Electronic Journal of Differential Equations, Vol. 2014 (2014), No. 170, pp. 1–13.
ISSN: 1072-6691. URL: http://ejde.math.txstate.edu or http://ejde.math.unt.edu ftp ejde.math.txstate.edu
NONLINEAR ELLIPTIC PROBLEM OF 2-q-LAPLACIAN TYPE WITH ASYMMETRIC NONLINEARITIES
DANDAN YANG, CHUANZHI BAI
Abstract. In this article, we study the nonlinear elliptic problem of 2-q- Laplacian type
−∆u−µ∆qu=−λ|u|r−2u+au+b(u+)θ−1 in Ω, u= 0 on∂Ω,
where Ω⊂RN is a bounded domain. Forais between two eigenvalues, we show the existence of three nontrivial solutions.
1. Introduction
In this article, we are interested in finding the multiple nontrivial weak solutions to the nonlinear elliptic problem of 2-q-Laplacian type,
−∆u−µ∆qu=−λ|u|r−2u+au+b(u+)θ−1 in Ω,
u= 0 on∂Ω, (1.1)
where Ω⊂RN is a bounded domain with samooth boundary∂Ω,λ, µ >0 are two parameters,N >2, 1<min{q, r} ≤max{q, r}<2< θ≤2∗=N2N−2,a∈R,b >0, andu+= max{u,0}. ∆qu= div(|∇u|q−2∇u) is theq-Laplacian ofu.
Paiva and Presoto [12] studied the semilinear elliptic problem with asymmetric nonlinearities,
−∆u=−λ|u|q−2u+au+b(u+)p−1 in Ω,
u= 0 on∂Ω. (1.2)
WhereN ≥3, 1< q <2< p≤2∗,a∈R,b >0 andλis a positive parameter.
Problem (1.2) is also closely related to the class of superlinear Ambrosetti-Prodi problems [6],
−∆u=au+ (u+)p+f(x) in Ω. (1.3) Further results for problem (1.3) can be found in [4, 5, 11, 14] and references cited therein.
2000Mathematics Subject Classification. 35J60, 35B38.
Key words and phrases. Quasilinear elliptic equations withq-Laplacian; critical exponent;
asymmetric nonlinearity; weak solution.
c
2014 Texas State University - San Marcos.
Submitted July 9, 2014. Published August 11, 2014.
1
Marano and Papageorgiou [10] obtained the existence of three solutions of the (p, q)-Laplacian problem
−∆pu−µ∆qu=f(x, u) in Ω,
u= 0 on∂Ω, (1.4)
by using variational methods and truncation arguments. Nonlinear elliptic problems involving the p-q-Laplacian operator is an active are of research; see [8, 9, 13, 15, 17, 18] and the references therein.
Motivated by the above works, we shall extend the results of problem (1.2) to problem (1.1). By using variational methods, we obtain three solutions to (1.1).
We say thatg is asymmetric whengsatisfies the Ambrosetti-Prodi type condition g−:= lim
t→−∞
g(t)
t < λk< g+:= lim
t→+∞
g(t) t .
Since problem (1.1) involves−∆ and−∆q, the arguments will be more compli- cated, and more analysis and estimates are needed.
The eigenvalue problem of the Laplacian, in Ω⊂RN, has the form
−∆u=λu in H01(Ω). (1.5)
By the Ljusternik-Schnirelman principle it is well known that there exists a non- decreasing sequence of nonnegative eigenvalues 0< λ1 < λ2≤ · · · ≤λj ≤. . . and a correspondent eigenfunctionsϕj. Also, the first eigenvalueλ1 is simple and the eigenfunctions associated withλ1do not change sign.
Now we are ready to state our main results.
Theorem 1.1. LetN ≥3,1<min{q, r} ≤max{q, r}<2< θ <2∗ andλk < a <
λk+1. Then, for λ > 0 and µ > 0 small enough, problem (1.1) has at least three nontrivial solutions.
Theorem 1.2. LetN ≥4,1<min{q, r} ≤max{q, r}<2< θ= 2∗ andλk < a <
λk+1. Then, for λ > 0 and µ > 0 small enough, problem (1.1) has at least three nontrivial solutions.
This article is organized as follows. In Section 2, we show some geometric con- ditions to establish the Mountain-Pass levels and give a technical lemma which is crucial in the proof of our main results. In Section 3, we establish the existence of three nontrivial solutions for the nonlinear elliptic problem (1.1).
2. Preliminaries
In this article,k·kpand|·|pdenote the norms onW01,p(Ω) andLp(Ω), respectively;
kukp=Z
Ω
|∇u|pdx1/p
, |u|p=Z
Ω
|u|pdx1/p .
For convenience, we substitutek · kfork · k2. The best Sobolev constant S of the embeddingH01(Ω),→L2∗(Ω) is denoted by
S= inf
u∈H01(Ω)\{0}
kuk2
|u|22∗
.
It is known thatS is independent of Ω and is never achieved except when Ω =RN (see [16]). Consider the energy functionalIλ,µ defined onH01(Ω) given by
Iλ,µ(u) =1
2kuk2+µ
qkukqq+λ r Z
Ω
|u|rdx−a 2
Z
Ω
|u|2dx−b θ
Z
Ω
(u+)θdx. (2.1) It is easy to know thatIλ,µis of classC2and there exists a one to one correspon- dence between the weak solutions of (1.1) and the critical points ofIλ,µ onH01(Ω).
By a weak solution of (1.1) we mean thatu∈H01(Ω) satisfying hIλ,µ0 (u), vi=
Z
Ω
[∇u∇v+µ|∇u|q−2∇u∇v]dx+λ Z
Ω
|u|r−2uvdx
−a Z
Ω
uvdx−b Z
Ω
(u+)θ−1vdx= 0 for allv∈H01(Ω).
Denote by ϕi a normalized eigenvector relative to eigenvalue λi of (1.5). Let Vk =hϕ1, . . . , ϕkiand Wk = Vk⊥. Without loss of generality, we suppose 0∈ Ω, andm∈Nlarge enough so thatB2/m⊂Ω, where B2/mdenotes the ball of radius 2/mwith center in 0. Consider the functions introduced in [7],
ζm(x) =
0 ifx∈B1/m,
m|x| −1 ifx∈Am=B2/m\B1/m, 1 ifx∈Ω\B2/m.
Setϕmi =ζmϕi,
Vkm=hϕm1, ϕm2, . . . , ϕmki
and Wkm = (Vkm)⊥. For each m ∈ N, define a positive cut-off function η ∈ Cc∞(B1/m) such that η ≡ 1 in B1/2m, η ≤ 1 in B1/m and k∇ηk∞ ≤ 4m; take ϕmk+1=ηϕk+1. Then
suppu∩suppϕmk+1=∅ (2.2)
wheneveru∈Vkm. By [7], it is easy to check the following Lemma.
Lemma 2.1. As m→ ∞we have
ϕmi →ϕi in H01(Ω) and max
u∈Vkm:R
Ω|u|2=1
kuk2≤λk+ckm2−N. Corollary 2.2. Formlarge enough
Vkm⊕Wk =H01. (2.3)
As an easy consequence of Lemma 2.1 we have the following decomposition of H01.
Lemma 2.3. Assume λ1 < a, 1 < min{q, r} ≤ max{q, r} < 2 < θ ≤ 2∗ and λ, µ >0. Then every(PS)sequence ofIλ,µ is bounded.
Proof. Suppose{un} ⊂H01(Ω) is a (PS) sequence ofIλ,µ; i.e., it satisfies
1
2kunk2+µ
qkunkqq+λ r Z
Ω
|un|rdx−a 2 Z
Ω
|un|2dx−b θ
Z
Ω
(u+n)θdx
≤C, (2.4)
Z
Ω
[∇un∇v+µ|∇un|q−2∇un∇v]dx+λ Z
Ω
|un|r−2unvdx
−a Z
Ω
unvdx−b Z
Ω
(u+n)θ−1vdx
≤nkvk, ∀v∈H01(Ω),
(2.5)
wheren →0 asn→ ∞. By (2.4) and (2.5), we obtain C+nkunk
≥
Iλ(un)−1
2hIλ0(un), uni
=
µ q −µ
2
kunkqq+ λ r −λ
2
Z
Ω
|un|rdx+ b 2 −b
θ
Z
Ω
(u+n)θdx
≥ b 2 −b
θ
Z
Ω
(u+n)θdx.
(2.6)
Thus, we have
Z
Ω
(u+n)θdx≤C+nkunk. (2.7) Moreover, by H¨older inequality, we have
Z
Ω
(u+n)2dx≤ |Ω|θ−2θ Z
Ω
(u+n)θdx2/θ
. (2.8)
On the other hand, by (2.5) we have
|hIλ,µ0 (un), u−ni|=
ku−nk2+µku−nkqq+λ|u−n|rr−a|u−n|22
≤nku−nk, (2.9) withu−= max{−u,0}. It follows from (2.4), (2.7), (2.8) and (2.9) that
1
2ku+nk2≤ µ 2 −µ
q
ku−nkqq+ λ 2 −λ
r
Z
Ω
|un|r
+a 2
Z
Ω
(u+n)2dx+b θ
Z
Ω
(u+n)θdx+1
2|hIλ,µ0 (un), u−ni|+C
≤a 2 Z
Ω
(u+n)2dx+ b θ
Z
Ω
(u+n)θdx+nku−nk+C
≤nkunk+nku−nk+C.
(2.10)
Firstly, we show that (u+n) is bounded inH01(Ω). Suppose by contradiction that ku+nk → ∞, by (2.10), we know that (u−n) is also unbounded. Letwn =un/kunk.
Since{wn} is bounded inH01(Ω), there existsw∈H01(Ω) such that wn * w inH01(Ω),
wn→w in Ls, ∀1≤s <2∗, wn→w a.e. in Ω.
From (2.10), there existsσ >0 satisfying
ku−nk ≥σku+nk2 (2.11)
whenevernis large. Notice that wn+= u+n
kunk = u+n
(ku+nk2+ku−nk2)1/2 ≤ u+n
(ku+nk2+σ2ku+nk4)1/2, which implies thatw≤0. Furthermore, by
w−n = u−n
kunk = u−n
(ku+nk2+ku−nk2)1/2 = u−n
ku−nk · ku−nk (ku+nk2+ku−nk2)1/2
and (2.11), we obtainkw−nk →1. Hence, by (2.9),
−λ|u−n|rr
ku−nk2 +µku−nkqq
ku−nk2 +a|u−n|2
ku−nk2 →1. (2.12) Recalling thatq, r <2, we obtain
ku−nkqq
ku−nk2 ≤ |Ω|2−q2 ku−nkq−2→0, (2.13)
|u−n|rr
ku−nk2 ≤ |Ω|2∗ −r2∗ S−22r∗ku−nk2r∗−2→0. (2.14) Moreover, by (2.11) andkwn−k →1, we have
u−n
ku−nk− u−n
kunk = u−n kunk
kunk ku−nk −1
→0 inH01(Ω).
Thus we may exchangeku−nkforkunkin (2.12), and substituting (2.13) and (2.14) into it, we obtain|w−n| →1/√
a, thenw6= 0. Takingv=ϕ1in (2.5), one has Z
Ω
[∇wn∇ϕ1dx+µkunkq−1q kunk
Z
Ω
|∇wn|q−2∇wn∇ϕ1dx
+ λ
kunk Z
Ω
|un|r−2unϕ1dx−a Z
Ω
wnϕ1dx− b kunk
Z
Ω
(u+n)θ−1ϕ1dx→0;
that is,
(λ1−a) Z
Ω
wnϕ1dx+µkunkq−1q kunk
Z
Ω
|∇wn|q−2∇wn∇ϕ1dx
+ λ
kunk Z
Ω
|un|r−2unϕ1dx− b kunk
Z
Ω
(u+n)θ−1ϕ1dx→0.
(2.15)
Since the second, the third and the fourth term above approach zero, it follows that (λ1−a)
Z
Ω
wϕ1dx= 0,
which is a contradiction, as w ≤0, w 6= 0 andλ1 < a, so that (u+n) is bounded.
Finally, assume that kunk → ∞ and ku+nk ≤C for all n∈N. Taking v =wn in (2.5), by (2.13) and
1 kunk
Z
Ω
(u+n)θdx→0,
forθ≤2∗, we obtain a|wn|22→1, so thatwn →win L2(Ω) withw6= 0. Then by (2.5) we obtain
Z
Ω
∇w∇vdx−a Z
Ω
wvdx= 0 for allv∈H01(Ω),
with w 6= 0 andw ≤0, which is a contradiction, as a is not the first eigenvalue.
Hence, we conclude that{un}must be bounded inH01(Ω).
In the subcritical case, 1≤θ <2∗, we can easily know according to the lemma above,Iλ,µ satisfies the (PS) condition at every level.
Lemma 2.4. Let λ1 < a and θ = 2∗. For each λ, µ >0, Iλ,µ satisfies the (PS) condition at levelc withc < N1b2−N2 SN/2.
Proof. Let{un} ⊂H01(Ω) be a sequence satisfying
Iλ,µ(un)→c and |hIλ,µ0 (un), vi| ≤nkvkp, ∀v∈H01(Ω), (2.16) withn→0 asn→ ∞. By Lemma 2.3 we obtain that {un}is bounded. Thus, by passing to a subsequence, we have
un* u inH01(Ω), un→u inLs, ∀1≤s <2∗,
un →u a.e. in Ω.
(2.17)
Since{u+n}is bounded inH01(Ω), from the Gagliardo-Nirenberg inequality it follows that {u+n} is also bounded in L2∗. By passing to a subsequence again, we have u+n * u+ in L2∗. Hence, we obtain by [11, Lemma 2.3] that
−∆u−µ∆qu=−λ|u|r−2u+au+b(u+)2∗−1, in Ω
u= 0 on∂Ω, (2.18)
Thus, by (2.18) we have Iλ,µ(u) = µ
q −µ 2
kukqq+ λ r −λ
2
Z
Ω
|u|rdx+ b 2− b
2∗
Z
Ω
(u+)2∗dx≥0. (2.19) Setwn =un−u. It is easy to check that
|u+n −u+|ss≤ |(un−u)+|ss=|w+n|ss, 1≤s≤2∗. (2.20) By (2.16) and the Brezis-Lieb Lemma, we have
kwnk2+µkwnkqq+λ|wn|rr−a|wn|22−b|u+n −u+|22∗∗
=kunk2− kuk2+µ(kunkqq− kukqq) +λ(|un|rr− |u|rr)
−a(|un|22− |u|22)−b |u+n|22∗∗− |u+|22∗∗
+on(1)
=hIλ,µ0 (un), uni − hIλ,µ0 (u), ui+o(1), which implies that
n→∞lim
kwnk2+µkwnkqq+λ|wn|rr−a|wn|22−b|u+n −u+|22∗∗
= 0. (2.21) Moreover, by (2.17) we havewn→0 inLrandL2. Thus, we have from (2.20) and (2.21) that
kwnk2+µkwnkqq =b|u+n −u+|22∗∗+o(1)≤b|wn+|22∗∗+o(1). (2.22) Without loss of generality, we assume that
kwnk2=d+o(1), kwnkqq =h+o(1). (2.23) By (2.22), (2.23) and Sobolev inequality, we obtain
d≥Sd+µh b
2/2∗
≥Sb−2/2∗d2/2∗. (2.24) Ifd= 0, then we complete the proof. Otherwise, (2.24) implies that
d≥SN/2b2−N2 . (2.25)
Then by (2.16), (2.19) and the Brezis-Lieb Lemma, we conclude c≥c−Iλ,µ(u) =Iλ,µ(un)−Iλ,µ(u) +o(1)
= 1
2 kunk2− kuk2 +µ
q kunkqq− kukqq +λ
r(|un|rr− |u|rr)−a
2 |un|22− |u|22
− b
2∗ |u+n|22∗∗− |u+|22∗∗
+o(1)
= 1
2kwnk2+µ
qkwnkqq+λ
r|wn|rr−a
2|wn|22− b
2∗|u+n −u+|22∗∗+o(1).
(2.26)
Letn→ ∞in (2.26), we obtain by (2.22), (2.23), (2.25) andwn →0 inLrandL2 that
c≥ d 2 +µh
q −d+µh 2∗
= 1 2− 1
2∗
d+ µ q − µ
2∗ h
≥ 1 2− 1
2∗ d
≥ 1
NSN/2b2−N2 ,
which is a contradiction.
3. Main result
Firstly, we consider the existence of the nonnegative solution of (1.1) . Define the functionalIλ,µ+ :H01(Ω)→Ras follows
Iλ,µ+ (u) =1
2kuk2+µ
qkukqq+λ r Z
Ω
(u+)rdx−a 2
Z
Ω
(u+)2dx−b θ
Z
Ω
(u+)θdx. (3.1) It follows that Iλ,µ+ ∈ C1 and the critical points u+ of Iλ,µ+ satisfy u+ ≥ 0 and so are critical points of Iλ,µ as well, actually, (Iλ,µ+ )0(u+)[(u+)−] = −k(u+)−k2− µk(u+)−kqq = 0.
Similar to the proofs of Lemma 2.3 and Lemma 2.4, we can show that Iλ,µ+ satisfies the (PS) condition.
Lemma 3.1. Let 2< θ≤2∗. If λ, µ >0, thenIλ,µ+ satisfies the(PS)condition at level cwith c < N1SN/2b2−N2 .
Lemma 3.2. The trivial solution u ≡ 0 is a local minimizer for Iλ,µ+ , for all λ, µ >0.
Proof. It suffices to show that 0 is a local minimizer of Iλ,µ+ in the topology (see [3]). Foru∈C01(Ω), we have
Iλ,µ+ (u) = 1
2kuk2+µ
qkukqq+λ r Z
Ω
(u+)rdx−a 2 Z
Ω
(u+)2dx−b θ
Z
Ω
(u+)θdx
≥ λ r Z
Ω
(u+)rdx−a 2
Z
Ω
(u+)2dx−b θ
Z
Ω
(u+)θdx
≥λ r −a
2|u|2−rC0 −b θ|u|θ−rC0
Z
Ω
(u+)rdx≥0
whenever
a
2|u|2−rC0 +b
θ|u|θ−rC0 ≤ λ r.
Lemma 3.3. There existst0>0such thatIλ,µ+ (t0ϕ1)≤0, for allλ, µin a bounded set.
Proof. Letϕ1 be the positive eigenfunction associated toλ1, fort >0, we have Iλ,µ+ (tϕ1) =t2
2kϕ1k2+tqµ
q kϕ1kqq+trλ r
Z
Ω
ϕr1dx−t2a 2
Z
Ω
ϕ21dx−tθb θ
Z
Ω
ϕθ1dx
=t2
2(λ1−a) Z
Ω
ϕ21dx+tqµ
q kϕ1kqq+trλ r
Z
Ω
ϕr1dx−tθb θ
Z
Ω
ϕθ1dx
Sinceλ1< aandq, r <2< θ, there exists a choice oft0>0 such thatIλ,µ+ (t0ϕ1)≤
0 forλ, µ in a bounded set.
Define
c+λ,µ= inf
γ∈Γ+ sup
t∈[0,1]
Iλ,µ+ (γ(t)), where
Γ+={γ∈ C([0,1], γ(0) = 0, γ(1) =t0ϕ1}.
On the other hand, by the proof of Lemma 3.3, we obtain Iλ,µ+ (tϕ1)≤ tqµ
q kϕ1kqq+trλ r
Z
Ω
ϕr1dx.
Then, if λand µ are small enough, c+λ,µ < N1SN/2b2−N2 , consequently, by means of the Mountain Pass Theorem,c+λ,µ is a critical value ofIλ,µ+ . Thus, we have the following result.
Lemma 3.4. Let N >2,1<min{q, r} ≤max{q, r}<2< θ≤2∗ andλ1< a. If λ, µ are small enough, then (1.1)has at least a nontrivial positive solution.
To obtain the negative solution, consider the functionalIλ,µ− :H01(Ω)→Rgiven by
Iλ,µ− (u) = 1
2kuk2+µ
qkukqq+λ r Z
Ω
(u−)rdx−a 2 Z
Ω
(u−)2dx. (3.2) Again, Iλ,µ− ∈ C1 and the critical points u− of Iλ,µ− satisfy u− ≤ 0 and so are critical points ofIλ,µas well. We will apply once again the mountain pass theorem to obtain a critical point ofIλ,µ− .
Lemma 3.5. The trivial solution u ≡ 0 is a local minimizer for Iλ,µ− , for all λ, µ >0.
Proof. It suffices to show that 0 is a local minimizer ofIλ,µ− in the topology. For u∈C01(Ω), we have
Iλ,µ− (u) = 1
2kuk2+µ
qkukqq+λ r Z
Ω
(u−)rdx−a 2 Z
Ω
(u−)2dx
≥ λ r Z
Ω
(u−)rdx−a 2 Z
Ω
(u−)2dx
≥ λ r −a
2|u|2−rC0
Z
Ω
(u−)rdx≥0
whenever a2|u|2−rC0 ≤λ/r.
Lemma 3.6. There exists t0 > 0 such that Iλ,µ− (−t0ϕ1) ≤ 0, for all λ, µ in a bounded set.
Proof. Fort >0, we have Iλ,µ− (−tϕ1) = t2
2kϕ1k2+tqµ
q kϕ1kqq+trλ r
Z
Ω
ϕr1dx−t2a 2
Z
Ω
ϕ21dx
= t2
2(λ1−a) Z
Ω
ϕ21dx+tqµ
q kϕ1kqq+trλ r
Z
Ω
ϕr1dx.
Sinceλ1< aand r, q <2, there exists a choice oft0 >0 which proves the lemma.
As in the nonnegative solution case, we obtain a critical value
c−λ,µ= inf
γ∈Γ− sup
t∈[0,1]
Iλ,µ− (γ(t)), where
Γ−={γ∈ C([0,1] :γ(0) = 0, γ(1) =−t0ϕ1}.
Similar to the proof of Lemma 3.5, we obtain the estimate c−λ,µ≤ max
s∈[0,1]Iλ,µ− (−st0ϕ1)≤ tq0µ
q kϕ1kqq+tr0λ r
Z
Ω
ϕr1dx,
which implies that if λ, µ are small enough, then we obtain the estimate c−λ,µ <
1
NSN/2b2−N2 , consequently, by the Mountain Pass Theorem, c−λ,µ is a critical value ofIλ,µ− . Hence, we obtain another important result.
Lemma 3.7. Let N >2,1<min{q, r} ≤max{q, r}<2< θ≤2∗ andλ1< a. If λ, µ small enough, then (1.1)has at least a nontrivial negative solution.
ForWk andVkm are as in Section 2, we now consider the existence of the third solution.
Lemma 3.8. There exist α >0 andρ >0 such that Iλ,µ(u)≥α wheneveru∈Wk andkuk=ρ.
Proof. Ifu∈Wk, then Iλ,µ(u) = 1
2kuk2+µ
qkukqq+λ r Z
Ω
|u|rdx−a 2 Z
Ω
|u|2dx− b θ
Z
Ω
(u+)θdx
≥ 1
2kuk2−a 2 Z
Ω
|u|2dx−b θ
Z
Ω
(u+)θdx
≥ 1 2 − a
2λk+1
kuk2−b θ|u|θθ
≥ kuk2 A−Bkukθ−2 ,
withA, B >0. Then it suffices to takeρ <(A/B)θ−21 .
Lemma 3.9. Given λ0>0 andµ0>0, there existm0∈NandR > ρ such that Iλ,µ(u)≤ µ
qkukqq+λ r Z
Ω
|u|rdx,
whenever u∈∂Qm, where Qm = (BR∩Vkm)⊕[0, Rϕmk+1], m≥m0, λ≤λ0 and µ≤µ0. Henceforth∂ means the boundary relative to subspaceVkm.
Proof. Letmbe large enough andak < asuch that
λk+ckm2−N ≤ak < a. (3.3) Foru∈Vkm, by Lemma 2.1 and (3.3) one can obtain
Iλ,µ(u) =1
2kuk2+µ
qkukqq+λ r Z
Ω
|u|rdx−a 2 Z
Ω
|u|2dx− b θ
Z
Ω
(u+)θdx
≤ 1 2 − a
2ak
kuk2+µ
qkukqq+λ r Z
Ω
|u|rdx− b θ
Z
Ω
(u+)θdx
≤µ
qkukqq+λ r Z
Ω
|u|rdx,
(3.4)
and
Iλ,µ(ξϕmk+1)
=ξ2
2 kϕmk+1k2+µξq
q kϕmk+1kqq+λξr r
Z
Ω
|ϕmk+1|rdx
−aξ2 2
Z
Ω
|ϕmk+1|2dx−bξθ θ
Z
Ω
((ϕmk+1)+)θdx
≤ξ2
2 kϕmk+1k2+µ0ξq
q kϕmk+1kqq+λ0ξr r
Z
Ω
|ϕmk+1|rdx−bξθ θ
Z
Ω
((ϕmk+1)+)θdx.
(3.5)
Sinceϕmk+1 →ϕk+1 in W01,2(Ω) asm→ ∞, ϕk+1 changes of sign, andθ >2, q, r, there existm0∈Nand R >0 such that
Iλ,µ(Rϕmk+1)≤0 ∀m≥m0. (3.6) Then combining (2.2), (3.4) and (3.6) leads to
Iλ,µ(u)≤ µ
qkukqq+λ r Z
Ω
|u|rdx, (3.7)
wheneveru∈Vkm∪(Vkm⊕Rϕmk+1). By (3.5), there existsβ >0 satisfying
Iλ,µ(ξϕmk+1)≤β, (3.8)
for allξ≥0 andm≥m0. Sincea > λk, we may takeR >0 such that Iλ,µ(u)≤ 1
2 − a 2λk
kuk2+µ
qkukqq+λ r Z
Ω
|u|rdx
≤ −β+µ
qkukqq+λ r Z
Ω
|u|rdx.
(3.9)
Hence, by (2.2), (3.8) and (3.9) we obtain
Iλ,µ(u+ξϕmk+1) =Iλ,µ(u) +Iλ,µ(ξϕmk+1)≤µ
qkukqq+λ r Z
Ω
|u|rdx (3.10) for allm≥m0 andu∈∂(BR∩Vkm). Thus, by (3.7) and (3.10), we complete the
proof.
Proof of Theorem 1.1. For the subcritical case, ifθ <2∗,αis given by Lemma 3.8.
Takeλandµsmall enough in order that µ
qkukqq+λ r Z
Ω
|u|rdx < α for allu∈∂Qm. Then by Lemma 3.9 we have
Iλ,µ(u)< α
wheneveru∈∂Qm andm≥m0. Applying the Linking Theorem,Iλ,µpossesses a critical pointuat level cλ,µ, where
cλ,µ= inf
Γ max
u∈Qm
Iλ,µ(η(u)),
Γ ={η∈ C(Qm, W01,p(Ω));η=Id on∂Qm},
Finally, sincecλ,µ≥α,Iλ,µ(u)≥α >0 andc±λ,µ→0 asλ, µ→0. Hence, ifλ, µare small enough c±λ,µ < α≤cλ,µ, and we know that umay be neither of the critical points found above forIλ,µ+ andIλ,µ− ; that is,uis the third solution of (1.1). Thus, combining Lemmas 3.4 and 3.7, we conclude that (1.1) has at least three nontrivial
solutions.
Proof of Theorem 1.2. For the critical case,θ = 2∗. Consider the family of func- tions taken from [1]:
u= CN(N−2)/2
(2+|x|2)(N−2)/2, >0, where
CN = (N(N−2))(N−2)/4.
Let um = ηu, where η is given as section 2, and Qm = (BR∩Vkm)⊕[0, Rum ].
Replacingum byϕmk+1 in Lemma 3.7, we obtain Iλ,µ(u)≤µ
qkukqq+λ r Z
Ω
|u|rdx, ∀u∈∂Qm
wheneverm is large. Hence, to conclude the proof of Theorem 1.2, it remains to show that
sup
u∈Qm
Iλ,µ(u)< 1
NSN/2b2−N2 (3.11)
for all,λandµsmall enough. Let J(u) =1
2kuk2−a 2 Z
Ω
|u|2dx− b 2∗
Z
Ω
(u+)2∗dx.
Then, we have
Iλ,µ(u) =J(u) +λ r Z
Ω
|u|rdx+µ qkukqq.
It is sufficient to prove that there existm0>0 and0>0 such that sup
u∈Qm
J(u)< 1
NSN/2b2−N2
for allm≥m0and < 0. It is not difficult to obtain the following expressions [2]:
Z
Ω
|∇um |2dx=SN/2+O(N−2), (3.12)
Z
Ω
|um |2∗dx=SN/2+O(N). (3.13) Moreover, we obtain
Z
Ω
|um |2dx= Z
B(0,1/m)
|u|2dx+O(N−2)
≥ Z
B(0,)
CN2N−2 [22]N−2 +
Z
<|x|<1/m
CN2N−2
[2|x|2]N−2 +O(N−2)
=
(d2|ln|+O(2), ifN= 4, d2+O(N−2), ifN≥5,
(3.14)
where dis a positive constant. If N = 4, according (3.12), (3.13) and (3.14), one has
kum k2−a|um |2
|um |22∗
≤ S2−ad2|ln|+O(2) (S2+O(4))1/2
=S−ad2|ln|S−1+O(2)< S, for >0 sufficiently small. And similarly, ifN≥5, we obtain
kum k2−a|um |2
|um |22∗
≤ SN/2−ad2+O(N−2) (SN/2+O(N))2/2∗
=S−ad2S(2−N)/2+O(N−2)< S,
for >0 sufficiently small. Let u=v+tum ∈ Qm. By simple computation, we obtain
maxt≥0 J(tum ) = b2−N2 N
kum k2−a|um |2
|um |22∗
N/2
< 1
NSN/2b2−N2 . (3.15) Fixm0>0 such thatλk+ckm2−N0 ≤σ < a. Then, form≥m0, we obtain
J(v) =1
2kvk2−a 2 Z
Ω
|v|2dx− b 2∗
Z
Ω
(v+)2∗dx
≤1
2kvk2−a
2|v|2≤σ
2|v|2−a
2|v|2≤0.
(3.16)
From (3.15) and (3.16), we obtain
J(u) =J(v+tum ) =J(v) +J(tum )≤J(tum )< 1
NSN/2b2−N2 .
So, (3.11) holds.
Lettingµ→0 in Theorem 1.1 and Theorem 1.2, we easily show that Theorems 1.1 and 1.2 extend the main results in Paiva and Presoto [12].
Acknowledgments. The authors want to thank the anonymous referees for their valuable comments and suggestions. This work is supported by Natural Science Foundation of Jiangsu Province (BK2011407) and Natural Science Foundation of China (11271364 and 10771212).
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Dandan Yang
School of Mathematical Science, Huaiyin Normal University, Huaian, Jiangsu 223300, China
E-mail address:[email protected]
Chuanzhi Bai
School of Mathematical Science, Huaiyin Normal University, Huaian, Jiangsu 223300, China
E-mail address:[email protected]