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CROSSED EXTENSIONS OF ALGEBRAS AND HOCHSCHILD COHOMOLOGY

HANS-JOACHIM BAUES and ELIAS GABRIEL MINIAN

(communicated by Clas L¨ofwall) Abstract

We introduce the notion of crossed n-fold extensions of an algebra B by a bimodule M and prove that such extensions represent classes in the Hochschild cohomology ofB with co- efficients inM. Moreover we consider this way characteristic classes of chain (resp. cochain) algebras in Hochschild coho- mology.

To Jan–Erik Roos on his sixty–fifth birthday

1. Introduction

Crossed modules over groups were introduced by J.H.C.Whitehead [12]. Mac Lane–Whitehead [11] observed that a crossed module over a groupGwith kernel a G-moduleM represents an element in the cohomologyH3(G, M). This result was generalized by Huebschmann [7] by showing that crossedn-fold extensions overG byM represent elements inHn+1(G, M).

In this paper we prove similar results for the Hochschild cohomology HHn+1(B, M) of an algebraB with coefficients in aB-bimoduleM. We show that crossed modules over algebras as introduced in [2] can be used to define crossed n-fold extensions ofB byM which represent elements inHHn+1(B, M) for n>2.

Our results are also available for graded algebras. In particular we show that each chain (resp. cochain) algebra C yields canonically a crossed module over the homology (resp. cohomology) algebraB =HC and this crossed module represents a characteristic classhCiin the Hochschild cohomology ofHC. The characteristic classhCidetermines all triple Massey products which are secondary operations on HC determined byC. We can consider hCias an analogue of the first k-invariant of a connected space X (in the Postnikov decomposition) which is an element in the cohomology of the fundamental group G=π1X. Berrick–Davydov [6] recently studied the classhCiwithout using crossed modules over algebras. We compute also the characteristic classhA⊗Biof the tensor product of chain algebrasA andB.

Received November 3, 2000, revised August 21, 2001; published on July 12, 2002.

2000 Mathematics Subject Classification: 18G99.

Key words and phrases: Hochschild cohomology, Massey products, crossed module.

c 2002, Hans-Joachim Baues and Elias Gabriel Minian. Permission to copy for private use granted.

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2. Hochschild cohomology

Letkbe a field. Classical Hochschild cohomology is defined for algebras and also for graded algebras overk. We consider here the graded and the non-graded case at the same time. In this paper an algebraBwill mean an associative (graded) algebra with unitk→B. AB-bimodule is a (graded) k-vector spaceV which is a left and a right B-module such that for a, b B and x∈ V we have (ax)b =a(xb). For exampleB can be considered as aB-bimodule via the multiplication in B. Given two (graded)k-vector spacesV andW we denote the tensor productV⊗kW simply byV ⊗W.

Recall that theHochschild cohomologyofB with coefficients in aB-bimoduleM is the family of extension groups

HH(B, M) = ExtBB(B, M) (2.1) between the B-bimodulesB andM.

One can associate toB the bar complex B(B), where Bn(B) =B(n+2) with differentiald:Bn(B)→Bn1(B) given by

d(x0⊗. . .⊗xn+1) = Xn

i=0

(1)i(x0⊗. . .⊗xi1⊗xixi+1⊗xi+2⊗. . .⊗xn+1) The bar complex is acyclic for anyB. This follows from the existence of a homotopy h between the identity ofB(B) and the zero map. The homotopy h: Bn(B) Bn+1(B) is defined byh(x) = 1⊗x.

The differential of the bar complex isB-bilinear. Thus we get thestandardreso- lution of theB-bimoduleB. Using this resolution one can identify the cohomology groupsHHn(B, M) with the cohomology of the complex

Fn(B, M) = HomBB(B(n+2), M) = Homk(Bn, M) (2.2) with differentialδ:Fn(B, M)→Fn+1(B, M) given by

(δf)(x1⊗. . .⊗xn+1) =x1f(x2⊗. . .⊗xn+1) +

’Xn i=1

(1)if(x1⊗. . .⊗xixi+1⊗. . .⊗xn+1)

“

+ (1)n+1f(x1⊗. . .⊗xn)xn+1.

3. Crossed modules over algebras and HH

3

We recall from [2] the following definition of crossed modules over algebras.

Definition 3.1. A Crossed module over a k-algebra is a triple (V, A, ∂) where A is a (graded) k-algebra, V is a (graded) A-bimodule and : V A is a map of A-bimodules such that (∂v)w = v(∂w) for v, w V. A map (α, β) : (V, A, ∂) (V0, A0, ∂0) between crossed modules consists of a mapα:V →V0ofk-vector spaces and a mapβ :A→A0ofk-algebras such that∂0α=β∂andα(avb) =β(a)α(v)β(b) fora, b ∈Aandv∈V.

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Given a crossed module :V →A, we considerB = coker(∂) andM = ker(∂) in the category of (graded)k-vector spaces. The algebra structure ofAinduces an algebra structure onB and theA-bimodule structure onV induces a B-bimodule structure onM given byπ(a)m=amandmπ(a) =mawhereπ:A→coker(∂) is the projection. This multiplication is well defined since (a+∂(v))m=am+∂(v)m= am+v∂(m) =am. Hence a crossed module yields an exact sequence

0 //M i //V //A π //B //0

in which all the maps are maps ofA-bimodules. Here theA-bimodule structure on M and B is induced by the map π. We call : V A a crossed module over the k-algebra B with kernelM. Let Cross(B, M) be the category of such crossed modules. Morphisms are maps between crossed modules which induce the identity onM andB.

For a categoryC, letπ0C be the class of connected components inC. An object in π0C is also termed a connected class of objects inC. In fact, π0Cross(B, M) is a set, as implied by the following result, which extends the well-known facts that HH1(B, M) is given byderivationsandHH2(B, M) classifies thesingular algebra extensions of M by B (cf. [10]). The proof of this result can also be found in [9].

Theorem 3.2. There exists a bijection

ψ:π0Cross(B, M)→HH3(B, M).

Proof. We defineψ:π0Cross(B, M)→HH3(B, M) as follows. Given E= ( 0 //M i //V //A π //B //0 )

choose k-linear sections s : B A, πs = 1 and q : Im(∂) V, ∂q = 1. For x, y∈B, we haveπ(s(x)s(y)−s(xy)) = 0 and thens(x)s(y)−s(xy)∈Im(∂). Take g(x, y) =q(s(x)s(y)−s(xy))∈V and define

θE(x, y, z) =s(x)g(y, z)−g(xy, z) +g(x, yz)−g(x, y)s(z) (§)

Since is a map of A-bimodules it follows that ∂(θE(x, y, z)) = 0 and therefore θE(x, y, z) M = ker(∂). Thus we have defined a k-linear map θE : B3 M which is a cocycle with respect to the coboundary mapδin (2.2). In fact, one easily checks thatδ(θE) = 0. We defineψ:π0Cross(B, M)→HH3(B, M) by takingψ(E) to be the class ofθE in HH3(B, M).

One has to check that ψ is a well defined function from π0Cross(B, M) to HH3(B, M), i.e. the class ofθE in HH3(B, M) does not depend on the sectionss andq. Moreover, ifE → E0 is a map in Cross(B, M), thenθE =θE0 inHH3(B, M).

We show first that the class of θE does not depend on the section s. Suppose s:B→A is another section ofπand letθE be the map defined usingsinstead of s. Since sand s are both sections ofπ there exists a linear map h: B →V with s−s=∂h. We have

E −θE)(x, y, z) =h(x)(s(y)s(z)−s(yz))−(s(x)s(y)−s(xy))h(z) +s(x)(g−g)(y, z)−(g−g)(xy, z)

+ (g−g)(x, yz)−(g−g)(x, y)s(z) ()

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whereg(x, y) =q(s(x)s(y)−s(xy)) andg(x, y) =q(s(x)s(y)−s(xy)). We define a mapb:B2→V as follows.

b(x, y) =s(x)h(y)−h(xy) +h(x)s(y)−h(x)∂h(y)

Since∂b=∂(g−g) then (g−g−b) is a map fromB2toM. Moreover we can replace (g−g) byb without changing the equality () inHH3(B, M) since the difference is the coboundary δ(g−g−b). After replacing (g−g) by b, since :V →A is a crossed module we obtain the following equality inHH3(B, M).

()≡∂h(x)s(y)h(z)−h(x)s(y)∂h(z)−∂h(x)h(yz) +h(x)∂h(yz) +∂h(x)h(y)s(z)−h(x)∂h(y)s(z) = 0

That proves that the class ofθE does not depend on the sections.

Consider a mapE → E0 as follows.

0 //M i //V //

Ꮟ

A π //

β

B //0

0 //M i0 //V0 0 //A0 π0 //B //0

Lets:B→A andq: Im(∂)→V be sections ofπand and lets0 :B →A0 and q0 : Im(∂0)→V0 be sections ofπ0 and0. Then

E−θE0)(x, y, z) =α(s(x)q(s(y)s(z)−s(yz))−q(s(xy)s(z)−s(xyz)) +q(s(x)s(yz)−s(xyz))−q(s(x)s(y)−s(xy))s(z))

−s0(x)q0(s0(y)s0(z)−s0(yz)) +q0(s0(xy)s0(z)−s0(xyz))

−q0(s0(x)s0(yz)−s0(xyz)) +q0(s0(x)s0(y)−s0(xy))s0(z) () Sinceπ0βs= 1 then βsis another section for π0 and therefore we can now replace s0 byβsand we obtain the following equality inHH3(B, M).

()≡βs(x)((αq−q0β)(s(y)s(z)−s(yz)))−(αq−q0β)(s(xy)s(z).s(xyz)) + (αq−q0β)(s(x)s(yz)−s(xyz))−(αq−q0β)(s(x)s(y)−s(xy))βs(z) Thus (θE −θE0)(x, y, z) = δφ(x, y, z) for some φ : B2 M. This proves that θE =θE0 in HH3(B, M) and that the class ofθE in HH3(B, M) does not depend on the sectionssandq. Thereforeψ is well defined.

The bijectivity ofψfollows from the following lemma.

Lemma 3.3. Givenc∈HH3(B, M)there exists a crossed moduleEc Cross(B, M) such that θEc =c. Moreover if E ∈Cross(B, M) andθE =c in HH3(B, M) there exists a map of crossed modules Ec → E.

Before we proceed with the proof, we show a construction which will be useful to prove the lemma.

Construction 3.4. Free crossed module.Given a (graded)k-algebraA, a (graded) k-vector space V and a k-linear map d: V →A (of degree 0) we obtain the free

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crossed modulewith basis (V, d) as follows. Define

A⊗V ⊗A⊗V ⊗A d2 //A⊗V ⊗A d1 //A by

d2(a⊗x⊗b⊗y⊗c) = (a(dx)b⊗y⊗c)−(a⊗x⊗b(dy)c) d1(a⊗x⊗b) =a(dx)b

fora, b, c∈Aandx, y ∈V. Sinced1d2= 0 thend1 induces

:W =A⊗V ⊗A/Im(d2)→A.

It is easy to see that (W, A, ∂) is a crossed module which has the universal property of the free crossed module with basis (V, d).

Proof of Lemma 3.3. Let

T(B) =M

n>0

Bn

be the tensor algebra generated byB as ak-vector space and letπ:T(B)→B be the map of algebras given byπ(a1⊗. . .⊗an) =a1. . . an. Let V =B⊗B and let d:V →T(B) be the linear map defined by

d(x⊗y) =x⊗y−xy

and consider (W, T(B), ∂) the free crossed module with basis (V, d). The cokernel of this crossed module is the algebraB. LetN be the kernel of∂.

Now consider the bar resolution (B(n+2), d) and the following commutative diagram of vector spaces

0 //N //

h

W //

h1



T(B)

h0

 //B //0

0 //B5/Im(d4)d3 //B4 d2 //B3 d1 //B2 µ //B //0 Here the maph0:T(B)→B3is not a bimodule map but a derivation defined by h0(b) = 1⊗b⊗1 forb ∈B and h0(xy) =π(x)h0(y) +h0(x)π(y) for x, y ∈T(B).

The map h1 : W B4 is the bimodule map defined by h1(x⊗a⊗b⊗y) = π(x)⊗a⊗b⊗π(y) forx, y∈T(B) anda, b∈B. It is easy to see thatd2h1=h0∂.

By restrictingh1to N we obtain the map of B-bimodulesh:N →B5/Im(d4).

An element c∈HH3(B, M) can be seen as a mapc :B5/Im(d4)→M of B- bimodules. Composing withhwe obtain the map ˜c=ch:N →M ofB-bimodules.

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Consider the pushout of T(B)-bimodules N

P ush

˜

c //W

r ””

M //

0 ++

W

""

T(B) .

We show thatEc = ( 0 //M //W //T(B) //B //0 ) is the de- sired crossed module.

The free crossed moduleF= ( 0 //N //W //T(B) //B //0 ) induces a cocycleθF:B5/Im(d4)→N as a map ofB-bimodules by the formula (§) via the linear sectionss:B→T(B) given bys(b) =bandq: Im(∂) = ker(π)→W defined byq(x⊗y−xy) = 1⊗x⊗y⊗1∈W. NowθEc can be computed from θF since the mapq=rq: Im(∂) = ker(π)→W is a section of∂, that is

θEc=chθF :B5/Im(d4)→M.

SinceF= 1 :B5/Im(d4)→B5/Im(d4) it follows that θEc =c.

Suppose now we have a crossed module

E= ( 0 //M //V α //A p //B //0 )

such that ψ(E) = c HH3(B, M). That implies that for certain choice of linear sectionss:B →Aandq: Im(α)→V we haveθE =c where θE is constructed by the formula (§). This induces a map of crossed modules

0 //N

ch

 //W //

g



T(B) π //

s



B //0

0 //M //V //A //B //0

where the map s : T(B) A is the map of algebras induced by s and the map g:W →V is induced by the linear mapg:B2→V, g(x, y) =q(s(x)s(y)−s(xy)).

By the universal property of the pushout N

P ush

˜

c //W

r

M //W ,

there is a mapEc→ E in Cross(B, M).

Any differential gradedk-algebra induces a crossed module as we can see in the following construction.

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Construction 3.5. The characteristic class of a cochain algebra.LetC be a dif- ferential gradedk-algebra with differential of degree +1, that isC=L

i>0Ci with CiCj ⊆Ci+j and a differentiald:C→Cof degree +1 satisfying d(xy) = (dx)y+ (1)|x|xd(y) andd2= 0. Consider the graded k-vector spacesV = coker(d)[1] and A= ker(d). Here we define for a graded vector space W theshifted graded vector spaceW[1] by

(W[1])n+1=Wn

The elements in (W[1])n+1 are denoted bys(w), wherew∈Wn. Hence for the cok- ernel of the differentialW = coker(d) we obtain the shifted objectV = coker(d)[1].

We denote bys(x)∈coker(d)[1] the element corresponding to x∈C via the pro- jectionCcoker(d). Thendinduces a map of gradedk-vector spaces

:V = coker(d)[1]→A= ker(d)

carryings(x) todx. The multiplication inCinduces a structure ofk-algebra onA.

Moreover it induces a structure ofA-bimodule onV by setting a∗s(x) = (−1)|a|s(ax)

s(x)∗b=s(xb)

In fact, for y =dz and a∈A we have (1)|a|ay=d(az) and therefore the multi- plication is well defined. We now check that:V →Ais a crossed module. Given a∈Aands(x)∈V we have

∂(a∗s(x)) = (−1)|a|∂(s(ax)) = (−1)|a|d(ax) =ad(x) =a∂(s(x))

In the same way one can check that∂(s(x)∗a) =∂(s(x))a. Given nows(x), s(y)∈V we have

∂(s(x))∗s(y) = (dx)∗s(y) = (−1)|x|+1s((dx)y) =s(x(dy)) =s(x)∗(dy) = s(x)∗∂(s(y)).

Thus the DG-algebraCinduces a crossed module (V, A, ∂), the cokernel of which is the algebraH(C) and the kernel is theH(C)-bimodule whose underlyingk-vector space isH(C)[1] and where the left multiplication is twisted, i.e.x∗y= (1)|x|xy and the right multiplication is the ordinary one. We denote this H(C)-bimodule byH(C)[1]. The crossed module : V Arepresents by 3.2 an element hCi ∈ HH3(H(C), H(C)[1]) which is termed the characteristic classof the cochain al- gebraC(compare with [6]).

Construction 3.6. The characteristic class of a chain algebra.For a chain algebra C={Ci, i>0} concentrated in non-negative degrees with differentiald:C →C of degree 1 satisfying d(xy) = (dx)y+ (1)|x|xd(y) and d2 = 0 we proceed in the same way as in 3.5. We consider the graded vector spacesV = coker(d)>1[1]

andA= ker(d). Here coker(d)>1[1] denotes the shifted graded vector space from coker(d)>1similarly as above. The differentialdinduces as before a crossed module

:V = coker(d)>1[1]→A= ker(d)

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the cokernel of which is the algebra H(C) and the kernel is the H(C)-bimodule whose underlying vector space is H>1(C)[1] and where the left multiplication is twisted and the right multiplication is the ordinary one. We denote this bi- module by H>1(C)[1]. The crossed module represents by 3.2 an element hCi ∈ HH3(H(C), H>1(C)[1]) which is termed the characteristic class of the chain al- gebraC.

Defination and Remark 3.7. Massey triple products of crossed modules.Let E= ( 0 //M i //V //A π //B //0 )

be a crossed module overB with kernelM. Givena, b, c∈B withab=bc= 0, we define theMassey triple productha, b, ci ∈M/(aM+M c) as follows. Lets:B →A be a k-linear section ofπ, i.e. πs= 1 and letq : Im(∂)→V be a k-linear section of∂. Sinceab= 0 then s(a)s(b)∈ker(π) and we can take q(s(a)s(b))∈V. In the same way, since bc = 0, we consider q(s(b)s(c)) V. Now consider the element {a, b, c}=s(a)q(s(b)s(c))−q(s(a)s(b))s(c)∈V. Since∂({a, b, c}) = 0 this element is in fact inM and we define

ha, b, ci={a, b, c} ∈M/(aM +M c),

where {a, b, c} denotes the class of {a, b, c} in the quotient. One can check that ha, b, cidoes not depend on the choice ofsandq. Moreover it depends only on the class of E in π0Cross(B, M) and the elements a, b and c. In fact ha, b, ci can be computed fromHH3(B, M) by taking

ha, b, ci=θE(a, b, c)

where θE is any cocycle representing the class of ψ(E) HH3(B, M). Note that for any DG-algebraC and any Massey triple x, y, z∈H(C) the Massey product defined here in terms of in 3.5 coincides with the classical one.

Remark 3.8. Connection with Baues–Wirsching cohomology of categories. Given a monoidCone can considerCas a categoryCwith one object. LetM :C × Cop Vectk be a functor, where Vectk denotes the category of k-vector spaces. Then the C-bimodule M induces a natural system on C also denoted by M (see [5]) and we have the Baues–Wirsching cohomology groups of C with coefficients in M denoted by Hn(C, M). On the other hand one can consider the k-algebra k[C]

and the k[C]-bimodule iM induced by the C-bimodule M. It is easy to see that HHn(k[C], iM) =Hn(C, M). Forn= 3 this isomorphism induces a bijection

π0Track(C, M) =π0Cross(k[C], iM).

Here Track(C, M) denotes the category of track extensions over C with kernel M (cf. [3],[4]).

In the last section of this paper we define theŒ-product of crossed modules in order to compute the characteristic class of a tensor product of differential algebras.

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4. crossed n-fold extensions and main result

We introduce in this section the groups Opextn(B, M) of crossed n-fold exten- sionsof ak-algebra B by aB-bimoduleM,n>2. These extensions are analogous to crossed extensions of groups (cf. [7]). Our result 4.3 shows that the connected classes of such extensions represent cohomology classes in HHn+1(B, M).

Definition 4.1. LetB be ak-algebra andM aB-bimodule. For n>2, acrossed n-fold extension ofB by M is an exact sequence

0 //M f//Mn1

n1//. . . 2//M1

1 //A π //B //0 ofk-vector spaces with the following properties.

1. (M1, A, ∂1) is a crossed module with cokernelB,

2. Mi is aB-bimodule for 1< i6n−1 andi andf are maps ofB-bimodules.

Note that the map1is a map ofA-bimodules since (M1, A, ∂1) is a crossed module and it makes sense to require2to be a map ofB-bimodules since the kernel of∂1

is naturally aB-bimodule.

Definition 4.2. Given a crossed n-fold extension ofB byM E= ( 0 //M f//Mn1

n1//. . . 2//M1

1 //A π//B //0 ) and a crossedn-fold extension ofB byM0

E0 = ( 0 //M0 f

0//Mn01

0n1//. . . 20//M10

10 //A0 π0 //B //0 )

a map fromE to E0 is a sequence (α, δn1, . . . , δ1, β) such that α: M M0 and δi : Mi Mi0 are morphisms of B-bimodules for i > 2, (δ1, β) : (M1, A, ∂1) (M10, A0, ∂01) is a map of crossed modules which induces the identity on B and the whole diagram commutes.

LetEn(B, M) be the following category. The objects are the crossed n-fold ex- tensions ofB byM and the morphisms are the maps between such extensions that induce the identity on M. We denote Opextn(B, M) = π0En(B, M). Of course Opext2(B, M) coincides withπ0Cross(B, M).

We will exhibit a natural structure of Abelian group on Opextn(B, M) and prove the main result of this section.

Theorem 4.3. There exists an isomorphism of Abelian groups Opextn(B, M) =HHn+1(B, M), n>2.

Definition 4.4. Forn>3 we define the element 0 Opextn(B, M) as the class of the extension

0 //M M //0 //. . . //0 //B B //0.

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Remark 4.5. If B is a projective algebra or M is injective as a B-bimodule, then Opextn(B, M) = 0. In general, if

E= ( 0 //M f//Mn1

n1//. . . 2//M1

1 //A π//B //0 )

and there is a mapg:Mn1→M such thatgf = 1M, thenE= 0 in Opextn(B, M), n>3.

Proposition 4.6. Given E ∈ Opextn(B, M) and a map α : M M0 of B- bimodules, there exists an extension αE ∈ Opextn(B, M0) and a morphism of the form(α, δn1, . . . , β)fromE toαE. Moreover,αE is unique in Opextn(B, M0)with this property.

Proof. Let E = ( 0 //M f//Mn1

n1//. . . 2//M1

1 //A π//B //0 ). Consider the following pushout ofB-bimodules

M //

α

 P ush Mn1

i ––

M0 //

0

,,

Mn1

##Mn2

Take αE = ( 0 //M0 //Mn1 //. . . . //M1

1 //A //B //0 ) in Opextn(B, M0) and the morphism (α, i,1, . . . ,1) :E →αE.

Given E0 Opextn(B, M0) and a morphism of the form (α, δn1, . . . , β) :E → E0, by properties of the pushout we find a map (1, j, δn2, . . . , β) : αE → E0 and thereforeαE =E0Opextn(B, M0).

Defination and Remark 4.7. By 4.6, a morphism ofB-bimodulesα:M →M0 induces a well defined function

α: Opextn(B, M)Opextn(B, M0) byα(E) =αE.

Lemma 4.8. If E= (0 //M f //Mn1 //. . .)∈Opextn(B, M), thenfE= 0∈Opextn(B, Mn1).

Proof. Consider the morphism of extensions

0 //M f //

f

Mn1

g //

(1,g)



Mn2 //

Identity

. . .

0 //Mn1

(1,0)//Mn1⊕Mn2

p2 //Mn2 //. . .

By definition the row in the bottom corresponds tofE, therefore by 4.5fE= 0.

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Definition 4.9. Given two crossed n-fold extensions ofB E= ( 0 //M f//Mn1

n1//. . . 2//M1

1 //A π//B //0 ) and

E0 = ( 0 //M0 f

0//Mn01

0n1//. . . 20//M10

10 //A0 π0 //B //0 )

thesum of E andE0 overB is denoted byE ⊕BE0 and corresponds to the following crossedn-fold extension

0 //M⊕M0 //Mn1⊕Mn01 //. . . //

//M1⊕M01(∂1,∂

10)//BA0 q //B //0.

Here the algebraBA0is defined as follows. The elements of it are the pairs (a, a0) witha∈A anda0∈A0 such thatπa=π0a0, addition and multiplication is defined coordinatewise. The mapq:BA0 →B is the mapq(a, a0) =π(a) =π0(a0). The action ofBA0 on M1⊕M10 is also defined coordinatewise. It is easy to check that this defines a crossed module (M1⊕M10, A×BA0,(∂1, ∂10)).

Definition 4.10. GivenE,E0 Opextn(B, M) withn>3, we define theBaer Sum E+E0Opextn(B, M) as follows.

E+E0=M(E ⊕BE0) whereM :M ⊕M →M is the codiagonal.

Theorem 4.11. Forn>3the set Opextn(B, M)equipped with the Baer sum is an abelian group with the zero element defined as in 4.4. The inverse of an extension

E = ( 0 //M f//Mn1

g //. . . . //M1

1 //A //B //0 ) is the extension

(1M)E= ( 0 //M f//Mn1

g //. . . . //M1

1 //A //B //0 )

Moreover, the mapsα:Opextn(B, M)→Opextn(B, M0)are morphisms of groups.

Proof. Follows the classical one (cf. [10]). One has to check that 1. (α+β)E=αE+βE

2. α(E+E0) =αE+αE0

The Baer sum in Opext2(B, M) is defined in a slightly different way. Recall that the elements in Opext2(B, M) are classes of crossed modules with cokernel B and kernelM. The class of 0Opext2(B, M) is the class of the extension

0 //M M 0 //B B //0

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Now given

E= ( 0 //M i //V //A π //B //0 ) and

E0= ( 0 //M i0 //V0 0 //A0 π0 //B //0 ), the Baer sumE+E0 is the class of the extension

E+E0 = ( 0 //M j //V +V0 ˜ //BA0 q //B //0 ) where q:BA0 →B is defined as in 4.9 andV +V0 is the pushout ofk-vector spaces

M⊕M

P ush



ii0 //V ⊕V0

r (∂,∂0)˜˜

M j //

0 ,,

V +V0

˜

%%

BA0 .

The structure of (A×BA0)-bimodule onV+V0is induced by the structure onV⊕V0 (coordinatewise) via the quotient map r : V ⊕V0 V +V0 by (a, a0)r(v, v0) = r(av, a0v0) and r(v, v0)(a, a0) =r(va, v0a0). Note that the multiplication is well de- fined since (a, a0) BA0 and therefore π(a) = π0(a0). It is easy to check that

˜:V +V0→A×BA0 is a crossed module.

Remark 4.12. With this structure of abelian group in Opext2(B, M) the bijection ψ: Opext2(B, M)→HH3(B, M)

of 3.2 is an isomorphism of groups.

Definition 4.13. Given a short exact sequence of B-bimodules 0 //M α //M0 β //M00 //0 we define a connecting homomorphism (n>2)

δ: Opextn(B, M00)Opextn+1(B, M)

as follows. Given an extensionE = ( 0 //M00 f //Mn1 //. . .), takeδ(E) to be the class of the extension ( 0 //M α //M0 f β //Mn1 //. . .).

Note thatδ is a well defined homomorphism for alln>2.

Theorem 4.14. A short exact sequence

0 //M α //M0 β //M00 //0

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of B-bimodules induces a long exact sequence of abelian groups(n>2) Opextn(B, M) α //Opextn(B, M0) β //Opextn(B, M00) δ //

Opextn+1(B, M) //. . .

Proof. To prove exactness at Opextn(B, M0) with n > 3 note first that βα = (βα) = 0. Now let

E= ( 0 //M0 f//Mn−1 g //Mn−2 //. . . //M1 //A //B //0 )Opextn(B, M0) andβE = 0. We suppose first that there is a mapβE →0, i.e.

βE= ( 0 //M00 h//Mn1

g0//Mn2 //. . . //M1

//A //B //0 ) and there is a mapr:Mn1→M00 such thatrh= 1. The following diagram shows thatE =αE.

0 //M f α//

α



kerrt g //

i

Mn2 //

Id

. . .

0 //M0 f //

β



Mn1

t

g //Mn2 //

Id

. . .

0 //M00 h //Mn1

g0 //Mn2 //. . .

Suppose now that there is a map 0→βE. In this case it is easy to see thatE= 0. The general case follows combining these both cases. Suppose for example there exists an extension ˜E = ( 0 //M00 l //M˜n1 //M˜n2 //. . .)Opextn(B, M00) and maps ˜E →βEand ˜E →0. In this case we construct the extensionEwithαE=E as follows. There exists a retractionr: ˜Mn1→M00such thatrl= 1. Consider the pushout ofB-bimodules

M˜n1 P ush r

 //Mn1

r

M00 //M00

and takeE = ( 0 //M f α//Kerrt g //Mn2 //. . .).

Forn= 2 exactness at Opext2(B, M0) follows from 3.2.

To prove exactness at Opextn+1(B, M) for n >2 note first that δ(E) has the form

δ(E) = ( 0 //M α//M0 f β//Mn1 //. . . //M1

//A //B //0 )

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and thereforeαδ(E) = 0 by 4.8. Now let E= ( 0 //M f//Mn1

g //Mn2 //. . . //M1

//A //B //0 )Opextn(B, M) withαE = 0. Applying the same argument as above, we can suppose that there is a mapαE →0, i.e.

αE= ( 0 //M0 l//Mn1

g0//Mn2 //. . . //M1

//A //B //0 ) and there is a mapt:Mn1→M0 such thattl= 1.

Consider the following diagram 0 //M f //Mn1

g //

tr

 P ush Mn2



//Mn3 //

Id

. . .

0 //M α //M0 j //Mn2 //Mn3 //. . .

The map j can be factored j = for some h : M00 Mn2 and therefore E=δ(E0) with

E0 = ( 0 //M00 h //Mn2 //Mn3 //. . .).

To prove exactness at Opextn(B, M00) forn>2 consider the following diagrams.

The first row of the first diagram corresponds toE ∈Opextn(B, M0) and the second row corresponds toβE ∈Opextn(B, M00).

0 //M0

β



f //Mn1 //



Mn2 //

Id

. . .

0 //M00 h //Mn1 //Mn2 //. . . 0 //M (1M,0)//M ⊕M0 0+f //

α+1M0



Mn1 //



Mn2 //

Id

. . .

0 //M α //M0 //Mn1 //Mn2 //. . .

Proof of 4.3. The result is true for n= 2 by 3.2. For n>3 we use theorem 4.14.

Since the category ofB-bimodules has enough injectives, we can find a short exact sequence

0 //M α //M0 β //M00 //0 withM0 injective. By 4.14 and 4.5 we have

Opextn+1(B, M) = Opextn(B, M00).

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On the other hand we have HHn+2(B, M) = HHn+1(B, M00) by the long exact sequence of cohomology. Hence the result follows by induction from 3.2.

Remark 4.15. Theorem 4.3 is the analogue of a corresponding result for the co- homology of groups. In fact, using crossed modules in the category of groups as introduced by J.H.C.Whitehead [12] one can consider crossed extensions of groups which represent elements in the cohomology of groups (cf. Huebschmann [7]).

5. The characteristic class of a tensor product of differential algebras

In this section we define the Œ-product of crossed modules. The definition of

1ζ2 is used below for the computation of the characteristic class of a tensor product of differential algebras (see 3.5 above).

Definition 5.1. Let1:V1→A1 and2:V2→A2 be crossed modules. Consider the diagram of (graded) vector spaces

V1⊗V2

d2 //(V1⊗A2)(A1⊗V2) d1 //(A1⊗A2) (*) whered1 andd2are defined as follows.

d2(v1⊗v2) =1v1⊗v2−v1⊗∂2v2

d1(v1⊗a2) =1v1⊗a2

d1(a1⊗v2) =a1⊗∂2v2

Sinced1d2= 0 we obtain a map induced by d1:

:W = (V1⊗A2)(A1⊗V2)

Im(d2) →A1⊗A2

Note that the diagram (*) is in fact a diagram of (A1⊗A2)-bimodules. Here the (A1⊗A2)-bimodule structure onV1⊗V2 is given by

(a1⊗a2)(v1⊗v2) = (1)|a2||v1|(a1v1⊗a2v2) (v1⊗v2)(a1⊗a2) = (1)|v2||a1|(v1a1⊗v2a2)

Thus the map:W →A1⊗A2is a map of (A1⊗A2)-bimodules. We show now that

is a crossed module. Given w, w0 ∈W we have to check that ∂(w)w0 =w∂(w0).

Forv1, v01∈V1, a2, a02∈A2 we have

∂(v1⊗a2)(v01⊗a02) = (∂1v1⊗a2)(v10 ⊗a02)

= (1)|a2||v10|((∂1v1)v01⊗a2a02) = (v1⊗a2)∂(v01⊗a02)

We have similar equation for∂(a1⊗v2)(a01⊗v20). Now for (v1⊗a2) and (a1⊗v2) we have

∂(v1⊗a2)(a1⊗v2) = (∂1v1⊗a2)(a1⊗v2) = (1)|a2||a1|(∂1(v1a1)⊗a2v2)

= (1)|a2||a1|(v1a1⊗∂2(a2v2)) = (v1⊗a2)∂(a1⊗v2)

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