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POSITIVE SOLUTIONS TO A SECOND ORDER MULTI-POINT BOUNDARY-VALUE PROBLEM

Daomin Cao & Ruyun Ma

Abstract. We prove the existence of positive solutions to the boundary-value prob- lem

u00+λa(t)f(u, u0) = 0 u(0) = 0, u(1) =

m−2X

i=1

aiu(ξi),

wherea is a continuous function that may change sign on [0,1],f is a continuous function withf(0,0)>0, andλ is a samll positive constant. For finding solutions we use the Leray-Schauder fixed point theorem.

1. Introduction

The study of multi-point boundary value problems for linear second order ordi- nary differential equations was initiated by Il’in and Moiseev [8, 9]. Motivated by the study of Il’in and Moiseev [8, 9], Gupta [4] studied certain three point boundary value problems for nonlinear ordinary differential equations. Since then, more gen- eral nonlinear multi-point boundary value problems have been studied by several authors using the Leray-Schauder Continuation Theorem, Nonlinear Alternative of Leray-Schauder, coincidence degree theory or fixed point theorem in cones. We refer the reader to [1-3, 5, 10-12] for some existence results of nonlinear multi-point boundary value problems. Recently, the second author[12] proved the existence of positive solutions for the three-point boundary value problem

u00+b(t)g(u) = 0, t∈(0,1) (1.1)

u(0) = 0, αu(η) =u(1), (1.2)

whereη ∈(0,1), 0< α < 1η,b≥0, andg≥0 is either superlinear or sublinear by the simple application of a fixed point theorem in cones.

In this paper, we consider the nonlinear eigenvalue m-point boundary value problem

u00+λa(t)f(u, u0) = 0 (1.3)

u(0) = 0, u(1) =

m−2X

i=1

aiu(ξi) (1.4)

2000 Mathematics Subject Classifications: 34B10.

Key words: Multi-point boundary value problem, positive solution, fixed point theorem.

c2000 Southwest Texas State University.

Submitted September 18, 2000. Published Ocotber 30, 2000.

R.Ma was supported by the Natural Science Foundation of China (grant 19801028) 1

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whereλis a positive parameter.

We make the following assumptions:

(A1) ai≥0 fori= 1,· · · , m−3 andam−2>0;ξi: 0< ξ1< ξ2<· · ·< ξm−2<1 andPm−2

i=1 aiξi<1.

(A2) f : [0,∞)×R→R is continuous andf(0,0) >0;

(A3) a∈ C[0,1] and there exist r0 ∈[0,1] and θ > 0 such that a(r0) 6= 0, and the solution of the linear problem

u00+a+(t)−(1 +θ)a(t) = 0, t∈(0,1) u(0) = 0, u(1) =

m−2X

i=1

aiu(ξi)

is nonnegative in [0,1], where a+ is the positive part of a and a is the negative part ofa.

(A4) There exist a constant k in (1,∞) such that

P(t)≥kQ(t) (1.5)

where P(t) =

Z t

0

a+(s)ds+

Pm−2

i=1 aiRξi

0i−s)a+(s)ds 1−Pm−2

i=1 aiξi + R1

0(1−s)a+(s)ds 1−Pm−2

i=1 aiξi and

Q(t) = Z t

0

a(s)ds+

Pm−2

i=1 aiRξi

0i−s)a(s)ds 1−Pm−2

i=1 aiξi + R1

0(1−s)a(s)ds 1−Pm−2

i=1 aiξi Our main result is

Theorem 1. Let (A1), (A2), (A3), and (A4) hold. Then there exists a positive number λ such that (1.3)-(1.4) has at least one positive solution for 0< λ < λ.

The proof of this theorem is based upon the Leray-Schauder fixed point theorem and motivated by [7].

2. Preliminary lemmas

In the sequel we shall denote byI the interval [0,1] of the real line. E will stand for the space of functionsu :I →R such that u(0) = 0, u(1) = Pm−2

i=1 aiu(ξi) and u0is continuous onI. We furnish the setEwith the norm|u|E = max{|u|0,|u0|0}=

|u0|0, where|u|0= max{u(t)|t∈I}. ThenE is a Banach space.

To prove Theorem 1, we need the following preliminary results.

Lemma 1 [6]. Let ai ≥ 0 for i = 1,· · · , m−2, and Pm−2

i=1 aiξi 6= 1, then for y∈C(I), the problem

u00+y(t) = 0, t∈(0,1) (2.1)

u(0) = 0, u(1) =

m−2X

i=1

aiu(ξi) (2.2)

has a unique solution,

u(t) =− Z t

0

(t−s)y(s)ds−t Pm−2

i=1 aiRξi

0i−s)y(s)ds 1−Pm−2

i=1 aiξi +t R1

0(1−s)y(s)ds 1−Pm−2

i=1 aiξi The following two results extend Lemma 2 and Lemma 3 of [12].

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Lemma 2. Let ai≥0 for i= 1,· · · , m−2, and Pm−2

i=1 aiξi <1. If y∈C(I) and y≥0, then the unique solution u of the problem (2.1)-(2.2) satisfies

u(t)≥0, ∀t∈I

Proof From the fact that u00(x) = −y(x) ≤ 0, we know that the graph of u(t) is concave down on I. So, if u(1) ≥ 0, then the concavity of u together with the boundary conditionu(0) = 0 implies that u≥0 for allt∈I.

If u(1)<0, then from the concavity ofu we know that u(ξi)

ξi ≥ u(1)

1 , fori= 1,· · · , m−2 (2.3) This implies

u(1) =

m−2X

i=1

aiu(ξi)≥

m−2X

i=1

aiξiu(1) (2.4)

This contradicts the fact that Pm−2

i=1 aiξi<1.

Lemma 3. Let ai ≥ 0 for i = 1,· · · , m−3, am−2 > 0, and Pm−2

i=1 aiξi > 1. If y∈C(I) and y(t)≥0 for t∈I, then (2.1)-(2.2) has no positive solution.

Proof Assume that (2.1)-(2.2) has a positive solution u, then u(ξi) > 0 for i = 1,· · · , m−2, and

u(1) =

m−2X

i=1

aiu(ξi) =

m−2X

i=1

aiξiu(ξi) ξi

m−2X

i=1

aiξiu( ¯ξ)

ξ¯ > u( ¯ξ) ξ¯

(2.5)

(where ¯ξ ∈ {ξ1,· · · , ξm−2} satisfies u(¯ξ¯ξ) = min{u(ξξii)|i = 1,· · ·, m−2}). This contradicts the concavity ofu.

If u(1) = 0, then applyingam−2>0 we know that

u(ξm−2) = 0 (2.6)

From the concavity ofu, it is easy to see thatu(t)≤0 for allt inI.

In the rest of this paper, we assume that ai≥0 for i= 1,· · ·, m−3,am−2>0, andPm−2

i=1 aiξi<1. We also assume that f(u, p) =f(0, p) for (u, p)∈(−∞,0).

Lemma 4. Let (A1) and (A2) hold. Then for every 0 < δ < 1, there exists a positive number ¯λsuch that, for 0< λ <λ, the problem¯

u00+λa+(t)f(u, u0) = 0 (2.7) u(0) = 0, u(1) =

m−2X

i=1

aiu(ξi) (2.8)

has a positive solution u˜λ with|u˜λ|E →0 and |u˜0λ|0→0 as λ→0 , and

˜

uλ≥λδf(0,0)p(t), t∈I (2.9)

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where

p(t) =− Z t

0

(t−s)a+(s)ds−t Pm−2

i=1 aiRξi

0i−s)a+(s)ds 1−Pm−2

i=1 aiξi +t R1

0(1−s)a+(s)ds 1−Pm−2

i=1 aiξi

Proof. By Lemma 2, we know that p(t) ≥0 for t∈I. From Lemma 1, (2.7)-(2.8) is equivalent to the integral equation

u(t) =λ h−

Z t

0

(t−s)a+(s)f(u(s), u0(s))ds

−t Pm−2

i=1 aiRξi

0i−s)a+(s)f(u(s), u0(s))ds 1−Pm−2

i=1 aiξi

+t R1

0(1−s)a+(s)f(u(s), u0(s))ds 1−Pm−2

i=1 aiξi

i

def= Au(t)

whereu∈C1(I). Further, we have that (Au)0(t) =λ

h− Z t

0

a+(s)f(u(s), u0(s))ds

Pm−2

i=1 aiRξi

0i−s)a+(s)f(u(s), u0(s))ds 1−Pm−2

i=1 aiξi

+ R1

0(1−s)a+(s)f(u(s), u0(s))ds 1−Pm−2

i=1 aiξi

i

(2.10)

Then A : C1(I) → C1(I) is completely continuous and fixed points of A are so- lutions of (2.7)-(2.8). We shall apply the Leray-Schauder fixed point theorem to proveAhas a fixed point forλ small.

Let >0 be such that

f(u, y)≥δf(0,0), for (u, y)∈[0, ]×[−, ] (2.11) Suppose that

λ <

2|P|0f˜() := ¯λ (2.12) where ˜f(r) = max

(u,y)∈[0,r]×[−r,r]f(u, y). By (A2) we know that

r→0lim+ f˜(r)

r = +∞. (2.13)

It follows that there existsrλ∈(0, ) such that f˜(rλ)

rλ = 1

2λ|P|0

(2.14)

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We note that (2.14) implies

rλ→0, asλ→0 (2.15)

Now, consider the homotopy equations

u=θAu, θ∈(0,1) (2.16)

Letu ∈C1(I) and θ∈(0,1) be such that u=θAu. We claim that |u|E 6=rλ. In fact,

u0(t) =θλ h−

Z t

0

a+(s)f(u(s), u0(s))ds

Pm−2

i=1 aiRξi

0i−s)a+(s)f(u(s), u0(s))ds 1−Pm−2

i=1 aiξi

+ R1

0(1−s)a+(s)f(u(s), u0(s))ds 1−Pm−2

i=1 aiξi

i

(2.17)

This implies that

|u0(t)| ≤λf˜(|u|E)P(t), t∈[0,1] (2.18) hence

|u|E ≤λ|P|0f˜(|u|E) (2.19)

or f˜(|u|E)

|u|E ≥ 1 λ|P|0

(2.20) which implies that|u|E6=rλ. Thus by Leray-Schauder fixed point theorem,A has a fixed point ˜uλ with

|u˜λ|E ≤rλ< (2.21)

Moreover, combining (2.21) and (2.11) and using (2.10) and Lemma 2, we have that

˜

uλ(t)≥λδf(0,0)p(t), (2.20)

fort∈I,λ≤λ¯ .

3. Proof of the main reuslt Proof of Theorem 1. Let

q(t) =− Z t

0

(t−s)a(s)ds−t Pm−2

i=1 aiRξi

0i−s)a(s)ds 1−Pm−2

i=1 aiξi +t R1

0(1−s)a(s)ds 1−Pm−2

i=1 aiξi (3.1) then from Lemma 2, we know thatq(t)≥0. By (A3) and (A4), there exist positive numbersc, d∈(0,1) such that for t∈I,

q(t) max{|f(u, y)| |0≤u≤c,−c≤y ≤c} ≤dp(t)f(0,0),

Q(t) max{|f(u, y)| |0≤u≤c,−c≤y ≤c} ≤dP(t)f(0,0). (3.2)

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Fix δ∈(d,1) and let λ>0 be such that

|u˜λ|E+λδf(0,0)|P|0 ≤c (3.3) forλ < λ, where ˜uλ is given by Lemma 4, and

|f(u1, y1)−f(u2, y2)| ≤f(0,0) δ−d 2

(3.4)

for (u1, y1),(u2, y2)∈[0, c]×[−c, c] with

max{|u1−u2|,|y1−y2|} ≤λδf(0,0)|P|0.

Let λ < λ. We look for a solution uλ of the form ˜uλ+vλ. Here vλ solves v00+λa+(t)(f(˜uλ+v,u˜0λ+v0)−f(˜uλ,u˜0λ))−λa(t)f(˜uλ+v,u˜0λ+v0) = 0

(3.5) v(0) = 0, v(1) =

m−2X

i=1

aiv(ξi) (3.6)

For each w∈C1(I), letv=T(w) be the solution of

v00+λa+(t)(f(˜uλ+w,u˜0λ+w0)−f(˜uλ,u˜0λ))−λa(t)f(˜uλ+w,u˜0λ+w0) = 0 v(0) = 0, quadv(1) =

m−2X

i=1

aiv(ξi)

ThenT :C1(I)→C1(I) is completely continuous.

Let v∈C1(I) and θ∈(0,1) be such thatv=θT v. Then we have

v00+θλa+(t)(f(˜uλ+v,u˜0λ+v0)−f(˜uλ,u˜0λ))−θλa(t)(f(˜uλ+v,u˜0λ+v0)) = 0 (3.7) v(0) = 0, v(1) =

m−2X

i=1

aiv(ξi) (3.8)

We claim that |v|E 6= λδf(0,0)|P|0. Suppose to the contrary that |v|E = λδf(0,0)|P|0. Then by (3.3), we obtain

|u˜λ+v|E≤ |u˜λ|E+|v|E ≤c,

|u˜λ+v|0≤ |u˜λ|0+|v|0≤c . (3.9) These inequalities and (3.4) imply

|f(˜uλ+v,u˜0λ+v0)−f(˜uλ,u˜0λ)|0≤f(0,0) δ−d 2

. (3.10)

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Using (3.10)and (3.2) and applying Lemma 1 and Lemma 2, we have that

|v(t)| ≤λδ−d

2 f(0,0)p(t) +λmax{|f(u, y)| |0≤u≤c,−c≤y≤c}q(t)

≤λδ−d

2 f(0,0)p(t) +λdf(0,0)p(t)

=λδ+d

2 f(0,0)p(t), t∈I

(3.11)

and

|v0(t)| ≤λδ−d

2 f(0,0)P(t) +λmax{|f(u, y)| |0≤u≤c,−c≤y≤c}Q(t)

≤λδ−d

2 f(0,0)P(t) +λdf(0,0)P(t)

=λδ+d

2 f(0,0)P(t), t∈I

(3.12)

In particular

|v|E ≤λδ+d

2 f(0,0)|P|0< λδf(0,0)|P|0 (3.13) a contradiction, and the claim is proved. Thus by Leray-Schauder fixed point theorem,T has a fixed ponit vλ with

|vλ|E ≤λδf(0,0)|P|0 (3.14) Finally, using (2.9) and (3.11), we obtain

uλ≥u˜λ− |vλ|

≥λδf(0,0)p(t)−λδ+d

2 f(0,0)p(t)

=λδ−d

2 f(0,0)p(t), t∈I

(3.15)

i.e.,uλ is a positive solution of (1.3)-(1.4).

References

[1] W. Feng and J. R. L. Webb, Solvability of a three-point boundary value problems at resonance, Nonlinear Analysis TMA 30(1997), 3227-3238.

[2] W. Feng and J. R. L. Webb, Solvability of am-point boundary value prob- lems with nonlinear growth, J. Math. Anal. Appl. 212 (1997), 467-480.

[3] W. Feng,On an m-point boundary value problem, Nonlinear Analysis TMA 30(1997), 5369-5374.

[4] C. P. Gupta, Solvability of a three-point nonlinear boundary value problem for a second order ordinary differential equation, J. Math. Anal. Appl. 168 (1992), 540-551.

[5] C. P. Gupta, A sharper condition for the solvability of a three-point second order bounder value problem, J. Math. Anal. Appl. 205 (1997), 586-597.

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[6] C. P. Gupta, S. K. Ntouyas and P. Ch. Tsamatos,On an m-point boundary value problem for second order ordinary differential equations, Nonlinear Analysis TMA23, (1994), 1427-1436.

[7] D. D. Hai,Positive solutions to a class of elliptic boundary value problems, J. Math. Anal. Appl. 227 (1998), 195-199.

[8] V. A. Il’in and E. I. Moiseev, Nonlocal boundary value problem of the first kind for a Sturm-Liouville operator in its differential and finite difference aspects, Differential Equations 23(7)(1987), 803-810.

[9] V. A. Il’in and E. I. Moiseev,Nonlocal boundary value problem of the second kind for a Sturm-Liouville operator, Differential Equations 23(8) (1987), 979-987.

[10] R. Ma, Existence theorems for a second order three-point boundary value problem, J. Math. Anal. Appl. 212(1997), 430-442.

[11] R. Ma, Existence theorems for a second order m-point boundary value prob- lem, J. Math. Anal. Appl. 211 (1997), 545-555.

[12] R. Ma,Positive solutions of a nonlinear three-point boundary value problem, Electron. J. Differential Equations341999 (1999) 1-8.

Daomin Cao

Institute of Applied Mathematics, Academy of Mathematics and System Sciences, Beijing 100080, People’s Republic of China

E-mail address: [email protected]

Ruyun Ma

Department of Mathematics, Northwest Normal University, Lanzhou 730070, Gansu, People’s Republic of China

E-mail address: [email protected]

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