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(1)

(2)

のグラフの特徴 y = a(xp)

2

y = 3(x − 5)

2

> 第2章 2次関数 > 第1節 2次関数  > 第2講:2次関数

 I

2次関数  y = a(xp) 2 のグラフ

a > 0

頂点は(   ,  )

a < 0

2 軸は, 軸

y = 2 x

2

x y

O

y = ax2x 軸方向に p だけ平行移動した

y = 2(x − 3)

2

3

もとの2次関数を

y = 3x

2 とするとき,

次の2次関数が x 軸方向にどれだけ平行移 動したか。また,その頂点も答えなさい。

y = 3(x + 2)

2

x = 3

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