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An involution principle-free bijective proof of Stanley’s hook-content formula

Christian Krattenthaler

Institut f¨ur Mathematik der Universit¨at Wien, Strudlhofgasse 4, A-1090 Wien, Austria.

e-mail kratt@pap.univie.ac.at WWW http://radon.mat.univie.ac.at/People/krat t received 14 Aug 1996, accepted 20 Jan 1997.

A bijective proof for Stanley’s hook-content formula for the generating function for column-strict reverse plane par- titions of a given shape is given that does not involve the involution principle of Garsia and Milne. It is based on the Hillman–Grassl algorithm and Sch¨utzenberger’s jeu de taquin.

Keywords: Plane partitions, tableaux, hook-content formula, Hillman–Grassl algorithm, jeu de taquin, involution principle

1 Introduction

The purpose of this article is to give a bijective proof for Stanley’s hook-content formula [15, Theo- rem 15.3] for a certain plane partition generating function. In order to be able to state the formula we have to recall some basic notions from partition theory. A partition is a sequence

with "!$# , for some% . The Ferrers diagram of is an array of cells with% left-

justified rows and& cells in row '. Figure 1.a shows the Ferrers diagram corresponding to )(*+*+ . The conjugate of is the partition, , -/. where,0 is the length of the1 -th column in the Ferrers diagram of . We label the cell in the'-th row and1 -th column of (the Ferrers diagram of) by the pair

)'12. Also, if we write354 we mean ‘3 is a cell of ’. The hook length67 of a cell38)'91: of is

; &=< 12?>@,

0 < 'AB> , the number of cells in the hook of3 , which is the set of cells that are either in

the same row as3 and to the right of3 , or in the same column as3 and below3 ,3 included. The content

C 7 of a cell3DE)'91: of is1 < '.

F

Supported in part by EC’s Human Capital and Mobility Program, grant CHRX-CT93-0400 and the Austrian Science Foundation FWF, grant P10191-PHY

1365–8050 c

G

1998 Maison de l’Informatique et des Math´ematiques Discr`etes (MIMD), Paris, France

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1 3 4 4

H H I

H J I

K

1 3 4 4

( J I

H I K

K

a. Ferrers diagram b. reverse plane c. column-strict reverse partition plane partition

Figure 1

Given a partitionL; M , a reverse plane partition of shape is a fillingN of the cells of with integers such that the entries along rows and along columns are weakly increasing. Figure 1.b displays a reverse plane partition of shape)(O*+*+ . A reverse plane partition is called column-strict if in addition columns are strictly increasing. Figure 1.c displays a column-strict reverse plane partition of shape)(O*+*+ . We writeNB7 for the entry in cell3 ofN . We call the sum of all the entries of a reverse plane partitionN the norm ofN , and denote it byPQRNS.

Now we are in the position to state Stanley’s hook-content formula [15, Theorem 15.3].

Theorem 1 (Stanley). LetT8 be a partition andU be an integerV% . The generating function WYX[Z2\^]=_, where the sum is over all column-strict reverse plane partitionsN of shape with entries between andU , is given by

Xa`Dbced . &-

cgf

7h

- < Xikj=l9m

< Xn

m (1.1)

Stanley proved this theorem by showing that the generating function in question equals a determinant, and then evaluated the determinant. However, such a proof does not explain why the generating function equals such a nice product. In particular, it does not give any clue why in (1.1) the hook lengths and contents appear. The desire to have an explanation for these phenomenons provides the motivation for the search for a bijective proof of this result. A bijective proof for Stanley’s Theorem 1 was given earlier by Remmel and Whitney [10]. Though being a significant advance, one cannot claim that this proof is really enlightening or explains formula (1.1) in a satisfying way. Aside from making use of the involution principle of Garsia and Milne [2] (which creates bijections in an indirect way), it was based on bijections that mimicked recurrence relations, which is certainly not the most direct route to attack the problem. Our proof of Theorem 1 explains the appearance of hook lengths and contents in a straight-forward way. It is based on the Hillman–Grassl algorithm [3] and on Sch¨utzenberger’s [14] jeu de taquin. It does not need the involution principle. However, the careful reader will notice that we set up a bijection between two sets of objects that are different from those for which Remmel and Whitney set up their bijection. In order to find a bijection between the sets that Remmel and Whitney consider, also we have to use the involution principle. However, the resulting bijection is considerably simpler than Remmel and Whitney’s.

We remark that a bijective proof of Theorem 1 for one-rowed shapes (i.e. the case of (ordinary) parti- tions withoV parts, each partopU ) can be found in Sagan’s paper [11, proof of Theorem 8]. However, this proof is different from our proof when restricted to one-rowed shapes. Besides, this proof does not

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seem to generalize to arbitrary shapes. In the same paper, which has bijective proofs of hook formulas as its theme, also the problem of finding a bijective proof of MacMahon’s product formula [7, Sec. 429, proof in Sec. 494] for the generating function of plane partitions of rectangular shapes with bounded en- tries is posed. Since MacMahon’s formula is actually contained in Theorem 1 (which is seen by an easy transformation of plane partitions into column-strict reverse plane partitions), our bijection also provides a solution to this problem. See also Section 4.

Our paper is organized as follows. In Section 2 our bijective proof of Theorem 1 is described. (A complete example for our bijection is carried out in the appendix of this paper). Then, in Section 3, we discuss some related bijections. In particular, it is there where we explain how our bijection described in Section 2 can be used to provide a much simpler (involution principle-based) bijection between the sets that Remmel and Whitney use in their bijective proof [10] of Theorem 1. Finally, in Section 4, we list some more plane partition formulas that also desire to receive bijective proofs.

In conclusion of the Introduction, a few comments on the relation of the present work to the recent beautiful bijective proof [8] of the Frame–Robinson–Thrall hook formula for the number of standard Young tableaux of a given shape by Novelli, Pak and Stoyanovskii (announced in [9]) are in order. Clearly, the Novelli–Pak–Stoyanovskii algorithm as well as our algorithm described in Section 2 are based on jeu de taquin (a modified jeu de taquin in our case). Still, I am not able to name an immediate, direct relation.

However, I discovered that it is possible to merge the Novelli–Pak–Stoyanovskii idea of how to keep track of the hooks with the modified jeu de taquin idea of this paper to obtain a new bijective proof of the hook- content formula (1.1), which also avoids the involution principle. (In fact, it sets up a bijection between the sets Remmel and Whitney consider in their paper [10].) This will be the subject of a forthcoming publication [5].

2 Bijective proof of Stanley’s hook-content formula

First, we rewrite (1.1) in the form (here CRPP is short for ‘column-strict reverse plane partition’)

q r

]

a CRPP of shape- with s entriess

i X Z2\^]t_vu f

7h

- < X

iMj=lm

VX ` bc^d

. &- c f

7h

- < Xn

m (2.1)

Let us call an arbitrary filling of the cells of with nonnegative integers a tabloid of shape . Further- more, let us define the hook weightw

n

Rxy of a tabloidx of shape byW 7h

- xz7{a67 , and the content

weightw

l

)xy of a tabloidx byW 7h - x 7

2;U|>

C 7 . Then the right-hand side of (2.1) is the generating functionWYX[Z}\^]a~_X[€\^‚[ƒ+_, where the sum is over all pairsRN?„Ox… , withN?„ being the “minimal” column- strict reverse plane partition of shape with entries , i.e. the column-strict reverse plane partition with all entries in row' equal to' for all', and withx … varying over all tabloids of shape . Similarly, the left- hand side of (2.1) is the generating functionW†X Z2\e]‡:_X €ˆk\^‚[‡:_, where the sum is over all pairs ;N?‰gOxz‰, withNB‰ varying over all column-strict reverse plane partitions of shape with entries between andU and varying over all tabloids of shape . So the task is to set up a bijection that maps a right-hand side pairRN „ Ox … to a left-hand side pair;N?‰ Oxz‰, such thatPQRN „ =>Šw

n

)x … QpPQ;N?‰t=>Šw

l

)xz‰t.

One step in our bijection was already done much earlier. In their celebrated paper [3], Hillman and Grassl constructed an algorithmic bijection between tabloidsxz… of shape and reverse plane partitions

‹

N?… of shape with nonnegative entries such thatPQ

‹

NB…QŒw Rx… . If we add such a reverse plane

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partition

‹

N … toN „ cell-wise, then we obtain a column-strict reverse plane partition N … of shape with entries , and we havePQRN … {ŽPQRN „ >pPQ

‹

N … S8PQRN „ >w

n

)x … . Therefore the new task is to set up a bijection that maps a column-strict reverse plane partition of shape with entries to a pair

RNB‰gvxz‰z, where N?‰ is a column-strict reverse plane partition of shape with entries between andU ,

and wherexz‰ is a tabloid of shape , such that

PQ;N

…

QVPQRNB‰t=>Šw

l

Rx‰tM (2.2)

We claim that the following algorithm performs this task.

Algorithm C. The input for the algorithm is a column-strict reverse plane partitionN … of shape with entries .

(C0) Set;Nvxy’‘“”;N

…

•, where• denotes the tabloid of shape with# in each cell.

(C1) IfN does not contain any entry!U then stop. The output of the algorithm is;Nvxy.

Otherwise, consider all corner cells of (which are the cells with no right and bottom neighbour cells).

Choose all corner cells that contain the maximal entry ofN , and among all these pick the left-most, cell– say. (Note that the maximal entry ofN must appear in a corner cell ofN sinceN is a column-strict reverse plane partition. Hence, in our situation it must be!—U .) Replace the entryN?˜ in cell– byN?˜ < RU™> C ˜. Call this entry special. Continue with (C2).

(C2) If a column-strict reverse plane partition is obtained then continue with (C3).

If not, i.e. if the special entry,š say, violates increase along rows or strict increase along columns, then we have the following situation, ›

œ š (2.3)

where at least one ofœ !š and

›

š holds. (One ofœ or

›

is also allowed to be actually not there.) If

œ ! ›

then do the move ›

š’>

œ (2.4)

Ifœ o

›

then do the move

š <

œ › (2.5)

The new special entry in (2.4) isšž> , the new special entry in (2.5) isš < . Repeat (C2). (Note that always after either type of move the only possible violations of increase along rows or strict increase along columns involve the new special entry and the entry to the left or/and above.)

(C3) LetN be the column-strict reverse plane partition just obtained. If we ended up with the special entry in cell3 then add to the entry in cell3 ofx . The tabloid thus obtained is the newx . Continue with (C1). Ÿ

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EXAMPLE C. A complete example for Algorithm C can be found in the appendix. There we choose

U ( and map the column-strict reverse plane partition of shape R(*+O* on the left of Figure 2 to the pair on the right of Figure 2, consisting of a column-strict reverse plane partition of shape )(O*+*+

with entries o( and a tabloid of shape )(O*O*+ , such that the weight property (2.2) holds. In fact, the norm of the column-strict reverse plane partition on the left of Figure 2 is(:¡ , while the norm of the column-strict reverse plane partition on the right is¢ J and the content weight of the tabloid is¢* .

* K

¢ * (

H I K

I

£¥¤

¦§§§§¨ *

¢ ¢ ¢

* * (

( # #

# #

* #

©ª

ªªª

«

PQA¬­p(¡ PQA¬Q®¢

J

?w

l

vQ¯¢*

Figure 2

The appendix has to be read in the following way. First of all, ignore all double circles, and all even rows in the right columns. What the left columns show is the pairRNOxy that is obtained after each loop (C1)-(C2)-(C3). Together with the pair ;Nvxy a filling of the shape R(O*O* is displayed that shows all valuesNB7y>—(|>

C 7 for all cells3 withxz7±°Ž# . This will be important for understanding Lemma C but can be ignored for the moment. At each stage, the entry that is chosen by (C1) is circled. Then each intermediate step during the loop (C1)-(C2)-(C3) is displayed in the odd rows of the right columns. The special entry is always underlined. When a column-strict reverse plane partition is reached, the special entry is boxed. The entry in the corresponding cell of the tabloid is subsequently increased by in step (C3). Ÿ

It should be noticed that, aside from adding/subtracting to/from the special entry, what happens from (2.3) to (2.4), respectively (2.5), is a jeu de taquin forward move (cf. [14, Sec. 2], [13, pp. 120/169]).

It is obvious that this algorithm mapsNB… to a pairRN ‰ vx ‰ , wherex ‰ is a tabloid of shape andN ‰ is a column-strict reverse plane partition of shape with entrieso$U . In fact, the entries ofN ‰ have to be . This is seen as follows. The only problem could arise with our special entry. However, when we arrive at (C3), a special entry o@# can only occur in cell , because otherwise step (C2) was not finished. Each loop (C1)-(C2)-(C3) of the algorithm starts with some entry N ˜ !$U in a corner cell– . It is replaced byN?˜ < RUD> C ˜z. Then it is (possibly) moved according to (2.4) and (2.5). It is easy to check that at each stage during performing the steps (C2), the special entry, if located in cell3 , will equal

N=˜ < ;U²>

C

7[ . This is a property so important that it has to be recorded for later use,

(special entry in3 )®N ˜ < RU²> C 7 k (2.6) Suppose we reach cell . When we arrive at , by (2.6) and sinceC

\

_

8# , our special entry has becomeN ˜ < U . But this is sinceN ˜ !´U .

So we have an algorithm that maps right-hand side objectsN?… of (2.1) to left-hand side objects;N ‰ vx ‰ of (2.1). Besides, this mapping satisfies the weight property (2.2). This is immediate from (2.6).

What remains is to establish that our algorithm is actually a bijection between right-hand side and left- hand side objects. This will be accomplished by constructing an algorithm, Algorithm C* below, that will

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turn out to be the inverse of Algorithm C. We could exhibit Algorithm C* immediately. However, we prefer to provide motivation for the definition of Algorithm C* first, in form of the following lemma. On the other hand, readers who are not interested in the details can safely skip the lemma and jump to the description of Algorithm C* at this point.

Lemma C. Let;Nvxy be obtained after some loop (C1)-(C2)-(C3) during Algorithm C. Suppose that the loop terminated in cellµ when reaching (C3). Then among all cells3 withxz7"°# ,µ is a cell for which the valueNB7t>U­>

C 7 attains its minimum, and if there are several cells3 withxz7¥°V# where the minimum is attained, thenµ is the right-most and top-most of those. Besides, there holds

N=¶{>ŠU·>

C

¶¸´¹¸º[»¼ entries inND½ (2.7)

PROOF. We prove the assertions by induction on the number of loops (C1)-(C2)-(C3).

The assertions are certainly true for the pair

‹

‹

obtained after the very first loop (C1)-(C2)-(C3)

fromRNB…•. This is because there is only one cell¾ in

‹

x with

‹

xz¿¥°V# , and, what regards (2.7), because

‹

N ¿

> U²>

C ¿

V¹¥º»¼ entries inN … ½S ¹¸º[»¼ entries in

‹

ND½ (2.8)

the equality holding because of (2.6), the inequality holding because of the following facts. In the tran- sition fromN … to

‹

N the multiset of entries remains the same, except for one entry, RN … , where– is the corner cell that is chosen when applying (C1) toN … . At the beginning of the loop (C1)-(C2)-(C3) leading fromN … to

‹

N , ;N … is replaced by RN … < ;UD> C ˜z , which is less than;N … because of

UÀ—%Á!—¹¸º[»¼ < C 7

‘3À45z½ (recall thatU % is one of the assumptions in Theorem 1.) Then the special

entryRNB…Q ˜ < RUS> C ˜ is (possibly) moved inwards according to (2.4) and (2.5). At the end of the loop (C1)-(C2)-(C3) a column-strict reverse plane partition is obtained, therefore the special entry in the end has to beo´¹¸º»¼ entries inNB…’½ in any case.

...

...

...

...

...

...

...

µ –

¾

The cells ,¿ ,˜ , the jeu de taquin path from˜ to¿ , and the four regions determined by .

Figure 3

So, let us assume that the assertions are true forRNvx², obtained after some loop (C1)-(C2)-(C3). Let

µ be the cell where the last loop, which gave rise to RNvx², terminated at (C3). Let– be the cell where the next loop starts, i.e. the corner cell ofN chosen by (C1), and let¾ be the cell where this next loop terminates at (C3). See Figure 3. Let

‹

‹

be the outcome after this loop. Note that by construction the cells3 with

‹

x 7 °V# are¾ and the cells withx 7 °p# . In particular,x 7 °p# implies

‹

x 7 °®# .

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First we prove (2.7) for

‹

N and¾ . By (2.6), the entry of

‹

N in cell¾ is

‹

NB¿²®N ˜ <

RU·>

C

¿M (2.9)

This immediately implies

‹

NB¿’> U·>

C

¿²pN ˜ ¹¸º»¼ entries inND½·—¹¥º»¼ entries in

‹

ND½: (2.10)

The last inequality follows from the arguments that proved (2.8), just replaceN … byN in the paragraph after (2.8). Obviously, (2.10) proves (2.7) for

‹

N and¾ , as desired.

Next we show that

‹

N 7 >UÁ>

C 7 , evaluated at cells3 with

‹

x 7 °# , attains its minimal value at¾ . By induction hypothesis, (2.7) holds forN andµ . Hence we have

N > U²>

C ´¹¥º»¼ entries inND½y®N=˜

‹

N ¿ > U²>

C ¿ (2.11)

Let3 be any cell with

‹

xz7¥°V# . Recall that this means3D®¾ orxz7¥°®# . We want to show

‹

NB7’> U·>

C

7S

‹

N ¿ > U²>

C ¿ (2.12)

If3Œ¾ then there is nothing to show. So let3±°¾ . Then we havexz7°@# . By induction hypothesis for

µ , we haveN >—US>

C o¯NB7™>—US>

C 7 for all cells withx75°Â# . So, if we supposeN?7¥

‹

NB7 , then we conclude, using (2.11),

‹

N 7 >ŠU·>

C 7 ®N 7 >ŠU·>

C 7 —N?¶²> U²>

C

¶À

‹

N?¿>ŠU{>

C

¿a

which verifies (2.12) in this case. However, the only entries that are changed during the performance of the loop (C1)-(C2)-(C3) are located in cells (weakly) to the right and (weakly) below of cell¾ , see Figure 3. For these cells there holds the following basic computation. For convenience, let¾ÀŽ)' 1 , and let3Œ)' 1 be in this region to the right and below of¾ , i.e. ' op' and1 o 1 . Then, since

‹

N

is a column-strict reverse plane partition, we have

‹

NB7> U²>

C

‹

N?7Ã> U²>®^1 Ã< '

@

‹

N ¿ >Š'Ã< ' t>ŠU·>Ve1 Ã< ' Q

‹

N ¿ > U²>Ä1 Ã< '

‹

N ¿ >ŠU{>±1 ’< ' ‹

N ¿ > U²>

C ¿ (2.13)

Therefore the value

‹

N 7 >DUz>

C 7 for any cell3 in the region to the right and below of¾ is at least

‹

NB¿2>DUt>

C ¿ , so also for the cells with

‹

x 7 °V# , which verifies (2.12) in this case, too. For later reference we remark that the computation (2.13) also shows that the only cells in this region for which we could have equality are in the same column as¾ .

Finally we show that¾ is the right-most and top-most among all cells3 with

‹

x 7 °p# where

‹

N 7 >TU>

C 7

attains its minimal value. Let3 be a cell with

‹

x 7 °8# where

‹

N 7 >UÁ>

C 7 attains its minimal value. In particular, we have

‹

NB7’> U·>

C

‹

N ¿ > U²>

C ¿ (2.14)

First, suppose that3 is a cell with

‹

N 7 °ÂN 7 . Then3 has to be located in the region (weakly) to the right and (weakly) below of¾ . As we noted after the computation (2.13), the only cells 3 in this region for

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which we could have equality in (2.13) lie in the same column as¾ . ¾ is the top-most and right-most of these, in agreement with our claim.

The more delicate case is when3 is a cell with

‹

xz7¥°V# and

‹

NB7²®N?7 . Of course, nothing is to show for

3D®¾ , so we may assume35°¯¾ . This impliesx7¸°V# , and so

‹

NB7g>±U’>

C

7²VN?7 >±U’>

C

7·N

>±U’>

C , the inequality holding by induction hypothesis forµ . Combining this with (2.11) and (2.14) we are forced to conclude

NB7’> U{>

C

7y®N >ŠU{>

C ‹

N ¿ > U²>

C ¿ (2.15)

We shall show that¾ has to lie in the region (weakly) to the right and (weakly) above ofµ (as is indicated in Figure 3). Sinceµ was the right-most and top-most of all the cells3 withx 7 $#° where the minimal value ofN 7 >ŠU{>

C 7 is attained, this would establish that¾ is the right-most and top-most of all the cells

3 with

‹

x 7 °®# where the minimal value of

‹

N 7 > U·>

C 7 is attained, as desired.

We prove the claim of the previous paragraph by excluding the other three quarter regions that are determined by the horizontal line and the vertical line running throughµ , see Figure 3.

First, suppose that¾ lies in the region strictly to the right and (weakly) below ofµ . ThenN

‹

N , since

µ was not met during the loop (C1)-(C2)-(C3) leading fromN to

‹

N . However, then the basic computation (2.13) applies with¾ replaced byµ , and3 replaced by¾ . Since we assumed that¾ is strictly to the right ofµ , the remark below (2.13) tells that actually strict inequality in (2.13), with the above replacements, holds, i.e.

‹

N ¿ >ŠU·>

C ¿ ! ‹

N > U{>

C . This contradicts (2.15) because ofN

‹

N . Thus, this region is excluded.

Next we show that¾ cannot lie in the region (weakly) to the left and (weakly) below ofµ ,µ excluded.

This would follow immediately from the claim that if two successive loops (C1)-(C2)-(C3) start with the same size of entry in the corner cells chosen by (C1) (which applies in our case since the loop that lead to

N started with an entryN=¶·>ŠU·>

C in some corner cell, and the loop that lead fromN to

‹

N started with

‹

N?¿ž>US>

C ¿ , both quantities being the same by (2.15)) then the second path of moves has to stay to the right of the first path of moves.

To check this claim, once again note that both loops started with the same size of entries in the cells chosen by (C1). By the rules in (C1), this means that either the second loop started strictly to the right of the first, or we started in the same cell, where in this case the first loop started with a left move (2.4).

(Note that if we start with an upward move (2.5) then, by column-strictness, a smaller entry is moved into the corner cell than has been there before.) Now, it is an easy-to-check property of our modified forward jeu de taquin (C2) that if the second “jeu de taquin path” is to the right of the first “jeu de taquin path”

somewhere, then it has to stay to the right from thereon. To make this precise, suppose that during the first loop the special entry,š say, went up by (2.5), see the left half of Figure 4. (The arrows mark the direction of move of the special entry.)

› Å

š/ Æ

during first loop

< ¤ Æ Å

Ǜ Æ Æ Å

›

š

during second loop

< ¤ Æ Æ

› ÇÅ

Figure 4 Since rows are weakly increasing, we have

› o Å

. Suppose that during the second loop we reach the cell neighbouring

›

and

Å

with a special entryš , see the right half of Figure 4. Then the definition of the algorithm forces us to stop here or to move up in the next step (C2). We already checked that the second

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“jeu de taquin path” starts to the right of the first, therefore it has to stay to the right always. So also this region is excluded.

Finally, we examine if¾ could be located in the region strictly to the left and (weakly) above ofµ . Once more the computation (2.13), with3 replaced byµ , applies and, together with the remark below (2.13) (note that we assumedµ to be strictly to the right of¾ ), implies

‹

N=¶D>¯U¸>

C

¶—!

‹

N?¿{>VU¸>

C ¿ , which contradicts (2.15) because of the simple factN?¶À

‹

N=¶ . This completes the proof of the Lemma. Ÿ

From Lemma C it is pretty obvious what the inverse algorithm of Algorithm C could be.

Algorithm C*. The input for the algorithm is a pairRNB‰ vxz‰z, whereN?‰ is a column-strict reverse plane partition of shape with entries between andU , and wherexz‰ is a tabloid of shape .

(C*0) Set;NvxyѬ”RNB‰ vxz‰z.

(C*1) IfxVV• then stop. The output of the algorithm isN .

Otherwise, consider all cells3 withx 7 °$# . Among these choose the cells for whichN 7 >U|>

C 7 is

minimal, and among all these pick the right-most and top-most, cell¾ say. (Observe that among two cells attaining the same value ofN 7 >pUÁ>

C 7 one is always (weakly) to the right and (weakly) above of the other, again because of the computation (2.13), with

‹

N replaced byN , and the remark below (2.13). So the right-most and top-most of these does exist.) Replace the entryNB¿ in cell¾ byN?¿Ã>ŠU·>

C ¿ . Call this entry special. Continue with (C*2).

(C*2) If the special entry,š say, is located in a corner cell of then continue with (C*3).

If not, then we have the following situation,

š œ

› (2.16)

(One ofœ or

›

is also allowed to be actually not there.) IfœTÈ

›

then do the move

œ š

› (2.17)

Ifœ

›

then do the move

› œ

š (2.18)

The new special entry in either case isš . Repeat (C*2).

(C*3) LetN be the column-strict reverse plane partition just obtained. (The fact that indeed a column- strict reverse plane partition is obtained will be proved in the subsequent Lemma C*.) Subtract from the entry in cell¾ ofx . The tabloid thus obtained is the newx . Continue with (C*1). Ÿ

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EXAMPLEC*. A complete example for Algorithm C* can be found in the appendix. There we choose

U5E( and map the pair on the right of Figure 2, consisting of a column-strict reverse plane partition of shape )(O*O*+ with entries oŽ( and a tabloid of shape )(O*+*+ , to the column-strict reverse plane partition of shape)(*+*+ on the left of Figure 2, such that the weight property (2.2) holds. It is simply the inverse of the example for Algorithm C given in Example C. Therefore, here the appendix has to be read in the reverse direction, and in the following way. First of all, ignore all single circles, and all odd rows in the right columns. What the left columns show is the pairRNOxy that is obtained after each loop (C*1)-(C*2)-(C*3) together with a filling of the shape )(O*O*+ that shows all valuesN 7 >—(·>

C 7 for

all cells3 withx 7 °# . At each stage, the entry that is chosen by (C*1) is doubly circled. Then each intermediate step during the loop (C*1)-(C*2)-(C*3) is displayed in the even rows of the right columns.

The special entry is always doubly underlined. When a column-strict reverse plane partition is reached, the special entry is doubly boxed. The entry in the corresponding cell of the tabloid is subsequently decreased by in step (C*3). Ÿ

Again, it should be noticed that (2.17) and (2.18) are exactly jeu de taquin backward moves (cf. [14, Sec. 2], [13, pp. 120/169]), which reverse the forward moves (2.4) and (2.5), respectively, except for the subtraction/addition of in (2.4) and (2.5).

In order to show that Algorithm C* is always well-defined, we have to confirm that when arriving at (C*3) we always obtained a column-strict reverse plane partition. This is established in the following lemma. Besides, this lemma contains the facts about Algorithm C* that are needed to prove that the Algorithms C and C* are inverses of each other.

Lemma C*. Let;Nvxy be obtained after some loop (C*1)-(C*2)-(C*3) during Algorithm C*. Then for all cells3 withx 7 °®# there holds

N?7>ŠU·>

C

7·´¹¸º»¼ entries inND½ (2.19)

Also,N is a column-strict reverse plane partition. Besides, if– is the corner cell that contained the special entry at the end of the loop (C*1)-(C*2)-(C*3) that lead toN , then– is the left-most corner cell inN that contains the maximal entry ofN .

PROOF. We prove the assertions by induction on the number of loops (C*1)-(C*2)-(C*3).

To begin with, we know that when we start with Algorithm C* we have a pair RNOxy, whereN is a column-strict reverse plane partition with entries between andU . So for any cell3D”)'12 we have

N?7>ŠU·>

C

7yVN

\

&R³ 0 _

>ŠU{>

C \

&)³ 0 _

´'z>ŠU{>Ve1 < 'A

!—U

!´¹¸º»¼ entries inND½ (2.20)

So the assertion (2.19) and the assertion thatN is a column-strict reverse plane partition hold at the very beginning. This will suffice for the start of the induction.

As induction hypothesis let us assume that the assertions of the Lemma are true for RNOxy and all preceding pairs occuring in step (C*3) during the process of the algorithm, except of course that the assertion about the corner cell– does not hold for the initial pair (because it does not make sense for the initial pair).

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Let ¾ be the cell where the loop (C*1)-(C*2)-(C*3) starts from RNOxy, i.e. the cell that is chosen by applying (C*1) to RNvx², and let É be the corner cell where the loop stops at (C*3). See Figure 5.

Furthermore, let

‹

‹

be the outcome after this loop. Then, by definition of the algorithm we have

‹

NgÊÁpNB¿’> U·>

C

¿ (2.21)

Note that, also by definition of the algorithm, the cells3 with

‹

xz7°Ë# are those withxz7°Ë# , except

possibly for¾ . In particular,

‹

x7¸°V# impliesxz7¥°p# .

¾ –

µ

É

The cells ,˜ ,¿ ,Ê , the jeu de taquin paths from to˜ and from¿ toÊ .

Figure 5

First we prove (2.19) for

‹

N . Let3 be any cell different fromÉ with

‹

xz7¸°®# . By definition of (C*2) we

have

‹

NB7¥¯NB7 . Besides, we already saw that

‹

xz7"°Â# impliesx7"°”# . Therefore, by construction of¾ in

(C*1), we have

‹

N 7 > U{>

C 7 N 7 >ŠU{>

C 7 N?¿>ŠU{>

C

¿ (2.22)

Note that (2.22) also holds for3¥¯É since by (2.21) we have

‹

N Ê

>´U²>

C Ê

E;N

¿

>ŠU·>

C ¿

?> U{>

C Ê

N ¿ >{U>

C ¿ , the inequality being true because ofU¸´%D!—¹¥º»¼ < C

7·‘3Œ4t½ (recall thatUŒ % is one of the

assumptions in Theorem 1.) Also by construction of¾ , we havex ¿ °p# , and hence by induction hypothesis (2.19) thatN ¿ >ŠU{>

C ¿ ´¹¸º»¼ entries inND½ . This implies thatN ¿ > U²>

C ¿ V¹¸º[»¼ entries in

‹

ND½ since the set of entries of

‹

N is the same as the set of entries inN except for the special entryNB¿=>5UÌ>

C ¿ created in (C*1) and finally located in cellÉ in

‹

N . Hence, (2.22) proves (2.19) withN replaced by

‹

N , as desired.

Now we prove that

‹

N is a column-strict reverse plane partition. IfN?¿ž>—US>

C

¿¸!@¹¸º[»¼ entries inND½

then this assertion certainly holds, since

‹

NgÊ|VNB¿­>ÍU²>

C ¿ is the only new entry in

‹

N . Note in particular, that by (2.20) we are in this case at the very beginning.

By induction hypothesis, (2.19) holds for¾ , so the only other case is

N ¿ >ŠU·>

C ¿ p¹¸º»¼ entries inND½ (2.23)

Observe that the only difficulty arises when we reach corner cellÉ at the end of a loop (C*1)-(C*2)-(C*3) from above, and when in additionNBÊD

‹

NgÊ holds. In this case column-strictness of

‹

N would be violated.

We have to show that this case cannot occur.

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Let ;N·,vx™,e be the pair preceding RNOxy, i.e. ;Nvxy is obtained by applying one loop (C*1)-(C*2)- (C*3) toRN·,Ox™,^. As we just noted,;N·,;Ox™,^ exists, since if RNvx² were the initial pair we would not be in this case because of (2.20). Furthermore, letµ be the cell where this loop starts, and let– be the corner cell where it stops, see Figure 5. By definition of the algorithm we have

N=˜5pN

,

> U²>

C (2.24)

Now, by induction hypothesis and the definition of the algorithm,

N ,

>ŠU·>

C

p¹¸º[»¼ entries inND½ (2.25)

Furthermore, there holds N·,¿

oN ¿ , by the definition of (C*1) if¾$°†– , but also if ¾V†– because of (2.24) and the induction hypothesis (2.19) forN·, and3´Îµ . Hence, again by definition of (C*1),

N·,

>UD>

C oEN·,

¿

>pU|>

C ¿ o$N ¿ >VU|>

C ¿ . Combining this with (2.23) and (2.25), we are forced to conclude

N ,

>ŠU{>

C VN

,

¿

> U{>

C ¿ 9VN ¿ > U²>

C ¿ k (2.26)

Therefore, again by definition of (C*1),¾ lies (weakly) to the left and (weakly) below ofµ , as is indicated in Figure 5.

It is an easy-to-check property of backward jeu de taquin (C*2) that if the second “jeu de taquin path”

is to the left of the first “jeu de taquin path” somewhere, then it has to stay to the left from thereon. To be precise, suppose that during the first loop (C*1)-(C*2)-(C*3) the special entry,š say, went down by (2.18), see the left half of Figure 6. (Again, the arrows mark the direction of move of the special entry.)

Æ š

Å › during

first loop

< ¤ Æ ›

Å ÏÆ š ›

Å Æ

during second loop

< ¤ Å ›

ÏÆ Æ

Figure 6 Since rows are weakly increasing, we have

Å o ›

. Suppose that during the second loop we reach the cell neighbouring

›

and

Å

with a special entryš , see the right half of Figure 6. Then the definition of the algorithm forces us to stop here or to move down in the next step (C*2).

We already saw that the second “jeu de taquin path” starts at¾ , which is (weakly) to the left and (weakly) below ofµ , the starting cell of the first “jeu de taquin path”. Therefore, if we suppose that the first path does not meet¾ , we are to the left of the first path when we start the second path. Then, if at the end of the second path we reach the same corner cell as the first path did, we have to reach it from the left. As noted above, this guarantees that

‹

N is a column-strict reverse plane partition. If we do not reach the same corner cell, then we reach a corner cellÉ to the left. In this case our induction hypothesis for– , the corner cell that was reached at the end of the first path, says thatNBÊ is strictly less than N ˜ ¹¸º[»¼ entries inND½ . Therefore, by using (2.21) and (2.23) we have NgÊ È ¹¸º[»¼ entries inND½Š

‹

NgÊ . Hence,

‹

N will be a column-strict reverse plane partition, regardless from which direction we reached cellÉ .

Now we have to consider the only remaining case that the first path, starting atµ , meets¾ . In this case,

¾ would have to lie in the same column asµ (and below). First suppose that¾ is left by the first path by a downward move. In this case, by (2.18), we would haveNB¿±!ŽN·,¿ , which contradicts (2.26). So the

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first path has to leave¾ by a right move. Hence, we are to the left of the first path at the beginning of the second path. Thus, the above considerations apply again.

Finally, we prove thatÉ is the left-most corner cell in

‹

N that contains the maximal entry in

‹

N . This is trivially true ifN ¿ >ÄUÃ>

C ¿ !´¹¸º[»¼ entries inND½ , again by remembering (2.21). Note that this inequality

is in particular true at the very beginning of Algorithm C*, because in this case (2.20) holds even for all cells3 , so also for¾ . Because of the induction hypothesis (2.19), the only other case isN ¿ >—UÁ>

C ¿

¹¥º»¼ entries inND½ . Since we are not at the very beginning, we are allowed to assume that this last

assertion of Lemma C* holds forN and– . However, we already considered the caseNB¿²>®U¥>

C

¿T

¹¥º»¼ entries inND½ before (see (2.23)) and showed that the “jeu de taquin path” leading from¾ toÉ has

to stay to the left of the “jeu de taquin path” leading fromµ to– . HenceÉ is (weakly) to the left of– . By induction hypothesis,– was the left-most corner cell containing the maximal entry ofN . SoÉ , which by (2.21) containsN ¿ >U|>

C ¿ $¹¥º»¼ entries inND½ in

‹

N , is the left-most corner cell of

‹

N containing

¹¥º»¼ entries in

‹

ND½ (p¹¸º[»¼ entries inND½ ), as desired.

This completes the proof of the Lemma. Ÿ

From Lemmas C and C* it is abundantly clear that the Algorithms C and C* are inverses of each other.

This finishes the bijective proof of (2.1).

3 Related bijections

In this section we discuss bijections related to the bijection in Section 2. It is mainly intended to serve the true purist among combinatorialists.

It is two items that we want to address in this section. First, one might argue that we did not prove Theorem 1 directly, but the variant (2.1). Well, as we show in the first part of this section, it is not difficult to construct a bijective proof of Theorem 1 directly, i.e. of

q r

]

a CRPP of shape- with ks entriess

i X

Z}\^]t_ u

pXa`

bc^d . &- c f

7h

- < X n m f

7h

- < X

iMj=lm

k (3.1)

by using our Algorithms C and C*. Secondly, Remmel and Whitney [10], in the first bijective proof of Stanley’s hook-content formula Theorem 1, gave an involution principle-based bijective proof for even another variant of Theorem 1, namely

q r

]

a CRPP of shape- with ks entriess

i X

Z2\e]t_u

f

7h

67ÑzVX `Ábc^d

. &- c f

7h -2Ð

U²>

C

(3.2)

where

Ð

PÑy‘“ >VX²>®X

>Â>pX

Z}Ò . While we do not know how to construct a direct bijection (in the sense of avoiding the involution principle) for (3.2), we are able to find a much simpler involution principle-based bijective proof of (3.2) by using our Algorithms C and C*. This is subject of the second part of this section.

Before we start, we introduce some special tabloids to be used in the course of the following bijections.

LetÓ be some function from the set of all cells of a Ferrers diagram into the integers, that maps the cell

3 to the valueÓ 7 , say. Then we call a tabloidx of shape a È Óz-tabloid ifx 7 È Ó 7 for all cells3Œ4T , and we callx aR# Óz-tabloid ifx 7 equals# orÓ 7 , for all cells3À45 . The signÔOÕaÖtRxy of aR#Óz-tabloid is always defined to be< number of nonzero entries in

‚ .

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