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Comment.Math.Univ.Carolin. 32,1 (1991)115–118 115

Convex orderings for stochastic processes

Bruno Bassan, Marco Scarsini

Abstract. We consider partial orderings for stochastic processes induced by expectations of convex or increasing convex (concave or increasing concave) functionals. We prove that these orderings are implied by the analogous finite dimensional orderings.

Keywords: stochastic orders, convex orders, orders for random processes Classification: Primary 60G99; Secondary 60G07, 60E99

1. LetE be a Polish space and letF be a class of functionals defined onEN. We consider two stochastic processesX ={Xn|n∈ N} and Y ={Yn|n∈N} taking values inE. Relations such as

(1) Eφ(X)≤Eφ(Y) ∀φ∈ F

are often used to define partial orders for stochastic processes which have many applications in probability, mathematical statistics, mathematical economics and operations research (see for example Stoyan (1983)).

Our goal is to find familiesFnof functions defined onEn, such that Eψ(X1, . . . , Xn)≤Eψ(Y1, . . . , Yn) ∀ ψ∈ Fn, ∀n∈N implies (1).

Kamae, Krengel and O’Brien (1977) proved the implication when Eis partially ordered and F and Fn are the classes of increasing functions. The problem is reported as open by Stoyan (1983) in the case of the classes of increasing convex and increasing concave functions defined on a linear spaceE. In this note, we give a solution for these two families and the families of convex and concave functions. It may be noted that a similar problem was studied by Lindqvist (1988), who showed that a stochastic process is associated, if all its finite dimensional distributions are associated.

2. We introduce the following classes of functions defined on a convex subsetU of a partially ordered topological vector space.

FI(U) ={f :U →R|f is increasing}, FV(U) ={f :U →R|f is convex}, FIV(U) =FI(U)∩ FV(U),

FC(U) ={f :U →R|f is concave}, FIC(U) =FI(U)∩ FC(U).

Work supported by M.P.I

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116 B. Bassan, M. Scarsini

LetWbe a convex subset of a partially ordered Polish space. For every setA⊂N, we endowWAwith the product topology and of the componentwise ordering. All the integrals that appear in the sequel are assumed to exist.

Theorem. LetX={Xn|n∈N}andY ={Yn|n∈N}be two stochastic processes with values inW, and letF be any of the classesFV,FIV, FC,FIC. If

Eφ(X1, . . . , Xn)≤Eφ(Y1, . . . , Yn) ∀ n∈N

for every measurable φ ∈ F(Wn) such that the above expectations exist, then Eg(X)≤Eg(Y)for every continuous functionalg∈ F(WN).

The proof is based upon the following lemma.

Lemma. Let E =E1×E2 be a convex subset of a topological vector space, let H : E → R be a convex function bounded from below, and let h : E1 → R be defined by the relation:

h(x) = inf

y∈E2

H(x, y).

Thenhis convex.

Proof of Lemma: Given a functionf :B→R, we define epi (f) ={(x, z)∈B×R|f(x)< z}.

Let also

Ay={(x, z)∈E1×R|(x, y, z)∈epi (H)}, y∈E2. Let us prove now that epi (h) =S

y∈E2Ay. If (x, z)∈S

y∈E2Ay, then there exists y0∈E2 such that (x, z)∈Ay0 and

h(x) = inf

y∈E2

H(x, y)≤H(x, y0)< z;

thus (x, z)∈epi (h). Conversely, let (x, z)∈epi (h), i.e. h(x) = infy∈E2H(x, y)<

z; we can choosey∈E2 such thatH(x, y)< z. Then (x, z)∈Ay ⊂S

yE2Ay. Since a functionf is convex, if and only if epi (f) is a convex set, the claim will follow if we prove thatS

yE2Ay is convex. Let (x1, z1), (x2, z2)∈S

yE2Ay; then there exist y1, y2 such that H(x1, y1)< z1 and H(x2, y2) < z2. The inequalities above and the convexity ofH imply

H α(x1, y1) + (1−α)(x2, y2)

≤αH(x1, y1) + (1−α)H(x2, y2)< αz1+ (1−α)z2, i.e.

αx1+ (1−α)x2, αz1+ (1−α)z2

∈Aαy1+(1−α)y2 ⊂ [

y∈E2

Ay.

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Convex orderings for stochastic processes 117

Proof of Theorem: First, we prove the result for the classesFVand FIV. Let g:WN→Rbe a function bounded from below; for everyn∈N, we define functions gn:WN→Randgen:Wn→Rby the following relation:

gn(u1, u2, . . .) =egn(u1, . . . , un) = inf

sk∈W k>n

g(u1, . . . , un, sn+1, . . .).

Ifg∈ F(WN), then the Lemma implies that egn∈ F(Wn). Thus Eegn(X1, . . . , Xn)≤Eegn(Y1, . . . , Yn) or, equivalently,

Egn(X)≤Egn(Y).

It is clear that{gn|n∈N}is an increasing sequence. We show now that it converges pointwise tog. For everyx∈WN andn >0, we choose a sequences(n)n+1, s(n)n+2, . . . such that, if

x(n)= (x1, . . . , xn, s(n)n+1, s(n)n+2, . . .), one has

|g(x(n))−gn(x)| <2−n. The relation

|g(x)−gn(x)| ≤ |g(x)−g(x(n))| + |g(x(n))−gn(x)|,

the continuity ofg and the convergence of the sequence {x(n)|n∈N} to ximply that limn→∞gn=g.

It follows from the monotone convergence theorem thatEg(X)≤Eg(Y).

Consider now the case of a functiong∈ F not necessarily bounded from below.

Let g+ = max(g,0), g = max(−g,0) and hn = max(g,−n). Then, for every n∈N, we have thath+n =g+andhn ↑g. Sincehn∈ F and hn is bounded from below, it follows that

Ehn(X)≤Ehn(Y).

The monotone convergence theorem implies that

n→∞lim Ehn(·) =Eg(·);

therefore

n→∞lim Ehn(·) =Eg(·) and the claim follows immediately.

The result for the classesFCandFICcan be easily proved now, sincef ∈ FC, if and only if (−f)∈ FVandf ∈ FIC, if and only ifh∈ FIV, whereh(x) =−f(−x).

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118 B. Bassan, M. Scarsini

References

[1] Stoyan D.,Comparison Methods for Queues and Other Stochastic Models, Wiley, New York, 1983.

[2] Kamae T., Krengel U., O’Brien G.L., Stochastic inequalities on partially ordered spaces, Annals of Probability5(1977), 899–912.

[3] Lindqvist B.H., Association of probability measures on partially ordered spaces, Journal of Multivariate Analysis26(1988), 111–132.

Dipartimento di Statistica, Probabilit`a e Statistiche Applicate, Universit`a di Roma

“La Sapienza”, Piazzale Aldo Moro 5, I–00185 Roma, Italy

Dipartimento di Scienze Attuariali, Universit`a di Roma “La Sapienza”, Via del Cas- tro Laurenziano 9, I–00161 Roma, Italy

(Received September 1, 1990)

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