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(1)

VOL. 18 NO. 4 (1995) 777-788

FRACTIONAL INTEGRATION OPERATOR OF VARIABLE ORDER IN THE HOLDER SPACES H

(x)

BERTRAM

ROSS University of New Haven

300 Orange

Avenue,

West

Haven,

CT 06516, USA and

STEFAN

SAMKO Rostov

State University

105, Bol’shaya Sadovaya,

Rostov-on-Don,

344711, Russia Currently Fulbright Scholar at the University of New

Haven,USA

(Received June 17, 1993 and in revised form September 20, 1993)

ABSTRACT.The fractional integrals

I+(x)0

of variable order e(x) are

considered. A theorem on mapping properties of

Ia+

(x) in Holder-type spaces

H

x(x) is proved, this being a generalization of the well known Hardy-Littlewood theorem.

KEYWORDS- Fractional integration, variable fractional order, mapping properties, Holder continuous functions, Hardy-Littlewood theorem.

1991 AHS SUBJECT CLASSIFICATION CODES. 26 A33, 26 A16

I.

NTROOUCTION

In

the paper [I] the authors introduced and investigated the fractional integrals

l(X)0 ’F[(x)] e(t)(x-t )(x)-

dt (1)

of variable order e(x)>O and considered the corresponding versions of fractional differentiation as well.

In

this paper we prove the theorem on the behaviour of the operator

l(X)

in the generalized Holder spaces

H

)’(*) the order of which also

(2)

depends on the point x This is a generalization of the Hardy Littlewood theorem, well known in the case of

constant

orders e(x)==const and x(x)=X=const (Hardy and Littlewood

[2];

see also Samko et al

[3],

p. 53-54).

Our interest in integration and differentiation of a variable order is motivated not only by the desire to generalize the classical notion, but by some far reaching goals as well. There is the well known theory of fractional Sobolev type spaces see its elements e.g. in

[3],

sections 26-27. These spaces consist of functions whose smoothness property can be expressed either globally or locally in terms of the existence of fractional derivatives. The smoothness property of a function may, however, vary from point

to

point. The construction of the corresponding Sobolev type spaces is an open question. The notion introduced in (1) is the appropriate tool for this purpose.

In

this paper we deal only with the question of improving the smoothness property, expressed in terms of the Holder type condition, by the operator

(1),

and the theorem proved may be considered as a starting point for further investigations of functions with varying order of smoothness.

In

Section we give all required definitions and some auxilliary lemmas, while Section 2 contains the statement and the proof of the main result.

In what follows the letter c may denote different positive constants.

2. PRELIMINARIES

Let

Q

[a,b] .

< a < b < 0. The following is a generalization of the Holder space

H

)" 0 < ),

DEFINITION I. We say that f(x) E

H

)’(x)(Q) where X(x) is a positive (not necessarily continuous) function, 0 < X(x) <

I,

if

If(x+h)-f(x)l cihlx() (2)

for all x x+h E [a,b]

It

is easily seen that (2) implies that f(x+h)-f(x)lclhlx(x+h)

So, it is not difficult to show that the definition of the class

H)’()(C))

by (2) is equivalent to the definition by means of the following symmetrical

(3)

nequal ty

If(x )-f(x )! clx-x

ImaX{X(Xl)’X(x2

))

2 2 (3)

It is easily seen that

HX()(O)

is a ring with respect to the usual multiplication.

It

is a Banach space with respect

to

the norm

f(x+h)-f(x)l sup sup

IlfllHx

(x) xeO h<

Ihl

x(x)

h+xEf

f(x )-f(x )1 sup 2

E

IX

--X

Imax((xl ’(x2)

Xl’

2 2

(4)

where denotes the equivalence- f g <= c

f<g;czf,

c >0, c2>0.

Generalizing Definition we give the following

DEFINITION 2. We say that f(x) E

H x(x)’W(*)(O)

where ),(x) are given functions, 0 < x(x) < 1,

,

<

p(x)

< if

and

(x)

i__11/(x)

If(x+h)-f(x)l clhl)’(x)

In Ihl <-2-

under assumption that

x,

x+h E O

We shal need the following auxi11iary assertions.

LEMMA I.

Let the function X(x) E C(O) satisfy the condition

for all

IX(x+h)-X(x)l <

A A const

> 0 l+ln h

x x+h E 0 Then the function

(5)

g

s,t(x) (x-a) (6)

where x,t,t+s(x-a) E O s E

[0,1]

is bounded from zero and infinity-

0 < d

-^

s g

(x)

_< d

^

<

,

(7)

with a

constant

d

max{e,b-a,I/(b-a)}

not depending on s,t and x

(4)

PROOF. Since

In

g (x)

{).[t+s(x-a)] )‘(t)}

In(x-a), by (5) we have

Iln

g (x)l < Alln(x-a)l Alln(x-a)l

b-a

b:a

s, 1+1n

s(xa

1+1n

x---E

simple calculations show that the maximum of the right-hand side is

A max{1,11n(b-a)l}

Really, let f(y) A lyl(l+c-y)

-,

where-

,

y s c ln(b-a). Suppose b-a z first. For y>O we have f(y)

Ay(l+c-y)-l

Ay <

Aln(b-a). If y<0, then f(y) Alyl(l+c+lyl)

-

< A Therefore,

f(y) A max 1, ln(b-a)

in the case c In(b-a) > 0 Let now c < 0 Then y < 0 and f(y)

A

A(l+c)(l+c-y)-1 if 1+c z 0 If 1+c < 0 we have f (y) A(l+c)(l+c-y)-2

> 0, so that f(y) < f(c) for y _< c which gives f(y) < Alcl=

A I]n(b-a)l. So,

f(y) A max 1, Iln(b-a)l

in all cases. Therefore,’ln g(x)l A

max{1,11n(b-a)l}

,whence

(6)

follows.

LEMNA

2.

For

any function (x) such that 0 < (x) the inequality

+h)cxcx)

xCX()

hcx(x)

h>O, x>O (8)

holds.

PROOF. By dividing a]] members in (8) by ha(x) we see that the inequality (8) is equivalent to the inequality

f(C)

with

f(()

(l+c)(x)_ ((x)>

0 for a]]

C

> 0 which is evident because f

(()

< 0 and f(O)

LEMNA

3. Let 0 < < and ( < X < Then

sin B(, 1+),)

[ tX[tx--(t+l) (z-]

dt

sin

(4:k)

O

(9)

(5)

PR(X)F.

Let A(.,)

denote the left-hand side in (9) After the substitution t+l

S-1

we have

)), (1-s)a- -1

o s

ds (10)

Hence

)X (1-s)" l+(l_s)p

A(,,=) [

(1-s 1++0

0

)X (1-s)/-1

ds ds + (1-s

0 S

with / not determined as yet.

Hence,

by (10)

A(;k =)

A()+/,=-/)

+

f

(l-s)X

(1-s)P-1

ds

o s

The second integral here is evaluated by means of analytical continuation with respect to

[

(l-s)

x (1-s)P-1 SI+X+(

ds

B(X++I

-X-a) B(X+I

0

under the appropriate conditions on the parameters M and X So,

[F(x++l

F(X+I

I]

A(),,) A(),+/,-p) +

r(-),-()

LF(+l_a)

Simple calculations show that

A(0,a) 1/a So,

choosing /=-), we have

A(X,) :X+I +

F(-X-) F(1-

which gives

(9)

after easy calculations.

3.

THE

HAIN THEOREN

Considering the fractional integral

Ia(X)0

defined in (1), of the

function

0(x) H

)’(x) we shall assume the following conditions on (x) and x(x)

to

be satisfied-

(6)

i) 0 < (x) with m inf (x) > 0 XEO

and (x)

H/(x)(o)

0 < 6 <

p(x)

<

ii) 0 < X(x) < and X(x) satisfies the condition (5)- iii) (x)

+

(x) <

THEOREM. Let the conditions i) iii) be satisfied and let

(x) _

HX(x)(O)

Then

I()0

has the form

I()0

F[I

(a) /(((x)]

(x-a

+

f(x) (11)

where

f(x) E

H(X)(o) (x)

min{),(x)+({(x),

p(x)}

(12)

if

max[X(x)+(x)]

< and xEO

f(x) E

H Y(x)’(O)

(13)

if

max[X(x)+(x)] In

both cases

If(x)l < c(x-a)x(’()+(’() <

c(x-a)

x()*() (14)

REMARK.

The assertion (13)

can

be exactified:

c 7(x)

If(x+h)-f(x)l

1-(x)-(x) Ihl

(15)

for all x e 0 such that (x)

+ X(x)

< and

If(x+h)-f(x)l clhl7(x)

In Ihl

< (16)

IIII

for those

x

which give the equality (x) + x(x) c being

a

positive

constant

not depending on x and h (see the proof of the theorem).

PROOF OF

THE

THEOREM.

From

the conditions i) and ii) it follows that

E

HP(x)(Q)

Really,

17(x+h)-7(x)l

< l(x+h) (x)l

(x)

I[o(x)]

(7)

ax

(lI"’(x)/F(x)l)

c

Ihl

pc)

So,

it is sufficient to consider the integral

)((x

-1

g(x) (x-t

0(t)dt

we have

to

prove that

g(x)

(a)

(x)

(X)’ (x-a)( + fo(x) (17)

where

f

(x)

c

H

)’cx)+cx) or f

(x)

c

H

xcx)+cx)’1 (18)

0 0

if

max[X(x)+(x)]<l

or

max[),(x)+(x)]=l

respectively (with the exactification (15)-(16), if we will). The derivation itself of the

equali.ty (17)

with the function

fo

(x) [ _(t)-(a)_

dt

(x-t)

1-cx)

is obvious.

For

the function f (x) we prove first the estimate (14). We have o

)e(x)-

If

0(x)l

I111 x()[

(x-t

(t-a)

dt

H

C(x_a)e(x),X(a [1(l_S)e(x)_isX[a,s(x_a)}

g

o

(x) ds

where g (x)- is the function (6). By lemma we have s,a

If

o(x)l < c (x-a)cx)+Xca)

[

o(1-s

)m-

ds c (x-a)2 (x)+)’ca)

Hence, to obtain the estimate

(14),

it remains to observe that

(x_a)(x)*x(a) <c(x-a)(x)*X(X)c (x-a)(a)*x()c

2(x_a)(*)/()

which follows from the lemma (we remark that the condition (5) for

(8)

X(x)+(x) is fulfilled because it is satisfied for x(x) by the assumption in ii) and for

(x)

by the assumption in i)

).Thus,

(14) is proved.

To

prove the

statements

(18) we consider the difference f (x+h) f (x)

0 0

taking h positive. (If h <

O,

by denoting x+h x x x +(-h) we reduce the consideration to the

case

of positive increment). We represent this difference as

o

(x-t)dt

i

0 (x-t)tit

f(x+h) f(x) I (t+h)-(x(x+h) t-(x)

-h 0

Co(X-t)

(t+h)(*+h)- (t+h)(*)-m dt

-h

-h

(t+h)a-c) t-cCx)

o

0

(19)

with

Po(t)_ e(t) e(a)

We estimate J0 first. We have

JJ o

max

Jeo(t)l I I(t+h)(x*h)-- (t+h)(x)-l

dt

-h

x+h-a

(x+h)-I

t(x)-

dt

Since

tu-t tlnt

(u-v) with between u and

v

we obtain

x+h-a

IJ !-o

cl(x+h)-(x)l

0

tF’-lln

tl dt

with ( between (x+h) and e(x) so that

z

m > 0 Since

t(-ls At

m-I with A

max{1,(b-a) -m},

we have

(9)

2(b-a)

IJol cAh/(x) I

o

tm-lln

tl dt c

h/(*)

(20)

As regards the term J in (19) it should be decomposed similarly to the proof of the Hardy Littlewood theorem for the case (x)

const

X(x)

x

const see Samko et al

[3].

We have

J=J +J +J

2. 3

with

xia+h [ go(X-t)-o(X)

Oo(X)

(t+h)(x)- dt J2

(t+h)-(x)

dt

-h

J3 I

o [(t+h)(x)-I t

(x)-l] [o(X-t) 0o(X)]

dt

The estimate of J

In

the case h x-a for the term

J

o(X)

(x) (x_a+h)

c(x) (x-a)

(xcx)]

we use the inequal ty

(x_a)x(x)

IOo(X)l

<

IIOllHX(X

(21)

and the inequality

(1+t)/-1

<

t

with

0</1

and t > 0 We have

IJ

c

(’x-a’X()+((x)

(x)

C(x)

(22)

c(x_a)X(x)+C(x)

h c(x-a)x()+c()- h c h -a

(10)

If x-a h we use (21) again and have

IJl c (x)

(x+h-a)(x) (x-a)(x)

Hence, by (8)

IJ I<

c

X(X)h(X)

c

hX(X)+(x)

--

(x-a) <

--m

The estimate of J The estimate of

2

of

constant

order:

J is completely like in the

case

2

o X(x) Id2 c

I

-h

(t+h)-(x)

Itl dt

C hX(x)+(x)

(23)

The estimate of J We have

3

IJ 13

<c

I tX(x)l(t+h)(x)-I- t(x)’l

dt

o

C hX(X)/(X) o

tX(x) [t(x)-I (t+l)(x)-l]

dt

(24)

If x-a < h we have

j31

c

hX(X)*"x) I tX(x) [te(x)-I

+

(t+l)(x)-l]

dt

o

< c hx(x)+(x)

I

o

(tm-1+1)dt

c h

Let x-a

z h Then

(11)

IJ dr3

sc

hX(X)*=(x) [tX(x) [t=(x)-l (t+l)=(x)-l]

o

under the assumption that X(x)

+

(x) < Then by the 1emma 3 we have

IJ

< c hx(X)/e(x) sin[(x)]

3 sin[e(x)+X(x)]

because

B(=(x),l+x(x)) const.

Since 1/(sint) c(1-t)

"1,

we have

c hx(X)+(X)

IJI

3

(25)

If X(x)+=(x) we split the integration in

(24)

fro 0

to

and fro to (x-a)/h and havehave f ro (24)

IJ

c h

+

h t-1 dt

3 2

since

Itx)-I (t+l)(x)-ll

c

t(x)-Z

for

t > So,

J31

s c h

[1 +

in

_]

< c h in (26)

because x-a h

Gathering the estimates

(20),

(22),

(23), (24),

(25) and

(26)

we obtain the inequalities

(15)

(16) which proves the theorem.

grant.

ACLEDGEMENT.

This work was partially funded by a Fulbright

The authors are thankful to the referee for a careful reading of the manuscript and his suggestions.

(12)

REFERENCES

ROSS,B. AND SAMKO,S.

Integration and differentiation

to

a variable fractional order, Integral Transforms and Special Functions, 1(1993),

N

3.

2.

HARDY,G.H. AND LITTLEWOOD,J.E.

Some properties of fractional integrals,

I,

Math. Zeit., 27(1928), N 4, 565-606.

3.

SAMKO,S. ,KILBAS A. AND MARICHEV,O.

Integrals and Derivatives of Fractional Order. Theory and Applications. Gordon & Breach Sci.

Publ., 1993 (to appear). (Russian edition by "Nauka Tekhnika", Minsk, 1987).

(13)

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