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Volume 2013, Article ID 216913,13pages http://dx.doi.org/10.1155/2013/216913

Research Article

Traveling Wave Solutions in a Reaction-Diffusion Epidemic Model

Sheng Wang,

1

Wenbin Liu,

2

Zhengguang Guo,

1

and Weiming Wang

1

1College of Mathematics and Information Science, Wenzhou University, Wenzhou 325035, China

2College of Physics and Electronic Information Engineering, Wenzhou University, Wenzhou 325035, China

Correspondence should be addressed to Weiming Wang; [email protected] Received 4 February 2013; Revised 17 March 2013; Accepted 17 March 2013

Academic Editor: Anke Meyer-Baese

Copyright © 2013 Sheng Wang et al. This is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited.

We investigate the traveling wave solutions in a reaction-diffusion epidemic model. The existence of the wave solutions is derived through monotone iteration of a pair of classical upper and lower solutions. The traveling wave solutions are shown to be unique and strictly monotonic. Furthermore, we determine the critical minimal wave speed.

1. Introduction

Recently, great attention has been paid to the study of the traveling wave solutions in reaction-diffusion models [1–17].

In the sense of epidemiology, the traveling wave solutions describe the transition from a disease-free equilibrium to an endemic equilibrium; the existence and nonexistence of non- trivial traveling wave solutions indicate whether or not the disease can spread [11]. The results contribute to predicting the developing tendency of infectious diseases, to determin- ing the key factors of the spread of infectious disease, and to seeking the optimum strategies of preventing and controlling the spread of the infectious diseases [18–21].

Some methods have been used to derive the existence of traveling wave solutions in reaction-diffusion models, and the monotone iteration method has been proved to be an effective one. Such a method reduces the existence of traveling wave solutions to that of an ordered pair of upper-lower solutions [6,7,9,10,14,15].

In [22], Berezovsky and coworkers introduced a simple epidemic model through the incorporation of variable pop- ulation, disease-induced mortality, and emigration into the classical model of Kermack and McKendrick [23]. The total population(𝑁)is divided into two groups of susceptible(𝑆)

and infectious (𝐼); that is to say, 𝑁 = 𝑆 + 𝐼. The model describing the relations between the state variables is

𝑑𝑆

𝑑𝑡 = 𝑟𝑁 (1 −𝑁 𝐾) − 𝛽𝑆𝐼

𝑁− (𝜇 + 𝑚) 𝑆, 𝑑𝐼

𝑑𝑡 = 𝛽𝑆𝐼

𝑁− (𝜇 + 𝑑) 𝐼,

(1)

where the reproduction of susceptible follows a logistic equa- tion with the intrinsic growth rate𝑟and the carrying capacity 𝐾,𝛽denotes the contact transmission rate (the infection rate constant),𝜇is the natural mortality;𝑑denotes the disease- induced mortality, and𝑚is the per-capita emigration rate of uninfected.

For model (1), the epidemic threshold, the so-called basic reproduction number𝑅0, is then computed as𝑅0 = 𝛽/(𝜇 + 𝑑). The disease will successfully invade when𝑅0 > 1but will die out if𝑅0 < 1.𝑅0 = 1is usually a threshold whether the disease goes to extinction or goes to an endemic. Large values of𝑅0may indicate the possibility of a major epidemic [19]. In addition, the basic demographic reproductive number𝑅𝑑is given by𝑅𝑑 = 𝑟/(𝜇 + 𝑚). It can be shown that if𝑅𝑑 > 1the population grows, while𝑅𝑑 ≤ 1implies that the population does not survive [22].

(2)

For simplicity, rescaling model (1) by letting𝑆 → 𝑆/𝐾, 𝐼 → 𝐼/𝐾, and𝑡 → 𝑡/(𝜇 + 𝑑)leads to the following model:

𝑑𝑆

𝑑𝑡 =]𝑅𝑑(𝑆 + 𝐼) [1 − (𝑆 + 𝐼)] − 𝑅0 𝑆𝐼 𝑆 + 𝐼−]𝑆, 𝑑𝐼

𝑑𝑡 = 𝑅0 𝑆𝐼 𝑆 + 𝐼− 𝐼,

(2)

where]= (𝜇+𝑚)/(𝜇+𝑑)is defined by the ratio of the average life span of susceptibles to that of infectious.

For details, we refer the reader to [20,22].

In this paper, we are interested in the existence of traveling wave solutions in the following reaction-diffusion epidemic model [20]:

𝜕𝑆

𝜕𝑡 =]𝑅𝑑(𝑆 + 𝐼) [1 − (𝑆 + 𝐼)] − 𝑅0 𝑆𝐼

𝑆 + 𝐼−]𝑆 + 𝑑𝜕2𝑆

𝜕𝑥2,

𝜕𝐼

𝜕𝑡 = 𝑅0 𝑆𝐼

𝑆 + 𝐼− 𝐼 + 𝑑𝜕2𝐼

𝜕𝑥2, 𝑆 (𝑥, 0) = 𝑆0(𝑥) , 𝐼 (𝑥, 0) = 𝐼0(𝑥) ,

(3)

where], 𝑅0, 𝑅𝑑 are all positive constants,𝑑is the diffusion coefficient, and(𝑥, 𝑡) ∈ 𝑅 × 𝑅+.

We are looking for the traveling wave solutions of model (3) with the following form:

𝑆 (𝑥, 𝑡) = 𝑆 (𝜉) , 𝐼 (𝑥, 𝑡) = 𝐼 (𝜉) , 𝜉 = 𝑥 + 𝑐𝑡, (4)

satisfying the following boundary value conditions:

(𝑆 (−∞) , 𝐼 (−∞))𝑇= 𝐸1, (𝑆 (+∞) , 𝐼 (+∞))𝑇= 𝐸2, (5) where𝐸1, 𝐸2are the equilibrium points of model (3).

This paper is arranged as follows. InSection 2, we con- struct a pair of ordered upper-lower solutions of model (3) and establish the uniqueness and strict monotonicity of the traveling wave solutions.

2. Existence and Asymptotic Decay Rates

In this section, we will establish the existence of traveling wave solutions of model (3) by constructing a pair of ordered upper-lower solutions. The definition of the upper solution and the lower solution is standard. We assume that the ineq- uality between two vectors throughout this paper is compo- nentwise.

Setting

̂𝑆 = 𝑅𝑑− 1

𝑅𝑑 − 𝑆, ̂𝐼 = 𝐼, (6)

then model (3) can be written as

𝜕̂𝑆

𝜕𝑡 = −]𝑅𝑑(𝑅𝑑− 1

𝑅𝑑 − ̂𝑆 + ̂𝐼) [1 − (𝑅𝑑− 1

𝑅𝑑 − ̂𝑆 + ̂𝐼)]

+ 𝑅0((𝑅𝑑− 1) /𝑅𝑑− ̂𝑆) ̂𝐼

(𝑅𝑑− 1) /𝑅𝑑− ̂𝑆 + ̂𝐼+](𝑅𝑑− 1

𝑅𝑑 − ̂𝑆) + 𝑑𝜕2̂𝑆

𝜕𝑥2,

𝜕̂𝐼

𝜕𝑡 = 𝑅0((𝑅𝑑− 1) /𝑅𝑑− ̂𝑆) ̂𝐼

(𝑅𝑑− 1) /𝑅𝑑− ̂𝑆 + ̂𝐼− ̂𝐼 + 𝑑𝜕2̂𝐼

𝜕𝑥2, (̂𝑆, ̂𝐼)𝑇(−∞) = (0, 0)𝑇, (̂𝑆, ̂𝐼)𝑇(+∞) = (̂𝑆, ̂𝐼)𝑇.

(7) For model (3), the equilibria are𝐸1= ((𝑅𝑑−1)/𝑅𝑑, 0)and 𝐸2= (𝑆, 𝐼), where

𝑆 =]𝑅0𝑅𝑑− 𝑅0−]+ 1

]𝑅20𝑅𝑑 , 𝐼= (𝑅0− 1) 𝑆, (8) and for model (7), the equilibria are𝐸̂1 = (0, 0)and 𝐸̂2 = (̂𝑆, ̂𝐼), where

̂𝑆= (𝑅0− 1) (]𝑅0𝑅𝑑−]𝑅0−]+ 1) ]𝑅20𝑅𝑑 ,

̂𝐼= (𝑅0− 1) (]𝑅0𝑅𝑑− 𝑅0−]+ 1) ]𝑅20𝑅𝑑 .

(9)

Obviously,

̂𝐼− ̂𝑆= (]− 1) (𝑅0− 1) ]𝑅0𝑅𝑑 ,

̂𝑆= 𝑅𝑑− 1

𝑅𝑑 − 𝑆, ̂𝐼= 𝐼.

(10)

For simplicity, we define the following functions and con- stants:

𝛼0= 𝑅𝑑− 1

𝑅𝑑 , 𝜙 (𝐼) = 𝛼0̂𝐼+ (̂𝐼− ̂𝑆)𝐼;

𝛽0= 𝛼0(̂𝐼)2𝑅0− 1

𝑅0 (𝑅0−]+ 1) ; 𝛾0= 2](𝑅𝑑− 1) (̂𝐼− ̂𝑆) − []̂𝐼+ (𝑅0− 1) ̂𝑆] ;

𝜓 (𝐼) =]𝑅𝑑(̂𝐼− ̂𝑆)2𝐼2+ 𝛾0̂𝐼𝐼 + 𝛽0; 𝜂0= − 𝛾0̂𝐼

2]𝑅𝑑(̂𝐼− ̂𝑆)2;

𝜑 (𝐼) = 1, 𝐼 > 0; 𝜑 (𝐼) = −1, 𝐼 ≤ 0;

𝐵 = ̂𝐼

2 [1 + 𝜑 (̂𝐼

2 − 𝜂0)] .

(11)

And we will always assume the following hypotheses throughout the rest of this paper:

(3)

[H1]

𝑅0> 1, 1 < 𝑅𝑑< 2𝑅20+ 2𝑅0− 2 3𝑅20− 2𝑅0 , max{27𝑅0(𝑅𝑑− 1)2

𝑅3𝑑 , 𝑅0− 1 𝑅0𝑅𝑑− 1}

<]< −1 𝑅0𝑅𝑑− 𝑅0− 1.

(12)

[H2]

]≥max{ 𝑅0

2 − 𝑅𝑑, 𝑅30− 2𝑅20+ 4𝑅0− 2

2𝑅20+ 2𝑅0− 2 − (3𝑅20− 2𝑅0) 𝑅𝑑} , 𝜓 (𝐵) ≤ 0.

(13)

Then we can obtain the following.

Lemma 1. If [H1] holds, then𝐸2and𝐸̂2are endemic points of model(3)and model(7), respectively.

Lemma 2. For model(7), if [H1] holds, then𝐸̂1 is unstable, and𝐸̂2is stable.

For the sake of convenience, let𝑥 = √𝑑 ̃𝑥. For simplicity, we still use the variables𝑆,𝐼, and𝑥 instead of̂𝑆,̂𝐼, and ̃𝑥, respectively, then model (7) could be rewritten as

𝜕𝑆

𝜕𝑡 = −]𝑅𝑑(𝛼0− 𝑆 + 𝐼) [1 − (𝛼0− 𝑆 + 𝐼)]

+ 𝑅0(𝛼0− 𝑆) 𝐼

𝛼0− 𝑆 + 𝐼+](𝛼0− 𝑆) + 𝜕2𝑆

𝜕𝑥2,

𝜕𝐼

𝜕𝑡 = 𝑅0(𝛼0− 𝑆) 𝐼

𝛼0− 𝑆 + 𝐼− 𝐼 + 𝜕2𝐼

𝜕𝑥2,

(𝑆, 𝐼)𝑇(−∞) = (0, 0)𝑇, (𝑆, 𝐼)𝑇(+∞) = (̂𝑆, ̂𝐼)𝑇. (14)

Following the definition of quasi-monotonicity [17], we can obtain the following results.

Lemma 3. Model(14)is a quasi-monotone decreasing system in(𝑆, 𝐼) ∈ [̂𝐸1, ̂𝐸2].

Proof. Let

𝐹1(𝑆, 𝐼) = −]𝑅𝑑(𝛼0− 𝑆 + 𝐼) [1 − (𝛼0− 𝑆 + 𝐼)]

+ 𝑅0(𝛼0− 𝑆) 𝐼

𝛼0− 𝑆 + 𝐼 +](𝛼0− 𝑆) , 𝐹2(𝑆, 𝐼) = 𝑅0(𝛼0− 𝑆) 𝐼

𝛼0− 𝑆 + 𝐼− 𝐼.

(15)

From [17], we can know that the functions𝐹1(𝑆, 𝐼)and 𝐹2(𝑆, 𝐼)are said to possess a quasi-monotone nonincreasing

system, if the sign of𝜕𝐹1(𝑆, 𝐼)/𝜕𝐼 and𝜕𝐹2(𝑆, 𝐼)/𝜕𝑆are both nonpositive.

Since

𝜕𝐹2(𝑆, 𝐼)

𝜕𝑆 = −𝑅0( 𝐼

𝛼0− 𝑆 + 𝐼)2≤ 0,

𝜕𝐹1(𝑆, 𝐼)

𝜕𝐼 = 𝑅0( 𝛼0− 𝑆

𝛼0− 𝑆 + 𝐼)2+ 2]𝑅𝑑(𝛼0− 𝑆 + 𝐼) −]𝑅𝑑,

𝜕

𝜕𝑆(𝜕𝐹1(𝑆, 𝐼)

𝜕𝐼 ) = −2]𝑅𝑑− 2𝑅0 (𝛼0− 𝑆) 𝐼

(𝛼0− 𝑆 + 𝐼)3 ≤ −2]𝑅𝑑< 0.

(16) Then,

𝜕𝐹1(𝑆, 𝐼)

𝜕𝐼 ≤ 𝑅0( 𝛼0

𝛼0+ 𝐼)2+ 2]𝑅𝑑(𝛼0+ 𝐼) −]𝑅𝑑. (17) Let

𝐺 (𝑧) = 𝛼02𝑅0

𝑧2 + 2]𝑅𝑑𝑧 −]𝑅𝑑, 𝑧 ∈ [𝛼0, 𝛼0+ ̂𝐼] , (18) then

𝐺󸀠(𝑧) = 2]𝑅𝑑−2𝛼20𝑅0

𝑧3 = 0, (19)

obviously,𝑧 =√𝛼3 20𝑅0/]𝑅𝑑is the unique real root of𝐺󸀠(𝑧).

Since]> 27𝑅0(𝑅𝑑− 1)2/𝑅3𝑑, consider𝛼0 = (𝑅𝑑− 1)/𝑅𝑑, then we can get

𝐺 (𝑧) = (𝛼02𝑅0)2/3[(27𝛼20𝑅0)1/3− (]𝑅𝑑)1/3]

(𝑧)2 < 0. (20) And

𝑧 → 0lim+𝐺 (𝑧) = lim

𝑧 → +∞𝐺 (𝑧) = +∞; (21)

hence,𝐺(𝑧)has two positive roots.

Since]≥ 𝑅0/(2 − 𝑅𝑑), thus𝐺(𝛼0) = 𝑅0+]𝑅𝑑− 2]≤ 0.

According to conditions[𝐻1]and[𝐻2], we can get 𝐺 (𝛼0+ ̂𝐼) =]𝑅𝑑− 2]+ 2]𝑅𝑑̂𝐼+ 𝑅0( 𝛼0

𝛼0+ ̂𝐼)

2

<]𝑅𝑑− 2]+ 2]𝑅𝑑̂𝐼+ 𝑅0

=(3𝑅02𝑅𝑑− 2𝑅20− 2𝑅0𝑅𝑑− 2𝑅0+ 2)] 𝑅20

+(𝑅30− 2𝑅20+ 4𝑅0− 2) 𝑅20

≤ 0.

(22)

Then,𝐺([𝛼0, 𝛼0+ ̂𝐼]) ≤ 0. Hence,𝜕𝐹1(𝑆, 𝐼)/𝜕𝐼 ≤ 0.

That is to say, model (14) is a quasi-monotone system in (𝑆, 𝐼) ∈ [̂𝐸1, ̂𝐸2].

(4)

Since the traveling wave solution of model (14) has the following form

𝑆 (𝜉) = 𝑆 (𝑥 + 𝑐𝑡) , 𝐼 (𝜉) = 𝐼 (𝑥 + 𝑐𝑡) , 𝜉 = 𝑥 + 𝑐𝑡, 𝑐 > 0;

(23) substituting (23) into model (14), we can get the following model:

𝑆󸀠󸀠− 𝑐𝑆󸀠−]𝑅𝑑(𝛼0− 𝑆 + 𝐼) [1 − (𝛼0− 𝑆 + 𝐼)]

+ 𝑅0(𝛼0− 𝑆) 𝐼

𝛼0− 𝑆 + 𝐼 +](𝛼0− 𝑆) = 0, 𝐼󸀠󸀠− 𝑐𝐼󸀠+ 𝑅0(𝛼0− 𝑆) 𝐼

𝛼0− 𝑆 + 𝐼− 𝐼 = 0,

(𝑆, 𝐼)𝑇(−∞) = (0, 0)𝑇, (𝑆, 𝐼)𝑇(+∞) = (̂𝑆, ̂𝐼)𝑇. (24)

Obviously, we can know the following.

Remark 4. Model (24) is also a quasi-monotone system in (𝑆, 𝐼) ∈ [̂𝐸1, ̂𝐸2].

Now we establish the existence of traveling wave solutions of model (24) through monotone iteration of a pair of smooth upper and lower solutions. Following [17], we give the definitions of the upper and lower solutions of model (24) as follows, respectively.

Definition 5. A smooth function(𝑆(𝜉), 𝐼(𝜉))𝑇(𝜉 ∈ R) is an upper solution of model (24) if its derivatives(𝑆󸀠, 𝐼󸀠)𝑇 and (𝑆󸀠󸀠, 𝐼󸀠󸀠)are continuous onR, and(𝑆, 𝐼)𝑇satisfies

𝑆󸀠󸀠− 𝑐𝑆󸀠−]𝑅𝑑(𝛼0− 𝑆 + 𝐼) [1 − (𝛼0− 𝑆 + 𝐼)]

+ 𝑅0(𝛼0− 𝑆) 𝐼

𝛼0− 𝑆 + 𝐼+](𝛼0− 𝑆) ≤ 0, 𝐼󸀠󸀠− 𝑐𝐼󸀠+ 𝑅0(𝛼0− 𝑆) 𝐼

𝛼0− 𝑆 + 𝐼− 𝐼 ≤ 0,

(25)

with the following boundary value conditions (𝑆𝐼)(−∞) = (0

0) , (𝑆𝐼)(+∞) ≥ (̂𝑆

̂𝐼) . (26) Definition 6. A smooth function(𝑆(𝜉), 𝐼(𝜉))𝑇 (𝜉 ∈ R) is a lower solution of model (24) if its derivatives(𝑆󸀠, 𝐼󸀠)𝑇 and (𝑆󸀠󸀠, 𝐼󸀠󸀠)are continuous onR, and(𝑆, 𝐼)𝑇satisfies

𝑆󸀠󸀠− 𝑐𝑆󸀠−]𝑅𝑑(𝛼0− 𝑆 + 𝐼) [1 − (𝛼0− 𝑆 + 𝐼)]

+ 𝑅0(𝛼0− 𝑆) 𝐼

𝛼0− 𝑆 + 𝐼+](𝛼0− 𝑆) ≥ 0, 𝐼󸀠󸀠− 𝑐𝐼󸀠+ 𝑅0(𝛼0− 𝑆) 𝐼

𝛼0− 𝑆 + 𝐼− 𝐼 ≥ 0,

(27)

with the following boundary value conditions (𝑆𝐼)(−∞) = (0

0) , (𝑆𝐼)(+∞) ≤ (̂𝑆

̂𝐼) . (28) The construction of the smooth upper-lower solution pair is based on the solution of the following KPP equation:

𝑤󸀠󸀠− 𝑐𝑤󸀠+ 𝑓 (𝑤) = 0,

𝑤 (−∞) = 0, 𝑤 (+∞) = 𝑏, (29) where𝑓 ∈ 𝐶2([0, 𝑏])and𝑓 > 0in the open interval(0, 𝑏) with𝑓(0) = 𝑓(𝑏) = 0,𝑓󸀠(0) = 𝑎1 > 0, and𝑓󸀠(𝑏) = −𝑏1 < 0 [15]. First, let us recall the following result.

Lemma 7 (see [1, 15]). Corresponding to every 𝑐 ≥ 2√𝑎1, model(29)has a unique (up to a translation of the origin) monotonically increasing traveling wave solution𝑤(𝜉)for𝜉 ∈ 𝑅. The traveling wave solution𝑤has the following asymptotic behaviors.

(i)For the wave solution with noncritical speed𝑐 > 2√𝑎1, one has

𝑤 (𝜉) = 𝑎𝜔𝑒((𝑐−√𝑐2−4𝑎1)/2)𝜉

+ 𝑜 (𝑒((𝑐−√𝑐2−4𝑎1)/2)𝜉) 𝑎𝑠 𝜉 󳨀→ −∞, 𝑤 (𝜉) = 𝑏 − 𝑏𝜔𝑒((𝑐−√𝑐2+4𝑏1)/2)𝜉

+ 𝑜 (𝑒((𝑐−√𝑐2+4𝑏1)/2)𝜉) 𝑎𝑠 𝜉 󳨀→ +∞,

(30)

where𝑎𝜔and𝑏𝜔are positive constants.

(ii)For the wave with critical speed𝑐 = 2√𝑎1, one has 𝑤 (𝜉) = (𝑎𝑐+ 𝑑𝑐𝜉) 𝑒√𝑎1𝜉+ 𝑜 (𝜉𝑒√𝑎1𝜉)𝑎𝑠 𝜉 󳨀→ −∞,

𝑤 (𝜉) = 𝑏 − 𝑏𝑐𝑒(√𝑎1−√𝑎1+𝑏1)𝜉

+ 𝑜 (𝑒(√𝑎1−√𝑎1+𝑏1)𝜉) 𝑎𝑠 𝜉 󳨀→ +∞,

(31)

where the constant𝑑𝑐is negative,𝑏𝑐is positive, and𝑎𝑐∈ 𝑅.

For constructing the upper solution of the model (24), we start with the following model:

𝐼󸀠󸀠− 𝑐𝐼󸀠+ 𝐼 (̂𝐼− 𝐼) 𝛼0(𝑅0− 1)

𝛼0̂𝐼+ (̂𝐼− ̂𝑆) 𝐼 = 0, 𝐼 (−∞) = 0, 𝐼 (+∞) = ̂𝐼.

(32)

Define𝑓(𝐼) = 𝐼(̂𝐼− 𝐼)(𝛼0(𝑅0− 1)/𝜙(𝐼)),𝐼 ∈ [0, ̂𝐼], one can verify that all of the following conditions are satisfied:

(i)𝑓(𝐼) = 𝐼(̂𝐼− 𝐼)(𝛼0(𝑅0− 1)/𝜙(𝐼)) ∈ 𝐶2([0, ̂𝐼]);

(5)

(ii)𝑓(𝐼) > 0, for all𝐼 ∈ (0, ̂𝐼)and𝑓(0) = 𝑓(̂𝐼) = 0;

(iii)𝑓󸀠(0) = 𝑅0− 1 > 0,𝑓󸀠(̂𝐼) = −𝛼0(𝑅0− 1)2/𝑅0̂𝐼< 0.

FromLemma 7, we know that, for each𝑐 ≥ 2√𝑅0− 1, equation (32) has a unique traveling wave solution𝐼(𝜉)(up to a translation of the origin), satisfying the given boundary value conditions (26).

Define

(𝑆 (𝜉)

𝐼 (𝜉)) = (̂𝑆

̂𝐼𝐼 (𝜉) 𝐼 (𝜉)

) , 𝜉 ∈ 𝑅, (33)

then we can get the following result.

Lemma 8. For each 𝑐 ≥ 2√𝑅0− 1,(33)is a smooth upper solution of model(24).

Proof. On the boundary,

(𝑆𝐼) (−∞) = (00), (𝑆𝐼) (+∞) ≥ (̂𝑆

̂𝐼) . (34) As for the𝐼component, we have

𝐼󸀠󸀠− 𝑐𝐼󸀠+ 𝑅0(𝛼0− 𝑆) 𝐼 𝛼0− 𝑆 + 𝐼− 𝐼

= −𝐼 (̂𝐼− 𝐼)𝛼0(𝑅0− 1)

𝜙 (𝐼) + 𝑅0(𝛼0− 𝑆) 𝐼 𝛼0− 𝑆 + 𝐼− 𝐼

= −𝐼 (̂𝐼− 𝐼)𝛼0(𝑅0− 1)

𝜙 (𝐼) + 𝑅0𝛼0̂𝐼− ̂𝑆𝐼 𝜙 (𝐼) 𝐼 − 𝐼

= −𝐼 (̂𝐼− 𝐼)𝛼0(𝑅0− 1) 𝜙 (𝐼)

+ 𝐼𝛼0(𝑅0− 1) ̂𝐼− (𝑅0̂𝑆− ̂𝑆+ ̂𝐼) 𝐼 𝜙 (𝐼)

= −𝐼 (̂𝐼− 𝐼)𝛼0(𝑅0− 1) 𝜙 (𝐼)

+ 𝐼𝛼0(𝑅0− 1) ̂𝐼− 𝛼0(𝑅0− 1) 𝐼 𝜙 (𝐼)

= 0.

(35)

As for the𝑆component, since] > 1, then̂𝐼 − ̂𝑆 = (]− 1)(𝑅0− 1)/]𝑅0𝑅𝑑> 0. And

(i) if𝜂0< ̂𝐼/2, then max𝜉∈[0,̂𝐼]𝜓(𝐼) = 𝜓(̂𝐼) = 𝜓(𝐵);

(ii) if𝜂0≥ ̂𝐼/2, then max𝜉∈[0,̂𝐼]𝜓(𝐼) = 𝜓(0) = 𝜓(𝐵).

Thus we can get:

𝑆󸀠󸀠− 𝑐𝑆󸀠−]𝑅𝑑(𝛼0− 𝑆 + 𝐼)[1 − (𝛼0− 𝑆 + 𝐼)]

+ 𝑅0(𝛼0− 𝑆) 𝐼

𝛼0− 𝑆 + 𝐼 +](𝛼0− 𝑆)

=̂𝑆

̂𝐼 (𝐼󸀠󸀠− 𝑐𝐼󸀠) −]𝑅𝑑(𝛼0− 𝑆 + 𝐼)[1 − (𝛼0− 𝑆 + 𝐼)]

+ 𝑅0(𝛼0− 𝑆) 𝐼

𝛼0− 𝑆 + 𝐼 +](𝛼0− 𝑆)

=̂𝑆

̂𝐼 (−𝑅0(𝛼0− 𝑆) 𝐼

𝛼0− 𝑆 + 𝐼+ 𝐼) −]𝑅𝑑(𝛼0− 𝑆 + 𝐼)

× [1 − (𝛼0− 𝑆 + 𝐼)] + 𝑅0(𝛼0− 𝑆) 𝐼

𝛼0− 𝑆 + 𝐼+](𝛼0− 𝑆)

= (1 −̂𝑆

̂𝐼) 𝑅0(𝛼0− 𝑆) 𝐼 𝛼0− 𝑆 + 𝐼+̂𝑆

̂𝐼𝐼 −]𝑅𝑑(𝛼0− 𝑆 + 𝐼)

× [1 − (𝛼0− 𝑆 + 𝐼)] +](𝛼0− 𝑆)

=̂𝐼− ̂𝑆

̂𝐼 𝑅0𝛼0̂𝐼− ̂𝑆𝐼 𝜙 (𝐼) 𝐼 +̂𝑆

̂𝐼𝐼 −]𝑅𝑑𝜙 (𝐼)

̂𝐼 [1 − 𝜙 (𝐼)

̂𝐼 ] +]𝛼0̂𝐼− ̂𝑆𝐼

̂𝐼

=(̂𝐼− ̂𝑆) 𝐼𝜓 (𝐼) (̂𝐼)2𝜙 (𝐼) ≤ 0.

(36) Hence,(𝑆, 𝐼)forms a smooth upper solution for model (24).

For constructing the lower solution of the model (24), we start with the following model:

𝐼󸀠󸀠− 𝑐𝐼󸀠+ 𝐼 [̂𝐼− (1 + 𝜀) 𝐼] 𝛼0(𝑅0− 1) 𝛼0̂𝐼+ (̂𝐼− ̂𝑆) 𝐼 = 0, 𝐼 (−∞) = 0, 𝐼 (+∞) = ̂𝐼

1 + 𝜀.

(37)

Define𝑔(𝐼) = 𝐼[̂𝐼− (1 + 𝜀)𝐼](𝛼0(𝑅0− 1)/(𝛼0̂𝐼+ (̂𝐼

̂𝑆)𝐼)),𝐼 ∈ [0, ̂𝐼/(1 + 𝜀)]. One can easily verify that all of the following conditions hold:

(i)𝑔(𝐼) = 𝐼[̂𝐼−(1+𝜀)𝐼](𝛼0(𝑅0−1)/(𝛼0̂𝐼+(̂𝐼−̂𝑆)𝐼)) ∈ 𝐶2([0, ̂𝐼/(1 + 𝜀)]);

(ii)𝑔(𝐼) > 0, for all𝐼 ∈ (0, ̂𝐼/(1+𝜀))and𝑔(0) = 𝑔(̂𝐼/(1+

𝜀)) = 0;

(6)

(iii)𝑔󸀠(0) = 𝑅0− 1 > 0,𝑔󸀠(̂𝐼/(1 + 𝜀)) = −(1 + 𝜀)𝛼0(𝑅0− 1)/(𝜀𝛼0+ (𝑅0/(𝑅0− 1))̂𝐼) < 0.

From Lemma 7, we know that, for each fixed 𝑐 ≥ 2√𝑅0− 1, model (37) has a unique traveling wave solution 𝐼(𝜉)(up to a translation of the origin), satisfying the given boundary value conditions (28).

Define

(𝑆 (𝜉)𝐼 (𝜉)) = (

̂𝑆

̂𝐼𝐼 (𝜉) 𝐼 (𝜉)

) , 𝜉 ∈ 𝑅, (38)

then we have the following result:

Lemma 9. For each fixed 𝑐 ≥ 2√𝑅0− 1,(38) is a lower solution of model(24).

Proof. On the boundary,

(𝑆𝐼)(−∞) = (0

0) , (𝑆𝐼)(+∞) = (

̂𝑆 1 + 𝜀

̂𝐼 1 + 𝜀

) ≤ (̂𝑆

̂𝐼) . (39) As for the𝐼component, we have

𝐼󸀠󸀠− 𝑐𝐼󸀠+ 𝑅0(𝛼0− 𝑆) 𝐼 𝛼0− 𝑆 + 𝐼− 𝐼

= −𝐼 [̂𝐼− (1 + 𝜀) 𝐼]𝛼0(𝑅0− 1)

𝜙 (𝐼) + 𝑅0(𝛼0− 𝑆) 𝐼 𝛼0− 𝑆 + 𝐼− 𝐼

= −𝐼 [̂𝐼− (1 + 𝜀) 𝐼]𝛼0(𝑅0− 1)

𝜙 (𝐼) + 𝐼 (̂𝐼− 𝐼)𝛼0(𝑅0− 1) 𝜙 (𝐼)

= 𝜀(𝐼)2𝛼0(𝑅0− 1) 𝜙 (𝐼) ≥ 0.

(40) As for the𝑆component, we have

𝑆󸀠󸀠− 𝑐𝑆󸀠−]𝑅𝑑(𝛼0− 𝑆 + 𝐼) [1 − (𝛼0− 𝑆 + 𝐼)]

+ 𝑅0(𝛼0− 𝑆) 𝐼

𝛼0− 𝑆 + 𝐼+](𝛼0− 𝑆)

= ̂𝑆

̂𝐼(𝐼󸀠󸀠− 𝑐𝐼󸀠) −]𝑅𝑑(𝛼0− 𝑆 + 𝐼) [1 − (𝛼0− 𝑆 + 𝐼)]

+ 𝑅0(𝛼0− 𝑆) 𝐼

𝛼0− 𝑆 + 𝐼+](𝛼0− 𝑆)

= ̂𝑆

̂𝐼{[𝜀 (𝐼)2𝛼0(𝑅0− 1)

𝜙 (𝐼) ] − [𝑅0(𝛼0− 𝑆) 𝐼 𝛼0− 𝑆 + 𝐼− 𝐼]}

−]𝑅𝑑(𝛼0− 𝑆 + 𝐼) [1 − (𝛼0− 𝑆 + 𝐼)] + 𝑅0(𝛼0− 𝑆) 𝐼 𝛼0− 𝑆 + 𝐼 +](𝛼0− 𝑆)

= 𝜀̂𝑆

̂𝐼(𝐼)2𝛼0(𝑅0− 1)

𝜙 (𝐼) +(̂𝐼− ̂𝑆) 𝐼𝜓 (𝐼) (̂𝐼)2𝜙 (𝐼) ≥ 0.

(41) Thus(𝑆, 𝐼)forms a smooth lower solution for model (24).

Next, we show that, by shifting the upper solution far enough to the left, then the upper-lower solution in Lemmas 8and9are ordered.

Lemma 10. Let𝑐 ≥ 2√𝑅0− 1,(𝑆, 𝐼)𝑇and(𝑆, 𝐼)𝑇be the upper solution and the lower solution defined in(33)and(38), then there exists a positive number𝑟, such that (𝑆, 𝐼)𝑇(𝜉 + 𝑟) ≥ (𝑆, 𝐼)𝑇(𝜉)for all𝜉 ∈ 𝑅.

Proof. Our proof is only for𝑐 > 2√𝑅0− 1, and the proof for the case of𝑐 = 2√𝑅0− 1is similar to it.

First, we derive the asymptotic behaviors of the upper solution and the lower solution at infinities.

According toLemma 7, when𝜉 → −∞, we can obtain:

(𝑆𝐼) (𝜉) = (̂𝑆

̂𝐼𝐴1 𝐴1

) 𝑒((𝑐−√𝑐2−4(𝑅0−1))/2)𝜉

+ 𝑜 (𝑒((𝑐−√𝑐2−4(𝑅0−1))/2)𝜉) ,

(𝑆𝐼)(𝜉) = (̂𝑆

̂𝐼𝐵1 𝐵1

) 𝑒((𝑐−√𝑐2−4(𝑅0−1))/2)𝜉

+ 𝑜 (𝑒((𝑐−√𝑐2−4(𝑅0−1))/2)𝜉) .

(42)

And let 𝜎0 = (1/2)(𝑐 −

√𝑐2+ 4(𝛼0(𝑅0− 1)2/𝑅0̂𝐼) < 0, 𝛿0 = (1/2)(𝑐 −

√𝑐2+ 4((1 + 𝜀)𝛼0(𝑅0− 1)/(𝜀𝛼0+ (𝑅0/(𝑅0− 1))̂𝐼)) < 0, when𝜉 → +∞, we can get

(𝑆𝐼) (𝜉) = (̂𝑆

̂𝐼) − (̂𝑆

̂𝐼𝐴2 𝐴2

) 𝑒𝜎0𝜉+ 𝑜 (𝑒𝜎0𝜉) ,

(𝑆𝐼)(𝜉) = 1 1 + 𝜀(̂𝑆

̂𝐼) − (̂𝑆

̂𝐼𝐵2 𝐵2

) 𝑒𝛿0𝜉+ 𝑜 (𝑒𝛿0𝜉) , (43)

where,𝐴1,𝐴2,𝐵1,𝐵2are all positive constants.

(7)

Since for anỹ𝑟 > 0,𝐼̃𝑟(𝜉) ≡ 𝐼(𝜉 + ̃𝑟)is also a solution of model (32). Thus,(𝑆̃𝑟, 𝐼̃𝑟)𝑇(𝜉)is an upper solution of model (24). So, according toLemma 7, when𝜉 → −∞, we can get:

(𝑆

̃𝑟

𝐼̃𝑟) (𝜉) = (̂𝑆

̂𝐼𝐴1 𝐴1

) 𝑒((𝑐−√𝑐2−4(𝑅0−1))/2)̃𝑟𝑒((𝑐−√𝑐2−4(𝑅0−1))/2)𝜉

+ 𝑜 (𝑒((𝑐−√𝑐2−4(𝑅0−1))/2)𝜉) .

(44) Since(𝑐 − √𝑐2− 4(𝑅0− 1))/2 > 0, we can choose a large enough number̃𝑟 ≫ 0, such that

(̂𝑆

̂𝐼𝐴1 𝐴1

) 𝑒((𝑐−√𝑐2−4(𝑅0−1))/2)̃𝑟> (̂𝑆

̂𝐼𝐵1 𝐵1

) , (45)

hence, there exists a large number𝑁1≫ 1, such that (𝑆

̃𝑟(𝜉)

𝐼̃𝑟(𝜉)) > (𝑆 (𝜉)𝐼 (𝜉)) , 𝜉 ∈ (−∞, −𝑁1] . (46) By using a similar argument as above, there exists a large enough number𝑁2≫ 1, such that

(𝑆̃𝑟(𝜉)

𝐼̃𝑟(𝜉)) > (𝑆 (𝜉)𝐼 (𝜉)) , 𝜉 ∈ [𝑁2, +∞) . (47) Second, we show that

(𝑆

̃𝑟(𝜉)

𝐼̃𝑟(𝜉)) > (𝑆 (𝜉)𝐼 (𝜉)) , 𝜉 ∈ [−𝑁1, 𝑁2] . (48) We deal with such two possible cases:

Case 1.If

(𝑆̃𝑟(𝜉)

𝐼̃𝑟(𝜉)) > (𝑆 (𝜉)𝐼 (𝜉)) , 𝜉 ∈ [−𝑁1, 𝑁2] , (49) then, the proof is completed.

Case 2.If there exists a point𝜉0∈ (−𝑁1, 𝑁2), such that (𝑆̃𝑟(𝜉0)

𝐼̃𝑟(𝜉0)) ≤ (𝑆 (𝜉0)

𝐼 (𝜉0)) (50)

satisfying𝑆̃𝑟(𝜉0) < 𝑆(𝜉0)or𝐼̃𝑟(𝜉0) < 𝐼(𝜉0).

In this case, we use the Sliding Domain method [15].

Step 1.we shift(𝑆̃𝑟, 𝐼̃𝑟)𝑇to the left by increasing the number

̃𝑟until finding a new number𝑟1 > ̃𝑟such that(𝑆𝑟1, 𝐼𝑟1)𝑇 >

(𝑆, 𝐼)𝑇on the smaller interval[−𝑁1, 𝑁2− (𝑟1− ̃𝑟)].

Step 2.we shift(𝑆𝑟1, 𝐼𝑟1)𝑇back to the right by decreasing𝑟1 to a smaller number̃𝑟 < 𝑟2 < 𝑟1 such that one of the

branches of the upper solution touches its counterpart of the lower solution at some point𝜉1 in the interval(−𝑁1 + (𝑟1 − 𝑟2), 𝑁2 − (𝑟1 − ̃𝑟)). On the endpoints of the interval (−𝑁1+(𝑟1−𝑟2), 𝑁2−(𝑟1−̃𝑟)), we still have(𝑆𝑟2, 𝐼𝑟2)𝑇> (𝑆, 𝐼)𝑇. Let𝑊(𝜉) = (𝑆⃗ 𝑟2, 𝐼𝑟2)𝑇− (𝑆, 𝐼)𝑇and ⃗𝐹 = (𝐹1, 𝐹2)𝑇, where

𝐹1= −]𝑅𝑑(𝛼0− 𝑆 + 𝐼) [1 − (𝛼0− 𝑆 + 𝐼)]

+ 𝑅0(𝛼0− 𝑆) 𝐼

𝛼0− 𝑆 + 𝐼 +](𝛼0− 𝑆) , 𝐹2= 𝑅0(𝛼0− 𝑆) 𝐼

𝛼0− 𝑆 + 𝐼− 𝐼.

(51)

For𝜉 ∈ (−𝑁1+ (𝑟1− 𝑟2), 𝑁2− (𝑟1− ̃𝑟)), we get that

⃗𝑊󸀠󸀠− 𝑐 ⃗𝑊󸀠+ (

𝜕𝐹1

𝜕𝑆 (𝑆 + 𝜁1𝜔1, 𝐼𝑟2) 𝜕𝐹1

𝜕𝐼 (𝑆𝑟2, 𝐼 + 𝜁2𝜔2)

𝜕𝐹2

𝜕𝑆 (𝑆 + 𝜁3𝜔1, 𝐼𝑟2) 𝜕𝐹2

𝜕𝐼 (𝑆𝑟2, 𝐼 + 𝜁4𝜔2) ) ⃗𝑊

= 0,

(52) where 𝜁𝑖 ∈ [0, 1], 𝑖 = 1, 2, 3, 4. Since the above model is monotone and the cube[(0, 0), (̂𝑆, ̂𝐼)] is convex, thus we can deduce by Maximum Principle that 𝑊 > 0⃗ for 𝜉 ∈ [−𝑁1+(𝑟1−𝑟2), 𝑁2−(𝑟1−̃𝑟)]. So𝜉1does not exist and we can decrease𝑟2further tõ𝑟. It is calculated that the point𝜉0does not exist either. The proof of this lemma is completed.

To ease the burden of notations, we still use (𝑆, 𝐼)𝑇 to denote the shifted upper solution as given inLemma 8. Let

𝐷11= −𝑅20+]𝑅0𝑅𝑑+]𝑅0− 4𝑅0− 2]+ 3

𝑅0 ,

𝐷12= ]𝑅0𝑅𝑑− 2𝑅0− 2]+ 3

𝑅0 ,

𝐷21= −(𝑅0− 1)2 𝑅0 , 𝐷22= −𝑅0− 1

𝑅0 ,

𝜇1= − (𝐷11+ 𝐷22) + √(𝐷11− 𝐷22)2+ 4𝐷12𝐷21

2 ,

𝜇2= − (𝐷11+ 𝐷22) − √(𝐷11− 𝐷22)2+ 4𝐷12𝐷21

2 .

(53)

With such constructed ordered upper-lower solution pair, we can get the following.

Theorem 11. For𝑐 ≥ 2√𝑅0− 1, model (24) has a unique (up to a translation of the origin) traveling wave solution.

The traveling wave solution is strictly increasing and has the following asymptotic properties:

(8)

(i)if𝑐 > 2√𝑅0− 1, when𝜉 → −∞, (𝑆𝐼)(𝜉) = (𝐴1

𝐴2) 𝑒((𝑐−√𝑐2−4(𝑅0−1))/2)𝜉 + 𝑜 (𝑒((𝑐−√𝑐2−4(𝑅0−1))/2)𝜉) .

(54)

when𝜉 → +∞, and if𝜇1 ̸= 𝜇2, then (𝑆𝐼)(𝜉) = (̂𝑆

̂𝐼) − (𝐴1

𝐴2) 𝑒((𝑐−√𝑐2+4𝜇)/2)𝜉 + 𝑜 (𝑒((𝑐−√𝑐2+4𝜇)/2)𝜉) ,

(55)

while𝜇1= 𝜇2:

(𝑆𝐼)(𝜉) = (̂𝑆

̂𝐼) − (𝐴11+ 𝐴12𝜉 𝐴21+ 𝐴22𝜉

) 𝑒((𝑐−√𝑐2+4𝜇)/2)𝜉

+ 𝑜 (𝑒((𝑐−√𝑐2+4𝜇)/2)𝜉) ,

(56)

where,𝜇 = min{𝜇1, 𝜇2} > 0,𝐴11, 𝐴21 ∈ R,𝐴1,𝐴2,𝐴1,𝐴2, 𝐴12and𝐴22are all positive constants.

(ii)if𝑐 = 2√𝑅0− 1, when𝜉 → −∞, (𝑆𝐼)(𝜉) = (𝐵11+ 𝐵12𝜉

𝐵21+ 𝐵22𝜉) 𝑒√𝑅0−1𝜉+ 𝑜 (𝜉𝑒√𝑅0−1𝜉) , (57) when𝜉 → +∞, and if𝜇1 ̸= 𝜇2, then

(𝑆𝐼)(𝜉) = (̂𝑆

̂𝐼) − (𝐵11

𝐵22) 𝑒(√𝑅0−1−√𝑅0−1+𝜇)𝜉 + 𝑜 (𝑒(√𝑅0−1−√𝑅0−1+𝜇)𝜉) ,

(58)

while𝜇1= 𝜇2,

(𝑆𝐼)(𝜉) = (̂𝑆

̂𝐼) − (𝐵11+ 𝐵12𝜉 𝐵21+ 𝐵22𝜉

) 𝑒(√𝑅0−1−√𝑅0−1+𝜇)𝜉

+ 𝑜 (𝑒(√𝑅0−1−√𝑅0−1+𝜇)𝜉) ,

(59)

where𝜇 =min{𝜇1, 𝜇2} > 0,𝐵12, 𝐵22 < 0,𝐵11, 𝐵21, 𝐵11, 𝐵21 ∈ R, and𝐵11,𝐵22,𝐵12,𝐵22are all positive constants.

Proof. FromLemma 3and Remark 4, we know that model (24) is a quasi-monotone nonincreasing system in (𝑆, 𝐼) ∈ [̂𝐸1, ̂𝐸2], and by using the monotone iteration scheme given in [3,13], we can obtain the existence of the solution(𝑆, 𝐼)𝑇to

the first two equations in model (24) for every𝑐 ≥ 2√𝑅0− 1, which satisfies

(𝑆 (𝜉)𝐼 (𝜉)) ≤ (𝑆 (𝜉)

𝐼 (𝜉)) ≤ (𝑆 (𝜉)

𝐼 (𝜉)) . (60) According to the above inequality, we can get that, on the boundary, the solution tends to(0, 0)𝑇as𝜉 → −∞and (̂𝑆, ̂𝐼)𝑇as𝜉 → +∞.

To derive the asymptotic decay rate of the traveling wave solutions as𝜉 → ±∞, we just let𝑐 > 2√𝑅0− 1and

𝑈 (𝜉) = (𝑆 (𝜉) , 𝐼 (𝜉))𝑇, −∞ < 𝜉 < +∞ (61) be the traveling wave solution of model (24) generated form the monotone iteration, since the case of (ii)𝑐 = 2√𝑅0− 1is similar to it.

We differentiate model (24) with respect to𝜉, and note that𝑈󸀠(𝜉) = (𝜒1, 𝜒2)𝑇(𝜉)satisfies

𝜒1󸀠󸀠− 𝑐𝜒1󸀠+ 𝐶11(𝑆, 𝐼) 𝜒1+ 𝐶12(𝑆, 𝐼) 𝜒2= 0,

𝜒2󸀠󸀠− 𝑐𝜒2󸀠+ 𝐶21(𝑆, 𝐼) 𝜒1+ 𝐶22(𝑆, 𝐼) 𝜒2= 0, (62) where

𝐶11(𝑆, 𝐼) =]𝑅𝑑[1 − (𝛼0− 𝑆 + 𝐼)] −]𝑅𝑑(𝛼0− 𝑆 + 𝐼)

− 𝑅0𝐼

𝛼0− 𝑆 + 𝐼+ 𝑅0(𝛼0− 𝑆) 𝐼 (𝛼0− 𝑆 + 𝐼)2 −], 𝐶12(𝑆, 𝐼) = −]𝑅𝑑[1 − (𝛼0− 𝑆 + 𝐼)] +]𝑅𝑑(𝛼0− 𝑆 + 𝐼)

+𝑅0(𝛼0− 𝑆)

𝛼0− 𝑆 + 𝐼 − 𝑅0(𝛼0− 𝑆) 𝐼 (𝛼0− 𝑆 + 𝐼)2, 𝐶21(𝑆, 𝐼) = − 𝑅0𝐼

𝛼0− 𝑆 + 𝐼+𝑅0(𝛼0− 𝑆) 𝐼 (𝛼0− 𝑆 + 𝐼)2, 𝐶22(𝑆, 𝐼) =𝑅0(𝛼0− 𝑆)

𝛼0− 𝑆 + 𝐼 −𝑅0(𝛼0− 𝑆) 𝐼 (𝛼0− 𝑆 + 𝐼)2 − 1.

(63) Now, we study the exponential decay rate of the traveling wave solution as𝜉 → −∞. The asymptotic model of model (62) as𝜉 → −∞is

𝜆󸀠󸀠− 𝑐𝜆󸀠+ 𝐸11𝜆 + 𝐸12𝜇 = 0,

𝜇󸀠󸀠− 𝑐𝜇󸀠+ 𝐸21𝜆 + 𝐸22𝜇 = 0, (64) where

𝐸11= −](𝑅𝑑− 1) , 𝐸12=]𝑅𝑑+ 𝑅0− 2],

𝐸21= 0, 𝐸22= 𝑅0− 1. (65) The second equation of model (64) has two independent solutions with the following form:

𝜇(1)(𝜉) = 𝑒((𝑐−√𝑐2−4(𝑅0−1))/2)𝜉, 𝜇(2)(𝜉) = 𝑒((𝑐+√𝑐2−4(𝑅0−1))/2)𝜉.

(66)

(9)

Relating the second equation of model (62) with the second equation of model (64), we can deduce that𝜒2(𝜉)has the following property as𝜉 → −∞:

𝜒2(𝜉) = 𝛼 [1 + 𝑜 (1)] 𝑒((𝑐−√𝑐2−4(𝑅0−1))/2)𝜉 + 𝛽 [1 + 𝑜 (1)] 𝑒((𝑐+√𝑐2−4(𝑅0−1))/2)𝜉

(67) for some constants𝛼and𝛽. Thus, we can obtain that

𝜒2(𝜉) = 𝛼𝑒((𝑐−√𝑐2−4(𝑅0−1))/2)𝜉+ 𝛽𝑒((𝑐+√𝑐2−4(𝑅0−1))/2)𝜉

+ Υ1(𝜉) + Υ2(𝜉) , (68)

where

𝜉 → −∞lim

Υ1(𝜉)

𝑒((𝑐−√𝑐2−4(𝑅0−1))/2)𝜉 = 0,

𝜉 → −∞lim

Υ2(𝜉)

𝑒((𝑐+√𝑐2−4(𝑅0−1))/2)𝜉 = 0.

(69)

So we obtain that

𝜉 → −∞lim

𝜒2(𝜉) − 𝛼𝑒((𝑐−√𝑐2−4(𝑅0−1))/2)𝜉 𝑒((𝑐−√𝑐2−4(𝑅0−1))/2)𝜉

= lim

𝜉 → −∞

Υ1(𝜉) + Υ2(𝜉) + 𝛽𝑒((𝑐+√𝑐2−4(𝑅0−1))/2)𝜉 𝑒((𝑐−√𝑐2−4(𝑅0−1))/2)𝜉

= lim

𝜉 → −∞

Υ1(𝜉)

𝑒((𝑐−√𝑐2−4(𝑅0−1))/2)𝜉+ 𝛽 lim

𝜉 → −∞𝑒√𝑐2−4(𝑅0−1)𝜉 + lim

𝜉 → −∞

Υ2(𝜉)

𝑒((𝑐+√𝑐2−4(𝑅0−1))/2)𝜉 lim

𝜉 → −∞𝑒√𝑐2−4(𝑅0−1)𝜉= 0.

(70)

Thus,𝜒2(𝜉) = 𝛼[1 + 𝑜(1)]𝑒((𝑐−√𝑐2−4(𝑅0−1))/2)𝜉.

Now, we consider the first equation of model (64). We rewrite it as

𝜆󸀠󸀠− 𝑐𝜆󸀠− ](𝑅𝑑− 1) 𝜆 = − (]𝑅𝑑+ 𝑅0− 2]) 𝜇. (71) One can verify that (𝑐 − √𝑐2− 4(𝑅0− 1))/2 is not a characteristic of

𝜆󸀠󸀠− 𝑐𝜆󸀠−](𝑅𝑑− 1) 𝜆 = 0. (72) The above equation has two independent solutions of the following form:

𝜆(1)(𝜉) = 𝑒((𝑐−√𝑐2+4](𝑅𝑑−1))/2)𝜉, 𝜆(2)(𝜉) = 𝑒((𝑐+√𝑐2+4](𝑅𝑑−1))/2)𝜉.

(73) Thus, when𝜉 → −∞,𝜒1(𝜉)has the following property:

𝜒1(𝜉) = 𝛼 [1 + 𝑜 (1)] 𝑒((𝑐+√𝑐2+4](𝑅𝑑−1))/2)𝜉 + 𝛽 [1 + 𝑜 (1)] 𝑒((𝑐−√𝑐2+4](𝑅𝑑−1))/2)𝜉 + 𝛾 [1 + 𝑜 (1)] 𝑒((𝑐−√𝑐2−4(𝑅0−1))/2)𝜉

(74)

for some constants𝛼, 𝛽;𝛾 ̸= 0. Since𝜒1(−∞) = 0, thus𝛽 = 0.

So, when𝜉 → −∞, we have the following formula:

(𝜒1(𝜉)

𝜒2(𝜉)) = (𝛾 [1 + 𝑜 (1)] 𝑒((𝑐−√𝑐2−4(𝑅0−1))/2)𝜉

𝛼 [1 + 𝑜 (1)] 𝑒((𝑐−√𝑐2−4(𝑅0−1))/2)𝜉) . (75) Then, we study the exponential decay rate of the traveling wave solution as𝜉 → +∞. The asymptotic model of model (62) as𝜉 → +∞is

𝜓󸀠󸀠1 − 𝑐𝜓1󸀠+ 𝐷11𝜓1+ 𝐷12𝜓2= 0,

𝜓󸀠󸀠2 − 𝑐𝜓2󸀠+ 𝐷21𝜓1+ 𝐷22𝜓2= 0. (76) By setting(𝜓𝑖)󸀠(𝜉) = ̃𝜓𝑖,𝑖 = 1, 2, we rewrite model (76) as a first order model of ordinary differential equation in the four components(𝜓1, ̃𝜓1, 𝜓2, ̃𝜓2)𝑇:

𝜓󸀠1= ̃𝜓1,

̃𝜓󸀠1= 𝑐̃𝜓1− 𝐷11𝜓1− 𝐷12𝜓2, 𝜓󸀠2= ̃𝜓2,

̃𝜓󸀠2= 𝑐̃𝜓2− 𝐷21𝜓1− 𝐷22𝜓2.

(77)

In the case of (i)𝜇1 ̸= 𝜇2, we can obtain that the solution of model (77) has the following form:

(𝜓1, ̃𝜓1, 𝜓2, ̃𝜓2)𝑇=∑4

𝑖=1

𝑐𝑖𝑖𝑒𝜆𝑖𝜉, (78)

where

𝜆1= 𝑐 + √𝑐2+ 4𝜇1

2 , 𝜆2= 𝑐 − √𝑐2+ 4𝜇1

2 ,

𝜆3= 𝑐 + √𝑐2+ 4𝜇2

2 , 𝜆4= 𝑐 − √𝑐2+ 4𝜇2

2 ,

(79)

and ℎ𝑖(𝑖 = 1, 2, 3, 4) are the eigenvectors of the constant matrix with𝜆𝑖 (𝑖 = 1, 2, 3, 4)as the corresponding eigenval- ues,𝑐𝑖 (𝑖 = 1, 2, 3, 4)are arbitrary constants. Since

𝜉 → +∞lim (𝜓1, ̃𝜓1, 𝜓2, ̃𝜓2)𝑇= 0, (80) thus(𝜓1, ̃𝜓1, 𝜓2, ̃𝜓2)𝑇 = 𝑐22𝑒𝜆2𝜉 + 𝑐44𝑒𝜆4𝜉, so when 𝜉 → +∞, we can get that

(𝜒1(𝜉)

𝜒2(𝜉)) = (𝜅11+ 𝑜 (1)] 𝑒((𝑐−√𝑐2+4𝜇1)/2)𝜉 𝜅11+ 𝑜 (1)] 𝑒((𝑐−√𝑐2+4𝜇1)/2)𝜉) + (𝜅22+ 𝑜 (1)] 𝑒((𝑐−√𝑐2+4𝜇2)/2)𝜉

𝜅22+ 𝑜 (1)] 𝑒((𝑐−√𝑐2+4𝜇2)/2)𝜉) . (81)

参照

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