Internat. J. Math. & Math. Sci.
VOL. 18 NO. 4 (1995) 649-652
649
COMPLETION OF PROBABILISTIC NORMED SPACES
BERNARDO LAFUERZA
GUILLIN JOSi
ANTONIORODRiGUE.ZLALLENADepartamento
deMatemtica, AplicadaUniversidadd,eAhneria 04120 Almeria, Spain
and CARLOSEMPI Dipartimento di Matematica
Universit di Lecce 73100
Lecce,
Italy(Received
December6, 1993 and in revised formJanuary
28,1994)
ABSTRACT. We prove that everyprobabilistic normed space, either according to the original definition given by
erstnev,
or according tothe recentone introducedby Alsina, Schweizer and Sklar,has acompletion.KEY
WORDSAND
PHRASES. Probabilistic NormedSpaces,
completion, triangle function, L6vydistance.1991 AMS
SUBJECT CLASSIFICATION
CODES. 54E70, 60E99.1.
INTRODUCTION.
As iswellknown,arealorcomplex normed linear space admitsacompletion, namely, given a normed linear space
(Y, I1" ),
there exists another linear space(V’, I1" I1")
such thatV"
isisometrictoadensesubspaceof
V.
It wasproved by Mutari
[2],
Sherwood([7], [8])
and Sempi[5]
that a probabilistic metric space has a completion.Here
we answer in the positive the natural question of whether a probabilistic normed space has a completion. In fact, there are twodefinitions ofprobabilistic normedspace(= Pg-space)"
theoriginalone byerstnev ([6],
but see[3]
for apresentation in agreement with ournotation),
and amore recent one by Alsina, Schweizer and Sklar(see [1]).
The proofwill be givenin both cases. For the notation and the concepts used we refer to the bookbySchweizer andSklar
[3];
weshallwrited.f. fordistribution function.Accordingto
erstnev,
aPN-space
is atriple(V,
v,’),
whereVis areallinear space; ris a trianglefunction ([3],
section7.1),
i.e., a binary operation on A+,
the space of distance distribution functions, that is commutative, associative and nondecreasing in each variable and whichhas the d.f. e0asidentity, i.e.,(a) VF,
G A+r(F,G) r(G,F);
(b) VF, G,H
A+v(F,r(G,H) T(r(F,G),H);
(c) VHA +F_<G=> v(F, H) _< r(G. H);
(d) VF
A +’(F, e0)
F.Here
0 isthe d.f. definedbyf0, ifx<:0,
0(z): =/1,
ifz>0;650 B. L.
GUILLN,
J. A. R. LALLENA AND C. SEMPIv is the probabilistic norm, i.e., v is a nap from V into /k+ that satisfies the following conditions:
(N.1)
t,(p) e0, if, and only if,p 0,where0is the nullvectorofV;
(N.2)
VzEI
+,aER,
witha#
0 v(ap)(x)u(p)(z/[a [);
(N.3) Vp,
q,z
t,(p+
q)>_ r[(p), v(q)].
Inbothdefinitionsthe trianglefunctionisassumedtobecontinuous.
The space A + canbe metrizedby different metrics
([9], [3], [4], [0]),
but we shalluseherethe modified
LSvy
metric dL[3].
2.
MAIN
RESULTS.THEOREM I.
Every PN-space (V,u,r)
hasacompletion,viz. is isometric toadenselinear subspaceofacompletePN-space (V’, v’, r).
PROOF.
Only the steps needed toconplement the treatment in[7]
andIS]
will be given.Now
V"
is theset of equivalence classes ofCauchysequences of elements ofV.In
order to prove thatV"
is a linear space, letp"
andq"
be elements of V" and let{p,,}
and{q,}
be Cauchy sequences of elements ofVwith{p,}
6p"
and{q,}
6q’.
Since V is a linear space, onehas,for everynN,
p,+
q,EV. Wewish toshow thatit ispossibleto define asumofp"
andq"
insuchawaythat
p" + q"
6V’. Since(V, q, ’),
with(p,q):v(p
q)is aprobabilisticmetric space([3],
Theorem
15.1.2),
onehas,ifnandmarelarg enough,q(P,, +
q,,,P,,,+ qm) u((p, + q,,)
(p,+ q,))
v((p, p,,) + (q, q,)) (because
of(N.3))
> ’[u(p,- p,,), v(q,,- q,)l.
Takingintoaccount
Lemma
4.3.4in[3],
onehasdL(q(P,, +
q,,P,+ q,,), 0) < dL(r[u(P,,- p,,),v(q,- q,,)], 0) dL([(P,, P,,,),(q,,q,,)],o).
The continuity of both
d
and r ensures that, when both m and rt tend to infinity,q(p,, +
q,,,p,,,+ q,,,) -e0. Thus {p,, + q,}
is aCauchysequenceand,
asaconsequence, it belongs
toanelementofV’,
which willbe denotedbyr’.
Thenwedefinep" + q"
r’. Thisdefinition does
notdependontheelements ofp"
andq"
selected, for,if{p,,}, {p,}
6p"
and{q,}, {q,} q’,
then
q(p,, + q,,,p, + q) v(p,,-p,,q,,-q,) > r[v(p,,- p,),v(q,,-q,)] ’[q(p,,,p,),(q,,,q,)],
sothat
dL((p, + q,,p, + q,), 0) < dL (r[(P=,P,),(q,,q,)],O)
Since both dLandrarecontinuousweobtain
(p,, +
q,,,p, + q,)
-%0,i.e.,{p,, + q,,} {p, + q,}.
Thus thesumdefined above isagood definition,whichimmediatelysatisfies the properties ofan abelian group.
For every a
R,
and for every Cauchy sequence{p,,}
of elements ofV,
also{a p,,}
is aCauchysequenceof elements ofV. This is obvious ifa 0. Ifa
#
0,onehas,foreveryx>
0,q(p., ,a)() (p. p.)(*) (p. p-)(/I I)
r(p., p,,,)(/l I),
and this lends to
{ap,}
is a Cauchy1,sequence;for every xlet>
us0,denoteas n andby u"mthe element oftend to infinity, i.e.,V"
towhichq(ap,,ap,,)
it belongs. Then- o. Thuswe
defineap’=
u’. This isagainagooddefinition;infact,let {p,,}, {p,}
Ep’.
Then
COMPLETION OF PROBABILISTIC NORMED SPACES 651 which tends to for all z
>
0when nx,whence{op,} {ap}.
Therefore it is inmediateto conclude that V"isalinearspace. All that isleft toshowisthat thedistanced.f."
derivesfromaprobabilistic normv"onV’. Forevery
p"
E1,’" set, if{p,,}
Ep"
with p, Vforeveryn I1 v’(p’): ’(p’,tg") l,m,, (p,,d)
lim,t,(p.). (2.1)
Thus
’(
p’,
q’) lira, (p,,q,) tim, v(p, q,) v’(p" q’).It
isnowaneasytasktoverify thatv"
doesindeedfulfill conditions(N.1), (N.2)
and(N.3).
13 We now turn to theproofof the analogousresult forPN-spaces
accordingto the definition given in[1].
This latter differs from theone given above in that condition(N.2)
is replaced by the weakerone(N.2") Vp
CVt,(-
p)u(p);
andanew oneisadded:
(N.4)
VaC[0,1]Vp
CV v(p)< r’[v(ap),v((1 cr)p)].
Then a
PN-space
is a quadruple(V,v,r, r*),
whereV,
asabove,
is a reallinear space,r,r"
arecontinuoustrianglefunctionsand
v’:
VA+ isamap such thatconditions(N.1), (N.2"), (N.3)
and
(N.4)
aresatisfied.The last part ofthis note isentirely devotedto
PN-spaces
accordingto this latter definition.LEMMA
2. Let(V,v,r,r*)
beaPN-space
and let h and k be tworeal constants such that 0<h<k; thenVp, q
V (kp,kq)<
(hp,hq),
whereq(p, q): v(p
q).PROOF. Thereis
A
q[0,1]
such that h Ak. Then5(kp, kq) (kp kq) [k(p q)] <
< r*[t,[Ak(p q)], t,[(1 A)k(p q)]] <
< r*[[Ak(p q)], 0] t[Ak(p q)] [h(p q)] (hp, hq).
13’I’ItIOtM 3.
Every PN-space (V,u,r,r’)
has a completion, viz. is isometric to a dense linearsubspaceofacompletePN-space (V’, r,’,
r,r’).
PROOF.
Exactly as inthe proofof Theorem 1, one canprove that if bothp"
andq"
belong toV’,
thenp’+ q" V’. However,
one can nolongerusethe sameproofof the fact that. ifcEN andp"
EV"
thenp" V’,
becauserecoursewasmade toproperty(N2)
which nowmay well not hold.Now
assumeR
andp" V’,
let{p,}
Ep"
and consider the sequence{cp,,}.
As a first step, we shall prove that it is a Cauchy sequence in V. This is obviously true for c 0 andct 1. Becauseof
(N.2"),
it sufficesto consideronly thecase c>
0. Nowassumethat{cp,,}
isaCauchysequence forcr 0,1, ,k-
l(k I1).
Then(kp,kp,,) [k(p,- p,,)] _> u(p p,), t,[(k- 1)(p,,- p,)]]
(p,,p,,),q((k-
1)p,,(k 1)p,)].
Sinceris continuousand
tim q(p,,p,)= lm,
;((k-
1)p,,,(k- 1)p,,)=0652 B. L.
GUILLN,
J. A. R. LALLENA AND C. SEMPIit follows that, also
{ap,,}
is a Cauchy sequence for every aEZ
+. If a is positive, but not integer, thereexists"
El+ such that k<n <k+
1. Lemma2nowgiveshenceit isimmediate to conclude that {op,,}isa Cauchysequence for every o6R+. Thus there exists element u"6V"suchthat
{op,,}
6u’. Let us defineu"op’. In
order to check that this is a gd definition, let{p.}{p:}.
Ifa6[O, 1],
it follows from Lemma 2 that(p.,p)
(op.,op:); since, by assumption(p.,p.)eo,
also(op,,,ap.)So. Ifa k6 +,above,one has
(’p,,,kp:) v[k(p. p,:)] v(p.
p:,),[(k-
1)(p.p:)]]
(p,,,p:,),((],
1)p,,,(k-1)p:)].
The same gumcnt above yields
{kp,} {’p:,}
forevery k +. Again, from this it is easy toobtain that,forevery Uonehs{ap,} {p}.
Therefore
V"
is a linear space. Only conditions(N.2")
and(N.4)
remainnow to beproved.Proceeding above, let
p"
V"and let{p,,}
be aCauchysequenceof elements ofVthatbelongs top’;
then{ p.} p’.
Sinceu"is defined by(2.1),
onehas,onaccount of(N.2"),
whichholds forMoreover,
for every[0,1],
oneh,because r*iscontinuous,’(F) i. (p.) ,. -[(.p.), (( -)p.)]
’[.’(-F),.(( -)F)].
ACKNOWLEDGEMENT. The authors aregrateful to their institutionsfor having made their cperation possible. The third authoris a member ofthe ItMian
G.N.A.F.A.-C.N.R.;
he gratefully acknowledgespartiM supportfromfunds providedbytheItalianM.U.R.S.T..REFERENC.
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