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(1)

The New Prime theorems(291)-(340)

Jiang, Chun-Xuan (蒋春暄)

Institute for Basic Research, Palm Harbor, FL34682-1577, USA

And: P. O. Box 3924, Beijing 100854, China (蒋春暄,北京3924信箱,100854)

[email protected], [email protected], [email protected], [email protected], [email protected]

Abstract: Using Jiang function J2( )

we prove that the new prime theorems (291)-340) contain infinitely many prime solutions and no prime solutions.

[Chun-Xuan Jiang. The New Prime theorems(291)(340)- . Academ Arena 2016;8(1s): 47-93]. (ISSN 1553-992X).

http://www.sciencepub.net/academia. 2. doi:10.7537/marsaaj0801s1602.

Keywords: new; prime; theorem; Jiang Chunxuan; mathematics; science; number; function The New Prime theorem(291)

, 502 ( 1, , 1)

P jP  k j j k

Chun-Xuan Jiang

[email protected] Abstract

Using Jiang function we prove that

jP502 k j contain infinitely many prime solutions and no prime solutions.

Theorem. Let k be a given odd prime.

, 502 ( 1, , 1)

P jP  k j j k . 1

contain infinitely many prime solutions and no prime solutions.

Proof. We have Jiang function [1,2]

2( ) [ 1 ( )]

P

J   P  P

2

where  P P

( )P is the number of solutions of congruence

1 502

1 0 (mod ), 1, , 1

k

j jq k j P q P

 

(3)

If ( )P P2 then from (2) and (3) we have

2( ) 0

J

(4)

We prove that (1) contain infinitely many prime solutions.

If ( )P P1 then from (2) and (3) we have

2( ) 0

J

5

We prove that (1) contain no prime solutions [1,2]

If J2( ) 0

then we have asymptotic formula [1,2]

502

2 1 1

( , 2) : ~ ( )

(502) ( ) log

k

k k k k

J N

N P N jP k j prime

N

 

 

  

(6)

where ( ) ( 1)

P P

   

.

(2)

Example 1. Let k 3, 503. From (2) and(3) we have

2( ) 0

J

7

we prove that for k 3, 503, (1) contain no prime solutions Example 2. Let k3, 503. From (2) and (3) we have

2( ) 0

J

8

We prove that for k3, 7 (1) contain infinitely many prime solutions

The New Prime theorem(292)

, 504 ( 1, , 1)

P jP  k j j k

Chun-Xuan Jiang

[email protected] Abstract

Using Jiang function we prove that

jP504 k j contain infinitely many prime solutions and no prime solutions.

Theorem. Let k be a given odd prime.

, 504 ( 1, , 1)

P jP  k j j k . (1)

contain infinitely many prime solutions and no prime solutions.

Proof. We have Jiang function [1,2]

2( ) [ 1 ( )]

P

J   P  P

2

where  P P

( )P is the number of solutions of congruence

1 504

1 0 (mod ), 1, , 1

k

j jq k j P q P

 

3

If ( )P P2 then from (2) and (3) we have

2( ) 0

J

(4)

We prove that (1) contain infinitely many prime solutions.

If ( )P P1 then from (2) and (3) we have

2( ) 0

J

(5)

We prove that (1) contain no prime solutions [1,2]

If J2( ) 0

then we have asymptotic formula [1,2]

504

2 1 1

( , 2) : ~ ( )

(504) ( ) log

k

k k k k

J N

N P N jP k j prime

N

 

 

  

(6)

where ( ) ( 1)

P P

   

.

Example 1. Let k 3, 5, 7,13,19, 29, 43,127. From (2) and(3) we have

2( ) 0

J

7

We prove that for k3, 5, 7,13,19, 29, 43,127 (1) contain no prime solutions.

Example 2. Let k 3, 5, 7,13,19, 29, 43,127. From (2) and (3) we have

(3)

2( ) 0 J

8

We prove that for k3, 5, 7,13,19, 29, 43,127, (1) contain infinitely many prime solutions

The New Prime theorem(293)

, 506 ( 1, , 1)

P jP  k j j k

Chun-Xuan Jiang

[email protected] Abstract

Using Jiang function we prove that

jP506 k j contain infinitely many prime solutions and no prime solutions.

Theorem. Let k be a given odd prime.

, 506 ( 1, , 1)

P jP  k j j k . (1)

contain infinitely many prime solutions and no prime solutions.

Proof. We have Jiang function [1,2]

2( ) [ 1 ( )]

P

J   P  P

2

where  P P

( )P is the number of solutions of congruence

1 506

1 0 (mod ), 1, , 1

k

j jq k j P q P

 

3

If ( )P P2 then from (2) and (3) we have

2( ) 0

J

4

We prove that (1) contain infinitely many prime solutions.

If ( )P P1 then from (2) and (3) we have

2( ) 0

J

(5)

We prove that (1) contain no prime solutions [1,2]

If J2( ) 0

then we have asymptotic formula [1,2]

506

2 1 1

( , 2) : ~ ( )

(506) ( ) log

k

k k k k

J N

N P N jP k j prime

N

 

 

  

6

where ( ) ( 1)

P P

   

.

Example 1. Let k 3, 23, 47. From (2) and(3) we have

2( ) 0

J

7

We prove that for k3, 23, 47, (1) contain no prime solutions.

Example 2. Let k 3, 23, 47. From (2) and (3) we have

2( ) 0

J

8

We prove that for k3, 23, 47 (1) contain infinitely many prime solutions

The New Prime theorem(294)

(4)

, 508 ( 1, , 1) P jP  k j j k

Chun-Xuan Jiang

[email protected] Abstract

Using Jiang function we prove that

jP508 k j contain infinitely many prime solutions and no prime solutions.

Theorem. Let k be a given odd prime.

, 508 ( 1, , 1)

P jP  k j j k . (1)

contain infinitely many prime solutions or no prime solutions.

Proof. We have Jiang function [1,2]

2( ) [ 1 ( )]

P

J   P  P

(2)

where  P P

( )P is the number of solutions of congruence

1 508

1 0 (mod ), 1, , 1

k

j jq k j P q P

 

3

If ( )P P2 then from (2) and (3) we have

2( ) 0

J

4

We prove that (1) contain infinitely many prime solutions.

If ( )P P1 then from (2) and (3) we have

2( ) 0

J

5

We prove that (1) contain no prime solutions [1,2]

If J2( ) 0

then we have asymptotic formula [1,2]

508

2 1 1

( , 2) : ~ ( )

(508) ( ) log

k

k k k k

J N

N P N jP k j prime

N

 

 

  

6

where ( ) ( 1)

P P

   

.

Example 1. Let k 3, 5, 509. From (2) and(3) we have

2( ) 0

J

(7)

We prove that for k3, 5, 509 (1) contain no prime solutions.

Example 2. Let k 3, 5, 509. From (2) and (3) we have

2( ) 0

J

8

We prove that fork 3, 5, 509 (1) contain infinitely many prime solutions

The New Prime theorem(295)

, 510 ( 1, , 1)

P jP  k j j k

Chun-Xuan Jiang

[email protected] Abstract

(5)

Using Jiang function we prove that

jP510 k j contain infinitely many prime solutions and no prime solutions.

Theorem. Let k be a given odd prime.

, 510 ( 1, , 1)

P jP  k j j k

. 1

contain infinitely many prime solutions and no prime solutions.

Proof. We have Jiang function [1,2]

2( ) [ 1 ( )]

P

J   P  P

2

where  P P

( )P is the number of solutions of congruence

1 510

1 0 (mod ), 1, , 1

k

j jq k j P q P

 

(3)

If ( )P P2 then from (2) and (3) we have

2( ) 0

J

(4)

We prove that (1) contain infinitely many prime solutions.

If ( )P P1 then from (2) and (3) we have

2( ) 0

J

(5)

We prove that (1) contain no prime solutions [1,2]

If J2( ) 0

then we have asymptotic formula [1,2]

510

2 1 1

( , 2) : ~ ( )

(510) ( ) log

k

k k k k

J N

N P N jP k j prime

N

 

 

  

6

where ( ) ( 1)

P P

   

.

Example 1. Let k 3, 7,11, 31,103. From (2) and(3) we have

2( ) 0

J

7

We prove that for k3, 7,11, 31,103, (1) contain no prime solutions.

Example 2. Let k 3, 7,11, 31,103. From (2) and (3) we have

2( ) 0

J

(8)

We prove that for k3, 7,11, 31,103, (1) contain infinitely many prime solutions

The New Prime theorem(296)

, 512 ( 1, , 1)

P jP  k j j k

Chun-Xuan Jiang

[email protected] Abstract

Using Jiang function we prove that

jP512 k j contain infinitely many prime solutions and no prime solutions.

Theorem. Let k be a given odd prime.

, 512 ( 1, , 1)

P jP  k j j k

. 1

(6)

contain infinitely many prime solutions and no prime solutions.

Proof. We have Jiang function [1,2]

2( ) [ 1 ( )]

J  P P  P

(2)

where  P P

( )P is the number of solutions of congruence

1 512

1 0 (mod ), 1, , 1

k

j jq k j P q P

 

(3)

If ( )P P2 then from (2) and (3) we have

2( ) 0

J

(4)

We prove that (1) contain infinitely many prime solutions.

If ( )P P1 then from (2) and (3) we have

2( ) 0

J

5

We prove that (1) contain no prime solutions [1,2]

If J2( ) 0

then we have asymptotic formula [1,2]

512

2 1 1

( , 2) : ~ ( )

(512) ( ) log

k

k k k k

J N

N P N jP k j prime

N

 

 

  

(6)

where ( ) ( 1)

P P

   

.

Example 1. Let k 3, 5,17, 257. From (2) and(3) we have

2( ) 0

J

(7)

We prove that for k3, 5,17, 257, (1) contain no prime solutions.

Example 2. Let k 3, 5,17, 257. From (2) and (3) we have

2( ) 0

J

8

We prove that for k 3, 5,17, 257, (1) contain infinitely many prime solutions The New Prime theorem(297)

, 514 ( 1, , 1)

P jP  k j j k

Chun-Xuan Jiang

[email protected] Abstract

Using Jiang function we prove that

jP514 k j contain infinitely many prime solutions and no prime solutions.

Theorem. Let k be a given odd prime.

, 514 ( 1, , 1)

P jP  k j j k , 1

contain infinitely many prime solutions and no prime solutions.

Proof. We have Jiang function [1,2]

2( ) [ 1 ( )]

P

J   P  P

(2)

where  P P

( )P is the number of solutions of congruence

(7)

1 514

1 0 (mod ), 1, , 1

k

j jq k j P q P

 

(3)

If ( )P P2 then from (2) and (3) we have

2( ) 0

J

4

We prove that (1) contain infinitely many prime solutions.

If ( )P P1 then from (2) and (3) we have

2( ) 0

J

(5)

We prove that (1) contain no prime solutions [1,2]

If J2( ) 0

then we have asymptotic formula [1,2]

514

2 1 1

( , 2) : ~ ( )

(514) ( ) log

k

k k k k

J N

N P N jP k j prime

N

 

 

  

6

where ( ) ( 1)

P P

   

.

Example 1. Let k 3. From (2) and(3) we have

2( ) 0

J

7

We prove that for k3, (1) contain no prime solutions.

Example 2. Let k 3. From (2) and (3) we have

2( ) 0

J

8

We prove that for k3, (1) contain infinitely many prime solutions

The New Prime theorem(298)

, 516 ( 1, , 1)

P jP  k j j k

Chun-Xuan Jiang

[email protected] Abstract

Using Jiang function we prove that

jP516 k j contain infinitely many prime solutions and no prime solutions.

Theorem. Let k be a given odd prime.

, 516 ( 1, , 1)

P jP  k j j k

, 1

contain infinitely many prime solutions and no prime solutions.

Proof. We have Jiang function [1,2]

2( ) [ 1 ( )]

P

J   P  P

2

where  P P

( )P is the number of solutions of congruence

1 516

1 0 (mod ), 1, , 1

k

j jq k j P q P

 

(3)

If ( )P P2 then from (2) and (3) we have

2( ) 0

J

4

We prove that (1) contain infinitely many prime solutions.

(8)

If ( )P P1 then from (2) and (3) we have

2( ) 0

J

5

We prove that (1) contain no prime solutions [1,2]

If J2( ) 0

then we have asymptotic formula [1,2]

516

2 1 1

( , 2) : ~ ( )

(516) ( ) log

k

k k k k

J N

N P N jP k j prime

N

 

 

  

6

where ( ) ( 1)

P P

   

.

Example 1. Let k 3, 5, 7,13,173. From (2) and(3) we have

2( ) 0

J

(7)

We prove that for k3, 5, 7,13,173, (1) contain no prime solutions.

Example 2. Let k3, 5, 7,13,173. From (2) and (3) we have

2( ) 0

J

(8)

We prove that for k3, 5, 7,13,173, (1) contain infinitely many prime solutions

The New Prime theorem(299)

, 518 ( 1, , 1)

P jP  k j j k

Chun-Xuan Jiang

[email protected] Abstract

Using Jiang function we prove that

jP518 k j contain infinitely many prime solutions and no prime solutions.

Theorem. Let k be a given odd prime.

, 518 ( 1, , 1)

P jP  k j j k

, 1

contain infinitely many prime solutions and no prime solutions.

Proof. We have Jiang function [1,2]

2( ) [ 1 ( )]

J  P P  P

(2)

where  P P

( )P is the number of solutions of congruence

1 518

1 0 (mod ), 1, , 1

k

j jq k j P q P

 

(3)

If ( )P P2 then from (2) and (3) we have

2( ) 0

J

4

We prove that (1) contain infinitely many prime solutions.

If ( )P P1 then from (2) and (3) we have

2( ) 0

J

5

We prove that (1) contain no prime solutions [1,2]

If J2( ) 0

then we have asymptotic formula [1,2]

(9)

518

2 1 1

( , 2) : ~ ( )

(518) ( ) log

k

k k k k

J N

N P N jP k j prime

N

 

 

  

(6)

where ( ) ( 1)

P P

   

.

Example 1. Let k 3. From (2) and(3) we have

2( ) 0

J

7

We prove that for k3, (1) contain no prime solutions.

Example 2. Let k3. From (2) and (3) we have

2( ) 0

J

8

We prove that for k 3, (1) contain infinitely many prime solutions

The New Prime theorem(300)

, 520 ( 1, , 1)

P jP  k j j k

Chun-Xuan Jiang

[email protected] Abstract

Using Jiang function we prove that

jP520 k j contain infinitely many prime solutions and no prime solutions.

Theorem. Let k be a given odd prime.

, 520 ( 1, , 1)

P jP  k j j k , (1)

contain infinitely many prime solutions and no prime solutions.

Proof. We have Jiang function [1,2]

2( ) [ 1 ( )]

J  P P  P

(2)

where  P P

( )P is the number of solutions of congruence

1 520

1 0 (mod ), 1, , 1

k

j jq k j P q P

 

3

If ( )P P2 then from (2) and (3) we have

2( ) 0

J

(4)

We prove that (1) contain infinitely many prime solutions.

If ( )P P1 then from (2) and (3) we have

2( ) 0

J

(5)

We prove that (1) contain no prime solutions [1,2]

If J2( ) 0

then we have asymptotic formula [1,2]

520

2 1 1

( , 2) : ~ ( )

(520) ( ) log

k

k k k k

J N

N P N jP k j prime

N

 

 

  

6

where ( ) ( 1)

P P

   

.

Example 1. Let k 3, 5,11, 41, 53,131, 521. From (2) and(3) we have

(10)

2( ) 0 J

7

We prove that for k3, 5,11, 41, 53,131, 521, (1) contain no prime solutions.

Example 2. Let k3, 5,11, 41, 53,131, 521. From (2) and (3) we have

2( ) 0

J

8

We prove that for k 3, 5,11, 41, 53,131, 521, (1) contain infinitely many prime solutions The New Prime theorem(301)

, 522 ( 1, , 1)

P jP  k j j k

Chun-Xuan Jiang

[email protected] Abstract

Using Jiang function we prove that

jP522 k j contain infinitely many prime solutions and no prime solutions.

Theorem. Let k be a given odd prime.

, 522 ( 1, , 1)

P jP  k j j k

. 1

contain infinitely many prime solutions and no prime solutions.

Proof. We have Jiang function [1,2]

2( ) [ 1 ( )]

P

J   P  P

2

where  P P

( )P is the number of solutions of congruence

1 522

1 0 (mod ), 1, , 1

k

j jq k j P q P

 

3

If ( )P P2 then from (2) and (3) we have

2( ) 0

J

4

We prove that (1) contain infinitely many prime solutions.

If ( )P P1 then from (2) and (3) we have

2( ) 0

J

(5)

We prove that (1) contain no prime solutions [1,2]

If J2( ) 0

then we have asymptotic formula [1,2]

522

2 1 1

( , 2) : ~ ( )

(522) ( ) log

k

k k k k

J N

N P N jP k j prime

N

 

 

  

6

where ( ) ( 1)

P P

   

.

Example 1. Let k 3, 7,19, 59, 523. From (2) and(3) we have

2( ) 0

J

7

we prove that for k 3, 7,19, 59, 523, (1) contain no prime solutions Example 2. Let k3, 7,19, 59, 523. From (2) and (3) we have

2( ) 0

J

(8)

(11)

We prove that for k3, 7,19, 59, 523 (1) contain infinitely many prime solutions

The New Prime theorem(302)

, 524 ( 1, , 1)

P jP  k j j k

Chun-Xuan Jiang

[email protected] Abstract

Using Jiang function we prove that

jP524 k j contain infinitely many prime solutions and no prime solutions.

Theorem. Let k be a given odd prime.

, 524 ( 1, , 1)

P jP  k j j k

. 1

contain infinitely many prime solutions and no prime solutions.

Proof. We have Jiang function [1,2]

2( ) [ 1 ( )]

P

J   P  P

2

where  P P

( )P is the number of solutions of congruence

1 524

1 0 (mod ), 1, , 1

k

j jq k j P q P

 

3

If ( )P P2 then from (2) and (3) we have

2( ) 0

J

4

We prove that (1) contain infinitely many prime solutions.

If ( )P P1 then from (2) and (3) we have

2( ) 0

J

5

We prove that (1) contain no prime solutions [1,2]

If J2( ) 0

then we have asymptotic formula [1,2]

524

2 1 1

( , 2) : ~ ( )

(524) ( ) log

k

k k k k

J N

N P N jP k j prime

N

 

 

  

6

where ( ) ( 1)

P P

   

.

Example 1. Let k 3, 5, 263. From (2) and(3) we have

2( ) 0

J

7

We prove that for k3, 5, 263 (1) contain no prime solutions.

Example 2. Let k 3, 5, 263. From (2) and (3) we have

2( ) 0

J

(8)

We prove that for k3, 5, 263, (1) contain infinitely many prime solutions

The New Prime theorem(303)

, 526 ( 1, , 1)

P jP  k j j k

(12)

Chun-Xuan Jiang

[email protected] Abstract

Using Jiang function we prove that

jP526 k j contain infinitely many prime solutions and no prime solutions.

Theorem. Let k be a given odd prime.

, 526 ( 1, , 1)

P jP  k j j k . (1)

contain infinitely many prime solutions and no prime solutions.

Proof. We have Jiang function [1,2]

2( ) [ 1 ( )]

P

J   P  P

2

where  P P

( )P is the number of solutions of congruence

1 526

1 0 (mod ), 1, , 1

k

j jq k j P q P

 

3

If ( )P P2 then from (2) and (3) we have

2( ) 0

J

4

We prove that (1) contain infinitely many prime solutions.

If ( )P P1 then from (2) and (3) we have

2( ) 0

J

(5)

We prove that (1) contain no prime solutions [1,2]

If J2( ) 0

then we have asymptotic formula [1,2]

526

2 1 1

( , 2) : ~ ( )

(526) ( ) log

k

k k k k

J N

N P N jP k j prime

N

 

 

  

6

where ( ) ( 1)

P P

   

.

Example 1. Let k 3. From (2) and(3) we have

2( ) 0

J

7

We prove that for k3, (1) contain no prime solutions.

Example 2. Let k 3. From (2) and (3) we have

2( ) 0

J

(8)

We prove that for k3 (1) contain infinitely many prime solutions

The New Prime theorem(304)

, 528 ( 1, , 1)

P jP  k j j k

Chun-Xuan Jiang

[email protected] Abstract

Using Jiang function we prove that

jP528 k j contain infinitely many prime solutions and no prime solutions.

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