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ISSN: 1072-6691. URL: http://ejde.math.txstate.edu or http://ejde.math.unt.edu ftp ejde.math.txstate.edu (login: ftp)

EXISTENCE AND UNIQUENESS OF GLOBAL SOLUTIONS TO A MODEL FOR THE FLOW OF AN INCOMPRESSIBLE,

BAROTROPIC FLUID WITH CAPILLARY EFFECTS

DIANE L. DENNY

Abstract. We study the initial-value problem for a system of nonlinear equa- tions that models the flow of an inviscid, incompressible, barotropic fluid with capillary stress effects. We prove the global-in-time existence of a unique, clas- sical solution to this system of equations, with a small initial velocity gradient.

The key to the proof lies in using anL2 estimate for the densityρ, and us- ing the smallness of the initial velocity gradient, to obtain uniqueness for the density.

1. Introduction

In this paper, we consider equations which arise from a model of the multi- dimensional flow of an incompressible, barotropic fluid with capillary stresses.

When viscosity is neglected, these equations reduce to the following system, written in terms of the densityρ, the pressurep, and velocityv:

Dv

Dt +ρ−1∇p=c∇∆ρ, (1.1)

∇ ·v= 0. (1.2)

Here c is a coefficient of capillarity which is a small, positive constant, and the material derivative D/Dt = ∂/∂t+v· ∇. The termc∇∆ρ arises from capillary stresses, as described in the theory of Korteweg-type materials developed by Dunn and Serrin [4]. The fluid’s thermodynamic state is determined by the density ρ.

The pressure p is determined from the density by an equation of statep = ˆp(ρ).

In related work, the existence of a solution to a similar system of equations for the case of viscous fluid flow, which also includes a hyperbolic equation for density and a parabolic equation for temperature, has been proven by Hattori and Li [7, 8], and by Bresch, Desjardins, and Lin [2]. Anderson, McFadden and Wheeler [1] have given a review of related theories and applications to diffuse-interface modelling.

In this model, it will be shown that ∂ρ/∂t, ∇ρ, and∇v are small, for suitable initial data. Although the conservation of mass equation is only approximately satisfied, the model equations (1.1), (1.2) might be useful as an approximation in

2000Mathematics Subject Classification. 35A05.

Key words and phrases. Existence; uniqueness; capillary; incompressible;

inviscid fluid.

c

2007 Texas State University - San Marcos.

Submitted August 10, 2006. Published March 6, 2007.

1

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the case of almost constant density, and nearly incompressible fluid flow with a small velocity gradient. We write equation (1.1) equivalently as

Dv

Dt +ρ−10(ρ)∇ρ=c∇∆ρ (1.3) The purpose of this paper is to prove the existence of a unique, global-in-time, classical solutionv,ρto equations (1.2), (1.3) with suitable initial velocity datav0∈ Hs, under periodic boundary conditions. That is, we choose for our domain the N- dimensional torusTN, whereN= 2 or N= 3. The proof of the existence theorem is based on the method of successive approximations, in which an iteration scheme, based on solving a linearized version of the equations, is designed and convergence of the sequence of approximating solutions to a unique solution satisfying the nonlinear equations is sought. The framework of the proof follows one used, for example, by A. Majda for proving the existence of a solution to a system of conservation laws [10]. Embid [5] also uses the same general framework to prove the existence of a solution to equations for zero Mach number combustion. Under this framework, the convergence proof is presented in two steps. In the first step, we prove uniform boundedness of the approximating sequence of solutions in a high Sobolev norm.

The second step is to prove contraction of the sequence in a low Sobolev norm.

Standard compactness arguments will be used to finish the proof. The key to the proof lies in using anL2 estimate for the densityρ, and using the smallness of the initial velocity gradient, to obtain uniqueness for the density.

2. A priori estimates

The main tools utilized in the existence proof are a priori estimates. We will work with the Sobolev spaceHs(Ω) (wheres≥0 is an integer) of real-valued functions in L2(Ω) whose distribution derivatives up to ordersare inL2(Ω), with norm given by kfk2s=P

|α|≤s

R

|Dαf|2dxand inner product (f, g)s=P

|α|≤s

R

(Dαf)·(Dαg)dx.

Here, we adopt the standard multi-index notation. For convenience, we will denote derivatives byfα=Dαf. We will let Df denote the gradient off. Also, we will denote theL2 inner product by (f, g) =R

f·g dx. We will use standard function spaces. L([0, T], Hs) is the space of bounded measurable functions from [0, T] into Hs(Ω), with the normkfk2s,T = ess sup0≤t≤Tkf(t)k2s. C([0, T], Hs) is the space of continuous functions from [0, T] intoHs(Ω). The following technical lemmas will be needed for the proof of the existence of a classical solution to the initial-value problem for the system (1.2), (1.3).

Lemma 2.1 (Standard Calculus Inequalities).

(a) If f ∈Hs1(Ω), g∈Hs2(Ω) and s3 = min{s1, s2, s1+s2−s0} ≥0, where s0= [N2] + 1, thenf g∈Hs3(Ω), and kf gks3 ≤Ckfks1kgks2. We note that s0= 2forN = 2 orN = 3.

(b) If f ∈ Hs(Ω), g ∈ Hs−1(Ω)∩L(Ω), Df ∈ L(Ω), and |α| ≤ s, then kDα(f g)−f Dαgk0≤C(|Df|Lkgks−1+|g|LkDfks−1).

In (a) the constant C depends on s1, s2, and Ω, while in (b) the constant C depends onsand Ω. These inequalities are well known. Proofs may be found, for example, in [9, 11].

Lemma 2.2 (Low-Norm Commutator Estimate). If Df ∈Hr1(Ω),g∈Hr−1(Ω), wherer1= max{r−1, s0},s0= [N2]+1, then for anyr≥1,f, gsatisfy the estimate

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kDα(f g)−f Dαgk0≤CkDfkr1kgkr−1, wherer=|α|, and the constant C depends onr,Ω.

Proof. The proof is based on the Sobolev calculus inequalities from Lemma 2.1. We consider separately the casesr−1< s0andr−1≥s0, wherer≥1. Ifr−1< s0, we expand the termDα(f g) using the Leibniz rule and then apply inequality (a) from Lemma 2.1 to obtain the desired estimate. If r−1≥s0, we apply the inequality (b) from Lemma 2.1 and the Sobolev inequality |h|L ≤Ckhks0 fors0= [N2] + 1, to obtain the estimate for this case. Combining these two results then completes

the proof.

Lemma 2.3. If u,v,a,f, andρare sufficiently smooth in Du/Dt=−a∇ρ+c∇∆ρ+f,

∇ ·u= 0,

where u(x,0) = u0(x), ∇ ·u0 = 0, Ω = TN, where N = 2,3, and where c is a positive constant, D/Dt=∂/∂t+v·∇, and∇ ·v= 0, then for anyr≥1,Duand usatisfy the estimates

kDuk2r−1≤Ce2t(1+te2teβ(t)kDvk2r1,T)(kDu0k2r−1+ Z t

0

(kfk2r+kDak2r1k∇ρk2r−1)dτ) and

kuk2r≤e2tku0k20+Ce2t(1 +te2teβ(t)kDvk2r1,T)(kDu0k2r−1 +

Z t

0

(kfk2r+kDak2r1k∇ρk2r−1)dτ)

where β(t) =te2tkDvk2r1,T. Here r1 = max{r−1, s0}, and s0 = [N2] + 1 = 2 for N = 2,3. The constant C depends onr,Ω.

Proof. First, we obtain an L2 estimate for u. Let ¯ρ = ρ− |Ω|1 R

ρdx. We then compute

1 2

d

dtkuk20= (ut,u)

=−(v· ∇u,u)−(a∇ρ,u) +c(∇∆ρ,u) + (f,u)

= 1

2(u∇ ·v,u) + (a¯ρ,∇ ·u) + ( ¯ρ∇a,u)−c(∆ρ,∇ ·u) + (f,u)

≤ |Da|Lkuk0kρk¯ 0+kfk0kuk0

≤ kuk20+1

2|Da|2Lkρk¯ 20+1 2kfk20

(2.1)

where we used the facts that ∇ ·u = 0, and ∇ ·v = 0. And we used Cauchy’s inequality. After applying Gronwall’s inequality, we obtain the estimate

kuk20≤e2tku0k20+e2t Z t

0

C(|Da|2Lkρk¯ 20+kfk20)dτ, (2.2) Next, we obtain an estimate forkDuk2r−1. After applying the operatorDγ+αto the equation foru, where 0≤ |α| ≤r−1 and|γ|= 1, we obtain

Duγ+α

Dt =−a∇ργ+α+c∇∆ργ+α+Fγ+α (2.3)

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whereFγ+α=fγ+α−[(v· ∇u)γ+α−v· ∇uγ+α]−[(a∇ρ)γ+α−a∇ργ+α]. For (2.3), estimate (2.1) becomes

1 2

d

dtkuγ+αk20≤ kuγ+αk20+1

2|Da|2Lk¯ργ+αk20+1

2kFγ+αk20 (2.4) Next, we estimatekFγ+αk20. Using the commutator estimate from Lemma 2.2, we obtain

kFγ+αk20≤Ckfγ+αk20+Ck(v· ∇u)γ+α−v· ∇uγ+αk20 +Ck(a∇ρ)γ+α−a∇ργ+αk20

≤Ckfk2k+CkDvk2k

1kDuk2k−1+CkDak2k

1k∇ρk2k−1

(2.5)

where k = |γ+α|, k1 = max{k−1, s0}, and s0 = [N2] + 1. Here, we used the triangle inequality and Cauchy’s inequality. Substituting estimate (2.5) into (2.4) yields

1 2

d

dtkuγ+αk20≤ kuγ+αk20+1

2|Da|2Lkρ¯γ+αk20+Ckfk2k +CkDvk2k1kDuk2k−1+CkDak2k1k∇ρk2k−1 Applying Gronwall’s inequality yields the following:

kuγ+αk20≤e2tk(u0)γ+αk20+Ce2t Z t

0

|Da|2Lkρ¯γ+αk20+kfk2k +kDvk2k1kDuk2k−1+kDak2k1k∇ρk2k−1

≤Ce2tkDu0k2k−1+Ce2t Z t

0

|Da|2Lkρk¯ 2k+kfk2k +kDvk2k1kDuk2k−1+kDak2k1k∇ρk2k−1

dτ,

(2.6)

where|γ|= 1, and |γ+α|=k≥1, andk1= max{k−1, s0}, withs0= [N2] + 1.

After adding the above inequality (2.6) over allγ, where|γ|= 1, and then adding over allα, where 0≤ |α| ≤r−1, we obtain the estimate

kDuk2r−1≤Ce2tkDu0k2r−1+Ce2t Z t

0

|Da|2Lkρk¯ 2r+kfk2r +kDvk2r1,TkDuk2r−1+kDak2r1k∇ρk2r−1

dτ,

(2.7)

where r1 = max{r−1, s0}, and where s0 = [N2] + 1 = 2 for N = 2,3. Here, we used the fact thatP

0≤|α|≤r−1

P

|γ|=1kuγ+αk20=P

0≤|α|≤r−1

PN i=1

R

|∂u∂xα

i|2dx= P

0≤|α|≤r−1kDuαk20=kDuk2r−1. After applying Gronwall’s inequality to (2.7), we get

kDuk2r−1≤Ce2t(1 +te2teβ(t)kDvk2r1,T)(kDu0k2r−1 +

Z t

0

(|Da|2Lkρk¯ 2r+kfk2r+kDak2r1k∇ρk2r−1)dτ),

(2.8)

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withβ(t) =te2tkDvk2r1,T. Adding the estimates (2.2), (2.8), we obtain kuk2r≤(kuk20+CkDuk2r−1)

≤e2tku0k20+Ce2t(1 +te2teβ(t)kDvk2r1,T)(kDu0k2r−1 +

Z t

0

(|Da|2Lkρk¯ 2r+kfk2r+kDak2r

1k∇ρk2r−1)dτ)

≤e2tku0k20+Ce2t(1 +te2teβ(t)kDvk2r1,T)(kDu0k2r−1 +

Z t

0

(kfk2r+kDak2r1k∇ρk2r−1)dτ)

wherer1= max{r−1, s0}, and wheres0= [N2] + 1 = 2 forN = 2,3. Here, we used Poincar´e’s inequality to estimatekρk¯ 20≤Ck∇ρk20, andkρk¯ 2r≤C(k∇ρk2r−1+kρk¯ 20)≤ Ck∇ρk2r−1. We also used Sobolev’s lemma |h|L ≤Ckhks0 where s0 = [N2] + 1.

Using the estimate|Da|2Lkρk¯ 2r≤CkDak2r1k∇ρk2r−1in the right-hand side of (2.8)

completes the proof.

Lemma 2.4. Let u, w be C1 functions on a bounded, open, connected, convex domainΩ. And letu(x0) =w(x0)at a single, fixed pointx0∈Ω. Thenu−wand usatisfy the estimates

ku−wk20≤Ck∇(u−w)k22, kuk20≤C0kwk20+C0k∇wk22+C0k∇uk22 Here C,C0 are constants which depend only on Ω.

Proof. First, we obtain an estimate for ku−wk20. From the mean value theorem, and sinceu−w is sufficiently smooth on the convex domain Ω, we have

(u−w)(x) = (u−w)(x0) +∇(u−w)(x)·(x−x0)

wherex is a point on the line segment joining the pointsx0∈Ω andx∈Ω.

Since we are given thatu(x0) =w(x0), at a single fixed pointx0∈Ω, it follows that

(u−w)(x) =∇(u−w)(x)·(x−x0) Taking the absolute value of both sides yields

|(u−w)(x)|=|∇(u−w)(x)·(x−x0)|

≤ |∇(u−w)|L|x−x0|

≤C|∇(u−w)|L

HereCdepends only on Ω. Squaring|(u−w)(x)|and integrating over Ω, and using the above inequality, yields

Z

|(u−w)(x)|2dx≤C Z

|∇(u−w)|2Ldx≤Ck∇(u−w)k22

where we used Sobolev’s inequality |h|L ≤Ckhks0, where s0 = [N2] + 1 = 2 for N = 2,3 andC depends on Ω.

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Next, we obtain an estimate for kuk20. From using the triangle inequality and Cauchy’s inequality, and from using the previous estimate forku−wk20, we obtain

kuk20≤Ckwk20+Cku−wk20

≤Ckwk20+Ck∇(u−w)k22

≤C0kwk20+C0k∇wk22+C0k∇uk22

HereC0 is a constant which depends only on Ω.

Lemma 2.5. Ifg is a sufficiently smooth function on the domainΩ =TN, theng satisfies the estimate k∇gk2r≤Ck∆gk2r−1 where r≥1andC depends onr.

Proof. First, we integrate−∆g by parts with the function ¯g=g−|Ω|1 R

g dxover Ω =TN, to obtain

(∇g,∇g) =−(∆g,¯g)

≤C()k∆gk20+k¯gk20

≤C()k∆gk20+Ck∇gk20

where we used Cauchy’s inequality with . We also used Poincar´e’s inequality to estimate k¯gk20 ≤ Ck∇gk20. Then Dα is applied, yielding −∆gα, which is then integrated by parts with the functiongαover Ω =TN, to obtain

(∇gα,∇gα) =−(∆gα, gα)

= (∆gα−γ, gα+γ)

≤C()k∆gα−γk20+kgα+γk20

≤C()k∆gk2k−1+Ck∇gk2k

where|γ|= 1, and|α|=k≥1. Here, we used Cauchy’s inequality with. Adding these two inequalities, for |α|=k≤r, and moving the terms containing to the

left-hand side, completes the proof.

Lemma 2.6. If u,v,a,f, andρare sufficiently smooth in the equation

2ρ=1

c∇ ·(a∇ρ) +1

c∇ ·(v· ∇u)−1

c∇ ·f (2.9)

where c is a positive constant, ∇ ·u = 0, ∇ ·v = 0, a(x, t) ≥ c1, with c1 > 0, and where Ω =TN, N = 2,3, and r ≥ 1, we obtain the following estimates for k∆ρk20+k∇ρk20 and fork∇ρk2r+1

k∆ρk20+k∇ρk20≤C|Dv|2LkDuk20+Ckfk20, k∇ρk2r+1≤C(k∆ρk2r+k∇ρk2r)

≤CkDak2r

1k∇ρk2r−1+Ckfk2r−1+CkDvk2r

2+1kDuk2r−1

wherer1= max{r−1, s0},r2= max{r−2, s0}, withs0= [N2] + 1, andN = 2,3.

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Proof. First, we obtain anL2estimate. Integrating equation (2.9) by parts with ¯ρ, where ¯ρ=ρ−|Ω|1 R

ρdx, yields

(∆ρ,∆ρ) = (∆2ρ,ρ) =¯ 1

c(∇ ·(a∇ρ),ρ) +¯ 1

c(∇ ·(v· ∇u),ρ)¯ −1

c(∇ ·f,ρ)¯

=−1

c(a∇ρ,∇ρ) +1

c(∇vT :∇u,ρ) +¯ 1 c(f,∇ρ)

≤ −c1

ck∇ρk20+C()|Dv|2LkDuk20+kρk¯ 20+C()kfk20+k∇ρk20

≤ −c1

ck∇ρk20+C()|Dv|2LkDuk20+k∇ρk20+C()kfk20+k∇ρk20 where we used Cauchy’s inequality with, and where we used the fact thata(x, t)≥ c1 wherec1 >0. We also used Poincar´e’s inequality to estimatekρk¯ 20 ≤Ck∇ρk20. And we used the fact that ∇ ·(v· ∇u) =∇vT :∇u, because ∇ ·u= 0. Moving thek∇ρk20 terms to the left-hand side yields the estimate

k∆ρk20+k∇ρk20≤C|Dv|2LkDuk20+Ckfk20 (2.10) Next, after applyingDαto the equation (2.9), we obtain the equation:

2ρα= 1

c∇ ·(a∇ρα) +1

c∇ ·(v· ∇u)α+Fα (2.11) whereFα=−1c∇ ·fα+1c[∇ ·(a∇ρ)α− ∇ ·(a∇ρα)]. Integrating equation (2.11) by parts withρα, when|α| ≥1, yields

(∆ρα,∆ρα) = (∆2ρα, ρα)

=1

c(∇ ·(a∇ρα), ρα) +1

c(∇ ·(v· ∇u)α, ρα) + (Fα, ρα)

=−1

c(a∇ρα,∇ρα) +1

c((∇vT :∇u)α, ρα) + (Fα, ρα)

=−1

c(a∇ρα,∇ρα)−1

c((∇vT :∇u)α−γ, ρα+γ) + (Fα, ρα)

≤ −c1

c (∇ρα,∇ρα) +Ck(∇vT :∇u)α−γk0α+γk0+|(Fα, ρα)|

≤ −c1

c (∇ρα,∇ρα) +C()k(∇vT :·∇u)α−γk20+kρα+γk20+|(Fα, ρα)|

(2.12) where|γ|= 1. Here, we used Cauchy’s inequality with, and we used the fact that a(x, t)≥c1 where c1 >0. Next, we estimate the terms on the right-hand side of the above inequality. First, we estimate k(∇vT : ∇u)α−γk20. When |α| = 1, we chooseγ=αand obtain

k(∇vT :∇u)α−γk20=k(∇vT :∇u)k20≤C|Dv|2LkDuk20 (2.13) Next, we use the triangle inequality and the commutator estimate from Lemma 2.2 to estimatek(∇vT :∇u)α−γk20, when|α|>|γ|= 1, obtaining

k(∇vT :∇u)α−γk20≤C(k∇vT :∇uα−γk20+k(∇vT :∇u)α−γ− ∇vT :∇uα−γk20)

≤C|Dv|2LkDuα−γk20+CkD2vk2k2kDuk2k−2

≤CkDvk2k2+1kDuk2k−1,

(2.14) Here |γ|= 1, k=|α|, andk2 = max{k−2, s0}, withs0= [N2] + 1. Here, we also used the Sobolev inequality|h|L ≤Ckhks0.

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Next, we estimate the following term from the right-hand side of (2.12), obtaining kρα+γk20≤Ck∇ρk2k (2.15) where|γ|= 1 and |α|=k.

Next, we use the commutator estimate from Lemma 2.2 to estimate |(Fα, ρα)|

from the right-hand side of (2.12), obtaining

|(Fα, ρα)| ≤ |1

c(∇ ·fα, ρα)|+|1

c([∇ ·(a∇ρ)α− ∇ ·(a∇ρα)], ρα)|

=|1

c(fα−γ,∇ρα+γ)|+|1

c([(a∇ρ)α−a∇ρα],∇ρα)|

≤Ckfkk−1k∇ρkk+1+CkDakk1k∇ρkk−1k∇ρkk

≤C()kfk2k−1+k∇ρk2k+1+C()kDak2k1k∇ρk2k−1+k∇ρk2k

(2.16)

where |γ| = 1, k =|α|, and k1 = max{k−1, s0}, with s0 = [N2] + 1. Again, we used Cauchy’s inequality with. Substituting (2.13)-(2.16) into (2.12), and adding (2.12) over|α|=k≤r, including theL2 estimate (2.10), we obtain for r≥1 the estimate

k∆ρk2r+k∇ρk2r≤CkDak2r1k∇ρk2r−1+Ckfk2r−1+CkDvk2r2+1kDuk2r−1

+Ck∇ρk2r+1+Ck∇ρk2r, (2.17) wherer1= max{r−1, s0},r2= max{r−2, s0}, with s0= [N2] + 1. Here, we also used the Sobolev inequality|h|L ≤Ckhks0.

From Lemma 2.5, we have k∇ρk2r+1 ≤Ck∆ρk2r. After substituting this esti- mate into the right-hand side of (2.17), we obtain the estimate

k∆ρk2r+k∇ρk2r≤CkDak2r

1k∇ρk2r−1+Ckfk2r−1+CkDvk2r

2+1kDuk2r−1, (2.18) where we have moved the terms Ck∆ρk2r and Ck∇ρk2r to the left-hand side.

Finally, using the estimate fork∇ρk2r+1from Lemma 2.5, we obtain from (2.18) the estimate

k∇ρk2r+1≤C(k∆ρk2r+k∇ρk2r)

≤CkDak2r1k∇ρk2r−1+Ckfk2r−1+CkDvk2r2+1kDuk2r−1

Lemma 2.7. If u,v,a,f, andρare sufficiently smooth in

2ρ=1

c∇ ·(a∇ρ) +1

c∇ ·(v· ∇u)−1

c∇ ·f (2.19)

wherec is a positive constant, ∇ ·u= 0,∇ ·v= 0,a(x, t)≥c1, with c1>0, and Ω =TN,N = 2,3, then forr≥1 ,ρsatisfies the following estimate

k∇ρk2r+1≤C k∆ρk2r+k∇ρk2r

≤Ch 1 +

r

X

j=1

kDak2jr1i

(kfk2r−1+kDvk2r2+1kDuk2r−1)

wherer1= max{r−1, s0},r2= max{r−2, s0}, withs0= [N2] + 1, and C depends onr.

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Proof. From Lemma 2.6 applied to equation (2.19), we have the estimate

k∆ρk2s+k∇ρk2s≤CkDak2s1k∇ρk2s−1+Ckfk2s−1+CkDvk2s2+1kDuk2s−1 (2.20) wheres≥1, and wheres1= max{s−1, s0},s2= max{s−2, s0}, withs0= [N2] + 1.

Lettings=r in the estimate (2.20) yields

k∆ρk2r+k∇ρk2r≤CkDak2r1k∇ρk2r−1+Ckfk2r−1+CkDvk2r2+1kDuk2r−1 (2.21) Applying the estimate (2.20), lettings=r−1, to the termCkDak2r1k∇ρk2r−1which appears on the right-hand side of (2.21) yields

k∆ρk2r+k∇ρk2r≤CkDak2r

1

hkDak2r

2k∇ρk2r−2+kfk2r−2+kDvk2r

3+1kDuk2r−2i +Ckfk2r−1+CkDvk2r2+1kDuk2r−1

≤CkDak4r1k∇ρk2r−2+CkDak2r1

kfk2r−2+kDvk2r2+1kDuk2r−2 +Ckfk2r−1+CkDvk2r2+1kDuk2r−1

(2.22) where r1 = max{r−1, s0}, r2 = max{r−2, s0}, and r3 = max{r−3, s0}, r3 ≤ r2 ≤r1, withs0 = [N2] + 1 = 2 for N = 2,3. Similarly, by repeatedly applying the estimate (2.20), letting s = r−j, to the term CkDak2jr1k∇ρk2r−j, for j = 2,3, . . . , r−1, which will appear on the right-hand side of (2.22) yields

k∆ρk2r+k∇ρk2r≤C

r−1

X

j=1

kDak2jr1

kfk2r−1−j+kDvk2r2+1kDuk2r−1−j +CkDak2rr1k∇ρk20+Ckfk2r−1+CkDvk2r2+1kDuk2r−1

≤Ch 1 +

r−1

X

j=1

kDak2jr1i

kfk2r−1+kDvk2r2+1kDuk2r−1 +CkDak2rr1k∇ρk20

(2.23)

Substituting the estimate for k∇ρk20 from Lemma 2.6 into the right-hand side of (2.23) yields

k∆ρk2r+k∇ρk2r≤C 1 +

r−1

X

j=1

kDak2jr1i

kfk2r−1+kDvk2r2+1kDuk2r−1 +CkDak2rr1

kfk20+|Dv|2LkDuk20

≤Ch 1 +

r

X

j=1

kDak2jr1i

kfk2r−1+kDvk2r2+1kDuk2r−1

This completes the proof.

3. Existence theorem

In this section, we prove the existence of a unique classical solution to the initial- value problem for equations (1.2), (1.3), on any given time interval 0≤t≤T, with periodic boundary conditions, for sufficiently small initial velocity gradient.

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Theorem 3.1. Supposes > N2 + 3 andΩ = TN, N = 2,3. For any given time interval 0 ≤ t ≤ T, equations (1.2), (1.3) have a unique classical solution ρ, v, for initial data v0(x) ∈ Hs(Ω), ∇ ·v0 = 0, and for given data ρ0(x, t) and x0, provided Dv0 is sufficiently small. Here ρ0(x, t) is a given positive function with sufficiently small gradient∇ρ0, andx0 is a point in the domain Ω. The regularity of the solution is

ρ∈C([0, T], C5)∩L([0, T], Hs+2), v∈C([0, T], C3)∩L([0, T], Hs),

∂v

∂t ∈C([0, T], C2)∩L([0, T], Hs−1).

andρ(x, t)≥c1, andρ−10(ρ)(x, t)≥c1, for some positive constantc1, for x∈Ω, and0≤t≤T.

Proof. We will construct the solution of the problem for (1.2), (1.3), with Ω =TN, through an iteration scheme. To define the iteration scheme, we will let the sequence of approximate solutions be vk and ρk. Set v0(x, t) = v0(x), the initial velocity data, and set ρ0(x, t)∈ C([0, T], C5)∩L([0, T], Hs+2) to be a positive function satisfyingk∇ρ0ks+1,T ≤ kDv0ks−1. Fork= 0,1,2, . . ., constructvk+1k+1 from the previous iteratesvkk by solving the linear system of equations

Dkvk+1

Dt + (ρk)−10k)∇ρk+1=c∇∆ρk+1, (3.1)

∇ ·vk+1= 0, (3.2)

whereDk/Dt=∂/∂t+vk· ∇, and with initial datavk+1(x,0) =v0(x). Since the solutionρk+1is unique up to an arbitrary function oft, we specify that the solution ρk+1 satisfy ρk+1(x0, t) = ρk(x0, t) at a single, fixed pointx0 ∈Ω, for all k ≥0.

Henceρk+1(x0, t) =ρ0(x0, t).

Existence of a sufficiently smooth solution to equations (3.1), (3.2) for fixed k follows from the results stated in Section 4. We proceed now to prove convergence of the iterates as k→ ∞to a unique classical solution of (1.2), (1.3). We assume thatpis a sufficiently smooth function of the thermodynamic state variableρin an open intervalG⊂R. We fix connected, bounded open setsG0 andG1 such that G¯0⊂G1 and ¯G1⊂G, and we require that the initial iterateρ0 satisfiesρ0 ∈G0. We fix δ= ˆδ(G0, G1) so that 0< δ <dist( ¯G0, ∂G1); therefore if|ρk−ρ0|L ≤δ, then ρk(x, t)∈ G1 for all x∈ TN, and for t ∈ [0, T]. The values ofρk ∈ G1 are assumed to be strictly positive, bounded, and bounded away from zero. And the values of (ρk)−10k) forρk∈G1are also assumed to be strictly positive, bounded, and bounded away from zero. Using a proof by induction on k, we assume that ρk ∈ G1, and then later we will show that ρk+1 ∈ G1. First, we proceed with the proof of uniform boundedness of the approximating sequence in a high Sobolev norm.

Proposition 3.2. Assume that the hypotheses of Theorem 3.1 hold. Let ρ0, v0

satisfy C00k20+C0k∇ρ0k22≤L20 ande2Tkv0k20≤L20, whereL0 is a constant and where C0 is the constant from Lemma 2.4. There are constants 0, L1, L2, L3, where0< 0<1, such that the following estimates hold fork= 1,2,3. . ., provided kDv0ks−1 is sufficiently small:

(a) k∇ρkk2s+1,T0,kρkks+2,T ≤L1,

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(b) kDvkk2s−1,T0,kvkks,T ≤L2, (c) k∂vk/∂tk2s−1,T0L3.

Proof. The proof is by induction onk. We show only the inductive step. We will derive estimates for ρk+1 and vk+1, and then use these estimates to prescribe0, L1,L2,L3 a priori, independent of k, so that ifρk andvk satisfy the estimates in (a)-(c), thenρk+1andvk+1also satisfy the same estimates. And we will show that 0 will be small if kDv0ks−1 is sufficiently small. In the estimates below, we use C to denote a generic constant whose value may change from one instance to the next, but is independent of0,L1,L2, andL3.

Estimate for ∇ρk+1: Applying the divergence operator to equation (3.1), we obtain

c∆2ρk+1− ∇ ·((ρk)−10k)∇ρk+1) =∇ ·(vk· ∇vk+1) (3.3) where we used the fact that ∇ ·vk+1 = 0, and where c is a positive constant.

Applying Lemma 2.7 we obtain from the above equation the following estimate for

∇ρk+1, fors >N2 + 3

k∇ρk+1k2s+1≤C(k∆ρk+1k2s+k∇ρk+1k2s)

≤C[1 +

s

X

j=1

kD((ρk)−10k))k2js1]kDvkk2s2+1kDvk+1k2s−1

≤C1kDvkk2s−1kDvk+1k2s−1

(3.4)

whereC1= ˆC1(L1). Here,s1= max{s−1, s0}=s−1,s2= max{s−2, s0}=s−2, where s0= [N2] + 1 = 2, and s > N2 + 3, sos≥5 forN = 2,3. And we used the induction hypothesis forρk,vk.

Estimate for ρk+1: To obtain an L2 estimate for ρk+1, we apply Lemma 2.4, where we define u = ρk+1 and we define w = ρ0 , to be used for the functions u, wappearing in Lemma 2.4. Note that since by hypothesis we haveρk+1(x0, t) = ρ0(x0, t) at a single fixed pointx0∈Ω, the hypotheses of Lemma 2.4 are satisfied, and so we obtain the estimate

k+1k20≤C00k20+C0k∇ρ0k22+C0k∇ρk+1k22

≤L20+C2kDvkk2s0+1kDvk+1k21

≤L20+C2kDvkk2s−1kDvk+1k21

(3.5)

whereC0is the constant from Lemma 2.4 (recallC0depends only on Ω), and where C2= ˆC2(L1). Here we used the estimate fork∆ρk+1k22+k∇ρk+1k22 from applying Lemma 2.7 to (3.3) with r = 2. We also used the hypothesis that C00k20+ C0k∇ρ0k22≤L20. Adding the estimates (3.4), (3.5) yields the following estimate for ρk+1,

k+1k2s+2≤ kρk+1k20+Ck∇ρk+1k2s+1

≤L20+C3kDvkk2s−1kDvk+1k2s−1 (3.6) whereC3= ˆC3(L1).

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Estimate for vk+1: Applying Lemma 2.3 to equations (3.1), (3.2), we obtain for Dvk+1 the estimate

kDvk+1k2s−1≤Ce2T(1 +T e2Teβ(T)kDvkk2s−1,T)(kDv0k2s−1 +

Z t

0

(kD((ρk)−10k))k2s1k∇ρk+1k2s−1)dτ)

≤Ce2T(1 +T e2TeT e2T)(kDv0k2s−1+C4 Z t

0

k∇ρk+1k2s−1dτ)

≤C5kDv0k2s−1+C5

Z t

0

kDvkk2s−1,TkDvk+1k2s−1

≤C5kDv0k2s−1+C5

Z t

0

kDvk+1k2s−1

(3.7)

where β(T) = T e2TkDvkk2s−1,T. Here, we used (3.4) to estimate k∇ρk+1k2s−1, and we used the fact that by the induction hypothesis, kDvkk2s−1,T0, where 0< 0<1. And here C4= ˆC4(L1, T),C5= ˆC5(L1, T).

Applying Gronwall’s inequality yields the estimate

kDvk+1k2s−1≤C6kDv0k2s−1 (3.8) where C6 = ˆC6(L1, T). We now choose 0 to satisfy 0 =C6kDv0k2s−1. It follows thatkDvk+1k2s−1,T0.

Substituting the estimate (3.8) forkDvk+1k2s−1into the right-hand side of (3.4), (3.6) yields the following estimates fork∇ρk+1k2s+1 andkρk+1k2s+2:

k∇ρk+1k2s+1≤C1kDvkk2s−1kDvk+1k2s−10C1C6kDv0k2s−1, kρk+1k2s+2≤L20+C3kDvkk2s−1kDvk+1k2s−1≤L20+0C3C6kDv0k2s−1 Therefore, we have kρk+1ks+2,T ≤ L1 and we have k∇ρk+1k2s+1,T0, pro- vided that we choose L1 large enough so that 12L21 > L20, and provided that we choosekDv0ks−1small enough so that0C3C6kDv0k2s−1< 12L21, and provided that we choose kDv0ks−1 small enough so that C1C6kDv0k2s−1 < 1. We also choose kDv0ks−1 small enough so that C6kDv0k2s−1 <1; therefore, we have 0 < 0 <1, since 0 = C6kDv0k2s−1. (Note that 0 will be small if kDv0ks−1 is sufficiently small.) This completes the proof of part (a).

Next, by applying Lemma 2.3 to (3.1), (3.2), and using the estimates (3.4), (3.7), (3.8), we have the estimate

kvk+1k2s≤e2Tkv0k20+Ce2T(1 +T e2Teβ(T)kDvkk2s−1,T)(kDv0k2s−1 +

Z t

0

(kD((ρk)−10k))k2s1k∇ρk+1k2s−1)dτ)

≤L20+C7kDv0k2s−1+C7 Z t

0

kDvk+1k2s−1

≤L20+C7kDv0k2s−1+C8kDv0k2s−1

withβ(T) =T e2TkDvkk2s−1,T. Heres1= max{s−1, s0}=s−1,s > N2 + 3, and s0 = [N2] + 1 = 2 forN = 2,3. We also used the hypothesis that e2Tkv0k20≤L20,

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