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Introduction In this paper we investigate the existence of bounded solutions for the following class of fractional order differential equations cDαy(t) =f(t, y(t),cDα−1y(t

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ISSN: 1821-1291, URL: http://www.bmathaa.org Volume 4 Issue 1(2012), Pages 62-71.

BOUNDED SOLUTIONS FOR FRACTIONAL ORDER DIFFERENTIAL EQUATIONS ON THE HALF-LINE

(COMMUNICATED BY CLAUDIO CUEVAS)

MOUFFAK BENCHOHRA, FARIDA BERHOUN, GASTON N’GU ´ER ´EKATA

Abstract. We provide in this paper, sufficient conditions for the existence of bounded solutions for a class of initial value problem on the half-line for fractional differential equations involving Caputo fractional derivative with a nonlinear term depending on the derivative, using the Schauder fixed point theorem combined with the diagonalization process.

1. Introduction

In this paper we investigate the existence of bounded solutions for the following class of fractional order differential equations

cDαy(t) =f(t, y(t),cDα1y(t)), t∈J:= [0,), 1< α≤2, (1.1) y(0) =y0, y is bounded on J, (1.2) where cDα is the Caputo fractional derivative of order 1< α≤2,f :J ×RR is a continuous function,y0R.

Differential equations of fractional order have recently proved to be valuable tools in the modeling of many phenomena in various fields of science and engineering.

Indeed, we can find numerous applications in viscoelasticity, electrochemistry, con- trol, porous media, electromagnetic, etc. (see [14, 17, 22, 23, 24]). There has been a significant development in the study of fractional differential equations in recent years; see the monographs of Kilbaset al[19], Lakshmikanthamet al. [20], Podlubny [23], Samkoet al. [25]. For some recent contributions on fractional differ- ential equations, see [1, 5, 7, 8, 9, 10, 11, 12, 13, 21, 26] and the references therein.

For more details on the geometric and physical interpretation for fractional deriva- tives of both the Riemann-Liouville and Caputo types see [16, 24]. Very recently, Agarwal et al. [2] have considered a class of boundary value problems involving Riemann-Liouville fractional derivative on the half line. They used the diagonaliza- tion process combined with the nonlinear alternative of Leray- Schauder type. In [6], by using Schauder’s fixed point theorem [15] combined with the diagonalization

2000Mathematics Subject Classification. 26A33, 26A42, 34A12.

Key words and phrases. Caputo fractional derivative; fractional integral; fixed point; bounded solutions; diagonalization process.

c2012 Universiteti i Prishtin¨es, Prishtin¨e, Kosov¨e.

Submitted Jun 15, 2011. Published December 13, 2011.

62

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process, the authors discussed the existence of bounded solutions of the following problem on unbounded domain

{ c

Dαy(t) =f(t, y(t)), t∈J := [0,),

y(0) =y0, y is bounded on J. (1.3) Let us mention that the diagonalization process method was widely used for integer order differential equations; see for instance [3, 4]. Notice that the right hand side in (1.1) depends on the fractional derivative. Hence our results extend and complement those with integer order derivative [3, 4] and those considered with a right hand side independent of the derivative [6].

2. Preliminaries

In this section, we introduce notations, definitions, and preliminary facts which are used throughout this paper. By C(J,R) we denote the Banach space of all continuous functions fromJ into Rwith the norm

∥y∥:= sup{|y(t)|:t∈J}.

Definition 2.1:([19, 23]). The fractional (arbitrary) order integral of the function h∈L1([a, b],R+) of orderα∈R+ is defined by

Iaαh(t) =

t a

(t−s)α1 Γ(α) h(s)ds,

where Γ is the gamma function. Whena= 0, we writeIαh(t) =h(t)∗φα(t),where φα(t) =tΓ(α)α−1 fort >0, andφα(t) = 0 fort≤0,and φα→δ(t) asα→0,where δ is the delta function.

Definition 2.2:([19, 23]). For a function h given on the interval [a, b], the αth Riemann-Liouville fractional-order derivative ofh, is defined by

(Dαa+h)(t) = 1 Γ(N−α)

(d dt

)Nt a

(t−s)Nα1h(s)ds.

HereN = [α] + 1 and [α] denotes the integer part ofα.

Definition 2.3:([18]). For a function h given on the interval [a, b], the Caputo fractional-order derivative ofh, is defined by

(cDa+α h)(t) = 1 Γ(N−α)

t a

(t−s)Nα1h(N)(s)ds.

Lemma 2.4:([27]) Letα >0,then the differential equation

cDαh(t) = 0 has solutions

h(t) =c0+c1t+c2t2+. . .+cN1tN1, ciR, i= 0,1,2, . . . , N1, N = [α] + 1.

Lemma 2.5:([27]) Letα >0,then

IαcDαh(t) =h(t) +c0+c1t+c2t2+. . .+cN1tN1 for someciR, i= 0,1,2, . . . , N1, N = [α] + 1.

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3. Existence of Solutions Letn∈N, and consider the space

C([0, n],˜ R) ={y∈C([0, n],R) such thatcDα1y∈C([0, n],R)}. On ˜C([0, n],R) we define the following norm

∥y∥n= max(∥y∥,∥cDα1y∥),

where∥y∥= sup0tn|y(t)|andcDα1y∥= sup0tn|cDα1y(t)|. Lemma 3.1: ( ˜C([0, n],R),∥.∥n) is a Banach space.

Proof. Let{yp}p=0 be a Cauchy sequence in the space ( ˜C([0, n],R),∥.∥n), then,

∀ϵ >0,∃N >0 such that |yp−ym|< ϵ f or any p, m > N.

Thus{yp(t)}p=0is a Cauchy sequence inR, then{yp(t)}p=0converges to somey(t) inRand we can verify easily thaty∈C([0, n],˜ R).

Moreover,{cDα1yp}p=0 converges uniformly to somez∈C([0, n],˜ R).

Next we need to prove thatz=cDα1y.

According to the uniform convergence of{cDα1yp(t)}p=0and the Dominated Con- vergence Theorem, we can arrive at

z(t) = lim

p+

cDα1yp(t) = lim

p+

1 Γ(2−α)

t 0

(t−s)1αyp(s)ds, so,

z(t) =cDα1y(t),

which completes the proof of Lemma 3.1.

First we address a boundary value problem on a bounded domain. Let n∈N, and consider the boundary value problem

cDαy(t) =f(t, y(t),cDα1y(t)), t∈Jn := [0, n], 1< α≤2, (3.1)

y(0) =y0, y(n) = 0. (3.2)

Leth:JnRbe continuous, and consider the linear fractional order differential equation

cDαy(t) =h(t), t∈Jn, 1< α≤2. (3.3) We shall refer to (3.3)-(3.2) as (LP). By a solution to (LP) we mean a function y∈C2(Jn,R) that satisfies equation (3.3) onJn and condition (3.2).

We need the following auxiliary result.

Lemma 3.2: The unique solution of the problem (LP) is given by y(t) =y0 t

Γ(α1)

n 0

(n−s)α2h(s)ds+ 1 Γ(α)

t 0

(t−s)α1h(s)ds. (3.4) Proof. Lety∈C(J˜ n,R) be a solution to (LP). Using Lemma 2, we have that

y(t) =Iαh(t)−c0−c1t=

t 0

(t−s)α1

Γ(α) h(s)ds−c0−c1t,

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for arbitrary constantsc0 andc1. By derivation we have y(t) =

t 0

(t−s)α2

Γ(α1) h(s)ds−c1. Applying the boundary condition (3.2), we find that

c0=−y0, c1=

n 0

(n−s)α2 Γ(α1) h(s)ds.

Our main result reads as follow.

Theorem 3.3: Assume that

(H) There exist nonnegative functionsa, b, c∈L1(Jn,R) such that

|f(t, u, v)| ≤a(t)|u|+b(t)|v|+c(t) for eacht∈Jn and allu, v∈R. Then BVP (3.1)-(3.2) has at least one solution onJn.

Proof. The proof will be given in two parts.

Part I: We begin by showing that (3.1)-(3.2) has a solution yn C(J˜ n,R).

Consider the operatorN : ˜C(Jn,R)−→C(J˜ n,R) defined by (N y)(t) = y0 t

Γ(α1)

n 0

(n−s)α2f(s, y(s),cDα1y(s))ds

+ 1

Γ(α)

t 0

(t−s)α1f(s, y(s),cDα1y(s))ds.

Thus

cDα1(N y)(t) = Γ(3t2−αα)n 0

(ns)α−2

Γ(α1) f(s, y(s),cDα1y(s))ds +∫t

0f(s, y(s),cDα1y(s))ds.

Using continuity off we can conclude thatN y(t) andcDα1N y(t) are continuous onJ.

We shall show thatNsatisfies the assumptions of Schauder’s fixed point theorem.

The proof will be given in several steps.

First, chooseRa number such that R >max

(|y0|Γ(α) + 2nα1c

Γ(α)2nα1c , (Γ(3−α)Γ(α−1) + 1)c

Γ(3−α)Γ(α−1)(Γ(3−α)Γ(α−1) + 1)c ) (3.5) wherec=∫n

0 c(s)ds, c=∫n

0[a(s) +b(s)]ds.

Set

C˜R={y∈C(J˜ n,R),∥y∥n ≤R}. It is clear that ˜CR is a closed, convex subset of ˜C(Jn,R).

Step 1: N( ˜CR)⊂C˜R.

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Lety∈C˜R,we show that N y∈C˜R. For eacht∈Jn, we have

|(N y)(t)|

≤ |y0|+ n Γ(α1)

n 0

(n−s)α2|f(s, y(s),cDα1y(s))|ds

+ 1

Γ(α)

n 0

(n−s)α1|f(s, y(s),cDα1y(s))|ds

≤ |y0|+ n Γ(α1)

n 0

(n−s)α2|f(s, y(s),cDα1y(s))|(1 + n−s n(α−1))ds

≤ |y0|+ n Γ(α1)

α α−1

n 0

(n−s)α2[a(s)|y(s)|+b(s)|cDα1y(s)|+c(s)]ds

≤ |y0|+ Γ(α)

n 0

(n−s)α2[∥y∥n(a(s) +b(s)) +c(s)]ds

≤ |y0|+nα1α

Γ(α) [Rc+c]≤R.

In other hand

|cDα1(N y)(t)| ≤ n2α Γ(3−α)

n 0

(n−s)α2

Γ(α1) |f(s, y(s),cDα1y(s))|ds +∫n

0 |f(s, y(s),cDα1y(s))|ds

(

1 + 1

Γ(3−α)Γ(α−1) )

[Rc+c]≤R.

Then

∥N y∥n ≤R.

Step 2: N is continuous.

Let{yq} be a sequence such thatyq→yin ˜C(Jn,R), Then for each t∈Jn

|(N yq)(t)(N y)(t)|

n

Γ(α1)

n 0

(n−s)α2|f(s, yq(s),cDα1yq(s))−f(s, y(s),cDα1y(s))|ds

+ 1

Γ(α)

t 0

(t−s)α1|f(s, yq(s),cDα1yq(s))−f(s, y(s),cDα1y(s))|ds, and

|cDα1(N yq)(t)cDα1(N y)(t)|

t2α Γ(3−α)

n 0

(n−s)α2

Γ(α1) |f(s, yq(s),cDα1yq(s))−f(s, y(s),cDα1y(s))|ds +

t 0

|f(s, yq(s),cDα1yq(s))−f(s, y(s),cDα1y(s))|ds.

Sincef is a continuous function, the right-hand side of the above inequalities tends to zero asqtends to . Then

∥N yq−N y∥n 0 as q→ ∞. Step 3: N mapsC˜R into a bounded set of C(J˜ n,R) SinceN( ˜CR)⊂C˜R, thenN( ˜CR) is bounded.

Step 4: N mapsC˜R into an equicontinuous set ofC(J˜ n,R).

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Letτ1, τ2∈Jn, τ1< τ2, andy∈C˜R. Then

|(N y)(τ2)(N y)(τ1)|

τ2−τ1 Γ(α1)

n 0

(n−s)α2|f(s, y(s),cDα1y(s))|ds

+ 1

Γ(α)

τ1

0

|1−s)α12−s)α1||f(s, y(s),cDα1y(s))|ds

+ 1

Γ(α)

τ2 τ1

2−s)α1|f(s, y(s),cDα1y(s))|ds,

τ2−τ1

Γ(α1)

n 0

(n−s)α2[a(s)|y(s)|+b(s)|cDα1y(s)|+c(s)]ds

+ 1

Γ(α)

τ1 0

|1−s)α12−s)α1[a(s)|y(s)|+b(s)|cDα1y(s)|+c(s)]ds

+ 1

Γ(α)

τ2

τ1

2−s)α1[a(s)|y(s)|+b(s)|cDα1y(s)|+c(s)]ds

τ2−τ1 Γ(α1)

n 0

(n−s)α2[(a(s) +b(s))∥y∥n+c(s)]ds

+ 1

Γ(α)

τ1 0

|1−s)α12−s)α1[(a(s) +b(s))∥y∥n+c(s)]ds

+ 1

Γ(α)

τ2 τ1

2−s)α1[(a(s) +b(s))∥y∥n+c(s)]ds

τ2−τ1

Γ(α1)

n 0

(n−s)α2[(a(s) +b(s))R+c(s)]ds

+ 1

Γ(α)

τ1 0

|1−s)α12−s)α1[(a(s) +b(s))R+c(s)]ds

+ 1

Γ(α)

τ2

τ1

2−s)α1[(a(s) +b(s))R+c(s)]ds and

|cDα1(N y)(τ2)cDα1(N y)(τ1)|

τ22α−τ12α Γ(3−α)

n 0

(n−s)α2

Γ(α1) |f(s, y(s),cDα1y(s))|ds +

τ2

τ1

|f(s, y(s),cDα1y(s))|ds

τ22α−τ12α Γ(3−α)

n 0

(n−s)α2

Γ(α1) [a(s)|y(s)|+b(s)|cDα1y(s)|+c(s)]ds +

τ2 τ1

[a(s)|y(s)|+b(s)|cDα1y(s)|+c(s)]ds

τ22α−τ12α Γ(3−α)

n 0

(n−s)α2

Γ(α1) [(a(s) +b(s))R+c(s)]ds +

τ2

τ1

[(a(s) +b(s))R+c(s)]ds.

As τ1 τ2, the right-hand side of the above inequalities tends to zero. As a consequence of Steps 2 to 4 together with the Arzel`a-Ascoli theorem, we conclude thatN is completely continuous.

Therefore, we deduce from Schauder’s fixed point theorem that N has a fixed pointyn in ˜C(Jn,R) which is a solution of BVP (3.1)–(3.2) with

|yn(t)| ≤Rfor eacht∈Jn.

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Part II: The diagonalization process

We now use the following diagonalization process. Fork∈N,let uk(t) =

{ ynk(t), t∈[0, nk],

ynk(nk) t∈[nk,∞). (3.6) Here{nk}kN is a sequence of numbers satisfying

0< n1< n2< . . . < nk< . . .↑ ∞. LetS={uk}k=1.Notice that

|unk(t)| ≤Rfor t∈[0, n1], kN. Also fork∈Nandt∈[0, n1] we have

unk(t) = y0 t Γ(α1)

n1 0

(n1−s)α2f(s, unk(s),cDα1unk(s))ds

+ 1

Γ(α)

t 0

(t−s)α1f(s, unk(s),cDα1unk(s))ds.

fork∈Nandt, x∈[0, n1] we have

|unk(t)−unk(x)| ≤ |x−t| Γ(α1)

n1 0

(n1−s)α2|f(s, unk(s),cDα1unk(s))|ds

+ 1

Γ(α)

t 0

|(t−s)α1(x−s)α1||f(s, unk(s),cDα1unk(s))|ds

+ 1

Γ(α)

t x

(x−s)α1|f(s, unk(s),cDα1unk(s))|ds.

In other hand

|cDα1unk(t)cDα1unk(x)|

|t2α−x2α| Γ(3−α)

n 0

(n1−s)α2

Γ(α1) |f(s, unk(s),cDα1unk(s))|ds +

t x

|f(s, unk(s),cDα1unk(s))|ds.

The Arzel`a-Ascoli Theorem guarantees that there is a subsequenceN1of Nand a functionz1 ∈C([0, n˜ 1],R) with unk →z1 in ˜C([0, n1],R) ask→ ∞ throughN1. LetN1=N1\{1}.Notice that

|unk(t)| ≤R fort∈[0, n2], kN. Also fork∈Nandt, x∈[0, n2] we have

|unk(t)−unk(x)| ≤ |x−t| Γ(α1)

n2

0

(n2−s)α2|f(s, unk(s),cDα1unk(s))|ds

+ 1

Γ(α)

t 0

|(t−s)α1(x−s)α1||f(s, unk(s),cDα1unk(s))|ds

+ 1

Γ(α)

t x

(x−s)α1|f(s, unk(s),cDα1unk(s))|ds.

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In other hand

|cDα1unk(t)cDα1unk(x)|

|t2α−x2α| Γ(3−α)

n 0

(n2−s)α2

Γ(α1) |f(s, unk(s),cDα1unk(s))|ds +

t x

|f(s, unk(s),cDα1unk(s))|ds.

The Arzel`a-Ascoli Theorem guarantees that there is a subsequenceN2 of N1 and a function z2 C([0, n˜ 2],R) with unk z2 in ˜C([0, n2],R) as k → ∞ through N2. Note that z1 = z2 on [0, n1] since N2 N1. Let N2 = N2\{2}. Proceed inductively to obtain form∈ {3,4, . . .}a subsequenceNm ofNm1 and a function zm C([0, n˜ m],R) with unk zm in ˜C([0, nm],R) as k → ∞ through Nm. Let Nm=Nm\{m}.Define a function y as follows. Fixt∈(0,) and let m∈Nwith s≤nm. Definey(t) = zm(t), theny ∈C([0,∞),R), y(0) =y0 and|y(t)| ≤R for t∈[0,).

Again fixt∈[0,) and letm∈Nwiths≤nm.Then forn∈Nmwe have unk(t) = y0 t

Γ(α1)

nm

0

(nm−s)α2f(s, unk(s),cDα1unk(s))ds

+ 1

Γ(α)

t 0

(t−s)α1f(s, unk(s),cDα1unk(s))ds.

We can use this method for eachx∈[0, nm],and for eachm∈N. Thus

cDαy(t) =f(t, y(t),cDα1y(t)), fort∈[0, nm]

for each m N and α (1,2] and the constructed function y is a solution of (1.1)-(1.2). This completes the proof of the theorem.

4. An Example

In this section, we give an example to illustrate the usefulness of our main results.

Let us consider the following fractional boundary value problem,

cDαy(t) = (et+1)

(2 +|y(t)|+|cDα1y(t)| 1 +|y(t)|+|cDα1y(t)|

)

, t∈J := [0,), 1< α≤2, (4.1)

y(0) = 1, (4.2)

where

f(t, u, v) =(

et+ 1) (2 +|u|+|v| 1 +|u|+|v|

) . It is clear that condition (H) is satisfied with

a(t) =b(t) =et+ 1, c(t) = 2(et+ 1).

It follows from Theorem 3 that the problem (4.1)–(4.2) has a bounded solution on [0,) for each value ofα∈(1,2].

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5. Conclusion

Using Schauder’s fixed point theorem combined with the diagonalization pro- cess, we have considered the existence of bounded solutions for a class of initial value problem on the half-line for fractional differential equations involving Caputo fractional derivative with a nonlinear term depending on the derivative. Many prop- erties of solutions for differential equations, such as stability or oscillation, require global properties of solutions. This is the main motivation to look for sufficient conditions that ensure global existence of solutions for IVP (1.1)-(1.2)

Acknowledgement. The authors are grateful to the referees for their remarks.

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Mouffak Benchohra

Laboratoire de Math´ematiques, Universit´e de Sidi Bel-Abb`es,, B.P. 89, 22000, Sidi Bel- Abb`es, Alg´erie

E-mail address:[email protected]

Farida Berhoun

Laboratoire de Math´ematiques, Universit´e de Sidi Bel-Abb`es,, B.P. 89, 22000, Sidi Bel- Abb`es, Alg´erie

E-mail address:berhoun22@yahoo

Gaston N’Gu´er´ekata

Department of Mathematics, Morgan State University, 1700 E. Cold Spring Lane, Bal- timore M.D. 21252, USA

E-mail address:Gaston.N’[email protected]

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