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UNIVALENCE CONDITION FOR A NEW GENERALIZATION OF THE FAMILY OF INTEGRAL OPERATORS

Serap Bulut

Abstract. In [3], Breaz et al. gave an univalence condition of the integral operator Gn,α introduced in [2]. The purpose of this paper is to generalize the definition of Gn,α by means of the Al-Oboudi differential operator and investigate univalence condition of this generalized integral operator. Our results generalize the results of [3].

2000 Mathematics Subject Classification: 30C45.

Keywords and phrases: Analytic functions, Univalent functions, Integral operator, Differential operator, Schwarz lemma.

1.Introduction Let A denote the class of all functions of the form

f(z) = z+

X

k=2

akzk (1)

which are analytic in the open unit disk U={z ∈C:|z|<1}, and S ={f ∈ A:f is univalent in U}.

For f ∈ A, Al-Oboudi [1] introduced the following operator:

D0f(z) =f(z), (2)

D1f(z) = (1−δ)f(z) +δzf0(z) = Dδf(z), δ≥0 (3) Dnf(z) = Dδ(Dn−1f(z)), (n∈N:={1,2,3, . . .}). (4) If f is given by (1), then from (3) and (4) we see that

Dnf(z) =z+

X

k=2

[1 + (k−1)δ]nakzk, (n ∈N0 :=N∪ {0}), (5)

(2)

with Dnf(0) = 0.

Remark 1. When δ= 1, we get S˘al˘agean’s differential operator [8].

The following results will be required in our investigation.

Schwarz Lemma [4]. Let the analytic function f be regular in the open unit disk U and let f(0) = 0. If

|f(z)| ≤1 (z ∈U), then

|f(z)| ≤ |z| (z ∈U), where the equality holds true only if

f(z) =Kz (z ∈U) and |K|= 1.

Theorem A [6]. Let

α∈C ( Reα >0) and

c∈C (|c| ≤1; c6=−1).

Suppose also that the function f(z) given by (1) is analytic in U. If

c|z|+ 1− |z|zf00(z) αf0(z)

≤1 (z ∈U), then the function Fα(z) defined by

Fα(z) :=

α

Z z

0

tα−1f0(t)dt α1

=z+· · · (6) is analytic and univalent in U.

Theoem B [5]. Let f ∈ A satisfy the following inequality:

z2f0(z) [f(z)]2 −1

≤1 (z ∈U). (7)

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Then f is univalent in U.

Theorem C [7]. Let the function g ∈ A satisfies the inequality (7). Also let

α∈R

α∈

1,3 2

and c∈C.

If

|c| ≤ 3−2α

α (c6=−1) and

|g(z)| ≤1 (z ∈U), then the function Gα(z)defined by

Gα(z) :=

α

Z z

0

(g(t))α−1dt α1

(8) is in the univalent function class S.

In [2], Breaz and Breaz considered the integral operator Gn,α(z) :=

[n(α−1) + 1]

Z z

0

(g1(t))α−1· · ·(gn(t))α−1dt

n(α−1)+11

(g1, . . . , gn∈ A) (9) and proved that the function Gn,α(z) is univalent in U.

Remark 2. We note that for n = 1, we obtain the integral operator in (8).

In [3], Breaz et al. proved the following theorem.

Theorem D [3]. Let M ≥ 1 and suppose that each of the functions gj ∈ A(j ∈ {1, . . . , n}) satisfies the inequality (7). Also let

α∈R

α∈

1, (2M + 1)n (2M+ 1)n−1

and c∈C.

If

|c| ≤1 +

1−α α

(2M+ 1)n

(4)

and

|gj(z)| ≤M (z ∈U; j ∈ {1, . . . , n}),

then the function Gn,α(z) defined by (9) is in the univalent function class S.

Now we introduce a new general integral operator by means of the Al- Oboudi differential operator.

Definition 1. Let n ∈ N, m ∈ N0 and α ∈ C. We define the integral operator Gn,m,α:An→ A by

Gn,m,α(z) :=

(

[n(α−1) + 1]

Z z

0 n

Y

j=1

(Dmgj(t))α−1dt

)n(α−1)+11

(z ∈U), (10) where g1, . . . , gn∈ A and Dm is the Al-Oboudi differential operator.

Remark 3. In the special case n= 1, we obtain the integral operator Gm,α(z) :=

α

Z z

0

(Dmg(t))α−1dt α1

(z ∈U). (11)

Remark 4. If we set m= 0 in (10) and (11), then we obtain the integral operators defined in (9) and (8), respectively.

2.Main results

Theorem 1. Let M ≥ 1 and suppose that each of the functions gj ∈ A(j ∈ {1, . . . , n}) satisfies the inequality

z2(Dmgj(z))0 (Dmgj(z))2 −1

≤1 (z ∈U; m∈N0). (12)

Also let

α∈R

α∈

1, (2M + 1)n (2M+ 1)n−1

and c∈C.

If

|c| ≤1 +

1−α n(α−1) + 1

(2M + 1)n

(5)

and

|Dmgj(z)| ≤M (z ∈U; j ∈ {1, . . . , n}),

then the integral operator Gn,m,α(z)defined by (10)is in the univalent function class S.

Proof. Since gj ∈ A (j ∈ {1, . . . , n}), by (5), we have Dmgj(z)

z = 1 +

X

k=2

[1 + (k−1)δ]mak,jzk−1 (m∈N0)

and Dmgj(z)

z 6= 0 for all z ∈U.

Also we note that Gn,m,α(z) =

(

[n(α−1) + 1]

Z z

0

tn(α−1)

n

Y

j=1

Dmgj(t) t

α−1

dt

)n(α−1)+11 .

Define a function

f(z) = Z z

0 n

Y

j=1

Dmgj(t) t

α−1

dt.

Then we obtain

f0(z) =

n

Y

j=1

Dmgj(z) z

α−1

. (13)

It is clear that f(0) =f0(0)−1 = 0.

The equality (13) implies that lnf0(z) = (α−1)

n

X

j=1

lnDmgj(z) z

or equivalently

lnf0(z) = (α−1)

n

X

j=1

(lnDmgj(z)−lnz).

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By differentiating above equality, we get f00(z)

f0(z) = (α−1)

n

X

j=1

(Dmgj(z))0 Dmgj(z) − 1

z

.

Hence we obtain

zf00(z)

f0(z) = (α−1)

n

X

j=1

z(Dmgj(z))0 Dmgj(z) −1

,

which readily shows that

c|z|2[n(α−1)+1]

+

1− |z|2[n(α−1)+1] zf00(z) [n(α−1) + 1]f0(z)

=

c|z|2[n(α−1)+1]

+

1− |z|2[n(α−1)+1]

α−1 n(α−1) + 1

n X

j=1

z(Dmgj(z))0 Dmgj(z) −1

≤ |c|+

α−1 n(α−1) + 1

n X

j=1

z2(Dmgj(z))0 (Dmgj(z))2

Dmgj(z) z

+ 1

.

From the hypothesis, we have |gj(z)| ≤ M (j ∈ {1, . . . , n} ; z ∈ U), then by the Schwarz lemma, we obtain that

|gj(z)| ≤M|z| (j ∈ {1, . . . , n} ;z ∈U).

Then we find

c|z|2[n(α−1)+1]

+

1− |z|2[n(α−1)+1] zf00(z) [n(α−1) + 1]f0(z)

≤ |c|+

α−1 n(α−1) + 1

n X

j=1

z2(Dmgj(z))0 (Dmgj(z))2

M + 1

≤ |c|+

α−1 n(α−1) + 1

n X

i=1

z2(Dmgj(z))0 (Dmgj(z))2 −1

M +M + 1

≤ |c|+

α−1 n(α−1) + 1

(2M + 1)n ≤1 since |c| ≤ 1 +

1−α n(α−1)+1

(2M + 1)n. Applying Theorem A, we obtain that Gn,m,α is in the univalent function classS.

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Remark 5. If we set m= 0 in Theorem ??, then we have Theorem D.

Corollary 2. Let each of the functions gj ∈ A (j ∈ {1, . . . , n}) satisfies the inequality (12). Suppose also that

α ∈R

α ∈

1, 3n 3n−1

and c∈C.

If

|c| ≤1 + 3

1−α n(α−1) + 1

n

and

|Dmgj(z)| ≤1 (z ∈U; j ∈ {1, . . . , n}),

then the integral operator Gn,m,α(z)defined by (10)is in the univalent function class S.

Proof. In Theorem 1, we consider M = 1.

Remark 6. If we set m = 0 in Corollary 2, then we have Corollary 1 in [3].

Corollary 3. Let M ≥ 1 and suppose that the functions g ∈ A satisfies the inequality (12). Also let

α ∈R

α ∈

1,2M + 1 2M

and c∈C.

If

|c| ≤1 +

1−α α

(2M + 1) and

|Dmg(z)| ≤M (z ∈U),

then the integral operator Gm,α(z) defined by (11) is in the univalent function class S.

Proof. In Theorem 1, we consider n= 1.

Remark 7. If we set m = 0 in Corollary 3, then we have Corollary 2 in [3].

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Remark 8. If we set M =n = 1 andm = 0 in Theorem 1, then we obtain Theorem C.

References

[1] F. M. Al-Oboudi,On univalent functions defined by a generalized S˘al˘agean operator, Int. J. Math. Math. Sci. 2004, no. 25-28, 1429-1436.

[2] D. Breaz and N. Breaz,Univalence of an integral operator, Mathematica (Cluj) 47 (2005), no. 70, 35-38.

[3] D. Breaz, N. Breaz and H. M. Srivastava, An extension of the univalent condition for a family of integral operators, Appl. Math. Lett. 22 (2009), no.

1, 41-44.

[4] Z. Nehari, Conformal Mapping, Dover, New York, NY, USA, 1975.

[5] S. Ozaki and M. Nunokawa, The Schwarzian derivative and univalent functions, Proc. Amer. Math. Soc. 33 (1972), 392-394.

[6] V. Pescar, A new generalization of Ahlfors’s and Becker’s criterion of univalence, Bull. Malaysian Math. Soc. (Ser. 2) 19 (1996), 53-54.

[7] V. Pescar,On the univalence of some integral operators, J. Indian Acad.

Math. 27 (2005), 239-243.

[8] G. S¸. S˘al˘agean, Subclasses of univalent functions, Complex Analysis- Fifth Romanian-Finnish seminar, Part 1 (Bucharest, 1981), Lecture Notes in Math., vol. 1013, Springer, Berlin, 1983, pp. 362-372.

Author:

Serap Bulut

Civil Aviation College Kocaeli University Arslanbey Campus 41285 ˙Izmit-Kocaeli Turkey

e-mail:[email protected]

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