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Descent Monomials, P-Partitions and Dense Garsia-Haiman Modules

EDWARD E. ALLEN [email protected]

Department of Mathematics, Wake Forest University, Winston-Salem, NC 27109, USA Received October 31, 2002; Revised September 19, 2003; Accepted September 29, 2003

Abstract. A two-variable analogue of the descents monomials is defined and is shown to form a basis for the dense Garsia-Haiman modules. A two-variable generalization of a decomposition of aP-partition is shown to give the algorithm for the expansion into this descent basis. Some examples of dense Garsia-Haiman modules include the coinvariant rings associated with certain complex reflection groups.

Keywords: descent monomials,P-partitions, Garsia-Haiman modules, convariant rings

1. Introduction

LetAdenote the infinite collection

A= {. . . ,(0,3),(0,2),(0,1),(0,0),(1,0),(2,0),(3,0), . . .}. (1.1) For (a1,b1),(a2,b2),∈A, we define (a1,b1)<A (a2,b2) whenevera1b1<a2b2. Let

S= {(a1,b1),(a2,b2), . . . ,(an,bn)} ⊂A

denote a finite subset ofAlisted so that (ai,bi)<A(ai+1,bi+1). Furthermore, letMSdenote then×nmatrix

MS = xiakyibk

1i,kn (1.2)

and letS(X,Y) denote the determinant ofMS. SetC[X,Y] to be the polynomial ring over the complex fieldCwith variables inX = {x1,x2, . . . ,xn}, andY = {y1,y2, . . . ,yn}. With

P(X,Y)∈C[X,Y], we will set P(∂X, ∂Y)=P

x1, ∂x2, . . . , ∂xn, ∂y1, ∂y2, . . . , ∂yn

,

wherexi denotes the partial differential operator with respect toxi. With

IS(X,Y)= {P(X,Y)∈C[X,Y] : P(∂X, ∂Y)S(X,Y)=0}, (1.3)

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setCS[X,Y] to be the polynomial quotient ring

CS[X,Y]=C[X,Y]/IS(X,Y). (1.4)

These ringsCS[X,Y] are calledGarsia-Haiman modules. A. Garsia and M. Haiman intro- duced modules of a similar nature to study the Kostkaq,tcoefficients (see[5]). The ideas, however, can be traced back to Macaulay.

Associated with a subset

S= {(0,b1),(0,b2), . . . ,(0,bj−1),(0,0),(aj+1,0), . . . ,(an,0)} (1.5) ofA, listed in increasing order with respect to<A, are two sequencesψS andψSdefined as follows.

First, for 1≤ jn−1, setψSto be

ψS =[[1, β2, . . . , βj],[1, α2, . . . , αn+1−j]], withβ1=α1 =1 and for 2≤kj,

βk=bj+1kbj+2k. and for 2≤hn+1−j,

αh=aj+h−1aj+h−2

wherebj =0 andaj =0. Collections ψS =[[β1, β2, . . . , βn],∅]

or

ψS =[∅,[α1, α2, . . . , αn]]

will be dealt with in Section 7.

Second, set

ψS = {[ρ1, . . . , ρj−1,0, ρj+1, . . . , ρn]}ρ (1.6) where

0≤ρk <bkbk+1=βj+1k,

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for 1≤kj−1, and

0≤ρh <ahah−1=αhj+1, for j+1≤hn.

For σSn (the symmetric group), ψ = [ [1, β2, . . . , βj],[1, α2, . . . , αn+1−j]] and ρ=[ρ1, ρ2, . . . , ρn]∈ψS, define

dσ,ρj (X,Y)= j−1

k=1

yρσk(1)· · ·yσρk(k)



1≤ij−1 σ(i)>σ(i+1)

yσ(1)· · ·yσ(i)



× n

h=j+1

xσ(h)ρh xσ(hρh +1)· · ·xσ(n)ρh



j+1≤i≤n

σ(i−1)>σ(i)

xσ(i)· · ·xσ(n)

. (1.7)

For example, ifσ =(5,8,4,2,3,6,1,7), ρ=[4,0,3,1,0,1,0,7] and j=5 then dσ,ρ5 (X,Y)

= y54

y50y80

y53y83y43

y15y81y41y21

(y5y8)(y5y8y4)(x6x1x7) x77

(x1x7)

= x13y2y45y510x6x79y86. Note that the terms

1ij1

σ(i)(i+1)

yσ(1)· · ·yσ(i)

and

j+1≤i≤n

σ(i−1)>σ(i)

xσ(i)· · ·xσ(n)

are partial terms of descent monomials and that j−1

k=1

yσ(1)ρk · · ·yσ(k)ρk



1≤i≤j−1

σ(i)>σ(i+1)

yσ(1)· · ·yσ(i)



and n

h=j+1

xσρh(h) xσρh(h+1)· · ·xσρh(n)



j+1≤i≤n

σi−1(i)

xσ(i)· · ·xσ(n)



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are correspondingly partial terms in the P-partition decomposition given in [10] (see page 213).

The purpose of this paper is to prove the following theorem. Note that the definition of a dense sequencewill be given in Section 2. Also, recall that jis implicitly defined inS.

Theorem 1.1 Let S be a dense sequence. The collection DS =

dσ,ρj (X,Y) :σSn, ρψS

(1.8)

is a basis forCS[X,Y]with coefficients fromC.

Note that Theorem 1.1 is a generalization of a well-studied theorem. Ifψ = [[1, . . . , 1,1],[1]] then j =nand

ψS = {[0,0, . . . ,0]}.

The only possible choice forρis ρ=[0,0, . . . ,0].

In this case,dσ,ρj (X,Y) reduces to the normal descent monomial dσ,ρj (X,Y)=

σii+1

yσ1· · ·yσi

and DS becomes the collection of descent monomials in the variables Y. Furthermore, S(X,Y) becomes the Vandermonde determinant inY andIS(X,Y) becomes the ideal generated by the elementary symmetric functions in the variablesY and{x1,x2, . . . ,xn}.

Essentially,CS[X,Y] is the coinvariant ring (i. e.,C[y1,y2, . . . ,yn]/IwhereI is the ideal generated by the elementary symmetric functions in the variablesY) associated with the symmetric groupSn. In [1, 4] and [8], various proofs have been given that show that the descent monomials are a basis forC[y1,y2, . . . ,yn]/I.

Additionally, with 1≤hgand

ψS =[[h,g, . . . ,g,g],∅], (1.9)

the idealIS(X,Y) is generated by the following symmetric polynomials

ek=

i1<i2<···<ik

yig1yig2· · ·yigk

for 1≤kn−1 and en=y1hy2h· · ·ynh.

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The rings CS[X,Y] are the coinvariant rings associated with certain complex reflection groups—(i.e.,CgSnand some particular subgroups ofCgSn, whereCgdenotes the cyclic group of orderg—see, for example, [2] for two sets of variablesXandYor [7, 10], or [11]

for the one variable X case. For example, when the sequence ψS = [[2,2,2, . . . ,2],∅]

the moduleCS[X,Y] corresponds to the coinvariant ring associated to the hyperoctahedral group. These rings in a single variable have been studied by various individuals. For example, in [11] the Hilbert Series ofCS[X,Y] was calculated (withψS given in Eq. (1.9)). Morita and Yamada studied the one variable case usingbideterminantsin [7]. In [2], a bipermanent basis was constructed over variablesXandY. As we will see,ψS =[[h,g, . . . ,g,g],∅] is an example of certain sequences that we will calldense(see Section 2). Thus, the results in this paper apply not only to the coinvariant rings associated to these certain complex reflection groups but also to a much larger classification of rings. Particularly, this paper deals with a certain two-variable generalization of these rings and an extension of the theory of descent monomials and P-Partitions to a broader class of rings, specifically the class of dense Garsia-Haiman modules. A generalization of a P-Partition decomposition gives us the needed combinatorics to prove the necessary theorems.

In Section 2, dense Garsia-Haiman modules will be defined. In Section 3 we will review some results about cocharge tableaux and the Hilbert series ofCS[X,Y] and prove that a summation of a statistic over the collection of descent monomials gives the Hilbert series for CS[X,Y]. In Section 4, we will identify some particular polynomials in the idealIS(X,Y).

In Section 5, we will describe a decomposition that is a generalization of the P-partition decomposition. In Section 6, we will prove that the descent monomials given in Eq. (1.8) are a basis forCS[X,Y]. Specifically, we will give an algorithm for expressing a monomial P(X,Y) as a linear combination of elements ofDS. In Section 7, we will look at analogous results for dense one-variable Garsia-Haiman modules.

2. Dense sequences Recall that

ψS =[[1, β2, . . . , βj],[1, α2, . . . , αn+1−j]]. (2.1) We will considerα1 =β1=1.For 1≤kj, set

fk= −1+ k i=1

βi (2.2)

and for 1≤hn+1−j, set gh = −1+

h i=1

αi. (2.3)

Note that fk=bjk+1andgh =aj+h1where fk,gh,bjk+1andaj+h1are as defined in Eqs. (1.5), (2.2) and (2.3). We will say thatψSisdenseif and only if both of the following two conditions hold.

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1. For all j such that 1≤kjand for all sequencesck, . . . ,cj of nonnegative integers not all zero, either

fkj

i=k

ci βi <0, (2.4)

or

fkj

i=k

ci βi = fp, (2.5)

for somep.

2. For allksuch that 1≤knj+1 and for all sequencesdk, . . . ,dnj+1of nonnegative integers not all zero, either

gk

nj+1 i=k

diαi<0, (2.6)

or

gk

nj+1 i=k

diαi =gq, (2.7)

for someq.

The collection of dense sequences is somewhat extensive. For example, any sequence of the form

ψs=[[1,g,g, . . . ,g],[1,h,h, . . . ,h]]

(with bothg,h≥1) is dense. Another possibility is ψs=[[1, β2, . . . , βj],[1, α2, . . . , αn+1−j]]

whereβkk+1 for 1 ≤ kj −1 andαhh+1 for 2 ≤ hnj. A third example occurs when we require αkk1

i=1αi for 1 ≤ kn +1− j or βkk1 i=1βi for 1≤kj. Many types of examples exist. Furthermore, note that being dense is a function of the sequences [1, β2, . . . , βj] and [1, α2, . . . , αn+1−j] separately. Thus in these previous example, we could have interchanged a [1, β2, . . . , βj] from one example into another and the resulting sequence

ψs=[[1, β2, . . . , βj],[1, α2, . . . , αn+1−j]]

would have remained dense.

We will say that the Garsia-Haiman moduleCS[X,Y] is dense, whenever the subsetSis dense.

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3. Cocharge tableaux and the Hilbert series ofCS[X,Y]

We will use French notation to denote ferrers diagrams and taleaux. Letλ=(λ1, λ2, . . . , λh) be a partition of n. Specifically, we have that λ1λ2 ≥ · · · ≥ λh > 0 and n = λ1+λ2+ · · · +λh. A ferrers diagram of shapeλhasλ1cells in its first row,λ2cells in its second row and, in general,λk cells in itskth cell as 1kh. A tableau of shapeλis a ferrers diagram of shapeλwhere the cells contain entries from some ordered alphabet.

A standard tableau is a tableau where the entries are taken from the set{1,2, . . . ,n}, each entry appears exactly once and the entries strictly increase from left to right (west to east) in each row and from bottom to top (south to north) in each column. Letsh(T) denote the shape ofT.

Define δ(i)=

1 ifiis southeast ofi+1;

0 ifiis northwest ofi+1.

Bysoutheast, we mean strictly south and weakly east. Similarly, bynorthwest, we mean strictly west and weakly north.

With

ψS =[[1, β2, . . . , βj],[1, α2, . . . , αn+1−j]], ρ=[ρ1, ρ2, . . . , ρn]∈ψS

and a standard tableauT, we can construct a cocharge tableauC =Cρ(T) withsh(C)= sh(T) in the following manner (see [3]).

A. Replace jinT by (0, 0) and setcj =(cj,1,cj,2)=(0,0).

B. Assuming that we have replacedhinT by (ch,1,0) (for somehj), replaceh+1 in T by (ch,1+ρh+1+δ(h),0).

C. Assuming that we have replacedginT by (0,cg,2) (for somegj), replaceg−1 in T by (0,cg,2+ρg1+δ(g−1)).

Note thatCρ(T) has entries from the alphabetAand that the entries ofCρ(T) increase strictly from south to north and increase weakly from west to east (with respect to<A).

Example LetT be the standard tableau of shape (5, 4, 3)

T =

6 9 10

3 5 7 12

1 2 4 8 11

With

ψS =[[1,1,2,5,5,10],[1,2,2,2,6,6,12]]

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and

ρ=[2,3,3,0,1,0,0,1,0,2,4,7], we haven=12,j =6 and

Cρ(T)=

(0,0) (2,0) (4,0)

(0,6) (0,2) (0,0) (16,0) (0,12) (0,10) (0,3) (1,0) (8,0)

. (3.1)

Let|Cρ,1(T)|and|Cρ,2(T)|denote the sum of the first coordinate entries and the sec- ond coordinate entries, respectively, of Cρ(T), WithCρ(T) given in Eq. (3.1) we have

|Cρ,1(T)| =31 and|Cρ,2(T)| =33, respectively.

Given a graded moduleRin the variablesXandY, we will letRs,r denote the homoge- neous subspace of total degreesin the variablesX = {x1,x2, . . . ,xn}and of total degree rinY = {y1,y2, . . . ,yn}. The Hilbert SeriesH(R) ofRis defined as

H(R)=

s,t

dim(Rs,r)tsqr.

The following theorem is proved in [3].

Theorem 3.1 If S is dense then the Hilbert SeriesH(CS[X,Y])is given by H(CS[X,Y])=

λn,

U,T∈STλ

ρ∈ψS

t|Cρ,1(T)|q|Cρ,2(T)|

=

λn

hλ

T∈STλ

ρ∈ψS

t|Cρ,1(T)|q|Cρ,2(T)| (3.2)

whereSTλdenotes the collection of standard tableaux of shapeλ,hλdenotes the number of standard tableaux of shapeλand|Cρ,1(T)|and|Cρ,2(T)|denote the sum of the first and second coordinates,respectively,of the entries of Cρ(T).

Let (Pσ,Tσ) denote the pair of standard tableaux that we obtain by the row insertion algorithm corresponding to the permutationσSn(see [6] or [9], note, however, that we are using the French notation for describing our tableaux). We denote the relationship between a permutation σSn and a pair of standard tableaux (Pσ,Tσ) induced by the row-insertion algorithm byσ −→RS (Pσ,Tσ).

Withσ =(σ1, σ2, . . . , σn)∈Snandσ −→RS (Pσ,Tσ), note that ifσ(i)> σ(i+1) then in Tσ the cell containingi is southeast (strictly south and weakly east) of the cell containing i+1 (follow the bumping path as described in [6]). Similarly, ifσ(i)< σ(i+1) then in Tσ the cell containingi is northwest (weakly north and strictly west) of the cell containing

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i+1. The entry inCρ(Tσ) that replacedjinTσis (0,0). Not that the exponents ofxσ(j)and yσ(j)indσ,ρj (X,Y) (see Eq. (1.7) are both precisely 0.

Now assume that (cm,0) replacedm(for somemsuch that jmn−1) inTσ and thatcmis the exponent ofxσm and 0 is the exponent ofyσ(m) indσ,ρj (X,Y).

Ifmis southeast ofm+1 inTσ then inCρ(Tσ),(cm+ρm+1+1,0) replaced the entry m+1 ofTσ. Ifmis southeast ofm+1 inTσ, thenσ(m)> σ(m+1) and the exponent of xσ(m+1)indσ,ρj (X,Y) iscm+ρm+1+1. The exponent ofyσ(m+1)indσ,ρj (X,Y) is 0.

Ifmis northwest ofm+1 inTσ, then (cm+ρm+1,0) replaced the entrym+1 ofTσ. Furthermore,σ(m)< σ(m+1) and the exponent ofxσ(m+1)iscm+ρm+1and the exponent ofyσ(m+1)is 0 indσ,ρj (X,Y).

Similar situations occur formwhen 2≤mjand in which we consider the entrycm−1

inCρ(Tσ) and the exponent ofxσ(m−1)andyσ(m−1)indσ,ρj (X,Y).

Thus if (a,b) is the entry that replacediinTσwhen we constructedCρ(Tσ), then the expo- nents ofxσ(i)andyσ(i)indσ,ρj are preciselyaandb, respectively. Therefore, ifσ −→RS (Pσ,Tσ) then|Cρ,1(Tσ)| = |dσ,ρ,j 1|and|Cρ,2(Tσ)| = |dσ,ρ,j 2|, where|dσ,ρ,j 1|and|dσ,ρ,j 2|denotes the sum of the exponents in the variables X = {x1,x2, . . . ,xn}andY = {y1,y2, . . . ,yn}of dσ,ρj (X,Y), respectively. Thus,

Theorem 3.2 If S is dense then the Hilbert SeriesH(CS[X,Y])is given by H(Cs[X,Y])=

λn

U,T∈STλ

ρ∈ψS

t|Cρ,1(T)|q|Cρ,2(T)|

=

dσ,ρj ∈DS

t|dσ,ρ,1j |q|dσ,ρ,2j |, (3.3)

where |dσ,ρ,j 1| and |dσ,ρ,j 2|denote the sum of the exponents of the variables in X and Y respectively,of dσ,ρj .

Thus to prove Theorem 1.1 all we need to do is show that the collection DS spans CS[X,Y]. To do so, we will need to identify some polynomials in the idealIS(X,Y) (recall Eq. (1.3)). This is the object of Section 4.

It should be noted that in [3], it is shown that the Hilbert seriesH(CS[X,Y]) ofCS[X,Y] is given by

H(CS[X,Y])= fψS(q,t)H(CS[X,Y]) where

fψS(q,t)= j i=1

1−q(j+1−i)βi 1−qj+1−i

n+1−j i=1

1−t(n+2−ji)αi 1−tn+2−ji

(3.4)

andH(CS[X,Y]) is the Hilbert series corresponding to shape =[[1j],[1n+1−j]].

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4. Some polynomials inIS(X,Y)

Withγi=(γi,1, γi,2) andγ =[γ1, γ2, . . . , γn] a sequence of lengthnwith entries fromA, we set

mγ(X,Y)=

ν∈Sn

x1γν(1),1y1γν(1),2x2γν(2),1y2γν(2),2· · ·xγnν(n),1ynγν(n),2. (4.1)

Essentially, we are permuting the exponents in Eq. (4.1) (definingmγ(X,Y) in this manner becomes very useful in Eq. (4.6) and (6.2)). Note that

σmγ(X,Y)=mγ(X,Y)

for allσSnwhere the action ofSnon a polynomialP(X,Y) is defined by setting σP(x1,x2, . . . ,xn,y1,y2, . . . ,yn)=P

xσ(1),xσ(2), . . . ,xσ(n),yσ(1),yσ(2), . . . ,yσ(n) .

With

ψS =[[1, β2, . . . , βj],[1, α2, . . . , αn+1−j]], setψSto be the collection of sequences

ψS = {[ej,ej1, . . . ,e2,(0,0),h2, . . . ,hn+1j]

: ε2+ · · · +εj+θ2+ · · · +θn+1−j >0}, (4.2) where eachεi and eachθiis a nonnegative integer, and

ek=

0, k

i=2

εiβi

(4.3)

(for 2≤kj) and hg=

g

i=2

θiαi,0

(4.4)

(for 2≤gn+1− j).

Theorem 4.1 If S is dense and ifγψSthen

mγ(X,Y)∈IS(X,Y). (4.5)

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Proof: Recall thatIS(X,Y) is defined in Eq. (1.3). With fkandghdefined as in Eqs. (2.2) and (2.3), and

γ =[ej,ej1, . . . ,e2,(0,0),h2, . . . ,hn+1j]=[γ1, γ2, . . . , γn]∈ψS, it is not difficult to see that

mγ(X, ∂Y)S(X,Y)

=

ν∈Sn

cν

w∈Sn

sign(ω)ω

x10−γν(1),1y1fj−γν(1),2· · ·x0−γj−1ν(j−1),1yjf−11−γν(j−1),2x0−γj ν(j),1 y0j−γν(j),2xgj+11,1−γν(j+1),1y0j+1−γν(j+1),2· · ·xngn−j+1,1−γν(n),1yn0−γν(n),2

, (4.6)

wherecν =0 if any of the exponents are negative.

Suppose thatcν =0 (specifically that none of the exponents in Eq. (4.6) are negative).

Suppose that there exists a k where 1 ≤ kj such that γν(j+1−k) = (0,0). Without loss of generality, letkbe the largest such integer. The fact thatψS is dense implies that (0,fkγν(j+1k)) = (0, ft) whereγν(j+1t) = (0,0) for somet (see Eqs. (2.4)–(2.7)).

Therefore the exponents of xk and yk are exactly equal to the exponents ofxt andyt in Eq. (4.6). Therefore,

ω∈Sn

sign(ω)ω

x10−γν(1),1y1fj−γν(1),2x20−γν(2),1y2fj−1−γν(2),2

· · · x0−γj ν(k),1yjf1−γν(k),2x0−γj+1ν(j+1),1y0−γj+1ν(j+1),2· · ·xngn−j−1,1−γν(n),1yn0−γν(n),2

=0.

Similar comments can be made if there exists akinj+2≤knsuch thatγν(k) =(0,0).

Therefore, if we have thatψS is dense andγψS thenmγIS(X,Y). Complete details with all of the calculations can be found in [3].

5. AP-partition type decomposition

LetP(X,Y) be a monomial such that

P(X,Y)=x1p1y1q1x2p2y2q2· · ·xnpnynqnIS(X,Y).

The condition that P(X,Y) ∈IS(X,Y) implies that (pi,qi)∈Afor 1≤in. We define theexponent sequence es(P,(X,Y)) ofP(X,Y) to be

es(P(X,Y))=(p1,q1),(p2,q2), . . . ,(pn,qn). (5.1) Label the entries of the sequencees(P) from smallest to largest with respect to<Abreaking ties by which is farthest left (an example can be found in Eq. (5.14)). Withφidenoting the

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label of (pi,qi), setφP to be the permutation φP =

1 2 3 · · · n φ1 φ2 φ3 · · · φn

(5.2)

and

σP =(φP)−1. (5.3)

Particularly,σP(i)=kimplies that (pk,qk) was labelledi.

Let (ri,1,ri,2) denote the entry ofes(P(X,Y)) labelledi. We can assume that (rj,1,rj,2)= (0,0) or elseP(∂X, ∂Y)S=0 andP(X,Y)∈IS(X,Y). With

ψS =[[1, β2, . . . , βj],[1, α2, . . . , αn+1j]]

and

χσP(i)=

1 ifσP(i)> σP(i+1) 0 ifσP(i)< σP(i+1), for 1≤kj−1, set

ρk=(rk,2rk+1,2χσP(k)) (modβj+1k), (5.4) for j+1≤hn,set

ρh =(rh,1rh−1,1χσP(h−1)) (modαh+1−j) (5.5) and

ρP =[ρ1, ρ2, . . . , ρj−1,0, ρj+1, . . . , ρn].

Note that we are considering (modαh+1j) and (modβj+1k) as functions so that 0≤ρkβj+1k−1 (for 1≤kj−1) and 0≤ρhαh+1j−1 (forj+1≤hn).

With es

dσjPP(X,Y)

=(h1,1,h1,2),(h2,1,h2,2), . . . ,(hn,1hn,2), (5.6) let (gi,1,gi,2) denote the entry ofes(dσjPP) labelledi. Set

γi=(γi,1, γi,2)=(ri,1gi,1,ri,2gi,2) (5.7)

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andγP to be the sequence γP =[γ1, γ2, . . . , γn] withγj =(0,0).

Suppose the entry labelled j−1 ines(P(X,Y)) is (0,rj−1,2). Note that the entry labelled jines(P(X,Y)) must be (0, 0) (or elseP(X,Y)∈IS(X,Y)). Now,ρj−1 =(rj−1,2−0− χσP(j−1)) (modβ2). Thus

rj1,2 =ρj1+ fi1β2+χσP(j−1), (5.8) some nonnegative integer fj1. Now,gj1,2is the exponent ofyσP(j1)so that

gj−1,2 =ρj−1+χσP(j−1) and

γj−1,2=rj−1,2gj−1,2=rj−1,2ρj−1χσP(j−1)= fj−1β2

by Eq. (5.8).

Assume (reverse) inductively that somek+1 (where 1≤kj−1), we have that rk+1,2gk+1,2=γk+1,2=

j1

i=k+1

fiβj+1−i (5.9)

where each fi is a nonnegative integer. Note that gk,2is the exponent of yσP(K) and thus Eq. (1.7) implies

gk,2=gk+1,2+ρk+χσP(k).

Recall from Eq. (5.4) that

ρk=(rk,2rk+1,2χσP(k)) (modβj+1−k), (5.10) or equivalently,

rk,2=ρk+rk+1,2+χσP(k)+ fkβj+1k, some nonnegative integer fk. Using Eq. (5.9), we have

γk,2 =rk,2gk,2

=ρk+rk+1,2+χσP(k)+ fkβj+1kgk+1,2ρkχσP(k)

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=rk+1,2+ fkβj+1−kgk+1,2

= fkβj+1k+γk+1,2

=

j−1

i=k

fiβj+1i

where each fiis a nonnegative integer.

Now (0, γk,2)=ej+1k,2whenεi = fj+1i(recalling Eq. (4.3)) for 2≤ij. The cases whenkj+1 are similar. Therefore, we have that

γP =[γ1, γ2, . . . , γn]∈ψS. Withφ=φP, set

ζP =γP =

γφ(1), γφ(2), . . . , γφ(n)

. (5.11)

It is easy to see thatφP(1)=φdσP,ρP(1), φP(2)=φdσP,ρP(2), etc. This givesφP =φdσP,ρPj . Note that ifσ(k)=i(so thatφ(i)=(σP)−1(i)=k) then (pi,qi) is labelledkin Eq. (5.1) and (hi,1,hi,2) is labelledkin Eq. (5.6). Therefore, we have (pi,qi)=(rk,1,rk,2),(hi,1,hi,2)= (gk,1,gk,2),

k,1, γk,2)=

γφ(i),1, γφ(i),2

=(ζi,1, ζi,2) and by Eq. (5.7)

xipiyiqi =xσrk,1k yσrk,2k =xσgkk,1yσgkk,2xσγkk,1yσγkk,2 =xihi,1yihi,2xiζi,1yiζi,2. (5.12) Thus, we have the following theorem.

Theorem 5.1 Given a sequence

ψS =[[1, β2, . . . , βj],[1, α2, . . . , αn+1j]]

and a sequence

P =(p1,1,p1,2),(p2,1,p2,2),(p3,1,p3,2), . . . ,(pn,1,pn,2)

where(pi,1,pi,2)∈Aand(pj,1,pj,2)=(0,0),there is a unique tripleP, ρP, γP),where σPSn, ρPψS andγPψS,such that if P = es(P(X,Y))and ζP = γPP = es(Q(X,Y))then

P(X,Y)=dσjPP(X,Y)Q(X,Y). (5.13)

Theorems 4.1 and 5.1 then yield

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Theorem 5.2 If S is dense,if(σP, ρP, γP)is the decomposition of P and ifγP is not a sequence consisting entirely of entries(0,0)then mγP(X, Y)IS(X,Y).

This decomposition of es(P(X,Y)) in Theorem 5.1 into the triple (es(dσjP), ρP, γP) is a generalization of a P-partition decomposition given in [10] (see page 213). It will reduce to exactly this P-partition decomposition when ψS = [[1,1, . . . ,1],∅] (forcing ρP = [0,0, . . . ,0]). Note that in this case, the requirement that (rj,1,rj,2) =(0, 0) (the entry in Eq. (5.1) labelled j) is not needed (see Section 7).

Example Withn=8, ψS=[[1,1,3,3],[1,1,2,2,4]] (which implies j =4) and P(X,Y)=x15x223 y39y421 y51x615x18

thenes(P(X,Y)) with its labelling is

es(P(X,Y))=(5,0)6,(23,0)8,(0,9)2,(0,21)1,(0,1)3,(15,0)7,(0,0)4,(1,0)5. (5.14) Now,

φP =

1 2 3 4 5 6 7 8

6 8 2 1 3 7 4 5

, σP =

1 2 3 4 5 6 7 8

4 3 5 7 8 1 6 2

. and

ρ =[21−9−1 (mod 3),9−1−0 (mod 3),1−0−0 (mod 1),0, 1−0−0 (mod 1),5−1−1 (mod 2),15−5−0 (mod 2), 23−15−1 (mod 4)]

=[2,2,0,0,0,1,0,3]. Note

dσ,ρ4 (X,Y)= y24

y32y42

(y4)(x1x6x2) x23

(x1x6x2)(x2)=x12x26y32y45x62, (5.15) es(dσ,ρ4 (X,Y)) (along with its exponent labelling) is

es(dσ,ρ4 (X,Y))=(2,0)6,(6,0)8,(0,2)2,(0,5)1,(0,0)3,(2,0)7,(0,0)4,(0,0)5

(5.16) and

γP =[(0,16),(0,7),(0,1),(0,0),(1,0),(3,0),(13,0),(17,0)]∈ψS.

参照

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