Internat.
J. Math.&
Math. Sci.Vol. i0 No. 2
(1987)
311-314311
ON SOME PROPERTIES OF POLYNOMIAL RINGS
H. AL-EZEH
Department of Mathematics University of Jordan
Amman Jordan
(Received February
4,
1986 and in its revised form April29,1986)
ABSTFCT. For a commutative ring with unity
R,
it is proved that R is a PF ring if and only if the annihilator,an(a),
for each a e R is a pure ideal inR,
Also it isproved that the polynlmial ring,
R[X],
is a PF-ring if and only if R is a PF-ring.Finally, we prove that R is a PP-ring if and only if
R[X]
is a PP-ring.KEY WORDS AND PHRASES. Polynomial Rings, Pure ideal, PF-ring, PP-ring, R-flatness, and idempotent elements.
1980 AMS SUBJECT CLASSIFICATION CODE: 13B.
1. INTRODUCTION.
All our rings in this paper are commutative with unity.
An
ideal I of a ring R is called pure if for any x eI,
there exists y eI
such that xy x A ring is called a PF-ring if every principal ideal aR is a flat R-module. A ring R is called a PP-ring if every principal ideal aR is a projective R-module. One can easily show that aR is projective if and only if the annihilator,an(a),
is generated by an idempotent element,(see
First, we state a proposition characterizing flat R-modules elementwise. This is a well known result in commutative ring theory,
(see [3]).
PROPOSITION
I.
An R-module M is a flat R-module if and only if for any pair of fi- nite subsets {x1, x2,Xn
and{al, a2,... an
of M and R respectively, such thatn
Y.
x.a.
0 there exists elements z zk e M andbij
e R; i1,2,...,k
i=l 1 1
n k
such that E b a
i 0 j=l 2, k, and x
i E z b
i’ i 2 n.
i=l j j=l j
In
the following theorem we establish that R is a PF-ring if and only ifann(a)
R for each a e R is B pure ideal.THEOREM
I.
For any ringR,
R is a PF-ring if and only ifan(m)
for each m e Ris a pure ideal.
n
PROOF. Let xI, x
2,...,x
n en
andal, a2,... an
e R withi=II xiai
0. Thenthere exists mI,
m2,... mn
e R such that xi
mim
iI, 2,...,
n. Son
i=Z! mmia
i 0. Hence m eann(R
i=Imiai )"
312 H.
AL-EZEH
n n
Since
ann(iElmfai)
R is a pure ideal, there exists b eann(=imiai)_
R such that bm m.n
Now take m e mR and bmI,
bm2,..., bmn
R. These elements satisfyII=l bmlai
0 andbm.m
m m xi i 2 n Therefore mR is a flat R-module
Conversely, let b
ann(m).
Then mb O. Since bR is a flat R-module, there exists Rc E bR and d e R such that dm 0 and b cd. Now c
Clb,
so b cdbCld.
MoreoverCld
eann(m).
Thereforeann(m)
is a pure ideal.R R
LEMM I.
n LetI.i, 12 In
be a finite set of pure ideals df arin R,
thenJ
n
I. is a pure ideal.j=1 J
PROOF.
Let
x eJ.
Then x eI.
J for each j. Thus there existsYl II’ Y2
e12 Yn
eIn
withxyj x, I,
2, n. Then yylY2...yne
J and xy x.Let R be a reduced without nonzero nilpotent elements) ring. Let h(X) h
0
+ hIX + +
hxn
e R[X]. Than andh(X))
NIX] where N is the annihilatorn R[XJ
of the ideal generated by h0, h
hn,
that is Nann(h0’R hI’’’’’ hn --i-- 0an(h i).
Moreover if f(X) a
0 /
alX + .+
amX
m e annR[X](h(X)) then a hi j 0 for all i 2 m andI,
2 n (see[4]).
LEMMA
2. Let R be a PF-ring, then R is reduced.PROOF. Let a be a nilpotent element in
R,
aO.
Let n be the least positive integer greater than such that an 0. Hence aann(an-l).
Since ann(an-l)-
is(an_
R n-1 Rpure, there exists b e ann with ab a. Now o ban- a since ba a.
R Contradiction. Thus R is reduced.
THEOREM 2. The ring of polynomials,
R[X],
is a PF-ring if and only if R is a PF-ring.PROOF.
Letf(X)
a0
+ alX + +am Xm
e ann (h(X)) whereh(X) ho+hiX+...+ hn Xn"
R
X
Since R[X] has no nonzero
nil.potent
elements,a e
J N ann(h ) i o, I, 2, ,m
By Lemma I,
J is pure. Hence there exist bI,
b2,..., bm
e J such thataib
i a i, i i,2,
m. Now our aim is to find c e J such that cf(X)
f(X). We construct this element inductively.First,
a0b
0 a0.
Considera0
+ alX )(
b0+
bblb
0a0b
0+ aob a0bob + alb0X + albl
XalboblX
a0
+ a0b aob + alboX + alX alboX
a0
+
aiX’
Let c b
0
+
bblb0,
thena0
+ alX + a2 X2 )(
c+
b2
Clb
2(a
0+ alX)C + b2(l Cl)(ao+al X) + a2ClX2 + a2b2 x2 a2b2ClX2
SOME PROPERTIES OF
POLYNOMIAL
RINGS 313 a0+ alX + a2ClX2 + a2b2X2 a2cl X2
a0
+ alX + a2 X2
Similarly, c
2 c
+
b2
Clb2,...
cm cm-i
+
bm cm-ibm
anda0
+ alX + ...+ ai Xi)
ci a0+ alX +...+ aiX
Ii
O, I,
2,..., m. Moreover co Cl,..., Cm
e J.Thus there exist c c e J with cf(X)
f(X).
m
Conversely, assume R[X] is a PF-ring. Let a e P and b e ann(a).
R Then b e ann
(a).
Since R is aPF-rng
there existsR[X]
g(X)
co + ClX + + ckXk
e annR[X] (a)
with b
g(X)
b. Hence bc0 b andCOa O.
Consequently, R is a PF-ring.
THEOREM 3. R is a PP-ring if and 8nly if R[X] is a PP-ring.
PROOF. It is enough to show that ann
(f(X))
isgenerated
by an idempotent R[X]elementin
R]
where f(X) a0+ alX + +a
nXn.
Since R is reducedann
(f(X))
N[X] where N is the annihilator of the ideal generated by R[X3a0, al,... an.
N ann
R(aO al,
annn_ann(a
i)
i=0 R
e.R, e.
2 e. because R is a PP-ring.i=0 1 1 I
ele2...e
n)R eR,
where eele2...e
n Hence ann(f(X)) eR[X],
e2 eR[X]
Conversely, let R[X] be a PP-ring, let a e
R,
then considerann(a).
Since R[X]R PP-ring 2
a an m
is
RxJ (a)L g(X)R[X]
whereg(X) g(X)
Ifg(X)
b0+ blX +...+
bxm
2
bo
then b 0 Thus b b
o
We claim
ann(a)
RboR.
Let b eanD(a) , then ba 0. So b e g(X)R[X3.
blX +...+ bm Xm )( Co + ClX +’’’+ ct xt )"
Therefore bb0c
O, that is+
be bR- o
For the other way
around,
let b eb0R.
Then bboC
0boa O.
That is b e andK(a).
Thusann(a)
Rb0R.
for some c
o
eR.
Since314 H.
AL-EZEH
REFERENCESi.
EVANS, M.
On commutative PP-rings,Pac.
Jour. Math., 41(1972) 687-697.2.
VASCONCELOS,
W. On finitely generated flat modules, Trans. Amer. Math.Soc.,
138(1969)
505-512.3.
LARSON, M.
andMCCARTHY, P. Multiplicative
IdealTheory,
Vol 43 in pure and applied lthematics, AcademicPress,
New York and London(1971).
4.