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2 Sufficient Conditions For Univalence

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Certain sufficient conditions for univalence

1

Narayanasamy Seenivasagan and Daniel Breaz

Abstract

In this paper, we determined conditions on β, αi and fi(z) so that the integral operator

( β

Z z

0

tβ−1 Yn i=1

(fi(t) t )αi1 dt

)1

β

is univalent in the open unit disk for the two subclasses analytic functions.

2000 Mathematical Subject Classification: Primary 30C80, Secondary 30C45.

Key words: Integral operator, univalent functions, Schwartz’s Lemma.

1 Introduction

Let A be the class of all analytic functions f(z) defined in the open unit disk U := {z C: |z| < 1} and normalized by the conditions f(0) = 0 = f0(0)1. Let Sbe the subclass ofAconsisting of univalent functions in U.

Let A2 be the subclass of Aconsisting of functions is of the form

(1.1) f(z) = z+

X

k=3

akzk.

1Received 12 September, 2007

Accepted for publication (in revised form) 15 October, 2007

7

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Let T be the univalent [6] subclass of A which satisfies (1.2)

¯¯

¯¯z2f0(z) (f(z))2 1

¯¯

¯¯<1 (z ∈U).

LetT2 be the subclass of T for whichf00(0) = 0. Let T2,µ be the subclass of T2 consisting of functions is of the form (1.1) which satisfy

(1.3)

¯¯

¯¯z2f0(z) (f(z))2 1

¯¯

¯¯≤µ (z ∈U)

for some µ (0 < µ 1), and let us denote T2,1 T2. Furthermore, for some real p with 0< p 2 we define a subclass S(p) of A consisting of all function f(z) which satisfy

¯¯

¯¯ µ z

f(z)

00¯

¯¯

¯≤p (z ∈U).

Singh [5] has shown that iff(z)S(p), thenf(z) satisfies (1.4)

¯¯

¯¯z2f0(z) (f(z))2 1

¯¯

¯¯≤p|z|2, (z ∈U).

Pascu [2] has proved the following theorem:

Theorem 1.1. [2, 3] Let β C, Reβ ≥γ >0. If f A satisfies 1− |z|

γ

¯¯

¯¯zf00(z) f0(z)

¯¯

¯¯1, (z ∈U), then the integral operator

Fβ(z) =

· β

Z z

0

tβ−1f0(t)dt

¸1

β

is in f S.

Theorem 1.2. [4] Let α, β C and Reβ Reα |α|3 . Let f A, that satisfies the condition

¯¯

¯¯z2f0(z) (f(z))2 1

¯¯

¯¯<1, (z ∈U)

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and |f(z)| ≤1, (z ∈U), then the integral operator

Hα,β(z) = (

β Z z

0

tβ−1 µf(t)

t

1

α

dt )1β

is in S.

Using Theorem1.1 and Theorem 1.2, Breaz and Breaz [1] obtained the following Theorems.

Theorem 1.3. [1] Let α, β C and Reβ ≥Reα > |α|3n. Let fi ∈T2 and

(1.5) fi(z) = z+

X

k=3

aikzk

for all i= 1,2,· · · , n, n N :=N\ {0} and if

|fi(z)| ≤1, (z ∈U, i= 1,2,· · · , n), then the integral operator

(1.6) Fα,β(z) = (

β Z z

0

tβ−1 Yn

i=1

µfi(t) t

1

α

dt )1

β

is in S.

Theorem 1.4. [1] Let α, β C and Reβ Reα > n(µ+2)|α| . Let fi T2,µ

defined by (1.5) for all i = 1,2,· · · , n, n N and if |fi(z)| ≤ 1, (z U, i= 1,2,· · · , n), then the integral operator defined by (1.6) is in S.

Theorem 1.5. [1] Let α, β C and Reβ Reα > n(p+2)|α| . Let fi S(p) defined by (1.5) for all i = 1,2,· · · , n, n N and if |fi(z)| ≤ 1, (z U, i= 1,2,· · · , n), then the integral operator defined by (1.6) is in S.

Theorem 1.2 is true even if Reβ Reα 3/|α| is replaced by the conditionReβ 3/|α|. Similarly Theorem1.3 is true even ifReβ≥Reα≥

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3n/|α| is replaced by the condition Reβ 3n/|α|, Theorem 1.4 is true even if Reβ Reα n(µ+2)|α| is replaced by the condition Reβ n(µ+2)|α|

and Theorem 1.5 is true even if Reβ Reα n(p+2)|α| is replaced by the condition Reβ≥ n(p+2)|α| .

In this paper we extend Theorems 1.3-1.5 and also obtain the sufficient condition for univalency of certain integral operator.

To prove our main results we need the following lemma:

Lemma 1.1. (Schwarz’s Lemma) If the function w(z) is analytic in the unit desk U, w(0) = 0, and |w(z)| ≤1, for all z ∈U, then

|w(z)| ≤ |z|, (z ∈U) and equality holds only if w(z) = ²z, where |²|= 1.

2 Sufficient Conditions For Univalence

Forfi A2(i= 1,2,· · · , n) andα1, α2,· · · , αn, β C, we define an integral operator by

(2.1) Fα12,···n(z) = (

β Z z

0

tβ−1 Yn

i=1

µfi(t) t

1

αi dt )1

β

.

When αi = α for all i = 1,2,· · · , n, Fα12,···n(z) becomes the integral operator Fα,β(z) considered in Theorem 1.3.

Theorem 2.1. Let M 1, fi ∈T2,µi defined by (1.5), αi, β C, Reβ≥γ and

(2.2) γ :=

Xn

i=1

(1 +µi)M + 1

i| (0< µi 1, f or all i= 1,2,· · · , n, n∈N).

If

|fi(z)| ≤M, (z ∈U, i= 1,2,· · · , n),

then the integral operator Fα12,···n(z) defined by (2.1) is in S.

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Proof. Define a function h(z) =

Z z

0

Yn

i=1

µfi(t) t

1

αi dt,

then we have h(0) =h0(0)1 = 0. Also a simple computation yields h0(z) =

Yn

i=1

µfi(z) z

1

αi

and

(2.3) zh00(z)

h0(z) = Xn

i=1

1 αi

µzfi0(z) fi(z) 1

.

From equation (2.3), we have

¯¯

¯¯zh00(z) h0(z)

¯¯

¯¯ Xn

i=1

1

i| µ¯¯

¯¯zfi0(z) fi(z)

¯¯

¯¯+ 1

= Xn

i=1

1

i| µ¯¯¯

¯z2fi0(z) (fi(z))2

¯¯

¯¯

¯¯

¯¯fi(z) z

¯¯

¯¯+ 1

¶ (2.4)

From the hypothesis, we have |fi(z)| ≤M (z∈U, i= 1,2,· · ·, n),then by Schwarz Lemma, we obtain that

|fi(z)| ≤M|z| (z ∈U, i= 1,2,· · · , n).

We apply this result in inequality (2.4), we obtain

¯¯

¯¯zh00(z) h0(z)

¯¯

¯¯ Xn

i=1

1

i| µ¯¯

¯¯z2fi0(z) (fi(z))2

¯¯

¯¯M + 1

Xn

i=1

1

i| µ¯¯

¯¯z2fi0(z) (fi(z))2 1

¯¯

¯¯M +M + 1

¶ (2.5)

= Xn

i=1

1

i|iM +M + 1) = Xn

i=1

(1 +µi)M + 1

i| .

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Because of fi ∈T2,µi, (1.3) in (2.5) and in view of (2.2) we have

¯¯

¯¯zh00(z) h0(z)

¯¯

¯¯ <

Xn

i=1

(1 +µi)M + 1

i| =γ.

(2.6)

Multiply (2.6) by

1− |z|

γ ,

we have

1− |z| γ

¯¯

¯¯zh00(z) h0(z)

¯¯

¯¯ 1− |z| <1 (z ∈U).

Since Reβ≥γ >0 it follows from Theorem1.1 that

· β

Z z

0

tβ−1h0(t)dt

¸1

β

S.

Since

· β

Z z

0

tβ−1h0(t)dt

¸1

β

=

"

β Z z

0

tβ−1 Yn

i=1

µfi(t) t

1

αi dt

#β1

=Fα12,···n(z), the integral operator Fα12,···,αn(z) defined by (2.1) is in S.

Remark 2.1. By taking M = 1, αi =α, f or all i= 1,2,· · · , n, then The- orem 2.1 reduces to Theorem 1.4. By taking µi =µ= 1, αi =α, f or all i= 1,2,· · · , n, then Theorem 2.1 reduces to Theorem 1.3.

Theorem 2.2. Let M 1, fi S(p)defined by (1.5), αi, β C, Reβ≥γ1 and

(2.7) γ1 :=

Xn

i=1

(1 +p)M+ 1

i| ( f or all i= 1,2,· · · , n, n∈N).

If

|fi(z)| ≤M (z ∈U, i= 1,2,· · · , n),

then the integral operator Fα12,···n(z) defined by (2.1) is in S.

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Proof. Define a function h(z) =

Z z

0

Yn

i=1

µfi(t) t

1

αi dt,

then we have h(0) =h0(0)1 = 0. Because of fi S(p), (1.4) in (2.5), in view of (2.7) we have

¯¯

¯¯zh00(z) h0(z)

¯¯

¯¯ Xn

i=1

1 +M +Mp|z|2

i| (2.8)

<

Xn

i=1

(1 +p)M+ 1

i| =γ1 (z ∈U).

(2.9)

Rest of the proof is similar to Theorem 2.1, then we omit the details.

Remark 2.2. By taking M = 1, αi = α, f or all i = 1,2,· · · , n, then Theorem 2.2 reduces to Theorem 1.5.

Theorem 2.3. Let αi, β C, Reβ ≥γ2 and (2.10) γ2 :=

Xn

i=1

βi

i| (0< βi 1, f or all i= 1,2,· · · , n, n∈N).

If fi A2 defined by (1.5) satisfy the conditions (2.11)

¯¯

¯¯zfi0(z) fi(z) 1

¯¯

¯¯≤βi (0< βi 1, z ∈U, i= 1,2,· · · , n), then the integral operator Fα12,···n(z) defined by (2.1) is inS.

Proof. From (2.3), we get (2.12)

¯¯

¯¯zh00(z) h0(z)

¯¯

¯¯=

¯¯

¯¯

¯ Xn

i=1

1 αi

µzfi0(z) fi(z) 1

¶¯¯¯

¯¯ Xn

i=1

1

i|

¯¯

¯¯zfi0(z) fi(z) 1

¯¯

¯¯. Substituting (2.11) in (2.12) and in view of (2.10) we have

¯¯

¯¯zh00(z) h0(z)

¯¯

¯¯ <

Xn

i=1

βi

i| =γ2. (2.13)

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Rest of the proof is similar to Theorem 2.1, then we omit the details.

By taking βi = 1 and αi =α (f or all i = 1,2,· · · , n) in Theorem 2.3, we obtained the following result.

Example 2.1. Let α, β C, Reβ≥ |α|n. If fi A2 defined by (1.5) satisfy the conditions

(2.14)

¯¯

¯¯zfi0(z) fi(z) 1

¯¯

¯¯1 (z ∈U, i= 1,2,· · · , n), then the integral operator Fα,β(z) defined by (1.6) is in S.

References

[1] D. Breaz and N. Breaz, The univalent conditions for an integral oper- ator on the classes S(p) and T2, Journal of Approximation Theory and Applications, Vol. 1, No.2, (2005), pp. 93–98.

[2] N. N. Pascu,On a univalence criterion. II, in Itinerant seminar on func- tional equations, approximation and convexity (Cluj-Napoca, 1985), 153–154, Univ. “Babe¸s-Bolyai”, Cluj.

[3] N. N. Pascu, An improvement of Becker’s univalence criterion, in Proceedings of the Commemorative Session: Simion Sto¨ılow (Bra¸sov, 1987), 43–48, Univ. Bra¸sov, Bra¸sov.

[4] V. Pescar, New criteria for univalence of certain integral operators, Demonstratio Math. 33(1) (2000), 51–54.

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[5] V. Singh, On a class of univalent functions, Int. J. Math. Math. Sci.

23(12) (2000), 855–857.

[6] S. Ozaki and M. Nunokawa, The Schwarzian derivative and univalent functions, Proc. Amer. Math. Soc. 33 (1972), 392–394.

Narayanasamy Seenivasagan 2A Kamarajar Street

Samatharmapuram, Theni 625531 India

E-mail: [email protected]

Daniel Breaz

Department of Mathematics and Computer Science

”1 Decembrie 1918” University of Alba Iulia 510009, str. N. Iorga, No. 11-13, Alba, Romania E-mail: [email protected]

参照

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