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Volume 2009, Article ID 762478,17pages doi:10.1155/2009/762478

Research Article

Global Attractivity Results for Mixed-Monotone Mappings in Partially Ordered Complete

Metric Spaces

D ˇz. Burgi´c,1 S. Kalabuˇsi ´c,2 and M. R. S. Kulenovi ´c3

1Department of Mathematics, University of Tuzla, 75000 Tuzla, Bosnia and Herzegovina

2Department of Mathematics, University of Sarajevo, 71000 Sarajevo, Bosnia and Herzegovina

3Department of Mathematics, University of Rhode Island, Kingston, R I 02881-0816, USA

Correspondence should be addressed to M. R. S. Kulenovi´c,[email protected] Received 28 October 2008; Revised 17 January 2009; Accepted 9 February 2009 Recommended by Juan J. Nieto

We prove fixed point theorems for mixed-monotone mappings in partially ordered complete metric spaces which satisfy a weaker contraction condition than the classical Banach contraction condition for all points that are related by given ordering. We also give a global attractivity result for all solutions of the difference equationzn1Fzn, zn−1,n2,3, . . . ,whereFsatisfies mixed- monotone conditions with respect to the given ordering.

Copyrightq2009 Dˇz. Burgi´c et al. This is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited.

1. Introduction and Preliminaries

The following results were obtained first in 1 and were extended to the case of higher- order difference equations and systems in2–6. For the sake of completeness and the readers convenience, we are including short proofs.

Theorem 1.1. Leta, bbe a compact interval of real numbers, and assume that

f :a, b×a, b−→a, b 1.1

is a continuous function satisfying the following properties:

afx, yis nondecreasing inx∈a, bfor eachy∈a, b, andfx, yis nonincreasing in y∈a, bfor eachx∈a, b;

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bIfm, M∈a, b×a, bis a solution of the system

fm, M m, fM, m M, 1.2

thenmM.

Then

xn1f

xn, xn−1

, n0,1, . . . 1.3

has a unique equilibriumx∈a, band every solution of1.3converges tox.

Proof. Set

m0 a, M0b, 1.4

and fori1,2, . . .set

Mif

Mi−1, mi−1

, mif

mi−1, Mi−1

. 1.5

Now observe that for eachi≥0,

m0m1≤ · · · ≤mi≤ · · · ≤Mi≤ · · · ≤M1M0, mixkMi, fork≥2i1.

1.6

Set

m lim

i→ ∞mi, M lim

i→ ∞Mi. 1.7

Then

M≥lim sup

i→ ∞ xi≥lim inf

i→ ∞ xim 1.8

and by the continuity off,

mfm, M, MfM, m. 1.9

Therefore in view ofb,

mM 1.10

from which the result follows.

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Theorem 1.2. Leta, bbe an interval of real numbers and assume that

f :a, b×a, b−→a, b 1.11

is a continuous function satisfying the following properties:

afx, yis nonincreasing inx∈a, bfor eachy∈a, b, andfx, yis nondecreasing in y∈a, bfor eachx∈a, b;

bthe difference equation1.3has no solutions of minimal period two ina, b. Then1.3 has a unique equilibriumx∈a, band every solution of 1.3converges tox.

Proof. Set

m0a, M0b 1.12

and fori1,2, . . .set

Mif

mi−1, Mi−1

, mif

Mi−1, mi−1

. 1.13

Now observe that for eachi≥0,

m0m1≤ · · · ≤mi≤ · · · ≤Mi≤ · · · ≤M1M0, mixkMi, fork≥2i1.

1.14

Set

m lim

i→ ∞mi, M lim

i→ ∞Mi. 1.15

Then clearly1.8holds and by the continuity off,

mfM, m, Mfm, M. 1.16

In view ofb,

mM 1.17

from which the result follows.

These results have been very useful in proving attractivity results for equilibrium or periodic solutions of 1.3 as well as for higher-order difference equations and systems of difference equations; see2,7–12. Theorems1.1and1.2have attracted considerable attention of the leading specialists in difference equations and discrete dynamical systems and have been generalized and extended to the case of maps inRn, see3, and maps in Banach space

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with the cone see4–6. In this paper, we will extend Theorems 1.1and 1.2to the case of monotone mappings in partially ordered complete metric spaces.

On the other hand, there has been recent interest in establishing fixed point theorems in partially ordered complete metric spaces with a contractivity condition which holds for all points that are related by partial ordering; see 13–20. These fixed point results have been applied mainly to the existence of solutions of boundary value problems for differential equations and one of them, namely20, has been applied to the problem of solving matrix equations. See also21, where the application to the boundary value problems for integro- differential equations is given and 22 for application to some classes of nonexpansive mappings and 23 for the application of the Leray-Schauder theory to the problems of an impulsive boundary value problem under the condition of non-well-ordered upper and lower solutions. None of these results is global result, but they are rather existence results. In this paper, we combine the existence results with the results of the type of Theorems1.1and 1.2to obtain global attractivity results.

2. Main Results: Mixed Monotone Case I

LetXbe a partially ordered set and letdbe a metric onXsuch thatX, dis a complete metric space. ConsiderX×X.We will use the following partial ordering.

Forx, y,u, v∈X×X, we have

x, yu, v⇐⇒ {x≤u, yv}. 2.1

This partial ordering is well known as “south-east ordering” in competitive systems in the plane; see5,6,12,24,25.

Letd1be a metric onX×Xdefined as follows:

d1x, y,u, v dx, u dy, v. 2.2

Clearly

d1x, y,u, v d1y, x,v, u. 2.3 We prove the following theorem.

Theorem 2.1. LetF :X×XXbe a map such thatFx, yis nonincreasing inxfor allyX, and nondecreasing inyfor allxX.Suppose that the following conditions hold.

iThere existsk∈0,1with dFx, y, Fu, vk

2d1x, y,u, v ∀x, yu, v. 2.4 iiThere existsx0, y0Xsuch that the following condition holds:

x0F y0, x0

, y0F

x0, y0

. 2.5

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iiiIf {xn} ∈ X is a nondecreasing convergent sequence such that limn→ ∞xn x, then xnx, for all nN and if {yn} ∈ Y is a nonincreasing convergent sequence such that limn→ ∞yn y, then yny, for all nN; if xnyn for every n, then limn→ ∞xn≤limn→ ∞ yn.

Then we have the following.

aFor every initial point x0, y0X ×X such that condition2.5holds,Fnx0, y0x, Fny0, x0y, n → ∞, wherex, ysatisfy

xFy, x, yFx, y. 2.6

Ifx0y0in condition2.5, thenxy.If in additionxy, then{xn},{yn}converge to the equilibrium of the equation

xn1F yn, xn

, yn1F

xn, yn

, n1,2, . . . . 2.7

bIn particular, every solution{zn}of

zn1F

zn, zn−1

, n2,3, . . . 2.8

such thatx0z0, z1y0converges to the equilibrium of 2.8.

cThe following estimates hold:

d Fn

y0, x0

, x

≤ 1 2

kn 1−k

d F

x0, y0

, y0

d

F y0, x0

, x0

, 2.9

d Fn

x0, y0

, y

≤ 1 2

kn 1−k

d F

y0, x0

, x0

d

F x0, y0

, y0

. 2.10

Proof. Letx1Fy0, x0andy1Fx0, y0.Sincex0Fy0, x0 x1andy0Fx0, y0 y1, forx2 Fy1, x1, y2Fx1, y1,we have

F2 y0, x0

:F

F x0, y0

, F y0, x0

F

y1, x1

x2,

F2 x0, y0

:F

F y0, x0

, F x0, y0

F

x1, y1

y2.

2.11

Now, we have

x2F2 y0, x0

F

y1, x1

F

y0, x0

x1, y2F2

x0, y0

F

x1, y1

F

x0, y0

y1.

2.12

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Forn1,2, . . . ,we let

xn1Fn1 y0, x0

F

Fn x0, y0

, Fn y0, x0

, yn1Fn1

x0, y0

F

Fn y0, x0

, Fn x0, y0

.

2.13

By using the monotonicity ofF, we obtain

x0F y0, x0

x1F2 y0, x0

x2≤ · · · ≤Fn1 y0, x0

≤ · · ·, y0F

x0, y0

y1F2 x0, y0

y2≥ · · · ≥Fn1 x0, y0

≥ · · · 2.14

that is

x0x1x2≤ · · · y0y1y2≥ · · · .

2.15

We claim that for alln∈Nthe following inequalities hold:

d xn1, xn

d

Fn1 y0, x0

, Fn y0, x0

kn 2 d1

x1, y1

, x0, y0

, 2.16

d yn1, yn

d

Fn1 x0, y0

, Fn x0, y0

kn 2 d1

x1, y1

, x0, y0

. 2.17

Indeed, forn1,usingx0Fy0, x0,y0Fx0, y0, and2.3, we obtain

d x2, x1

d

F y1, x1

, F y0, x0

k

2d1

y1, x1

, y0, x0

k

2d1

x1, y1

, x0, y0

,

d y2, y1

d

Fx1, y1

, F x0, y0

k

2d1

x1, y1

, x0, y0

.

2.18

Assume that2.16holds. Using the inequalities

Fn1 y0, x0

Fn y0, x0

, Fn1

x0, y0

Fn x0, y0

,

2.19

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and the contraction condition2.4, we have d

xn2, xn1 d

Fn2 y0, x0

, Fn1 y0, x0

d

F Fn1

x0, y0

, Fn1 y0, x0

, F Fn

x0, y0

, Fn y0, x0

k 2

d Fn1

x0, y0

, Fn x0, y0

d

Fn1 y0, x0

, Fn y0, x0

k 2

kn 2

d F

x0, y0

, y0

d

F y0, x0

, x0

d

F y0, x0

, x0

d

F x0, y0

, y0

kn1 2 d1

x1, y1

, x0, y0

.

2.20

Similarly,

d

yn2, yn1 d

Fn2 x0, y0

, Fn1 x0, y0

kn1

2 d1

x1, y1

, x0, y0

. 2.21

This implies that{xn}{Fny0, x0}and{yn}{Fnx0, y0}are Cauchy sequences inX.

Indeed, d

Fn y0, x0

, Fnp y0, x0

d

Fn y0, x0

, Fn1 y0, x0

· · · d

Fnp−1 y0, x0

, Fnp y0, x0

kn 2 d

F x0, y0

, y0

d

F y0, x0

, x0

· · · knp−1

2 d

F x0y0

, y0

d

F y0, x0

, x0

kn

2

1kk2· · ·kp−1 d

F x0, y0

, y0

dF

y0, x0

, x0

kn

2 1−kp

1−k d

F x0, y0

, y0

d

F y0, x0

, x0

.

2.22

Sincek∈0,1,we have

d

xn, xnp d

Fn y0, x0

, Fnp y0, x0

kn

21−kd1

x1, y1

, x0, y0

. 2.23

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Using 2.23, we conclude that {xn} {Fny0, x0} is a Cauchy sequence. Similarly, we conclude that{yn}{Fnx0, y0}is a Cauchy sequence. SinceX is a complete metric space, then there existx, yXsuch that

nlim→ ∞xn lim

n→ ∞Fn y0, x0

x , lim

n→ ∞yn lim

m→ ∞Fm x0, y0

y. 2.24

Using the continuity ofF,which follows from contraction condition2.4, the equations xn1F

yn, xn

, yn1F

xn, yn

2.25

imply2.6.

Assume thatx0y0.Then, in view of the monotonicity ofF x1F

y0, x0

F

x0, y0

y1, x2F

y1, x1

F

x1, y1

y2, x3F

y2, x2

F

x2, y2

y3.

2.26

By using induction, we can show thatxnynfor alln.Assume thatx0z0, z1y0.Then, in view of the monotonicity ofF, we have

x1F y0, x0

F

z1, z0

z2F x0, y0

y1, x1F

y0, x0

F

z2, z1

z3F x0, y0

y1.

2.27

Continuing in a similar way we can prove thatxizkyifor allk≥2i1.By using condition iiiwe conclude that whenever limn→ ∞zkexists we must have

x≤ lim

k→ ∞zky 2.28

which in the case whenxyimplies limk→ ∞zkx.

By lettingp → ∞in2.23, we obtain the estimate2.9.

Remark 2.2. Propertyiiiis usually called closedness of the partial ordering, see6, and is an important ingredient of the definition of an orderedL-space; see17,19.

Theorem 2.3. Assume that along with conditions (i) and (ii) ofTheorem 2.1, the following condition is satisfied:

ivevery pair of elements has either a lower or an upper bound.

Then, the fixed pointx, yis unique andxy.

Proof. First, we prove that the fixed pointx, yis unique. Conditionivis equivalent to the following. For everyx, y,x, yX×X,there existsz1, z2X×Xthat is comparable tox, y,x, y.See16.

Letx, yandx, ybe two fixed points of the mapF.

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We consider two cases.

Case 1. If x, y is comparable to x, y, then for all n 0,1,2, . . .Fny, x, Fnx, y is comparable toFny, x, Fnx, y x, y.We have to prove that

d1

x, y,

x, y

0. 2.29

Indeed, using2.2, we obtain d1

x, y,

x, y d

x, x d

y, y d

Fny, x, Fn

y, x d

Fnx, y, Fn

x, y

. 2.30

We estimatedFny, x, Fny, x, anddFnx, y, Fnx, y. First, by using contraction condition2.4, we have

d

Fy, x, F

y, x

k 2

d y, y

d x, x

k 2d1

x, y,

x, y , d

Fx, y, F

x, y

k 2

d x, x

d y, y

k 2d1

x, y,

x, y .

2.31

Now, by using2.31and2.30, we have d1

x, y,

x, y

kd1

x, y,

x, y

< d1

x, y,

x, y

, 2.32

which implies that

d1

x, y,

x, y

0. 2.33

Case 2. If x, y is not comparable to x, y, then there exists an upper bound or a lower bound z1, z2 of x, y and x, y. Then, Fnz2, z1, Fnz1, z2 is comparable to Fny, x, Fnx, yandFny, x, Fnx, y.

Therefore, we have d1

x, y,

x, y d1

Fny, x, Fnx, y ,

Fn y, x

, Fn

x, y

d1

Fny, x, Fnx, y ,

Fn z2, z1

, Fn z1, z2

d1

Fn z2, z1

, Fn z1, z2

,

Fn y, x

, Fn

x, y d

Fny, x, Fn z2, z1

d

Fn z2, z1

, Fn

y, x d

Fnz1, z2

, Fn

x, y d

Fn

z2, z1, Fn

y, x .

2.34

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Now, we obtain d1

x, y,

x, y d

Fny, x, Fn z2, z1

d

Fn z2, z1

, Fn

y, x d

Fn z1, z2

, Fn

x, y d

Fn z2, z1

, Fn

y, x .

2.35 We now estimate the right-hand side of2.35.

First, by using

d

Fy, x, F z2, z1

k

2 d

y, z2

d

x, z1

, 2.36

we have d

F2y, x, F2 z2, z1

d

FFx, y, Fy, x, F F

z1, z2

, F z2, z1

k 2d

Fx, y, F z1, z2

d

Fy, x, F z2, z1

k 2

k 2

d x, z1

d

y, z2

k

2 d

y, z2

d

x, z1

k2 2

d x, z1

dy, z2

.

2.37

Similarly, d

F2x, y, F2 z1, z2

d

FFy, x, Fx, y, F F

z2, z1

, F z1, z2

k 2

d

Fy, x, F z2, z1

d

Fx, y , F

z1, z2

k 2

k 2

d y, z2

d

x, z1

k

2 d

y, z2

d

x, z1

k2 2

d x, z1

d

y, z2

.

2.38

So,

d

F2y, x, F2 z2, z1

k2 2

d x, z1

d

y, z2

,

d

F2x, y, F2 z1, z2

k2 2

d x, z1

d

y, z2

.

2.39

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Using induction, we obtain

d

Fny, x, Fn z2, z1

kn 2

d x, z1

d

y, z2

,

d

Fnx, y, Fn z1, z2

kn 2

d x, z1

dy, z2

,

d Fn

z2, z1

, Fn

y, x

kn 2

d z1, x

, d z2, y

, d

Fn z1, z2

, Fn

x, y

kn 2

d z1, x

, d z2, y

.

2.40

Using2.40, relation2.35becomes

d1

x, y,

x, y

kn 2

d x, z1

d

y, z2

kn

2 d

x, z1

d

y, z2

kn

2 d

z1, x d

z2, y kn

2 d

z1, x d

z2, y kn

d x, z1

d

y, z2

d

z1, x d

z2, y

−→0, n−→ ∞.

2.41

So,

d1

x, y,

x, y

0. 2.42

Finally, we prove thatxy.We will consider two cases.

Case A. Ifxis comparable toy,thenFy, x xis comparable toFx, y y.Now, we obtain

dx, y dFy, x, Fx, yk

2dx, y dy, x kdx, y, 2.43

sincek∈0,1,this implies

dx, y 0⇐⇒xy. 2.44

Case B. Ifxis not comparable toy,then there exists an upper bound or alower bound ofx andy, that is, there existszXsuch thatxz, yz.Then by using monotonicity character

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ofF,we have

Fx, yFx, z, Fy, xFy, z,

Fx, yFz, y, Fy, xFz, x. 2.45

Now,

F2x, y FFy, x, Fx, y≤FFz, x, Fx, z F2x, z, 2.46

that is

F2x, y≤F2x, z. 2.47

Furthermore,

F2x, y FFy, x, Fx, yFFy, z, Fz, y F2y, z, 2.48

that is

F2x, y≥F2y, z. 2.49

Similarly,

F2y, x FFx, y, Fy, xFFz, y, Fy, z F2y, z, 2.50

that is

F2y, x≤F2y, z, 2.51

and

F2y, x FFx, y, Fy, x≥FFx, z, Fz, x F2z, x. 2.52

By using induction, we have

Fn1x, y≤Fn1x, z, Fn1x, y≥Fn1y, z, Fn1y, x≤Fn1y, z, Fn1y, x≥Fn1z, x.

2.53

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Sincex, yis a fixed point, we obtain

dx, y d

Fn1y, x, Fn1x, y d

F

Fnx, y, Fny, x , F

Fny, x, Fnx, y

d F

Fnx, y, Fny, x , F

Fnx, z, Fnz, x d

F

Fnx, z, Fnz, x , F

Fny, x, Fnx, y

d F

Fnx, y, Fny, x , F

Fnx, z, Fnz, x d

F

Fnz, x, Fnx, z , F

Fnx, z, Fnz, x d

F

Fny, x, Fnx, y , F

Fnz, x, Fnx, z .

2.54

Using the contractivity condition2.4onF,we have

dx, yk 2

d

Fnx, y, Fnx, z d

Fny, x, Fnz, x k

2 d

Fnz, x, Fnx, z d

Fnx, z, Fnz, x k

2 d

Fny, x, Fnz, x d

Fny, x, Fnx, y k

2 2d

Fnx, y, Fnx, z 2d

Fny, x, Fnz, x 2d

Fnx, z, Fnz, x k

d

Fnx, y, Fnx, z d

Fny, x, Fnz, x d

Fnx, z, Fnz, x .

2.55

Now, we estimate the terms on the right-hand side

d

Fnx, y, Fnx, z d

F

Fn−1y, x, Fn−1x, y , F

Fn−1z, x, Fn−1x, z

k 2

d

Fn−1y, x, Fn−1z, x d

Fn−1x, y, Fn−1x, z , d

Fny, x, Fnz, x d

F

Fn−1x, y, Fn−1y, x , F

Fn−1x, z, Fn−1z, x

k 2

d

Fn−1x, y, Fn−1x, z d

Fn−1y, x, Fn−1z, x , d

Fnx, z, Fnz, x d

F

Fn−1z, x, Fn−1x, z , F

Fn−1x, z, Fn−1z, x

k 2

d

Fn−1z, x, Fn−1x, z d

Fn−1x, z, Fn−1z, x .

2.56

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Now, we have dx, yk2

d

Fn−1y, x, Fn−1z, x d

Fn−1x, y, Fn−1x, z d

Fn−1z, x, Fn−1x, z . 2.57

Continuing this process, we obtain

dx, ykndFy, x, Fz, x dFx, y, Fx, z dFz, x, Fx, z. 2.58

Using the contractivity ofF,we have dx, ykn

k

2dx, x dy, z dy, z dx, x dx, z dz, x kn1dy, z dz, x.

2.59

That is

dx, ykn1dy, z dz, x−→0, n−→ ∞. 2.60

So,

dx, y 0⇐⇒xy. 2.61

3. Main Results: Mixed Monotone Case II

LetXbe a partially ordered set and letdbe a metric onXsuch thatX, dis a complete metric space. ConsiderX×X.We will use the following partial order.

Forx, y,u, v∈X×X, we have

x, yu, v⇐⇒ {x≥u, yv}. 3.1

Letd1be a metric onX×Xdefined as follows:

d1x, y,u, v dx, u dy, v. 3.2 The following two theorems have similar proofs to the proofs of Theorems 2.1 and 2.3, respectively, and so their proofs will be skipped. Significant parts of these results have been included in 14 and applied successfully to some boundary value problems in ordinary differential equations.

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Theorem 3.1. LetF :X×XXbe a map such thatFx, yis nondecreasing inxfor allyX, and nonincreasing inyfor allxX.Suppose that the following conditions hold.

iThere existsk∈0,1with dFx, y, Fu, vk

2d1x, y,u, v ∀x, yu, v. 3.3 iiThere existsx0, y0Xsuch that the following condition holds:

x0F x0, y0

, y0F

y0, x0

. 3.4

iiiIf {xn} ∈ X is a nondecreasing convergent sequence such that limn→ ∞xn x, then xnx, for all nN and if {yn} ∈ Y is a nonincreasing convergent sequence such that limn→ ∞yn y, then yny, for all nN; if xnyn for every n, then limn→ ∞xn≤limn→ ∞yn.

Then we have the following.

aFor every initial pointx0, y0X×Xsuch that the condition3.2holds,Fnx0, y0x, Fny0, x0y, n → ∞, wherex, ysatisfy

xFx, y, yFy, x. 3.5

Ifx0y0in condition3.4, thenxy.If in additionxy, then{xn},{yn}converge to the equilibrium of the equation

xn1F xn, yn

, yn1F

yn, xn

, n1,2, . . . . 3.6

bIn particular, every solution{zn}of

zn1F

zn, zn−1

, n2,3, . . . 3.7

such thatx0z0, z1y0converges to the equilibrium of 3.7.

cThe following estimates hold:

d Fn

x0, y0

, x

≤ 1 2

kn 1−k

d F

x0, y0

, x0

d

F y0, x0

, y0

,

d Fn

y0, x0

, y

≤ 1 2

kn 1−k

d F

x0, y0

, x0

d

F y0, x0

, y0

.

3.8

Theorem 3.2. Assume that along with conditions (i) and (ii) ofTheorem 3.1, the following condition is satisfied:

ivevery pair of elements has either a lower or an upper bound.

Then, the fixed pointx, yis unique andxy.

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Remark 3.3. Theorems3.1and3.2generalize and extend the results in14. The new feature of our results is global attractivity part that extends Theorems1.1and1.2. Most of presented ideas were presented for the first time in14.

Acknowledgment

The authors are grateful to the referees for pointing out few fine details that improved the presented results.

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