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volume 7, issue 3, article 93, 2006.

Received 21 December, 2005;

accepted 28 July, 2006.

Communicated by:H.M. Srivastava

Abstract Contents

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Journal of Inequalities in Pure and Applied Mathematics

MEROMORPHIC FUNCTIONS THAT SHARE ONE VALUE WITH THEIR DERIVATIVES

KAI LIU AND LIAN-ZHONG YANG

School of Mathematics & System Sciences Shandong University

Jinan, Shandong, 250100, P. R. China EMail:liuk@mail.sdu.edu.cn EMail:lzyang@sdu.edu.cn

URL:http://202.194.3.2/html/professor/ylzh/YangIndex.html

c

2000Victoria University ISSN (electronic): 1443-5756 373-05

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Meromorphic Functions that Share One Value with their

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Abstract

In this paper, we deal with the problems of uniqueness of meromorphic func- tions that share one finite value with their derivatives and obtain some results that improve the results given by Rainer Brück and Qingcai Zhang.

2000 Mathematics Subject Classification:30D35.

Key words: Meromorphic functions, Uniqueness, Sharing values.

This work was supported by the NNSF of China (No.10371065) and the NSF of Shandong Province, China (No.Z2002A01).

Contents

1 Introduction and Main Results. . . 3

2 Some Lemmas. . . 8

3 Proof of Theorem 1.2 . . . 9

4 Proof of Theorem 1.4 . . . 14

5 Proof of Theorem 1.6 and Theorem 1.7 . . . 18 References

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1. Introduction and Main Results

In this paper, a meromorphic function will mean meromorphic in the finite com- plex plane. We say that two meromorphic functionsf andgshare a finite value aIM (ignoring multiplicities) whenf−aandg−ahave the same zeros. Iff−a andg−ahave the same zeros with the same multiplicities, then we say thatf andgshare the valueaCM (counting multiplicities). We say thatf andg share

∞ CM provided that1/f and 1/g share 0 CM. It is assumed that the reader is familiar with the standard symbols and fundamental results of Nevanlinna Theory, as found in [3,6].

Let f(z) be a meromorphic function. It is known that the hyper-order of f(z),denoted byσ2(f),is defined by

σ2(f) = lim sup

r→∞

log logT(r, f) logr . In 1996, R. Brück posed the following conjecture (see [1]).

Conjecture 1.1. Let f be a non-constant entire function such that the hyper- orderσ2(f)off is not a positive integer andσ2(f)<+∞.Iff andf0 share a finite valueaCM, then

f0 −a f −a =c, wherecis nonzero constant.

In [1], Brück proved that the conjecture holds when a = 0. In 1998, Gun- dersen and Yang [2] proved that the conjecture is true whenf is of finite order.

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In 1999, Yang [4] confirmed that the conjecture is also true whenf0is replaced byf(k)(k ≥2)andf is of finite order.

In 1996, Brück obtained the following result.

Theorem A ([1]). Letf be a nonconstant entire function. Iff andf0 share the value 1 CM, and ifN

r,f10

=S(r, f), then

f0−1 f−1 ≡c

for a non-zero constantc.

In 1998, Q. Zhang proved the next two results in [7].

Theorem B. Letf be a nonconstant meromorphic function. Iff andf0 share the value 1 CM, and if

N(r, f) +N

r, 1 f0

<(λ+o(1))T(r, f0),

0< λ < 1 2

,

then f0−1

f−1 ≡c for some non-zero constantc.

Theorem C. Let f be a nonconstant meromorphic function, k be a positive integer. Iff andf(k)share the value 1 CM, and if

2N(r, f) +N

r, 1 f0

+N

r, 1

f(k)

<(λ+o(1))T(r, f(k)), (0< λ <1),

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then

f(k)−1 f−1 ≡c for some non-zero constantc.

The above results suggest the following question: What results can be ob- tained if the condition that f and f0 share the value 1 CM is replaced by the condition thatf andf0 share the value 1 IM?

In this paper, we obtained the following results.

Theorem 1.2. Letf be a nonconstant meromorphic function, iff andf0 share the value 1 IM, and if

N(r, f) +N

r, 1 f0

<(λ+o(1))T(r, f0)

0< λ < 1 4

,

then f0−1

f−1 ≡c for some non-zero constantc.

Corollary 1.3. Let f be a nonconstant entire function. If f and f0 share the value 1 IM, and if

N

r, 1 f0

<(λ+o(1))T(r, f0),

0< λ < 1 4

,

then f0−1

f−1 ≡c for some non-zero constantc.

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Theorem 1.4. Let f be a nonconstant meromorphic function, k be a positive integer. Iff andf(k)share the value 1 IM, and if

(3k+ 6)N(r, f) + 5N

r, 1 f

<(λ+o(1))T(r, fk), (0< λ <1), then

f(k)−1 f−1 ≡c for some non-zero constantc.

Corollary 1.5. Let f be a nonconstant entire function. Iff andf(k) share the value 1 IM, and if

N

r, 1 f

<(λ+o(1))T(r, f),

0< λ < 1 10

, then

f(k)−1 f−1 ≡c for some non-zero constantc.

Theorem 1.6. Let f be a nonconstant meromorphic function, k be a positive integer. Iff andf(k)share the valuea 6= 0CM, and satisfy one of the following conditions,

(i) δ(0, f) + Θ(∞, f)> 2k+14k , (ii) N(r, f) +N

r, 1f

<(λ+o(1))T(r, f), 0< λ < 2k+12 ,

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(iii) k+12

N(r, f) + 32N

r,f1

<(λ+o(1))T(r, f), (0< λ <1).

Thenf ≡f(k).

Theorem 1.7. Letf be a nonconstant meromorphic function. Iff andf0share the valuea6= 0IM, and if

N(r, f) +N

r, 1 f

<(λ+o(1))T(r, f),

0< λ < 2 3

, thenf ≡f0.

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2. Some Lemmas

Lemma 2.1 ([7]). Letf be a nonconstant meromorphic function,kbe a positive integer. Then

N

r, 1 f(k)

< N

r, 1 f

+kN(r, f) +S(r, f), (2.1)

N

r, f(k) f

< kN(r, f) +kN

r, 1 f

+S(r, f), (2.2)

N

r,f(k) f

< kN(r, f) +N

r, 1 f

+S(r, f).

(2.3)

Suppose that f andg share the value a IM, and let z0 be aa-point of f of orderp, aa-point off(k) of orderq. We denote byNL

r,f(k)1−a

the counting function of thosea-points off(k)whereq > p.

Lemma 2.2. Letfbe a nonconstant meromorphic function. Iff andf(k)share the value 1 IM, then

(2.4) NL

r, 1 f(k)−1

< N

r, 1 f(k)

+N(r, f) +S(r, f).

Lemma 2.3 ([7]). Letf be a nonconstant meromorphic function,kbe a positive integer. Iff andf(k)share the value 1 IM, then

T(r, f)<3T(r, f(k)) +S(r, f), specially iff is a nonconstant entire function, then

T(r, f)<2T(r, f(k)) +S(r, f).

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3. Proof of Theorem 1.2

Let N1)

r,f−a1

denote the counting function of the simple zeros of f − a, N(2

r,f−a1

denote the counting function of the multiplea-points of f. Each point in these counting functions is counted only once. We denote byN2

r,f−a1

the counting function of the zeros off−a,where a simple zero is counted once and a multiple zero is counted twice. It follows that

(3.1) N2

r, 1 f−a

=N1)

r, 1 f−a

+ 2N(2

r, 1 f−a

. Set

F = f000

f00 − 2f00 f0−1−

f00

f0 − 2f0 f −1

.

We suppose thatF 6≡0. By the lemma of logarithmic derivatives, we have

(3.2) m(r, F) =S(r, f)

and

(3.3) N(r, F)≤N(r, f) +N

r, 1 f0

+N(2

r, 1 f0−1

+N0

r, 1

f00

+S(r, f),

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where N(2

r,f01−1

denotes the counting function of multiple 1-points off0, and each 1-point is counted only once; N0

r,f100

denotes the counting func- tions off00which are not the zeros off0andf0−1.

Sincef andf0 share the value 1 IM, we know thatf −1has only simple zeros. Iff0−1also has only simple zeros, thenf andf0share the value 1 CM, and Theorem1.2follows by the conclusion of TheoremB.

Now we assume thatf0−1has multiple zeros. By calculation, we know that the common simple zeros of f −1and f0 −1are the zeros of F; we denote by NE1)

r,f−11

the counting function of common simple zeros off −1 and f0−1. It follows that

(3.4) NE1)

r, 1 f−1

≤N

r, 1 F

≤T(r, F) =N(r, F) +S(r, f).

From (3.3) and (3.4), we have (3.5) NE1)

r, 1

f −1

≤N(r, f) +N

r, 1 f0

+N(2

r, 1 f0−1

+N0

r, 1

f00

+S(r, f).

Notice that

(3.6) N

r, 1

f0−1

=NE1)

r, 1 f −1

+N(2

r, 1

f0−1

.

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By the second fundamental theorem, we have (3.7) T(r, f0)< N(r, f) +N

r, 1

f0

+N

r, 1 f0−1

−N0

r, 1 f00

+S(r, f).

From Lemma2.2, (3.8) N(2

r, 1

f0−1

=NL

r, 1 f0−1

< N(r, f) +N

r, 1 f0

+S(r, f).

Combining (3.5), (3.6), (3.7) and (3.8), we obtain T(r, f0)≤N(r, f) +N

r, 1

f0

+NE1)

r, 1 f−1

+NL

r, 1 f0−1

−N0

r, 1 f00

+S(r, f)

≤N(r, f) +N

r, 1 f0

+N(r, f) +N

r, 1 f0

+ 2NL

r, 1 f0−1

+S(r, f)

≤4N(r, f) + 4N

r, 1 f0

+S(r, f),

which contradicts the condition of Theorem1.2. Therefore, we haveF ≡0.By integrating twice, we have

1

f−1 = A

f0−1+B,

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whereA6= 0andB are constants.

We distinguish the following three cases.

Case 1. IfB 6= 0,−1, then

f = (B+ 1)f0+ (A−B−1) Bf0+ (A−B) ,

f0 = (B −A)f+ (A−B−1 Bf −(B+ 1) , and so

N r, 1

f0+ A−BB

!

=N(r, f)

By the second fundamental theorem T(r, f0)< N(r, f0) +N

r, 1

f0

+N r, 1 f0+ A−BB

!

+S(r, f)

<2N(r, f) +N

r, 1 f0

+S(r, f), which contradicts the assumption of Theorem1.2.

Case 2. IfB =−1, then

f = A

−f0+ (A−1)

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and so

N

r, 1

f0−(A+ 1)

=N(r, f).

We also get a contradiction by the second fundamental theorem.

Case 3. IfB = 0, it follows that

f0−1 f −1 =A, and the proof of Theorem1.2is thus complete.

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4. Proof of Theorem 1.4

Let

F = f(k+2)

f(k+1) −2 f(k+1)

f(k)−1 −f00

f0 + 2 f0 f−1

We suppose thatF 6≡0.Since the common zeros (with the same multiplicities) off −1andf(k)−1are not the poles ofF,and the common simple zeros of f −1andf(k)−1are the zeros ofF,we have

(4.1) NE1)

r, 1 f−1

≤N

r, 1 F

≤T(r, F) =N(r, F) +S(r, f).

and

(4.2) N(r, F)≤N(r, f) +NL

r, 1 f −1

+NL

r, 1 f(k)−1

+N(2(

r, 1 f

+N(2

r, 1

f(k)

+N0

r, 1 f0

+N0

r, 1

f(k+1)

+S(r, f),

whereN0

r,f(k+1)1

denotes the counting function of the zeros off(k+1)which are not the zeros off(k) andf(k)−1, N0

r,f10

denotes the counting function

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of the zeros off0which are not the zeros off. Since N

r, 1 f(k)−1

=N

r, 1 f −1

(4.3)

=NE1)

r, 1 f −1

+N(2E

r, 1

f −1

+NL

r, 1 f−1

+NL

r, 1 f(k)−1

,

we obtain from (4.1), (4.2) and (4.3) that N

r, 1 f(k)−1

≤N(r, f) + 2NL

r, 1 f −1

+N(2E

r, 1

f−1

+N(2

r, 1 f

+N

0r, 1 f0

+ 2NL

r, 1 f(k)−1

+N(2

r, 1 f(k)

+N0

r, 1

f(k+1)

+S(r, f)

≤N(r, f) + 2N

r, 1 f0

+ 2NL

r, 1 f(k)−1

+N(2

r, 1 f(k)

+N0

r, 1

f(k+1)

+S(r, f),

whereN(2E

r,f−11

is the counting function of common multiple zeros off−1 andf(k)−1,each point is counted once. By the second fundamental theorem

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and Lemma2.2, we have

T(r, f(k))≤N(r, f) +N

r, 1 f(k)

+N

r, 1 f(k)−1

−N0

r, 1 f(k+1)

+S(r, f)

≤N(r, f) +N

r, 1 f(k)

+N(r, f) + 2N

r, 1 f0

+ 2NL

r, 1 f(k)−1

+N(2

r, 1

f(k)

+S(r, f)

≤2N(r, f) +N

r, 1 f(k)

+ 2N

(r, 1

f0

+ 2N

r, 1 f(k)

+ 2N(r, f) +S(r, f)

≤(3k+ 6)N(r, f) + 5N

r, 1 f

+S(r, f),

which contradicts the assumption of Theorem1.2. HenceF ≡0.

By integrating twice, we get 1

f −1 = C

f(k)−1 +D,

whereC 6= 0andDare constants. By arguments similar to the proof of Theo- rem1.2, Theorem1.4follows.

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Remark 1. Let f be a non-constant entire function. Then we obtain from Lemma2.3that

1

2T(r, f)≤T(r, f(k)) +S(r, f).

By Theorem1.4, Corollary1.5holds.

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5. Proof of Theorem 1.6 and Theorem 1.7

Suppose thatf 6≡f(k). Let

F = f f(k). Then

(5.1) T(r, F) =m

r, 1 F

+N

r, 1

F

=N

r,f(k) f

+S(r, f).

Sincef andf(k)share the valuea 6= 0CM, we have N

r, 1

f−a

≤N

r, 1 f−f(k)

(5.2)

≤N

r, 1 F −1

≤T(r, F) +O(1).

By the lemma of logarithmic derivatives and the second fundamental theorem, we obtain

(5.3) m

r, 1

f

+m

r, 1 f −a

< m

r, 1 f(k)

+S(r, f),

and

(5.4) T r, f(k)

< N

r, 1 f(k)

+N(r, f(k)) +N

r, 1 f(k)−a

+S(r, f),

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from (5.4), we have

(5.5) m

r, 1

f(k)

< N(r, f) +N

r, 1 f(k)−a

+S(r, f).

Combining with (5.1), (5.2), (5.3), (5.4), (5.5) and (2.2) of Lemma 2.1, we obtain

2T(r, f)≤m

r, 1 f(k)

+N

r, 1

f

+N

r, 1 f −a

+S(r, f)

≤N(r, f) +N

r, 1 f(k)−a

+N

r, 1

f

+N

r, 1 f −a

+S(r, f)

≤N(r, f) +N

r, 1 f

+ 2N

r, 1

f−a

+S(r, f)

≤N(r, f) +N

r, 1 f

+ 2N

r,f(k)

f

+S(r, f)

≤N(r, f) + 2(kN(r, f) +kN

r, 1 f

+N

r, 1

f

+S(r, f)

≤(2k+ 1)N(r, f) + (2k+ 1)N

r, 1 f

+S(r, f),

which contradicts the assumptions (i) and (ii) of Theorem1.6. Hencef ≡f(k). Similarly, by the above inequality and (2.3) of Lemma 2.1, and suppose that (iii) is satisfied, then we get a contradiction if f 6≡ f(k), and we complete the proof of Theorem1.6.

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Remark 2. For a nonconstant meromorphic function f, if f and f0 share the valuea 6= 0IM andf 6≡f(k), since aa-point off is not a zero off0, we know thatf−ahas only simple zeros, and we have

N

r, 1 f−a

≤N

r, 1 F −1

≤T(r, F) +O(1),

whereF =f /f0.By the arguments similar to the proof of Theorem1.6, Theo- rem1.7follows.

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References

[1] R. BRÜCK, On entire functions which share one value CM with their first derivatives, Result in Math., 30 (1996), 21–24.

[2] G.G. GUNDERSEN AND L.-Z. YANG, Entire functions that share one value with one or two of their derivatives, J. Math. Anal. Appl., 223 (1998), 88–95.

[3] C.C. YANGANDH.-X. YI, Uniqueness Theory of Meromorphic Functions, Kluwer Academic Publishers, 2003.

[4] L.-Z. YANG, Solution of a differential equation and its applications, Kodai Math. J., 22 (1999), 458–464.

[5] H.-X. YI, Meromorphic function that share one or two value II, Kodai Math.

J., 22 (1999), 264–272.

[6] H.-X. YIANDC.C. YANG, Uniqueness Theory of Meromorphic Functions, Science Press, Beijing, 1995. [In Chinese].

[7] Q.-C. ZHANG, The uniqueness of meromorohic function with their deriva- tives, Kodai Math. J., 21 (1998), 179–184.

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Supported by the NNSF of China (Grant No. 10471065), the NSF of Education Department of Jiangsu Province (Grant No. 04KJD110001) and the Presidential Foundation of South

inter-universal Teichm¨ uller theory, punctured elliptic curve, number field, mono-complex, ´ etale theta function, 6-torsion points, height, explicit esti- mate, effective

His idea was to use the existence results for differential inclusions with compact convex values which is the case of the problem (P 2 ) to prove an existence result of the