• 検索結果がありません。

Later, the problems with non- local integral conditions for parabolic equations were investigated by Kamynin [10], Ionkin [9], Yurchuk [18], Bouziani [2]

N/A
N/A
Protected

Academic year: 2022

シェア "Later, the problems with non- local integral conditions for parabolic equations were investigated by Kamynin [10], Ionkin [9], Yurchuk [18], Bouziani [2]"

Copied!
8
0
0

読み込み中.... (全文を見る)

全文

(1)

ISSN: 1072-6691. URL: http://ejde.math.swt.edu or http://ejde.math.unt.edu ftp ejde.math.swt.edu (login: ftp)

EXISTENCE OF SOLUTIONS FOR ONE-DIMENSIONAL WAVE EQUATIONS WITH NONLOCAL CONDITIONS

SERGEI A. BEILIN

Abstract. In this article we study an initial and boundary-value problem with a nonlocal integral condition for a one-dimensional wave equation. We prove existence and uniqueness of classical solution and find its Fourier repre- sentation. The basis used consists of a system of eigenfunctions and adjoint functions.

1. Introduction

Certain problems of modern physics and technology can be effectively described in terms of nonlocal problems for partial differential equations. These nonlocal conditions arise mainly when the data on the boundary cannot be measured directly.

The first paper, devoted to second-order partial differential equations with non- local integral conditions goes back to Cannon [4]. Later, the problems with non- local integral conditions for parabolic equations were investigated by Kamynin [10], Ionkin [9], Yurchuk [18], Bouziani [2]; problems for elliptic equations with operator nonlocal conditions were considered by Mikhailov and Guschin [7], Scubachevski [17], Paneiah [13].

Then, Gordeziani and Avalishvili [5], Bouziani [3] devoted a few papers to non- local problems for hyperbolic equations. Pulkina [14, 15] studied the nonlocal analogue to classical Goursat problem.

In this paper we investigate the nonlocal analogue to classical mixed problem, which involves initial, boundary and nonlocal integral conditions. In the rectangular domainD={(x, t) : 0< x < l, 0< t < T}, we consider the equation

LU ≡Utt−Uxx=F(x, t) (1.1)

with initial data

U(x,0) = Φ(x), Ut(x,0) = Ψ(x), (1.2) Dirichlet boundary condition

U(0, t) = 0 (1.3)

and the nonlocal condition

Z l

0

U(x, t)dx= 0, (1.4)

2000Mathematics Subject Classification. 35L99, 35L05, 35L20.

Key words and phrases. Mixed problem, non-local conditions, wave equation.

2001 Southwest Texas State University.c

Submitted August 21, 2001. Published December 10, 2001.

1

(2)

where Φ(x), Ψ(x) are given, Φ(x)∈C[0, l]∩C2(0, l), Ψ(x)∈C[0, l]∩C1(0, l) and satisfy the compatibility conditions

Φ(0) = 0, Ψ(0) = 0, Z l

0

Φ(x)dx= Z l

0

Ψ(x)dx= 0.

Note that we do not lose generality by assuming that (1.3) and (1.4) are homo- geneous. Indeed, if U(0, t) = m(t) and Rl

0U(x, t)dx = n(t), we introduce a new unknown functionv(x, t) =U(x, t)−W(x, t), where

W(x, t) = (1−2x

l )m(t) +2x l2n(t).

Then (1.1) is converted into the similar equation

vtt−vxx=g(x, t), g(x, t) =F(x, t)− LW, while the Dirichlet and integral conditions are now homogeneous.

The presence of integral conditions complicates the application of standard tech- niques. Therefore, we first reduce (1.1)-(1.4) to an equivalent problem.

Lemma 1.1. Problem (1.1)-(1.4) is equivalent to (1.1)-(1.3) and

Ux(0, t)−Ux(l, t) = Z l

0

F(x, t)dx. (1.5)

Proof. LetU(x, t) is a solution of (1.1)-(1.4). Integrating (1.1) with respect tox over (0, l), and taking in account (1.4), we obtain

Ux(0, t)−Ux(l, t) = Z l

0

F(x, t)dx.

Let now U(x, t) be a solution of (1.1)-(1.3), (1.5). We need only to show that Rl

0U(x, t)dx= 0. For this end we integrate again (1.1) and obtain d2

dt2 Z l

0

U(x, t)dx= 0.

By virtue of the compatibility conditions, Z l

0

U(x,0)dx= 0, Z l

0

Ut(x,0)dx= 0. ThenRl

0U(x, t)dx= 0 is a unique solution to homogeneous Cauchy problem.

Introduce a new unknown function u(x, t) =U(x, t)−w(x, t), where w(x, t) =

x2l2Rl

0F(x, t)dx.Then (1.1)-(1.3), (1.5) is transformed now into

utt−uxx=g(x, t), (1.6)

u(x,0) =ϕ(x), ut(x,0) =ψ(x), (1.7)

u(0, t) = 0, (1.8)

ux(0, t) =ux(l, t), (1.9)

(3)

where

g(x, t) =F(x, t) +x2 2l

Z l

0

Ftt(x, t)dx−1 l

Z l

0

F(x, t)dx, ϕ(x) = Φ(x) +x2

2l Z l

0

F(x,0)dx, ψ(x) = Ψ(x) +x2

2l Z l

0

Ft(x,0)dx.

2. Uniqueness

Theorem 2.1. There exists at most one solution to (1.6)-(1.9).

Proof. Letu1(x, t),u2(x, t) be two different solutions of (1.6)-(1.9). Thenu(x, t) = u1(x, t)−u2(x, t) is a nontrivial solution to the homogeneous problem

utt−uxx= 0, u(x,0) = 0, ut(x,0) = 0, u(0, t) = 0, ux(0, t) =ux(l, t).

Asu∈C1( ¯D)∩C2(D), then u(x, t) takes on certain value forx=l. Letu(l, t) = µ(t). Consider mixed problem for the equation utt−uxx = 0 with homogeneous initial data and the boundary conditions

u(0, t) = 0, u(l, t) =µ(t).

Note, that µ(t) is required to satisfy the compatibility conditions µ(0) = 0 and µ0(0) = 0.

For all conditions to be homogeneous, we let ˜u =u−xlµ(t). Then, taking in account the compatibility conditions forµ(t), we obtain

˜

utt−u˜xx= x lµ00(t),

˜

u(x,0) = 0, u˜t(x,0) = 0,

˜

u(0, t) = 0, u(l, t) = 0.˜

It is well known that there exists unique solution ˜u(x, t) to this problem [1], hence u(x, t) assumes the form

u(x, t) = 2l π2

X

k=1

(−1)k k2

Z t

0

µ00(τ) sinkπ(t−τ)

l dτ

sinkπx l +x

lµ(t).

Now we find that ux(0, t) = 2

π

X

k=1

(−1)k k

Z t

0

µ00(τ) sinkπ(t−τ) l dτ +1

lµ(t),

ux(l, t) = 2 π

X

k=1

1 k

Z t

0

µ00(τ) sinkπ(t−τ) l dτ+1

lµ(t)

and consider

ux(l, t)−ux(0, t) = 4 π

Z t

0

µ00(τ)

X

m=1

1

2m−1sin(2m−1)π(t−τ)

l dτ.

(4)

As in [6]

X

m=1

sin (2m−1)x 2m−1 =

π/4, if 0< x < π

−π/4, ifπ < x <2π . Then by (1.9) we can write

0 =|ux(l, t)−ux(0, t)|= Z t

0

µ00(τ)dτ.

Taking into account the compatibility conditionsµ(0) =µ0(0) = 0, we easily obtain µ(t)≡0. Now from the uniqueness theorem [1], we obtainu(x, t)≡0.

3. Existence

Obviously, the solution to the problem (1.6)-(1.9), if it exists, is a sum of solutions to the following two problems:

Problem H

utt−uxx= 0,

u(x,0) =ϕ(x), ut(x,0) =ψ(x), u(0, t) = 0, ux(0, t) =ux(l, t) Problem N H

utt−uxx=g(x, t),

u(x,0) =ut(x,0) = 0, u(0, t) = 0, ux(0, t) =ux(l, t).

First consider problemHand use separation of variables. Letu(x, t) =X(x)T(t).

Substituting in the equationutt−uxx= 0 and taking into account (1.8), (1.9), we obtain

X00(x) +λX(x) = 0, X(0) = 0, X0(0) =X0(l). (3.1) Note that problem (3.1) is not self-adjoint: The adjoint problem is

Y00(x) + ¯λY(x) = 0, Y0(l) = 0, Y(l) =Y(0). (3.2) The eigenvalues and eigenfunctions of problem (3.1) are

λk= (2πk

l )2, k= 1,2, . . . (3.3)

X0=x, Xk = sin2πkx

l (3.4)

respectively. Note, that fork >0 the functions (3.4) are not orthonormal withX0. To construct a basis inL2, we complete (3.4) by using adjoint functions.

Following M. Keldysh [11], we define an adjoint function ˜Xk, corresponding eigenvalueλk from (3.3), as a solution to the boundary-valued problem

k00(x) +λkk(x) =−2p

λkXk(x), X˜k(0) = 0, X˜k0(0) = ˜Xk0(l). (3.5) We obtain

k(x) =xcos2πkx

l , k= 1,2, . . .

Rewrite now a system of eigenvalue and adjoint functions of (3.1) as X0=x, X2k1(x) =xcos2πkx

l , X2k(x) = sin2πkx

l . (3.6)

(5)

In a similar way we find the system of eigenvalue and adjoint functions (3.2):

Y0(x) = 2

l2, Y2k1(x) = 4

l2cos2πkx

l , Y2k(x) = 4(l−x)

l2 sin2πkx

l , (3.7) where for everyλk withk >0,X2k(x),Y2k(x) are eigenvalue functions,X2k1(x), Y2k1(x) are adjoint functions of the problems (3.1) and (3.2) respectively. Direct calculations show that (3.6) and (3.7) form a biorthogonal system forx∈(0, l):

(Xi, Yj) = Z l

0

Xi(x)Yj(x)dx=δij.

As it was shown in [8] the system (3.6) is complete and forms a basis inL2(0, l).

Hence, an arbitrary functionf(x)∈L2(0, l) may be expanded as f(x) =A0X0(x) +

X

k=1

(A2kX2k(x) +A2k1X2k1(x)), where

Ai= Z l

0

f(x)Yi(x)dx. (3.8)

Returning to the separation variables technique, forT(t) we obtain Tk(t) =aksin2πkt

l +bkcos2πkt l . We assume now that a solution toHis of the form

u(x, t) =A0X0+

X

k=1

(A2kX2k+A2k1X2k1)Tk− lt

2πkA2k1X2kTk0

. (3.9) SubstituteTk(t) and rewrite the coefficients. Then

u(x, t) =C0X0+

X

k=1

(X2k(C2ksin2πkt

l +D2kcos2πkt l ) +X2k1(C2k1sin2πkt

l +D2k1cos2πkt l )

−tX2k(C2k1cos2πkt

l −D2k1sin2πkt l )).

(3.10)

The initial data (1.7) give us the following two equalities ϕ(x) =C0X0+

X

k=1

(D2kX2k+D2k1X2k1),

ψ(x) =

X

k=1

(2πk

l C2k−C2k1)X2k+2πk

l C2k1X2k1

,

and the coefficients can be found via formula (3.8).

Assume a solution to the problemN H is of the form u(x, t) =V0(t)X0(x) +

X

k=1

(V2k(t)X2k(x) +V2k1(t)X2k1(x)), (3.11)

(6)

whereVi(t) are unknown coefficients satisfying the initial conditionsVi(0) =Vi0(0) = 0. Substitute (3.11) into the equationutt−uxx= g(x, t), where g(x, t) has been expanded as a biorthogonal series:

g(x, t) =g0(t)X0(x) + X k=1

(g2k(t)X2k(x) +g2k1(t)X2k1(x)), with coefficients

gi(t) = Z l

0

g(x, t)Yi(x)dx, i= 0,1, . . . We obtain

V000(t)x+

X

k=1

V2k00(t) +4π2k2 l2 V2k(t)

sin2πkx l

+

X

k=1

V2k001(t) +4π2k2

l2 V2k1(t)

xcos2πkx l

+

X

k=1

V2k1(t)4πk

l sin2πkx l

= g0(t)X0(x) +

X

k=1

(g2k(t)X2k(x) +g2k1(t)X2k1(x)).

Thus we have a Cauchy problem for the system of ordinary differential equations V000(t) =g0(t)

V2k00 +4πk l (πk

l V2k(t) +V2k1(t)) =g2k(t) V2k001(t) +4π2k2

l2 V2k1(t) =g2k1(t) with initial data

V0(0) =V00(0) = 0, V2k(0) =V2k0 (0) = 0, V2k1(0) =V2k0 1(0) = 0, which has a unique solution

V0(t) = Z t

0

(t−τ)g0(τ)dτ, V2k1(t) = 1

kπ Z t

0

g2k1(τ) sinkπ(t−τ)

l dτ,

V2k(t) = 1 kπ

Z t

0

(g2k(τ)−4πkV2k1(τ)) sinkπ(t−τ)

l dτ.

Theorem 3.1. Let:

(1) g(x, t)∈C2(D),gx(x, t)∈C[0, l]for all t∈(0, T),|g(x, t)| ≤P,(x, t)∈D (2) ϕ∈C[0, l]∩C2(0, l),ψ∈C[0, l],ϕ(0) = 0,ϕ0(0) =ϕ0(l),ψ(0) = 0.

Then there exists the solution to (1.6)–(1.9),

u(x, t)∈C( ¯D)∩C1( ¯D\ {t=T})∩C2(D) which has the form of a sum of (3.9) and (3.11).

(7)

Series Proof. It is sufficient to prove uniform convergence of the series (3.9) and (3.11) and the series, obtained with formal differentiation. Let |ϕ0(x)| ≤M1,

00(x)| ≤M2,|ψ(x)| ≤N, |ψ0(x)| ≤N1,|gx| ≤P1, |gxx| ≤P2.

Integrating Ci, Di, Vi by parts and taking in account the abovementioned as- sumptions, we obtain:

|D2k| ≤ 1 k2

l(lM2+ 2M1)

π2 , |D2k1| ≤ 1 k2

M2l π2 ,

|C2k| ≤ 1 k2

l(N1+ 2N)

2 , |C2k1| ≤ 1 k2

N1l π2 ,

|V2k| ≤ 1 k2

4T2(2p1+P2l)

π2 , |V2k1| ≤ 1 k2

2T P1 π2 ,

and hence the series (3.9) and (3.11) and the series, obtained with formal differen-

tiation, converge uniformly.

References

[1] A. V. Bitzadze,Urawnenija matematicheskoj fiziki,M.,“Nauka”, 1976.

[2] A. Bouziani,On a class of parabolic equations with nonlocal boundary conditions,Bulletin de la Classe des Sciences, Acad´emie Royale de Belgique, T.X, 1999, p. 61-77.

[3] A. Bouziani,Solution forte d’un probl`eme mixte avec conditions non locales pour une classe d’´equations hyperboliques,Bulletin de la Classe des Sciences, Acad´emie Royale de Belgique, T. VIII, 1997, p. 53-70.

[4] J. R. Cannon, The solution of the heat equation subject to specification of energy.Quart.

Appl. Math., 21, n2, 155-160, 1963.

[5] D. G. Gordeziani, G. A. Avalishvili,On the constructing of solutions of the nonlocal initial boundary problems for one-dimentional medium oscillation equations,Matem. Modelirovanie, 12, N. 1, 2000, 94-103.

[6] I. S. Gradshtein, I. M. Ryzhik,Tables of integrals, sums, series and products,M., 1963.

[7] A. K. Gushin, V. P. Mikhailov,On solvability of nonlocal problems for second-odered elliptic equation,Matem. Sbornik, V. 185, 1994, p. 121-160.

[8] V. A. Ilyin,Necessary and sufficient properties of being a basis of a subsystem of eigenfunc- tions and adjoint functions for Keldysh bundle for odrinary differential operators,Doklady Acad. Nauk SSSR, 227, N. 4, 1976, p. 796-799.

[9] N. I. Ionkin,Solutions of boundary value problem in heat conductions theory with nonlocal boundary conditions,Differents. Uravn., Vol. 13, N2, 1977, p. 294-304.

[10] L. I. Kamynin,A boundary value problem in the theory of the heat conduction with nonclas- sical boundary condition,Z. Vychisl. Mat. Fiz., 4, N6, 1964, p. 1006-1024.

[11] M. V. Keldysh,On eigenvalues and eigenfunctions of certain classes of not self-adjoint equa- tions,Doklady Acad. Nauk SSSR, 87, 1951, p. 11-14.

[12] S. Mesloub, A. Bouziani,On a class of singular hyperbolic equation with a weighted integral condition,Internat. J. Math. & Math. Sci., Vol. 22, No. 3, 1999, pp. 511-519.

[13] B. P. Paneiah,On certain nonlocal boundary problemsfor linear differential operators,Matem.

zametki., 1984, v. 35, N.3, p. 425-434.

[14] L. S. Pulkina,A nonlocal problem with integral conditions for hyperbolic equations,Electron.

J. Ddiff. Eqns., Vol. 1999(1999), No. 45, 1-6.

[15] L. S. Pulkina,On solvability inL2 of nonlocal problem with integral conditions for a hyper- bolic equation,Differents. Uravn., V. N. 2, 2000.

[16] A. A. Samarskii,Some problems in differential equations theory,Differents. Uravn., Vol. 16, n11, 1980, p. 1221-1228.

[17] A. L. Skubachevski, G. M. Steblov,On spectrum of differential operators with domain non- dense inL2,Dokladi AN USSR, 1991. v. 321, N.6, p. 1158-1163.

[18] N. I. Yurchuk, Mixed problem with an integral condition for certain parabolic equations, Differents. Uravn., Vol. 22, N. 12, 1986, p. 2117-2126.

(8)

Sergei A. Beilin

Department of Mathematics, Samara State University, 1, Ac.Pavlov st., 443011 Samara Russia

E-mail address:[email protected], [email protected]

参照

関連したドキュメント