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(1)No. 6]. Proc. Japan Acad., 94, Ser. A (2018). 59. Automorphism group of plane curve computed by Galois points, II By Takeshi H ARUI,Þ Kei MIURAÞ and Akira O HBUCHIÞ (Communicated by Heisuke HIRONAKA,. M.J.A.,. May 14, 2018). Abstract: Recently, the first author [3] classified finite groups obtained as automorphism groups of smooth plane curves of degree d  4 into five types. He gave an upper bound of the order of the automorphism group for each types. For one of them, the type (a-ii), that is given by maxf2dðd  2Þ; 60dg. In this article, we shall construct typical examples of smooth plane curve C by applying the method of Galois points, whose automorphism group has order 60d. In fact, we determine the structure of the automorphism group of those curves. Key words:. Icosahedral group; Galois point; plane curve; automorphism group.. 1. Introduction. The purpose of this article is to give typical examples of smooth plane curve of degree d whose automorphism group has order 60d. In fact, we study the structure of that group. Our method is based on the classification theorem of automorphism groups by the first author and the theory of Galois points for smooth plane curves. First, we recall several definitions of Galois points in brief. Throughout the present article, we work over the complex number field C. The concept of Galois points was introduced by Yoshihara in 1996 (e.g. [6]). Let C  P2 be a smooth plane curve of degree d ðd  4Þ and CðCÞ the function field of C. Let P be a point of P2 . Consider the morphism P : C ! P1 , which is the restriction of the projection P2 --K P1 with the center P . Then we obtain the field extension induced by P , i.e., P : CðP1 Þ ,! CðCÞ. Putting KP ¼ P ðCðP1 ÞÞ, we have the following definition. Definition 1. The point P is called a Galois point for C if the field extension CðCÞ=KP is Galois. Furthermore, a Galois point is said to be inner (resp. outer) if P 2 C (resp. P 2 P2 n C). The group GP ¼ GalðCðCÞ=KP Þ is called the Galois group at P. We denote by ðCÞ (resp. 0 ðCÞ) the number of 2010 Mathematics Subject Classification. Primary 14H37; Secondary 14H50. Þ Department of Core Studies, Kochi University of Technology, 185 Miyanokuchi, Tosayamada, Kami, Kochi 782-8502, Japan. Þ Department of Mathematics, National Institute of Technology, Ube College, 2-14-1 Tokiwadai, Ube, Yamaguchi 7558555, Japan. Þ Department of Mathematical Sciences, Faculty of Science and Technology, Tokushima University, 2-1 Minamijosanjima-cho, Tokushima 770-8502, Japan.. doi: 10.3792/pjaa.94.59 #2018 The Japan Academy. inner (resp. outer) Galois points for C. There are many known results on Galois points. We recall some of them. Theorem 1 ([6], [7]). Suppose that C is a smooth plane curve of degree d ðd  4Þ. Then, (i) 0 ðCÞ ¼ 0; 1 or 3. Further, 0 ðCÞ ¼ 3 if and only if C is projectively equivalent to the Fermat curve. (ii) ðCÞ ¼ 0; 1 or 4 if d ¼ 4. Further, ðCÞ ¼ 4 if and only if C is projectively equivalent to the curve defined by X 4 þ Y 4 þ Y Z 3 ¼ 0. When d  5, we have ðCÞ ¼ 0 or 1. Theorem 2 ([7]). Suppose that C is a smooth plane curve of degree d ðd  4Þ. If P is an inner ðresp. outerÞ Galois point, then GP is isomorphic to the cyclic group of degree d  1 (resp. d), i.e., GP  ¼ Zd1 (resp. Zd ). Remark 1. If C has singularities, then the theorem above does not hold true. Namely, there exist a singular plane curve C and a Galois point P for C such that GP is not cyclic. For example, see [4]. When C has a Galois point, we can give a concrete defining equation of C. Proposition 3 ([7]). By a suitable change of coordinates, the defining equation of C with an outer Galois point can be expressed as Z d þ Fd ðX; Y Þ ¼ 0, where Fd ðX; Y Þ is a homogeneous polynomial of degree d without multiple factors. Referring to [3], we may infer that plane curves with ðCÞ 6¼ 0 or 0 ðCÞ 6¼ 0 play an important role when we classify the automorphism group of smooth plane curves. In [3], the first author classified finite groups obtained as automorphism groups of C into five types. First of all, we recall several definitions. Let.

(2) 60. T. HARUI, K. MIURA and A. OHBUCHI. G be a group of automorphisms of C. Then, it is well-known that G is considered as a subgroup of PGLð3; CÞ ¼ AutðP2 Þ. Let Fd be the Fermat curve X d þ Y d þ Z d ¼ 0. We denote by Kd a smooth curve defined by XY d1 þ Y Z d1 þ ZX d1 ¼ 0 (In [3], Kd is called Klein curve of degree d). For a non-zero monomial cX i Y j Z k with c 2 C n f0g, we define its exponent as maxfi; j; kg. For a homogeneous polynomial F ðX; Y ; ZÞ, the core of F ðX; Y ; ZÞ is defined as the sum of all terms of F ðX; Y ; ZÞ with the greatest exponent. Definition 2. Let C0 be a smooth plane curve with defining equation F0 ðX; Y ; ZÞ ¼ 0. Then a pair ðC; GÞ of a smooth plane curve C and a subgroup G  AutðCÞ is said to be a descendent of C0 if C is defined by a homogeneous polynomial whose core coincides with F0 ðX; Y ; ZÞ and G acts on C0 in a suitable coordinate system. Definition 3. We denote by PBDð2; 1Þ the following subgroup of PGLð3; CÞ: 8 9, 1 0 a11 a12 0 > > < = C B PBDð2; 1Þ :¼ A ¼ @ a21 a22 0 A 2 GLð3; CÞ C : > > : ; 0 0 . We remark that there exists a natural group homomorphism  : PBDð2; 1Þ ! PGLð2; CÞ, i.e., A 7! ðaij Þ. Using these concepts, the first author proved the following theorem. Theorem 4 ([3]). Let C be a smooth plane curve of degree d  4, G a subgroup of AutðCÞ. Then one of the following holds: (a-i) G fixes a point on C and G is a cyclic group whose order is at most dðd  1Þ. Furthermore, if d  5 and jGj ¼ dðd  1Þ, then C is projectively equivalent to the curve Y Z d1 þ X d þ Y d ¼ 0 and AutðCÞ  ¼ Zdðd1Þ . (a-ii) G fixes a point not lying on C and there exists a commutative diagram 1. 1. C. N. PBD(2, 1). G. ρ. PGL(2, C). 1. G. 1,. where N is a cyclic group whose order is a factor of d and G0 is a subgroup of PGLð2; CÞ, i.e., a cyclic group Zm , a dihedral group D2m , the tetrahedral group A4 , the octahedral group S4 or the icosahedral group A5 . Furthermore, m  d  1 and if G0  ¼ D2m then. [Vol. 94(A),. m j d  2 or N is trivial. In particular, jGj  maxf2dðd  2Þ; 60dg. (b-i) ðC; GÞ is a descendant of the Fermat curve Fd : X d þ Y d þ Z d ¼ 0. In this case jGj  6d2 . (b-ii) ðC; GÞ is a descendant of the Klein curve Kd : XY d1 þ Y Z d1 þ ZX d1 ¼ 0. In this case jGj  3ðd2  3d þ 3Þ if d  5. (c) G is conjugate to a finite primitive subgroup of PGLð3; CÞ. Namely, the icosahedral group A5 , the Klein group of order 168, the alternating group A6 , the Hessian group H216 or its subgroup of order 36 or 72. In particular, jGj  360. 2. Remark on (a-i). Let P1 ; ; Pm be all inner and outer Galois points for C and GðCÞ denote the group generated by GPi ði ¼ 1; 2; . . . ; mÞ. The group GðCÞ is called the group generated by automorphisms belonging to all Galois points for C. In [5], we have studied the difference between AutðCÞ and GðCÞ. Referring to [2], if ðCÞ  1 and 0 ðCÞ  1, then C is projectively equivalent to the curve as in Theorem 4 (a-i). We denote the curve by CðdÞ, i.e., CðdÞ : Y Z d1 þ X d þ Y d ¼ 0. If d  5, then P ¼ ð0 : 0 : 1Þ is the only inner Galois point and Q ¼ ð1 : 0 : 0Þ is the only outer Galois point for CðdÞ. We put GP ¼ hi and GQ ¼ hi. Then GðCðdÞÞ ¼ h; i. In [5], we obtain AutðCðdÞÞ ¼ GðCðdÞÞ. Thus Galois points play an important role in studying the automorphism groups of smooth plane curves. 3. Main results. In this section, we first remark on Theorem 4 (a-ii). In general, we have 2dðd  2Þ > 60d. However, clearly 2dðd  2Þ < 60d if d < 32. Hence we consider the case d < 32, and try to construct C with jAutðCÞj ¼ 60d. Let Fi ðX; Y Þ (i ¼ 1; 2; 3) be the homogeneous polynomials of X and Y defined by F30 ¼ X 30 þ 522 ðX 25 Y 5  X 5 Y 25 Þ  10005ðX 20 Y 10 þ X 10 Y 20 Þ þ Y 30 , F20 ¼ X 20  228 ðX 15 Y 5  X 5 Y 15 Þ þ 494X 10 Y 10 þ Y 20 and F12 ¼ XY ðX 10 þ 11X 5 Y 5  Y 10 Þ. For these polynomials, we have well-known facts as follows: Fact 1. Let 5 be a primitive 5th root of unity and put !   0 1 53 0 ¼ ; ¼ ; 1 0 0 52.

(3) No. 6]. Automorphism group computed by Galois points, II. 1. ¼ 2 5  53. 5 þ 51. 1. 1. ð5 þ 51 Þ. !. 0. and I ¼ h; ; i. Then C½X; Y I ¼ C½F30 ; F20 ; F12 . Note that I  ¼ SLð2; 5Þ: the binary icosahedral subgroup of SLð2; CÞ. Under the situation above, our main results are stated as follows: Theorem 5. Let C30 , C20 and C12 be the plane curves defined by C30 : Z 30 þ F30 ðX; Y Þ ¼ 0, C20 : Z 20 þ F20 ðX; Y Þ ¼ 0 and C12 : Z 12 þ F12 ðX; Y Þ ¼ 0. Then jAutðCd Þj ¼ 60d (d ¼ 30; 20; 12). Furthermore, the following hold:  Z15  SLð2; 5Þ, AutðC30 Þ ¼ AutðC20 Þ  ¼ Z5  ðSLð2; 5Þ o Z2 Þ and AutðC12 Þ  ¼ Z3  ðSLð2; 5Þ o Z2 Þ. 4. Proofs of Theorem 5. First of all, we review Theorem 4 (a-ii) from the viewpoint of Galois points. Let C be a smooth plane curve of degree d  4 with a unique Galois point P , G a subgroup of AutðCÞ. Then by Proposition 3, we may assume that the defining equation of C is given by Z d þ Fd ðX; Y Þ ¼ 0 for some homogeneous polynomial Fd ðX; Y Þ of degree d and P ¼ ð0 : 0 : 1Þ. Let P : P2 ! P1 be the projection with the center P . Then P is represented as P ððX : Y : ZÞÞ ¼ ðX : Y Þ. The Galois group GP is represented by 0 1 * 1 0 0 + B C GP ¼ @ 0 1 0 A ; 0 0 d where d is a primitive d-th root of unity. We denote by d this matrix generating GP . Then we get the following commutative diagram as in Theorem 4 (a-ii): 1. 1. C. PBD(2, 1). N. ρ. G. PGL(2, C). 1. G. 1.. In this case N ¼ GP . Thus we get the exact sequence ð]Þ. . 1 ! GP ! G ! G0 ! 1;. where G0  PGLð2; CÞ. Now, we put. B ¼B @. 5 54 pffiffi 5. 53 52 pffiffi 5. 53 52 pffiffi 5.  5pffiffi5 5. 0. 0. 0. 61. 0. 1. C C 0 A;.   4. 1. 53 B ¼@ 0. 0 52. 1 0 C 0A. 0. 0. 1. and. 5. B ’¼@ 0 0. B. 0 ¼ @. 0. 1. 1 0. C 0 A; 1. 0. 0. 1. 0. 1 0. 0. 1. C 0 A; ¼ @. C A;. 1 B. 0 ¼ @. 5. B  ¼@ 0 0 0. where

(4) 12 ¼ 5 . We also put 0 1. 0. 0. B. C 0 A;

(5). 1 1. C A 2 GLð3; CÞ: 1. Referring to [1], we see that the image of I under the natural homomorphism SLð2; CÞ ! PGLð2; CÞ is isomorphic to A5 . Further, we define Sð2; 1Þ :¼ h0 ; 0 ; 0 i  ¼ I. f0 ¼ h; ; 30 i  First we deal with C30 . Put G GLð3; CÞ and H ¼ h; i. Then we can check that 0 1 0 12 5 0 0 5 0 0 ð 4 Þ2 ¼ @ 0 5 0 A and  ¼  @ 0 5 0 A . 0 0 1 0 0 1 So we have  2 H. Furthermore, since 0 ¼ ð2 Þ2 , 0 ¼ ð2 Þ2  and 0 ¼ 2 , we obtain H Sð2; 1Þ. 0 1 1 0 0 We also remark that @ 0 1 0 A 2 Sð2; 1Þ 0 0 1 0 1 1 0 0 and  ¼ @ 0 1 0 A 0 0 , ¼ 0 0 1 0 1 0 12 1 0 0 5 0 0 @ 0 1 0 A0 @ 0 5 0 A . Thus we ob0 0 1 0 0 1 0 1+ * 5 0 0 tain Sð2; 1Þ; @ 0 5 0 A ¼ Sð2; 1Þ  0 0 1 1+ *0 5 0 0 @ 0 5 0 A ¼ H. 0 0 1 Therefore, we have that.

(6) 62. T. HARUI, K. MIURA and A. OHBUCHI. 0 * 1 f0 ¼ H  B G @0. 0 1. 0 0 0 * 5 B ¼ Sð2; 1Þ  @ 0 0 Put. Z. 1 0 + C 0 A 30. we obtain *. 1 0 + C 0 A : 0 1 0 0 30 80 9 1  < 0 0 = f0 \ @ 0 0 A  2 C ¼ :¼ G  : ; 0 0 1 0 1+ 0 5 0 0 0 A; @ 0 5 0 A . Then 1 0 0 5 0 5. *0 1 0 @ 0 1 0 0 f0 =Z  G and G0 :¼ G 0 * 1 B Sð2; 1Þ  @ 0. 0 1 0 + * 1 B C 0A  @0. 0 1. 1 + 0 C 0 A 0 0 1 1 G0 ¼ *0 + 1 0 0 B C @ 0 1 0 A 0 0 1 0 1 0 1 + * 5 0 0 + * 1 0 0 B C B C @ 0 5 0 A  @ 0 1 0 A 0 0 1 0 0 15 0 1 :  * 5 0 0 + B C @ 0 5 0 A 0 0 5  Hence G0 ¼ SLð2; 5Þ  Z15 . In particular, jG0 j ¼ 120 15 ¼ 1800. On the other hand, we see that jGj ¼ 30 60 ¼ 1800 by ð]Þ. Hence G0 ¼ G, which completes the proof of this case. By a similar argument to the above, we can prove the other cases. So, we give the proofs in brief. f0 ¼ h; ; 20 i  For the curve C20 , we put G GLð3; CÞ. We see that 0 1 * 1 0 + 0 B C f0 ¼ Sð2; 1Þ  @ 0 1 0 A G pffiffiffiffiffiffiffi 0 0 1 0 1 0 1 * 5 0 0 + * 1 0 0 + B C B C  @ 0 5 0 A  @ 0 1 0 A : 0. 0. 0 1. 1. Since its center Z is 0 1 0 * 1 0 0 5 B C B 0 1 0 ; @ A @ 0 0 0 1 0. [Vol. 94(A),. 0 0 5 0. 0 5 1. + C 0 A ; 5 0. 0. 1. + B C Sð2; 1Þ  @ 0 1 0 A pffiffiffiffiffiffiffi 0 0 1 0 1 G0 ¼ * 1 0 + 0 B C @ 0 1 0 A 0 0 1 0 0 1 * 5 0 0 + * 1 0 B B C @ 0 5 0 A  @ 0 1 0 0 1 0 0 0 1  * 5 0 0 + B C @ 0 5 0 A 1. 0. 0. 0. 0. f0 =Z  G. where G0 ¼ G Further, since. 0. 1. C 0 A 5. +. ;. 5. 1 + 1 0 0 B C Sð2; 1Þ  @ 0 1 0 A 0 0 1 0 1 SLð2; 5Þ  ¼ * 1 0 + ; 0 B C @ 0 1 0 A 0 0 1 *. 0. we have the following exact sequence: 0 * 1 0 B Sð2; 1Þ  @ 0 1. 1 + 0 C 0 A pffiffiffiffiffiffiffi 0 0 1 0 1 * 1 0 + 0 B C @ 0 1 0 A 0 0 1. 1 ! SLð2; 5Þ !. . ! f

(7) 1g ! 1; 0 B where  : @ 0. 1. A. 0 by 1 7! @ 1 0. C A 7! 2 . The sequence is split  1 0 0. 1 0 A p0ffiffiffiffiffiffiffi . 1. Hence G0  ¼ ðSLð2; 5Þ o Z2 Þ  Z5 . In particular, jG0 j ¼ 120 2 5 ¼ 1200. On the other hand, we see that jGj ¼ 20 60 ¼ 1200 by ð]Þ. Hence G0 ¼ G, which completes the proof of this case. f0 ¼ h; ’i, Finally, for the curve C12 , we put G and K ¼ h; i. We can check that K ¼ Sð2; 1Þ..

(8) No. 6]. Automorphism group computed by Galois points, II. 0. 5 0 Putting " :¼ ð’4 Þ3 ¼ @ 0 5 0 0 f0 ¼ hK; 12 ; "i. Furthermore we G f0 ¼ hKi  h 12 i  h"i G 0 * 1 0 B ¼ Sð2; 1Þ  @ 0 1 * . 0. 1 B @0 0. 1 0 0 A, we obtain 5 get 1. 0 1. + 0 C 0 A pffiffiffiffiffiffiffi 0 0 1 1 0 + * 0 5 0 C B 0 A  @ 0 5. 0. !. 0. 0. 1 0 + C 0 A ; 5. where ! is a cubic root of unity.  ðSLð2; 5Þ o Z2 Þ  Z3 . In particular, Hence G0 ¼ jG0 j ¼ 120 2 3 ¼ 720. On the other hand, we see that jGj ¼ 12 60 ¼ 720 by ð]Þ. Hence G0 ¼ G, which completes the proof of this case.  Acknowledgments. The second author was partially supported by JSPS KAKENHI Grant Number JP26400057. The third author was partial-. 63. ly supported by JSPS KAKENHI Grant Number JP15K04822. References [ 1 ] H. F. Blichfeldt, Finite collineation groups, with an introduction to the theory of groups of operators and substitution groups, Univ. of Chicago Press, Chicago, Ill., 1917. [ 2 ] S. Fukasawa, On the number of Galois points for a plane curve in positive characteristic. III, Geom. Dedicata 146 (2010), 9–20. [ 3 ] T. Harui, Automorphism groups of smooth plane curves, arXiv:1306.5842v2. [ 4 ] K. Miura, Field theory for function fields of singular plane quartic curves, Bull. Austral. Math. Soc. 62 (2000), no. 2, 193–204. [ 5 ] K. Miura and A. Ohbuchi, Automorphism group of plane curve computed by Galois points, Beitr. Algebra Geom. 56 (2015), no. 2, 695–702. [ 6 ] K. Miura and H. Yoshihara, Field theory for function fields of plane quartic curves, J. Algebra 226 (2000), no. 1, 283–294. [ 7 ] H. Yoshihara, Function field theory of plane curves by dual curves, J. Algebra 239 (2001), no. 1, 340–355..

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