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PII. S0161171204301031 http://ijmms.hindawi.com

© Hindawi Publishing Corp.

ON CHUNG-TEICHER TYPE STRONG LAW FOR ARRAYS OF VECTOR-VALUED RANDOM VARIABLES

ANNA KUCZMASZEWSKA Received 2 January 2003

We study the equivalence between the weak and strong laws of large numbers for arrays of row-wise independent random elements with values in a Banach spaceᏮ. The conditions under which this equivalence holds are of the Chung or Chung-Teicher types. These con- ditions are expressed in terms of convergence of specific series ando(1)requirements on specific weighted row-wise sums. Moreover, there are not any conditions assumed on the geometry of the underlying Banach space.

2000 Mathematics Subject Classification: 60F15, 60B12.

Let(Ω,,P)be a probability space and letᏮbe a real separable Banach space with norm·. A strongly measurable transformation fromΩtoᏮis said to be aᏮ-valued random variable or a random element. IfEX<∞, then the expected value is defined by the Bochner integral.

Let{Xn, n≥1}be a sequence ofᏮ-valued random variables. Then{Xn, n≥1}is said to obey the strong law of large numbers (SLLN) if there exist sequences of real numbers{an, n≥1}and{bn, n≥1}such that

n j=1

aj Xj−bj

→0 a.s.,n → ∞. (1)

Sufficient conditions for SLLN use very often the geometry of a Banach space, that is, they assume thatᏮis a special-type space, for instanceᏮis of Rademacher typep, 1< p≤2.

The spaceᏮis of Rademacher typepif there exists a positive constantCsuch that

E

n=1

εnxn

p

≤C n=1

xnp (2)

for each(x1,x2,...)∈C(B), wheren, n≥1}is a Bernoulli sequence, that is,εn,n≥1, are i.i.d. random variables andP[εn=1]=P[εn= −1]=1/2,C(B)= {(x1,x2,...)∈B:

n=1εnxnconverges in probability},B=B×B×B×···.

The sufficient conditions for SLLN for random elements taking value in a space of Rademacher typepwere presented by Woyczy´nski [15], Hoffmann-Jørgensen and Pisier [6], Kuczmaszewska and Szynal [8], and Adler et al. [1].

(2)

444 ANNA KUCZMASZEWSKA

The type of Marcinkiewicz-Zygmunt SLLN provides that for 1≤α <2 and a sequence {Xn, n≥1}of i.i.d.Ꮾ-valued random variables,

1 n1

n i=1

Xi−EXi

→0 a.s.,n→ ∞, (3)

if and only ifEX1<∞and the Banach spaceᏮis of a Rademacher typepforα < p≤2 (cf. [15]).

The classical result of Hoffmann-Jørgensen and Pisier [6] proved that the assumption that a Banach spaceᏮis the space of Rademacher typep, 1≤p≤2, is equivalent to the fact that the condition

n=1

EXnp

np <∞ (4)

implies SLLN for a sequence ofᏮ-valued independent random variables{Xn, n≥1} withEXn=0,n≥1.

In view of many statistical applications, it is important to consider the array-type SLLN.

Let{kn, n≥1}be a strictly increasing sequence of positive integers. An array of Ꮾ-valued random variables{Xni, 1≤i≤kn, n≥1}obeys the general array type of SLLN if

kn

i=1

ani

Xni−cni

→0 a.s.,n→ ∞, (5)

where{ani,1≤i≤kn, n≥1}and{cni,1≤i≤kn, n≥1}are suitable arrays of con- stants (weights) andᏮ-valued elements, respectively, and 0 denotes the zero-element inᏮ.

Hu and Taylor [7] considered SLLN for arrays of row-wise independent random vari- ables{Xni, 1≤i≤n, n≥1}.

Row-wise independence means that the random elements within each row are inde- pendent but no independence is assumed between rows.

In [3] Bozorgnia et al. obtained the Chung-type SLLN for arrays of row-wise indepen- dent random elements in a separable Banach space of Rademacher typep, 1< p≤2.

They proved the following result.

Theorem1. Let{Xni,1≤i≤n, n≥1}be an array of row-wise independent random elements in a separable Banach space of Rademacher typep,1< p≤2. Letϕ:RR be a positive, even, and continuous function such that

ϕ

|x|

|x|r , ϕ

|x|

|x|r+p−1 as|x| , (6)

for some integerr≥2.

(3)

Then the conditions

EXni=0, 1≤i≤n, n≥1,

n=1

n i=1

EϕXni ϕ

an <∞, n=1

n

i=1

E Xni

an

p

pk

<∞, (7)

for some positive integerk, imply 1 an

n i=1

Xni →0 a.s.,n → ∞, (8)

where{an, n≥1}is a sequence of positive increasing real numbers such that

n→∞liman= ∞. (9)

This theorem generalizes Hu and Taylor’s result (cf. [7]) on the case ofᏮ-valued random variables{Xni,1≤i≤n, n≥1}taking value in a Banach space of Rademacher typep. Moreover, the assumptions of the functionϕhave some relationships with the geometric condition Rademacher typepof the Banach space.

Some results which consider the problem of equivalence between weak law of large numbers (WLLN) and SLLN for a sequence{Xn, n≥1}of independentᏮ-valued random variables can be found in Kuelbs and Zinn [10], de Acosta [4], Etemadi [5], Mikosch and Norvaiša [11,12], Wang et al. [14], and Kuczmaszewska and Szynal [9].

Now, we recall some definitions and a lemma which will be used in the paper.

Definition2. A double array{ani, i≥1, n≥1}of real numbers is said to be a Toeplitz array if limn→∞ani=0 for eachi≥1 and

i=1|ani| ≤C for alln≥1, where C >0.

In further consideration, we need an extension of the concept of stochastic domina- tion by a random variable to an array ofᏮ-valued random variables.

An array{Xni, i≥1, n≥1}ofᏮ-valued random variables is stochastically dominated by the random elementXif there exists a constantD >0 such that

PXni> x

≤DP

DX> x

(10) for allx≥0,i≥1, andn≥1.

We also need some inequalities which will be very important in our consideration.

The following lemma presents one of them.

Lemma3(cf. Yurinskii [16]). LetX1,X2,...,Xnbe independent-valued random va- riables withEXi<∞,i=1,2,...,n. LetᏲ be aσ-field generated by(X1,X2,...,Xk), k=1,2,...,n, and let0= {Ω,∅}. Then for1≤k≤nandSn=n

i=1Xi, ESnk

−ESnk−1≤Xk+EXk. (11) Theorem4. Let{Xni, 1≤i≤kn, n≥1}be an array of row-wise independent- valued random variables withEXni=0for all1≤i≤kn,n≥1, and for some increasing

(4)

446 ANNA KUCZMASZEWSKA

sequence{kn, n≥1}of positive integers. Letϕni:RR+andψni:RR+be positive, even, and continuous functions, which for constantsαni1,0< βni2,Kni>0, and Mni>0,1≤i≤kn,n≥1, satisfy the following conditions:

x1≤x2ϕnix1

x1αni ≤Kniϕnix2

x2αni , (12) x1≤x2x1βni

ψnix1≤Mni

x2βni

ψnix2. (13)

Suppose that for some array{ani, (1≤i≤kn, n≥1)}of nonzero reals andk≥1/2,

n=1

E

kn

i=1

MniψniXni ψni

a−1ni

k

<∞, (14)

n=1

kn

i=1

PXni≥cni

<∞, (15)

for some array{cni,1≤i≤kn, n≥1}of positive numbers such that

n=1

n i=1

Kni2 ·ϕni

cniniXni ϕ2ni

a−1ni <∞. (16) Then

kn

i=1

aniXni P0, n → ∞, (17)

if and only if

kn

i=1

aniXni →0 a.s.,n→ ∞. (18)

Proof. LetXni =XniI[Xni ≤ |ani1|]andXni=Xni −EXni . Now we introduce the following notation:

Sn=

kn

i=1

aniXni, Sn =

kn

i=1

aniXni . (19)

Note that using this notation, condition (12) on the Borel functionsϕni, and assump- tions (15) and (16), we have

n=1

P

Sn=Sn

= n=1

P

kn

i=1

aniXniIXni>a−1ni > ε

n=1

kn

i=1

PXniIXni>ani1=0

= n=1

kn

i=1

PXni>a−1ni

(5)

n=1

kn

i=1

EIXni>a−1ni·IXni≥cni +

n=1

kn

i=1

EIXni>ani1·IXni< cni

n=1

kn

i=1

PXni≥cni +

n=1

kn

i=1

E



Xniαni a−1niαni

2

IXni>ani1·IXni< cni

n=1

kn

i=1

PXni≥cni +

n=1

kn

i=1

Kni2 ·ϕni

cniniXni ϕni2

a−1ni <∞.

(20) Thus the two sequences{Sn, n≥1}and{Sn, n≥1}are equivalent.

Now we must prove that

ESn →0, n → ∞. (21)

First we will show that

Sn−ESn P0, n → ∞. (22) Using the Markov inequality, the Marcinkiewicz-Zygmunt inequality in its Banach space version (cf. de Acosta [4] or Berger [2]), and assumptions (12) and (14), for anyε >0, we get

PSn−ESn> ε

≤ε2kESn−ESn2k

≤ε2kAkE

kn

i=1

aniXni 2

k

2kAkE

kn

i=1

Xni 2 ani12

k

−2kAkE

kn

i=1

Xni βni

ani1βni· Xni 2−βni ani12−βni

k

≤ε−2kAkE

kn

i=1

MniψniXni ψni

a−1ni

k

×ε−2kAkE

kn

i=1

MniψniXni ψni

a−1ni

k

=o(1).

(23)

Thus we conclude that (22) holds and, together with (17) and the equivalence between {Sn, n≥1}and{Sn, n≥1}, gives (21).

(6)

448 ANNA KUCZMASZEWSKA

Now, we will show thatSn0 a.s., asn→ ∞. By (21) it is enough to prove that Sn−ESn →0 a.s.,n→ ∞. (24) As before, using the Markov inequality, the Marcinkiewicz-Zygmunt inequality, condi- tion (13), and assumption (14), we have

n=1

PSn−ESn> ε

≤ε2k n=1

ESn−ESn2k

≤ε2kAk

n=1

E

kn

i=1

Xni 2 ani12

k

−2kAk

n=1

E

kn

i=1

Xni βni

ani1βni· Xni 2−βni ani12−βni

k

≤ε2kAk

n=1

E

kn

i=1

MniψniXni ψni

ani1

k

<∞.

(25)

Hence, by the Borel-Cantelli lemma, we obtain (24), which, by the equivalence between {Sn, n≥1}and{Sn, n≥1}, completes the proof.

Note that if we put inTheorem 4ϕniandψni, whereϕ:RR+,ψ:RR+

are positive, even, and continuous functions such that ϕ

|x|

|x|α , ψ

|x|

|x|β as|x| , (26) for someα≥1 and 0< β≤2, we get the following result.

Corollary5. Let{Xni,1≤i≤kn, n≥1}be an array of row-wise independent- valued random variables withEXni=0for all1≤i≤kn,n≥1, and for any increasing sequence{kn, n≥1}of positive integers. Letϕ:RR+ andψ:RR+ be positive, even, and continuous functions satisfying (26) for someα≥1and0< β≤2.

Suppose that for some array{ani,1≤i≤kn, n≥1}of nonzero reals andk≥1/2,

n=1

E

kn

i=1

ψXni ψ

ani1

k

<∞, n=1

kn

i=1

PXni≥cni

<∞, (27)

for some array{cni, (1≤i≤1, n≥1)}of positive numbers such that

n=1 kn

i=1

ϕ

cniEϕXni ϕ2

ani1 <∞. (28)

Then (17) is equivalent to (18).

Puttingψ(x)= |x|p,1< p≤β≤2, andcni= |a−1ni|, we obtain the following result for a separable Banach space of Rademacher typep.

(7)

Corollary6. Let{Xni,1≤i≤kn, n≥1}be an array of row-wise independent- valued random variables in a separable Banach space of Rademacher typep,1< p≤β≤ 2, withEXni=0for all1≤i≤kn,n≥1, and for some increasing sequence{kn, n≥1} of positive integers. Letϕ:RRbe a positive, even, and continuous function such that

ϕ

|x|

|x|α as|x| , (29)

for someα≥1.

Then, for some array{ani, (1≤i≤kn, n≥1)}of nonzero reals and some integer k≥1, the conditions

n=1

kn

i=1

EXnip ani−p

k

<∞, (30)

n=1

kn

i=1

EϕXni ϕ

a−1ni <∞ (31)

imply (18).

Proof. PuttingMni=Kni=1 and using (20), we see that it is enough to show that Theorem 4holds for{Xni,1≤i≤kn, n≥1}andk≥2.

Indeed, we have

n=1

E

kn

i=1

Xni p a−1nip

k

n=1

k s1,...,skn

E Xn1p an11p

s1

E Xn2p an21p

s2

···E Xnk np ank1np

skn

, (32)

where the sum k

s1,...,skn

is over all choices of{s1,s2,...,skn},si∈ {0,1,2,...,k}, such thatkn

i=1si=k. Choosensufficiently large so thatkn> k. Letm=m(s1,s2,...,skn)be a number ofsi=0. We see thatmtakes all the values from the set{1,2,...,k}. Changing the order in our sum, we can express the right-hand side of (32) in the following form:

n=1

k m=1

1≤ij≤kn, j=1,2,...,m ij=ik∀k=j

k si1,...,sim

E

Xni 1p ani11p

si1

E

Xni 2p ani12p

si2

···E

Xnimp ani1mp

sim

n=1

















1≤i1<i2<···<ik≤kn

E

Xni 1p a−1ni1p

E

Xni 2p a−1ni2p

···E

Xni kp a−1nikp

(8)

450 ANNA KUCZMASZEWSKA

+









k−1 m=1

1≤ij≤kn, j=1,2,...,m ij=ik∀k=j

k s1,...,sim



L h=1sijh≥2

E

 Xni

jh

p ani1jhp



sijh











·



N j=1

E

Xni hjp a−1ni

hj

p

















 ,

(33)

whereL=number ofsi2,N=number ofsi=1, and{si1,...,sim}={sijh,h=1,...,L}∪

{sihj,sihj=1,h=1,...,N},{sijh,h=1,...,L}∩{sihj,sihj=1,h=1,...,N}=∅.

But

 Xni jp a−1nijp



sij

Xni jp a−1nijp, E

Xni jp a−1nijp

kn

i=1

EXni jp

a−1nijp for 1≤ij≤kn, (34) so the right-hand side of (33) can be estimated as follows:

C n=1





kn

i=1

EXni p ani1p

k

+

kn

i=1

EXni p ani1p

L

·

kn

i=1

EXni p ani1p

M





≤C n=1

kn

i=1

EXnip ani1p

k

<∞.

(35)

Therefore, assumption (14) ofTheorem 4holds. Moreover, by (31), we get (15) and (16) ofTheorem 4. We also note that ifᏮis a Banach space of Rademacher typep, 1< p≤2, we have the following estimation:

PSn≥ε

≤ε−pESnp≤ε

kn

i=1

EaniXnip≤ε−p

kn

i=1

EXnip

ani−p =o(1). (36)

This fact, together with (20), completes the proof.

Now we present the result which gives the sufficient conditions for the equivalence of (17) and (18) in the Chung-Teicher terms (cf. Teicher [13]).

Theorem7. Let{Xni, 1≤i≤kn, n≥1}be an array of row-wise independent- valued random variables withEXni=0for all1≤i≤kn,n≥1, and for some increas- ing sequence{kn, n≥1}of positive integers. Letϕni:RR+ be positive, even, and

(9)

continuous functions which, for constantsαni1, 0< βni2,Kni>0, andMni>0, n≥1,i≥1, satisfy (12) and

x1≤x2x1βni

ϕnix1≤Mni

x2βni

ϕnix2. (37)

Suppose that for some array{ani, (1≤i≤kn, n≥1)}of nonzero reals,

n=1 kn

i=2

MniniXni ni

a−1ni

i−1

j=1

MnjnjXnj ϕnj

a−1nj <∞, (38)

kn

i=1

MniniXni ϕni

ani1 =o(1), (39)

kn

i=1

KniniXni ϕni

a−1ni =o(1), (40)

n=1

kn

i=1

PXni≥cni

<∞, (41)

for some array{cni, i≥1, n≥1}of positive numbers such that

n=1 kn

i=1

Mni2 ·ϕni

cniniXni ϕ2ni

a−1ni <∞, (42)

n=1 kn

i=1

Kni2 ·ϕni

cniniXni ϕ2ni

ani1 <∞. (43) Then (17) is equivalent to (18).

Proof. LetXni =XniI[Xni ≤ |a−1ni|],Xni =Xni−EXni ,Sn =kn

i=1aniXni, andSn= kn

i=1aniXni. By (20), we state that{Sn, n≥1}and{Sn, n≥1}are equivalent.

Moreover, we have by (40)

kn

i=1

aniEXniIXni≤a−1ni

kn

i=1

ani·EXniIXni≤a−1ni

=

kn

i=1

ani·EXniIXni>ani1

kn

i=1

EXniIXni>ani1 a−1ni

kn

i=1

EXniαniIXni>a−1ni a−1niαni

kn

i=1

Kni·EϕniXni ϕni

a−1ni =o(1).

(44)

(10)

452 ANNA KUCZMASZEWSKA Now we define

Yni=ESnni

−ESnni−1

, (45)

whereᏲni=σ (Xn1,Xn2,...,Xni)andᏲn0= {∅,Ω}. Then we have Sn−ESn=

kn

i=1

Yni (46)

and we note that{Yni,1≤i≤kn}is a sequence of martingale differences for a fixedn. Now we are going to prove that

ESn →0, n → ∞. (47)

First we will show that

Sn−ESn P0, n → ∞. (48)

Using Chebyshev’s inequality,Lemma 3, and assumption (39), we get, for anyε >0, PSn−ESn> ε

≤ε−2ESn−ESn2−2E

kn

i=1

Yni

2

−2

kn

i=1

E Yni2

≤ε2

kn

i=1

EaniXni+EaniXni28ε2

kn

i=1

a2niEXni 2

=8ε−2

kn

i=1

EXni βni

ani1βni·Xni 2−βni ani12−βni 8ε−2

kn

i=1

MniniXni ϕni

ani =o(1).

(49)

Thus, we conclude that (48) holds and, together with (17), (20), and (44), gives (47).

Now we want to show thatSn0 a.s., asn→ ∞. By (47) it is enough to prove that

Sn−ESn →0 a.s.,n→ ∞. (50)

Taking into account the identity

Sn−ESn2=

kn

i=1

Yni2+2

kn

i=2

Yni i−1

j=1

Ynj (51)

and using the notation

Zni=Yni2IXni< cni

−E

Yni2IXni< cnini−1

, 1≤i≤kn, (52)

(11)

we have, by Chebyshev’s inequality,Lemma 3, and assumption (42),

n=1

P

kn

i=1

Zni

> ε

≤ε−2 n=1

E

kn

i=1

Zni

2

−2 n=1

kn

i=1

E Zni2

≤C·ε−2 n=1

kn

i=1

E

Yni4IXni< cni

≤C·ε−2 n=1

kn

i=1

EaniXni 4IXni< cni

≤C·ε2 n=1

kn

i=1

E

Xni 2βni

a−1nini·Xni 42βni

a−1ni4−2βniIXni< cni

≤C·ε−2 n=1

kn

i=1

Mni·ϕni cni

·EϕniXni ϕ2ni

a−1ni <∞.

(53)

Hence, by the Borel-Cantelli Lemma, we obtain

kn

i=1

Yni2IXni< cni

kn

i=1

E

Yni2IXni< cnini−1

→0 a.s.,n → ∞. (54)

UsingLemma 3, we can note by assumption (39) that

kn

i=1

E

Yni2IXni< cnini−1

8

kn

i=1

EaniXni 2

kn

i=1

E

Xni βni

a−1niβni·Xni 2−βni a−1ni2−βni

kn

i=1

Mni·EϕniXni ϕni

a−1ni =o(1),

(55)

which, together with (54), allows us to state that

kn

i=1

Yni2IXni< cni

→0 a.s.,n → ∞. (56)

To prove that

kn

i=1

Yni2 →0 a.s.,n → ∞, (57)

we only need to show that

kn

i=1

Yni2IXni≥cni

→0 a.s.,n → ∞. (58)

(12)

454 ANNA KUCZMASZEWSKA Indeed, by (41) andLemma 3, we have

n=1

P

kn

i=1

Yni2IXni≥cni ≥ε

≤ε1 n=1

E

kn

i=1

Yni2IXni≥cni ≤C

n=1

kn

i=1

EaniXni 2IXni≥cni

≤C n=1

kn

i=1

EIXni≥cni

≤ε−1 n=1

kn

i=1

PXni≥cni

<∞,

(59)

and, by the Borel-Cantelli Lemma, we get (57). To close this proof, we must show that

kn

i=2

Yni i−1 j=1

Ynj →0 a.s.,n→ ∞. (60)

Using the fact that{Ynii−1

j=1Ynj, 2≤i≤kn}is a sequence of martingale differences for eachn, we have, by Chebyshev’s inequality,Lemma 3, and assumption (38),

n=1

P

kn

i=2

Yni i−1

j=1

Ynj

> ε

≤ε−2 n=1

kn

i=2

E

aniXni+EaniXni2·

i−1

j=1

Ynj

2



≤ε2 n=1

kn

i=2

EaniXni+EaniXni2·

i−1

j=1

E Ynj2

≤C n=1

kn

i=2

EaniXni2i−1

j=1

EanjXnj 2C n=1

kn

i=2

MniniXni ϕni

a−1ni

×

i−1 j=1

MnjnjXnj ϕnj

anj1 <∞,

(61)

which, together with the Borel-Cantelli Lemma, implies (60).

Thus, we have proved that

kn

i=1

ani

Xni −EXni

→0 a.s.,n→ ∞. (62)

But{kn

i=1aniXni , n≥1}and{kn

i=1aniXni, n≥1}are equivalent and (44) holds, so we get (18).

Now we consider an array{Xni, i≥1, n≥1}of independent random elements which are stochastically dominated by a random elementXin the sense of (10).

Corollary 8. Let{Xni, 1≤i≤kn, n≥1}be an array of row-wise independent-valued random variables withEXni=0for all1≤i≤kn,n≥1, and some increasing

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