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BASS NUMBERS OF GENERALIZED LOCAL COHOMOLOGY MODULES Sh. Payrovi, S. Babaei, and I. Khalili-Gorji

Abstract. Let Rbe a Noetherian ring, M a finitely generated R-module andN an arbitraryR-module. We consider the generalized local cohomology modules, with respect to an arbitrary idealIofR, and prove that, for all non- negative integersr, tand allp Spec(R) the Bass numberµr(p, HIt(M, N)) is bounded above by Pt

j=0µr p,Extt−jR (M, HIj(N)). A corollary is that Ass HIt(M, N)

St

j=0Ass ExttRj(M, HIj(N))

.In a slightly different di- rection, we also present some well known results about generalized local coho- mology modules.

1. Introduction

The local cohomology theory has been a significant tool in commutative alge- bra and algebraic geometry. As a generalization of the ordinary local cohomology modules, Herzog [8] introduced the generalized local cohomology modules and these had been studied further by Suzuki [15] and Yassemi [16] and some other authors.

They studied some basic duality theorems, vanishing and other properties of gen- eralized local cohomology modules which also generalize several known facts about Ext and ordinary local cohomology modules.

An important problem in commutative algebra is to determine when the Bass numbers of the i-th local cohomology module is finite. In [9] Huneke conjectured that if (R,m, k) is a regular local ring, then for any prime idealp of R the Bass numbers µi(p, HIj(R)) = dimk(p)ExtiRp(k(p), HIRj

p(Rp)) are finite for all i and j.

There is evidence that this conjecture is true. It is shown by Huneke and Sharp [10] and Lyubeznik [11] that the conjecture holds for regular local ring containing a field. This conjecture is also true for unramified regular local rings of mixed characteristic; this is part of the main theorem of [12]. On the other hand there is a negative answer to the conjecture (over non-regular ring) that is due to Harts- horne [7]. In [5] Dibaei and Yassemi studied the relationship between the Bass numbers of a module and its local cohomology modules. We would like to study

2010Mathematics Subject Classification: Primary 13D45; Secondary 14B15.

Key words and phrases: generalized local cohomology, Bass numbers.

Communicated by Žarko Mijajlović.

233

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the relationship between the Bass numbers of generalized local cohomology modules HIi(M, N) and ExtiR(M, HIj(N)) wheneverR is a Noetherian ring,M is a finitely generated R-module andN is an arbitraryR-module.

2. Main results

Throughout this sectionRis a Noetherian ring,Iis an ideal ofR,M is a finitely generatedR-module,N is an arbitraryR-module andr, tare non-negative integers.

For a prime idealpofR ther-th Bass number ofM is denoted byµr(p, M).

The following lemma will be used to prove the main result of this paper.

Lemma 2.1.

µr(p, HI1(M, N))6µr(p,Ext1R(M,ΓI(N))) +µr(p,HomR(M, HI1(N))).

Proof. In view of [3, Corollary 11.1.6] and [6, Lemma 2.1]µr(p, HIt(M, N)) = µr(pRp, HIt(Mp, Np)); also in view of [3, Corollary 4.3.3]

µr(p,ExttRj(M, HIj(N))) =µr(pRp,ExttRj

p(Mp, HIRj

p(Np))).

So, we may assume thatRis a local ring with maximal idealp. We denoteµr(p, M) byµr(M) and we have to show that

µr(HI1(M, N))6µr(Ext1R(M,ΓI(N))) +µr(HomR(M, HI1(N))).

By Theorem 11.38 of [14] there is a Grothendieck spectral sequence E2p,q := ExtpR(M, HIq(N))⇒pHIp+q(M, N) =Ep+q

and there exists a finite filtration 0 = φ2E1φ1E1φ0E1 =HI1(M, N) such that E0,1 = E11E1 and E1,0 ∼= φ1E1. Thus µr(E1) 6 µr(E0,1) +µr(E1,0).

Now, by the sequence 0 −→ E20,1 d

0,1

−→2 E22,0 we haveE0,1 ∼=E30,1 ∼= kerd0,12 . Also E1,0∼=E21,0. Hence,µr(E1)6µr(kerd0,12 ) +µr(E21,0)6µr(E20,1) +µr(E21,0) from

which the result follows.

Theorem 2.1. We haveµr(p, HIt(M, N))6Pt

j=0µr(p,ExttRj(M, HIj(N))).

Proof. The proof which we include for the reader’s convenience, is based on [5, Theorem 2.1]. By the same argument as Lemma 2.1 we may assume thatR is a local ring with maximal ideal p. We have to show that

µr(HIt(M, N))6

t

X

j=0

µr(Extt−jR (M, HIj(N))).

We use induction ont. In the caset= 0, we haveHI0(M, N) = HomR(M,ΓI(N)) so that there is nothing to prove. In the case when t = 1, the claim follows from Lemma 2.1. We therefore assume, inductively, that t >1 and the result has been proved for smaller values of t. Then the exact sequence 0 −→ΓI(N)−→ N −→

N/ΓI(N)−→0 induces a long exact sequence

· · · −→HIt(M,ΓI(N))−→HIt(M, N)−→HIt(M, N/ΓI(N))−→ · · ·

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which implies that

µr(HIt(M, N))6µr(HIt(M,ΓI(N))) +µr(HIt(M, N/ΓI(N))).

LetE be an injective hull of ΓI(N) and letL=E/ΓI(N). Then by the sequence 0−→ΓI(N)−→E−→L−→0 it follows thatHIi1(M, L))∼=HIi(M,ΓI(N)), for alli>2. Thus by induction hypothesis fort−1, we have

µr(HIt1(M, L))6

t−1

X

j=0

µr(ExttR1j(M, HIj(L))) =µr(ExttR(M,ΓI(N)))

since HIi(L) ∼=HIi+1I(N)) = 0, for all i > 1. Also, the exact sequence 0 −→

ΓI(N)−→ ΓI(E) −→ΓI(L) −→0 shows Extt−R1(M, HI0(L))∼= ExttR(M,ΓI(N))) because ΓI(E) is an injectiveR-module. LetEbe an injective hull ofN/ΓI(N) and letK=E/N/ΓI(N). Then by the sequence 0−→N/ΓI(N)−→E−→K−→0 it follows thatHIi1(M, K))∼=HIi(M, N/ΓI(N)), for alli>2. Thus by induction hypothesis fort−1, we have

µr(HIt1(M, K))6

t1

X

j=0

µr(ExttR1j(M, HIj(K)))

=

t1

X

j=1

µr(ExttR1j(M, HIj(K))) +µr(ExttR1(M, HI0(K)))

=

t1

X

j=1

µr(ExttR1j(M, HIj+1(N/ΓI(N))))+µr(ExttR1(M, HI0(K)))

=

t1

X

j=1

µr(Extt−R1−j(M, HIj+1(N))) +µr(ExttR1(M, HI0(K)))

=

t

X

j=2

µr(ExttRj(M, HIj(N))) +µr(Extt−R1(M, HI0(K))).

Now, the exact sequence 0−→ΓI(E)−→ΓI(K)−→HI1(N/ΓI(N))−→0 shows that ExttR1(M, HI0(K))∼= ExttR1(M, HI1(N/ΓI(N)))∼= ExttR1(M, HI1(N)). Thus

µr(HIt1(M, K))6

t

X

j=2

µr(Extt−jR (M, HIj(N))) +µr(ExttR1(M, HI1(N)))

=

t

X

j=1

µr(ExttRj(M, HIj(N))).

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Hence,

µr(HIt(M, N))6µr(HIt(M,ΓI(N))) +µr(HIt(M, N/ΓI(N)))

=µr(HIt1(M, L)) +µr(HIt1(M, K)) 6µr(ExttR(M,ΓI(N))) +

t

X

j=1

µr(ExttRj(M, HIj(N)))

which is claimed.

Corollary 2.1. [13, Theorem 1.1]We have Ass(HIt(M, N))⊆

t

[

j=0

Ass(ExttRj(M, HIj(N))).

Proof. Letp∈Ass(HIt(M, N)). Thenµ0(p, HIt(M, N))6= 0. So, by Theorem 2.1 we havePt

j=1µ0(p,ExttRj(M, HIj(N)))6= 0. Hence, there exists 06j6tsuch that µ0(p,Extt−jR (M, HIj(N))) 6= 0. Therefore,p ∈St

j=0Ass(Extt−jR (M, HIj(N))).

Definition2.1. AnR-moduleXis said to beI-cofinite, whenever Supp(X)⊆ V(I) and ExtiR(R/I, X) is finitely generatedR-module, for alli>0.

Corollary 2.2. If Supp(M) ⊆ V(I) and HIj(N) is I-cofinite, for all 0 6 j 6 t, then µr(p, HIi(M, N)) < ∞, for all 0 6 i 6 t. In particular, if I is an ideal of R with Spec(R) =V(I) andHIj(N) isI-cofinite, for all 0 6j 6t, then µr(p, HIi(N))<∞, for all 06i6t.

Proof. In view of [4, Proposition 1] Extt−jR (M, HIj(N)) is a finitely generated R-module, for all 06j6t. Now, the claim is obvious by Theorem 2.1.

Corollary 2.3. If Supp(M)⊆V(I) andN is a finitely generatedR-module for whichHIj(N)is finitely generated, for all06j < t, thenµr(p, HIi(M, N))<∞, for all 0 6i 6t. In particular, if I is an ideal of R with Spec(R) =V(I) and N is a finitely generated R-module for which HIj(N) is finitely generated, for all 06j < t, thenµr(p, HIi(N))<∞, for all 06i6t.

Proof. In view of [1, Theorem 2.5] and [4, Proposition 1] ExttRj(M, HIj(N)) is a finitely generated R-module, for all 0 6 j 6 t. Now, the claim follows by

Theorem 2.1.

Corollary 2.4. [2, Proposition 5.2]Let pdM <and letdimN <∞, then HIt(M, N) = 0, for all t >pdM+ dimN. In particular,

µr(p, HIpdM+dimN(M, N))6µr(p,ExtpdR M(M, HIdimN(N))).

Proof. By Theorem 2.1 it follows that µ0(p, HIt(M, N)) = 0, for any prime ideal p of R and for all t > pdM + dimN. Thus HIt(M, N)) = 0. The second

assertion also follows by Theorem 2.1.

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Corollary 2.5. [16, Theorem 2.5] Let pdM <and letara(I)<∞; then HIt(M, N) = 0, for all t >pdM + ara(I), where ara(I), the arithmetic rank of the idealI, is the least number of elements ofRrequired to generate an ideal which has the same radical as I. In particular,

µr(p, HIpdM+ara(I)(M, N))6µr(p,ExtpdR M(M, HIara(I)(N))).

Proof. It follows by the same argument as that of Corollary 2.4.

Theorem 2.2. We have µr(p,ExttR(M, HI0(N)))6

t

X

j=2

µr(p,ExttRj(M, HIj1(N))) +µr(p, HIt(M, N)).

Proof. We may assume that R is a local ring with maximal ideal p. So we have to show that

µr(ExttR(M, HI0(N)))6

t

X

j=2

µr(ExttRj(M, HIj1(N))) +µr(HIt(M, N)).

Theorem 11.38 of [14] shows that there is a Grothendieck spectral sequence E2p,q:= ExtpR(M, HIq(N))⇒pHIp+q(M, N) =Ep+q.

Now, the exact sequence

· · · −→E2t2,1d

t2,1

−→2 E2t,0−→0

and E3t,0 =E2t,0/Imdt22,0 show that µr(Et,02 ) 6µr(E2t2,1) +µr(E3t,0). Also, the exact sequence

· · · −→E3t−3,2d

t3,2

−→3 E3t,0−→0

andE4t,0=E3t,0/Imdt33,2 show thatµr(E3t,0)6µr(E4t,0) +µr(E3t3,2). Hence, µr(E2t,0)6µr(E2t2,1) +µr(E3t3,2) +µr(E4t,0)

6µr(E2t2,1) +µr(E2t3,2) +µr(E4t,0) 6· · ·=

t

X

j=2

µr(E2tj,j1) +µr(Et+1t,0)

=

t

X

j=2

µr(E2t−j,j−1) +µr(Et)

since Ekt−j,j−1 is a subquotient of E2t−j,j−1, for all 3 6 k 6 t, and Et+1t,0 is a subquotient ofEt, whereEt,0∼=φtEtt+1Et∼=φtEtEtand

0 =φtEt⊆ · · · ⊆φ1Etφ0Et=Et

is a finite filtration. This completes the proof.

Acknowledgment. The authors are deeply grateful to the referee for his/her careful reading of the manuscript and very helpful suggestions.

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Department of Mathematics (Received 06 11 2013)

Imam Khomeini International University Qazvin, Iran

[email protected] [email protected] [email protected]

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