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THE GALOIS ALGEBRAS AND THE AZUMAYA GALOIS EXTENSIONS

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PII. S0161171202110386 http://ijmms.hindawi.com

© Hindawi Publishing Corp.

THE GALOIS ALGEBRAS AND THE AZUMAYA GALOIS EXTENSIONS

GEORGE SZETO and LIANYONG XUE Received 26 October 2001

LetB be a Galois algebra over a commutative ringR with Galois groupG,Cthe center ofB,K= {g∈G|g(c)=cfor allc∈C},Jg= {b∈B|bx=g(x)bfor allx∈B}for eachg∈K, andBK=(⊕

g∈KJg). ThenBKis a central weakly Galois algebra with Galois group induced byK. Moreover, an Azumaya Galois extensionBwith Galois groupKis characterized by usingBK.

2000 Mathematics Subject Classification: 16S35, 16W20.

1. Introduction. LetBbe a Galois algebra over a commutative ringR with Galois group Gand C the center ofB. The class of Galois algebras has been investigated by DeMeyer [2], Kanzaki [6], Harada [4,5], and the authors [7]. In [2], it was shown that if R contains no idempotents but 0 and 1, thenB is a central Galois algebra with Galois groupK andC is a commutative Galois algebra with Galois groupG/K whereK= {g∈G|g(c)=cfor allc∈C}[2, Theorem 1]. This fact was extended to the Galois algebraBoverRcontaining more than two idempotents [6, Proposition 3], and generalized to any Galois algebraB [7, Theorem 3.8] by using the Boolean algebraBagenerated by{0,eg|g∈Gfor a central idempotenteg}whereBJg=Beg

andJg= {b∈B|bx=g(x)bfor allx∈B}for eachg∈G [6]. The purpose of this paper is to show that there exists a subalgebraBK ofB such that BK is a central weakly Galois algebra with Galois groupK|BK induced byK where a weakly Galois algebra was defined in [8] and thatBKBKis an Azumaya weakly Galois extension with Galois groupK|BKBK where an Azumaya Galois extension was studied in [1]. Thus some characterizations of an Azumaya Galois extensionBofBKwith Galois groupK are obtained, and the results as given in [2,6] are generalized.

2. Definitions and notations. Throughout, letB be a Galois algebra over a com- mutative ring R with Galois groupG, C the center of B, and K= {g∈G |g(c)= cfor allc∈C}. We keep the definitions of a Galois extension, a Galois algebra, a cen- tral Galois algebra, a separable extension, and an Azumaya algebra as defined in [7].

An Azumaya Galois extensionAwith Galois group Gis a Galois extensionAofAG which is aCG-Azumaya algebra whereCthe center ofA[1]. A weakly Galois exten- sionAwith Galois groupGis a finitely generated projective left moduleAoverAG such thatAlGHomAG(A,A)whereAl= {al,a left multiplication map bya∈A}[8].

We call thatAis a weakly Galois algebra with Galois groupGifAis a weakly Galois extension with Galois groupGsuch thatAG is contained in the center ofAand that

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Ais a central weakly Galois algebra with Galois groupG ifAis a weakly Galois ex- tension with Galois group G such thatAG is the center of A. An Azumaya weakly Galois extensionAwith Galois groupGis a weakly Galois extensionAofAGwhich is aCG-Azumaya algebra whereCthe center ofA.

3. A weakly Galois algebra. In this section, letBbe a Galois algebra overRwith Galois groupG,Cthe center ofB,BG= {b∈B|g(b)=bfor allg∈G}, andK= {g∈ G|g(c)=cfor allc∈C}. Then, B= ⊕

g∈GJg =(⊕

g∈KJg)⊕(⊕

g∈KJg) where Jg= {b∈B|bx=g(x)bfor allx∈B}[6, Theorem 1] . We denote

g∈KJg byBK and the center ofBKbyZ. Clearly,Kis a normal subgroup ofG. We show thatBKis an Azumaya algebra overZand a central weakly Galois algebra with Galois groupK|BK.

Theorem3.1. The algebraBKis an Azumaya algebra overZ.

Proof. By the definition ofBK,BK= ⊕

g∈KJg, soC(=J1)⊂BK. SinceBis a Galois algebra with Galois groupGandK= {g∈G|g(c)=cfor allc∈C}, the order ofKis a unit inCby [6, Proposition 5]. Moreover,Kis anC-automorphism group ofB, soBK

is aC-separable algebra by [5, Proposition 5]. ThusBKis an Azumaya algebra overZ.

In order to show thatBKis a central weakly Galois algebra with Galois groupK|BK, we need two lemmas.

Lemma3.2. LetL= {g∈K|g(a)=afor alla∈BK}. Then,Lis a normal subgroup ofKsuch thatK(=K/L)is an automorphism group ofBKinduced byK(i.e.,K|BKK).

Proof. Clearly,Lis a normal subgroup ofK, so for anyh∈K, h

BK

= ⊕

g∈K

h Jg

= ⊕

g∈K

Jhgh−1= ⊕

g∈hKh−1

Jg= ⊕

g∈K

Jg=BK. (3.1)

ThusK|BKK.

Lemma3.3. The fixed ring ofBKunderK,(BK)K=Z.

Proof. Letxbe any element in(BK)Kandbany element inBK. Thenb=

g∈Kbg wherebg∈Jg for eachg∈K. Hencebx=

g∈Kbgx=

g∈Kg(x)bg=

g∈Kxbg= x

g∈Kbg =xb. Thereforex ∈Z. Thus (BK)K ⊂Z. Conversely, for any z∈Z and g∈K, we have thatzx=xz=g(z)xfor anyx∈Jg, so(g(z)−z)x=0 for anyx∈Jg. Hence(g(z)−z)Jg= {0}. Noting thatBJg=JgB=B, we have that(g(z)−z)B= {0}, sog(z)=zfor anyz∈Zandg∈K. ThusZ⊂(BK)K. Therefore(BK)K=Z.

Theorem3.4. The algebraBKis a central weakly Galois algebra with Galois group K|BKK.

Proof. ByLemma 3.3, it suffices to show that (1)BK is a finitely generated pro- jective module overZ, and (2)(BK)lKHomZ(BK,BK). Part (1) is a consequence of Theorem 3.1. For part (2), sinceBK is an Azumaya algebra overZ byTheorem 3.1 again, BKZBoK HomZ(BK,BK) [3, Theorem 3.4, page 52] by extending the map (a⊗b)(x)=axb linearly for a⊗b ∈BKZBoK and eachx ∈BK where BKo is the

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opposite algebra ofBK. By denoting the left multiplication map witha∈BKbyaland the right multiplication map withb∈BKbybr,(a⊗b)(x)=(albr)(x)=axb. Since BK= ⊕

g∈KJg,BKZBKo=

g∈K(BK)l(Jg)r. Observing that(Jg)r =(Jg)lg1 where g=g|BK∈K|BKK, we have thatBKZBKo=

g∈K(BK)l(Jg)r=

g∈K(BK)l(Jg)lg1=

g∈K(BKJg)lg1. Moreover, sinceBJg=B for eachg∈KandB= ⊕

h∈GJh=BK (⊕

h∈KJh),BK⊕(⊕

h∈KJh)=B=BJg=BKJg⊕(⊕

h∈KJhJg)such thatBKJg⊂BK

and

h∈KJhJg⊂ ⊕

h∈KJh. HenceBKJg=BKfor eachg∈K. ThereforeBKZBKo=

g∈K(BKJg)lg1=

g∈K(BK)lg1=(BK)lK. Thus(BK)lKHomZ(BK,BK). This com- pletes the proof of part (2). ThusBK is a central weakly Galois algebra with Galois groupK|BKK.

Recall that an algebraAis called an Azumaya weakly Galois extension ofAKwith Galois groupKifAis a weakly Galois extension ofAKwhich is aCK-Azumaya algebra whereC is the center ofA. Next, we show thatBKBK is an Azumaya weakly Galois extension with Galois groupK|BKBK K. We begin with the following two lemmas aboutBK.

Lemma3.5. The fixed ring ofBunderK,BK=VB(BK).

Proof. For anyb∈BKandx∈Jgfor anyg∈K, we have thatxb=g(b)x=bx, so b∈VB(Jg)for anyg∈K. Thusb∈VB(BK). Conversely, for anyb∈VB(BK)andg∈K, we have thatbx=xb=g(b)x for anyx∈Jg, so(g(b)−b)x=0 for anyx∈Jg. Hence(g(b)−b)Jg= {0}. ButBJg=JgB=Bfor anyg∈K, so(g(b)−b)B= {0}. Thus g(b)=bfor anyg∈K; and sob∈BK. ThereforeBK=VB(BK).

Lemma3.6. The algebraBKis an Azumaya algebra overZwhereZis the center of BK.

Proof. SinceBis a Galois algebra overRwith Galois groupG,B is an Azumaya algebra over its centerC. By the proof ofTheorem 3.1,BKis aC-separable subalgebra ofB, soVB(BK)is aC-separable subalgebra ofBandVB(VB(BK))=BKby the commu- tator theorem for Azumaya algebras [3, Theorem 4.3, page 57]. This implies thatBK andVB(BK)have the same centerZ. ThusVB(BK)is an Azumaya algebra overZ. But, byLemma 3.5,BK=VB(BK), soBKis an Azumaya algebra overZ.

Theorem3.7. LetA=BKBK. ThenAis an Azumaya weakly Galois extension with Galois groupK|AK.

Proof. SinceBK is a central weakly Galois algebra with Galois groupK|BK K by Theorem 3.4, BK is a finitely generated projective module overZ and (BK)lK HomZ(BK,BK). ByLemma 3.6,BKis an Azumaya algebra overZ, soA(BKZBK)is a finitely generated projective module overBK(=AK). Moreover, sinceBK=VB(BK)by Lemma 3.5and(BK)lKHomZ(BK,BK),

AlK=BKBK

lK=BK

lKBK

rBKK⊗ZBKHomZBK,BK

ZBK HomBK

BKZBK,BKZBK

HomBK

BKBK,BKBK

=HomAK(A,A).

(3.2)

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ThusAis a weakly Galois extension ofAKwith Galois groupK|AK. Next, we claim thatAhas centerZ andAK is an Azumaya algebra over ZK. In fact,BK andBK are Azumaya algebras overZbyTheorem 3.1andLemma 3.6, respectively, soA(=BKBK) has centerZandAK=(BKBK)K=BK. Noting thatBK is an Azumaya algebra overZ, we conclude thatAK is an Azumaya algebra overZK. ThusAis an Azumaya weakly Galois extension with Galois groupK|AK.

4. An Azumaya Galois extension. In this section, we give several characterizations of an Azumaya Galois extensionB by usingBK. This generalizes the results in [2,6].

TheZ-module{b∈BK|bx=g(x)bfor allx∈BK} is denoted byJg(BK) forg∈K whereK(=K/L)is defined inLemma 3.2.

Lemma4.1. The algebraBKis a central Galois algebra with Galois groupK|BKK if and only ifJg(BK)= ⊕

l∈LJglfor eachg∈K.

Proof. LetBK be a central Galois algebra with Galois groupK|BKK. ThenBK=

g∈KJg(BK) [6, Theorem 1]. Next it is easy to check that

l∈LJgl Jg(BK). But BK = ⊕

g∈KJg, so

g∈KJg= ⊕

g∈KJg(BK) where

l∈LJgl ⊂Jg(BK). Thus Jg(BK)=

l∈LJgl for each g K. Conversely, since J(BgK) = ⊕

l∈LJgl for each g K, BK = ⊕

g∈KJg = ⊕

g∈KJg(BK). Moreover, by Lemma 3.3, (BK)K = Z, so K is a Z-automorphism group ofBK. HenceJg(BK)Jg(B−1K)=Zfor eachg∈K. ThusBKis a cen- tral Galois algebra with Galois groupK|BKKbecauseBKis an AzumayaZ-algebra byTheorem 3.1(see [4, Theorem 1]).

Next, we characterize an Azumaya Galois extensionBwith Galois groupK.

Theorem4.2. The following statements are equivalent:

(1) Bis an Azumaya Galois extension with Galois groupK;

(2) Z=C;

(3) B=BKBK;

(4) BKis a central Galois algebra overCwith Galois groupK|BKK.

Proof. (1)(2). SinceBis an Azumaya Galois extension with Galois groupK,BK is aCK-Azumaya algebra. But, byLemma 3.6,BK is an Azumaya algebra overZ, so Z=CK. HenceC⊂Z=CK⊂C. ThusZ=C.

(2)(3). Suppose thatZ=C. Then, byTheorem 3.1,BKis an Azumaya algebra over C. Hence by the commutator theorem for Azumaya algebras,B=BKVB(BK)[3, Theo- rem 4.3, page 57]. But, byLemma 3.6,BK=VB(BK), soB=BKBK.

(3)(4). By hypothesis,B=BKBK, soL= {1}whereLis given inLemma 3.2. By the proofs ofTheorem 3.1andLemma 3.6,BKandBKareC-separable subalgebras of the AzumayaC-algebraBsuch thatB=BKBK, soBKandBKare Azumaya algebras overC [3, Theorem 4.4, page 58]. ThusCis the center ofBK. Next, we claim thatJg=Jg(BK)for eachg∈K. In fact, it is clear thatJg⊂Jg(BK). Conversely, for eacha∈Jg(BK)andx∈B such thatx=yzfor somey∈BKandz∈BK, noting thatBK=VB(BK), we have that ax=ayz=g(y)az=g(y)za=g(yz)a=g(x)a. ThusJ(BgK)⊂Jg. This proves that Jg=J(BgK)(=Jg(BK)sinceL= {1})for eachg∈K. Hence,BKis a central Galois algebra overCwith Galois groupK|BKKbyLemma 4.1.

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(4)(1). SinceBis a Galois algebra with Galois groupG,Bis a Galois extension with Galois groupK. By hypothesis,BKis a central Galois algebra overCwith Galois group K|BKK, so the center ofBKisC, that is,Z=C. HenceBKis an Azumaya algebra over C(=CK)byLemma 3.6. ThusBis an Azumaya Galois extension with Galois groupK.

Theorem 4.2generalizes the following result of Kanzaki [6, Proposition 3].

Corollary4.3. IfJg= {0}for eachg∈K, thenBis a central Galois algebra with Galois groupKandCis a Galois algebra with Galois groupG/K.

Proof. This is the case inTheorem 4.2thatB=BKBK=BKwhereBK=C.

We conclude the present paper with two examples, one to illustrate the result in Theorem 4.2, and another to show thatZC.

Example4.4. LetA=R[i,j,k], the real quaternion algebra over the field of real numbersR,B=(A⊗RA)⊕A⊕A⊕A⊕A, andGthe group generated by the elements in {g1,ki,kj,kk,hi,hj,hk}whereg1is the identity ofGand for all(a⊗b,a1,a2,a3,a4)∈ B,

kia⊗b,a1,a2,a3,a4

=iai1⊗b,ia1i1,ia2i1,ia3i1,ia4i1, kj

a⊗b,a1,a2,a3,a4

=

jaj1⊗b,ja1j1,ja2j1,ja3j1,ja4j1 , kk

a⊗b,a1,a2,a3,a4

=

kak−1⊗b,ka1k−1,ka2k−1,ka3k−1,ka4k−1 , hi

a⊗b,a1,a2,a3,a4

=

a⊗ibi−1,a2,a1,a4,a3

,

hja⊗b,a1,a2,a3,a4

=a⊗jbj−1,a3,a4,a1,a2, hka⊗b,a1,a2,a3,a4

=a⊗kbk1,a4,a3,a2,a1.

(4.1)

Then,

(1) we can check that B is a Galois algebra overBG with Galois group G where BG= {(r1⊗r2,r ,r ,r ,r )|r1,r2, r∈R} ⊂C, andC=(R⊗R)⊕R⊕R⊕R⊕R, the center ofB;

(2) K= {g∈G|g(c)=cfor allc∈C} = {g1,ki,kj,kk};

(3) J1=C, Jki =(Ri⊗1)Ri⊕Ri⊕Ri⊕Ri, Jkj =(Rj⊗1)Rj⊕Rj⊕Ri⊕Rj, Jkk=(Rk⊗1)Rk⊕Rk⊕Ri⊕Rk, soBK=(A⊗RR)⊕A⊕A⊕A⊕A. HenceBK has centerC, that isZ=C, andBKis a central Galois algebra overCwith Galois groupK|BKK;

(4) BK=(R⊗A)⊕RRRR and B=BKBK, that is,B is an Azumaya Galois extension with Galois groupK.

Example4.5. LetA=R[i,j,k], the real quaternion algebra over the field of real numbersR,B=A⊕A⊕A,G= {1,gi,gj,gk}, and for all(a1,a2,a3)∈B,

gi

a1,a2,a3

=

ia1i1,ia2i1,ia3i1 , gj

a1,a2,a3

=

ja1j−1,ja3j−1,ja2j−1 , gka1,a2,a3

=ka1k−1,ka3k−1,ka2k−1.

(4.2)

(6)

Then,

(1) Bis a Galois algebra overBG whereBG= {(r1,r ,r )|r1, r∈R} ⊂C, andC= R⊕R⊕R, the center ofB. TheG-Galois system is{ai;bi|i=1,2,...,8}where

a1=(1,0,0), a2=(i,0,0), a3=(j,0,0), a4=(k,0,0), a5=(0,1,0), a6=(0,j,0), a7=(0,0,1), a8=(0,0,k);

b1=1

4a1, b2= −1

4a2, b3= −1

4a3, b4= −1 4a4, b5=1

2a5, b6= −1

2a6, b7=1

2a7, b8= −1 2a8,

(4.3)

(2) K= {g∈G|g(c)=cfor allc∈C} = {1,gi}whereJgi=Ri⊕Ri⊕Ri, soBK= R[i]⊕R[i]⊕R[i]which is a commutative ring not equal toC, that is,ZC.

Acknowledgments. This work was supported by a Caterpillar Fellowship at Bradley University. The authors would like to thank the Caterpillar Inc. for the support.

References

[1] R. Alfaro and G. Szeto,On Galois extensions of an Azumaya algebra, Comm. Algebra25 (1997), no. 6, 1873–1882.

[2] F. R. DeMeyer,Galois theory in separable algebras over commutative rings, Illinois J. Math.

10(1966), 287–295.

[3] F. R. DeMeyer and E. Ingraham,Separable Algebras over Commutative Rings, Lecture Notes in Mathematics, vol. 181, Springer-Verlag, Berlin, 1971.

[4] M. Harada,Supplementary results on Galois extension, Osaka J. Math.2(1965), 343–350.

[5] ,Note on Galois extension over the center, Rev. Un. Mat. Argentina24(1968/1969), no. 2, 91–96.

[6] T. Kanzaki,On Galois algebra over a commutative ring, Osaka J. Math.2(1965), 309–317.

[7] G. Szeto and L. Xue,The structure of Galois algebras, J. Algebra237(2001), no. 1, 238–246.

[8] O. E. Villamayor and D. Zelinsky,Galois theory with infinitely many idempotents, Nagoya Math. J.35(1969), 83–98.

George Szeto: Department of Mathematics, Bradley University, Peoria, IL61625, USA E-mail address:[email protected]

Lianyong Xue: Department of Mathematics, Bradley University, Peoria, IL61625, USA E-mail address:[email protected]

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