0 due to2.1and because zΔt1−γΔ

1−γ1

0

hzΔσt 1−hzΔt −γzΔΔtdh

≤

1−γ1

0

hzΔσt 1−hzΔσt −γzΔΔtdh

1−γ

zΔσt−γ zΔΔt.

2.82

Upon integration we arrive at

t

t1

kσsps

rs

h2δs, t0 σs

γ

Δs≤ t

t1

zΔs1−γΔ 1−γ Δs−

t

t1

ωΔs

rs Δs

zΔt1−γ 1−γ −

zΔt11−γ 1−γ −

t

t1

ωΔs

rs Δs

≤

zΔt11−γ

γ−1 ωt1 rt1 −ωt

rt

t

t1

ωσs 1

rs Δ

Δs

≤

zΔt11−γ

γ−1 ωt1 rt1

2.83

fromrΔt≥0.This contradicts2.78. If caseiiholds, fromLemma 2.1, then limt→ ∞xt 0.If caseiiiholds, byLemma 2.4, then limt→ ∞xt 0.The proof is complete.

Theorem 2.12. Assume thatH,2.2,2.26, and2.38hold,γ ≤ 1.Furthermore, assume that there exists a positive functionη∈Crd1 t0,∞T,Rsuch that for some 0< k <1 and for all constants L >0

lim sup

t→ ∞

t

t0

ηspsζs− rs

ηΔs2

4kγLσsγ−1ηs

Δs∞, 2.84

where ζ is as defined as in Theorem 2.5. Then every solution x of 1.2 is either oscillatory or limt→ ∞xt 0.

Proof. Suppose that 1.2 has a nonoscillatory solution x.We may assume without loss of generality thatxt>0, xτt>0 andxδt>0 for allt1t∈t1,∞T, ∈t0,∞T.Then by Lemma 2.1,zsatisfies three cases. Assumezsatisfies casei.Define the functionωas2.44.

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We proceed as in the proof ofTheorem 2.5and we get2.49. In view ofγ≤1,from2.1and iofLemma 2.1, we have

zΔtγΔ γ

1

0

hzΔσt 1−hzΔt γ−1zΔΔtdh

≥γ

zΔσtγ−1 zΔΔt,

2.85

from2.27, there exists a constantL >0 such thatzΔt≤Lt,so

zΔtγΔ

≥γLσtγ−1zΔΔt. 2.86 By2.49, we have

ωΔt≤ ηΔt

ησtωσt−kηtptζt−γLσtγ−1 ηt

rt

ησt2ωσt2. 2.87 Therefore, we obtain

ωΔt≤ −kηtptζt rt ηΔt2

4γLσtγ−1ηt. 2.88

Integrating inequality2.88fromt1tot, we obtain

−ωt1≤ωt−ωt1≤ − t

t1

kηspsζs− rs

ηΔs2 4γLσsγ−1ηs

Δs, 2.89

which yields

t

t1

kηspsζs− rs

ηΔs2

4γLσsγ−1ηs

Δs≤ωt1 2.90

for all larget,which contradicts2.84. If caseiiholds, fromLemma 2.1, then limt→ ∞xt 0.If caseiiiholds, byLemma 2.4, then limt→ ∞xt 0.The proof is complete.

Remark 2.13. From Theorem 2.12, we can obtain different conditions for oscillation of all solutions of1.2with different choices ofη.

For example, letηt t.NowTheorem 2.12yields the following results.

Corollary 2.14. Assume thatH,2.2,2.26, and2.38hold,γ≤1.If

lim sup

t→ ∞

t

t0

sps

h2δs, t0 s

γ

− rs

4kγLσsγ−1s

Δs∞ 2.91

(18)

holds for some 0< k <1 and for all constantsL >0,then every solutionxof1.2is either oscillatory or limt→ ∞xt 0.

For example, letηt 1.FromTheorem 2.12, we have the following result which can be considered as the extension of the Leighton-Wintner theorem.

Corollary 2.15. Assume thatH,2.2,2.26, and2.38hold,γ ≤1.If 2.59holds, then every solutionxof 1.2is either oscillatory or limt→ ∞xt 0.

In the following theorem, we present a new Kamenev-type oscillation criteria for1.2.

Theorem 2.16. Assume thatH,2.2,2.26, and2.38hold,γ≤1.Letζandηbe as defined in Theorem 2.12. If for some 0< k <1 and for all constantsL >0

lim sup

t→ ∞

1 tm

t

t0

t−smηspsζs− rsB2t, s ησs2

4kγLσsγ−1ηst−sm

Δs∞, 2.92

wherem >1,and

Bt, s t−smηΔs

ησs −mt−σsm−1, t≥σs≥t0, 2.93 then every solutionxof1.2oscillates or limt→ ∞xt 0.

The proof is similar to that of Theorem 2.9using inequality 2.88, so we omit the details.

In the following theorem, we present a new Philos-type oscillation criteria for1.2.

Theorem 2.17. Assume thatH,2.2,2.26, and2.38hold,γ≤1.Letζandηbe as defined in Theorem 2.12. Furthermore, assume that there exist functionsH,h∈CrdD,R, whereD≡ {t, s: t≥s≥t0}such that2.71holds, andHhas a nonpositive continuousΔ-partial derivationHΔst, s with respect to the second variable and satisfies2.72. If

lim sup

t→ ∞

1 Ht, t0

t

t0

Kt, sΔs∞ 2.94

holds for some 0< k <1 and for all constantsL >0,where

Kt, s Ht, sηspsζs− rsh−t, s2

4kγLσsγ−1ηs, 2.95

whereh−t, s max{0,−ht, s}.Then every solutionxof1.2oscillates or limt→ ∞xt 0.

The proof is similar to that of the proof ofTheorem 2.10using inequality2.88, so we omit the details.

The following result can be considered as the extension of the Belohorec’s theorem 40 .

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Theorem 2.18. Assume thatH,2.2,2.26, and2.38holdγ <1.If

lim sup

t→ ∞

t

t0

ps

rγδsh2δs, t0γΔs∞, 2.96

then every solutionxof1.2is either oscillatory or satisfies limt→ ∞xt 0.

Proof. Suppose that 1.2 has a nonoscillatory solution x.We may assume without loss of generality thatxt>0, xτt>0,andxδt>0 for allt1t∈t1,∞T, ∈t0,∞T.Then by Lemma 2.1,zsatisfies three cases. Assume thatzsatisfies casei.Fromiand2.1we have

rtzΔΔt1−γΔ

1−γ1

0

hrtzΔΔtσ 1−hrtzΔΔt −γ

rtzΔΔtΔ dh

≤

1−γ1

0

hrtzΔΔt 1−hrtzΔΔt −γ

rtzΔΔtΔ dh

1−γ

rtzΔΔt−γ

rtzΔΔtΔ ,

2.97

so

rtzΔΔt−γ

rtzΔΔtΔ

≥

rtzΔΔt1−γΔ

1−γ . 2.98

By1.2, we have that2.35holds. Using2.25and2.27, for any 0< k <1,we obtain after dividing2.35byrtzΔΔtγfor all larget

0≥

rtzΔΔtΔ

ptzγδt rtzΔΔtγ

rtzΔΔt−γ

rtzΔΔtΔ pt

zδt rtzΔΔt

γ

≥

rtzΔΔt1−γΔ

1−γ pt

rγδt

zδt zΔδt

zΔδt zΔΔδt

γ

≥

rtzΔΔt1−γΔ

1−γ pt

rγδt

kh2δt, t0

δt δt

γ

rtzΔΔt1−γΔ

1−γ kγ pt

rγδth2δt, t0γ.

2.99

参照

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