1. Hartogs Extension Theorem
The following is a classical result known as Hartogs Extension Theorem.
Theorem I. ([2]) Let n≧ 2 and suppose that 0 < rj< 1 for 1≦j≦n. Then every holomorphic function f on the domain
H(r) = {z∈Cn; |zj| < 1 for 1≦j≦n−1, rn< |zn| < 1}
∪{z∈Cn; |zj| < rj for 1≦j≦n−1, |zn| < 1}.
has a unique holomorphic extension ˜f to the polydiscΔ(0 ; 1).
This theorem leads us to the following which has somewhat excessive assumptions, and which induces, in the next section, more general notions of pseudoconvexity than Hartogs one.
Theorem I′. Let n≧2 and 0 < ri< 1 for 1≦i≦n, and we set
H(r) = {z∈Cn; |zi| < rifor 1≦i≦q, |zj| < 1 for q + 1≦j≦n}
Hk={z∈Cn; |zi| < 1 for 1≦i≦q, |zj| < 1 for q + 1≦j≦n and j ≠k, rk< |zk| < 1}, for q + 1≦k ≦n.
Then every holomorphic function f on the domain H = H(r) ∪
( ∪
Hk)
has a unique holomorphic extension ˜f to the polydiscΔ(0 ; 1).2. Hartogs Pseudoconvexity
The following defnitions are seen in [2]. We call the pair (Γ,^Γ) of the following compact sets Γ,^Γ ⊂
(
Memoirs of the Faculty of Education and Human Studies)
Akita University(Natural Science)
62,1−8(2007)
Remarks on Hartogs Pseudoconvexity of Domains in C
nToshio UDA
Abstract
We remark Hartogs pseudoconvexity of domains in Cn. The notion of Hartogs q-pseudoconvexity is introduced, in this paper, and we study the relationship between various pseudoconvexity.
n k=q+1
Cnthe Hartogs frame in Cn.
Γ0 = {z∈Cn; zi= 0 for 1≦i≦n−1, |zn|≦1},
Γn = {z∈Cn; zi= 0 for 1≦i≦n−2, |zn−1|≦1, |zn| = 1}, Γ = Γ0∪ Γn,
^Γ = {z∈Cn; zi= 0 for 1≦i≦n−2, |zj|≦1 for n−1≦j≦n}.
A pair (Γ*, ^Γ*) of compact sets Γ*,^Γ* ⊂ Cnis called a Hartogs figure if there exists a biholomorphic map F :^Γ→^Γ*, such that F(Γ) =Γ*.
The following result is obvious by Theorem I.
Proposition 1. ([2]) Let (Γ*, ^Γ*) be a Hartogs figure. Then every f∈O(Γ*) has a holomorphic extension
˜f ∈O(^Γ*).
A domain D⊂ Cnis called Hartogs pseudoconvex if for every Hartogs figure (Γ*, ^Γ*) with Γ* ⊂ D one has ^Γ* ⊂D as well.
Now, according to Theorem I′, we shall define more general notions. Let 0 < q≦n−1. The pair (Γ,^Γ) of compact sets Γ,^Γ⊂ Cndefined as follows is called the Hartogs q - frame in Cn.
Γ0 = {z∈Cn; |zi| = 0 for 1≦i≦q, |zj| ≦1 for q + 1 ≦j ≦ n},
Γk = {z∈Cn; |zi| = 0 for 1≦i≦q−1, |zj| ≦1 for q ≦j ≦ n and j≠k, |zk|=1 }, for q+1≦ k≦n
Γ = Γ0∪
( ∪
Γk)
^Γ = {z∈Cn; |zi| = 0 for 1≦i≦q−1, |zj|≦1 for q≦j≦n}.
A pair (Γ*, ^Γ*) of compact sets Γ*, ^Γ* ⊂Cnis called a Hartogs q - figure if there exists a biholomor- phic map F : ^Γ→ ^Γ*, such that F(Γ) = Γ*.
A domain D⊂Cnis called Hartogs q - pseudoconvex if for every Hartogs q - figure (Γ*, ^Γ*) with Γ*
⊂D one has ^Γ* ⊂D as well. The case q = n−1, it is Hartogs pseudoconvex.
By Theorem I′we have
Proposition 2. Let (Γ*, ^Γ*) be a Hartogs q - figure. Then every f∈O(Γ*) has a holomorphic extension
˜f ∈O(^Γ*).
Hartogs q - pseudoconvexity is a notion which is weaker than Hartogs pseudoconvexity as follows.
Proposition 3. Every Hartogs pseudoconvex domain is Hartogs q - pseudoconvex for 0 < q≦n−1.
n k=q+1
Proof. Let D⊂Cnbe a Hartogs pseudoconvex domain, (Γ′, ^Γ′) the Hartogs frame and (Γ,^Γ) the Har- togs q - frame. For a biholomorphic map F :^Γ → F〜 (^Γ) with F(Γ) ⊂D, we shall show that F(^Γ) ⊂D.
For any fixed (ζ0q, . . . ,ζ0n−2), |ζ0j|≦1, it is suffcient to show that if |ζn−1|≦1 and |ζn|≦1, then we have
F(0″,ζ0n−1,ζ0q+1, . . . , ζ0n−2,ζ0q,ζn) ∈D, where 0″= (0, . . . , 0) ∈Cq−1.
Let G be a biholomorphic map defined by
G : (0″, 0, . . . 0, ζn−1,ζn) (0″,ζn−1,ζ0q+1, . . . ,ζ0n−2,ζ0q,ζn).
We set ζn−1= 0 and |ζn|≦1, then G(Γ′0) ⊂ Γ0. We set |ζn−1|≦1 and |ζn| = 1, then G(Γ′n) ⊂ Γn. So we have G(Γ′) = G(Γ′0∪Γ′n) ⊂ Γ0∪ Γn⊂ Γ. It follows, for a biholomorphic map F G, F G(Γ′) ⊂ F(Γ) ⊂ D. Since D is Hartogs pseudoconvex, we have F G(^Γ′) ⊂ D. Hence, for |ζn−1|≦ 1 and
|ζn|≦1, we have
F(0″,ζn−1,ζ0q+1, . . . , ζ0n−2,ζ0q,ζn) = F。G(0″, 0, . . . , 0, ζn−1,ζn) ∈F。G(^Γ′) ⊂D
Thus D is Hartogs q - pseudoconvex.
More generally, we have
Proposition 4. Let q′< q. If D⊂Cnis Hartogs q - pseudoconvex, then D is Hartogs q′- pseudoconvex.
Proof. Let (Γ′, ^Γ′) with Γ′= Γ′0 ∪(
∪
Γ′k) be the Hartogs q′- frame, (Γ,^Γ) the Hartogs q - frame and F :^Γ′→ F〜 (^Γ′) a biholomorphic map with F(Γ′) ⊂ D. We shall show F(^Γ′) ⊂ D. It saffices to show that for any fixed (ζ0q′, . . . ,ζ0q−1) with |ζ0j|≦1, if |ζj|≦1 for q≦j≦n, thenF(0″,ζq,ζ0q′+1, . . . ,ζ0q−1,ζ0q′,ζq+1, . . . ,ζn) ∈D,
Let G be a biholomorphic map defined by
G : (0″, 0, . . . , 0, ζq, . . . ,ζn) (0″,ζq,ζ0q′+1, . . . ,ζ0q−1,ζ0q′,ζ0q+1, . . . ,ζn),
where 0″= (0, . . . , 0)∈Cq′−1. We set |ζj|≦1 for q≦j≦n and j≠k, and |ζk| = 1, then G(Γk) ⊂ Γ′k for q + 1≦k≦n. And we set ζq= 0 and |ζj|≦1 for q + 1≦j≦n, then G(Γ0) ⊂ Γ′0. Since
G(Γ) = G
(
Γ0∪( ∪
Γk))
⊂ Γ′0∪( ∪
Γ′k)
⊂ Γ′,q
︶ n−1
︶
q′
︶
q−1
︶
q
︶
n k=q+1
n k=q+1 q
︶
q
︶
n−1︶
q′
︶
q′
︶
q
︶ n
k=q′+1
F G(Γ) ⊂ F(Γ′) ⊂ D. Hence, since D is Hartogs q - convex, we have F G(^Γ) ⊂ D. Thus, if |ζj|≦1 for q ≦j ≦n, we have
F(0″, (0″,ζq,ζ0q′+1, . . . ,ζ0q−1,ζ0q′,ζq+1, . . . ,ζn) = F G(0″, 0, . . . , 0, ζq, . . . ,ζn) ∈F G(^Γ) ⊂D, as desired.
A domain D⊂Cnis said to satisfy Theorem of continuity (C) of order q if we set, for 0 < r′< r and 0 <
ρ′< ρ,
Δ0= {z∈Cn; |zi| < r′for 1≦i≦q, |zj| < ρfor q + 1≦j≦n},
Δk= {z∈Cn; |zi| < r for 1≦i≦q, |zj| < ρfor q + 1≦j≦n and j≠k, ρ′< |zk| < ρ}, for q + 1≦k≦n.
Δ = {z∈Cn; |zi| < r for 1≦i≦q, |zj| < ρfor q + 1≦j≦n},
then Δ0∪
( ∪
Δk)
⊂D follows Δ ⊂D as well (cf. [3]).Proposition 5. If D ⊂ Cn satisfies Theorem of continuity (C) of order q, then D is Hartogs q - pseudo- convex.
Proof. Let (Γ,^Γ) be the Hartogs q - frame and F :^Γ→ F〜 (^Γ) a biholomorphic map with F(Γ) ⊂D. For sufficiently small 0 < r′< r and for sutable ρ′< 1 < ρ, if we set
Δ0= {z∈Cn; |zi| < r′for 1≦i≦q, |zj| < ρfor q + 1≦j≦n},
Δk= {z∈Cn; |zi| < r for 1≦i≦q, |zj| < ρfor q + 1≦j≦n and j≠k, ρ′< |zk| < ρ}, for q + 1≦k≦n.
then we have F(Δ0) ⊂D and F(Δk) ⊂D, q + 1≦k≦n. Since D satisfies Theorem of continuity (C) of order q, a polydisc
Δ = {z∈Cn; |zi| < r for 1≦i≦q, |zj| < ρfor q + 1≦j≦n}
satisfies that F(Δ) ⊂D. Hence
^Γ= {z∈Cn; |zi| = 0 for 1 ≦i≦q−1, |zj| ≦ 1 for q≦j≦n}
satisfies F(^Γ) ⊂D. Thus D is Hartogs q - pseudoconvex, as desired.
Now, D⊂Cnis said to have Ckboundary at p ∈∂D if there exist an open neighborhood U of p and a
n k=q+1
q
︶ q′
︶ q−1
︶ q′
︶
real valued function r ∈Ck(U) with the following properties:
U∩D = {z ∈U ; r(z) < 0} and dr(z)≠0 for z ∈U.
If D has Ckboundary at every point p ∈∂D, D is said to have Ckboundary.
Notice that this includes
U∩∂D = {z ∈U ; r(z) = 0}, U−−D = {z ∈U ; r(z) > 0}.
The function r ∈Ck(U) is called a (local) defining function. If U = U(∂D), r is called a defining function.
Theorem 6. Let D ⊂Cn be Hartogs q - pseudoconvex. Suppose D has C1 boundary at p ∈∂D. Then there exists no complex n−q dimensional submanifold M such that p ∈M and M - {p} ⊂D.
Proof. We may assume n≧2. We shall show that the existence of M with the properties stated in the theorem implies that D is not Hartogs q - pseudoconvex at p ∈∂D.
Given such an M, after applying a holomorphic coordinate change in a neighborhood U of p, we may as- sume that
p = 0, M∩U = {z ∈U ; zi= 0 for 1≦i≦q, |zj| < 2δfor q + 1≦j≦n},
and that defining function r(z) for D satisfies
r(z1, . . . , zn) = xq−ϕ(z1, . . . , zq−1, yq, zq+ 1, . . . , zn), dϕ0= 0.
Since M∩U−{0} ⊂D, for q + 1≦k≦n,
r(0, . . . , 0, zq + 1, . . . , zn) = −ϕ(0, . . . , 0, zq + 1, . . . , zn) < 0,
for |zj| < 2δ(j≠k) and 0 < |zk| < 2δ. Hence
ϕ(0, . . . , 0, zq + 1, . . . , zn) ≧0, for |zj| < 2δ, q + 1≦j≦n.
The continuity of r follows that, for a sufficiently smallη> 0,
r(0, . . . , 0, zq, zq + 1, . . . , zn) < 0, (1)
where |zq+η|≦η, |zj|≦δfor q + 1≦j≦n and j≠k, |zk| =δ,
q
︶
and that
r(0, . . . , 0, −η, zq + 1, . . . , zn) < 0, for |zj|≦δ(q + 1≦j≦n). (2) From (1), if we set
Kk= {(0, . . . , 0, zq, zq + 1, . . . , zn) ;
|zq+η|≦η, |zj|≦δfor q + 1≦j≦n and j≠k, |zk| =δ},
then Kk⊂D∩U for q + 1≦k≦n. And from (2), if we set
K0= {(0, . . . ,−η, zq + 1, . . . , zn) ; |zj|≦δfor q + 1≦j≦n},
then K0⊂D∩U. We set
Γ* = K0∪
( ∪
Kk)
^Γ* = {(0, . . . , 0, zq, zq + 1, . . . , zn) ; |zq+η|≦η, |zj|≦δfor q + 1≦j≦n}.
Let F : (t1, . . . , tn) (z1, . . . , zn) be a biholomorphic map defined by
zi= tifor i≦q−1, zq=ηtq−ηand zj=δtjfor q + 1≦ j≦n.
Then F(^Γ) =^Γ* and F(Γ) = Γ*, so (Γ*,^Γ*) is a Hartogs q - figure in U. Then we have Γ*⊂ D, while
^Γ* ⊂/ D since 0∈^Γ*. Thus D is not Hartogs q - pseudoconvex, as desired.
3. Levi pseudoconvexity
Let r be a defining function for D at p ∈∂D. A complex tangent space TpC(∂D) at p ∈∂D is given by
TpC(∂D) = {z ∈Cn; ∂rp(z) : =
Σ
―(p)zi= 0}.Notice that this space does not depend on the choice of the defining function r.
A domain D ⊂Cn with C2 boundary is called Levi pseudoconvex at p if the Levi condition holds for some C2defining function r for D near p∈∂D;
Lq(r ; z) : =
Σ
―― (q)zj-zk≧0, for all z∈TpC(∂D) and q∈U(p).D is said to be Levi pseudoconvex if the Levi condition holds at all points p∈∂D.
n j,k=1
∂2r
∂zj∂-zk
n i=1
∂r
∂zi q
︶
n k=q+1
q
︶
Theorem 7. ([2]) If D ⊂Cn is Hartogs pseudoconvex and D has C2 boundary, then D is Levi pseudocon- vex.
A domain D⊂ Cnwith C2boundary is said to be Levi q - pseudoconvex at p∈∂D if there exists a sub- space E⊂TpC(∂D) with dim E≧n−q + 1, such that Levi condition holds on E; Lp(r ; z) ≧0 for all z∈E.
Theorem 8. Let D have C1boundary at p ∈∂D. If there exists a complex submanifold M with dimM = n
−q in a neighborhood U of p such that p ∈M and M ∩U−{p}⊂D, then D is not Levi q - pseudocon- vex at p∈∂D.
Proof. Given a subspace E ⊂TpC(∂D) with dim E≧n−q + 1 . We shall show that Lp(r ; t) < 0 for some t∈E.
After applying a holomorphic change of coordinates we can assume that
p = 0, M = {z∈U ; z1= · · · = zq= 0}, E= {t∈TpC(∂D) ; t1= · · · = tq−1= 0}.
From the Taylor expansion of a defining function r at 0 we obtain
r(0, . . . , 0, zq + 1, . . . , zn) = 2Re h(z) + L0(r ; z) + o(|z|2) < 0,
where h(z) =
Σ
=―(0)zj+―Σ
―― (0)zjzk. For a vectort = (0, . . . , 0, tq, . . . , tn)∈E with tq= 0 and h(t) = 0, we obtain
r(0, . . . , 0, tq+1, . . . , tn) = L0(r ; t) + o(|t|2) < 0.
Since |L0(r ; t)| = O(|t|2), if, for a sufficiently small ε> 0 and t ∈B(0 ; ε) ⊂U, we obtain L0(r ; t) < 0. Thus D is not Levi q - pseudoconvex at 0∈∂D, as desired.
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DEPARTMENT OFMATHEMATICS
FACULTY OFEDUCATION ANDHUMANSTUDIES
AKITAUNIVERSITY
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