Weighted inequalities for commutators of one-sided singular integrals
M. Lorente, M.S. Riveros
Abstract. We prove weighted inequalities for commutators of one-sided singular integrals (given by a Calder´on-Zygmund kernel with support in (−∞,0)) with BMO functions. We give the one-sided version of the results in [C. P´erez,Sharp estimates for commutators of singular integrals via iterations of the Hardy-Littlewood maximal function, J. Fourier Anal. Appl., vol. 3 (6), 1997, pages 743–756] and [C. P´erez, Endpoint estimates for commutators of singular integral operators, J. Funct. Anal., vol 128 (1), 1995, pages 163-185]. We improve these results for one-sided singular integrals by putting in the right hand side of the inequalities a smaller operator and a wider class of weights.
Keywords: one-sided weights, one-sided singular integrals Classification: Primary 42B25
1. Introduction
In this paper we obtain non standard weighted inequalities for commutators of singular integral operators given by a Calder´on-Zygmund kernelK with support in (−∞,0). This estimates will reflect a higher degree of singularity compared with the standard Calder´on-Zygmund singular integral operators.
Let T denote a Calder´on-Zygmund singular integral operator and M denote the Hardy-Littlewood maximal operator. Coifman proved in [C] that T and M satisfy
(1.1)
Z
Rn
|T f|pw≤C Z
Rn
|M f|pw,
for 0< p <∞,w∈A∞(Rn) andf such that the left hand side is finite. This is a very important estimate in weighted theory since it implies the boundedness of T fromLp(w) intoLp(w), forp >1, whenw∈Ap.
Combining (1.1) with certain sharp two weighted inequalities forM one can derive a two weighted estimate for T with no assumption on the weight w: If
This research has been supported by D.G.E.S. (PB97-1097), Junta de Andaluc´ıa and Uni- versidad Nacional de C´ordoba.
T is a Calder´on-Zygmund singular integral operator, P´erez [P1] proves that for 1< p <∞,
(1.2)
Z
Rn
|T f|pw≤C Z
Rn
|f|pM[p]+1w,
whereMkis thek-times iterated of the Hardy-Littlewood maximal operator. The case 1< p≤2 was first obtained in [W], but for singular integral operators with much stronger conditions on the kernel, namely they must be of convolution type withC∞kernel.
It is possible to generalize inequalities (1.1) and (1.2) for a large family of singu- lar integral operators, i.e., the higher order commutators introduced by Coifman, Rochberg and Weiss in [CRcW]. LetK be a Calder´on-Zygmund kernel. For ap- propriatebandf we define
Tbkf(x) = Z
Rn
(b(x)−b(y))kK(x−y)f(y)dy,
k = 0,1,2. . . (in the principal value sense). Fork = 1 the operator is usually denoted by [Mb, T] =Mb◦T−T◦Mb, whereMbis the operatorMbf =bf, and bis called the symbol of the operator. These generalizations were given by P´erez in [P2]:
Theorem A ([P2]). Let0< p <∞, w∈A∞ andb∈BMO. Then there exists a constantCsuch that
Z
Rn
|Tbkf|pw≤CkbkkpBMO Z
Rn
Mk+1fp
w,
for allf such that the left hand side is finite.
Theorem B([P2]). Let1< p <∞andb∈BMO. Then for each weightwthere exists a constantC such that
Z
Rn
|Tbkf|pw≤CkbkkpBMO Z
Rn
|f|pM[(k+1)p]+1w.
Recently, Aimar, Forzani and Mart´ın-Reyes [AFM] have studied singular inte- gral operators associated to a Calder´on-Zygmund kernel with support in (−∞,0) or (0,∞). They prove that the maximal operators which control these singular integrals are the one-sided Hardy-Littlewood maximal operators M+ and M− defined for locally integrable functionsf by
M+f(x) = sup
h>0
1 h
Z x+h x
|f| and M−f(x) = sup
h>0
1 h
Z x x−h
|f|,
and the good weights for these operators are the one-sided weights introduced by Sawyer [S]. Their result improves (1.1) for singular integrals with kernel supported in (−∞,0) in two ways, by putting in the right hand side a smaller operator and by allowing a wider class of weights for which the inequality holds. More precisely, they prove that ifT is a singular integral operator given by a kernel with support in (−∞,0) then there existsC such that
(1.3)
Z
R
|T f|pw≤C Z
R
|M+f|pw,
for 0< p <∞andw∈A+∞(R) (see [MPT] for the definition ofA+∞(R)).
The aim of this paper is to study the results of C. P´erez for this kind of singular integrals and to extend them in the double sense as in [AFM]. Our results are the following:
Theorem 1. Let0 < p <∞, k = 0,1, . . ., w∈A+∞ and b∈ BMO. LetK be a Calder´on-Zygmund kernel with support in (−∞,0) and let Tb+,k be defined (in the principal value sense)by
Tb+,kf(x) = Z ∞
x
(b(x)−b(y))kK(x−y)f(y)dy.
Then there existsC such that Z
R
|Tb+,kf|pw≤CkbkkpBMO Z
R
(M+)k+1fp
w
for all bounded functionsf with compact support.
Corollary 1. Under the same hypotheses as in Theorem 1, if 1 < p <∞ and w∈A+p then there existsCsuch that
Z
R
|Tb+,kf|pw≤CkbkkpBMO Z
R
|f|pw for all bounded functionsf with compact support.
We also give a weak type result that generalizes the result in [P3] for this kind of singular integrals:
Theorem 2. Letw∈A+∞,b∈BMOandTb+,k be as in Theorem1. Then there existsC such that
w({x:|Tb+,kf(x)|> λ})
≤Cφk(kbkkBMO) Z
R
|f(x)|
λ 1 + log+(|f(x)|/λ)k
M−w(x)dx for all bounded functionsf with compact support, whereφk(t) =t(1 + log+t)k.
Corollary 2. Under the same hypotheses as in Theorem2, if w∈A+1 then there existsC such that
w({x:|Tb+,kf(x)|> λ})
≤Cφk(kbkkBMO) Z
R
|f(x)|
λ 1 + log+(|f(x)|/λ)k
w(x)dx
for all bounded functionsf with compact support.
Theorem 3. Let1< p <∞,b∈BMOandTb+,k be as in Theorem1. Then, for each weightwthere existsC such that
(1.4)
Z
R
|Tb+,kf|pw≤CkbkkpBMO Z
R
|f|p(M−)[(k+1)p]+1w for all bounded functionsf with compact support.
The casek= 0, i.e., the generalization of the result in [P1] for these singular integrals, can be found in [RRoT].
Clearly, every theorem has its analogue reversing the orientation ofR. 2. Definitions and preliminaries
We introduce some definitions and tools that we need for proving the main results.
Definition 2.1. We shall say that a functionK in L1loc(R\ {0}) is a Calder´on- Zygmund kernel if the following properties are satisfied:
(a) there exists a finite constantB1 such that
Z
ǫ<|x|<N
K(x)dx
≤ B1,
for allǫand allN with 0< ǫ < N and, furthermore, limǫ→0+R
ǫ<|x|<1K(x)dxexists;
(b) there exists a finite constantB2 such that
|K(x)| ≤ B2
|x|
for allx6= 0;
(c) there exists a finite constant B3 such that
|K(x−y)−K(x)| ≤B3|y||x|−2 for allxandy with|x|>2|y|.
A one-sided singular integralT+is a singular integral associated to a Calder´on- Zygmund kernel with support in (−∞,0); therefore, in that case,
T+f(x) = lim
ǫ→0+
Z ∞ x+ǫ
K(x−y)f(y)dy.
Examples of such kernels are given in [AFM].
F.J. Mart´ın-Reyes and A. de la Torre introduced the one-sided sharp functions in [MT].
Definition 2.2. Let f be a locally integrable function. The one-sided sharp maximal function is defined by
M+,#f(x) = sup
h>0
1 h
Z x+h
x
f(y)−1 h
Z x+2h
x+h
f
!+
dy.
It is proved in [MT] that M+,#f(x)≤sup
h>0 a∈Rinf
1 h
Z x+h
x
(f(y)−a)+dy+1 h
Z x+2h
x+h
(a−f(y))+dy≤ kfkBMO. See [MT] for other results and definitions.
We shall also need the following maximal operators:
Mǫ+f(x) = (M+|f|ǫ(x))1/ǫ and Mδ+,#f(x) =
M+,#|f|δ(x)1/δ
. Now we give definitions and results about Young functions. A function B : [0,∞) → [0,∞) is a Young function if it is continuous, convex and increasing satisfying B(0) = 0 and B(t) → ∞ as t → ∞. The Luxemburg norm of a functionf associated to B is
kfkB= inf
λ >0 : Z
B |f|
λ
≤1
, and so the B-average off overI is
kfkB,I= inf
λ >0 : 1
|I|
Z
I
B |f|
λ
≤1
.
We will denote byBthe complementary function associated toB(see [BS]). Then the generalized H¨older’s inequality
1
|I|
Z
I
|f g| ≤ kfkB,IkgkB,I,
holds. There is a further generalization that turns out to be useful for our purposes (see [O]). IfA, B, C are Young functions such that
A−1(t)B−1(t)≤C−1(t), then
kf gkC,I ≤2kfkA,IkgkB,I.
Definition 2.3. For each locally integrable function f, the one-sided maximal operators associated to the Young functionB are defined by
MB+f(x) = sup
x<b
kfkB,(x,b) and MB−f(x) = sup
a<xkfkB,(a,x).
Definition 2.4. Let B be a Young function. We say that B satisfies the Bp
condition, or thatB∈Bp,p >1, if there existsc >0 such that Z ∞
c
B(t) tp
dt t ≈
Z ∞ c
tp′ B(t)
!p−1
dt t <∞.
TheBp condition appears for the first time in [P4]. The point of Definition 2.4 is that it implies the boundedness ofMB+fromLp(R) into Lp(R) for 1< p <∞.
In fact one has
Theorem C ([RRoT]). Let 1 < p < ∞, w be a weight and B be a Young function. Then the following statements are equivalent:
(a) B∈Bp;
(b) there existsCsuch that Z
(MB+f)pw≤C Z
|f|pM−w.
We will be working most of the time withB(t) =t(1 + log+t)k,k≥0 and for thisB, it is proved in [RRoT] that
(2.1) MB+f ≈(M+)k+1f.
3. Proofs
To prove Theorem 1 we need the following lemma:
Lemma 1. Let0< δ <1. Then
(a) there existsC=Cδ>0such that Mδ+,# T+f
(x)≤CM+f(x);
(b) for eachb∈BMO,δ < ǫ <1 andk= 1,2, . . ., there exists C=Cδ,ǫ>0 such that
Mδ+,#
Tb+,kf
(x)≤C
k−1
X
j=0
kbkk−jBMOMǫ+(Tb+,jf)(x) +CkbkkBMO(M+)k+1f(x).
Proof: We start by proving (b). Letλ be an arbitrary constant. Thenb(x)− b(y) = (b(x)−λ)−(b(y)−λ) and
Tb+,kf(x) = Z
R
(b(x)−b(y))kK(x−y)f(y)dy (3.1)
=
k
X
j=0
Cj,k(b(x)−λ)j Z
R
(b(y)−λ)k−jK(x−y)f(y)dy
=T+((b−λ)kf)(x) +
k
X
j=1
Cj,k(b(x)−λ)j Z
R
(b(y)−λ)k−jK(x−y)f(y)dy
=T+((b−λ)kf)(x) +
k
X
j=1 k−j
X
s=0
Cj,k,s(b(x)−λ)s+j Z
R
(b(x)−b(y))k−j−sK(x−y)f(y)dy
=T+((b−λ)kf)(x) +
k−1
X
m=0
Ck,m(b(x)−λ)k−mTb+,mf(x),
where m=k−j−s. Let us fix xand h > 0 and let I = [x, x+ 8h]. Then we write f =f1+f2 where f1 =f χI. Taking into account (3.1), for alla∈R, we have the following:
1 h
Z x+h x
|Tb+,kf(y)|δ− |a|δ dy
!1δ
+ 1
h Z x+2h
x+h
|Tb+,kf(y)|δ− |a|δ dy
!1δ (3.2)
≤ 1 h
Z x+h x
|Tb+,kf(y)−a|δdy
!1δ
+ 1
h Z x+2h
x+h
|Tb+,kf(y)−a|δdy
!1δ
≤C
k−1
X
m=0
1 h
Z x+2h x
|b(y)−λ|(k−m)δ|Tb+,mf(y)|δdy
!1δ
+ 1
h Z x+2h
x
|T+((b−λ)kf)(y)−a|δdy
!1δ
≤C
k−1
X
m=0
1 h
Z x+2h x
|b(y)−λ|(k−m)δ|Tb+,mf(y)|δdy
!1δ
+ 1
h Z x+2h
x |T+((b−λ)kf1)(y)|δdy
!1δ
+ 1
h Z x+2h
x
|T+((b−λ)kf2)(y)−a|δdy
!1δ
= (I) + (II) + (III).
Letλ=bI = 8h1 Rx+8h
x b(y)dy. Since 0< δ < ǫ <1, we can choose qsuch that 1< q <δǫ. Then, using H¨older’s inequality forqandq′, we get
(I)≤C
k−1
X
m=0
1 h
Z x+2h
x
|b(y)−bI|(k−m)δq′dy
!δq1′
×
× 1 h
Z x+2h
x
|Tb+,mf(y)|δqdy
!δq1 (3.3)
≤C
k−1
X
m=0
1 h
Z x+8h
x
|b(y)−bI|(k−m)δq′dy
! 1
δq′(k−m)
k−m
×
× 1 h
Z x+2h x
|Tb+,mf(y)|δqdy
!δq1
≤C
k−1
X
m=0
kbkk−mBMOMδq+(Tb+,mf)(x)
≤C
k−1
X
m=0
kbkk−mBMOMǫ+(Tb+,mf)(x).
Using thatT+ is of weak type (1,1), Kolmogorov’s inequality gives that (II)≤C1
h Z x+2h
x
|b−bI|k|f|χI(y)dy.
And by the generalized H¨older’s inequality forB(t) =t(1 + log+t)k andB(t)≈ et1/k we get,
(II)≤Ckb−bIkB,Ikf χIkB,I.
Now ifD(t) =et, using the John-Nirenberg’s inequality, we have (3.4) (II)≤Ckb−bIkkD,Ikf χIkB,I≤CkbkkBMOMB+f(x)
≤CkbkkBMO(M+)k+1f(x).
For (III) we takea=T+((b−bI)kf2)(x+ 2h). Then, by Jensen’s inequality, (3.5) (III)≤C1
h Z x+2h
x
|T+((b−bI)kf2)(y)−T+((b−bI)kf2)(x+ 2h)|dy.
Forj≥3, letIj = [x+ 2jh, x+ 2j+1h] and ˜Ij= [x, x+ 2j+1h]. Using property (c) of the kernelK, for everyy∈[x, x+ 2h], we have
(3.6)
|T+((b−bI)kf2)(y)−T+((b−bI)kf2)(x+ 2h)|
≤ Z ∞
x+8h
x+ 2h−y
(t−(x+ 2h))2|b(t)−bI|k|f(t)|dt
≤Ch
∞
X
j=3
Z x+2j+1h
x+2jh
|b(t)−bI|k
(t−(x+ 2h))2|f(t)|dt
≤Ch
∞
X
j=3
2j+1 (2j−2)2h
1 2j+1h
Z
I˜j
|b(t)−bI|k|f(t)|dt.
Observe that by the generalized H¨older’s inequality and using again the John- Nirenberg’s inequality, we obtain
(3.7) 1 2j+1h
Z
I˜j
|b(t)−bI|k|f(t)|dt
≤ C
2j+1h|bI˜
j−bI|k Z
I˜j
|f(t)|dt+ C 2j+1h
Z
I˜j
|b(t)−bI˜
j|k|f(t)|dt
≤C(2j)kkbkkBMOM+f(x) +Ckb−bI˜
jkB,I˜
jkf χI˜
jkB,I˜
j
≤C(2j)kkbkkBMOM+f(x) +CkbkkBMO(M+)k+1f(x).
So inequalities (3.5), (3.6) and (3.7) give
(3.8)
(III)≤C
∞
X
j=3
2j+1
(2j−2)2(2j)kkbkkBMOM+f(x) +C
∞
X
j=3
2j+1
(2j−2)2kbkkBMO(M+)k+1f(x)
≤CkbkkBMO(M+)k+1f(x).
Putting together inequalities (3.2), (3.3), (3.4) and (3.8), we obtain that Mδ+,#
Tb+,kf
(x)≤CkbkkBMO(M+)k+1f(x) +C
k−1
X
m=0
kbkk−mBMOMǫ+(Tb+,mf)(x).
The proof of part (a) follows the same pattern as the proof of (b) but it is
easier and therefore we omit it.
We will now prove Theorem 1.
Proof of Theorem 1: Observe that the casek= 0 is the inequality for singular integrals with support in (−∞,0) (see [AFM]). We will proceed by induction on k. So assume that the theorem is true for allj ≤k and let us see how it follows the case k+ 1. Sincew ∈ A+∞, there exists r > 1 such that w ∈A+r. Observe that for allδ >0 small enough, we have thatr < pδ and thus,w∈A+p
δ
. To apply Theorem 4 in [MT] we needkMδ+(Tb+,k+1f)kLp(w)to be finite. Suppose this for the moment. Then, by Lemma 1, for allǫwithδ < ǫ <1, we have
kTb+,k+1fkLp(w)≤ kMδ+(Tb+,k+1f)kLp(w)
≤CkMδ+,#(Tb+,k+1f)kLp(w)
≤C
k
X
j=0
kbkk+1−jBMO kMǫ+(Tb+,jf)kLp(w)
+Ckbkk+1BMOk(M+)k+2fkLp(w). We chooseǫ >0 such thatr < pǫ. Thenw∈A+p
ǫ
and we obtain kMǫ+(Tb+,jf)kpLp(w)=
Z
R
(M+(|Tb+,jf|ǫ)pǫw
≤C Z
R
(|Tb+,jf|ǫ)pǫw=CkTb+,jfkpLp(w). Then, by recurrence
kTb+,k+1fkLp(w)≤C
k
X
j=0
kbkk+1−jBMO kTb+,jfkLp(w)
+Ckbkk+1BMOk(M+)k+2fkLp(w)
≤C
k
X
j=0
kbkk+1−jBMO kbkjBMOk(M+)j+1fkLp(w)
+Ckbkk+1BMOk(M+)k+2fkLp(w)
≤Ckbkk+1BMOk(M+)k+2fkLp(w).
Ifwis bounded, then
kMδ+(Tb+,k+1f)kLp(w)≤CkMδ+(Tb+,k+1f)kLp(dx)
≤CkTb+,k+1fkLp(dx)≤Ckbkk+1BMOkfkLp(dx)<∞.
Then the theorem is proved ifw is bounded. For the general case, we consider wN = min{w, N}. It is not hard to prove thatwN ∈A+∞ (A+p is a lattice) with constant independent ofN. Therefore, we have
Z
R
|Tb+,kf|pwN ≤CkbkkpBMO Z
R
(M+)k+1fp
wN.
Now, we obtain the desired result after applying the monotone convergence the- orem.
To prove Theorem 2 we need the following two lemmas.
Lemma 2. Let f ∈ L1loc(R) and λ > 0. Then for every weight w there exists C >0 such that
w({x∈R: (M+)k+1f(x)> λ})≤C Z
R
|f(y)|
λ
1 + log+|f(y)|
λ k
M−w(y)dy.
Proof: This lemma is a consequence of (2.1) and Theorem 2.5 in [RRoT] with B(t) =t(1 + log+t)k, since (w, M−w)∈A+1. Lemma 3. Let φk(t) = t(1 + log+t)k, k = 0,1, . . ., b ∈ BMO and w ∈ A+∞. Then there existsC >0 such that
sup
t>0
1
φk(1t)w({x∈R:|Tb+,kf(x)|> t})
≤Cφk(kbkkBMO) sup
t>0
1
φk(1t)w({x∈R: (M+)k+1f(x)> t}) for all bounded functionsf with compact support.
Proof: We first suppose thatkbkBMO= 1. We shall prove the following, sup
t>0
1
φk(1t)w({x∈R:|Tb+,kf(x)|> t})
≤Csup
t>0
1
φk(1t)w({x∈R: (M+)k+1f(x)> t}).
Now, setbm =b if −m≤b ≤m, bm =m ifb ≥m and bm =−m ifb ≤ −m.
Also, set wN = inf{w, N}. As we have said before, wN ∈ A+∞ with constant independent of N. On the other hand kbmkBMO ≤ C′kbkBMO = C′ with C′ independent ofm. In order to simplify notation, renameb =bm and w =wN. Observe that for allδ >0 we have
w({x∈R:|Tb+,kf(x)|> t})≤w({x∈R:Mδ+(Tb+,kf)(x)> t}).
Let us consider the functional Lb,w,φk,δ(f) =Lδ(f) = sup
t>0
1
φk(1t)w({x∈R:Mδ+(Tb+,kf)(x)> t}).
We claim that for someγ >0 and every 0< ǫ <1 we have (3.9) Lδ(f)≤ǫγCLδ(f) +Csup
t>0
1
φk(1t)w({x∈R: (M+)k+1f(x)> t}).
IfLδ(f)<∞then the result (forbmandwN) follows from (3.9), choosingǫsmall enough.
In what follows we prove that Lδ(f) < ∞. In [MT] it was proved that if w∈A+∞ andM+f ∈Lp0(w) for somep0, then
(3.10) w({x∈R:M+f(x)> t, M+,#f(x)≤tǫ})
≤Cǫγw({x∈R:M+f(x)> t 2}) for someγ >0. Observe that we haveMδ+(Tb+,kf)∈Lp0(w) for somep0 sincef is bounded with compact support,w≤N and|b| ≤m. Then
(3.11)
w({x∈R:Mδ+(Tb+,kf)(x)> t})
=w({x∈R:M+(|Tb+,kf|δ)(x)> tδ, M+,#(|Tb+,kf|δ)(x)≤tδǫ}) +w({x∈R:M+(|Tb+,kf|δ)(x)> tδ, M+,#(|Tb+,kf|δ)(x)> tδǫ})
≤Cǫγw({x∈R:Mδ+(Tb+,kf)(x)≥t/2δ1}) +w({x∈R:Mδ+,#(Tb+,kf)(x)> tǫ1/δ})
=I+II.
Using Lemma 1 forǫ=δrand 1< r <1δ, we have
(3.12)
II ≤w({x∈R:
k−1
X
j=0
(C′)k−jMδr+(Tb+,jf)(x)> tǫ1δ 2C}) +w({x∈R: (M+)k+1f(x)> tǫ1δ
2C(C′)k}).
Bearing in mind (3.11) and (3.12) we obtain
(3.13)
1
φk(1t)w({x∈R:Mδ+(Tb+,kf)(x)> t})
≤ Cǫγ
φk(1t)w({x∈R:Mδ+(Tb+,k)f(x)> t 21δ}) +
k−1
X
j=0
1
φk(1t)w({x∈R:Mδr+(Tb+,jf)(x)> tǫ1δ 2Ck(C′)k−j})
+ 1
φk(1t)w({x∈R: (M+)k+1f(x)> tǫ1δ 2C(C′)k})
=I′+II′+III′.
Observe that there existsC such that φk(2t)≤Cφk(t) for all t >0 (i.e. φk is doubling). Letl ∈Nbe such that 21δ <2l. Using thatφk is non-decreasing, we get
φk 21δ t
!
≤φk 2l t
!
≤Cφk 1
t
. Then
I′≤ Cǫγ φk(2
1 δ
t )
w({x∈R:Mδ+(Tb+,kf)(x)> t
21δ})≤CǫγLδ(f).
Now letaj = 2Ck(C
′)k−j
ǫ1δ andh∈Zbe such thataj ≤2h, for allj. Therefore φkaj
t
≤φk 2h t
!
≤Cφk 1
t
. As a consequence,
(3.14)
II′≤C
k−1
X
j=0
1
φk(atj)w({x∈R:Mδr+(Tb+,jf)(x)> t aj})
≤C
k−1
X
j=0
sup
t>0
1
φk(1t)w({x∈R:Mδr+(Tb+,jf)(x)> t}).
Now for each j = 0,1. . . , k −1, let us estimate supt>0 1
φk(1t)w({x ∈ R : Mδr+(Tb+,jf)(x)> t}).
Using that φk is doubling and non-decreasing, it follows from (3.10) and Lemma 1(a) that, for all 0< ǫ <1,
sup
t>0
1
φk(1t)w({x:Mǫ+(T+f)(x)> t})≤sup
t>0
1
φk(1t)w({x:Mǫ+,#(T+f)(x)> t})
≤Csup
t>0
1
φk(1t)w({x:M+f(x)> t})
≤Csup
t>0
1
φk(1t)w({x: (M+)k+1f(x)> t}).
FixJ < k−1 and suppose that, for every 0≤j≤J and for all 0< ǫ <1, there existsC such that
(3.15) sup
t>0
1
φk(1t)w({x∈R:Mǫ+(Tb+,jf)(x)> t})
≤Csup
t>0
1
φk(1t)w({x∈R: (M+)k+1f(x)> t}).
We will prove, that (3.15) holds forj =J + 1. Using again thatφk is doubling, non-decreasing, (3.10) and Lemma 1(b) we obtain
sup
t>0
1
φk(1t)w({x:Mǫ+(Tb+,J+1f)(x)> t})
≤Csup
t>0
1
φk(1t)w({x:Mǫ+,#(Tb+,J+1f)(x)> t})
≤C
" J X
i=0
sup
t>0
1
φk(1t)w({x:Mǫ+′(Tb+,if)(x)> t}) +w({x: (M+)J+1f(x)> t})
#
≤C
J
X
i=0
sup
t>0
1
φk(1t)w({x: (M+)k+1f(x)> t}) +Csup
t>0
1
φk(1t)w({x: (M+)J+1f(x)> t})
≤Csup
t>0
1
φk(1t)w({x: (M+)k+1f(x)> t}),
whereǫ < ǫ′ <1. As a consequence, forǫ=δr, (3.15) together with (3.14) gives II′ ≤Csup
t>0
1
φk(1t)w({x∈R: (M+)k+1f(x)> t}).
Finally, leta= ǫ
1δ
2C(C′)k. Then III′ ≤ C
φk(at1)w({x∈R: (M+)k+1f(x)> at})
≤Csup
t>0
1
φk(1t)w({x∈R: (M+)k+1f(x)> t}).
Putting all these estimates together we get (3.9).
Therefore if we prove thatLb,w,φk,δf <∞, using (3.9) we obtain Lb,w,φk,δ(f)≤Csup
t>0
1
φk(1t)w({x∈R: (M+)k+1f(x)> t}).
Assume now that suppf ⊂(−R, R), for someR >0. Then forx≤ −2Rwe have
|Tb+,kf(x)| ≤C Z R
−R
|b(x)−b(y)|k
|x−y| |f(y)|dy (3.16)
≤ 2Cmk
|x|
Z R x
|f(y)|dy
≤CmkM+f(x).
Using that 0< δ <1, the fact thatM+is of weak type (1,1) with respect to the pair (w, M−w)∈A+1, Lemma 2 and (3.16), we get
1
φk(1t)w({x∈R:Mδ+(Tb+,kf)(x)> t})
≤ 1
φk(1t)w({x∈R:Mδ+(χ(−2R,2R)Tb+,kf)(x)> t/2})
+ 1
φk(1t)w({x∈R:Mδ+(χ(−∞,−2R)Tb+,kf)(x)> t/2})
≤ 1 φk(1t)
C t
Z 2R
−2R
|Tb+,kf(x)|M−w(x)dx
+ 1
φk(1t)w({x∈R: (M+)k+1f(x)> Cmt})
≤C4N R 1 4R
Z 2R
−2R
|Tb+,kf(x)|2dx
!12
+ C
φk(1t) Z
R
φk
|f(x)|
Cmt
M−w(x)dx
≤C4N R 1 4R
Z R
−R
|f(x)|2dx
!12 +CN
Z R
−R
φk(|f(x)|)dx.
Sincef is bounded and with compact support the last expression is finite.
Then, we have obtained the following:
sup
t>0
1
φk(1t)wN({x∈R:|Tb+,km f(x)|> t})
≤Csup
t>0
1
φk(1t)wN({x∈R: (M+)k+1f(x)> t}).
Observe thatn bjmfo
converges tobjfinL1(dx), sincef is bounded with compact support and b ∈ BMO implies that b is locally in Lp(dx) for all p≥ 1. Then, taking into account thatT+ is of weak type (1,1) with respect to the Lebesgue measure, we obtain that n
T+(bjmf)o
converges to T+(bjf) in measure. This implies that, for a subsequence, we have almost everywhere convergence. On the other hand,n
bjmT+fo
converges tobjT+f almost everywhere. As a consequence, a subsequence of n
|Tb+,km f|o
converges to |Tb+,kf| almost everywhere. We shall continue denoting this subsequence byn
|Tb+,k
m f|o
. Then, by Fatou’s lemma, sup
t>0
1
φk(1t)wN({x∈R:|Tb+,kf(x)|> t})
= sup
t>0
1 φk(1t)
Z
R
m→∞lim wN(x)χ{x∈R:|T+,k
bm f(x)|>t}dx
≤sup
t>0
1
φk(1t)lim inf
m→∞ wN({x∈R:|Tb+,km f(x)|> t})
≤Csup
t>0
1
φk(1t)wN({x∈R: (M+)k+1f(x)> t}).
LettingN go to infinity we obtain the desired result.
Now, for generalb ∈ BMO (kbkBMO > 0), we consider h = kbkb
BMO. Then, sinceTh+,kf = kbkk1
BMO
Tb+,kf and taking into account thatφkis submultiplicative, we have
sup
t>0
1
φk(1t)w({x∈R:|Tb+,kf(x)|> t})
= sup
t>0
1
φk(1t)w({x∈R:|Th+,kf(x)|> t kbkkBMO})
≤φk(kbkkBMO) sup
t>0
1 φk
kbkkBMO t
w({x∈R:Th+,kf(x)> t kbkkBMO})
≤Cφk(kbkkBMO) sup
t>0
1
φk(1t)w({x∈R:Mk+1f(x)> t}).
Proof of Theorem 2: It suffices to consider the caseλ= 1. (For λ >0 the result follows by consideringfλ). By Lemma 3, the fact thatφkis submultiplicative and by Lemma 2 we get,
w({x∈R:|Tb+,kf(x)|>1})≤sup
t>0
1
φk(1t)w({x∈R:|Tb+,kf(x)|> t})
≤Cφk(kbkkBMO) sup
t>0
1
φk(1t)w({x∈R: (M+)k+1f(x)> t})
≤Cφk(kbkkBMO) sup
t>0
1 φk(1t)φk(1
t) Z
R
φk(|f(x)|)M−w(x)dx
=Cφk(kbkkBMO) Z
R
|f(x)|(1 + log+|f(x)|)kM−w(x)dx.
Proof of Theorem 3: By duality, (1.4) is equivalent to Z
R
|Tb−,kf|p′((M−)[(k+1)p]+1w)1−p′ ≤C Z
R
|f|p′w1−p′.
Observe that ((M−)[(k+1)p]+1w)1−p′ ∈A−∞, and by Theorem 1, we get Z
R
|Tb−,kf|p′((M−)[(k+1)p]+1w)1−p′
≤C Z
R
((M−)k+1f)p′((M−)[(k+1)p]+1w)1−p′. Therefore it suffices to prove that
(3.17)
Z
R
((M−)k+1f)p′((M−)[(k+1)p]+1w)1−p′ ≤C Z
R
|f|p′w1−p′. Now observe that proving (3.17) is equivalent to
(3.18)
Z
R
((M−)k+1(f w1p))p′((M−)[(k+1)p]+1w)1−p′ ≤C Z
R
|f|p′.
Ifφk(t) =t(1 + log+t)k, then (3.18) is equivalent to (3.19)
Z
R
((Mφ−
k)(f w1p))p′((M−)[(k+1)p]+1w)1−p′ ≤C Z
R
|f|p′.
For larget, φ−1k (t)≈ t
log(t)k. Then, forǫ >0, φ−1k (t)≈ t1p
log(t)k+p
−1+ǫ p
×tp1′ log(t)p
−1+ǫ
p =A−1(t)×B−1(t),
where A(t) ≈ tplog(t)(k+1)p−1+ǫ and B(t) ≈ tp′
log(t)1+(p′−1)ǫ. Then, by the generalized H¨older’s inequality, we have
(Mφ−
k)(f wp1)≤CMB−(f)MA−(w1p)≤CMB−(f)(MD−(w))1p,
whereD(t) =t(logt)(k+1)p−1+ǫ. We chooseǫsuch that (k+1)p−1+ǫ= [(k+1)p].
Then Z
R
((Mφ−
k)(f w1p))p′((M−)[(k+1)p]+1w)1−p′
≤C Z
R
(MB−(f))p′((MD−(w))p
′
p((M−)[(k+1)p]+1w)1−p′
≤C Z
R
(MB−(f))p′((MD−(w))p′−1((MD−(w))1−p′
≤C Z
R
|f|p′,
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An´alisis Matem´atico, Facultad de Ciencias, Universidad de M´alaga, 29071 M´alaga, Spain
E-mail: [email protected]
FaMAF, Universidad Nacional de C ´ordoba, 5000 C´ordoba, Argentina E-mail: [email protected]
(Received February 29, 2000,revised April 10, 2000)