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Volume 2012, Article ID 242736,12pages doi:10.1155/2012/242736

Research Article

Decomposition of Automorphisms of

Certain Solvable Subalgebra of Symplectic Lie Algebra over Commutative Rings

Xing Tao Wang and Lei Zhang

Department of Mathematics, Harbin Institute of Technology, Harbin 150001, China

Correspondence should be addressed to Xing Tao Wang,[email protected] Received 26 March 2012; Accepted 26 April 2012

Academic Editor: Helge Holden

Copyrightq2012 X. T. Wang and L. Zhang. This is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited.

LetCl1Rbe the 2l1×2l1matrix symplectic Lie algebra over a commutative ringRwith 2 invertible. ThentCl1R {m01−mm2T

1 | m1is anl1 upper triangular matrix,mT2 m2, over R}is the solvable subalgebra ofCl1R. In this paper, we give an explicit description of the auto- morphism group oftCl1R.

1. Introduction

Classical Lie algebras occupy an important place in matrix algebras. LetRbe a commutative ringR with the identity 1 andR the group of invertible elements inR. LetMnRbe the R-algebra ofnbynmatrices overRthat has a structure of a Lie algebra overRwith bracket operationx, y xyyxfor anyx, yMnR. The symplectic Lie algebra

Cl1R

X|X 0 Il

−Il 0

0 Il

−Il 0

XT 0, X∈M2l2R

1.1

is one of classical Lie algebras, whereT denotes the matrix transpose. It is easy to show that the following subalgebra ofCl1Rsuch that

tCl1R

m1 m2

0 −mT1

|m1 is anl1 upper triangular matrix, mT2 m2 1.2

is solvable.

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Lete be the identity matrix inMnRand leteijndenotes the matrix inMnRall of whose entries are 0, except thei, jth entry which is 1. Let

αi,ikeni,ikenlik1,li1, i1, . . . , l−k1, k0,1, . . . , l, γi,ikeni,lik1eik,li1n , i1, . . . , l−k1, k1, . . . , l,

γiiei,li1n , i1, . . . , l1,

1.3

wheren2l1,l≥1. For discussion latter, we rewritetCl1Ras

tCl1R l

k0 l−k1

i1

i,ikl

k0 l−k1

i1

i,ik. 1.4

Automorphisms of associative algebras have been explored in many articles 1–8.

Encouraged by Dokovi´c9and Cao’s10papers which described the automorphism groups of Lie algebra consisting of all upper triangularn×nmatrices of trace 0 over a connected commutative ring and a commutative ring withninvertible, respectively, in this paper we use similar techniques to those in11to prove that any automorphismψ oftCl1Rcan be uniquely expressed asψ θλD, where θ and λD are inner and diagonal automorphisms, respectively, forl≥1 andRis a commutative ring with 2 invertible. We also give an explicit description of the remaining casel0.

Theorem 1.1. For any automorphismψoftCl1R l≥1there are unique inner and diagonal auto- morphisms,θandλD, respectively, oftCl1Rsuch thatψθλD.

Theorem 1.2. Let I and D be the inner and diagonal automorphism groups, respectively. Then AuttCl1R ID, where AuttCl1Rdenotes the automorphism group oftCl1R.

2. Preliminaries

Let

Pni,ik|i1, . . . , l−k1, k0,1, . . . , l}, Wn

γi,ik|i1, . . . , l−k1, k0,1, . . . , l .

2.1

Then the setPnWnis a basis oftCl1R.

Lemma 2.1. LetHnbe the set generated by the setjj, αi,i1, γl1,l1|1≤jl1,1≤il}, where n2l1. ThenHntCl1R.

(3)

Proof. We only need to show thattCl1R⊆ Hn. It is obvious thatαi,ikHn, whenk 0,1.

Whenk2, we have

αi,i2 eni,i2eli3,li1n

eni,i1eli2,li1n ,

ei1,i2neli3,li2n αi,i1, αi1,i2Hn.

2.2

Assume thatαi,ik−1Hn, thenαi,ik αi,ik−1, αik−1,ikHn, that is,PnHn. Sinceγl1,l1Hn, for anyγl−k1,l−k2Wn, whenk1,

γl,l1enl,2l2el1,2l1n

enl,l1en2l2,2l1

, enl1,2l2

αl,l1, γl1,l1

Hn.

2.3

Assume that whenkm−1,γl−m2,l−m3Hn, then whenk m,γl−m1,l−m2 αl−m1,l−m3, γl−m2,l−m3Hn, that is,γi,i1Hn,i 1, . . . , l. For anyγi,ikHn k ≥ 1, whenk 1, γi,i1Hn. Whenk≥2,γi,ik αi,ik−1, γik−1,ikHn. Since 2γii αi,i1, γi,i1Hn, and 2 is invertible, we haveγiiHnfor 1≤il. ThusWnHn. BecausePnWnis a basis oftCl1R, we obtaintCl1R⊆Hn.

Now, denotetCl1R bynC0 . Let nC1 nC0 ,nC0 ,nC2 nC1 ,nC1 ,nCj nC1 , nCj−1,j 3, . . . ,2l1. It is not difficult to know

nCj l

kj l−k1

i1

i,ikl

kj

l1

il2−k1/2

2l−k−i3,i

2l1

kl1

l1−k/2

i1

i,2l−k−i3, 1≤jl,

nCj 2l1

kj

l1−k/2

i1

i,2l−k−i3, l1≤j ≤2l1l≥2, nCj 0, 2l2≤j.

2.4

It is easy to check thatnCm ,nClnCmlforml≤2l1 ornCm ,nCl 0 forml≥ 2l2. For anyψ ∈ AutnC0 , we haveψnC1 ψnC0 , ψnC0 nC0 ,nC0 nC1 and ψnCj nCj ,j 2, . . . ,2l1. Therefore,ψnCj−1\nCj nCj−1\nCj ,j 1, . . . ,2l1. Note that ifγijWn, thenγijnC2l−i−j3\nC2l−i−j4.

For any maximal idealMofR,R R/Mis a field. The natural homomorphismπ : RR induces a homomorphism ψM : tCl1R → tCl1R which is surjective. So every

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automorphismψ oftCl1Rmay induce an automorphismψ of tCl1R. Using this fact and thatnC2l1 11 for l ≥ 1, we have thatψγ11 c11γ11, wherec11R. Otherwise,c11

should be contained in a maximal idealMofR, thenψγ11 0 ontCl1R, whereγ11 is the image ofγ11intCl1R, which is impossible.

Lemma 2.2. Letψbe in AutnC0 . Ifψαjj,ψαj,j1andψγl1,l1are expressed, respectively, as

ψ αjj

l1

i1

ajii αiimodnC1 , j1, . . . , l1, 2.5

ψ αj,j1

l

i1

aji,i1αi,i1cjl1,l1γl1,l1modnC2 , j1, . . . , l, 2.6

ψ γl1,l1

l

i1

al1i,i1αi,i1cl1l1,l1γl1,l1modnC2 , 2.7

then the following matrices are invertible.

iA ajil1×l1, whereajiajii ,j1, . . . , l1,i1, . . . , l1;

iiB bjil1×l1, wherebjiaji,i1,j 1, . . . , l,i1, . . . , l,bj,l1 cjl1,l1,j 1, . . . , l, bl1,ial1i,i1,i1, . . . , landbl1,l1 cl1l1,l1.

Proof. iThatAis invertible follows from the fact thatψ induces an automorphism of the freeR-modulenC0 /nC1 of rankl1 on the basis{αjjnC1 | j 1, . . . , l1}.iiNote that ψinduces an automorphism of the freeR-modulenC1 /nC2 of rankl1 on the basis{αj,j1 nC2 , γl1,l1nC2 | j1, . . . , l}.

Lemma 2.3. Letψ ∈ AutnC0 l ≥ 2. Writeψαjj,ψαj,j1, andψγl1,l1as in2.5–2.7, respectively. Then the following conclusions hold.

iFor 1m, k, hl,amh,h1amk,k1 0h /k,amh,h1cml1,l1 0,al1h,h1al1k,k1 0h /k and al1h,h1cl1,l1l1 0.

iiFor 1k, hl,aihh−aih1,h1aikk−aik1,k1 0 h /k andaihh−aih1,h1ail1,l10 1≤hl, herel≥1, where i1, l1.

iiiFor 2mland 1i, k, hl,amiiami1,i1amhhamh1,h1amkkamk1,k1 0 i /h /k /i, herel≥3andamiiami1,i1amhhamh1,h1aml1,l101≤i /hl.

Proof. iWhenj /m, m1,ψαjj, ψαm,m1 0. So

ami,i1

ajiiaji1,i1

0, cml1,l1ajl1,l10. 2.8

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Fromψαmm, ψαm,m1 ψαm,m1andψαm1,m1, ψαm,m1 −ψαm,m1, we have

ami,i1

amiiami1,i1

ami,i1, 2cml1,l1aml1,l1cl1,l1m ,

ami,i1

am1iiam1i1,i1

ami,i1, 2cml1,l1am1l1,l1cl1,l1m .

2.9

Whenj /l1,ψαjj, ψγl1,l1 0. So

al1i,i1

ajiiaji1,i1

0, cl1l1,l1ajl1,l10. 2.10

Fromψαl1,l1, ψγl1,l1 2ψγl1,l1, we have

al1i,i1

al1iial1i1,i1

2al1i,i1, cl1,l1l1 al1l1,l1cl1l1,l1. 2.11

LetC cjil1×l1, wherecjiajiiaji1,i1,j 1, . . . , l1,i1, . . . , l, andcj,l1 2ajl1,l1, j 1, . . . , l1. By Lemma 2.2, detAR, so detCR. Investigating amh,h1amk,k1detC, we may find that hth column and kth column are linearly dependent both are the form 0, . . . ,0,amj,j1,amj,j1,0, . . . ,0t, j h, kby2.6and2.7, soamh,h1amk,k1detC0. Similarly,

amh,h1cml1,l1detC 0, al1h,h1al1k,k1detC 0h /k andal1h,h1cl1l1,l1detC 0. Then amh,h1

amk,k10h /k,amh,h1cml1,l10,al1h,h1al1k,k10 h /k, andal1h,h1cl1,l1l1 0.

iiWheni1, froma1hha1h1,h1a1kka1k1,k1detB 0h /k, we havea1hha1h1,h1a1kka1k1,k1 0 h /k. Similarly, we havea1hha1h1,h1a1ll a1l1,l1 01 ≤ hl. Whenil1, we get the results similarly.

iiiThe proving process is similar toiandii.

Lemma 2.4. Letψ ∈AutnC0 . Then

iwhenl1,ψα12 a112α12modnC2 , wherea112R;

iiif ψα12 a112α12modnC2 , where a112R, then ψαi,i1 aii,i1αi,i1modnC2 andψγl1,l1 cl1l1,l1γl1,l1modnC2 , whereaii,i1,cl1l1,l1R.

Proof. iNoting thatαi,i1, γl1,l1nC1 \nC2 andγ12nC2l \nC2l1, we haveψα12nC1 \nC2 and ψγ12 c1212 γ12modnC2l1nC2l \nC2l1, where c1212R. Using 2.7, from ψα11, ψγ12 ψγ12, we havec1212a111 a122 c1212 , that is,a111 a122 1. Writeψα11andψγ11 asψα11

l1

i1a1ii αii modnC1 andψγ11 c11 γ11nC2l1, wherec11R. From 2ψγ11

ψα11, ψγ11 2a111c11γ11, we havea111 1. Thena122 0. ByLemma 2.3we havea1iia1i1,i1 0, i2, . . . , lherel≥2anda1l1,l10. Soa1ii 0, i2, . . . , l1, that is,ψα11

a111 modnC1 . Thenψα12 ψα11, ψα12 a112α12modnC2 anda112R. ByLemma 2.3, iholds.

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iiWriteψαj,j1andψγl1,l1as2.6and2.7, respectively. Fromψα13 ψα12, ψα23, we haveψα13 a112a223α13 modnC3 . Sinceα13nC2 \nC3 ,ψα13nC2 \nC3 . So

a112a223R, that is,a223R. In general, form2, . . . , l, we have

ψα1,m1

m i1

aii,i1α1,m1modnCm1nCm \nCm1, m1, . . . , l,

ψ γ1,l1

ψα1,l1, ψ

γl1,l1 l

i1

aii,i1cl1l1,l1γ1,l1modnCl2nCl1 \nCl2,

2.12

hereaii,i1, cl1l1,l1 should be inR,i 1, . . . , l. By Lemma 2.3we have thataji,i1 0i /j,

cjl1,l1 0,j 1, . . . , l, andal1i,i1,i1, . . . , l. Henceψαl,l1andψγl1,l1have the required forms, respectively.

3. The Standard Automorphisms of t

Cl1

R

Now let us introduce two types of Lie automorphisms oftCl1R.

(i) Inner Automorphisms

Letr Iniji /jorrInij. It is easy to check thatryr−1nC0 . The mapθr:tCl1R → tCl1Rsuch thatxrxr−1,xnC0 , defines an automorphism ofnC0 , which is called an inner automorphismnote thatr is a symplectic matrix defined by

0 Il1

−Il1 0

. We denoteθr

byθij,θij, respectively. In these cases, we have θ−1ij θ−aαij,θ−1ij θ−aγij, respectively, and thatθijαii αiiij,θijαjj αjj ij,θijαkk αkkk /i, j,θijαk,k1 αk,k1k /j, i−1,θijαj,j1 αj,j1i,j1,θijαi−1,i αi−1,ii−1,j,θiiαii αii−2aγii, θi,i1αi,i1 αi,i1−2aγiiandθi,i1γi,i1 γi,i12aγii. All inner automorphisms oftCl1R generate a subgroup of AutnC0 , which is denoted byI.

(ii) Diagonal Automorphisms

LetdiR,i 0,1, . . . , l1,d diagd1, . . . , dl1andD diagd, d−1d0. The mapλD: tCl1R → tCl1Rsuch thatxDxD−1,xnC0 , defines an automorphism oftCl1R, which is called a diagonal automorphism. It is clear thatλDλDλDD. So the set of diagonal automor- phisms oftCl1Ris a subgroup of AutnC0 , which is denoted byD.

4. Lemmas for Main Results

Lemma 4.1. Letψ ∈AutnC0 . The following two statements are equivalent:

(i)ψαj,j1 ajj,j1αj,j1modnC2 andψγl1,l1 cl1l1,l1γl1,l1modnC2 , whereajj,j1, cl1l1,l1R,j 1, . . . , l;

(ii)ψαjj αjj modnC1 , j 1, . . . , l1.

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Proof. i⇒ii. Writeψαjjas in2.5. By the process of proving Lemma 2.3, we have a112 a111a122 a112,aii,i1ai1iiai1i1,i1aii,i1,ai1i1,i2ai1i1,i1ai1i2,i2 ai1i1,i2,i1, . . . , l−1 andall,l1al1llal1l1,l1all,l1,cl1l1,l1al1l1,l1 cl1,l1l1 . Then we obtain thata111a122 1, ai1iiai1i1,i1−1,ai1i1,i1ai1i2,i21,i1, . . . , l−1 andal1l1,l1 1. ByLemma 2.3, we have ajjj 1 1≤jl1andajii 0i /j.

ii⇒i. Writeψαj,j1andψγl1,l1, respectively, as in2.6and2.7. Then ψ

αj,j1

ψ αjj

, ψ αj,j1

ajj,j1αj,j1modnC2 , j 1, . . . , l, 2ψ

γl1,l1

ψαl1,l1, ψ

γl1,l1

2cl1,l1l1 γl1,l1modnC2 ,

4.1

that is,ψγl1,l1 cl1l1,l1γl1,l1modnC2 . By the method of modularizing a maximal ideal of Rto a residue field, we know thatajj,j1,cl1l1,l1R,j1, . . . , l.

Lemma 4.2. Letψbe in AutnC0 . Ifψαjj αjjmodnC1 , then ψα11 α11a112α12modnC2 , ψ

αjj

αjjaj−1j−1,jαj−1,jajj,j1αj,j1modnC2 , j2, . . . , ll≥2, ψαl1,l1 αl1,l1all,l1αl,l1cl1l1,l1γl1,l1modnC2 .

4.2

Proof. We expressψαjjas

ψ αjj

αjjl

i1

aji,i1αi,i1cjl1,l1γl1,l1modnC2 , j1, . . . , l1. 4.3

Fromψαjj, ψαkk 0 j /kwe have

ψα11 α11a112α12modnC2 , ψ

αjj

αjjajj−1,jαj−1,jajj,j1αj,j1modnC2 , j 2, . . . , l l≥2,

ψαl1,l1 αl1,l1al1l,l1αl,l1cl1,l1l1 γl1,l1 modnC2 ,

4.4

whereajj,j1aj1j,j1 0, j1, . . . , l.Lemma 4.2is proved.

Lemma 4.3. Letψ be in AutnC0 . If everyψαjjis expressed as the form inLemma 4.2, one may find an inner automorphism

θl

j1

θaj

j,j1αj,j1θ2−1cl1l1,l1γl1,l1 4.5

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such that

θψ αjj

αjj modnC2 , j1, . . . , l1. 4.6

Proof. Note thatθ2−1cl1,l1l1 γl1,l1αl1,l1 αl1,l1cl1l1,l1γl1,l1. Then, byLemma 4.2, it is not difficult to proveLemma 4.3.

Lemma 4.4. Letψbe in AutnC0 . Ifψαjj αjjmodnCk , j1, . . . , l1 1≤kl1, then

ψ αjj

αjjajj,jkαj,jk modnCk1 , j 1, . . . ,min{k, l−k1}k≤l, l≥1,

ψ αjj

αjjaj−kj−k,jαj−k,j ajj,jkαj,jkmodnCk1, jk1, . . . , l−k1

k

l1 2

, l≥2

, ψ

αjj

αjjaj−kj−k,jαj−k,jcj,2l−k−j3j γj,2l−k−j3modnCk1, j lk2, . . . , l−

k 2

1

kl1

2

, l≥1

, ψ

αjj

αjjcjj,2l−k−j3γj,2l−k−j3modnCk1, j lk2, . . . , l−

k 2

1

1 l1

2

k, l≥2

, ψ

αjj

αjjcjj,2l−k−j3γj,2l−k−j3modnCk1, j l

2 1

k l

21, l≥4, herep even

, ψ

αjj

αjjaj−kj−k,jαj−k,jcj,2l−k−j3j γj,2l−k−j3modnCk1, j l

22, . . . , l− k

2

1

k l

2 1, l≥4, herepeven

, ψ

αjj

αjjc2l−k−j32l−k−j3,jγ2l−k−j3,j modnCk1, jl

k 2

2, . . . , k

l2≤k k

2

, l≥3

, ψ

αjj

αjjaj−kj−k,jαj−k,jc2l−k−j3,j2l−k−j3γ2l−k−j3,j modnCk1, j max

k1, l− k

2

2

, . . . , l1

kp, k

2

≥1, l≥2

.

4.7

Proof. We expressψαjj, j1, . . . , l1, as

ψ αjj

αjjl−k1

i1

aji,ikαi,ik l1

il2−k1/2

cj2l−k−i3,iγ2l−k−i3,imodnCk1. 4.8

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Whenk1 that is the case inLemma 4.2. The conclusion follows from repeating the process of provingLemma 4.4.

Lemma 4.5. Letψbe in AutnC0 . If everyψαjjbe expressed as the form inLemma 4.4, one may find an inner automorphism

θl−k1

j1

θaj

j,jkαj,jk

l−k/21

jl−k2

θ

jl−1cjj,2l−k−j3γj,2l−k−j3, 4.9

where

δij

1, ij,

0, i /j, hl1−k−1/2k an odd. 4.10

Then

θψ αjj

αjj modnCk1, i1, . . . , l1. 4.11

Proof. Applyθtoψαjjand useLemma 4.4to obtainLemma 4.5.

Lemma 4.6. Letψbe in AutnC0 . Ifψαjj αjjmodnCk , j1, . . . , l1,l1k≤2l1l≥1, then

ψ αjj

αjjcjj,2l−k−j3γj,2l−k−j3modnCk1, j 1, . . . , l− k

2

1,

ψ αjj

αjjc2l−k−j32l−k−j3,jγ2l−k−j3,j modnCk1, jlk

2

2, . . . ,2l−k2, ψ

αjj

αjj modnCk1, j2l−k3, . . . , l1.

4.12

Proof. We expressψαjj, j1, . . . , l1, as

ψ αjj

αjjl−k/21

i1

ci,2l−k−i3j γi,2l−k−i3modnCk1. 4.13

The process of provingLemma 4.6is similar toLemma 4.2.

Lemma 4.7. Letψ be in AutnC0 . If everyψαjjis expressed as the form inLemma 4.6, one may find an inner automorphism

θl−k/21

j1

θ

jh−1cjj,2l−k−j3γj,2l−k−j3, 4.14

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wherehl1−k−1/2 (kan odd). Then

θψ αjj

αjj modnCk1. 4.15

Whenk2l1,θψαjj αjj, j 1, . . . , l1.

Proof. It is similar to provingLemma 4.5.

Lemma 4.8. Whenl1, letψbe in AutnC0 . Ifψαjj αjj, j 1, . . . , l1, there exists a diagonal automorphismλDsuch thatλDψαj,j1 αj,j1,i1, . . . , l, andλDψγl1,l1 γl1,l1.

Proof. By Lemma 4.1we know that ψαj,j1 ajj,j1αj,j1modnC2 and ψγl1,l1 cl1l1,l1 γl1,l1modnC2 , whereajj,j1,cl1l1,l1R,j 1, . . . , l. We express ψαj,j1and ψγl1,l1, respectively, as

ψ αj,j1

ajj,j1αj,j1l

k2 l−k1

i1

aji,ikαi,ik

l

k2

l1 il2−k1/2

c2l−k−i3,ij γ2l−k−i3,i

2l1

kl1

l1−k/2

i1

cji,2l−k−i3γi,2l−k−i3, 1≤jl,

ψ γl1,l1

cl1l1,l1γl1,l1l

k2 l−k1

i1

al1i,ikαi,ik

l

k2

l1 il2−k1/2

cl12l−k−i3,iγ2l−k−i3,i 2l1

kl1

l1−k/2

i1

cl1i,2l−k−i3γi,2l−k−i3.

4.16

Then

ϕ αj,j1

ϕ

αjj

, ϕ

αj,j1 , ϕ

αj1,j1

ajj,j1αj,j1cjj,j1γj,j1, j 1, . . . , l.

4.17

In addition,

ϕ αj,j1

ϕ

αjj

,

ajj,j1αj,j1bjj,j1βj,j1

, ϕ

αj1,j1

ajj,j1αj,j1cjj,j1γj,j1, j1, . . . , l.

4.18

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Thuscjj,j10, j1, . . . , l. So ψ

αj,j1

ajj,j1αj,j1, j1, . . . , l. 4.19 Furthermore,

γl1,l1

ψαl1,l1, ψ

γl1,l1

2cl1l1,l1γl1,l1l−1

i1

al1i,l1αi,l1l−1

i1

cl1i,l1γi,l1. 4.20

Fromψαii, ψγl1,l1 0i /l−1, we haveal1i,l1 0 andcl1i,l1 0,i1,· · ·, l−1, that is, ψ

γl1,l1

cl1,l1l1 γl1,l1. 4.21

Letddiagd1, . . . , dl1andd0cl1l1,l1d2l1, whered1 1, djj

i2aj−i1j−i1,j−i2,j 2, . . . , l1.

ApplyingλDtoψαj,j1,j 1, . . . , l, andψγl1,l1, we get the result.

5. Proofs of Main Results

Proof ofTheorem 1.1. By Lemmas4.3,4.5,4.7, and4.8we haveλDθψαjj αjj, j1, . . . , l1, λDθψαj,j1 αj,j1, j 1, . . . , l, andλDθψγl1,l1 γl1,l1. Since the set{γl1,l1,αl1,l1,αjj, αj,j1 | j 1, . . . , l}generatestCl1R, we know that λDθψ is the identity automorphism of tCl1R. Henceψ θλD−1. The uniqueness of the decomposition follows fromTheorem 1.2.

Proof ofTheorem 1.2. By the first part ofTheorem 1.1we have AuttCl1R ID. For anyxtCl1RandαijnC1 we have

λDθijλ−1Dx D

Inij

D−1xD

Inij

−1 D−1

InD

αij

x

InD

αij

−1 θDαijx.

5.1

So λDθij θDαijλD. ForγijnC1 , we haveλDθij θDγijλD. Therefore, I ID.

ObviouslyI ∩ D1. Then,IDID.

6. Discussion for l 0

In this case,tC1 R is generated byα11 and γ11. For any automorphismψ of tC1 R, write ψα11 and ψγ11, respectively, as ψα11 a11α11 c11γ11 and ψγ11 11, where cR. From 2ψγ11 ψα11, ψγ11, we have a11 1. Then θ2−1c11γ11ψα11 α11 and θ2−1c11γ11ψγ11 11. Alsoηcθ2−1c11γ11ψα11 α11 andηcθ2−1c11γ11ψγ11 γ11. Soψ θ−2−1c11γ11

ηc−1.

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Acknowledgments

The research was supported partially by National Natural Science Foundation of China Grant nos. 10871056 and 10971150and by Science Research Foundation in Harbin Institute of TechnologyGrant no. HITC200708.

References

1 G. Ancochea, “On semi-automorphisms of division algebras,” Annals of Mathematics. Second Series, vol. 48, pp. 147–153, 1947.

2 K. I. Beidar, M. Breˇsar, and M. A. Chebotar, “Jordan isomorphisms of triangular matrix algebras over a connected commutative ring,” Linear Algebra and Its Applications, vol. 312, no. 1–3, pp. 197–201, 2000.

3 M. Breˇsar, “Jordan mappings of semiprime rings,” Journal of Algebra, vol. 127, no. 1, pp. 218–228, 1989.

4 Y. A. Cao, “Automorphisms of the Lie algebra of strictly upper triangular matrices over certain commutative rings,” Linear Algebra and its Applications, vol. 329, no. 1–3, pp. 175–187, 2001.

5 L. N. Herstein, “Jordan homomorphisms,” Transactions of the American Mathematical Society, vol. 81, pp. 331–351, 1956.

6 S. Jøndrup, “Automorphisms of upper triangular matrix rings,” Archiv der Mathematik, vol. 49, no. 6, pp. 497–502, 1987.

7 F. Kuzucuoglu and V. M. Levchuk, “The automorphism group of certain radical matrix rings,” Journal of Algebra, vol. 243, no. 2, pp. 473–485, 2001.

8 X. T. Wang and Y. M. Li, “Decomposition of Jordan automorphisms of triangular matrix algebra over commutative rings,” Glasgow Mathematical Journal, vol. 52, no. 3, pp. 529–536, 2010.

9 D. ˇZ. Dokovi´c, “Automorphisms of the Lie algebra of upper triangular matrices over a connected commutative ring,” Journal of Algebra, vol. 170, no. 1, pp. 101–110, 1994.

10 Y. A. Cao, “Automorphisms of certain Lie algebras of upper triangular matrices over a commutative ring,” Journal of Algebra, vol. 189, no. 2, pp. 506–513, 1997.

11 X. T. Wang and H. You, “Decomposition of Lie automorphisms of upper triangular matrix algebra over commutative rings,” Linear Algebra and its Applications, vol. 419, no. 2-3, pp. 466–474, 2006.

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