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THE GALOIS ALGEBRAS AND THE AZUMAYA GALOIS EXTENSIONS
GEORGE SZETO and LIANYONG XUE Received 26 October 2001
LetB be a Galois algebra over a commutative ringR with Galois groupG,Cthe center ofB,K= {g∈G|g(c)=cfor allc∈C},Jg= {b∈B|bx=g(x)bfor allx∈B}for eachg∈K, andBK=(⊕
g∈KJg). ThenBKis a central weakly Galois algebra with Galois group induced byK. Moreover, an Azumaya Galois extensionBwith Galois groupKis characterized by usingBK.
2000 Mathematics Subject Classification: 16S35, 16W20.
1. Introduction. LetBbe a Galois algebra over a commutative ringR with Galois group Gand C the center ofB. The class of Galois algebras has been investigated by DeMeyer [2], Kanzaki [6], Harada [4,5], and the authors [7]. In [2], it was shown that if R contains no idempotents but 0 and 1, thenB is a central Galois algebra with Galois groupK andC is a commutative Galois algebra with Galois groupG/K whereK= {g∈G|g(c)=cfor allc∈C}[2, Theorem 1]. This fact was extended to the Galois algebraBoverRcontaining more than two idempotents [6, Proposition 3], and generalized to any Galois algebraB [7, Theorem 3.8] by using the Boolean algebraBagenerated by{0,eg|g∈Gfor a central idempotenteg}whereBJg=Beg
andJg= {b∈B|bx=g(x)bfor allx∈B}for eachg∈G [6]. The purpose of this paper is to show that there exists a subalgebraBK ofB such that BK is a central weakly Galois algebra with Galois groupK|BK induced byK where a weakly Galois algebra was defined in [8] and thatBKBKis an Azumaya weakly Galois extension with Galois groupK|BKBK where an Azumaya Galois extension was studied in [1]. Thus some characterizations of an Azumaya Galois extensionBofBKwith Galois groupK are obtained, and the results as given in [2,6] are generalized.
2. Definitions and notations. Throughout, letB be a Galois algebra over a com- mutative ring R with Galois groupG, C the center of B, and K= {g∈G |g(c)= cfor allc∈C}. We keep the definitions of a Galois extension, a Galois algebra, a cen- tral Galois algebra, a separable extension, and an Azumaya algebra as defined in [7].
An Azumaya Galois extensionAwith Galois group Gis a Galois extensionAofAG which is aCG-Azumaya algebra whereCthe center ofA[1]. A weakly Galois exten- sionAwith Galois groupGis a finitely generated projective left moduleAoverAG such thatAlGHomAG(A,A)whereAl= {al,a left multiplication map bya∈A}[8].
We call thatAis a weakly Galois algebra with Galois groupGifAis a weakly Galois extension with Galois groupGsuch thatAG is contained in the center ofAand that
Ais a central weakly Galois algebra with Galois groupG ifAis a weakly Galois ex- tension with Galois group G such thatAG is the center of A. An Azumaya weakly Galois extensionAwith Galois groupGis a weakly Galois extensionAofAGwhich is aCG-Azumaya algebra whereCthe center ofA.
3. A weakly Galois algebra. In this section, letBbe a Galois algebra overRwith Galois groupG,Cthe center ofB,BG= {b∈B|g(b)=bfor allg∈G}, andK= {g∈ G|g(c)=cfor allc∈C}. Then, B= ⊕
g∈GJg =(⊕
g∈KJg)⊕(⊕
g∈KJg) where Jg= {b∈B|bx=g(x)bfor allx∈B}[6, Theorem 1] . We denote⊕
g∈KJg byBK and the center ofBKbyZ. Clearly,Kis a normal subgroup ofG. We show thatBKis an Azumaya algebra overZand a central weakly Galois algebra with Galois groupK|BK.
Theorem3.1. The algebraBKis an Azumaya algebra overZ.
Proof. By the definition ofBK,BK= ⊕
g∈KJg, soC(=J1)⊂BK. SinceBis a Galois algebra with Galois groupGandK= {g∈G|g(c)=cfor allc∈C}, the order ofKis a unit inCby [6, Proposition 5]. Moreover,Kis anC-automorphism group ofB, soBK
is aC-separable algebra by [5, Proposition 5]. ThusBKis an Azumaya algebra overZ.
In order to show thatBKis a central weakly Galois algebra with Galois groupK|BK, we need two lemmas.
Lemma3.2. LetL= {g∈K|g(a)=afor alla∈BK}. Then,Lis a normal subgroup ofKsuch thatK(=K/L)is an automorphism group ofBKinduced byK(i.e.,K|BKK).
Proof. Clearly,Lis a normal subgroup ofK, so for anyh∈K, h
BK
= ⊕
g∈K
h Jg
= ⊕
g∈K
Jhgh−1= ⊕
g∈hKh−1
Jg= ⊕
g∈K
Jg=BK. (3.1)
ThusK|BKK.
Lemma3.3. The fixed ring ofBKunderK,(BK)K=Z.
Proof. Letxbe any element in(BK)Kandbany element inBK. Thenb=
g∈Kbg wherebg∈Jg for eachg∈K. Hencebx=
g∈Kbgx=
g∈Kg(x)bg=
g∈Kxbg= x
g∈Kbg =xb. Thereforex ∈Z. Thus (BK)K ⊂Z. Conversely, for any z∈Z and g∈K, we have thatzx=xz=g(z)xfor anyx∈Jg, so(g(z)−z)x=0 for anyx∈Jg. Hence(g(z)−z)Jg= {0}. Noting thatBJg=JgB=B, we have that(g(z)−z)B= {0}, sog(z)=zfor anyz∈Zandg∈K. ThusZ⊂(BK)K. Therefore(BK)K=Z.
Theorem3.4. The algebraBKis a central weakly Galois algebra with Galois group K|BKK.
Proof. ByLemma 3.3, it suffices to show that (1)BK is a finitely generated pro- jective module overZ, and (2)(BK)lKHomZ(BK,BK). Part (1) is a consequence of Theorem 3.1. For part (2), sinceBK is an Azumaya algebra overZ byTheorem 3.1 again, BK⊗ZBoK HomZ(BK,BK) [3, Theorem 3.4, page 52] by extending the map (a⊗b)(x)=axb linearly for a⊗b ∈BK⊗ZBoK and eachx ∈BK where BKo is the
opposite algebra ofBK. By denoting the left multiplication map witha∈BKbyaland the right multiplication map withb∈BKbybr,(a⊗b)(x)=(albr)(x)=axb. Since BK= ⊕
g∈KJg,BK⊗ZBKo=
g∈K(BK)l(Jg)r. Observing that(Jg)r =(Jg)lg−1 where g=g|BK∈K|BKK, we have thatBK⊗ZBKo=
g∈K(BK)l(Jg)r=
g∈K(BK)l(Jg)lg−1=
g∈K(BKJg)lg−1. Moreover, sinceBJg=B for eachg∈KandB= ⊕
h∈GJh=BK⊕ (⊕
h∈KJh),BK⊕(⊕
h∈KJh)=B=BJg=BKJg⊕(⊕
h∈KJhJg)such thatBKJg⊂BK
and⊕
h∈KJhJg⊂ ⊕
h∈KJh. HenceBKJg=BKfor eachg∈K. ThereforeBK⊗ZBKo=
g∈K(BKJg)lg−1=
g∈K(BK)lg−1=(BK)lK. Thus(BK)lKHomZ(BK,BK). This com- pletes the proof of part (2). ThusBK is a central weakly Galois algebra with Galois groupK|BKK.
Recall that an algebraAis called an Azumaya weakly Galois extension ofAKwith Galois groupKifAis a weakly Galois extension ofAKwhich is aCK-Azumaya algebra whereC is the center ofA. Next, we show thatBKBK is an Azumaya weakly Galois extension with Galois groupK|BKBK K. We begin with the following two lemmas aboutBK.
Lemma3.5. The fixed ring ofBunderK,BK=VB(BK).
Proof. For anyb∈BKandx∈Jgfor anyg∈K, we have thatxb=g(b)x=bx, so b∈VB(Jg)for anyg∈K. Thusb∈VB(BK). Conversely, for anyb∈VB(BK)andg∈K, we have thatbx=xb=g(b)x for anyx∈Jg, so(g(b)−b)x=0 for anyx∈Jg. Hence(g(b)−b)Jg= {0}. ButBJg=JgB=Bfor anyg∈K, so(g(b)−b)B= {0}. Thus g(b)=bfor anyg∈K; and sob∈BK. ThereforeBK=VB(BK).
Lemma3.6. The algebraBKis an Azumaya algebra overZwhereZis the center of BK.
Proof. SinceBis a Galois algebra overRwith Galois groupG,B is an Azumaya algebra over its centerC. By the proof ofTheorem 3.1,BKis aC-separable subalgebra ofB, soVB(BK)is aC-separable subalgebra ofBandVB(VB(BK))=BKby the commu- tator theorem for Azumaya algebras [3, Theorem 4.3, page 57]. This implies thatBK andVB(BK)have the same centerZ. ThusVB(BK)is an Azumaya algebra overZ. But, byLemma 3.5,BK=VB(BK), soBKis an Azumaya algebra overZ.
Theorem3.7. LetA=BKBK. ThenAis an Azumaya weakly Galois extension with Galois groupK|AK.
Proof. SinceBK is a central weakly Galois algebra with Galois groupK|BK K by Theorem 3.4, BK is a finitely generated projective module overZ and (BK)lK HomZ(BK,BK). ByLemma 3.6,BKis an Azumaya algebra overZ, soA(BK⊗ZBK)is a finitely generated projective module overBK(=AK). Moreover, sinceBK=VB(BK)by Lemma 3.5and(BK)lKHomZ(BK,BK),
AlK=BKBK
lK=BK
lKBK
rBKK⊗ZBKHomZBK,BK
⊗ZBK HomBK
BK⊗ZBK,BK⊗ZBK
HomBK
BKBK,BKBK
=HomAK(A,A).
(3.2)
ThusAis a weakly Galois extension ofAKwith Galois groupK|AK. Next, we claim thatAhas centerZ andAK is an Azumaya algebra over ZK. In fact,BK andBK are Azumaya algebras overZbyTheorem 3.1andLemma 3.6, respectively, soA(=BKBK) has centerZandAK=(BKBK)K=BK. Noting thatBK is an Azumaya algebra overZ, we conclude thatAK is an Azumaya algebra overZK. ThusAis an Azumaya weakly Galois extension with Galois groupK|AK.
4. An Azumaya Galois extension. In this section, we give several characterizations of an Azumaya Galois extensionB by usingBK. This generalizes the results in [2,6].
TheZ-module{b∈BK|bx=g(x)bfor allx∈BK} is denoted byJg(BK) forg∈K whereK(=K/L)is defined inLemma 3.2.
Lemma4.1. The algebraBKis a central Galois algebra with Galois groupK|BKK if and only ifJg(BK)= ⊕
l∈LJglfor eachg∈K.
Proof. LetBK be a central Galois algebra with Galois groupK|BKK. ThenBK=
⊕
g∈KJg(BK) [6, Theorem 1]. Next it is easy to check that ⊕
l∈LJgl ⊂ Jg(BK). But BK = ⊕
g∈KJg, so⊕
g∈KJg= ⊕
g∈KJg(BK) where⊕
l∈LJgl ⊂Jg(BK). Thus Jg(BK)=
⊕
l∈LJgl for each g ∈ K. Conversely, since J(BgK) = ⊕
l∈LJgl for each g ∈ K, BK = ⊕
g∈KJg = ⊕
g∈KJg(BK). Moreover, by Lemma 3.3, (BK)K = Z, so K is a Z-automorphism group ofBK. HenceJg(BK)Jg(B−1K)=Zfor eachg∈K. ThusBKis a cen- tral Galois algebra with Galois groupK|BKKbecauseBKis an AzumayaZ-algebra byTheorem 3.1(see [4, Theorem 1]).
Next, we characterize an Azumaya Galois extensionBwith Galois groupK.
Theorem4.2. The following statements are equivalent:
(1) Bis an Azumaya Galois extension with Galois groupK;
(2) Z=C;
(3) B=BKBK;
(4) BKis a central Galois algebra overCwith Galois groupK|BKK.
Proof. (1)⇒(2). SinceBis an Azumaya Galois extension with Galois groupK,BK is aCK-Azumaya algebra. But, byLemma 3.6,BK is an Azumaya algebra overZ, so Z=CK. HenceC⊂Z=CK⊂C. ThusZ=C.
(2)⇒(3). Suppose thatZ=C. Then, byTheorem 3.1,BKis an Azumaya algebra over C. Hence by the commutator theorem for Azumaya algebras,B=BKVB(BK)[3, Theo- rem 4.3, page 57]. But, byLemma 3.6,BK=VB(BK), soB=BKBK.
(3)⇒(4). By hypothesis,B=BKBK, soL= {1}whereLis given inLemma 3.2. By the proofs ofTheorem 3.1andLemma 3.6,BKandBKareC-separable subalgebras of the AzumayaC-algebraBsuch thatB=BKBK, soBKandBKare Azumaya algebras overC [3, Theorem 4.4, page 58]. ThusCis the center ofBK. Next, we claim thatJg=Jg(BK)for eachg∈K. In fact, it is clear thatJg⊂Jg(BK). Conversely, for eacha∈Jg(BK)andx∈B such thatx=yzfor somey∈BKandz∈BK, noting thatBK=VB(BK), we have that ax=ayz=g(y)az=g(y)za=g(yz)a=g(x)a. ThusJ(BgK)⊂Jg. This proves that Jg=J(BgK)(=Jg(BK)sinceL= {1})for eachg∈K. Hence,BKis a central Galois algebra overCwith Galois groupK|BKKbyLemma 4.1.
(4)⇒(1). SinceBis a Galois algebra with Galois groupG,Bis a Galois extension with Galois groupK. By hypothesis,BKis a central Galois algebra overCwith Galois group K|BKK, so the center ofBKisC, that is,Z=C. HenceBKis an Azumaya algebra over C(=CK)byLemma 3.6. ThusBis an Azumaya Galois extension with Galois groupK.
Theorem 4.2generalizes the following result of Kanzaki [6, Proposition 3].
Corollary4.3. IfJg= {0}for eachg∈K, thenBis a central Galois algebra with Galois groupKandCis a Galois algebra with Galois groupG/K.
Proof. This is the case inTheorem 4.2thatB=BKBK=BKwhereBK=C.
We conclude the present paper with two examples, one to illustrate the result in Theorem 4.2, and another to show thatZ≠C.
Example4.4. LetA=R[i,j,k], the real quaternion algebra over the field of real numbersR,B=(A⊗RA)⊕A⊕A⊕A⊕A, andGthe group generated by the elements in {g1,ki,kj,kk,hi,hj,hk}whereg1is the identity ofGand for all(a⊗b,a1,a2,a3,a4)∈ B,
kia⊗b,a1,a2,a3,a4
=iai−1⊗b,ia1i−1,ia2i−1,ia3i−1,ia4i−1, kj
a⊗b,a1,a2,a3,a4
=
jaj−1⊗b,ja1j−1,ja2j−1,ja3j−1,ja4j−1 , kk
a⊗b,a1,a2,a3,a4
=
kak−1⊗b,ka1k−1,ka2k−1,ka3k−1,ka4k−1 , hi
a⊗b,a1,a2,a3,a4
=
a⊗ibi−1,a2,a1,a4,a3
,
hja⊗b,a1,a2,a3,a4
=a⊗jbj−1,a3,a4,a1,a2, hka⊗b,a1,a2,a3,a4
=a⊗kbk−1,a4,a3,a2,a1.
(4.1)
Then,
(1) we can check that B is a Galois algebra overBG with Galois group G where BG= {(r1⊗r2,r ,r ,r ,r )|r1,r2, r∈R} ⊂C, andC=(R⊗R)⊕R⊕R⊕R⊕R, the center ofB;
(2) K= {g∈G|g(c)=cfor allc∈C} = {g1,ki,kj,kk};
(3) J1=C, Jki =(Ri⊗1)⊕Ri⊕Ri⊕Ri⊕Ri, Jkj =(Rj⊗1)⊕Rj⊕Rj⊕Ri⊕Rj, Jkk=(Rk⊗1)⊕Rk⊕Rk⊕Ri⊕Rk, soBK=(A⊗RR)⊕A⊕A⊕A⊕A. HenceBK has centerC, that isZ=C, andBKis a central Galois algebra overCwith Galois groupK|BKK;
(4) BK=(R⊗A)⊕R⊕R⊕R⊕R and B=BKBK, that is,B is an Azumaya Galois extension with Galois groupK.
Example4.5. LetA=R[i,j,k], the real quaternion algebra over the field of real numbersR,B=A⊕A⊕A,G= {1,gi,gj,gk}, and for all(a1,a2,a3)∈B,
gi
a1,a2,a3
=
ia1i−1,ia2i−1,ia3i−1 , gj
a1,a2,a3
=
ja1j−1,ja3j−1,ja2j−1 , gka1,a2,a3
=ka1k−1,ka3k−1,ka2k−1.
(4.2)
Then,
(1) Bis a Galois algebra overBG whereBG= {(r1,r ,r )|r1, r∈R} ⊂C, andC= R⊕R⊕R, the center ofB. TheG-Galois system is{ai;bi|i=1,2,...,8}where
a1=(1,0,0), a2=(i,0,0), a3=(j,0,0), a4=(k,0,0), a5=(0,1,0), a6=(0,j,0), a7=(0,0,1), a8=(0,0,k);
b1=1
4a1, b2= −1
4a2, b3= −1
4a3, b4= −1 4a4, b5=1
2a5, b6= −1
2a6, b7=1
2a7, b8= −1 2a8,
(4.3)
(2) K= {g∈G|g(c)=cfor allc∈C} = {1,gi}whereJgi=Ri⊕Ri⊕Ri, soBK= R[i]⊕R[i]⊕R[i]which is a commutative ring not equal toC, that is,Z≠C.
Acknowledgments. This work was supported by a Caterpillar Fellowship at Bradley University. The authors would like to thank the Caterpillar Inc. for the support.
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George Szeto: Department of Mathematics, Bradley University, Peoria, IL61625, USA E-mail address:[email protected]
Lianyong Xue: Department of Mathematics, Bradley University, Peoria, IL61625, USA E-mail address:[email protected]