• 検索結果がありません。

A note on lattice renormings

N/A
N/A
Protected

Academic year: 2022

シェア "A note on lattice renormings"

Copied!
10
0
0

読み込み中.... (全文を見る)

全文

(1)

A note on lattice renormings

Mari´an Fabian, Petr H´ajek, V´aclav Zizler

Abstract. It is shown that every strongly lattice norm onc0(Γ) can be approximated by C smooth norms. We also show that there is no lattice and Gˆateaux differentiable norm onC0[0, ω1].

Keywords: smooth norms, approximation, lattice norms,c0(Γ),C0[0, ω1] Classification: 46B03, 46B20

It has been recently shown in [1] and [2] that every equivalent norm on the classical separable Banach spaces c0 or ℓp, p even, (as well as on many other spaces) can be uniformly approximated on bounded sets by a sequence of C- Fr´echet smooth norms.

Although the method of construction requires some technical conditions on the space to be satisfied (in particular the existence of a Schauder basis), it seems to suggest that perhaps the following statement should be valid:

SupposeX is a separable Banach space that admits an equivalentCk-Fr´echet smooth norm. Then every equivalent norm onX can be approximated uniformly on bounded sets by a sequence ofCk-Fr´echet smooth norms.

On the other hand, we do not know of any example of a nonseparable Banach space where a similar statement would be valid fork≥2.

In the present note we give a partial solution to this problem for the spacec0(Γ) andk=∞. More precisely we show that onc0(Γ), Γ uncountable, every equiv- alent strongly lattice norm can be approximated by a sequence of C-Fr´echet smooth norms.

In the second part of our paper, we show that there exists no lattice Gˆateaux differentiable norm onC0([0, ω1]), the space of continuous functions on the ordi- nal segment [0, ω1] that vanish atω1 (where ω1 is the first uncountable ordinal and [0, ω1] is in its normal topology as in [4]). More information on the space C0([0, ω1]) can be found e.g. [3, p. 259]. Proposition 2 of this paper is of interest when compared with some results of Haydon [5]–[6]. In [5], a lattice norm on C0[0, ω1]⊕c0[0, ω1] is constructed, which isC-Fr´echet differentiable and locally dependent on finitely many coordinates when restricted to a rather large open

In part supported by NSERC (Canada).

Supported by Grants AV 101–95–02 and GA ˇCR 201–94–0069

(2)

subset of C0[0, ω1]⊕c0[0, ω1]. This norm is then used to obtain C-Fr´echet smooth (necessarily non-lattice) renormings ofC0[0, ω1].

The notation and terminology we use are mostly standard, as in [3].

By a strongly lattice norm onc0(Γ) we mean an equivalent normk · ksuch that k P

γ∈Γ

yγeγk ≥ k P

γ∈Γ

xγeγkwhenever P

γ∈Γ

yγeγ, P

γ∈Γ

xγeγ∈c0(Γ) are such that for everyγ∈Γ|yγ| ≥ |xγ|is satisfied.

Theorem 1. Every equivalent strongly lattice norm on c0(Γ) can be approxi- mated(uniformly on bounded sets)byC-Fr´echet smooth norms.

Proof: Denote the given strongly lattice norm byk · k. We first introduce an auxiliary functionf. For arbitrary 1>∆>0 and P

γ∈Γ

xγeγ ∈c0(Γ) denote by

f X

γ∈Γ

xγeγ

= sup

kX

γ∈Γ

yγeγk,

where yγ=xγ if |xγ|>∆ and |yγ| ≤∆ if |xγ| ≤∆

. Clearly,f(·)≥ k · k onc0(Γ).

In fact,f(·) is a Lipschitz function on (c0(Γ),k · k) with the Lipschitz con- stant less than or equal to the Lipschitz constant ofk · k(on (c0(Γ),k · k)).

It is standard to check the following elementary properties off(·):

(i) f(P

γ∈Γ

xγeγ) = f( P

γ∈{α∈Γ,|xα|>∆}

xγeγ). In other words, the value of f(x) depends only on those coordinates ofxthat are in absolute value larger than ∆.

(ii) f(P

γ∈Γ

xγeγ)≤f(P

γ∈Γ

yγeγ)

whenever we havekyγk ≥ kxγkfor everyγ∈Γ.

The property (ii) is a “strongly lattice” property off(·) and follows directly from the strongly lattice property ofk · k.

We now proceed with our construction of approximatingC-norm.

Givenε >0, from the equivalence ofk · kandk · kit follows that there exists 1>∆>0 such that

k · k ≤f(·)≤ k · k+ε for everyx∈c0(Γ).

PutF(x) =f2(x).

ThenF(·) shares properties (i), (ii) and satisfies:

k · k2≤F(·)≤(k · k+ε)2=k · k2+ 2εk · k+ε2.

(3)

Thus the convex functionC(·) defined by:

C(x) = inf n

X

i=1

λiF(xi), x=

n

X

i=1

λixi,

n

X

i=1

λi= 1, λi>0

also satisfiesk·k2≤C(·)≤(k·k+ε)2, becausek·k2is convex andC(·)≤F9(·).

It is straightforward to show that also the strongly lattice property for C(·) is preserved, i.e. C(x)≥C(y) forx, y ∈c0(Γ), such that for everyγ∈Γ either kyγk ≥ kxγk. We will now show that for 1> ε >0 we have

C(x) = inf n

X

i=1

λiF(xi), x=

n

X

i=1

λixi,

n

X

i=1

λi= 1, λi>0 andkxik ≤100

for everyx∈c0(Γ) withkxk ≤2.

To this end, it is enough to find for every {xi}ni=1, λi > 0, Pn

i=1

λi = 1, x = Pn

i=1

λixi another system{yi}mi=1, λi >0, Pm

i=1

λi = 1,x= Pm

i=1

λiyi, where kyik ≤ 100 and such that

m

X

i=1

λiF(yi)≤

n

X

i=1

λiF(xi).

Suppose without loss of generality thatkxik ≤100 for 1≤i≤jandkxik>100 for j < i ≤n. We may assume that j ≥1, since otherwise F(xi)≥ 1002 for every 1≤i≤n, and thenF(x)≤32<1002 would give us a better estimate.

Put

v1=

j

P

i=1

λixi

j

P

i=1

λi

, v2 = Pn i=j+1

λixi Pn i=j+1

λi ,

ξ1=

j

X

i=1

λi, ξ2= 1−ξ1. Clearly,x=ξ1v12v2.

We may assume thatF(v1)≥ ξ11

j

P

i=1

λiF(xi) and F(v2)≥ξ12 Pn

i=j+1

λiF(xi).

(4)

Indeed, if for example F(v1)< ξ1

1

j

P

i=1

λiF(xi), we obtain that x=ξ1v1+ Pn

i=j+1

λixi1+ Pn

i=j+1

λi = 1,ξ1≥0,λi≥0 and

ξ1F(v1) +

n

X

i=j+1

F(xi)<

n

X

i=1

λiF(xi) gives us even a better estimate ofC(x).

By assumption, F(xi)≥1002 forj+ 1≤i≤n. Thus ξ1

2

n

P

i=j+1

λiF(xi)≥ 1002. The trivial estimate forC(x) isF(x)≤32= 9. Thus ξ1

1

j

P

i=1

λiF(xi)≤ 9 (otherwise the trivial estimate would give us a smaller value than Pn

i=1

λiF(xi) = ξ1 ξ1

1

j

P

i=1

λiF(xi) +ξ2 ξ1

2

Pn i=j+1

λiF(xi) .

Consequently,kv1k2 ≤C(v1)≤9 and we havekv1k ≤3. Similarly, kv2k+ ε2

≥F(v2)≥1002 and we havekv2k ≥99.

Thus there existsv3∈c0(Γ),kv3k= 50,v31v12v2 whereα12= 1, αi ≥0. Since v3−α1v12v2, we have 47≤α2kv2k. Thus

α1 1 ξ1

j

X

i=1

λiF(xi) +α2 1 ξ2

n

X

i=j+1

λiF(xi)≥α2kv2k2 ≥47kv2k ≥47·99.

Moreover the trivial estimate gives us

F(v3)≤ kv3k+ε2≤512<47·99.

Therefore

F(v3)≤α1 1 ξ1

j

X

i=1

λiF(xi) +α2 1 ξ2

n

X

i=j+1

λiF(xi), ξ2

α2F(v3)≤ ξ2 α2

α1 ξ1

j

X

i=1

λiF(xi) +

n

X

i=j+1

λiF(xi),

j

X

i=1

λiF(xi)− ξ2 α2

α1 ξ1

j

X

i=1

λiF(xi) + ξ2

α2F(v3)≤

n

X

i=1

λiF(xi),

j

X

i=1

1− ξ2 α2

α1 ξ1

λiF(xi) + ξ2

α2F(v3)≤

n

X

i=1

λiF(xi).

(5)

However, 1− ξ2

α2 α1

ξ1

j

X

i=1

λixi+ ξ2

α2v31v12 v3 α2 −α1

α2v1

1v12v2=x.

It is easy to verify that

j

P

i=1

1−αξ22αξ1

1

λi+αξ22 = 1. It follows thatα2> ξ2, since kv3k= 50 whilekxk ≤2. Therefore (1−αξ22αξ11i ≥0 for every 1≤i≤j.

Thus the system{xi}ji=1∪ {v3},{ 1−αξ22αξ1

1

λi}ji=1∪ {αξ22}gives us a smaller estimate ofC(x) than the original one {xi}ni=1, {λi}. Clearly, all kxik ≤ 100, 1≤i≤j,kv3k ≤100.

Sincek ·kandk ·kare equivalent norms onc0(Γ), it follows from our previous considerations that there exists a constantksuch that

C(x) = inf j

X

i=1

λiF(xi), x=

j

X

i=1

λixi,

j

X

i=1

λi= 1, λi>0 andkxik≤k

for everykxk ≤2.

We proceed by proving that there existsδ >0 such that

C X

γ∈Γ

xγeγ

=C X

γ∈{α,|xα|>δ}

xγeγ

for everyx= P

γ∈Γ

xγeγ∈c0 such thatkxk ≤2.

In fact, we will show that choosingδ < 2k+2+∆2 is sufficient.

SinceC is upper semi-continuous (as the infimum of a family of continuous functions - F is continuous as the square of a Lipschitz function f), and, moreover, from the strongly lattice property ofCit is enough to prove that

C(X

γ∈Γ

xγeγ) =C(X

γ∈Γ γ6=γ0

xγeγ),

whenever|xγ0| ≤δ.

We will proceed as follows. Givenx= P

γ∈Γ

xγeγ, for arbitrary{yi}ni=1⊂c0(Γ), {λi}ni=1, λi > 0, Pn

i=1

λi = 1, kyik ≤ k such that Pn

i=1

λiyi = P

γ∈Γ γ6=γ0

xγeγ, we will construct {xi}ni=1 ⊂c0(Γ) such that (xi)γ = (yi)γ for 1 ≤ i ≤ n, γ 6= γ0,

Pn i=1

λixi =xand in addition

n

X

i=1

λiF(xi)≤

n

X

i=1

λiF(yi).

(6)

Consequently,

C(X

γ∈Γ

xγeγ)≤C(X

γ∈Γ γ6=γ0

xγeγ).

This implies our claim, since C(·) shares the strongly lattice property, so the opposite inequality is satisfied.

Without loss of generality assume that,δ≥xγ0 >0 and k≥(yi)γ0 >∆ for 1≤i≤j1,

∆≥(yi)γ0 ≥0 for j1 < i≤j2, 0>(yi)γ0 ≥ −∆ for j2 < i≤j3,

−∆>(yi)γ0 ≥ −k for j3 < i≤n.

Puts1=

j1

P

i=1

λi,s2=

j2

P

i=j1+1

λi,s3 =

j3

P

i=j2+1

λi, s4= Pn

i=j3+1

λi. If (s3+s4)∆≥δ, then

j2

X

i=1

λi(yi)γ0+

n

X

i=j2+1

λi∆≥

n

X

i=j2+1

λi∆≥(s3+s4)∆≥δ.

Therefore for everyj2< i≤nwe can find numbers ˜yi, such that ∆≥y˜i≥(yi)γ0

and j2

X

i=1

λi(yi)γ0+

n

X

i=j2+1

λii=xγ0. We definexi =yi for 1≤i≤j2, andxi= P

γ∈Γ γ6=γ0

(yi)γeγ+ ˜yieγ0 forj2< i≤n. It follows that

F(xi) =F X

γ∈Γ γ6=γ0

(yi)γeγ

≤F(yi).

Thus Pn

i=1

λiF(xi)≤ Pn

i=1

λiF(yi) and the claim is established.

If (s3+s4)∆< δ, we obtain 0 = Pn

i=1

λi(yi)

γ0 ≥s1∆−(s3+s4)k. Therefore s1δk2.Thuss2 = 1−s1−s3−s4≥1−δ(k+1)2 . We can find numbers ˜yi for j1< i≤j2, such that (yi)γ0 ≤y˜i ≤∆ and

j1

X

i=1

λi(yi)γ0+

n

X

i=j2+1

λi(yi)γ0+

j2

X

i=j1+1

λii =xγ0.

(7)

Indeed,

n

P

i=j2+1

λi(yi)γ0

≤ (s3 +s4)k ≤ δk. Consequently, s2∆− δk ≥ ∆−

δ(k+1)

δk > δby our choice ofδ.

Putting (xi)γ = ˜yi for j1 < i ≤j2, γ = γ0 and (xi)γ = (yi)γ for any other choices ofiandγ, we obtain again

n

X

i=1

λiF(xi) =

n

X

i=1

λiF(yi).

Hence we proved thatC(·) is a convex function on c0(Γ), k · k2 ≤C(·) ≤ k · k+ε2

and, forkxk ≤2, C(x) depends only on those coordinatesxγ of x for which|xγ| ≥δ. More precisely,

C X

γ∈Γ

xγeγ

=C X

γ∈Γ1

xγeγ ,

where Γ1 ={γ∈Γ, |xγ| ≥δ}.

We will now construct aC-Fr´echet smooth convex function on the set {x∈ c0(Γ), kxk < 2}, which uniformly approximates C(·). To this end, choose a C-smooth bump function b(t) on R, 0 ≤ b(t) = b(−t), suppb ⊂ [−δ4,δ4],

R

−∞

b(t)dt= 1.

It is elementary to check that from the symmetry condition on b and the convexity off it follows that

f(r)≤ Z

−∞

f(t)b(r−t)dt for arbitrary convex continuous function defined onR.

It is standard to check that for arbitraryγ0∈Γ, the function Cγ0 X

γ∈Γ

xγeγ

=

Z

−∞

C X

γ∈Γ γ6=γ0

xγeγ+teγ0

b(xγ0−t)dt

is convex andCγ0(·)≥C(·).

Put Π =

π={γ1, . . . , γn}, n∈N, γi ∈Γ to be the set of all finite subsets of Γ. Forπ={γ1, . . . , γn} ∈Π define

Cπ X

γ∈Γ

xγeγ

=

= Z

−∞

· · · Z

−∞

C X

γ∈Γ γ /∈π

xγeγ+

n

X

i=1

tieγi

b(xγ1−t1). . . b(xγn−tn)dt1. . . dtn.

(8)

For every π ∈Π, Cπ is a convex function satisfying Cπ2(·)≥ Cπ1(·) whenever π1 ⊂π2.

Define ˜C(x) = sup{Cπ(x), π∈Π}.

Supposex= P

γ∈Γ

xγeγ, kxk ≤ 2−δ2, Γ1 ={γ ∈ Γ, |xγ| ≤ δ4}, Γ2 = Γ\Γ1. Clearly Γ2 ∈Π. For everyy∈c0(Γ) such thatky−xk< δ4, we have|yγ| ≤ δ2 forγ∈Γ1. For suchy the following formula is satisfied:

(y) =CΓ2(y) =

= Z

−∞

· · · Z

−∞

C X

γ∈Γ γ /∈Γ2

yγeγ+

n

X

i=1

tieγi

b(yγ1−t1). . . b(yγn−tn)dt1. . . dtn,

where Γ2 ={γ1, . . . , γn}.

Indeed, for every Γ3={γ1, . . . , γm}, Γ2 ⊂Γ3 we have

CΓ3(y) =

Z

−∞

· · ·

Z

−∞

C X

γ∈Γ γ /∈Γ3

yγeγ+

m

X

i=1

tieγi

b(yγ1−t1). . . b(yγn−tn)dt1. . . dtm,

and thus CΓ3(y)

= Z

−∞

· · · Z

−∞

C X

γ∈Γ γ /∈Γ2

yγeγ+

n

X

i=1

tieγi

b(yγ1 −t1). . . b(yγn−tn)dt1. . . dtn

=CΓ2(y),

because the functionφ(t1, . . . , tm) =C P

γ∈Γ γ /∈Γ3

yγeγ+ Pm

i=1

tieγi

is for any given

t1, . . . , tn constant in variables tn+1, . . . , tm satisfying |tn+1−yγn+1| ≤ δ4, . . . ,

|tm−yγm| ≤ δ4. The function ˜C(·) restricted toBk·k x,δ4

thus depends only on the coordinates {yγ1, . . . , yγn} of y and is easily observed to be C-Fr´echet smooth. The trivial estimate gives us

kxk2≤C(x)≤C˜(x)≤sup{C(x+v),kvk< δ 2}

≤sup{ kx+vk+ε2

, kvk<δ 2}.

(9)

By the standard argument of choosing ε and δ small enough, we obtain, via the implicit function theorem, that theC-Fr´echet smooth norm defined as the Minkowski functional of the set{x, C˜(x)≤1}approximates arbitrary well (on bounded sets) the original normk · k.

We say that a normk| · k| defined on aC(K) space depends locally on finitely many coordinates if for every f ∈ C(K) there exist a finite set {k1, . . . , kn} ⊂ K, ε >0 andφ:Rn→Rsuch that

|||g|||=φ g(k1), . . . , g(kn) ,

wheneverkg−fk< ε.

Proposition 2. There exists no lattice and Gˆateaux differentiable(not neces- sarily equivalent)normC0([0, ω1]). There exists no lattice(not necessarily equiv- alent)norm onC0([0, ω1])that depends locally on finitely many coordinates.

Proof: Assume thatk · kis a given norm onC0([0, ω1]). Let us first define, for a given non-limit ordinalα < ω1α on [α, ω1) by

ϕα(β) =kχ[α,β]k forβ a nonlimit ordinal,

ϕα(β) = sup{ϕα(γ), γ < β, γ nonlimit}forβ a limit ordinal.

The functionϕαis well defined sinceχ[α,β]∈C0[0, ω1] wheneverα, βare nonlimit ordinals. By the lattice condition onk · k,ϕα is a nondecreasing function defined on [0, ω1). Thus for some nonlimitβα> α we have

ϕαα) =ϕα(γ) for everyγ∈[βα, ω1].

Similarly, by the lattice assumption, whenever α1 < α2 are nonlimit ordinals, ϕα1α1)≤ϕα2α2). Therefore, there existsα0∈ω1 such that

ϕα0α0)≥ϕα(β) wheneverβ≥α≥α0.

Let us define, by induction, a sequence{αi}i=0 as follows: α0 comes from the above consideration,αi+1αi+ 1.

Choose a closed and open countable interval [α0, β]⊂[0, ω1) such thatβ ≥αi for everyi∈N. Clearly,χ0,β]∈C0([0, ω1]) and

0<kχ0,β]k=kχiαi]k for everyi∈N. Also,

0,β]+t χi

αi]k ≥ k(1 +t)χi

αi]k= (1 +t)kχ0,β]k for everyt≥0.

(10)

Thus, the directional derivative of k · k at χ0,β] in direction of vi = χiαi] satisfies:

∂kχ0,β]k

∂vi ≥ ∂kχiαi]k

∂vi ≥ kχiαi]k=kχ0,β]k.

However, assuming the existence of the Gˆateaux derivativekχ0,β]k, we estimate

0,β]k 1

hkχ0,β]k,Pn

i=0

vii Pn

i=0

vi

= Pn i=0

∂kχ0,β]k

∂vi

0,β]k ≥n

for all n∈ N. (kPn

i=0

vik = kχ0,β]k by the lattice property of k · k.) This is a

contradiction.

This proves the first half of Proposition 2. The proof for the second part requires only minor modifications.

Acknowledgment. We would like to thank the referee for suggesting some im- provements and for finding an error in the original version. The second author would also like to thank the Department of Mathematics, University of Alberta, for hospitality and support during the preparation of this note.

References

[1] Deville R., Fonf V., H´ajek P.,Analytic and polyhedral approximations of convex bodies in separable polyhedral Banach spaces, Israel J. Math., to appear.

[2] Deville R., Fonf V., H´ajek P.,Analytic andCk-smooth approximations of norms in sepa- rable Banach spaces, Studia Math., to appear.

[3] Deville R., Godefroy G., Zizler V.,Smoothness and renormings in Banach spaces, Pitman Monographs and Surveys in Pure and Applied Mathematics 64, 1993.

[4] Dugundji J.,Topology, Allyn and Bacon Inc., 1966.

[5] Haydon R.,Normes infiniment differentiables sur certains espaces de Banach, C.R. Acad.

Sci. Paris, t. 315, Serie I (1992), 1175–1178.

[6] Haydon R.,Trees in renormings theory, to appear.

Mathematical Institute, Czech Academy of Sciences, ˇZitn´a 25, 115 67 Prague 1, Czech Republic

E-mail: [email protected]

Mathematical Institute, Czech Academy of Sciences, ˇZitn´a 25, 115 67 Prague 1, Czech Republic

E-mail: [email protected]

Department of Mathematics, University of Alberta, Edmonton, T6G 2G1, Canada E-mail: [email protected]

(Received March 22, 1996)

参照

関連したドキュメント

The Spino-Bulbar Tracts. Surgical Clinic of Kanazawa University School of Medicine. In fact, in the centrifugal half the dual innervation of the viscera was elucidated

Found in the diatomite of Tochibori Nigata, Ureshino Saga, Hirazawa Miyagi, Kanou and Ooike Nagano, and in the mudstone of NakamuraIrizawa Yamanashi, Kawabe Nagano.. cal with

主として、自己の居住の用に供する住宅の建築の用に供する目的で行う開発行為以外の開

[r]

We also note that since Y ∗∗ is weakly K-analytic, the space Y ∗ admits an equivalent locally uniformly rotund (LUR) norm ||| · |||, the dual norm of which is also LUR.. Fabian,

原研 核融合 栗田 源一く Gen-ichl Kurlta) 安積 正史 (Masafum Azumi) 鴬松俊秀 (Toshlhide Tsunematsu) 滝塚知典〈 Tomonori Takizuka) 竹田 辰興 (Tatsuoki

In section 3, the existence of a horizontal skew symmetric conformal (abbreviated SC) vector field C is proved by an exterior differential system in involution (in the sense of

(= R.RAO CHIVUKULA) Invariant means on spaces of continuous or measurable functions, Trans. Invariant means on vector valued functions I, Ann. Invariant means on vector valued